Find the equation of the line through P=(8,7) such that the triangle bounded by this line and the axes in the first quadrant has the minimal area.

Find The Equation Of The Line Through P=(8,7) Such That The Triangle Bounded By This Line And The Axes

Answers

Answer 1

The area of the triangle is given by the product of 0.5 and the distances of the x and y intercepts from the origin.

[tex]\mathrm{The \ equation \ of \ the \ line \ is, }\displaystyle \ \underline{ y = 14 - \frac{7}{8} \cdot x}[/tex]

Reasons:

The area of the triangle, A = 0.5·x·y

Where;

x and y are the values of the line at the intercepts

The equation of the line is; (y - 7) = m·(x - 8)

At the y-intercept, x = 0, therefore;

(y - 7) = m·(0 - 8) = -8·m

At the y-intercept, y = 7 - 8·m

At the x-intercept, y = 0, therefore;

(0 - 7) = m·(0 - 8) = -8·m

At the x-intercept, -7 = m·x - 8·m

8·m - 7 = m·x

[tex]\displaystyle x = \mathbf{8 - \frac{7}{m}}[/tex]

Therefore;

[tex]\displaystyle A = 0.5 \times \left(7 - 8 \cdot m\right) \times \left(8 - \frac{7}{m} \right) = \mathbf{\frac{-32 \cdot m^2 +56 \cdot m - 24.5}{m}}[/tex]

When the area is minimal, we have;

[tex]\displaystyle \frac{dA}{dm} =0 = \frac{d}{dm} \left(\frac{-32 \cdot m^2 +56 \cdot m - 24.5}{m}\right) = \mathbf{-\frac{32 \cdot m^2 - 24.5}{m^2}}[/tex]

m² × 0 = 24.5 - 32·m²

[tex]\displaystyle m^2 = \frac{24.5}{32} = \frac{49}{64}[/tex]

[tex]\displaystyle m = \sqrt{\frac{49}{64}} = \frac{7}{8}[/tex]

[tex]\displaystyle m = \pm \frac{7}{8}[/tex]

The equation of the line when [tex]\displaystyle m = + \frac{7}{8}[/tex] is therefore;

(y - 7) = m·(x - 8)

[tex]\displaystyle (y - 7) = \mathbf{\frac{7}{8} \cdot (x - 8)}[/tex]

[tex]\displaystyle (y - 7) = \frac{7}{8} \cdot (x - 8) = \frac{7}{8} \cdot x - \frac{7}{8} \times 8 = \frac{7}{8} \cdot x - 7[/tex]

[tex]\displaystyle y = \frac{7}{8} \cdot x - 7 + 7 = \frac{7}{8} \cdot x[/tex]

[tex]\displaystyle y = \mathbf{\frac{7}{8} \cdot x}[/tex]

The x and y intercept of the above line are 0

When [tex]\displaystyle m = - \frac{7}{8}[/tex], we have;

[tex]\displaystyle (y - 7) = -\frac{7}{8} \cdot (x - 8) = -\frac{7}{8} \cdot x + \frac{7}{8} \times 8 = -\frac{7}{8} \cdot x + 7[/tex]

Which gives;

[tex]\displaystyle y = \frac{7}{8} \cdot x + 7 + 7 = \frac{7}{8} \cdot x + 14[/tex]

[tex]\mathrm{The \ equation \ of \ the \ line \ is, }\displaystyle \ y = \mathbf{14 - \frac{7}{8} \cdot x}[/tex]

The equation of the line through P = (8, 7) such that the triangle bounded by the line and the axes in the first quadrant has minimal area is therefore;

[tex]\displaystyle \ \underline{ y = 14 - \frac{7}{8} \cdot x}[/tex]

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Answers

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Step-by-step explanation:

Answer:

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Answers

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Step-by-step explanation:

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Answers

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Answers

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0


1


5


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Answers

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Answers

9514 1404 393

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  1 solution (x = -36 2/3)

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Answers

Answer:

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X =
=
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Answers

Answer:

X = 48 inches  for the shortest side

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9s = first side

10s = second side

4s = third side

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 276/23 = s

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10s = second side;  10(12) = 120

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Which expression is the factored form of−4.5n+3?


−1.5(3n+2)

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Answers

Answer:

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