Find the difference.
0 - (-5) =

Answers

Answer 1

Answer:

= 5

Step-by-step explanation:

the two negatives cancel out to create a positive so the equation would be

0 + 5 =

= 5

Answer 2

Answer:

5

Step-by-step explanation:

[tex]0-(-5)[/tex]

When subtracting a negative number, the two negatives cancel out and subtraction turns to addition.

[tex]0+5[/tex]

[tex]5[/tex]

I hope this helps!


Related Questions

Describe how the graph of y= x2 can be transformed to the graph of the given equation.
y = (x + 14)^2 (5 points)

Shift the graph of y = x2 down 14 units.
Shift the graph of y = x2 right 14 units.
Shift the graph of y = x2 left 14 units.
Shift the graph of y = x2 up 14 units.

Answers

Step-by-step explanation:

For y = x², y = 0 when x = 0.

For y = (x + 14)², y = 0 when x = -14.

Notice that the zero of the function has went from 0 to -14, or 14 units to the left.

The answer is "Shift the graph of y = x² left 14 units.".

Answer:

We conclude that the graph y = x² can be transformed into the graph of the given equation y = (x + 14)² by shifting the graph of y = x² left 14 units.

Step-by-step explanation:

Please check the attached graph.

The blue graph is representing the graph of y = x². The red graph is representing the graph of y = (x + 14)².

If we carefully analyze the given graph which is attached below, it is clear that the given graph y = (x + 14)² is the transformed image of form f(x+b) of parent graph y = x².

In this graph, the function y = x² has been moved over 14 units to the left.

In other words,

f(x+2) = f(x+14)² means the function f(x) is shifted 14 units to the left.

Therefore, the graph y = x² can be transformed into the graph of the given equation y = (x + 14)² by shifting the graph of y = x² left 14 units.

Anita received 3 postcards of zebras and 2 postcards of monkeys each month for 3 months. How many postcards is that?​

Answers

Answer:

8 post cards

Step-by-step explanation:

Eight

Answer:

15

Step-by-step explanation:

3+2=5

5x3=15

what is the domain and range

Answers

Answer:

domain: [0, positive infinity)

range: (negative infinity, positive infinity)

PLEASE HELP QUICKLYYY!!!!


A triangle and a vertical line are shown. If the triangle is revolved about the vertical line, what is the resulting object? a right triangle with one side against a vertical line solid cylinder hollow cylinder hollow cone with truncated top solid cone

Answers

Answer:

a solid cone

Step-by-step explanation:

A solid revolution is a general method that is used to revolve a given figure about its reference plane and produce the required solid. This process produces a three dimensional shape from a two dimensional figure.

A triangle in placed vertically on a straight vertical line. When the triangle is revolved about the vertical line a solid cone figure is obtained. The triangle generates a cone shape figure.

Which equation could have the graph shown below? y = (x – 4)(x – 1)(2 + x)(3 + x) y = (x – 4)(1 – x)(2 + x)(3 + x) y = (x + 4)(x + 1)(2 – x)(3 – x) y = (x + 4)(x + 1)(2 – x)(x – 3)

Answers

Answer: (x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2

Step-by-step explanation: Step by Step Solution

More Icon

STEP

1

:

Equation at the end of step 1

((((((((((((((x-4)•(x-1)•(x+2))•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

2

:

Equation at the end of step 2

(((((((((((((x-4)•(x-1)•(x+2)•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

3

:

Equation at the end of step 3

((((((((((((x-4)•(x-1)•(x+2)•(x+3)•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

4

:

Multiplying Exponential Expressions:

4.1 Multiply (x-4) by (x-4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-4) and the exponents are :

1 , as (x-4) is the same number as (x-4)1

and 1 , as (x-4) is the same number as (x-4)1

The product is therefore, (x-4)(1+1) = (x-4)2

Equation at the end of step

4

:

(((((((((((x-4)2•(x-1)•(x+2)•(x+3)•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

5

:

5.1 Rewrite (1-x) as (-1) • (x-1)

Multiplying Exponential Expressions:

5.2 Multiply (x-1) by (x-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-1) and the exponents are :

1 , as (x-1) is the same number as (x-1)1

and 1 , as (x-1) is the same number as (x-1)1

The product is therefore, (x-1)(1+1) = (x-1)2

STEP

7

:

Pulling out like terms

7.1 Pull out like factors :

-x - 2 = -1 • (x + 2)

Multiplying Exponential Expressions:

7.2 Multiply (x + 2) by (x + 2)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+2) and the exponents are :

1 , as (x+2) is the same number as (x+2)1

and 1 , as (x+2) is the same number as (x+2)1

The product is therefore, (x+2)(1+1) = (x+2)2

STEP

9

:

Pulling out like terms

9.1 Pull out like factors :

-x - 3 = -1 • (x + 3)

Multiplying Exponential Expressions:

9.2 Multiply (x + 3) by (x + 3)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+3) and the exponents are :

1 , as (x+3) is the same number as (x+3)1

and 1 , as (x+3) is the same number as (x+3)1

The product is therefore, (x+3)(1+1) = (x+3)

((((((((x-4)2•(x-1)2•(x+2)2•-1•(x+3)2•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

10

:

Equation at the end of step 10

(((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

11

:

STEP

12

:

Pulling out like terms

12.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Equation at the end of step

12

:

((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1)•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

13

:

STEP

14

:

Pulling out like terms

14.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Equation at the end of step

14

STEP

15

STEP

16

:

Pulling out like terms

16.1 Pull out like factors :

-x - 4 = -1 •

Equation at the end of step

16

:

STEP

17

:

STEP

18

:

Pulling out like terms

18.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Multiplying Exponential Expressions:

18.2 Multiply (x + 4) by (x + 4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+4) and the exponents are :

1 , as (x+4) is the same number as (x+4)1

and 1 , as (x+4) is the same number as (x+4)1

The product is therefore, (x+4)(1+1) = (x+4)2

Equation at the end of step

18

:

(((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(-x-1)•(2-x)•(3-x)•(x+1))•(2-x))•(x-3)

STEP

19

:

STEP

20

:

Pulling out like terms

20.1 Pull out like factors :

-x - 1 = -1 • (x + 1)

Multiplying Exponential Expressions:

20.2 Multiply (x + 1) by (x + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+1) and the exponents are :

1 , as (x+1) is the same number as (x+1)1

and 1 , as (x+1) is the same number as (x+1)1

The product is therefore, (x+1)(1+1) = (x+1)2

Equation at the end of step

20

:

((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)•(3-x)•(2-x))•(x-3)

STEP

21

:

21.1 Rewrite (2-x) as (-1) • (x-2)

Multiplying Exponential Expressions:

21.2 Multiply (x-2) by (x-2)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-2) and the exponents are :

1 , as (x-2) is the same number as (x-2)1

and 1 , as (x-2) is the same number as (x-2)1

The product is therefore, (x-2)(1+1) = (x-2)2

22.1 Multiply (x-3) by (x-3)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-3) and the exponents are :

1 , as (x-3) is the same number as (x-3)1

and 1 , as (x-3) is the same number as (x-3)1

The product is therefore, (x-3)(1+1) = (x-3)2

Final result :

(x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2

SOME PLEASE HELP PLEASE

Answers

Answer:

i think y= 6x+4

Step-by-step explanation:

Prove ΔABC ∼ ΔGEF. (10 points)


Answers

Answer:

Step-by-step explanation:

If we take the below diagram for the given triangles, then ∠B=∠E and ∠A=∠G if AB=GE or if BC=EF, then corresponding angles will be equal.

Therefore, if we rotate the diagram, then also the angles will remain the same.

1. < DCE=< DEC in the picture

2. ⇒⇒ the triangles ABC and EFG have 2 angles equals ⇒ ABC~ EFG

5. ⇒ < ABC=6. < GFE = < BCA= < ECD =
⇒ the triangles ABC and EFG have 2 angles equals ⇒ ABC~ EFG

is this right or no?

Answers

Yes it is. You can get that answer by acting like there are 12 oranges.
1/3 of 12= 4
5/12 of 12= 5
1/4 of 12= 3

and y
together
in 10 days
15 days. In how
alone
can do a piece
of wool
x alone
do it
mony
would y
can finish
work?
the​

Answers

Answer:

what its hard tho can you scan tha problem

Riley buys ice cream and oranges at the store.
She pays a total of $37.15.
She pays a total of $3.62 for the ice cream.
She buys 7 bags of oranges that each cost the same amount.

How much does each bag of oranges cost?

Answers

Answer:

4.79 dollars.

Step-by-step explanation:

7x + 3.62 = 37.15

7x= 37.15-3.62

7x=33.53

x= 33.53/7=4.79 dollars.

Two cards are dealt at random from a standard deck of 52 cards. What is the probability that the first card is a King and the second card is a $\heartsuit$

Answers

Answer:

1 / 51

Step-by-step explanation:

Given that :

Number of cards in a deck = 52

Number of heart suit = 13

Number of kings = 4

Recall:

Probability = (required outcome / Total possible outcomes)

P(first card is king) = 4/52 = 1/13

P(second card is heart) = 13/51

Hence,

P(first card is king) * P(second card is heart)

(1/ 13) * (13/51) = 13 / 663 = 1/ 51

Answer:

1/53

Step-by-step explanation:

So, you have 4 kings in a deck. You have a 4/52 chance in the first one which simplifies to 1/13. There are 13 hearts in a deck. 13/53 * 1/13 = 1/53. Sorry if I got this one wrong.

what is 25% of 50 please

Answers

answer is idk because it is a half

what is 8 ÷ 2(2 + 2) = i have been stuck on this problem for 1 year now Halp !!!
will give brainliest for the right answer thats funny

Answers

Answer:

ok after reviewing this answer for the past 8 years i just figured it out

1(6)

Step-by-step explanation:

i know this may come as a huge shock however this is actually true. It's been a long emotionally journey finding this answer but please bear with me, as im crying really hard right now since I cannot believe I actually solved it. As unbelievable as it sounds I will not be providing work as i think my mind is too big and swag, but please believe me on this because im  literally the kid genius

edit: ok just ran this through my totally not paid for calculator with my mcdonalds money but it is actually 16 i am literally deleteing   my account this is so embarassing for me

Answer:

8÷2= 4 and (2+2)= 4 .....

1 divided by 20 equalyufghytfjbhbh

Answers

Answer:

1 divided by 20 is equal to 0.05.

Step-by-step explanation:

In this problem, we need to find 1 divided by 20 is equal to what.

1 should be in the numerator and 20 should be in the denominator.

[tex]\dfrac{1}{20}=\dfrac{1}{2}\times \dfrac{1}{10}\\\\=0.5\times 0.1\\\\=0.05[/tex]

Hence, 1 divided by 20 is equal to 0.05.

Someone can help me with this assignment about The Pythagorean Theorem.
I have to solve it for the missing side length (s).

Answers

Answer:

√45^2-27^2

which is 36

hope it helps u dear

Mark me BRAINLIEST ❣️❤️❤️❣️❣️

find the locus of a point which moves such that its distance from (1,2) is always 5 units​

Answers

Answer:

TbH my brain is to tired lol

Step-by-step explanation:

sorry

JjjjjjsjsjjzjkKJJJJJ

Lynn, Jude, and Anne were given the function f (x) = -3x^2 + 12 and they were asked to find (2). Lynn's answer was 48, Jude's answer v correct? Show Your Work​

Answers

Answer:

(2) is equal to 48 because you substitute x for 2 in the equation.  F(2)= -3(2)^2 +12= -3 times 2 is -6 then you square it to get 36 and add 12 to get 48

Step-by-step explanation:

Evaluate the expression
-5+(-13) + 10 - 10 =

Answers

-5 - 13 + 10 - 10 =
the tens cancel out
-5 - 13 = -18

Answer:
-18

Answer:

-18

Step-by-step explanation:

A add and a minus makes a minus so you do -5  - 13 = -18

-18 + 10 = -8    -8 - 10 = -18   You do not have to write this out as positive 10 - 10 is equal to 0

answer plz ill mark you brainliest bro
ALGEBRA-
Which expression is equivalent to (3x−2)(x+6) ?

4x + 4
3x² + 20x + 12
3x2+16x−12
4x² + 12x + 4

Answers

Answer:

1= false

2= one sloution

3=All real numbers are solutions.

4=No real solutions.

Step-by-step explanation:

hope this helps

3x2+16x-12
Hope this helps! Mark as brainliest please!!

Hamza decides to increase the prices of all items in his shop by 10%, Work out the new price of in item normally priced at £210

Answers

100% = 210
10% = 21
New price = 110%
110% = 231

£231

Where is the point (-8,0) located on the coordinate plane?

1. On the X-axis
2. In quadrant ll
3. In quadrant lll
4. On the y-axis​

Answers

Answer:

On the X-asis

Tell me if I am wrong. :) Hope it helps though.

Step-by-step explanation:

Answer:

in quadrant ii (-8,0) located

how much is 21 hundreds

Answers

21 hundreds would be 2100

Answer:

21,000

Step-by-step explanation:

does anyone minding helping me with exterior angles ? due in 2 days

Answers

Answer:

x=25

Step-by-step explanation:

(x+40)+(3x+10)=6x

4x+50=6x

50=2x

25=x

Answer:

see explanation

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ CBD is an exterior angle of the triangle, then

6x = x + 40 + 3x + 10, that is

6x = 4x + 50 ( subtract 4x from both sides )

2x = 50 ( divide both sides by 2 )

x = 25

Thus

∠ CBD = 6x = 6 × 25 = 150°

∠ CBA and ∠ CBD are adjacent angles and supplementary, sum to 180°, then

150° + ∠ CBA = 180° ( subtract 150° from both sides )

∠ CBA = 30°

2200 people attend a football game. If 3/4 of those who came were not season ticket holders, how many were

Answers

3/4 = 0.75

2200 x 0.75 = 1650

2200 - 1650 = 550.

550 were season ticket holders

Plssssss I neeed help I will mark brainlist

Answers

Answer:

so i think it is rst on the right

Dianna made several loaves of bread yesterday. Each loaf required 2 and two-thirds cups of flour. All together, she used 13 and one-third cups of flour. How many loaves did Dianna make?Which is the best estimate of 11 and one-fifth divided by 2 and three-fourths?

Answers

Answer:

5 loaves and 4

Step-by-step explanation:

Kara recorded the ages of the people in her book club in this table.

29 34 31 39 43
28 37 35 33 60
26 33 38 36 41
If the outlier is not included, what will happen to the range and the IQR of this data set?

A.
The range will stay the same, but the IQR will change.
B.
The range and the IQR will both stay the same.
C.
The IQR will stay the same, but the range will change.
D.
The range and the IQR will both change.

Answers

Answer:

D.

The range and the IQR will both change.

Step-by-step explanation:

PLATO

The correct answer is C. The IQR will stay the same, but the range will change.

How to calculate the IQR?

To determine what will happen to the range and the IQR of this data set if the outlier is not included, we first need to identify the outlier.

One way to identify an outlier is to use the 1.5 x IQR rule. According to this rule, any data point that is more than 1.5 times the IQR away from the first or third quartile is considered an outlier.

Using this rule, we can calculate the IQR of the data set:

Arrange the data set in order from smallest to largest:

26 28 29 31 33 33 34 35 36 37 38 39 41 43 60

Find the median, Q₂, of the data set. In this case, Q₂ = 36.

Divide the data set into two halves: the lower half, which includes all values less than or equal to Q₂, and the upper half, which includes all values greater than or equal to Q₂:

Lower half: 26 28 29 31 33 33 34 35

Upper half: 36 37 38 39 41 43 60

Find the median, Q₁, of the lower half. In this case, Q₁= 30.

Find the median, Q₃, of the upper half. In this case, Q₃ = 41.

Calculate the IQR as the difference between Q₃ and Q₁: IQR = Q₃ - Q₁ = 11.

Multiply the IQR by 1.5: 1.5 x 11 = 16.5.

Add 16.5 to Q₃ and subtract 16.5 from Q₁ to get the upper and lower bounds for outliers:

Upper bound: Q₃ + 16.5 = 57.5

Lower bound: Q₁ - 16.5 = 13.5

Any value outside this range is considered an outlier.

In this data set, the value 60 is greater than the upper bound of 57.5, so it is an outlier.

Therefore, the correct answer is C. The IQR will stay the same, but the range will change.

To know more about IQR follow

https://brainly.com/question/31257728

#SPJ3

Guy spent £11.40 buying ingredients to make cupcakes. He sold all the cakes for a total of £39.90. What percentage profit did Gary make?

Answers

Answer:

sup

Step-by-step explanation:

What is the ratio of red circles to blue circles

Answers

Answer:

1:1 or one red circle to one blue circle

There is one red and one blue circle

I need help ASAP!!!!!!!!!!!!!!!!

Answers

Answer: 5/13

Step-by-step explanation: Cosine equals adjacent over hypotenuse so adjacent is the side closest to the angle neglecting the hypotenuse of course because that's always the longest side. So Cos=A/H or 5/13

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