Find the altitude of the triangle in the figure below. Answer in units of m.

The heigth of the cliff is 63.504 m.

Height is the vertical distance  between two points.

To calculate the height of the cliff, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the heigth of the cliff is 63.504 m.

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Explanation:

probably luck or the right material's

The distance travelled by Ann before she begins to slow down is 11.65 m

First, we shall enlighten ourselves on what speed is. This is given below.

Speed is the distance an object travelled per unit time. It can be expressed as:

Speed = distance / time

Finally, we can obtain the distance Ann travelled as illustrated below.

From the question given above, the following data were obtained:

Speed = distance / time

15.56 = distance / 0.749

Cross multiply

Distance = 15.56 × 0.749

Distance = 11.65 m

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It will take the fugitive 4.83 s to catch the empty box car

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The time taken for the fugitive to catch the car if he maintains his maximum speed can be obtained as follow:

a = (v – u) / t

Thus,

t = (v – u) / a

t = (5.8 – 0) / 1.2

t = 5.8 / 1.2

t = 4.83 s

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The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash, therefore the correct answer is option A.

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem, a test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction of the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.

Thus, the initial acceleration vector will point in the direction of the wall and be smaller than the crash's acceleration vector, therefore the correct answer is option A.

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Answer:

13.33 mA s

Explanation:

400 mA * 1/30 s = 13.33 mA s

The speed over the ground is 0 m/s.

The speed of an object or body is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

As it is given that the mosquito is flying at 2 m/s relatives to the air caught in a 2 m/s right angle crosswind.

As we know that speed over the ground is the difference between the flight speed and resistance speed.

So, the general equation for the speed over the ground is :

v = Flight Speed of the mosquito - Resistance Speed of the crosswind

This implies, [tex]v= 2 {~}m / s - 2{~} m / s[/tex]

[tex]v = 0 {~}m / s[/tex]

Hence, the speed over the ground is 0 m/s.

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The angular momentum can be indicated by formula mvr. The correct option is A.

The property of any rotating object given by moment of inertia times angular velocity is defined as angular momentum.

It is the property of a rotating body determined by the product of the rotating object's moment of inertia and angular velocity.

The rotational equivalent of linear momentum is the angular momentum formula. Both concepts are concerned with the rate at which anything moves.

It can be represented by symbol L.

L = mvr.

Thus, the correct option is A.

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Answer:

35

Explanation:

A bowling ball results in kinetic friction compared to a sliding bowling ball.

According to Conservation of momentum, if a bowling ball hits some pins, the momentum that lost by the bowling ball is known to be equal to the momentum obtained by the pins.

The friction that is used in bowling is kinetic friction because the more oil that is placed down, the lower the friction that is found between the ball and that of the lane surface. The  little friction, the stronger it is for the bowler to be able to send the ball in a curved path and thus the formula to find the kinetic friction is know to be : µk=F k/mg.

Therefore, A bowling ball results in kinetic friction compared to a sliding bowling ball.

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The time of flight of the ball is 17.12 seconds.

The horizontal distance or range of the ball is 354.8 m.

The time of flight of the ball is calculated as follows;

T = (2u sinθ)/g

where;

T = (2 x 25 sin34) / (¹/₆ x 9.8)

T = 17.12 s

The range of the golf ball is calculated as follows;

R = Uxt

R = (U cosθ)t

R = (25 cos34) x 17.12

R = 354.8 m

Thus, the time of flight of the ball is 17.12 seconds.

The horizontal distance or range of the ball is 354.8 m.

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Answer: 1 > 3 > 2

Explanation: The range will increase with the velocity. If they are all launched at the same time the ones that are launched the hardest or with the most velocity will go the furthest horizontally. But because they are all launched from the same height and the force of gravity on all three projectiles is constant (the same for all three) they will all hit the ground at the same time but different distances from the starting point.

The space cruiser is 11070000 m far from the planet's surface

The following data were obtained from the question:

We can obtain the distance of the space cruiser from the planet's surface as follow:

s = ut + ½gt²

s = (0 × 600) + (½ × 61.5 × 600²)

s = 0 + (½ × 61.5 × 360000)

s = 0 + 11070000

s = 11070000 m

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First, see that in the time interval 3.44 to 9.49, the average velocity is [tex]2.9\text{m} / (9.49\text{s} - 3.44\text{s})=2.9\text{m}/6.05\text{s} \approx 0.479\text{m/s}[/tex]. So, as we have uniform acceleration, the velocity must be linearly increasing over this entire interval, so for the average to be 0.479 m/s over this interval, the velocity must be 0.479 m/s in the exact middle of this interval, or at 5.465s.

We now note that the object starts from rest, which means that at 0s, the velocity is 0 m/s.  So, in 5.465 seconds, the velocity increases by 0.479 m/s.  We again have that the object undergoes uniform acceleration, meaning that the acceleration over this interval is a constant [tex]\frac{0.479\text{m/s}}{5.465\text{s}} \approx 0.0876 \text{m/s}^2[/tex].

Finally, note again that as we are looking at uniform acceleration, by the same principle at the beginning, the average velocity of the object during the time interval from 18.6s to 22.92s is the same as the velocity at the exact middle of this interval, or at 20.76s.  We have that acceleration is constant and 0.0876 m/s^2, and initial velocity is 0 at 0s. So, in 20.76 seconds, the object will have accelerated [tex]0.0876\text{m/s}^2 \cdot 20.76\text{s} \approx 1.82 \text{m/s}[/tex].

So, average velocity will be 1.82 m/s over the time interval 18.6s to 22.92s.

The attractive force of Earth on the moon will be said to be double when there is a doubling of the mass of the moon.

Since the moon has an attracting force, it is one that will remain the same on Earth. In gravitational forces, the two concerned objects always feel the same force.

The explanation of how this would affect the gravity between earth and the moon is that this can result to the earth tilt a little bit harder to change, which could imply that there will be a more stable climate and  ice ages may not occur as often.

Therefore, The attractive force of Earth on the moon will be said to be double when there is a doubling of the mass of the moon. Since the moon has an attracting force, it is one that will remain the same on Earth. In gravitational forces, the two concerned objects always feel the same force.

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The magnitude of the change in velocity is determined as 408.94 km/h.

The change in direction of the velocity is 64.4⁰ north of west.

The magnitude of the average acceleration during the trip is 0.0105 m/s².

The magnitude of change in velocity is the resultant velocity of the plane.

v² = a² + b² - 2ab cosθ

where;

v² = (192²) + (250²) - 2(192 x 250) cos(135)

v² = 167,236

v = √167,236

v = 408.94 km/h

vyi = 192 km/h

vy2 = 250 x sin(45) = 176.77 km/h

vy(total) = 192 km/h + 176.77 km/h = 368.77 km/h

vxi = 0

vx2 = - 250 km/h x cos(45) = -176.77 km/h

θ = arc tan (Vy/Vx)

θ = arc tan(368.77 / -176.77)

θ = -64.4 ⁰

θ = 64.4⁰ north of west.

a = v/t

v = 408.94 km/h = 113.6 m/s

h = 3 h = 10,800 seconds

a = (113.6 m/s) / ( 10,800 s)

a = 0.0105 m/s²

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You throw a rock from the upper edge of a 75.0 -m vertical dam with a speed of 25.0 m/s at 65.0∘ above the horizon.

The horizon is the line that, when seen from a position on or near the surface of a celestial body, appears to separate the surface from the sky of that body. All viewing directions are split according to whether it crosses the surface of the relevant body or not.

Since the true horizon is an imaginary line, it can only be seen with any degree of accuracy when it is situated along a generally flat surface, such as the oceans of the Earth. On Earth, the geography may also cause biological objects like trees and/or man-made objects like buildings to obstruct this line in some locations. The location where these obstructions overlap the sky is known as the visible horizon.

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The car travels 25 meters before coming to rest and will hit the deer.

Given in the Question,

Initial speed = u = 15 m/s

Deceleration = a = 4.5 m/s²

According to the question, if the car stops before traveling 20m, it will avoid hitting the deer. So, we need to find the stopping distance for the car.

Deceleration is negative acceleration, so the sign of acceleration is will be -.

Also, the car comes to rest after applying the brakes. Therefore the final speed of the car will be zero.

Final speed = v = 0 m/s

Using the Third equation of motion,

v² - u² = 2as

Put in the values, we get

(0)² - (15)² = 2(-4.5)s

-2×4.5 × s = - 15× 15

s = 225/9

s = 25 m

So the car will come to rest after traveling 25 meters. But the Deer is present at 20 meters; therefore the car will hit the deer.

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Link walks 5 miles east, then 7 miles north then 2 miles south

If you draw a simple diagram you’ll see that your displacement from the start is 5 miles East and 7 miles North and then 2 miles south

These distances are the sides of a right-angled triangle. The displacement you are looking for is the hypotenuse of the triangle. Use the Pythagorean theorem to calculate it.

Displacement

= √ (5+2)^2 + 7^2)

= 9.899 miles

Distance

= 5+7+2

= 14 miles

Time to complete his whole journey = 4 hours

Average Speed= Distance travelled / Time

= 14÷4

= 3.5 miles/hour

Average velocity= Displacement / Time

= 9.899÷4

= 2.47475 miles/hour

The distance is 14 miles and the displacement is 9.899 miles, the Average Speed is 3.5 miles/hour and the Average Velocity is 2.47475 miles/hour

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Answer:

A battery

Explanation:

A battery is the biggest conductor. I think.

If you were standing still on the equator of Earth you would move at nearly 1,000 miles/hour which is approximately 1,600 km/hr.

What is speed?

Speed is measured as the ratio of distance to the time in which the distance was covered.

The Earth is round and spins once every 24 hours. This spinning of the earth causes the daily motion which we feel here. If you were standing still on the equator of Earth you would move at nearly 1,600 km/hr.

Speed is a scalar quantity as it has only direction and no magnitude.

Speed is defined mathematically as distance/ time.

speed = distance/time expressed in m/s.

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Alexus was resting on the couch but then decided she needed some food. She ran at up to 15m/s, accelerating at 3m/s² the whole time, until she got to the fridge . The fridge will be 37.5 m far away from the couch

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Equation of kinematics  are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

given

final velocity = 15m/s

initial velocity = 0

a = 3m/s²

s = ?

a = acceleration = final - initial / time

3 = 15 - 0 / time

time = 15 /3 = 5 seconds

[tex]v^{2}[/tex] - [tex]u^{2}[/tex] = 2as

[tex]15^{2}[/tex] - 0 = 2 * 3 * s

s = 225 /6

  = 37.5 m

The fridge will be 37.5 m away from the couch

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Answer: I believe that the answer to your question is "Inertia", or A

Explanation:

The electric force on one of the masses is 0.6 N.

The acceleration of the mass is 0.35 m/s².

The electric force between the masses is calculated as follows;

F = kq²/r²

where;

F = (9 x 10⁹ x (9.8 x 10⁻⁶)²)/(1.2²)

F = 0.6 N

The acceleration of the mass is calculated as follows;

F = ma

a = F/m

a = (0.6 N) / (1.7 kg)

a = 0.35 m/s²

Thus, the electric force on one of the masses is 0.6 N.

The acceleration of the mass is 0.35 m/s².

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The correct answer is :

Here 100 N force is applied to make the box move with constant velocity from rest. That means 100 N force is applied to overcome the limiting  static friction and as soon as 100 N force is applied it starts moving.

Now,

Constant velocity means acceleration = 0

Net force acting on the box =mass × accelaration = mass × 0 = 0

Conceptually it is zero as it is balanced by kinetic friction which has equal value that of applied force. Because net force =Applied force - friction force and hence here friction force =applied force.

If there was any accelaration then there would exist a net force and then frictional force and applied force will be the same.  

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Answer:

100

Explanation:

3-2=1

100/1=100