Find m P. Quadrilateral

Total cost of gazebo's floor is $3556.8 when the gazebo has 12 feet on each side. 10.4 feet tall is the apothem.

Given that,

In Clark's backyard, a sizable gazebo is being constructed. It has a typical hexagonal form. The gazebo has 12 feet on each side. 10.4 feet tall is the apothem. He must get stones for the flooring. The price of a particular kind of interlocking stone is $9.50 per square foot.

We have to identify the gazebo's floor's cost.

We know that,

The distance from the center of the regular polygon to the mid point of the side. Here, AB is the chord and AM =BM. O is the center of the circumcircle.

Segments joining the center of a circle to the midpoint of the chord is perpendicular to the chord.

So, OM ⊥AB

In ΔOAB,

AB is the base and OM is the height.

AB = 12 feet

OM = 10.4 feet.

The area of the triangle OAB =1/2×base×height

= 1/2×12×10.4

=62.4 square feet.

A regular hexagon is divided into 6 equilateral triangle having each side  12 feet.

Area of the regular hexagon = 6× area of the one triangle

=6×62.4=374.4 square feet

Cost of inter locking stones = $9.50 per square feet.

Total cost of gazebo's floor = 374.4× 9.50 =$3556.8

Therefore, Total cost of gazebo's floor is $3556.8 when the gazebo has 12 feet on each side. 10.4 feet tall is the apothem.

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Answer:

55

Step-by-step explanation:

IHG = 123

IHS = x + 65

SHG = x + 78

IHG = IHS + SHG

123 = x + 65 + x + 78

123 = 2x + 143

123 - 143 = 2x

-20 = 2x

-10 = x

IHS = x + 65

IHS = - 10 + 65

IHS = 55

Answer:

Isosceles right triangle

Step-by-step explanation:

Step-by-step explanation:

Isosceles Right Triangle

Answer:

- 3/x-1

Step-by-step explanation:

Answer:

[tex]-\frac{3}{x-1}[/tex]

Step-by-step explanation:

Factor the denominator and then combine fractions:

[tex]\frac{3}{(x-1)(x-2)} -\frac{3}{x-2}[/tex]

Find LCM (Least Common Multiple) of denominators:

LCM of (x-1)(x-2) and x-2 is (x-1)(x-2)

Adjust fractions based on LCM:

[tex]\frac{3}{(x-1)(x-2)} -\frac{3(x-1)}{(x-2)(x-1)}[/tex]

Denominators are now equal so you can subtract the fractions:

[tex]\frac{3-3(x-1)}{(x-1)(x-2)}[/tex]

Factor the numerator:

[tex]\frac{3(-x+2)}{(x-1)(x-2)}[/tex]

Cancel:

[tex]-\frac{3}{x-1}[/tex]

Answer:

[tex]Range: \{2,4, 3, -9\}[/tex]

Step-by-step explanation:

Given

The ordered pairs

Required

The range of the function

The range of a function is represented as:

[tex]Range = \{y_1,y_2,y_3,,,y_n\}[/tex]

i.e. we only write out the y values.

So, the given ordered pairs can be represented as

[tex](x,y) = \{(1,2), (-3,4), (3, 3), (0, -9)\}[/tex]

So, we have:

[tex]Range= \{2,4, 3, -9\}[/tex]

Answers:  

Explanation:

The angles TSO and QRP are marked with the same double angle arc markers. This signifies they are congruent or the same measure. For example, they both could be 30 degrees each.

The naming "angle TSO" is the same as saying "angle OST". The order of the letters does not matter as long as point S is in the middle. Similarly, saying "angle QRP" is the same as "angle PRQ".

Answer:

21i² + 45i + 24

Step-by-step explanation:

Answer:

-5-4i

Step-by-step explanation:

Answer:

-39

Step-by-step explanation:

Substitute x by - 3 and y by 4

(-3)^3 - 3 *4 = - 39

Answer:

what's the question?

Step-by-step explanation:

Answer:

Combine like terms for the than you do to other side the multiply last for least you divide both sides

Step-by-step explanation:

Answer:

The answer is B

I hope you got it right!!!

Answer:

3 more students

Step-by-step explanation:

6-3=3

How did you get that?

6 students live 2 miles away, while only 3 students live 3 miles away. To find the difference, subtract the two numbers.

Answer:

C.  SA = (1/2)(5)(12) + (1/2)(5)(12) + (5)(2) + (12)(2) + (13)(2)

Step-by-step explanation:

C.

Answer:

It's C

Explanation:

I got it correct on Edge

-1 on the left x-axis and 4 on the right y-axis.

Start at -2 on the y-axis, move up the y-axis six times, and you should arrive at 4. However, you must identify the first line in order to complete the puzzle.

Start at -2 on the y-axis, count up until it is on a corner of the graph, then move 4 up on the y-axis and once to the right, making the fraction 4/1.

Since you should be at 4, apply the formula rise/run 4/1 to ascend 6 on the y-axis.

step 1: ascend the y-axis six times.

Step 2: Use 4/1 to increase from the y-4 axis's by 1  to the right

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a. The exact volume, in cubic inches, of water flowing out of the pipe every second is 32π cubic inches.

b. The height, in inches, of the water in the tank after 5 minutes is 600 feet.

c. It will take 0.132 minutes to fill 75% of the tank

A cylinder is a three-dimensional solid object with two bases that are identically circular and are connected by a curving surface that is located at a specific height from the center.

Examples of cylinders are toilet paper rolls and cold beverage cans.

The volume of a cylinder is πr²h.

Curved surface area = 2πrh.

Total surface area = 2πr(h + r).

Given, Water flows at 2 feet per second through a pipe with a diameter of 8 inches so it is a cylindrical shape.

Therefore, The exact volume, in cubic inches, of water flowing out of the pipe every second is,

= π(4)²×2.

= 32π cubic inches.

The volume of the cylindrical tank is,

= π(7.5)²×6.

= 337.5π cubic inches.

The height, in inches, of the water in the tank after 5 minutes would be

= (32π×300)/π×16).

= 600 feet.

Now, 75% of 337.5π cubic inches is (0.75×337.5π) = 253.125π cubic inches.

Therefore the time required to fill 75% of the tank is,

= [(253.125π/32π)]/60 minutes.

= 7.91/60 minutes.

= 0.132 minutes.

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Answer:

[tex] \frac{1}{12} [/tex]

Step-by-step explanation:

Coin has 2 outcomes dice has 6 outcomes

A tail is 1/2 and a 3 is 1/6

So a tail and a 3 is 1/2 x 1/6

=1/12

Answer:

The width of the park should be 7.5 feet.

I uploaded the answer to[tex]^{}[/tex] a file hosting. Here's link:

bit.[tex]^{}[/tex]ly/3gVQKw3

Hello there!

Answer:

16

Step-by-step explanation:

[tex] |x| = x \: \: \: if \: \: x \: \geqslant 0 \\ |x| = - x \: \: \: if \: \: \: x \: \leqslant 0[/tex]

-12 < 0 so |-12| = -(-12) = 12

4 > 0 so |4| = 4

|-12| + |4| = 12 + 4 = 16

Answer:

16

Step-by-step explanation:

Hello! This question is looking for the absolute value of integers. The absolute value is the distance the number has from zero. For example, -12 as twelve numbers away from zero, twelve away in the negative direction. The absolute value of -12, then, is just twelve. An easy way to remember this is to take away the negative sign when taking the absolute value, since an absolute value can never be negative. The absolute value sign is represented by a squarish bracket [ and ].

This question says to find the absolute value of each integer and then add the two. First we have [-12]. This is 12 away from zero, and we can take away the - sign from the asked integer and we get 12.

The second integer given is 4, and when we take the absolute value of 4, [+4], we get positive four. This is because four is four spaces away from zero on the number line.

Thus, we have +12 and +4 as are values to add since they are the absolute values and we can form this equation

12+4=16

Thus, the answer is 16.

Hope this helps! Remember the hint, when something has brackets like that or asks for the absolute value, take away a negative sign and make it positive! Have a great day!

Answer: A. U.S. Landmarks to European Landmarks

Maria has 25 U.S. landmark postcards and 20 European landmark postcards. The ratio of U.S. landmarks to European landmarks can be written as 25:20 or as 25/20.

Alternatively, we can express the ratio as a fraction. If we divide the number of U.S. landmark postcards by the total number of U.S. and European landmark postcards, we get 25/(25+20)=25/45

The last way we can express the ratio as a decimal. By dividing the number of U.S. landmark postcards by the total number of U.S. and European landmark postcards, we can find that the ratio of U.S. landmarks to European landmarks is 25/45 =0.555 or 55.5%

Step-by-step explanation:

Answer:

The table with (-3, 2), (0, 2), etc.

Every input has exactly one output.

Hope this helps :)

Answer:

Where's the picture?

Step-by-step explanation:

Can't see it.

Answer:

(0, 12)

Step-by-step explanation:

Answer:

(-2,5), refer to the step-by-step. Feel free to comment any questions you may have!

Step-by-step explanation:

Given the system of equation, [tex]\left \{ {{x+6y=28} \atop {2x-3y=-19}} \right.[/tex], solve by elimination.

[tex]\left \{ {{-2(x+6y=28)} \atop {2x-3y=-19}} \right.[/tex] , multiply the top equation by -2.

We get,  [tex]\left \{ {{-2x-12y=-56} \atop {2x-3y=-19}} \right.[/tex]

[tex]+ {{-2x-12y=-56} \atop {2x-3y=-19}} \right.[/tex], add the equations together.

We get, [tex]-15y=75[/tex], we just eliminated the variable, x, we can now solve this equation for y.

[tex]-15y=-75 = > y=\frac{-75}{-15}[/tex], [tex]y=\frac{75}{15} = > y=5[/tex]

We just found the value y, which is y=5. Now we can take this value and plug it into y for either of the two original equations and solve for x. I will take the top equation...

[tex]x+6y=28 = > x+6(5)=28 = > x+30=28[/tex], subtract the value, 30, from both sides. We get, [tex]x=-2[/tex].

We found the value x, x=-2.

Thus the solution to the given system of equations is (-2,5).

Answer:

(-2, 5)

Step-by-step explanation:

Given linear system of equations:

[tex]\begin{cases}x+6y=28\\2x-3y=-19\end{cases}[/tex]

To solve by the method of elimination, first multiply the first equation by -2:

[tex]\implies -2 (x+6y=28)[/tex]

[tex]\implies -2x-12y=-56[/tex]

Add this to the second equation to eliminate the term in x:

[tex]\begin{array}{lrcrcr}& 2x & - & 3y & = & -19\\+\vphantom{\dfrac12}&(-2x & - & 12y & = & -56\\\cline{2-6}&\vphantom{\dfrac12}&- & 15y & = &-75\end{array}[/tex]

Solve the expression for y:

[tex]\implies -15y=-75[/tex]

[tex]\implies y=5[/tex]

Substitute the found value of y into the expression for x and solve for x:

[tex]\implies x=28-6(5)[/tex]

[tex]\implies x=28-30[/tex]

[tex]\implies x=-2[/tex]

Check by substituting the found values of x and y into both equations.

Equation 1

[tex]\implies -2+6(5)=-2+30=28[/tex]

Equation 2

[tex]\implies 2(-2)-3(5)=-4-15=-19[/tex]

Hence proving that the solution (-2, 5) is true.

Answer:

∠FDA

Step-by-step explanation:

Angle FDA is vertical to angle EDG.

Picture shows vertical angles.

Answer:

x = 71

Step-by-step explanation:

180 - 109 = 71

The formula needed to transform a quadratic polynomial or equation into a perfect square with an additional constant is known as the square formula. It is expressed as, [tex]ax^2 + bx + c = a(x + m)^2 + n[/tex], where, m and n are real numbers.

When a square is complete, a quadratic is written in the shape of a squared bracket, and if necessary, a constant is added. A good example is [tex]x^2 + 6x + 7[/tex] . First, let's note that [tex](x + 3)^2 = (x + 3)(x + 3) = x^2 + 6x + 9. x[/tex]  because this is two more than our expression.

The polynomial equations of degree two in one variable of type[tex]f(x) = ax^2 + bx + c = 0[/tex] and with a, b, c, and R R and a 0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f(x).

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Answer:

2 she draws it they are not real