Find f given that:

f'(x) = √x (2 + 3x), f(1) = 3

The elementary row operation [tex]R_i - R_j[/tex] can be used to manipulate the rows of a matrix and is a fundamental tool in the process of row reduction (also known as Gaussian elimination) for solving systems of linear equations and computing matrix inverses.

A matrix is a rectangular array of numbers or other mathematical objects arranged in rows and columns. Matrices are used in many areas of mathematics, as well as in physics, engineering, and computer science. The dimensions of a matrix are given by the number of rows and columns it contains. For example, a matrix with three rows and two columns is called a 3x2 matrix.

The entries of a matrix can be any mathematical object, but they are usually real or complex numbers. Matrices can be added and multiplied, which leads to many useful operations and applications. Matrix addition and multiplication are defined element-wise, meaning that the corresponding entries of two matrices are added or multiplied. Matrices can also be used to represent transformations of geometric objects, such as rotations, translations, and scaling.

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Complete Question:

Xavier performs the elementary row operation represented by Ri - R, on matrix A.

The gradient vector at point P and the unit vector in the direction of u, the rate of change off(x, y, z) at P in the direction of the vector  u = 〈0, 12,-2, -2〉is Duf(2,-2,-2) = (-2)(0) + (-2)(0) + (-2)(32) = -64.

The gradient of the function f(x, y, z) = x2yz-xyz is a vector and can be found using partial derivatives. The gradient is ▽f(x, y, z) = (2xyz-yz^3, x^2-xyz^2, x^2y-3xyz).

To evaluate the gradient at the point P(2, -2,-2), we substitute these values into the gradient vector. So, Vf(2,-2,-2) = (0,0,32).

The rate of change off f(x, y, z) at P in the direction of the vector u = 〈0, 12,-2, -2〉 can be found by taking the dot product of the gradient vector at point P and the unit vector in the direction of u. So, Duf(2,-2,-2) = (-2)(0) + (-2)(0) + (-2)(32) = -64.

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The equation of the tangent plane for z = x sinpx ` yq at (1, 1) is z - z₀ = y - 1.

The equation of the tangent plane at a point (x₀, y₀, z₀) on a surface z = f(x, y) is given by:

z - z₀ = fx(x₀, y₀)(x - x₀) + fy(x₀, y₀)(y - y₀)

where fx(x₀, y₀) and fy(x₀, y₀) are partial derivatives of f(x, y) evaluated at (x₀, y₀).

In the given problem, z = x sinpx ` yq and (x₀, y₀) = (1, 1). So,

fx(1, 1) = sinp1 ` 1q = 0

fy(1, 1) = xp1 ` yq = 1

Therefore, the equation of the tangent plane at (1, 1) is given by:

z - z₀ = 0(x - 1) + 1(y - 1)

Simplifying,

z - z₀ = y - 1

Therefore, the equation of the tangent plane for z = x sinpx ` yq at (1, 1) is z - z₀ = y - 1.

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The surface area of the complex shape in the image shown is calculated as: 508 ft².

To Find the Surface Area of the Complex Shape, decompose the shape into two rectangular prism.

Rectangular prism 1 dimensions would be:

Length = 12 ft

Width = 5 ft

Height = 7 ft

Surface area (SA) = 2(wl + hl + hw)

= 2·(5·12 + 7·12 + 7·5) = 358 ft²

Rectangular prism 2 dimensions would be:

Length = 12 - 7 = 5 ft

Width = 5 ft

Height = 12 - 7 = 5 ft

Surface area (SA) = 2(wl + hl + hw)

= 2·(5·5 + 5·5 + 5·5) = 150 ft²

Therefore, surface area of the complex shape = 358 + 150 = 508 ft².

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The product of -7 and p³ is determined as - 7p³.

The product of two numbers is obtained by multiplying the two numbers.

In other words, product of numbers implies the multiplicative result of the numbers.

The product of -7 and p³ is calculated as follows;.

= -7 x p³

= - 7p³

Thus, the product of -7 and p³ is obtained by multiplying the numbers together, since 7 is the only digit in the expressions, we simply attach 7 as the coefficient of p³.

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The rational number, which expresses a loss of $ 25. 30 is -253/10 = -25.30. So, option(b) is right one. Similarly, The rational number, which expresses a gain of $ 31.10 = 311/10 = 31.10. So, option(a) is right one.

A rational number is a number that can be represented as the quotient or fraction [tex] \frac{p}{q}[/tex] of two numbers, a numerator p and a non-zero denominator q. Loss always implies something lose or decrease and profit represents something gain or increase. So, loss denotes by negative sign and profit by positive sign. We have to determine rational numbers that expresses a loss of $25.30 and a profit of $31.10. First we consider the loss, to express in rational number form, Loss

= -253 ÷ 10

= -25.3

In case of Profit, express in form of rational numbers as profit, 31.10 = 3110 ÷100 = 311 ÷ 10

= 311/10 = 31.1

Hence, the rational number that expresses a loss of $ 25. 30 is -25.3, and the rational number that represents a profit of $ 31.10 is 31.1.

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Complete question :

The rational number that expresses a loss of $25.30 is ?

a) +$25.30

b) -$25.30

c) +$2.53

d) -$2.53.

and the rational number that represents a profit of $31.10 is

a) +$31. 10

b) -$31. 10

c) +$3. 11

d) -$3. 11.

There are exactly 18 red apples and 8 yellow apples in the bag. Then the correct option is C.

Given that:

Ratio, Red : Yellow = 9 : 4

The utilization of two or more additional numbers that compares is known as the ratio.

The ratio can be written as,

Red : Yellow = 9 : 4

Red : Yellow = 9 x 2 : 4 x 2

Red : Yellow = 18 : 8

There are exactly 18 red apples and 8 yellow apples in the bag. Then the correct option is C.

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An exchange rate of $1.25: ¥1 implies that one U.S. dollar (USD) that is equivalent to 1.25 Japanese yen (JPY) or alternatively, 1 JPY is equivalent to 0.8 USD.

The USD is weaker than the JPY, since more USD is needed to purchase one unit of JPY.

So, if someone wanted to exchange USD for JPY.

JPY would receive fewer JPY for their USD than if the exchange rate was lower.

We can say oppositely,

if someone wanted to exchange JPY for USD then for their JPY than if the exchange rate was more. they would receive more USD .

The exchange rate is effected by factors such as interest rates, inflation, political stability, and trade relationships between the two countries.

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The critical numbers in increasing order, we have:

x = 0, 4/9, 4

At x = 0, the function has a local minimum.

At x = 4/9, the function has a local maximum.

At x = 4, the function has neither a local maximum nor minimum.

Here, we have,

To find the critical numbers of the function f(x) = x^8(x - 4)^7:

We need to take the derivative of the function and set it equal to zero.

f'(x) = 8x^7(x - 4)^7 + 7x^8(x - 4)^6(-1)

Setting f'(x) = 0 and solving for x, we get:

x = 0 or x = 4/9

To describe the behavior of f at these critical numbers:

At x = 0, the function has a local minimum.

This is because the derivative changes sign from negative to positive at this point, indicating a change from decreasing to increasing behavior.

At x = 4/9, the function has a local maximum.

This is because the derivative changes sign from positive to negative at this point, indicating a change from increasing to decreasing behavior.

At x = 4, the function has neither a local maximum nor minimum.

This is because the derivative is zero at this point, but does not change sign. Instead, the behavior of the function changes from decreasing to increasing to decreasing again as we move from left to right around

x = 4.

Listing the critical numbers in increasing order, we have:

x = 0, 4/9, 4

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The dimensions of the garden that require the least amount of fencing subject to the given constraint are [tex]$x = 25\sqrt{2}$[/tex] feet and [tex]$y = 50/\sqrt{2}$[/tex]feet.

Let the length of the garden be [tex]$x$[/tex] and the width be [tex]$y$[/tex].

Then we have the equation [tex]$xy = 1250$[/tex] (since the area of the garden is 1250 square feet).

Without loss of generality, let us assume that the side of the garden adjacent to the barn has length [tex]$y$[/tex].

Then the total amount of fencing required is [tex]$y+2x$[/tex].

We want to minimize this quantity subject to the constraint. [tex]$xy = 1250$.[/tex]

From the equation [tex]$xy = 1250$[/tex], we can solve for [tex]$y$[/tex] to get[tex]y = \frac{1250}{x}[/tex]

Substituting this into the expression for the amount of fencing required, we get [tex]$y+2x = \frac{1250}{x} + 2x$[/tex].

To minimize this expression, we can take its derivative with respect to [tex]$x$[/tex] and set it equal to zero:

[tex]\frac{d}{dx}(\frac{1250}{x}+2)=\frac{1250}{x^2}+2=0[/tex].

Solving for[tex]$x$, we get $x = \sqrt{\frac{1250}{2}} = 25\sqrt{2}$[/tex].

Then the corresponding value of [tex]$y$ is $y = \frac{1250}{x} = 50/\sqrt{2}$[/tex].

The dimensions of the garden that require the least amount of fencing subject to the given constraint are [tex]$x = 25\sqrt{2}$[/tex] feet and [tex]$y = 50/\sqrt{2}$[/tex]feet.

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For the expression (1 + b), f(x) = 1 + x and a = 0. Therefore, L(x) = f(0) + f'(0)(x-0) = 1 + x. We have a local maxima at x = -2 and a local minima at x = 2. Since the function y = x^3 - 12x is a cubic function and has no bounds, there are no absolute minima or maxima over the interval (-∞,∞).

The numerical error in the linear approximation is 0 because the linear function is an exact match for the original function.
For y = 3x - x + 6, the differential is dy/dx = 2x + 3. When x = 2 and dx = 0.1, dy/dx = 2(2) + 3 = 7, and the differential is 7(0.1) = 0.7.
To find the local and absolute minima and maxima for y = x - 12x over the interval (-00,00), we take the derivative of y with respect to x: y' = 1 - 12 = -11. The only critical point is at x = 1/12. We evaluate y'' = -11 at x = 1/12 to find that it is a local maximum. There is no absolute maximum or minimum over the given interval.
For the cost function C(x) = x^2 - 1200x + 36,400, we take the derivative with respect to x to find the critical point: C'(x) = 2x - 1200 = 0, which gives x = 600. This is the only critical point. To determine whether it is a minimum or maximum, we evaluate C''(x) = 2 at x = 600. Since C''(600) > 0, we know that x = 600 is a local minimum.
The local and absolute minima and maxima for the function y = x^3 - 12x over the interval (-∞,∞).
1. To find the local minima and maxima, we need to find the critical points of the function. To do this, we first find the first derivative of the function:
y'(x) = d(x^3 - 12x)/dx = 3x^2 - 12
2. Next, set the first derivative equal to zero and solve for x:
3x^2 - 12 = 0
x^2 = 4

x = ±2
3. Now, find the second derivative of the function:
y''(x) = d(3x^2 - 12)/dx = 6x
4. Use the second derivative test to classify the critical points:
y''(-2) = -12 (negative, so it is a local maxima)
y''(2) = 12 (positive, so it is a local minima)
5. Thus, we have a local maxima at x = -2 and a local minima at x = 2. Since the function y = x^3 - 12x is a cubic function and has no bounds, there are no absolute minima or maxima over the interval (-∞,∞).

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The third side must be greater than 0 in order to become a triangle

From the question, we have the following parameters that can be used in our computation:

Side lengths = 4 cm and 4 cm

Express the third side of the triangle with x

Using the triangle inequality theorem, we have the following

4 + x > 4

4 + 4 > x

4 + x > 4

Evaluating the inequalities. we have

x > 0

x < 8

x > 0

This means that x must be greater than 0

Hence, the third side must be greater than 0

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Answer:

The distance between the two points (4,-3) and (7,-7) is 5 units.

Step-by-step explanation:

Matt's coffee shop makes a blend that is a mixture of two types of coffee. Type a coffee costs miguel $4.60 per pound, and type b coffee costs $5.95 per pound. Matt's coffee shop used 50 pounds of Type A coffee in this month's blend.

To answer this question, we can use algebraic equations. Let x be the number of pounds of type A coffee used in the blend. Since there were two times as many pounds of type B coffee used as type A, we know that the number of pounds of type B used is 2x.
The cost of the type A coffee is $4.60 per pound, so the cost of x pounds of type A is 4.6x. Similarly, the cost of the type B coffee is $5.95 per pound, so the cost of 2x pounds of type B is 11.9x.
The total cost of the blend is given as $825, so we can set up the equation:
4.6x + 11.9x = 825
Simplifying this equation, we get:
16.5x = 825
Dividing both sides by 16.5, we get:
x = 50
To help solve this problem, we'll use a system of equations based on the given information. Let's denote the amount of Type A coffee as x pounds and Type B coffee as y pounds.
Since Type B coffee used is two times the amount of Type A coffee, we have the equation:
y = 2x
Now, we know that the total cost of the blend is $825. The cost equation would be:
4.60x + 5.95y = 825
Now we can substitute the first equation into the second equation to solve for x:
4.60x + 5.95(2x) = 825
4.60x + 11.90x = 825
16.50x = 825
Now we divide both sides of the equation by 16.50 to find the value of x:
x = 825 / 16.50
x = 50
So, Matt's coffee shop used 50 pounds of Type A coffee in this month's blend.

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The problem presents a mystery number that is less than 100 and satisfies certain conditions. It is not divisible by 2, 3, 5, or 7, and its digits add up to 7. The goal is to determine what this mystery number is.

Since the number is not divisible by 2, its units digit must be odd. Since it is not divisible by 3 or 5, the sum of its digits cannot be a multiple of 3 or 5, respectively. This leaves a limited number of possibilities for the digits that add up to 7. One possibility is that the number consists of the digits 1 and 6, which add up to 7 and are not divisible by any of the given numbers. By trying out different combinations of these digits, we can determine that the mystery number is 61.

Therefore, the mystery number that satisfies the given conditions is 61. It is not divisible by 2, 3, 5, or 7, and its digits add up to 7. By analyzing the divisibility and sum conditions, we were able to narrow down the possibilities for the digits and arrive at the solution of 61.

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Answer:

x = √(2^2 + 4^2) = √20 = 2√5

y = √(4^2 + 8^2) = √80 = 4√5

√(2√5)^2 + (4√5)^2) = √(20 + 80) = √100 = 10

The side lengths of the largest triangle are 2√5, 4√5, and 10.

You would need 120 square inches of paper to cover an entire prism with an area of 120 square inches.

In Mathematics and Geometry, the surface area of a rectangular prism can be calculated and determined by using this mathematical equation or formula:

SA = 2(WH + LW + LH)

Where:

Based on the information provided about the surface area of this rectangular prism, we can reasonably infer and logically deduce that you would need 120 square inches of paper to cover the entire prism.

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The given statement x y means 8 is congruent to 1 modulo 3, 1 is congruent to 2 modulo 5, and 0 is congruent to 3 modulo 2.

To show that 8 is congruent to 1 modulo 3, we need to find integers x and y such that 5x + 2y = 3k + 1 for some integer k. Let x = 1 and y = 1. Then, 5x + 2y = 5 + 2 = 7, which is not divisible by 3. Let x = 2 and y = 1. Then, 5x + 2y = 10 + 2 = 12 = 3 x 4, which shows that 8 is congruent to 1 modulo 3.

To show that 1 is congruent to 2 modulo 5, we need to find integers x and y such that 5x + 2y = 5k + 2 for some integer k. Let x = 1 and y = 0. Then, 5x + 2y = 5, which is congruent to 0 modulo 5. Let x = 0 and y = 1. Then, 5x + 2y = 2, which is congruent to 2 modulo 5. Hence, 1 is congruent to 2 modulo 5.

To show that 0 is congruent to 3 modulo 2, we need to find integers x and y such that 5x + 2y = 2k + 3 for some integer k. Let x = 0 and y = 1. Then, 5x + 2y = 2, which is not equal to 2k + 3 for any integer k. Let x = 1 and y = -2. Then, 5x + 2y = 5 - 4 = 1, which is not equal to 2k + 3 for any integer k. Let x = 0 and y = 0.

Then, 5x + 2y = 0, which is congruent to 0 modulo 2. Hence, 0 is congruent to 3 modulo 2.

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A. The product of z₁ and z₂ is approximately 71.784 + 5.323i.

B. The quotient of z₁ and z₂ is approximately 7.66(cos 32° + i sin 32°).

a. To find the product of z₁ and z₂, simply multiply their magnitudes and add their angles:

z₁z₂ = 24(cos 36° + i sin 36°) × 3(cos 4° + i sin 4°)

= 72(cos 36°cos 4° - sin 36°sin 4° + i(sin 36°cos 4° + cos 36°sin 4°))

≈ 71.784 + 5.323i

Therefore, the product of z₁ and z₂ is approximately 71.784 + 5.323i.

b. To find the quotient of z₁ and z₂, divide their magnitudes and subtract their angles:

z₁/z₂ = 24(cos 36° + i sin 36°) ÷ 3(cos 4° + i sin 4°)

= 8(cos 36° - 4° + i sin 36° - 4°)

= 7.66(cos 32° + i sin 32°)

Therefore, the quotient of z₁ and z₂ is approximately 7.66(cos 32° + i sin 32°).

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The response of an LTI system to each signal should be simple enough in structure to provide us with a convenient representation of the response of the system to any signal constructed.

as a linear combination of the basic signal, Both of these properties are provided by Fourier analysis, The importance of complex exponentials in the study of the LTI system is that the response of an LTI system to a complex exponential input is the same complex exponential with only a change.

in amplitude; that is Continuous time: st e ® H(s)e, (3.1) Discrete-time: n n z ® H(z)z, (3.2) here the complex amplitude factor H(s) or H(z) will be in general be a function of the complex variable s or z, A signal for which the system output is a (possibly complex) constant times the input is referred.

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To answer the specific question, we need more information about Prob. 4.10, such as the velocity distribution and whether the flow is incompressible.

Once we have this information, we can check continuity and determine if the Navier-Stokes equations are valid. If so, we can determine the pressure distribution by solving the equations for pressure. For the velocity distribution of Prob. 4.10, we need to check continuity to ensure that the flow is physically possible. The continuity equation states that the mass flow rate in a pipe must remain constant, which means that the product of the cross-sectional area and the fluid velocity must remain constant along the pipe. We can check continuity by calculating the mass flow rate at different points in the pipe and comparing them.

To determine if the Navier-Stokes equations are valid, we need to check if the flow is incompressible, which means that the density of the fluid remains constant along the pipe. If the flow is incompressible, the Navier-Stokes equations can be used to describe the fluid motion.

If the flow is incompressible and the Navier-Stokes equations are valid, we can determine the pressure distribution by solving the equations for pressure. We need to know the pressure at a certain point in the pipe to determine the pressure distribution. If we have the pressure at one point, we can use the Bernoulli equation to calculate the pressure at other points along the pipe.

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Answer: he travel 80 minutes in the first 4 minutes the bike was stationary for 2 minutes

From the graph we get,

(a) Mr. Bond travelled 80 meters in the first 4 minutes.

(b) For 2 minutes (From 4th minute to 6th minute) the bike was stationary.

(c) Mr. Bond was travelling at greatest speed from 6th minute to 8th minute.

(d) The greatest speed of the car was 50 meters/min.

In given graph, X axis refers to time in minutes and Y axis refers to the distance along road in meters.

Here (4, 80) is a point on the graph.

So, in 4 minutes Mr. Bond rode 80 meters on road.

From 4 to 6 minutes the distance travelled by bike remain same that 80 meters.

Hence, for (6 - 4) = 2 minutes the bike was stationary.

The speed from 0 minute to 4 minutes was = (80 - 0)/(4 -0) = 80/4 = 20 meters/min.

From 4 minutes to 6 minutes the speed remained same.

From 6 minute to 8 minute the speed was = (180 - 80)/(8 - 6) = 100/2 = 50 meters/min.

From 8 minute to 10 minute the speed was = (220 - 180)/(10 - 8) = 40/2 = 20 meters/min.

Hence the Mr. Bond was travelling at greatest speed at 6 to 8 minutes.

So, the greatest speed of the car = 50 meters/min.

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The final step in creating a frequency distribution is to count the number of observations in each class. After determining the class width and deciding on the number of classes, the next step is to set individual class limits.

This involves establishing the lower and upper limits for each class interval. Once the class limits have been set, the next step is to tally the number of observations that fall within each interval. This process involves counting the number of data points that fall within each class and recording this information in a tally chart. After tallying the number of observations in each class, the final step is to create a frequency table that summarizes this information. The frequency table will typically include the class intervals, the frequency (i.e., the number of observations) in each interval, and the relative frequency (i.e., the proportion of observations) in each interval. By following these steps, you can create a comprehensive frequency distribution that provides insights into the distribution of your data.

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As a student, you can calculate the probability of this event occurring by using the multiplication rule of probability.  The probability of the die landing on the face numbered 1 and the coin landing showing tails is 1/12.

The probability of the die landing on the face numbered 1 is 1/6, as there are six possible outcomes and only one of them is a 1. The probability of the coin landing showing tails is 1/2, as there are two possible outcomes and only one of them is tails.

To find the probability of both events occurring together, you multiply the probability of the die landing on 1 by the probability of the coin landing on tails:

P(die landing on 1 AND coin landing on tails) = P(die landing on 1) x P(coin landing on tails)

= 1/6 x 1/2

= 1/12

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The area of the triangle is 98.48. To solve the given triangles, we need to use trigonometric ratios such as sine, cosine, and tangent. Here are the steps for each triangle:

Triangle 1:
Angle A = 30 degrees
Side B = 7
Angle C = 95 degrees

To find side A, we can use the sine ratio:
sin(A)/7 = sin(95)/B
sin(A) = 7(sin(95)/B)
A = sin^-1(7(sin(95)/B))
A = 12.37 degrees

To find side C, we can use the angle sum property:
A + B + C = 180
30 + 95 + C = 180
C = 55 degrees

Now we can find side A using the sine ratio again:
sin(A)/7 = sin(C)/B
sin(A) = 7(sin(C)/B)
A = sin^-1(7(sin(C)/B))
A = 12.37 degrees

Triangle 2:
Side a = 600
Side b = 10
Angle B = 20 degrees

To find angle A, we can use the law of sines:
sin(A)/a = sin(B)/b
sin(A) = (a/b)sin(B)
A = sin^-1((a/b)sin(B))
A = 86.63 degrees

To find angle C, we can use the angle sum property:
A + B + C = 180
86.63 + 20 + C = 180
C = 73.37 degrees

Now we can find the area of triangle I using the formula:
Area = (1/2)ab(sin(C))
Area = (1/2)(600)(10)(sin(10))
Area = 51.51 square units

Triangle 3:
Side a = 10
Angle A = 20 degrees
Side b = 20

To find angle B, we can use the law of sines:
sin(B)/b = sin(A)/a
sin(B) = (b/a)sin(A)
B = sin^-1((b/a)sin(A))
B = 41.81 degrees

To find angle C, we can use the angle sum property:
A + B + C = 180
20 + 41.81 + C = 180
C = 118.19 degrees

Now we can find the area of the triangle using the formula:
Area = (1/2) ab (sin(C))
Area = (1/2) (10) (sin (118.19))
Area = 98.48 square units

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The probability of rolling a six, and then getting heads upon tossing the coin is 1/12.

The probability of rolling a six on a die is one-sixth, while the likelihood of landing on heads on a coin flip is one-half. To find the probability of both events happening together, we need to multiply the probabilities.

P(rolling a six and getting heads) = P(rolling a six) × P(getting heads)

P(rolling a six and getting heads) = 1/6 × 1/2

P(rolling a six and getting heads) = 1/12

Therefore, the probability of rolling a six and getting heads upon tossing the coin is 1/12.

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The given statement "– = If g(x) = x5, then lim lim g(x) – g(2) = 80. X - 2 x - 2" is False because the limit does not exist.

We have:

g(x) = [tex]x^5[/tex]

g(2) = [tex]2^5[/tex] = 32

We want to evaluate:

lim lim (g(x) - g(2))

x → 2 x - 2

Using algebra, we can rewrite the expression as:

lim lim [tex](x - 2)(x^4 + 2x^3 + 4x^2 + 8x + 16)[/tex]

x → 2 x - 2

We can see that the denominator approaches 0 as x approaches 2, while the numerator approaches a nonzero value. Therefore, the limit does not exist, and the statement is false.

Note that we can also use L'Hôpital's rule to evaluate the limit, which gives the same result:

lim lim (g(x) - g(2))

x → 2 x - 2

= lim lim ([tex]5x^4[/tex])

x → 2 1

= 80

However, this is incorrect, since L'Hôpital's rule can only be used if both the numerator and denominator approach 0 or infinity. In this case, only the denominator approaches 0, while the numerator approaches a nonzero value.

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The percentage of the students are between 62 and 69 inches tall is 46.0%

From the question, we have the following parameters that can be used in our computation:

Mean = 69

Standard deviation = 4

Scores = between 62 and 69

So, the z-scores are

z = (62 - 69)/4 = -1,75

z = (69 - 69)/4 = 0

i.e. between a z-score of -1.75 and a z-score of 0

This is represented as

Probability = (-1.75 < z < 0)

Using a graphing calculator, we have

Probability =  0.45994

Approximate

Probability =  46.0%

Hence, the probability is 46.0%

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The reflection of (-3,-3) is (-1,-3), the reflection of (-2,-2) is (-2,-2), and the reflection of (-1,1) is (-3,1), respectively

To reflect a point across an axis of symmetry, you can use the following steps:

Determine the equation of the axis of symmetry. This is a vertical or horizontal line that passes through the vertex of the parabola (if the original points come from a parabola).

Determine the distance between the point and the axis of symmetry.

Reflect the point across the axis of symmetry by moving the same distance on the other side of the line.

Let's apply these steps to the given points and the axis of symmetry x = -2:

The equation of the axis of symmetry is x = -2, which is a vertical line passing through (-2,0).

For the first point (-3,-3), the distance between the point and the axis of symmetry is 1 unit (|-3 - (-2)| = 1).

To reflect (-3,-3) across the axis of symmetry, we move 1 unit to the right of the line. So the reflection is ( -1,-3).

For the second point (-2,-2), the distance between the point and the axis of symmetry is 0 units (|-2 - (-2)| = 0).

Since the point is already on the axis of symmetry, its reflection is itself, which is (-2,-2).

For the third point (-1,1), the distance between the point and the axis of symmetry is 1 unit (|-1 - (-2)| = 1).

To reflect (-1,1) across the axis of symmetry, we move 1 unit to the left of the line. So the reflection is (-3,1).

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To prove that someone who follows the two rules would live forever, let's analyze the situation.

According to the rules:

(1) Always speak the truth.

(2) Each day, say "I will repeat this sentence tomorrow."

Let's assume that there is a person, let's call them Alice, who follows these rules.

On the first day, Alice says, "I will repeat this sentence tomorrow." Since Alice always speaks the truth, we can trust that she will indeed repeat the sentence the next day.

On the second day, Alice repeats the sentence as promised. Now, on this day, she again says, "I will repeat this sentence tomorrow." According to the rules, she must speak the truth, so we can trust that she will repeat the sentence the following day.

This pattern continues indefinitely. Every day, Alice faithfully repeats the sentence, always speaking the truth.

Now, if Alice were to live forever, she would continue following these rules and repeating the sentence every day. Therefore, it seems that Alice could potentially live forever based on this reasoning.

However, in reality, this scenario cannot work for a few reasons:

1. Mortality: Humans are mortal beings, which means they have a limited lifespan. Regardless of the rules or statements, humans are subject to aging and eventual death. Following the given rules cannot override this fundamental aspect of human existence.

2. Logical Paradox: The statement "I will repeat this sentence tomorrow" leads to a logical paradox. If Alice were to live forever and always repeat the sentence the next day, there would never be a day when the sentence is not repeated.

This creates a contradiction because at some point, the sentence would have to be broken or not repeated, which contradicts the initial statement.

Therefore, while the reasoning may appear valid on the surface, it does not align with the reality of human mortality and leads to logical contradictions. Following these rules cannot guarantee eternal life.

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