find dy/dx in the following
1) y= sin x+ e^{x}
2) y= e^{x}-1/x+㏒e x

Answer:

it need to =90

Step-by-step explanation:

We can make x the subject of the equation by moving all the other terms to the opposite side of the equal sign while x is on the next.

  x/y+z=w                       [multiply both sides by y+z]

        x = w (y + z)

Answer:

10

Step-by-step explanation:

sqrt. 100 = 10

because base x height = area

base and height must be same length in a square

its 304.8 milimeter

The actual length of the bus that the scale model represents is 252 inches.

To find the actual length of the bus represented by the scale model, you can use the scale ratio.

Given:

Scale model length = 12 inches

Scale ratio = 1:21

Let "x" be the actual length of the bus.

Using the scale ratio:

Scale model length / Actual length = Scale ratio

12 inches / x inches = 1/21

Now, solve for "x":

x = 12 inches / (1/21)

x = 12 inches × 21

x = 252 inches

Therefore, the actual length of the bus that the scale model represents is 252 inches.

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[tex]\\ \sf\longmapsto \sqrt{108x^2y^3}-\sqrt{12x^2y^3}+x\sqrt{75y^3}[/tex]

[tex]\\ \sf\longmapsto \sqrt{2\times 2\times 3\times 3\times 3\times x\times x\times y\times y\times y}-\sqrt{2\times 2\times 3\times x\times x\times y\times y\times y}+\sqrt{5\times 5\times 3\times y\times y\times y}[/tex]

[tex]\\ \sf\longmapsto 6\sqrt{3}xy\sqrt{y}-2\sqrt{3}xy\sqrt{y}+5\sqrt{3}xy\sqrt{y}[/tex]

[tex]\\ \sf\longmapsto \sqrt{3}xy\sqrt{y}(6-2+5)[/tex]

[tex]\\ \sf\longmapsto 9\sqrt{3}xy\sqrt{y}[/tex]

Answer:

[tex]{ \rm{ \sqrt{108 {x}^{2} {y}^{3} } - \sqrt{12 {x}^{2} {y}^{3} } + x \sqrt{75 {y}^{3} } }} \\ \\ = { \rm{\sqrt{(36 \times 3) {x}^{2} {y}^{3} } - \sqrt{(4 \times 3) {x}^{2} {y}^{3} } + x \sqrt{(3 \times 25)} {y}^{3} }} \\ \\ = { \rm{ \sqrt{ {x}^{2} {y}^{3} } ( \sqrt{36 \times 3} - \sqrt{4 \times 3} + \sqrt{3 \times 25} }}) \\ \\ { = \rm{x {y}^{ \frac{3}{2} } (6 \sqrt{3} - 2 \sqrt{3} + 5 \sqrt{3} ) }} \\ \\ = { \rm{x {y}^{ \frac{3}{2} } \{(6 - 2 + 5) \sqrt{3} \} }} \\ \\ = { \rm{x {y}^{ \frac{3}{2} } \times 9 \sqrt{3} }} \\ \\ = { \boxed{ \rm{9x \sqrt{3 {y}^{3} } }}}[/tex]

a. Just add 0.2 to 0.15 in equation a. y = mx + b shows that m is the slope. Answer would be 0.35.

b. 2y = 3x + 1

y = 3x/2 + 1/2

Perpendicular = negative reciprocal of original function's slope.

3/2 -> -2/3x.

Only the first one fulfills the equation, thus:

-2/3x + 3.

(1) The slope of line b is 0.35. The correct option is A.

(2) The equation perpendicular to the line y = - 2/3x + 3. The correct option is A.

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

(1) An equation for line a is y = 0.15x + 5000. The slope of line b is 0.2 greater than the slope of the line.

The slope of line b,

b = 0.2 + a

b = 0.2 + 0.15

b = 0.35

(2) The equation of the line perpendicular to the line 2y = 3x + 1 is calculated as:-

The slope of the line perpendicular to the other line is the opposite reciprocal. The equation will be,

y = -2/3x + 3

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The cost can be optimized by using a Linear Programming given the  linear constraint system

Reason:

Let X represent Type 1 bacteria, and let Y, represent Type II bacteria, we have;

The constraints are;

4·X + 3·Y ≥ 240

20 ≤ X ≤ 60

Y ≤ 70

P = 5·X + 7·Y

Solving the inequality gives;

4·X + 3·Y ≥ 240

The boundary of the feasible region are;

(20, 70)

(20, 53.[tex]\overline 3[/tex])

(60, 0)

(60, 70)

The cost are ;

[tex]\begin{array}{|c|c|c|}X&Y&P= 5\times X + 7 \times Y\\20&70&590\\20&53.\overline 3&473.\overline 3\\60&0&300\\60&70&790\end{array}\right][/tex]

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Answer:

B

Step-by-step explanation:

going down on the right

Answer:

B

Step-by-step explanation:

Aline with zero slope is a horizontal line parallel to the x- axis

A line with undefined slope is a vertical line parallel to the y- axis

A line sloping upwards from left to right has a positive slope

A line sloping downwards from left to right has a negative slope.

The line shown slopes downwards from left to right and has a negative slope

Answer: X = 20

Step-by-step explanation:

Answer: X = 20

Step-by-step explanation:

To get this

3 * 20 + 12 = 20

3*20=60

60+12=72

72

Answer:

it's 25qr 78 5×4 and then 12÷5= 2r28

Answer:

x>18

Step-by-step explanation:

[tex]\frac{x}{2} -5>4\\\\\\\frac{x}{2} >9\\\\\\\\x>9(2)\\\\\\x>18[/tex]

Answer:

x = 5

Step-by-step explanation:

The exterior angle theorem states that the measure of each exterior angle of a triangle is equal to the sum of the opposite and non-adjacent interior angles.

In the given problem, the exterior angle is < B, and the non-adjacent interior angles are < D and < C.

Given that:

< B = 12x + 8

< D = 8x + 8

< C = 20°

Set up the following formula to solve for x:

(8x + 8) + 20 = 12x + 8

Combine like terms:

8x + 28 = 12x + 8

Subtract 8 from both sides:

8x + 28 - 8 = 12x + 8 - 8

8x + 20 = 12x

Subtract 8x from both sides:

8x - 8x + 20 = 12x - 8x

20 = 4x

Divide both sides by 4 to solve for x:

20/4 = 4x/4

5  = x

Therefore, x = 5.

Answer:(-6,30)

Step-by-step explanation:

x=-6

y=30

Answer: (-6,30)

Step-by-step explanation:

-5x=-x+24

+x=+x

-4x=24

÷-4=÷-4

X=-6

Y=-5x

Y=-5(-6)

Y=30

(-6,30)

Answer:  x3+y3+z3=k

Step-by-step explanation:

x3+y3+z3=k                                    

You're welcome mr/ms

Answer:

Simplifying

c + -2 = 3c + 14

Reorder the terms:

-2 + c = 3c + 14

Reorder the terms:

-2 + c = 14 + 3c

Solving

-2 + c = 14 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.

-2 + c + -3c = 14 + 3c + -3c

Combine like terms: c + -3c = -2c

-2 + -2c = 14 + 3c + -3c

Combine like terms: 3c + -3c = 0

-2 + -2c = 14 + 0

-2 + -2c = 14

Add '2' to each side of the equation.

-2 + 2 + -2c = 14 + 2

Combine like terms: -2 + 2 = 0

0 + -2c = 14 + 2

-2c = 14 + 2

Combine like terms: 14 + 2 = 16

-2c = 16

Divide each side by '-2'.

c = -8

Simplifying

c = -8

Step-by-step explanation:

Answer:

1. 1/200

2. 15/2

3. 11/36

4. 8/5

Step-by-step explanation:

Answer:

75

Step-by-step explanation:

Each pound costs 75¢ so by each pound it increases by 75¢

7200

Step-by-step explanation:

The number was 72. you move the decimal 2 places to the right (left if it was negative) There are no numbers there. So you add 0's .

(Sorry if I did not explain good enough. I am not very good at explaining things.)

Step-by-step explanation:

let the number be x

x +3= 2x

collect the like terms

x-2x= -3

-x = -3

x=3

PLEASE MARK BRAINLIEST

Answer: 35

Step-by-step explanation: (lol I read the question wrong). Basically subtract 7 from 63, then divide 56 by 2 to find Pamela’s age. Then add 28+7 because Jiri is 7 years older than Pamela

Answer:

-8m+24-32n

Step-by-step explanation:

8×m,-3and 4n

Answer: 2(x + 10)

Step-by-step explanation: you have to add all of the perimeter sides together so you will have to times the length by 2 so your equation would be (8 × 2 = 16). Then the width by 2 ( 2 × (x+2) = 2x + 4) now you add them together

16 + 2x + 4

2x + 20

Now you have to take out the highest common factor which is 2

So it will be 2(x + 10)

Answer:

[tex] \frac{ - 1}{3} w \leqslant - 5[/tex]

[tex]w \leqslant - 5 \div \frac{ - 1}{3} [/tex]

[tex]w \leqslant - 5 \times - 3[/tex]

[tex]w \leqslant 15[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\huge\boxed{\mathsf{\sqrt{121} = x^2}}[/tex]

[tex]\huge\boxed{\mathsf{x^2 = \sqrt{121}}}[/tex]

[tex]\large\boxed{\large\boxed{\bullet\rm{ \ TAKE \ your \ SQUARE \ ROOT}}}[/tex]

[tex]\huge\boxed{\mathsf{x = \pm \sqrt{121}}}[/tex]

[tex]\large\boxed{\large\boxed{\bullet\ \rm{The \ symbol\ \boxed{\pm}\ means \ plus \ or \ minus, so \ that \ means}}}\\\large\boxed{\boxed{\rm{either \ the \ result \ will \ be \ \underline{\underline{positive}} \ or \ \underline{\underline{negative}}}}}}}\large\checkmark[/tex]

[tex]\huge\boxed{\mathsf{\sqrt{121} = -\sqrt{121}}}[/tex]

[tex]\huge\boxed{\sqrt{121} = \bf 11}[/tex]

[tex]\huge\boxed{\mathsf{-\sqrt{121} = \bf -11}}[/tex]

[tex]\huge\boxed{\text{Therefore, your answer is: \textsf{x = -11 or x = 11}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day! }[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The quadratic equation that contains the three points is y = -x² + 3x + 40

A quadratic equation is in the form:

y = ax² + bx + c

At point (-4, 12):

12 = a(-4)² + b(-4) + c

16a - 4b + c = 12      (1)

At point (2, 42):

42 = a(2)² + b(2) + c

4a + 2b + c = 2      (2)

At point (3, 40):

40 = a(3)² + b(3) + c

9a + 3b + c = 40     (3)

Solving equation 1, 2, and 3 gives:

a = -1, b =3, c = 40

y = -x² + 3x + 40

Hence the quadratic equation is y = -x² + 3x + 40

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Answer:

14

Step-by-step explanation:

Convert [tex]\frac{7}{2}[/tex] to a fraction with a common denominator

[tex]\frac{7}{2} (\frac{2}{2} )=\frac{14}{4}[/tex]

You now divide the fractions to find the amount of correct measurements needed.

[tex]\frac{\frac{14}{4} }{\frac{1}{4} }[/tex] For dividing by a fraction it is the same a multiplying by its reciprocal.

This becomes [tex]\frac{14}{4} (\frac{4}{1} )=\frac{14}{4} (4)=14[/tex]

You will need 14 correct measurements.

Answer:

First option, relation 1 and relation 4

Step-by-step explanation:

Because they both cross one of the two axes once, which from what I remember, makes it a function.

Hope this makes sense, and please correct me if I'm wrong :)