F.BF.1b Combine standard function types using arithmetic o
Give the equation for f(x) + g(x) given that
f(x) = x² - x + 1 and g(x) = 2x + 3

Answer:

960 pages

Step-by-step explanation:

By answering the presented question, we may conclude that There are polygon four vertex designated HT , HB, TE and EB in the provided picture.

A polygon is a two-dimensional shape that is formed by joining three or more points in a closed loop. Triangles, tetrahedra, pentagons, hexagons, and other forms are examples of polygons. Polygons are a fundamental geometric concept used to define and analyze a wide range of real-world forms and structures, such as buildings, layouts, and computer graphics. Polygons are examined not just for their perimeter, area, and angles, but also for their symmetry.

The vertex of the polygon in the image are the line segments that link the polygon's opposing vertices and are perpendicular to its base. There are four vertex designated HT , HB, TE and EB   in the provided picture.

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Answer:

first option (30x4 − 20x3 + 15x2)

A. The equation that relates these variables is:

d = s * t. B. The biker would travel 10 miles in 20 minutes. C. The biker would bike for 96 minutes to travel 48 miles. Rounded to the nearest tenth, this is 96.0 minutes.

a. Let's define the variables:

t = time in minutes

d = distance traveled by the biker in miles

s = speed of the biker in miles per minute

The equation that relates these variables is:

d = s * t

b. If the biker travels for 20 minutes, we can use the equation above to find the distance traveled:

d = s * t

d = s * 20 (since t = 20 minutes)

We need to know the speed of the biker to calculate the distance traveled. Let's assume that the biker's speed is 0.5 miles per minute (which is equivalent to 30 miles per hour):

d = 0.5 * 20

d = 10

Therefore, the biker would travel 10 miles in 20 minutes.

c. If the biker traveled 48 miles, we can rearrange the equation above to find the time:

d = s * t

t = d / s

We need to know the speed of the biker to calculate the time. Let's assume that the biker's speed is still 0.5 miles per minute:

t = 48 / 0.5

t = 96

Therefore, the biker would bike for 96 minutes to travel 48 miles. Rounded to the nearest tenth, this is 96.0 minutes.

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The amount of coffee of type A that was used is given as follows:

27 lbs.

The amounts of each type of coffee used are obtained using a system of equations, for which the variables are given as follows:

The total cost was of 503.55, hence:

5.75x + 4.3y = 503.55.

The amount of coffee B used was the triple of the amount of coffee A used, hence:

y = 3x.

Replacing the second equation into the first, the amount of coffee A used is given as follows:

5.75x +  4.3(3x) = 503.55

x = 503.55/18.65

x = 27 lbs.

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Step-by-step explanation:

law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

a,b,c being the sides of the triangle, A, B, C are the corresponding opposite angles in the triangle.

the angle of depression is the external angle of the triangle vertex at the balloon. that means the internal angle is 60°, as both together must be 90° (the angle between the height of the balloon and the horizontal line at the balloon).

the angles at the ground at the fire are mirrored : the internal angle there is 30°, the external angle is 60°.

and so,

height/sin(30) = 150/0.5 = distance/sin(60)

distance = sin(60)×150/0.5 = sin(60)×300 =

= 259.8076211... ft ≈ 260 ft

Answer: 80 mph fet stream

Step-by-step explanation:

2576/4 + the jet stream=3216/4- jet stream

simplified, 80 mph

The critical value Zc is ±2.170.

What is a confidence interval?

An estimated range for an unknown parameter is known as a confidence interval. The 95% confidence level is the most popular, however other levels, such as 90% or 99%, are occasionally used when computing confidence intervals.

Here, we have

Given: a confidence interval at the level of confidence shown below.

c=0.97

We have to find the critical value Zc.

c = 0.97

we get a = 1 - c

a = 1 - 0.97

a = 0.03

Critical value Zc = ±2.170

Hence, the critical value Zc is ±2.170.

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The answer of A is The point (-2,2) is included in the graph of g(x) regardless of the value of b and c.The answer of B the point (2,2) would be transformed to the point (2,1) on the graph of h(x).

What is graph?

A graph is a visual representation of data, functions, or relationships between variables. It is a way of displaying information in a way that is easy to interpret and understand. Graphs typically consist of two axes, the x-axis and y-axis, and points or lines plotted on the graph to represent the data or function being displayed.

There are many different types of graphs, including line graphs, bar graphs, pie charts, scatter plots, and more. Each type of graph is used for different purposes and can display different types of data.

Graphs are commonly used in many fields, including science, economics, finance, engineering, and more. They allow researchers and analysts to easily visualize data and identify trends or patterns, making it easier to draw conclusions and make informed decisions based on the data.

A. To include the point (-2,2), we need to shift the graph of f(x) two units to the right and two units upwards. So we have:

g(x) = a f(x - (-2)) + 2

g(x) = a f(x + 2) + 2

Now we need to find the value of "a". Since the point (3,4) on the graph of f(x) is mapped to the point (2,2) on the graph of g(x), we have:

g(3) = a f(3 + 2) + 2 = 2

4a + 2 = 2

4a = 0

a = 0

Therefore, the function g(x) is:

g(x) = 0 f(x + 2) + 2

g(x) = 2

So the point (-2,2) is included in the graph of g(x) regardless of the value of b and c.

B. The function h(x) is a linear function with slope 2 and y-intercept -1. To find where the point (2,2) would end up after the transformations, we plug in x=2 into h(x) and get:

h(2) = 2(2+1)-3 = 1

So the point (2,2) would be transformed to the point (2,1) on the graph of h(x).

The transformations made to f(x) to obtain h(x) are a horizontal shift to the left by one unit (x+1), a vertical stretch by a factor of 2 (2(x+1)), and a vertical shift downwards by three units (-3).

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f[g(-2)] = 2 as the function f(x) = x - 5 must then be used to evaluate the function f[g(-2)] .

A function is a mathematical construct that transforms a set of inputs (referred to as the domain) into a single output from another set (called the range). A function is, in other words, a rule that allots precisely one output to each input in the domain. The notation f(x) is frequently used to denote functions, where f stands for the function name and x for the input value. As an illustration, the function f(x) = 2x + 1 doubles any input x, adds 1, and returns the result.

given

To begin, we must calculate g(-2) using the formula g(x) = x2 + 3:

[tex]g(-2) = (-2)^2 + 3 = 4 + 3 = 7[/tex]

The function f(x) = x - 5 must then be used to evaluate the function f[g(-2)]:

f[g(-2)] = f(7) = 7 - 5 = 2

Hence, f[g(-2)] = 2.

f[g(-2)] = 2 as the function f(x) = x - 5 must then be used to evaluate the function f[g(-2)] .

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Answer:

[tex]1 \frac{1}{81} \ [/tex]

Solution:

[tex] \frac{a - 1}{a} = \frac{2}{3} [/tex]

1) 2a = 3(a - 1)

2a = 3a - 3

2a - 3a = -3

-a = -3 / * (-1)

a = 3

2) Replace the a with 3 in this:

[tex] \frac{ {a}^{4} + 1}{ {a}^{4} } [/tex]

[tex] \frac{ {3}^{4} + 1}{ {3}^{4} } = \frac{81 + 1}{81} = \frac{82}{81} = 1 \frac{1}{81} [/tex]

I don't know if I got this right, but at least I tried

After solving the given equation 3x+7y=11 we know that (A) (6, -1)  lies on the graph of the given equation.

A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.

A mathematical equation is a statement that two amounts or values are equal, such as 6 x 4 = 12 x 2. 2.

A noun that counts.

When two or more components must be taken into account collectively in order to comprehend or describe the overall situation, this is known as an equation.

So, we are asked to identify the point on its graph.

(6, -1)

Adding "x=6" and "y=-1"

3x+7y=3×6+7×(-1)

= 18-7

= 11

Thus, on the graph of 3x+7y=11, (6, -1) is located.

(1,-2)

X = 1 and Y = -2

3x+7y=3×1+7×(-2)

= 3-14

= -11

As a result, the graph of 3x+7y=11 does not contain (1, -2)

(0,-4)

X = 0 and Y = -4

3x+7y=3×0+7×(-4)

= -28

Hence, the graph of 3x+7y=11 does not contain (0, -4)

(0,4)

By setting x=0 and y=4,

3x+7y=3×0+7×4

= 28

In light of this, the graph of 3x+7y=11 does not contain (0, 4)

Therefore, after solving the given equation 3x+7y=11 we know that (A) (6, -1)  lies on the graph of the given equation.

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Complete question:

Which ordered pair is on the graph of equation 3x+7y=11?

a. (6,-1)

b. (1,-2)

c. (0,-4)

d. (0,4)

Therefore, the solutions to the quadratic equation x² + 7x - 8 = 0 are -8 and 1. The answers are D and E.

An equation is a mathematical statement that shows that two expressions are equal. It typically consists of variables, constants, and mathematical operations. Equations can be solved by manipulating the expressions to find the value of the variables that satisfy the equation. Equations can be used to model real-world situations, and they are an important tool in many fields, including mathematics, physics, engineering, and economics.

Here,

To check which values are solutions to the quadratic equation, we can substitute each value into the equation and see if it equals zero.

Substituting -1 into the equation:

(-1)² + 7(-1) - 8 = 1 - 7 - 8 = -14, which is not equal to zero.

Substituting 2 into the equation:

2² + 7(2) - 8 = 4 + 14 - 8 = 10, which is not equal to zero.

Substituting -4 into the equation:

(-4)² + 7(-4) - 8 = 16 - 28 - 8 = -20, which is not equal to zero.

Substituting -8 into the equation:

(-8)² + 7(-8) - 8 = 64 - 56 - 8 = 0, which is equal to zero. Therefore, -8 is a solution to the equation.

Substituting 1 into the equation:

1² + 7(1) - 8 = 1 + 7 - 8 = 0, which is equal to zero. Therefore, 1 is a solution to the equation.

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Answer:

The area of the shaded region is 21.

Step-by-step explanation:

Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:

[tex]A_s=2\times A_t[/tex]

Where At is the area of each triangle.

[tex]A_t=\dfrac{AB\times BC/2}{2}[/tex]

[tex]A_t=\dfrac{AB\times BC}{4}[/tex]

We know AB=7 and BC=6, thus:

[tex]A_t=\dfrac{7\times6}{4} =\dfrac{42}{4}[/tex]

Simplifying:

[tex]A_t=\dfrac{21}{2}[/tex]

Finally:

[tex]A_s=2\times\dfrac{21}{2}[/tex]

[tex]A_s=21[/tex]

The area of the shaded region is 21.

Note the area of the shaded region is half the area of the rectangle.

Answer:

  3 6 4 2 1 5

Step-by-step explanation:

You want to know the sequence of solving the problem of finding the time until the rope hits the ground when thrown at 10 m/s down a 50 m cliff.

The equation describing the height of the rope is of the form ...

  h(t) = -4.9t² +v₀t +h₀

where v₀ is the initial upward velocity (meters per second), and h₀ is the initial height (meters).

Here, the initial velocity is described as 10 m/s downward, so we expect v₀ to have a value of -10. However, the offered equation(s) show v₀ = +10, so we will be solving the problem assuming the rope is initially thrown upward.

For v₀ = 10 and h₀ = 50, the equation for the height of the rope is ...

  h(t) = -4.9t² +10t +50 . . . . . . . step 1

We want to find the time (t) when the height is 0, so we substitute h(t) = 0 into the above equation:

  0 = -4.9t² +10t +50 . . . . . . . . step 2

This can be solved nicely using the quadratic formula. We recognize that a=-4.9, b=10, c=50, so the filled-in formula is ...

  [tex]t=\dfrac{-10\pm\sqrt{10^2-4(-4.9)(50)}}{2(-4.9)}\qquad\textsf{step 3}[/tex]

Simplifying this and taking the square root, we have ...

  [tex]t\approx\dfrac{-10\pm32.86}{-9.8}\qquad\textsf{step 4}[/tex]

Evaluating this expression gives ...

  t ≈ -2.33  or  t ≈ 4.37 . . . . . . . . . step 5

Writing the answer as a sentence is the last step:

  The rope will hit the ground in about 4.37 seconds. . . . . . step 6

The sequence of step numbers is ...

  3 6 4 2 1 5

__

Additional comment

The equation assume ballistic motion, with no air resistance or other impediment to the rope falling only due to gravity. We assume that Krystal plans to use the rope for rappelling, so it is probably coming uncoiled as it falls. That process usually changes the motion from one that is purely defined by the force of gravity.

We also note that if the initial throwing direction is downward, then the solution to the equation h(t) = -4.9t² -10t +50 is actually t ≈ 2.33 s.

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Answer:

I think its C. sorry if I'm wrong.

Some of the radicals below that are like terms are; √2, 5√2, − 3√2, √32.

The like terms can be combined as 7√2.

The reason why the leftover terms are NOT like terms with the others is that the radicals lack the same root number also  radicand (expression under the root).

Radicals with the same root number AND radicand are similar radicals (expression under the root)

A number's radical and root are the same thing. A cube root, a square root, or an nth root could be the root. Therefore any number or phrase that uses a root is a radical. The word "radical" is derived from the Latin word radix, which means root. The radical can be used to explain a number's square, cube, fourth, and other forms of roots. The number that comes before the radical is known as the index number or degree.

3a. Some of the radicals that are like terms are; √2, 5√2, − 3√2, √32 and the reason why √32 is part of it is that √32 = 4√2

3b. The like terms can be combined as ;

(√2+ 5√2 − 3√2 + √32)

= (√2+ 5√2 − 3√2 + 4√2)

=7√2

3c. The reason why the leftover terms are NOT like terms with the others is that the radicals  do not have the same root number as well as  radicand (expression under the root).

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Answer:

a. $682.09

Step-by-step explanation:

We can use the present value formula to find the value of the bond today:

PV = FV / (1 + r)^n

where PV is the present value, FV is the future value, r is the interest rate, and n is the number of periods.

Substituting the given values, we get:

PV = 1000 / (1 + 0.045)^8 = $682.09

Therefore, the bond is worth $682.09 today, which is option (a).

The function with the greater initial value in this problem is given as follows:

Function f(x), the graphed function.

The initial value of a function, often denoted as f(0), is the value of the function when the independent variable (usually denoted as x) is equal to 0. In other words, it is the value of the function at the starting point of its domain.

Hence the initial value of each function in this problem is given as follows:

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Answer: -7

Step-by-step explanation:

in the linear equation, y=mx+b, m represents the slope of the line, so when looking at an equation the best way to find the slope is to find where the m variable would be

The answer of the given question based on series to match the correct summation is the given series matches with option 2: 1 + 0.5 + 0.25 + 0.125 + ...

In mathematics, an infinite series is a sum of infinitely many terms. An infinite series can be thought of as the limit of the sequence of partial sums, which is obtained by adding only the first n terms of the series. If the limit of the sequence of partial sums exists and is finite, then the infinite series is said to be convergent; otherwise, it is said to be divergent.

Infinite series have many applications in mathematics, science, and engineering, and are used to approximate functions, solve differential equations, and model physical phenomena.

The given infinite series is: 3 - 9/4 + 27/16 - 81/64 + ...

This series is a geometric series with first term a = 3 and common ratio r = -3/4.

The formula for the sum of an infinite geometric series with first term a and common ratio r (|r| < 1) is given by:

S = a / (1 - r)

Plugging in the values of a and r, we get:

S = 3 / (1 - (-3/4)) = 3 / (7/4) = 12/7

Therefore, the given series matches with option 2: 1 + 0.5 + 0.25 + 0.125 + ...

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The composite function [g . f](x) when evaluated has its value to be 4x² + 20x + 22

Given that, we have the following functions

f(x) = 2x + 5

g(x) = x² - 3

To find [g . f](x) we make use of g(f(x)), where we first need to find f(x) and then plug it into g(x) in place of x.

Given, f(x) = 2x + 5 and g(x) = x^2 - 3.

So,

g(f(x)) = g(2x + 5) [Substitute f(x) in place of x in g(x)]

g(f(x)) = (2x + 5)² - 3 [Substitute 2x + 5 in place of x in g(x)]

g(f(x)) = (4x² + 20x + 25) - 3

g(f(x)) = 4x² + 20x + 22

This means that

[g . f](x) = 4x² + 20x + 22

Therefore, [g . f](x) = 4x² + 20x + 22

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The function oscillates between two horizontal asymptotes, y=3 and y=-3, as x approaches the vertical asymptotes.

How to study graph?

To graph the function y=3cot(x) between 0 and 2, we can start by identifying the key characteristics of the cotangent function. The cotangent function is defined as the ratio of the adjacent side to the opposite side of a right triangle, with respect to a given angle. As such, the cotangent function is periodic with a period of π and has vertical asymptotes at x=nπ, where n is an integer.

The coefficient of 3 in the given function y=3cot(x) vertically stretches the function by a factor of 3, and does not affect the period or the vertical asymptotes.

Between 0 and 2, there are two vertical asymptotes at x=0 and x=π. To graph the function, we can plot a few points along the curve, using the symmetry properties of the cotangent function. Specifically, the cotangent function is odd, meaning that cot(-x)=-cot(x), and thus the graph is symmetric about the origin.

At x=π/4, we have cot(π/4)=1, and thus y=3cot(π/4)=3. Similarly, at x=3π/4, we have cot(3π/4)=-1, and thus y=3cot(3π/4)=-3. Using the symmetry property, we can also plot points at x=-π/4 and x=-3π/4, with y=3cot(-π/4)=-3 and y=3cot(-3π/4)=3, respectively.

Connecting these points with smooth curves, we can see that the graph of y=3cot(x) oscillates between two horizontal asymptotes, y=3 and y=-3, as x approaches the vertical asymptotes at x=0 and x=π.

Overall, the graph of y=3cot(x) between 0 and 2 can be summarized as follows:

There are two vertical asymptotes at x=0 and x=π.

The function oscillates between two horizontal asymptotes, y=3 and y=-3, as x approaches the vertical asymptotes.

The graph is symmetric about the origin.

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The lengths of the edges of the cubes are 45cm and 63cm respectively.

To determine the edge length of a cube with a volume of 91,125 cm³, we can use the formula:

Volume of a cube = edge length³

Plugging in the given value, we get:

91,125 = edge length³

Taking the cube root of both sides, we get edge length

edge length ≈ 45

Therefore, the edge length of the cube is approximately 45 cm.

To determine the side length of a square with an area of 3,969 cm², we can use the formula

Area of a square = side length²

Plugging in the given value, we get:

3,969 = side length²

side length = √3,969

Using a calculator, we can simplify this to

side length ≈ 63

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Triangle JKL's area is 3 square units as a result.

The vertices' coordinates and the following formula must be used to determine the area of triangle JKL:

Area equals 1/2*base*height

We must first determine the triangle's height and base length. The distance between points J and K, which is the base, is:

base = √[(x2 - x1)² + (y2 - y1)²]

= √[(-4 - (-7))² + (-8 - (-9))²]

= √[3² + 1²]

= √10

The height is calculated as the distance between point L and the base-containment line. To calculate it, we can use the following formula for the separation between a point and a line:

height = |(y2 - y1)x0 - (x2 - x1)y0 + x2y1 - y2x1| / √[(y2 - y1)² + (x2 - x1)²]

= |(-9 - (-8))(-5) - (-7 - (-4))(-6) + (-4)(-9) - (-8)(-7)| / √[(1)² + (3)²]

= 6 / √10

Now, we can enter the height and base values into the triangle's area formula:

Area = 1/2 * √10 * 6 / √10

= 3

Triangle JKL's area is 3 square units as a result.

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Answer:

Step-by-step explanation:

Let x be the side length of the square window. Then the area of the square window is x^2, and the area of the rectangular window is 16 * 4 = 64.

We can write the equation:

x^2 = 64

To solve for x, we can take the square root of both sides:

x = √64

x = 8

Therefore, the side length of the square window is 8 inches.

Answer:

differentiate between tropical and subtropical climate zone on the basis of climate and economic activities in 4 points class 10