Exercise V (4×5=20 points )
True or False? Explain clearly. 1. Every matrix with ones down the main diagonal is invertible. 2. Let A,B,M be square matrices of the same size. If B=M−1AM, then detB=detA. 3. Suppose that a matrix A satisfies the equation A2=A. Then det A=0. 4. If A and B are invertible n×n matrices, then A is invertible and the inverse of AB is B−1A−1

Step-by-step explanation:

I am going to assume this is a quadratic so

[tex]f(x) = {ax}^{2} + bx + c[/tex]

When 3 is c

[tex] {ax}^{2} + bx + 3[/tex]

When x is 7,

[tex]a( {7}^{2} ) + b(7) + 3 = 13[/tex]

[tex]49a + 7b = 10[/tex]

When x is 9,

[tex]a(9) {}^{2} + 9b + 3 = - 11[/tex]

[tex]81a + 9b = - 14[/tex]

We have two system, let's eliminate the b variable by multiplying the second system by

[tex] \frac{7}{9} [/tex]

[tex]63a + 7b = - \frac{98}{9} [/tex]

Bring down the first system

[tex]49a + 7b = 10[/tex]

Subtract the two system,

[tex]14a = \frac{ - 188}{9} [/tex]

[tex]a = - \frac{94}{63} [/tex]

Plugging in a, we will eventually get

[tex]b = \frac{748}{63} [/tex]

So our quadratic is

[tex] - \frac{94}{63} {x}^{2} + \frac{748}{63} x + 3[/tex]

Answer: 14.6

Step-by-step explanation:

The solutions to the given equations are T1 = 0.2 and T = 4.5.

To solve the given equations, we will use algebraic methods to isolate the variable on one side of the equation.

First, let's solve the equation 0.2=1−(1−T1​).

0.2 = 1 - (1 - T1)
0.2 = 1 - 1 + T1
0.2 = T1

So, T1 = 0.2

Next, let's solve the equation 30T=135.

30T = 135
T = 135/30
T = 4.5

So, T = 4.5

Therefore, the solutions to the given equations are T1 = 0.2 and T = 4.5.

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The probability of A) 3 arrivals in an hour is approximately 0.1404, of B) at least 2 arrivals an hour is 0.918, of C) at most 1 arrival in an hour is 0.0821, and of D) no arrivals in an hour is 0.0067.

a. The probability of 3 arrivals in an hour can be calculated using the Poisson distribution formula: [tex]P(X = 3) = (e^{-5} * 5^3) / 3! = 0.1404[/tex]

b. The probability of at least 2 arrivals in an hour can be calculated by finding the complement of the probability of 0 or 1 arrival: [tex]P(X \geq 2) = 1 - P(X = 0) - P(X = 1) = 1 - e^{-5} * (5^0 / 0!) - e^{-5} * (5^1 / 1!) = 0.918[/tex]

c. The probability of at most 1 arrival in an hour can be calculated by adding the probabilities of 0 and 1 arrival: [tex]P(X \leq 1) = P(X = 0) + P(X = 1) = e^{-5} * (5^0 / 0!) + e^{-5} * (5^1 / 1!) = 0.0821[/tex]

d. The probability of no arrivals in an hour can be calculated by using the Poisson distribution formula: [tex]P(X = 0) = e^{-5} * (5^0 / 0!) = 0.0067[/tex]

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Answer:

To solve this problem, we can set up a proportion:

9.5 cups of flour / 18 cookies = 15 cups of flour / x cookies

To solve for x, we can cross-multiply:

9.5 cups of flour * x cookies = 18 cookies * 15 cups of flour

Dividing both sides by 9.5 cups of flour gives us:

x cookies = 18 cookies * 15 cups of flour / 9.5 cups of flour

x cookies ≈ 28.42

Since we can't make a fraction of a cookie, we'll round down to the nearest whole number. Therefore, Lan can make about 28 cookies with 15 cups of flour using the same recipe.

The numbers are 4 and 5, as their difference is -1 and adding 2 times the first to 3 times the second results in 13.

To solve the problem, we can start by using algebra. Let x be the first number and y be the second number. Then we can write two equations based on the given information:

We can solve this system of equations by substituting x - 1 for y in the second equation, which gives:

Simplifying this equation, we get:

Adding 3 to both sides, we get:

Dividing both sides by 5, we get:

Now that we know x, we can use the first equation to find y:

Adding y to both sides, we get:

Subtracting 4 from both sides, we get:

Therefore, the first number is 4 and the second number is 5, which satisfies both equations.

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Find a positive value of c so that the following trinomial is factorable. [tex]x^2-4x+c[/tex], The value of [tex]c[/tex] will be given by [tex]c=4[/tex].

To find a positive value of c so that the trinomial [tex]x^2-4x+c[/tex] is factorable, we need to use the formula for the sum of two squares. This formula states that [tex](a-b)^2=a^2-2ab+b^2[/tex].

In this case, we can let [tex]a=x[/tex] and [tex]b=2[/tex], so the formula becomes [tex](x-2)^2=x^2-4x+4.[/tex]

Comparing this formula to the given trinomial, we can see that the value of c must be 4 in order for the trinomial to be factorable.

Therefore, the positive value of c that makes the trinomial [tex]x^2-4x+c[/tex] factorable is [tex]c=4[/tex].

In factored form, the trinomial becomes [tex](x-2)^2[/tex].

Answer: [tex]c=4.[/tex]

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The correct slope and y-intercept for the linear equation y=2x+7 are 2 and 7, respectively.

The y-intercept of a graph is the point where the graph crosses the y-axis. It is written as (0, b), where b is the y-intercept. The y-intercept is the value of y when x is equal to zero. It can be used to determine the equation of a line when two points on the line are known.

The slope of a linear equation is the coefficient of the x variable, which is 2 in this case. The y-intercept is the constant term, which is 7 in this case.

So, the slope is 2 and the y-intercept is 7.

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Answer:

66%

Step-by-step explanation:

"of the" something = means denominator of a fraction

of the tickets sold = denomination here

question asked about child tickets , so child tickets = numerator here

what percentage? = fraction x 100%

answer:

2640 / (2640+1360) x 100

c = 3.

a) A is linearly dependent for any value of c because the vectors are not linearly independent.

This means that one of the vectors can be written as a linear combination of the others.

For example, the vector (1,2,c) can be written as (2,2,0) + (-1,0,c-0) = (1,2,c).

This means that the set of vectors is linearly dependent.

b) For c = 0, Vector (A) is the set of all linear combinations of the vectors (2,2,0), (1,2,0), (0,0,0), and (1,0,0).

This means that Vect (A) is the set of all points in the xy-plane, or the set of all vectors in R^2.c).

To find all the values of c for which (4,1,3) is in Vect (A),

we need to solve the equation (4,1,3) = a(2,2,0) + b(1,2,c) + d(0,0,c) + e(1,0,0) for the scalars a, b, d, and e.

This gives us the system of equations:4 = 2a + b + e1 = 2a + 2b3 = bc + dc.

Solving this system of equations gives us the values of a, b, d, and e in terms of c.

We can then use these values to find the values of c for which (4,1,3) is in Vect (A).

After solving the system of equations, we find that c = 3 and a = 1, b = -1, d = 0, and e = 2.

Therefore, the value of c for which (4,1,3) is in Vect (A) is c = 3.

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The answer is ((81c^(8))/(16d^((32)/(5)))).

To simplify ((3c^(2))/(2d^((8)/(5))))^(4), we can use the power of a power rule and distribute the exponent of 4 to each term inside the parentheses.

((3c^(2))/(2d^((8)/(5))))^(4) = (3^(4))(c^(2*4))/(2^(4))(d^((8*4)/(5)))

Simplifying further, we get:

= (81)(c^(8))/(16)(d^((32)/(5)))

= (81c^(8))/(16d^((32)/(5)))

This is the simplified answer with no variables. It cannot be simplified further. Therefore, the answer is ((81c^(8))/(16d^((32)/(5)))).

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The slope of the line in simplest form is 1/3.

In Mathematics, the slope of any straight line can be determined by using this mathematical equation;

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = rise/run

Substituting the given data points into the slope formula, we have the following;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (-2 + 5)/(9 - 0)

Slope, m = 3/9

Slope, m = 1/3

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The area under the curve is 4.55 square units.

Here we have to find the area,

That lies under the curve y -x + 1 between x = 0 and x = 10

Therefore,

To estimate the area that lies under the curve y = -x + 1 between x = 0 and x = 10,

Use the Riemann Sum method,

Divide the interval [0, 10] into n subintervals of equal width,

And let Δx be the width of each subinterval.

Then, we can estimate the area under the curve as the sum of the areas of n rectangles with heights given by the function.

The formula for the Riemann Sum is,

⇒ Δx [f(0) + f(Δx) + f(2Δx) + ... + f((n-1)Δx)]

where Δx = (b-a)/n, a = 0, b = 10, and f(x) = -x + 1.

Let's choose,

n = 100 for a reasonably accurate estimate.

Then, Δx = (10-0)/100 = 0.1

Put it into the formula, we get.

⇒ 0.1[1 + 0.9 + 0.8 + ... + 0.1]

Evaluating the sum using the formula for the sum of an arithmetic series, we get:

⇒ 0.1(0.5)[2 + (99)(-0.9)]

Simplifying, we get,

⇒ 4.55

Therefore, the required area be 4.55 square units.

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Answer: 8.5 by 11 inches.

Step-by-step explanation:

The standard 8.5″ x 11″ or Letter size so prevalent in full sized notebooks.

Using the properties of the exponents, we solve the expression and found the result as  [tex]w^{15} y^{12}[/tex].

The exponent of a number indicates how many times a number has been multiplied by itself. Exponent is another name for a number's power. It could be an integer, a fraction, a negative integer, or a decimal. How many times we must multiply the reciprocal of the base is indicated by a negative exponent. When writing exponentiated fractions, negative exponents are employed. A fractional exponent is one where the exponent of a number is a fraction. Parts of fractional exponents include square roots, cube roots, and nth roots. The square root of a base is a number with a power of half.

Given,

[tex](w^5 * y^4)^3[/tex]

We have to solve this using the properties of the exponents.

Now, this can be written as:

[tex](w^5)^3 * (y^4)^3[/tex]

When the exponent is raised to another power, we can follow the power rule for exponents.

This rule states that multiply the exponent by the power to raise a number with an exponent to that power.

Then the above expression becomes

[tex]w^{(5*3)} * y^{(4*3)}[/tex] = [tex]w^{15} y^{12}[/tex]

Therefore using the properties of the exponents, we solve the expression and found the result as [tex]w^{15} y^{12}[/tex].

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The value of the expression c^(2)-5c+2 when c = 3 is -4.

Evaluating a quadratic expression involves substituting the given value of the variable into the expression and simplifying. In this case, we are given that c=3 and the expression is c^(2)-5c+2. We will substitute 3 in for c and simplify.

Step 1: Substitute 3 in for c: (3)^(2)-5(3)+2
Step 2: Simplify the expression: 9-15+2
Step 3: Combine like terms: -4

Therefore, the value of the expression when c=3 is -4.

A quadratic term is any expression that has in its unknowns (in which letters are used) one that is squared (or two), these terms are part of a quadratic function.

For a term to be quadratic it must be multiplied by itself (twice), for example:

a² + a + 1

We can see that it is a quadratic function and that its literal term is a while the quadratic term is a², i.e. a*a.

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The area of the triangle with the given vertices is 4.47.

To find the area of the triangle with the given vertices, we can use the formula:
Area = (1/2) * |(B-A) x (C-A)|
Where "x" represents the cross product of two vectors.
First, we need to find the vectors B-A and C-A:
B-A = (1-5, 1-(-1), 0-(-2)) = (-4, 2, 2)
C-A = (3-5, 2-(-1), -1-(-2)) = (-2, 3, 1)
Next, we need to find the cross product of these two vectors:
(B-A) x (C-A) = (2*1 - 2*3, 2*(-2) - (-4)*1, (-4)*3 - 2*(-2)) = (-4, 0, -8)
Finally, we can find the area of the triangle by plugging in the values into the formula:
Area = (1/2) * |(-4, 0, -8)|
Area = (1/2) * √((-4)^2 + 0^2 + (-8)^2)
Area = (1/2) * √(80)
Area = (1/2) * 8.94
Area = 4.47
Therefore, the area of the triangle with the given vertices is 4.47.

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If the mean of x, y and z is 88 1/3% of 360. The range of x, y and z is 2,852.

To solve this problem, we need to use the given ratios and proportions to find the values of x, y, and z, and then use the given mean to find their range.

From the first ratio, we have:

x:y = 5:3

This can be written as:

x = (5/3) * y

Substituting this value of x into the second ratio, we get:

y:2 = 11:6

Multiplying both sides by 3, we get:

3y = 22

y = 22/3

Substituting this value of y into the equation for x, we get:

x = (5/3) * (22/3) = 110/9

To find z, we can use the mean of x, y, and z:

(1/3)(x + y + z) = (8/3) * 360

x + y + z = 2880

Substituting the values we found for x and y, we get:

(110/9) + (22/3) + z = 2880

Multiplying both sides by 9, we get:

110 + (66/3) + 9z = 25920

110 + 22 + 9z = 25920

9z = 25788

z = 2864

Therefore, the values of x, y, and z are:

x = 110/9

y = 22/3

z = 2864

To find the range, we need to subtract the smallest value from the largest value:

Range = z - x = 2864 - (110/9) = 2,852

Therefore, the range of x, y, and z is 2,852.

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By the properties of rhombuses, m∠1 = 90°, m∠2 = 41°, and m∠3 = 49°.

A quadrilateral with all equal sides is a rhombus.

Rhombuses are a particular kind of parallelogram in which all of the sides are equal since the opposite sides of a parallelogram are equal.

A rhombus has 360° of interior angles total.

A rhombus's adjacent angles add up to 180°.

A rhombus's diagonals are perpendicular to one another and cut each other in half.

From the given figure and properties of the rhombus, m∠1 = 90°, As the diagonals bisect each other perpendicularly.

Now, The two diagonals have created 4 congruent right-angled triangles,

Therefore, m∠2 = 41°.

And m∠3 = 180° - (41° + 90°).

m∠3 = 49°.

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The value of R is -10.

The polynomial p(x)=x^(3)-3x^(2)+4x-12 can be expressed as p(x)=q(x)*(x-1)+R. To find the value of R, we need to divide the polynomial p(x) by (x-1) using synthetic division.

Set up the synthetic division by writing the coefficients of the polynomial p(x) in a row and placing the divisor (x-1) to the left of the row.

1 | 1 -3  4 -12
 |_____________

Bring down the first coefficient (1) and multiply it by the divisor (1) to get 1. Place this value below the second coefficient (-3) and add them to get -2.

1 | 1 -3  4 -12
 |   1
 |_____________
   1 -2

Multiply the new value (-2) by the divisor (1) to get -2. Place this value below the third coefficient (4) and add them to get 2.

1 | 1 -3  4 -12
 |   1 -2
 |_____________
   1 -2  2

Multiply the new value (2) by the divisor (1) to get 2. Place this value below the fourth coefficient (-12) and add them to get -10.

1 | 1 -3  4 -12
 |   1 -2  2
 |_____________
   1 -2  2 -10

The final value (-10) is the remainder, or the value of R.

Therefore, the value of R is -10.

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Using graph it is seen that the solution of the linear system  is found as (-1, 1).

The points for the two intersecting lines are-

Red points:  (0, 5), (-1, 1), and (-3, -6)

Green points: (-3, 5), (-2, 3), (-1, 1), (0, -1), (1, -3), and (2, -5).

Graph of there points are plotted.

Thus, it is seen that the solution of the linear system graphically  is found as (-1, 1).

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The correct question is-

Estimate the solution of the linear system graphically and check the solution algebraically:

A line graph showing 2 intersecting lines, the first line passes through the points (0, 5), (-1, 1), and (-3, -6) and the second line passes through the points (-3, 5), (-2, 3), (-1, 1), (0, -1), (1, -3), and (2, -5).

The Variation of Parameters is a method used to find a particular solution for ordinary differential equations (ODES). The method involves finding the general solution to the homogeneous equation and then using that to find a particular solution to the non-homogeneous equation.

For the given ODES:

(a) y" - 2y' + y = et^2

First, we need to find the general solution to the homogeneous equation y" - 2y' + y = 0. The characteristic equation is r^2 - 2r + 1 = 0, which has a repeated root r = 1. Therefore, the general solution to the homogeneous equation is yh = c1e^t + c2te^t.

Next, we use the Variation of Parameters to find a particular solution. We assume that the particular solution has the form yp = u1e^t + u2te^t, where u1 and u2 are functions of t. We then find the first and second derivatives of yp and substitute them into the original equation. After simplifying, we obtain a system of equations for u1' and u2'. We solve for u1' and u2' and then integrate to find u1 and u2. Finally, we substitute u1 and u2 back into the equation for yp to find the particular solution.

(b) y" + y = sec(x)

Similarly, we first find the general solution to the homogeneous equation y" + y = 0. The characteristic equation is r^2 + 1 = 0, which has complex roots r = i and r = -i. Therefore, the general solution to the homogeneous equation is yh = c1cos(x) + c2sin(x).

Next, we use the Variation of Parameters to find a particular solution. We assume that the particular solution has the form yp = u1cos(x) + u2sin(x), where u1 and u2 are functions of x. We then find the first and second derivatives of yp and substitute them into the original equation. After simplifying, we obtain a system of equations for u1' and u2'. We solve for u1' and u2' and then integrate to find u1 and u2. Finally, we substitute u1 and u2 back into the equation for yp to find the particular solution.

(c) y" + y = sin^2(x)

The general solution to the homogeneous equation y" + y = 0 is the same as in part (b). We use the Variation of Parameters to find a particular solution in the same way as in part (b), but with the right-hand side of the equation being sin^2(x) instead of sec(x).

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Answer: The inequality is:

1.2 + m ≤ 5.5

This inequality can be read as "the sum of 1.2 and m is less than or equal to 5.5."

To solve for m, you need to isolate it on one side of the inequality symbol.

1.2 + m ≤ 5.5

Subtract 1.2 from both sides:

m ≤ 5.5 - 1.2

Simplify:

m ≤ 4.3

Therefore, the solution to the inequality is m ≤ 4.3.

Step-by-step explanation:

Answer

10 is the answer

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The equation of the image is x = 32 - 2y which is dilated by a scale factor of 1/4 about the center.

Dilation is a process for creating similar figures by modifying the dimensions.

To dilate a line by a scale factor of 1/4 about the center, we can first find the coordinates of the center of dilation.

Since no center is given in the problem, we can assume that the center is the origin (0,0).

To find the equation of the image, we need to apply the dilation to the original line. The dilation multiplies all distances by the scale factor, so the image of the point (x, y) is (1/4)x, (1/4)y).

So, the image of line 8 - 2y = x under this dilation is:

8 - 2(1/4)y = (1/4)x

8 - (1/2)y = (1/4)x

32 - 2y = x

Therefore, the equation of the image is x = 32 - 2y.

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Answer:

$1.50

Step-by-step explanation:

3 boxes = $4.50

1 box= $4.50÷3

1box= $1.50

Answer:$1.50

Step-by-step explanation:

Answer: a = 3, b = 2

Step-by-step explanation:

When a system of linear equations has no solution, they are parallel and do not share the same y-intercept.

Parallel lines have the same slope so a must equal 3.

The first equation's y-intercept is -2, so the only other option is b = 2.

Hope this helps!

AB =

BC = 2x

T.P. =>

4x² = x² + 6²

3x² = 36

x² = 12

=> x = 2sqrt3

Answer: Dragonfly wings for the boys cost $1 while fairy wings for the girls cost $2. Phoebe's mom spent $18 on the gifts. How many dragonfly wings and fairy wings

Step-by-step explanation:

Answer:

The answer to the first question is A) P(c) = 2c, because the wings will be sold for double the cost of supplies.

The answer to the second question is B) N(p) = p - 0.3, because the price will be marked down by 30%.

The answer to the third question is A) 0.9c, which represents the markup of the discounted price over the supply cost.

The domain of all the functions is A) [0, infinity), because prices and costs must be positive numbers. Therefore, options B, C, and D are incorrect.