Answer:
360 watts
Explanation:
P =V × I
= 120×3.0
= 360
A newspaper carrier pulls a wagon with a force of 275 N at an angle of 45° to the horizontal. How much work is required to move the wagon 8 m?
Answer: 1100 [tex]\sqrt{2[/tex] N -m
Explanation:
As work = force × displacement
Because iron is more reactive than copper;it takes its place in a reaction with copper sulphate.What is the word equation?
Answer:
The word equation for the reaction between iron and copper sulfate can be written as:
Iron + Copper sulfate -> Iron sulfate + CopperThis is a displacement reaction, where the more reactive iron displaces the less reactive copper from the copper sulfate solution, forming iron sulfate and copper as products.
Explanation:
The balanced chemical equation for the reaction between iron and copper sulfate is:
Fe + CuSO4 → FeSO4 + CuThis equation shows that one atom of iron (Fe) reacts with one molecule of copper sulfate (CuSO4) to produce one molecule of iron sulfate (FeSO4) and one atom of copper (Cu). The equation is balanced, meaning that the same number of atoms of each element are present on both sides of the equation.
An object R leaves a platform XY with a horizontal velocity of 7ms1 and lands at Q. If it takes the same object 0.3s to fall freely from Y to P, calculate the distance PQ. (Take g = l0m−2 ) A. 7.30m B.2.55m C.2.l0m D. 1.65m E.0.45m
With a 7ms1 horizontal velocity, an object R departs from a platform XY and lands at Q. The length PQ is 0.45m if the identical object falls freely from Xy to P in 0.3 seconds.
Is the initial velocity constant across all angles?There is no possible for the items to have the same start y-component velocity unless they're shot with distinct initial speeds given that each is launched at a various perspectives. The objects must have been shot at different speeds if they had the same maximum height.
Why is a launch angle of 45 degrees ideal?We can observe that over the longest-range the signal reaches its maximum output value, 1, at an output data angle of 90 degrees Punts 2 are at a 90-degree angle, so is at a 45-degree angle. In other words, a projectile moves and furthest when it is fired at a 45-degree angle.
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J
Question 5 of 10
A pot of water is heated on a gas-flame stove and begins to boil. Which two
transfers of thermal energy involved in this system are examples of radiation?
A. From the burner to air that is not touching it
B. In the surrounding air as air currents develop
C. From the water to the air
D. From the burner to a nearby spoon
In this system, there are two thermal energy transfers that are instances of radiation: A. From the flame to air that isn't in contact with it D. From the hob to a spoon in the area
What kind of energy is transmitted to the water's particles when it is heated on a stove?Thermal energy can be seen in the boiling of water on a stove. As a substance's atoms and molecules vibrate more quickly as a result of a rise in temperature, thermal energy is created.
What is the process for transferring heat from the burner to the pot called?The most typical method of heat transfer is conduction, which involves the direct exchange of heat between two things. Burners on stoves, for instance, will transfer heat energy to the bottom of a pan that is resting on top of them when cooking. The pan then transfers the heat to its contents.
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What is the height of a shelf that has a 15 kg object with 450 J of gravitational potential energy?
Hello and greetings postlauraann.
So, the height of a shelf with an object that has a mass of 15 kg and Epg of 450 J, is 3.06 meters.
Explanation:We have that this exercise is gravitational potential energy.
We learn that:
Gravitational potential energy is the energy associated with the position of an object in a gravitational field. It is defined as the work done to move an object from a reference position to its current position against the gravitational force.
The formula for gravitational potential energy is:
Epg = m * g * hwhere:
Epg is the gravitational potential energy (in joules)m is the mass of the object (in kilograms)g is the acceleration due to gravity (approximately 9.8 m/s² at the Earth's surface)h is the height of the object above a reference position (in meters)He is asking us to calculate the height of a shelf that has an object with a mass of 15 kg, and an Epg of 450 Joules, knowing the gravity is 9.8 m/s².
What we do next is clear is the Epg formula, to calculate the height, then
Epg = m × g × hh = (Epg)/(m × g)Now, we substitute the data in the cleared formula to calculate the height:
h = (Epg)/(m × g)
h = (450 J)/(15 kg × 9.8 m/s²)
h = (450 J)/(147 kg × m/s²)
h ≅ 3.06 m
So, the height of a shelf with an object that has a mass of 15 kg and Epg of 450 J, is 3.06 meters.
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As a beam of light enters a swimming pool, it will_____
1. bend
2.remain on a straight path
3. be absorbed
because light waves____when they pass from one medium to a different medium.
1. reflect
2.refract
3.diffract
Answer:
bend
refract
................
A stick is resting on a concrete step with 29
of its total length
hanging over the edge. A single ladybug lands on the end of the stick hanging over the edge, and the stick begins to tip. A moment later, a second, identical ladybug lands on the other end of the stick, which results in the stick coming momentarily to rest at =62.1∘
with respect to the horizontal, as shown in the figure.
If the mass of each bug is 3.09
times the mass of the stick and the stick is 15.1 cm
long, what is the magnitude
of the angular acceleration of the stick at the instant shown? Use =9.81 m/s2.
In physics, angular acceleration refers to the time rate of change of angular velocity. the magnitude of the angular acceleration of the stick at the instant shown results in tan(θ/2) = 0.010 and θ= 1.15.
Let stand in for the angle formed by the directions of the vectors A and B. The magnitudes of A and B being equal, A, B, and R = A + B form an isosceles triangle with angles of 180, - θ/2, and θ /2. R then equals 2A cos (θ/2) to determine its magnitude. By using the fact that B=A and the isosceles triangle, the law of cosines can be used to demonstrate this.
Once more, A, -B, and D = A-B form an isosceles triangle with an angle at the top of. D = 2Asin(θ/2) is the result of using the law of cosines and the identity (1-cosθ ) = 2sin² (θ/2).
R must equal 100D for the equation to hold, hence 2A cos(θ/2) = 200A sin(θ/2).
This results in tan(θ/2) = 0.010 and θ= 1.15.
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If sound waves travel along a guitar string at 220 m/s (based on the medium it is made of), what would be the wavelength of the ‘C’ note from Problem 2 in this guitar string?
To calculate the wavelength of the 'C' note from Problem 2 in this guitar string, we also need to know its frequency. Assuming you're referring to the 'C' note with a frequency of 261.63 Hz (C4), we need to use the formula,
Using the formula, wavelength = speed / frequency, we can calculate the wavelength as follows:
Wavelength = Speed of Sound / Frequency
wavelength = 220 m/s / 261.63 Hz
wavelength = 0.8415 meters.
wavelength = 84.15 cm.
Therefore, the wavelength of the 'C' note on this guitar string is approximately 0.8415 meters or 84.15 cm.
therefore the correct answer is : his guitar string is approximately 0.8415 meters or 84.15 cm.
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A motorist travels a distance of 40 km during a 7 hour period. What was the average
speed? Round to nearest tenth.
Answer:
The average speed of the motorist was 5.7 kilometers per hour, rounded to the nearest tenth.
Explanation:
The average speed of the motorist can be calculated by dividing the distance traveled by the time taken.
[tex]\boxed{\sf Speed = \dfrac{Distance}{Time}}[/tex]
For this problem, the distance traveled is 40 km and the time taken is 7 hours.
Substitute these values into the formula:
[tex]\implies \sf Average\;speed = \dfrac{40\;km}{7\;hours}[/tex]
This simplifies to:
[tex]\implies \sf Average\;speed = 5.7\;km/h\;(nearest\;tenth)[/tex]
Therefore, the average speed of the motorist was 5.7 kilometers per hour, rounded to the nearest tenth.
Answer:
[tex] 5.7 \ km \ hr^{-1}[/tex]Explanation:
To find:-
The average speed.Answer:-
We are here given that, a motorist travels 40km in 7hrs . And we are interested in finding out the average speed of the motorist . We can find the average speed as ,
Average speed:-
It is defined as the total distance travelled divided by total time taken.Mathematically,
[tex]\longrightarrow \boxed{\rm v_{average}=\dfrac{Distance_{Total}}{Time_{Total }}} \\[/tex]
Here the total distance is 40km and the total time taken is 7hrs . So on substituting the respective values, we have;
[tex]\longrightarrow v_{average}=\dfrac{40\ km}{7\ hr} \\[/tex]
Simplify,
[tex]\longrightarrow v_{average}= 5.714 \ km \ hr^{-1} \\[/tex]
Rounding off to nearest tenth,
[tex]\longrightarrow \boxed{\boldsymbol{ v_{avg}= 5.7 \ km\ hr^{-1}}}\\[/tex]
Hence the average speed of the motorist to the nearest tenth is 5.7 km hr-¹ .
In a test of "g-suit," a volunteer is rotated in a horizontal circle of radius 7.0 m. What is the period of rotation at which the centripetal acceleration has a magnitude of (a) 3.0 g? (b) 10 g?
The rotational period during which the centripetal acceleration is 3.0 g is 4.35 s. The rotational period during which the centripetal acceleration is 10 g is 1.68 s.
What is the centripetal acceleration?centripetal acceleration is the rate at which a body moves through a circle. Because velocity is a vector number, it constantly changes while a body travels in a circle, which causes a change in velocity and an acceleration.
a = magnitude of the centripetal acceleration
r = radius of the circle
v = velocity
We can use the centripetal acceleration formula,
v = sqrt(ar)
(a) To find the period of rotation at which the centripetal acceleration has a magnitude of 3.0 g, we need to convert g into meters per second squared (m/s^2).
We know that 1 g = 9.8 m/s^2, so 3.0 g = 29.4 m/s^2.
we get,
v = sqrt(ar) = sqrt(29.4 x 7.0) = 20.3 m/s
The period of rotation,
T = 2πr / v
T = period of rotation.
T = 2π x 7.0 / 20.3 = 4.35 s
(b) To find the period of rotation at which the centripetal acceleration has a magnitude of 10 g,
We know that 1 g = 9.8 m/s^2, so 10 g = 98 m/s^2.
we get:
v = sqrt(ar) = sqrt(98 x 7.0) = 26.3 m/s
The period of rotation,
T = 2πr / v
T = period of rotation.
T = 2π x 7.0 / 26.3 = 1.68 s
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Write an essay on the meaning of life.
35 points cuz it's kinda hard
Answer:
The meaning of life is one of the most profound and enduring questions that has plagued humanity for centuries. Philosophers, scientists, and theologians have all attempted to answer this question in their own ways, yet it remains an enigma that has yet to be fully understood. At its core, the meaning of life is a subjective concept that is shaped by individual beliefs, experiences, and values. However, there are several common themes and ideas that have emerged from various attempts to answer this question. One of the most prominent views on the meaning of life is that it is to find purpose and fulfillment. This view suggests that we should strive to find something that gives our lives meaning, whether it be through our work, relationships, or personal pursuits. This idea is often associated with the concept of happiness, as many believe that true happiness can only be achieved by finding purpose and meaning in one's life. Another
PLEASE HELP ASAP!!
A vector has an x-component of -309m and a y-component of 187m. Find the magnitude of the vector
Therefore, the magnitude of the vector is approximately 361.3 meters.
How big is the output vector of 2?The magnitude of either vector is the same as the magnitude of the outcome of two equal vectors. As a result, the components of V 1 in the X and Y coordinates are, respectively, -6.6 units and 0 units.
Using the Pythagorean equation, we can determine the magnitude of a vector with x and y components:
|v| = √(x² + y²)
where |v| denotes the vector's size.
The vector in this instance has a y-component of 187 m and an x-component of 309 m.
When we enter these numbers into the solution, we obtain:
|v| = √((-309)² + (187)²)
|v| = √(95658 + 34969)
|v| = √(130627)
|v| ≈ 361.3
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What must be the current I
in the bar for the bar to be in rotational equilibrium when it is at an angle 30.0 ∘
above the horizontal? Use the fact that τ=12IBL2
for a uniform bar of length L
carrying a current I
in a magnetic field B
.
The current required for a uniform bar to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal and carrying a current I in a magnetic field B is zero, as the torque acting on the bar is zero at this angle.
To find the current I in the bar for it to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal, we need to use the torque equation for a uniform bar carrying a current I in a magnetic field B:
τ = 1/2 IBL² sinθ
where τ is the torque, I is the current, B is the magnetic field, L is the length of the bar, and θ is the angle of the bar relative to the magnetic field.
Since we want the bar to be in rotational equilibrium, the torque must be zero, so we can set the torque equation equal to zero:
0 = 1/2 IBL² sin30°
Solving for I, we get:
I = 0 / (1/2 B L² sin30°)
I = 0
Therefore, the current required for the bar to be in rotational equilibrium when it is at an angle of 30.0° above the horizontal is zero. This is because the torque acting on the bar is zero at this angle, which means that the bar is not experiencing any rotational force and is already in rotational equilibrium.
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A sample of iron with a mass of 2.00 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a temperature of 20.0°C is added to the container, and the entire interior of the container is allowed to come to thermal equilibrium, where it reaches a final temperature of 61.0°C. What mass of water (in kg) was added? Assume any water turned to steam subsequently recondenses.
sample of iron with a mass of 2.00 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a temperature of 20.0°C is added to the container, and the entire interior of the container is allowed to come to thermal equilibrium, where it reaches a final temperature of 61.0°C then the mass of water added is 5.5 kg.
the principle of conservation of energy, which states that the total energy in a system remains constant.
Q = mCΔT
First, let's calculate the amount of heat transferred by the iron:
Q_iron = m_iron * C_iron * ΔT_iron
Q_iron = (2.00 kg) * (449 J/kg·°C) * (-89.0°C)
Q_iron = -80062 J
where C_iron is the specific heat capacity of iron and is equal to 449 J/kg·°C.
The negative sign indicates that heat is lost by the iron.
Next, let's calculate the amount of heat gained by the water:
Q_water = m_water * C_water * ΔT_water
Q_water = (m_water) * (4186 J/kg·°C) * (41.0°C)
Q_water = 173326 J
where C_water is the specific heat capacity of water and is equal to 4186 J/kg·°C.
The positive sign indicates that heat is gained by the water.
Since the container is well-insulated, the total heat transferred is equal to zero:
Q_iron + Q_water = 0
Substituting the values we get:
-80062 J + 173326 J = 0
Simplifying, we get:
93264 J = 0
assuming that the calculation was correct, we can find the mass of water added by using the equation:
m_water = Q_water / (C_water * ΔT_water)
Substituting the values, we get
m_water = (93264 J) / (4186 J/kg·°C * 41.0°C)
m_water = 5.5 kg
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Two identical rectangular strips of copper and the steel are pivoted to form bimetallic strips. If the
coefficient of linear expansivity of copper is more than that of steal, what will happen on
heating?
When the bimetallic strip is heated, the copper strip will expand more than the steel strip due to its higher coefficient of linear expansivity. As a result, the bimetallic strip will bend towards the steel strip.
This occurs because the copper strip, which is on the outer side of the bend, expands more than the steel strip, which is on the inner side of the bend. This phenomenon is known as the bimetallic effect and is commonly used in thermostats, thermometers, and other devices that require precise temperature control. By using different combinations of metals with varying coefficients of linear expansivity, the sensitivity and temperature range of the device can be adjusted to meet specific requirements. When the bimetallic strip is heated, the copper strip will expand more than the steel strip due to its higher coefficient of linear expansivity. As a result, the bimetallic strip will bend towards the steel strip.
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An ice cube has a mass of 64 g and is initially at a temperature of 0°C . The ice cube is heated until 56.6 g has become water at 100°C and 7.4 g has become steam at 100°C. How much energy (in kJ) was transferred to the ice cube to accomplish the transformation?
Answer:
An ice cube has a mass of 64 g and is initially at a temperature of 0°C . The ice cube is heated until 56.6 g has become water at 100°C and 7.4 g has become steam at 100°C. How much energy (in kJ) was transferred to the ice cube to accomplish the transformation?
Two pure tones Cs and Gs, with frequencies from the Pythagorean diatonic scale, are sounded simultaneously. Find a) the frequencies of the three combination tones and b) the notes on the Pythagorean scale to which these tones belong.
The three combination tones have frequency that are roughly 882.33 Hz, 588.00 Hz, and 293.67 Hz. E, G, and D are the notes on the Pythagorean scale to which the combination tones correspond.
How does Pythagorean differ from simple tuning?Uniformity is provided by Pythagorean tuning, but not chords. The chords are provided via just tuning, which is based on the overtone series' simpler ratios, but it suffers from interval inequality. Even in simple music, meantone tuning produces multiple unfavourable chords despite offering equal intervals.
Sum tone frequency: F1 + F2
Difference tone frequency: F2 - F1
where F1 and F2 are the frequencies of the two pure tones.
Using the Pythagorean diatonic scale, we can find the frequencies of Cs and Gs:
Cs has a frequency ratio of 9/8 with C (fundamental frequency) and a frequency of (9/8) x 261.63 ≈ 294.33 Hz
Gs has a frequency ratio of 3/2 with G (fundamental frequency) and a frequency of (3/2) x 392.00 ≈ 588.00 Hz
Sum tone frequency: 294.33 + 588.00 = 882.33 Hz (approx.)
Difference tone frequency: 588.00 - 294.33 = 293.67 Hz (approx.)
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help please!!!
1 . A particle moves in a straight line with constant acceleration. The particle starts moving from rest. It takes the particle 2 seconds to travel 800 meters. Find the acceleration?
2. A golf ball accelerates off a tee at 15m/s2, changing its velocity from 10 m/s to 80m/s down the fairway. How long did it take the golf ball to accelerate?
3. A roller coasters accelerates from an initial velocity of of 40 m/s to a final velocity of 4.0 m/s over 4 seconds. What's the acceleration?
4. If the average speed of a car is 110 km/h, how long will it take the car to travel 715 km?
If a particle travels in a straight line while accelerating continuously. Starting at rest, the particle begins to move. The particle accelerates to a speed of 200 m/s² and travels 800 meters in 2 seconds.
The speed of a golf ball increases from 10 m/s to 80 m/s down the fairway as it accelerates off the tee at 15 m/s2. How much time did the golf ball need to accelerate?We can apply the formula: Initial velocity + acceleration over time equals velocity.
Here, initial velocity is equal to 10 m/s, final velocity is equal to 80 m/s, acceleration is equal to 15 m/s2, and we must determine the time.
Thus, 80 = 10 + 15 x time.
By solving for time, we obtain:
time = (80 - 10)/15, or 4 seconds.
A roller coaster accelerates throughout the course of 4 seconds from an initial speed of 40 m/s to a top speed of 4 m/s. How fast is it going?We can apply the formula: (Final velocity - Initial velocity) / Time = acceleration
Here, the initial speed is 40 m/s, the final speed is 4 m/s, and the time is 4 s.
Acceleration is therefore (4 - 40) / 4 = -9.0 m/s2. Remember that the roller coaster is decelerating, hence the acceleration is negative.
How long will it take a car travelling at an average speed of 110 km/h to cover 715 km?Time can be calculated using the formula: distance x speed.
Speed in this case is 110 km/h, and distance is 715 km.
Time therefore = 715 / (110/3600) = 28.7 hours.
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The total amount of charge that has entered a wire at time t is given by the expression Q=(20C)(1−e−t/(2.0s)) , where t is in seconds and t≥0 . Part A Part complete Find an expression for the current in the wire at time t . Assume the numeric values in your entry are in SI units. Express your answer in terms of t . I(t) = (10)e−t2 Previous Answers Correct Part B What is the maximum value of the current?
This equation has no real solutions, so the current does not have a maximum value. Instead, it approaches a limiting value of 0 as t approaches infinity.
To find the expression for the current in the wire at time t, we need to take the derivative of the expression for the charge with respect to time.
Q = (20C)[tex](1 - e^(-t/2.0s))[/tex]
dQ/dt = (20C)(1/2.0s)[tex](e^(-t/2.0s))[/tex]
dQ/dt = (10C/s)[tex](e^(-t/2.0s[/tex]))
So the expression for the current in the wire at time t is:
I(t) = dQ/dt = [tex](10C/s)(e^(-t/2.0s))[/tex]
To find the maximum value of the current, we can take the derivative of the expression for the current with respect to time and set it equal to zero.
dI/dt = [tex]-(5C/s^2)(e^(-t/2.0s))[/tex]
Setting dI/dt equal to zero, we get:
[tex]-(5C/s^2)(e^(-t/2.0s))[/tex] = 0
[tex]e^(-t/2.0s)[/tex]= 0.
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At time t = 0.00 s, a car is traveling along a straight line at a speed of 20 m/s with constant acceleration. The car travels 56.0 m during the time interval between t = 2.00 s and t = 4.00 s. What is the acceleration of the car?
Answer:
We can solve this problem using the following kinematic equation: d = vit + 1/2at^2 where d is the displacement, vi is the initial velocity, a is the acceleration, and t is the time interval. We are given that the car is traveling at a speed of 20 m/s at t=0.00 s, so the initial velocity is vi = 20 m/s. We are also given that the car travels 56.0 m during the time interval between t=2.00 s and t=4.00 s, so the displacement is d = 56.0 m and the time interval is t = 2.00 s - 0.00 s = 2.00 s. Plugging these values into the equation, we get: 56.0 m = (20 m/s)(2.00 s) +
A velocity field is given by u = Ax, v = -Ay; the units of velocity are m/s; x and y are given in meters; A = 0.3 s-¹. a) Obtain an equation for the streamlines in the xy plane. b) Plot the streamline passing through the point (xo, yo) = (2,8). c) Determine the velocity of a fluid particle at the point (2,8). d) If the fluid particle passing through the point (xo, yo) is marked at time t = 0, determine the location of the particle at time t = 6 s. e) What is the velocity of this fluid particle at time t = 6 s? f) Show that the equation of the fluid particle path (i.e., the pathline) is the same as the equation of the streamline.
Answer:
Explanation:
(A)The equation for the streamlines can be obtained by equating the differential element of the stream function to zero:
ψ = constant
dψ = 0
We know that u = ∂ψ/∂y and v = -∂ψ/∂x, so
dψ = udy - vdx
0 = Ady(x-x0) - Adx(y-y0)
0 = Ady x - Adx y - Ady x0 + Adx y0
0 = x(A dy) - y(A dx) + (dx y0 - dy x0)A
Thus, the equation for the streamlines is:
ˣ²-ʸ² = C
where C is a constant.
(B) To plot the streamline passing through point (2,8), we need to substitute these values into the equation for the streamline:
2² - 8² = C
C = -60
So the equation for the streamline passing through the point (2,8) is:
ˣ²-ʸ² = -60
(C) To determine the velocity of a fluid particle at the point (2,8), we substitute x = 2 and y = 8 into the given velocity field:
u = Ax = (0.3 ˢ⁻¹)(2 m) = 0.6 m/s
v = -Ay = -(0.3 ˢ⁻¹)(8 m) = -2.4 m/s
Therefore, the velocity of the fluid particle at points (2,8) is (0.6 m/s, -2.4 m/s).
(D) If the fluid particle passing through the point (2,8) is marked at time t = 0, we can determine its location at time t = 6 s by using the following equations for the path of the fluid particle:
dx/dt = A x
dy/dt = -A y
We can separate the variables and integrate them to obtain the following:
x = x0 ᵉ⁽ᴬ ᵗ⁾
y = y0ᵉ⁽⁻ᴬ ᵗ⁾
Substituting x0 = 2, y0 = 8, and A = 0.3 ˢ⁻¹, we get:
x = 2 ᵉ(⁰.³ ᵗ)
y = 8 ᵉ(-⁰.³ ᵗ)
So the location of the fluid particle at time t = 6 s is:
x = 2 ᵉ(⁰.³⁶) = 7.13 m
y = 8 ᵉ(-⁰.³⁶) = 3.19 m
Therefore, the fluid particle is located at (7.13 m, 3.19 m) at time t = 6 s.
(E) To find the velocity of the fluid particle at time t = 6 s, we differentiate the equations for x and y with respect to time:
dx/dt = A x = 0.3(7.13) = 2.14 m/s
dy/dt = -A y = -0.3(3.19) = -0.96 m/s
Therefore, the velocity of the fluid particle at time t = 6 s is (2.14 m/s, -0.96 m/s).
A machine off efficiency 80% is used to lift a box. If the effort applied by the machine is
twice the weight of the box. Calculate the velocity ratio of the machine.
Therefore, the velocity ratio of the machine is 0.004.
What do you mean when you say a machine's effectiveness is 60?If the machine has a 60% efficiency, it can convert 60% of input labour into output. If we add 100 J of work to the machine as input and the machine's efficiency is 60%, we will only get 60 J of work as an output.
The machine's effectiveness is listed as 80%, or 0.8.
Efficiency = (Output work/Input work) x 100%
0.8 = (Output work/Input work) x 100%
Output work = (Effort x Distance moved by effort)
Output work = (2W x D)
Output work = 2WD
Input work = (Weight of the box x Distance moved by the box)
Input work = (W x D)
When we enter the output work and input work numbers into the efficiency equation, we obtain:
0.8 = (2WD / WD) x 100%
0.8 = 2 x Velocity ratio x 100%
Velocity ratio = 0.8 / (2 x 100%)
Velocity ratio = 0.004
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Astronauts collected a lunar rock with a mass of 73 grams. What was the
rock's weight when they brought it back to Earth? (1 point)
1. 0.715 N
2. 715 N
3. 0.118 N
4. 0.007 N
Answer: 0.715
Explanation: from grams to newtons
Amanda runs a business in a market where all firms are price takers. Bob suggests that she lower her price to attract even more customers. Should Amanda follow Bob's suggestion? Should she consider raising her price?
Amanda should carefully consider the elasticity of demand, cost of production, and competition before deciding whether to lower or raise prices. The ultimate goal is to find the right balance between attracting customers and maintaining profitability.
In a market where all firms are price takers, lowering the price may attract more customers, but it may also lead to lower profit margins. It is essential to weigh the potential benefits and costs of lowering the price before making a decision.
Amanda should consider several factors before deciding whether to follow Bob's suggestion or raise her price. These factors may include the elasticity of demand for her products, the cost of production, the pricing strategy of her competitors, and the level of competition in the market.
If the demand for Amanda's products is elastic, meaning that customers are very sensitive to price changes, lowering the price may increase the quantity sold but may not lead to higher revenues. In this case, Amanda may need to consider other strategies to increase revenue, such as expanding her product line or improving the quality of her products.
If the demand for Amanda's products is inelastic, meaning that customers are less sensitive to price changes, lowering the price may lead to increased revenue. However, Amanda should still consider the cost of production and ensure that the lower price still results in a profit.
Raising the price may be a viable option if Amanda has a unique product or a competitive advantage over her competitors. A higher price may signal higher quality or exclusivity, which can attract customers who are willing to pay a premium for the product. However, Amanda should ensure that the price increase does not lead to a significant decline in the quantity sold.
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8. What is the natural force of attraction between any massive bodies.
a. Weight
b. Gravity
c. Friction
Answer:
Friction
Explanation:
Neglecting air resistance, firing a projectile at an angle of ____
degrees will allow it to have the greatest horizontal displacement or ____
First blank answers :
45
60
90
Second blank answer choices:
Height
Trajectory
Range
Neglecting air resistance, firing a projectile at an angle of 45
degrees will allow it to have the greatest horizontal displacement or range.
We can prove this by using the range formula, which is...
[tex]R=\frac{v^2sin(2 \theta)}{g}[/tex]
In order to maximize the value R, [tex]sin(2 \theta)[/tex] has to be equal to 1. What values of theta make sine equal 1? In degrees, that would be 90. So if we let θ equal 45 we get....
[tex]R=\frac{v^2sin(2 (45))}{g} \Longrightarrow R=\frac{v^2sin(90)}{g} \Longrightarrow R=\frac{v^2(1)}{g}[/tex]
Thus, the value of R is maximized.
One litre of oxygem combines with one litre of hydrogen to produce one litre of hydrogen
peroxide.Given that the molecules of oxygen and hydrogen contain two atoms each, determine the
number of atoms in a molecule of hydrogen peroxide. Show your work.
The molecule of hydrogen peroxide contains four atoms.
Number of atoms calculation.The chemical equation for the reaction between oxygen and hydrogen to form hydrogen peroxide is:
O2 + 2H2 → 2H2O2
This equation shows that one molecule of oxygen (O2) reacts with two molecules of hydrogen (H2) to produce two molecules of hydrogen peroxide (H2O2).
We are given that one liter of oxygen (O2) combines with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2). Since one mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters, we can assume that one mole of oxygen (O2) reacts with one mole of hydrogen (H2) to produce one mole of hydrogen peroxide (H2O2) at STP.
Using Avogadro's number (6.022 x 10^23), we can calculate the number of molecules of each substance in one mole:
Oxygen (O2): 1 mole = 6.022 x 10^23 molecules
Hydrogen (H2): 1 mole = 6.022 x 10^23 molecules
Hydrogen peroxide (H2O2): 1 mole = 6.022 x 10^23 molecules
From the balanced chemical equation, we know that two molecules of hydrogen peroxide (H2O2) are produced for every one molecule of oxygen (O2) that reacts. Therefore, the number of molecules of hydrogen peroxide (H2O2) produced is equal to the number of molecules of oxygen (O2) that react.
Since we are given that one liter of oxygen (O2) reacts with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2), we can say that the volumes of the gases are proportional to their number of molecules. Therefore, the number of molecules of hydrogen peroxide (H2O2) produced is also equal to the number of molecules of hydrogen (H2) that react.
So, we can start with one mole of hydrogen (H2) and use the balanced chemical equation to find the number of moles of hydrogen peroxide (H2O2) produced:
1 mole H2 → 2 moles H2O2
Since one molecule of hydrogen peroxide (H2O2) contains two hydrogen atoms and two oxygen atoms, we can find the total number of atoms in a molecule of hydrogen peroxide:
2 hydrogen atoms + 2 oxygen atoms = 4 atoms
Therefore, a molecule of hydrogen peroxide contains four atoms.
In summary:
The chemical equation for the reaction between oxygen and hydrogen to form hydrogen peroxide is: O2 + 2H2 → 2H2O2
One mole of oxygen (O2) reacts with two moles of hydrogen (H2) to produce two moles of hydrogen peroxide (H2O2).One liter of oxygen (O2) reacts with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2).Using Avogadro's number, we can calculate the number of molecules of each substance in one mole.Since the number of molecules of hydrogen peroxide (H2O2) produced is equal to the number of molecules of hydrogen (H2) that react, we can find the number of atoms in a molecule of hydrogen peroxide by considering the atoms in a molecule of hydrogen. Therefore, a molecule of hydrogen peroxide contains four atoms (two hydrogen atoms and two oxygen atoms).
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The terminal velocity of a 3 × 10−5 raindrop is about 9 m
/
s. Assuming a drag
force = −, determine (a) the value of the constant b and (b) the time required
for such a drop, starting from rest, to reach 63% of terminal velocity.
Answer:
The drag force on an object is given by the equation:
F_d = -bv^2
where F_d is the drag force, b is a constant that depends on the properties of the fluid and the shape of the object, and v is the velocity of the object.
We know that for a 3 × 10^(-5) raindrop, the terminal velocity is about 9 m/s. At terminal velocity, the drag force balances the weight of the raindrop, so we can write:
F_d = mg
where m is the mass of the raindrop and g is the acceleration due to gravity (9.8 m/s^2).
Using these equations, we can solve for the value of b:
mg = bv_t^2
b = mg/v_t^2
Plugging in the values given, we get:
b = (3 × 10^(-5) kg)(9.8 m/s^2)/(9 m/s)^2
b ≈ 3.14 × 10^(-5) kg/m
To find the time required for the raindrop to reach 63% of terminal velocity, we can use the following equation:
v(t) = v_t(1 - e^(-kt/m))
where v(t) is the velocity of the raindrop at time t, k is a constant related to b and the density of the fluid (air), and e is the base of the natural logarithm.
At 63% of terminal velocity, v(t) = 0.63v_t. Plugging this into the equation above and solving for t, we get:
t = -m/k * ln(1 - 0.63)
Plugging in the values of m, k, and b, we get:
t = -(3 × 10^(-5) kg)/(0.5 * 1.2 kg/m^3 * 3.14 × 10^(-5) kg/m) * ln(0.37)
t ≈ 0.068 s
Therefore, it would take approximately 0.068 seconds for the raindrop to reach 63% of its terminal velocity.
A cylindrical glass of height h = 10 cm was covered with a piston of mass 3.5 kg and has a cross sectional area of 450 cm2.
(i) Determine the pressure that is exerted by this piston on the gas in the chamber, as shown in the figure. Assume gravitational acceleration 'g' to be 9.81 m/s2. (3)
(ii) Determine the work done when the same cylinder is heated afterwards at a constant pressure of 1 atm and its initial volume changes from Vo to 3Vo. (3)
Answer:
(i) The pressure exerted by the piston on the gas in the chamber can be calculated using the formula:
Pressure = Force / Area
The force exerted by the piston on the gas is equal to its weight, which can be calculated as:
Force = mass x gravitational acceleration
= 3.5 kg x 9.81 m/s^2
= 34.335 N
The area of the piston is 450 cm^2, which is equal to 0.045 m^2.
Therefore, the pressure exerted by the piston on the gas is:
Pressure = Force / Area
= 34.335 N / 0.045 m^2
= 763 N/m^2 or 763 Pa
(ii) The work done when the cylinder is heated at a constant pressure of 1 atm can be calculated using the formula:
Work = Pressure x Change in Volume
The initial volume of the cylinder is Vo, and the final volume is 3Vo. Therefore, the change in volume is:
Change in Volume = 3Vo - Vo
= 2Vo
The pressure is given as 1 atm, which is equal to 101,325 Pa.
Therefore, the work done is:
Work = Pressure x Change in Volume
= 101,325 Pa x 2Vo
= 202,650 Pa.Vo or 202,650 J:
I need help this subject is kinda hard for me
An atom is considered neutral when it has an equal number of protons (positively charged) and electrons (negatively charged).
When an atom gains or loses electrons, it becomes an ion, which is an atom with an unequal number of protons and electrons, resulting in a net positive or negative charge.
If an atom gains electrons, it becomes an anion with a negative charge. If an atom loses electrons, it becomes a cation with a positive charge.
The magnitude of the negative or positive charge of an ion is equal to the number of electrons gained or lost, respectively.
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