Every neutral atom of a given element has the same number of what two subatomic particles?
A. Protons and neutrons
B. Protons and electrons

Electronic configuration of carbon at excited state is 1s₂, 2s₂, 2p₂. so, option A is correct.

What is electronic configuration ?

According to electronic configurations, each electron moves individually within an orbital while being surrounded by an average field produced by all other orbitals.

Electronic configuration includes the number of shell, orbit, orbital. s, p, d, f different shell present in it.

One orbital can house a maximum of two electrons, and there are four different types of orbitals (s, p, d, and f). More electrons can be held in the p, d, and f orbitals since they contain various sublevels.

As was said, each element's position on the periodic table determines the specific electron configuration of that element.

Thus, option A is correct.

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The molar mass of gas = 206.36 g/mol

In general, the gas equation can be written

[tex]\large{\boxed{\bold{PV=nRT}}}[/tex]

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

mass (m)= 2.89 g

volume(V) = 346 ml = 0.346 L

T = 28.3 C + 273 = 301.3 K

P = 760 mmHg=1 atm

The molar mass (M) :

[tex]\tt PV=\dfrac{m}{M}RT\\\\M=\dfrac{mRT}{PV}\\\\M=\dfrac{2.89\times 0.082\times 301.3}{1\times 0.346}\\\\M=206.36~g/mol[/tex]

Answer:

A Cellulose not digested by humans.

b. the storage form of carbohydrates in plants is starch

C amylose contains 1-4 glycosidic bond

D Glycogen and starch are highly branched polysaccharides.

Explanation:

The name of one or more polysaccharides that matches each of the following descriptions are given as: a. not digestible by humans- cellulose, b. the storage form of carbohydrates in plants-starch, c. contains only oc (1-4)-glycosidic bonds-amylose, d. the most highly branched polysaccharide-glycogen.

Monosaccharides—repeated sugar units—are joined by glycosidic linkages to form polysaccharides, which are large, complex carbohydrates. They are polymers consisting of hundreds of monosaccharide molecules or even thousands of them.

a. Humans cannot digest the carbohydrate known as cellulose. It is a part of the structure of plant cell walls.

b. The plant stores carbohydrates in the form of starch. It functions as a store of energy and is made up of the molecules amylose and amylopectin.

c. A polysaccharide called amylose only has linkages that are (1-4)-glycosidic. It consists of glucose units joined together by (1-4)-glycosidic linkages, and is a linear polymer.

d. The polysaccharide that has the most branches is glycogen. In particular, the liver and muscles, it is the most prevalent form of carbohydrate storage in both animals and people.

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Answer:

The answer is 2.31×10^12

Explanation:

(4.2×10^9)(5.5×10^2)

(4.2×5.5)×(10^9×10^2)

23.1×10^9+2

23.1×10^11

Answer:2.31×10^12

Explanation:

Given parameters:

Density of the ethanol  = 0.789g/mL

Volume of the ethanol in the cylinder = 900mL

Unknown:

Mass of the ethanol  = ?

Solution:

Since density is the mass per unit volume of a substance;

      mass  = density x volume

Now insert the parameters and solve;

   mass  = 0.789g/mL x 900mL

   mass  = 710g

In scientific notation we have 7.10 x 10²g

Answer:

B. habitat

Explanation:

got it right on my test hope this helps:)

Answer:

It's habitat.

Explanation:

I took the Module 3 Exam and got it right.

Answer:

Strontium (Sr)

Explanation:

Atomic number 38

Relative atomic mass 87.62

Answer:

The correct answer is 82.18%.

Explanation:

Based on the given information, the mass of the pure soluble bromide compound is 0.4708 grams, and the mass of the formed silver bromide is found to be 0.9093 grams.

The molecular weight of AgBr is 187.77 g/mol, and the molecular weight of Br is 79.9 g/mol.

So, 0.9093 grams of AgBr comprise (79.9 * 0.9093)/187.77 = 0.3869 grams of bromine.

Now, 0.4708 grams of sample comprise 0.3869 grams of bromine. Therefore, 100 grams of sample comprise (0.3869*100) / 0.4708 g = 82.18 grams of bromine.

The mass % of bromine in the original compound is 82.18%.

The density of the rock in g/mL : 14 g/ml

Complete question :

A rock with a mass of 70 grams is dropped into a graduated cylinder with 30 mL of water in it. The water level rose to 35 mL calculate the density of the rock in g/mL

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

[tex]\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}[/tex]

ρ = density  

m = mass  

v = volume  

mass of rock = 70 g

Volume of the rock : 35 - 30 = 5 ml

So the density :

[tex]\tt \rho=\dfrac{70}{5}\\\\\rho=14~g/ml[/tex]

Answer:

I think its 117

Explanation:

H20

2*39 (hydrogens)

78

78+39(oxygens)

117

Answer: equivalence point

When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the equivalence point.

The equivalence point is called the moment when the equivalents of the titrated substance and those of the titrant substance are equal.

When a strong acid is neutralized with a strong base, the pH undergoes a sharp change just at the equivalence point.

At the time of neutralization, it is true that the number of equivalents of acid that have reacted is equal to the number of equivalents of the base.

This equivalence point is very easily detected since a sharp pH jump is observed in its vicinity, which can be detected in a pH meter or with an indicator.

Therefore, we can conclude that the equivalence point of a reaction is the point at which an equivalent amount of acid and base has been added.

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Answer:

6CO2 + 6H2O → C6H12O6 + 6O2 is a balanced equation

Explanation:

Carbon, Oxygen, Hydrogen

Reactants are carbon dioxide and water, products are glucose and oxygen

Dynamic Equilibrium I have no idea about (soz)

I believe this might be endothermic

Answer:

ZnCl2

H2

Explanation:

The products of the given reaction is:

      ZnCl₂  and H₂

The two species are the products of the chemical combination

Answer:runner has a1 and a2 it is heterozygous because it is two different gene verions.

Explanation:

The average atomic mass of the element, Uk is 67.44 amu.

The average atomic mass of the element Uk is determined from the sum of the isotopic masses of the isotopes of the element and their relative abundances.

The isotopic masses and relative abundance of the isotopes are given below:

Isotope:Uk-66; Isotopic mass = 65.994; relative abundance = 58.00%

Isotope:Uk-69; Isotopic mass = 68.958; relative abundance = ?

Isotope:Uk-71; Isotopic mass = 70.975; relative abundance = 10.00%

Relative abundance of Uk-69 = 100% - (58 + 10)% = 32%

The average atomic mass of Uk =  (65.994 * 58.00%) + (68.958 * 32%) + (70.975 * 10.00%)

The average atomic mass of Uk = 67.44 amu

In conclusion,  the average atomic mass of an element is obtained from the of the isotopic masses of the isotopes of the element and their relative abundances.

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Answer:

V ≈ 646.50 L

General Formulas and Concepts:

Chemistry - Gas Laws

Explanation:

Step 1: Define

RxN:   N₂H₄ (g) + O₂ (g) → N₂ (g) + 2H₂O (l)

Given:   34.9 °C, 755.08 torr, 914.894 g H₂O

Step 2: Identify Conversions

Kelvin Conversion

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

Stoichiometry:   [tex]914.894 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} )(\frac{1 \ mol \ N_2}{2 \ mol \ H_2O} )[/tex] = 25.3955 mol N₂

Temperature:    34.9 + 273.15 = 308.05 K

Step 4: Find Volume

Step 5: Check

We are given 5 sig figs as our lowest. Follow sig fig rules and round.

646.502 L ≈ 646.50 L

Answer:

yh thats true lol, ty for that very interesting fact

If the pH is higher the concentration of hydrogen ions becomes less and the solution becomes less acidic.

As the pH becomes lower, the concentration of hydrogen ions becomes greater, and the solution becomes more acidic.

HOPE IT'S HELPFUL : )

Answer:

it contains O3, therefore making it an oxide

Answer:

iron (11) oxide

Explanation:

Answer:

The answer is "23765.4"

Explanation:

Motor weight average number [tex](\bar{M_n}) = 1000000 \frac{g}{mol}[/tex]

Poly condensation degree dependent on the average number of molecular weights is as follows:

[tex]DP_n = \frac{\text{Mol.Wt Number Medium}}{\text{Monomer Unit Mol.Wt}}[/tex]

All monomer module, in this case, is propylene  

Sunrise. Unit Wt = Mol. Propylene weight

                           [tex]= \ Mol. \ Wt \ of \ C_3H_6\\\\= 3 \times 12.01 +6 \times 1.008 \ \ \frac{g}{mol}\\\\= 42.078 \frac{g}{mol}\\\\[/tex]

[tex]DP_n = \frac{1000000}{42.078}\\\\[/tex]

    [tex]=23765.4[/tex]

Answer:

The correct answer is 70.41 kJ ≅ 70.4 kJ

Explanation:

The heat required to sublimate the solid at its sublimation temperature is calculated by using the following formula:

heat = ΔHs x moles of substance

Where ΔHs is the heat of sublimation, which is known (32.3 kJ/mol).

So, we have to calculate the moles of substance. For this, we can divide the mass of substance by the molecular weight of substance (CO₂):

mass CO₂ = 96.0 g

molecular weight CO₂ = (12 g/mol x 1) + (16 g/mol x 2) = 44 g/mol

⇒ moles of CO₂ = mass CO₂/molecular weight CO₂ = (96.0 g)/(44 g/mol) = 2.18 moles

Finally, we use the first formula to calculate the heat:

heat = ΔHs x moles = 32.3 kJ/mol x 2.18 mol = 70.41 kJ ≅ 70.4 kJ

Answer:

good luckkkkkkkkkkkkkkk

Answer:

K^+ and NO3-

Explanation:

The correct answer to the question is Option C. K⁺ and NO₃¯

Spectator ions are ions that remains unchanged in a reaction i.e they can be seen in the reactants and products of a particular reaction.

To obtain the spectator ions in the reaction between KCl (aq) and AgNO₃ (aq), we shall write the ionic equation. This is illustrated below:

KCl (aq) —> K⁺(aq) + Cl¯(aq)

AgNO₃ (aq) —> Ag⁺(aq) + NO₃¯(aq)

KCl (aq) + AgNO₃ (aq) —>

K⁺(aq) + Cl¯(aq) + Ag⁺(aq) + NO₃¯(aq) —> AgCl(s) + K⁺(aq) + NO₃¯(aq)

From the ionic above, we can see that K⁺ and NO₃¯ appears on both side of the equation.

Therefore, K⁺ and NO₃¯ are the spectator ions.

Thus, Option C. K⁺ and NO₃¯ gives the correct answer to the question.

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Answer:

Explanation:

The final pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the new pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

From the question we have

[tex]P_2 = \frac{25 \times 2}{100} = \frac{50}{100} = \frac{1}{2} \\ [/tex]

We have the final answer as

Hope this helps you

The ionization energy increases as the ration of protons to electrons increases.

On the periodic table, as we move from left to right through a period, the initial ionization energy rises. This is due to the outermost electron becoming more closely bound to the nucleus as the nuclear charge increases.

Ionization energy - the energy needed to remove an electron from a gaseous atom, is the one that best exemplifies periodic behavior.

The energy needed to remove each additional electron from an atom grows gradually, with the removal of an electron from a filled inner shell causing a significant increase.

A stable atom becomes electrically imperfect or imbalanced if we remove one of its electrons. In other words, the nucleus's protons (positive charges) outnumber its electrons (negative charges). It is a positive ion because the atom has a plus-one charge after losing an electron.

Therefore on removing the second electron more ionization energy will be required than first. So option D is correct.

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427 g Mo

Chemistry

Atomic Structure

Math

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

2.68E24 atoms Mo or 2.68 × 10²⁴ atoms Mo

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Mo - 95.94 g/mol

Step 3: Convert

[tex]2.68 \cdot 10^{24} \ atoms \ Mo(\frac{1 \ mol \ Mo}{6.022 \cdot 10^{23} \ atoms \ Mo} )(\frac{95.94 \ g \ Mo}{1 \ mol \ Mo} )[/tex] = 426.966 g Mo

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

426.966 g Mo ≈ 427 g Mo

Answer:

wind blowing

Explanation:

"Wind is energy in motion—kinetic energy"

Answer: Wind Blowing

Explanation:

Answer:

bent

Explanation:

The chlorite ion has been pictured in the image attached with its two main resonance contributors.

The ion has four regions of electron density as shown. On the basis of the VSEPR theory, we expect a tetrahedral geometry.

However, the ion is bent due to the effect of the lone pairs on chlorine which is the central atom in the ion. This distorts the bond angle of the ion hence the ion has a bent molecular geometry.