Answer:
3x + 7
Step-by-step explanation:
Hope this helps you :)
13. The Largo
Middle School track team needs new
uniforms. The students plan to sell plush toy tigers
(the school mascot) for $5. The students find three
companies online that sell stuffed mascots.
a.
Which company has the lowest cost per tiger?
b. If they use that company, how much profit
will the students make for each tiger sold?
a) The lowest cost per tiger is $2.74, according to Company C. (Divide the costs by how many stuffed animals there are; in this case, it's $41.10/15).
b) They would make $2.26 profit for each tiger sold.
How to know which company has the lowest cost per tiger and how much profit will the students make for each tiger sold?You must divide the pricing by the anticipated number of sales to determine how much money customers must pay for each plush toy. For Company C, the calculation would be $41.10 divided by 15. You'll discover that Company C is the least expensive of all the companies when you do that.
By deducting $2.74 from $5, you can calculate their profit.
Although they had to spend $2.74 to purchase the plush animals, they are selling it for $5. $5 - $2.74 = $2.26
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Again it’s me, PLEASE PLEASE PLEASE I am so tired it’s 10 pm and I literally do not know what to do for this question if any of you know what to do please solve it
Answer:
x=1 and 4
suppose t=x1.5
Find all real solutions of the equation, rounded to two decimals. (Enter your answers as a comma-separated list.)
x^4 − 4x^2 + 2 = 0
The real solution of the equation are +0.77, -0.77, +1.85, -1.85.
What is quadratic equation?A quadratic equation is a second-order polynomial equation in a single variable x, ax²+bx+c=0. with a ≠ 0 .
Given:
x^4 − 4x^2 + 2 = 0
(x²)² - 4x² + 2 =0
let us consider y= x², then the above equation become
y² - 4y + 2 =0
On further solving for 'y' we have
y= -b±√(b² -4ac) / 2a
y= 4±√(16-8)/2
y=4±2√2/2
y= 2 + √2, y=2-√2
Now, y= x²
x² = (2 + √2), x²= 2-√2
x= +1.8477, -1.8477 , +0.7653, -0.7653
x= +0.77, -0.77, +1.85, -1.85
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[tex]6\frac{1}{3}+4\frac{3}{4}+3\frac{7}{12}=[/tex]
Answer:
14[tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Make equivalent fractions with all the same denominator. Let's us 12 as our common denominator
[tex]\frac{1}{3}[/tex] x [tex](\frac{4}{4})[/tex] = [tex]\frac{4}{12}[/tex] Another name for [tex]\frac{4}{4}[/tex] is 1. (4 divided by 4 is 1) I am just making an equivalent fraction of [tex]\frac{1}{3}[/tex]
[tex]\frac{3}{4}[/tex] x [tex](\frac{3}{3})[/tex] = [tex]\frac{9}{12}[/tex] another name for [tex]\frac{3}{3}[/tex] is 1 (3 divided by 3 is 1) I am just making an equivalent fraction of [tex]\frac{3}{4}[/tex].
Now that my denominators are all the same size I can see how many 12's I have.
6 [tex]\frac{4}{12}[/tex] + 4 [tex]\frac{9}{12}[/tex] + 3 [tex]\frac{7}{12}[/tex] I can rearrange this to add all the whole numbers together and all of the fractions together.
6 + 4 + 3 = 13
[tex]\frac{4}{12}[/tex] + [tex]\frac{9}{12}[/tex] + [tex]\frac{7}{12}[/tex] = [tex]\frac{20}{12}[/tex] I have 20 12ths. every [tex]\frac{12}{12}[/tex] makes another whole, so
[tex]\frac{20}{12}[/tex] 1 whole with [tex]\frac{8}{12}[/tex] Left over. If we put this all together, we have
13 + 1 + [tex]\frac{8}{12}[/tex]
14 [tex]\frac{8}{12}[/tex] To simplify this. I will divide [tex]\frac{8}{12}[/tex] ÷ [tex]\frac{4}{4}[/tex] = [tex]\frac{2}{3}[/tex].
the final answer is 14 [tex]\frac{2}{3}[/tex]
what is the perimeter of (-2,1) (3,1) (3,-1) (-2,-1)
Answer:
14
Step-by-step explanation:
Given the points (-2,1), (3,1), (3,-1), and (-2,-1) that are the vertices of a quadrilateral, you want to find the perimeter.
PerimeterThe perimeter of a plane figure is the sum of the lengths of its sides. When you plot these points, you see they define a rectangle with horizontal sides of length (3-(-2)) = 5, and vertical sides of length (1 -(-1)) = 2. There are two sides of each of these lengths, so the perimeter is ...
P = 2(L+W) = 2(5 +2) = 2(7)
P = 14
The perimeter of the figure is 14 units.
__
Additional comment
When trying to work out measures associated with a set of points, it is often useful to graph those points.
5x - 7 > 8 ?? what is the answer solve the inequality
Answer:
Step-by-step explanation:
Explanation:
This can be rewritten as
−
18
<
5
x
+
7
<
2
To solve this, isolate
x
. The first step will be subtracting
7
. However, subtract
7
from all parts of the inequality.
−
18
−
7
<
5
x
+
7
−
7
<
2
−
7
Which yields
−
25
<
5
x
<
−
5
Now, divide each part by
5
.
−
5
<
x
<
−
1
wolframalpha.com
Answer:
x>3
Step-by-step explanation:
Thats all hope this helps.
Answer for brainlyist
There are 2 pictures.
1. The equation 4x=7(x-3) is x=7.
2. Given ∠2≅∠4 and ∠2 and ∠3 are supplementary. we have proved ∠1≅∠3.
Given that,
There are 2 pictures.
1st picture is
We have to solve the given equation.
Equation is 4x=7(x-3)------> given
4x=7x-21 ---------> multiplying 7 to x and -3
4x-7x=-21
-3x=-21 --------> taking 7x to right side and subtracting 4x and 7x
x=-21/-3
x=7--------> taking -3 to left we get divided by 21, after division we got 7
Therefore, the equation 4x=7(x-3) is x=7.
2nd picture is
We have to prove the statement.
∠2≅∠4 --------> given
m ∠2=m ∠4 --------> angle congruence postulate
∠2 and ∠3 are supplementary ----------> given
m ∠2+m ∠3=180° ---------> Definition of supplementary angles
∠1 and ∠4 are supplementary ------> ∠2 ≅∠4 and ∠2 and ∠3 are supplementary then ∠2 and ∠1 also supplementary then ∠1 and ∠4 are supplementary.
m ∠1+m ∠4=180° --------> Definition of supplementary
m ∠1+m ∠4=m ∠2+m ∠3 ------> from step 4 we can write
m ∠1+m ∠4=m ∠4+m ∠3 -------> we know ∠2≅∠4
m ∠1=m ∠3 --------> ∠4 is remove from both sides.
∠1≅∠3 --------> definition of midpoint
Therefore, the statement is proved.
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Line Segment AD=11x+10.6. Find the length of AB and CD. Show all work
The lengths of AB and CD are 12 and 26.5 units
How to find the lengths of AB and CD?The given parameters are
AB = 2x + 3
BC = 21
CD = 7x - 5
AD = 11x + 10
The points are on line AD
So, we have
AD = AB + BC + CD
This gives
11x + 10 = 2x + 3 + 21 + 7x - 5
Evaluate the like terms
2x = 9
Divide by 2
x = 4.5
Substitute x = 4.5 in AB = 2x + 3 and CD = 7x - 5
AB = 2 * 4.5 + 3 = 12
CD = 7 * 4.5 - 5 = 26.5
Hence, the lengths of AB and CD are 12 and 26.5 units
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A new Community Sports Complex is being built in Del Rio. The perimeter of the rectangular playing field is 354 yards.
The length of the field is 7 yards less than triple the width. What are the dimensions of the playing field?
We need to know about the perimeter of a rectangle to solve this problem.The length of the field is 131 yards and width is 46 yards.
The perimeter of a rectangle is the summation of it's length and breadth, the longer side of a rectangle is called length and the shorter side is called breadth. The perimeter of a rectangle is given by the formula 2(l+b) where l is the length of the rectangle and b is the breadth of the rectangle. In this question we have been told the perimeter of the rectangular field is 354 yards. The length of the field is 7 yards less than triple the width. Let the width of the field be x yard, then the length is
length=3x-7
Then perimeter in terms of x= 2(l+b)=2((3x-7)+x)=2(4x-7)=8x-14
8x-14=354
8x=368
x=46
Then breadth=46 yards
length =3x-7=138-7=131 yards
Therefore we found out the dimensions of the field to be, the length is 131 yards and breadth is 46 yards.
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What is the volume of a cube with
1/3 inch sides?
Answer:
1/27 in^3.
Step-by-step explanation:
1/3 * 1/3 * 1/3
can someone awnser this for me please?
Answer:
1.Yes
2.Yes
3.No
4.Yes
5.Yes
6.No
I hope it's help
Answer:
1. yes
2.Yes
3.no
4.no
5.yes
6.yes
Step-by-step explanation:pa brainliest po thankyou
A survey of 163 persons was conducted at TCC, and it was found that 90 persons carried a cell phone, 81 persons carried a tablet computer, and 43 carried both a cell phone and a tablet.
1. The number of people who carried a cell phone or a tablet is 128.
2. The probability that a person carries a cell phone or a tablet is 78.5%.
3. The number of people who carried neither a cell phone nor a tablet is 35.
4. The probability that a person carried neither a cell phone nor a tablet is 21.5%.
5. The number of people who carried a cell phone only is 43.
6. The probability that a person carried a cell phone only is 26.4%.
7. The number of people who carried a tablet but not a cell phone is 38.
8. The probability that a person carried a tablet but not a cell phone is 23.3%.
Data and Calculations:The sample size of the survey = 163
The number of persons who carried a cell phone = 90
The number of persons who carried a tablet computer = 81
The number of persons who carried both a cell phone and a tablet = 43
1. The number of people who carried a cell phone or a tablet is 128 (90 + 81 - 43).
2. The probability that a person carries a cell phone or a tablet is 78.5%. (128/163).
3. The number of people who carried neither a cell phone nor a tablet is 35 (163 - 128).
4. The probability that a person carried neither a cell phone nor a tablet is 21.5% (35/163).
5. The number of people who carried a cell phone only is 43.
6. The probability that a person carried a cell phone only is 26.4%(43/163).
7. The number of people who carried a tablet but not a cell phone is 38 (81 - 43).
8. The probability that a person carried a tablet but not a cell phone is 23.3% (38/163).
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Question Completion:1. How many people carried a cell phone or a tablet?
2. What is the probability that a person carries a cell phone or a tablet?
3. How many people carried neither a cell phone nor a tablet?
4. What is the probability that a person carried neither a cell phone nor a tablet?
5. How many people carried a cell phone only?
6. What is the probability that a person carried a cell phone only?
7. How many people carried a tablet but not a cell phone?
8. What is the probability that a person carried a tablet but not a cell phone?
You're a manager in a company that produces rocket ships. Machine A and Machine B both
produce cockpits and propulsion systems. Machine A ran for 22 hours and produced 3 cockpits
and 5 propulsion systems. Machine B ran for 44 hours and produced 6 cockpits and 10
propulsion systems.
Assume both machines produce cockpits at the same rate and both produce propulsion systems
at the same rate.
Step-by-step explanation:
so, what's the question ?
I don't need to "assume" that both machines have the same rate. it is clearly written there :
A produces in 22 hours 3 cockpits and 5 propulsion systems.
and B produces in twice the time (44 hours) twice the results (6 cockpits, 10 propulsion systems).
that means they have exactly the same production rate for both products.
so, this is confirmed. but what should we do now with this information ?
Answer:
C - No; the system has many solutions
Step-by-step explanation:
I just got it right on khan.
What number n is four times as close to 10 as it is to 2 ?
Answer: n=38/3
Step-by-step explanation:
4*(n-10)=(n-2)
4*(n-10)=n-2
4n-40=n-2
3n-40=-2
3n=38
n=38/3
The number n is four times as close to 10 as it is to 2 would be 38/3.
What is the number pattern?A number pattern is a pattern in a series of numbers that represents the common relationship between the numbers.
The equation form here;
4*(n-10)=(n-2)
4*(n-10)=n-2
4n-40=n-2
3n-40=-2
3n=38
n=38/3
Therefore, The number n is four times as close to 10 as it is to 2 would be 38/3.
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PLEASE HELP !!!!!!!!!!!!!! Asap Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fract
AB and
BC form a right angle at their point of intersection, B.
AB
If the coordinates of A and B are (14, -1) and (2, 1), respectively, the y-intercept of AB is
is y =
x +
If the y-coordinate of point C is 13, its x-coordinate is
Answer:
The y-intercept is (0, 4/3) and the equation of is y = -1/6x + 4/3. if the y-coordinate of point c is 13, its x-coordinate is -70
Equation of a lineThe equation of a line in slope-intercept form is y = mx + b
where;
m is the slope
b is the y-intercept
Given the coordinate points (14, -1) and (2, 1)
Slope = 1-(-1)/2-14
Slope = 2/-12
Slope = -1/6
Determine the y-intercept
1 = -1/6(2) + b
1 = -1/3 + b
b = 1 + 1/3
b = 4/3
The given equation of the line is y = -1/6x + 4/3
For the y-intercept
y = -1/6(0) + 4/3
y = 4/3
Hence the y-intercept is (0, 4/3)
For the x-intercept
0 = -1/6(x) + 4/3
1/6x = 4/3
24x = 3
x = 1/8
Hence the x-intercept is (1/8, 0)
If the y-coordinate of point C is 13, hence;
y = -1/6x + 4/3
13 = -1/6x + 4/3
-1/6x = 13 - 4/3
-1/6x = 35/3
-1/2 x = 35
x = -70
The y-intercept is (0, 4/3) and the equation of is y = -1/6x + 4/3. if the y-coordinate of point c is 13, its x-coordinate is -70
Jasmine used the number line to find the distance between 0 and 5. what was Jasmine’s error
1.jasmine should have counted from 5 to 0
2.jasmine started with the wrong integer.
3.jasmine gave a negative answer for distance.
4. Jasmine ended with the wrong integer.
The correct answer is option c.
Jasmine gave a negative answer for distance.
The number line is the main visual base in statistics and we often want to look at two points on the number line and determine the distance between them. This is used to find the base of a rectangle or another figure that lies above the number line. By the end of this section, you will be able to determine the distance between any two points on a number line that comes from a statistics application.
The absolute value of 5 is 5, because it is 5 units away from 0. A negative number is a number that is less than zero. On a horizontal number line, negative numbers are usually shown to the left of 0. Two numbers are opposites if they are the same distance from 0 and on different sides of the number line.
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1. Olivia and Brandon take a road trip that is 1, 792 miles. The odometer reading on their car when they start out is
58, 236 miles. After one day, the odometer reading is 58, 857 miles. How many miles do they have left before they
reach their destination?
1,351 miles
1,171 miles
Answer:
1,171 miles
Step-by-step explanation:
The trip is 1792 miles.
They have driven (58857 - 58236) miles of the trip so far (because the odometer change is equal to the distance driven).
(58857 - 58236) = 621
They still need to drive 1792 - 621 miles
1792 - 621 = 1171
So they have 1171 miles left until they complete the trip.
Rewrite (225 + 45) using factoring.
Answer:
15(16+3) is the right answer
Step-by-step explanation:
mark me brainliest PLS
To conserve water, many communities have developed water restrictions. The water utility charges a fee of $38, plus an additional $1.28 per hundred cubic feet (HCF) of water. The recommended monthly bill for a household is between $57 and $87 dollars per month. If x represents the water usage in HCF in a household, write a compound inequality to represent the scenario and then determine the recommended range of water consumption. (Round your answer to one decimal place.)
the recommended range of water consumption is defined by the compound inequality:
14.84 ≤ x ≤ 38.28
How to write a compound inequality?The water utility charges a fixed amount of $38 plus $1.28 per hundred cubic feet of water. So, if you consume x hundred cubic feet of water, the cost is given by the linear relation:
$38 + $1.28*x
Now, this needs to be between $57 and $87 (values included) so we can write the inequality:
$57 ≤ $38 + $1.28*x ≤ $87
Now we just need to solve this for x. If you subtract $38 in both sides you will get:
$57 - $38 ≤ $1.28*x ≤ $87 - $38
$19 ≤ $1.28*x ≤ $49
Now we divide by $1.28 so we get:
$19/$1.28 ≤ x ≤ $49/$1.28
14.84 ≤ x ≤ 38.28
So to be in the recommended range of water consumption, your water consumption x must be in the range:
[14.84, 38, 28]
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On a number line, P has coordinate-35 and Q has coordinate 21. Find PQ
Answer:
42
Step-by-step explanation:
because its 42
(x)/(p)+(x)/(q)=s solve for x
Answer:
x = s/(1/q + 1/p)
Step-by-step explanation:
Solve for x:
x/p + x/q = s
Collect in terms of x:
x (1/q + 1/p) = s
Divide both sides by 1/q + 1/p:
Answer: x = s/(1/q + 1/p)
Solve for v -10 = -14v + 44v
if 3 divided by a number y is 18, then what is the value of the number y plus 2? Steps?
[tex]\frac{3}{y}=18 \\ \\ 3=18y \\ \\ y=1/6 \\ \\ \implies y+2=\boxed{13/6}[/tex]
PLEASE HELP!!!! WIILL MARK BRAINLIEST
The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $6.50 and each adult ticket sells for $10. The auditorium can hold no more than 140 people. The drama club must make at least $1100 from ticket sales to cover the show's costs. If a represents the number of student tickets sold and y represents the number of adult tickets sold, write and solve a system of inequalities graphically and determine one possible solution.
Answer:
y ≥ -0.65x +110
y ≤ -x +140
45 students, 95 adults
Step-by-step explanation:
6.50x + 10y ≥ 1100 --> 10y ≥ -6.50x + 1100 --> y ≥ -0.65x +110
x + y ≤ 140 --> y ≤ -x +140
An ounce of sugar has about 100
calories. If a handful of sugar has
412.6 calories, what's the weight of
the sugar in ounces?
Below is a distance with given lengths to help Cecil cross the tightrope. Find a way to get cecil cross the tightrope.Write your
solutions as numerical expressions. the length of the tightrope is 15 feet long the lengths are 2,6 and 8 feet. Explain why or why not you can use these lengths. PLEASE HELP WORTH A LOt OF POINTS
The lengths can be used since it's more than the tightrope.
How to illustrate the information?It should be noted that the the length of the tightrope is 15 feet long and the lengths given are 2,6 and 8 feet.
The addition of the lengths will be:
= 2 + 6 + 8
= 16 feet
Therefore, the lengths can be used since it's more than the tightrope. In this case, 26 feet is more than 15 feet.
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Consideri the expression 5/6(1/2x+6) - 3x
Therefore, the value for the algebraic expression 5 / 6 ( 1 / 2 (x) + 6 ) - 3x for x = 12 is -26.
Given algebraic expression is 5/6(1/2 (x) + 6 )-3x
As we know An algebraic expression in mathematics is an expression that consists of variables and constants, along with algebraic operations such as addition, subtraction, etc., and are made up of terms
Solve the expression for x = 12
To solve this algebraic expression we have to substitute the value of x = 12 in an expression as below
= 5 / 6 ( 1 / 2 (x) + 6 ) - 3x
Substitute the value of x in the given expression as below
= 5 / 6 ( 1 / 2 * 12 + 6 ) - 3 * 12
= 5 / 6 ( 6 + 6 )) - 36
= 5 / 6 ( 12 ) - 36
= 5 * 2 - 36
= 10 - 36
= -26
Therefore, the value for the expression 5 / 6 ( 1 / 2 (x) + 6 ) - 3x for x = 12 is -26.
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Can anyone help? Cause i dont really understand the thing.
The function represents a continuous function because it can be measured and not counted.
The domain is; x ≤ 19 gallons
The range is ; d(x) ≤ 323 miles
What is the Dependent and Independent Variable?
We are given the function that represents the distance d(x) in miles that the car can travel with x gallons of gasoline as;
d(x) = 17x
A) The Independent Variable is Number of gallons of gasoline used while the dependent variable is the distance that the car travels.
B) Discrete data is a numerical type of data that includes whole, concrete numbers with specific and fixed data values determined by counting. Continuous data includes complex numbers and varying data values measured over a particular time interval.
Thus, the situation represents a continuous function because it can be measured and not counted.
C) The domain is the set of all possible input values. You have 19 gallons and so the domain is; x ≤ 19 gallons
The range is the set of all possible output values. Thus, the range is;
d(x) ≤ (19 * 17)
d(x) ≤ 323 miles
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Which expressions are equivalent to…
Answer: E
Step-by-step explanation:
[tex]\frac{5}{6}(18x^{2} -3x)-\frac{6}{5} (5x^{3} -10x-30x^{2} )[/tex]
[tex]=\frac{5}{6}(18x^{2}) + \frac{5}{6} (-3x) - \frac{6}{5} (5x^{3} )-\frac{6}{5} (-10x)-\frac{6}{5} (-30x^{2} )[/tex]
[tex]= 15x^{2} -\frac{5}{2} x-6x^{3} +12x+36x^{2}[/tex]
[tex]=-6x^{3} + (15x^{2} +36x^{2} )+(-\frac{5}{2}x+12x)[/tex]
[tex]=-6x^{3} + 51x^{2} -\frac{5}{2}x+12x[/tex]
Therefore, the answer is E.
Answer: E.
Step-by-step explanation:
[tex]\displaystyle\\\frac{5}{6} (18x^2-3x)-\frac{6}{5} (5x^3-10x-30x^2)=\\\\\frac{5}{6}(18)(x^ 2)-\frac{5}{6} (3)(x)-\frac{6}{5} (5)(x^3)+\frac{6}{5}(10)(x)+\frac{6}{5} (30)(x^2)=\\\\ \frac{5*18}{6} x^2-\frac{5*3}{6}x -\frac{6*5}{5} x^3+\frac{6*10}{5}x+\frac{6*30}{5} x^2=\\\\5*3*x^2-\frac{5}{2} x-6x^3+6*2*x+6*6*x^2=\\\\15x^2-\frac{5}{2}x-6x^3+12x+36x^2=\\ -6x^3+51x^2-\frac{5}{2} x+12x[/tex]
Which relation is a function?