The expression when evaluated is -5
How to evaluate the expressionFrom the question, we have the following parameters that can be used in our computation:
6(− 2/3 ) − 1.5 + ( 1/2 )
To solve the given expression, we need to apply the order of operations, which is a set of rules that dictate the order in which mathematical operations should be performed.
Using the order of operations, we can simplify the given expression as follows:
6(− 2/3 ) − 1.5 + ( 1/2 ) = -4 − 1.5 + 0.5
Evaluate
6(− 2/3 ) − 1.5 + ( 1/2 ) = -5
Hence, the solution is (b) - 5
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A dealer sold a car to a man and made a profit of 15percent .The man then sold it to a woman for 120175 naira at a loss of 50percent . how much did the dealer buy the car
The dealer bought the car, which he sold to a man and made a profit of 15 percent at $209,000.
How is the dealer's purchase price determined?To compute the dealer's purchase price, we use backward calculations and percentages.
First, the man's purchase price is determined as $240,350 since he incurred a loss of 50% amounting to $120,175.
By equating the proportional loss to the selling price, we can determine the purchase price paid by the man as $240,350.
Since the dealer generated a profit of 15% on $240,350, we determine his cost as $209,000 based on the profit percentage.
The dealer's profit percentage = 15%
The man's loss percentage = 50%
The selling price by the man to the woman = $120,175
The purchase price by the man = $240,350 ($120,175/50%)
The dealer's purchase price = $209,000 ($240,350/1.15)
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How long would Debbie have to leave her money in two accounts, $5000 at 8.75% and $7000 at
9.5%, in order to earn $8820 in interest?
Assuming this is a simple interest situation:
The 8.75% account will earn (0.0875)(5000) each year.
$437.5 earned per year
The 9.5 % account will earn (0.095)(7000) each year
$665 earned per year
Together, these accounts earn $1102.5 per year.
If x is the number of years until the desired interest is earned, then you need to solve 1102.5x = 8820. Dividing by 1102.5 on both sides, you find x=8.
Again, assuming this is simple interest and not compound interest, it will take 8 years.
13. The volume of a rectangular box is given by the functionV(w)=(60−4w)w2. What is a reasonable domain for the function in this situation? Express the domain as an inequality, in interval notation, and in set notation. 14. Sketch a graph of the function in Item 13 over the domain that you found. Include the scale on each axis. 15. Use a graphing calculator to find the coordinates of the maximum point of the function given in Item 13. 16. What is the width of the box, in inches, that produces the maximum volume? 17. Reason abstractly. An architect uses a cylindrical tube to ship blueprints to a client. The height of the tube plus twice its radius must be less than60 cm. a. Write an expression forh, the height of the tube, in terms ofr, the radius of the tube. b. Write an expression forV, the volume of the tube, in terms ofr, the radius of the tube. c. Find the radius that produces the maximum volume. d. Find the maximum volume of the tube.
13. The reasonable domain for the function V(w) = (60-4w)w^2 is when the volume is greater than 0.
14. The graph will look like a parabola with a maximum point at w = 7.5.
15.The coordinates of the maximum point are (7.5, 506.25).
16. The width of the box that produces the maximum volume is 7.5 inches, as found in the previous question.
17. a. The expression for the height of the tube in terms of the radius is h = 60 - 2r.
This means that the values of w must be between 0 and 15, since the volume becomes negative when w is greater than 15. Therefore, the domain can be expressed as an inequality as 0 < w < 15, in interval notation as (0, 15), and in set notation as {w | 0 < w < 15}.
14. To sketch a graph of the function V(w) = (60-4w)w^2 over the domain (0, 15), we can plot points at different values of w and connect them with a smooth curve. The scale on each axis can be 1 unit per grid line.
15. Using a graphing calculator, we can find the coordinates of the maximum point of the function V(w) = (60-4w)w^2 by using the maximum function.
b. The expression for the volume of the tube in terms of the radius is V = πr^2h = πr^2(60 - 2r).
c. To find the radius that produces the maximum volume, we can take the derivative of the volume function and set it equal to 0. This gives us 2πr(60 - 4r) = 0. Solving for r, we get r = 7.5 cm.
d. The maximum volume of the tube is V = π(7.5)^2(60 - 2(7.5)) = 1265.49 cm^3.
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Kevin claims that if two rectangles each have a perimeter of 26 meters, both rectangles must have the same length and the same width. Is he correct? If not, give an example.
Kevin's assertion is untrue. The perimeter of two rectangles can be the same although their lengths and widths differ.
What does "area" mean?The area of a planar figure is the space enclosed by its perimeter. An enclosed figure's area is the total number of unit squares that completely encircle its surface. Cm2 and m2 are two square measures. Only two dimensions are available for measuring a shape's area.
According to the given information:Kevin's claim is incorrect. Two rectangles can have the same perimeter but different lengths and widths.
For example, consider two rectangles with perimeters of 26 meters:
Rectangle A: Length = 8 meters, Width = 5 meters
Rectangle B: Length = 9 meters, Width = 4 meters
Both rectangles have a perimeter of 26 meters (8+5+8+5=26 and 9+4+9+4=26), but they have different lengths and widths.
Kevin's claim is not true in general.
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f(x) = x^2 - 4x - 1
Give the vertex, axis of symmetry, and intercepts. (If an answer does not exist, enter DNE.) I need the smaller
x
-value intercept and the larger
x
value intercept for this quadratic function. I have already determined that 2- sqrt of 5 and
2+
sqrt of
5,−0.267949
and
3.73205,−0.24,0
and
4.24,0
are not the correct answers so if that's what you get, please do not respond with those answers.
The vertex of the function is (2 , -5), the axis of symmetry is x = 2, and the intercepts are (2 + √(5) , 0), (2 - √(5) , 0), and (0 , -1).
To find the vertex, axis of symmetry, and intercepts of the function f(x) = x² - 4x - 1, we can use the following formulas:
Vertex: (-b/2a, f(-b/2a))
Axis of symmetry: x = -b/2a
Intercepts:
x-intercept: set f(x) = 0 and solve for x
y-intercept: set x = 0 and solve for y
Using these formulas, we can find the vertex, axis of symmetry, and intercepts of the function:
f(x) = x² - 4x - 1
a = 1, b = -4, c = -1
Vertex: (-b/2a , f(-b/2a)) = (-(-4)/(2)(1) , f(-(-4)/(2)(1))) = (2 , f(2)) = (2 , (2)² - 4(2) - 1) = (2 , -5)
Axis of symmetry: x = -b/2a = -(-4)/(2)(1) = 2
Intercepts:
x-intercept: 0 = x² - 4x - 1
use the quadratic formula to solve for x: x = (-b ± √(b² - 4ac))/(2a) = (-(-4) ± √((-4)² - 4(1)(-1)))/(2(1)) = (4 ± √(20))/2 = (4 ± 2√(5))/2 = 2 ± √(5)
so the x-intercepts are (2 + √(5) , 0) and (2 - √(5) , 0)
y-intercept: f(0) = (0)² - 4(0) - 1 = -1; so the y-intercept is (0 , -1)
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factor by grouping
8v-6vw+4-3w
The fully factored form of 8v - 6vw + 4 - 3w is (2v + 1)(4 - 3w).
How to factor the expressionFrom the question, we have the following parameters that can be used in our computation:
8v - 6vw + 4 - 3w
To factor by grouping, we'll group the first two terms and the last two terms:
(8v - 6vw) + (4 - 3w)
Next, we'll factor out the greatest common factor (GCF) from each group:
2v(4 - 3w) + 1(4 - 3w)
Notice that both groups now have a common factor of (4 - 3w), which we can factor out:
(2v + 1)(4 - 3w)
Hence, the factored expression is (2v + 1)(4 - 3w)
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I need help with this Quadratic equation-standard form
Use elementary row operations to transform each augmented coefficient matrix to echelon form, then solve the system by back substitution. [5 Marks] 4x1 - 2x2 – 3x3 + x4 = 3 2x1 - 2x2 - 5x3 = -10 4x1 + x2 + 2x3 + x4 = 17 3x1 + x3 + x4 = 12
x1 = 0.75, x2 = 5, x3 = 0, x4 = 12
To transform the augmented coefficient matrix to echelon form using elementary row operations:
1. Subtract twice the first row from the second row.
2. Subtract the first row from the third row.
3. Subtract the first row from the fourth row.
4. Subtract the third row from the fourth row.
The resulting augmented coefficient matrix in echelon form is:
4x1 - 2x2 - 3x3 + x4 = 3
0x1 - 4x2 - 8x3 = -16
0x1 + x2 + 2x3 + x4 = 17
0x1 + 0x2 + x3 + x4 = 12
To solve the system by back substitution:
1. x4 = 12 (from the last equation)
2. x3 = 12 - x4 = 0 (substitute x4 from step 1 into the third equation)
3. x2 = (17 - x4) / (1) = 5 (substitute x4 from step 1 into the second equation)
4. x1 = (3 - 2*5 - 3*0) / (4) = 0.75 (substitute x2 and x3 from steps 2 and 3 into the first equation)
The solution is x1 = 0.75, x2 = 5, x3 = 0, x4 = 12.
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.a local blood center needs donors and has advertised on the college campus. faculty, staff and students all donated during the drive. many also volunteered to help set up , hand out materials and clean up at the end of the event. there were a total of 500 people surveyed about their involvement that day. two hunded seventeen of them gave blood. one hundred fifty-six helped with setting up and cleaning up, as well as handing out materials. if ninety-three people both helped and donated, find out how many people neiher donated nor helped.
Answer:
There are 500 total people. 215 gave blood and 159 helped set up, giving a total of 374. However, since 89 people did both, we counted those 89 people twice. So we subtract 89 to get 285 total volunteers.
500-285=215 did not volunteer
There were 220 people that neither donated nor helped.
To find out how many people neither donated nor helped, we can use the formula for the union of two sets:
A∪B = A + B - A∩B.
In this case, A is the number of people who donated, B is the number of people who helped, and A∩B is the number of people who both donated and helped.
Plugging in the given values, we get:
A∪B = 217 + 156 - 93 = 280
This tells us that there were 280 people who either donated or helped. To find out how many people neither donated nor helped, we can subtract this number from the total number of people surveyed:
500 - 280 = 220
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In evaluating, a student concluded that ((1)/(x))^(n)>(1)/(x), where x is positive, except x!=0,x!=1 and n is a natural number excluding zero. TRUE or FALSE?
The statement ((1)/(x))^(n)>(1)/(x) is FALSE as (1)/(x^n) will always be smaller than (1)/(x).
To evaluate this expression, let's look at the properties of exponents. When we have a fraction raised to a power, it is equivalent to raising both the numerator and denominator to that power.
So, ((1)/(x))^(n) is equivalent to (1^n)/(x^n), which simplifies to (1)/(x^n).
Now, let's compare (1)/(x^n) to (1)/(x). Since x is positive and n is a natural number excluding zero, x^n will always be greater than x.
For example, if x=2 and n=3, then x^n=8 and (1)/(x^n)=(1)/(8) while (1)/(x)=(1)/(2).
So, (1)/(x^n) will always be smaller than (1)/(x).
Therefore, the statement ((1)/(x))^(n)>(1)/(x) is FALSE.
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Pls give simple working
Answer:
Step-by-step explanation:
i dk
Starting time: 9:55 A. M. Elapsed time: 27 minutes
In the following question, Starting time: 9:55 A. M. Elapsed time: 27 minutes provide a snapshot of a specific moment in time and the amount of time that has passed since a particular event or task began.
You have provided two pieces of information: the starting time and the elapsed time.
The starting time is 9:55 A.M., which means that an event or task began at that time. The time is given in the 12-hour clock format, where A.M. stands for "ante meridiem" and refers to the period between midnight and noon.
The elapsed time is 27 minutes, which means that 27 minutes have passed since the event or task started. "Elapsed time" refers to the amount of time that has passed since the start of an event or task.
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Volume of a cone with 48 radius and 64 height
Consider a gamble X such that X = | -$100 with probability 0.4 (a) Is this a fair gamble? Verify your answer (b) Suppose that Anh has an initial wealth of $100 and her utility function over money is u(w) = Vw. Will she join this gamble? Justify your answer. (c) Suppose that Chris has an initial wealth of $0 and his utility function over money is u (w) = e ico. Will he join this gamble? Justify your answer. (d) Suppose that Beth has an initial wealth of $10000 and her utility function over money is u(w) = vw. Will she join this gamble? Justify your answer and explain difference from part (b)
The difference from part (b) is that Beth has a much higher initial wealth, so the negative expected value of the gamble has a smaller impact on her overall utility.
This is not a fair gamble because the expected value of the gamble is negative. The expected value of a gamble is calculated by multiplying the probability of each outcome by the value of that outcome and summing the results. In this case, the expected value is 0.4(-$100) = -$40. Since the expected value is negative, the gamble is not fair.
Anh will not join this gamble because her expected utility from the gamble is lower than her utility from her initial wealth. Her expected utility from the gamble is
0.4u(-$100) = 0.4v(-$100) = -40v.
Her utility from her initial wealth is
u($100) = v($100) = 100v.
Since -40v < 100v, her expected utility from the gamble is lower than her utility from her initial wealth, so she will not join the gamble.
Chris will not join this gamble because his expected utility from the gamble is lower than his utility from his initial wealth. His expected utility from the gamble is
0.4u(-$100) = 0.4e^(-100c) = -40e^(-100c).
His utility from his initial wealth is
u($0) = e^(0c) = 1.
Since -40e^(-100c) < 1, his expected utility from the gamble is lower than his utility from his initial wealth, so he will not join the gamble.
Beth will not join this gamble because her expected utility from the gamble is lower than her utility from her initial wealth. Her expected utility from the gamble is
0.4u(-$100) = 0.4v(-$100) = -40v.
Her utility from her initial wealth is
u($10000) = v($10000) = 10000v.
Since -40v < 10000v, her expected utility from the gamble is lower than her utility from her initial wealth, so she will not join the gamble.
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A line has a slope of 4 and contains the point (x/2,7) and (-10,15.) what is the missing x-value for the coordinate point?
Answer:
We can start by using the slope formula to find the equation of the line:
slope = (change in y) / (change in x)
We know the slope is 4, so we can plug in the coordinates (-10, 15) and (x/2, 7) to solve for x:
4 = (15 - 7) / (-10 - x/2)
Multiplying both sides by (-10 - x/2) gives:
-40 - 2x = 8
Solving for x, we get:
x = -24
Therefore, the missing x-value for the coordinate point is -24.
Step-by-step explanation:
The Class 2022 had 202 students who took the Statistics course. Their mean score in the Final Test was 80.
For the Class 2023, suppose the mean score of the Final Test is 70. The friend of yours now concludes that Class 2022 did better than Class 2023 in the Final Test. Are you sceptical of your friend’s claim? Explain why.
Yes, I am sceptical of my friend's claim that Class 2022 did better than Class 2023 in the Final Test because the mean score only tells us the average score of the students in each class. It does not give us the full picture of how the students in each class performed in the Final Test.
To better compare the performance of the two classes, we need to look at other measures of central tendency, such as the median and mode, as well as measures of dispersion, such as the range, variance, and standard deviation. These measures will give us a better understanding of the distribution of scores in each class and allow us to make a more accurate comparison.
For example, if the range of scores in Class 2022 is much larger than the range of scores in Class 2023, it could indicate that there were a few students in Class 2022 who scored very high, which skewed the mean score upward. In this case, the median and mode may be a better measure of central tendency for comparing the two classes.
Similarly, if the variance and standard deviation of scores in Class 2022 are much larger than those in Class 2023, it could indicate that there is more variability in the scores of students in Class 2022, which could also skew the mean score upward.
In conclusion, while the mean score is a useful measure of central tendency, it should not be used alone to compare the performance of two classes. Other measures of central tendency and dispersion should also be considered to get a more accurate comparison.
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How much carpet does Mrs. Baker need? Responses 192 ft2 192 ft2 228 ft2 228 ft2 336 ft2 336 ft2 576 ft2
Answer:
Step-by-step explanation:
its is 192 ft2
find the 12th term of the geometric sequence 2,-12,8, ...
The 12th term of the geometric sequence 2, -12, 8, ... is -111,974,400.
What is Geometric Progression?A geometric progression is a sequence of numbers in which each term after the first is found by multiplying the preceding term by a fixed number, called the common ratio.
To find the 12th term of the geometric sequence, we need to use the formula:
[tex]an = a1 * r^{(n-1)[/tex]
where:
an = the nth term
a1 = the first term
r = the common ratio
We can see that the common ratio is -6, since:
-12/2 = 8/-12 = -6
So, we have:
[tex]a12 = 2 * (-6)^{(12-1)[/tex]
[tex]a12 = 2 * (-6)^{11}[/tex]
a12 = -111,974,400
Therefore, the 12th term of the geometric sequence 2, -12, 8, ... is -111,974,400.
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printing task. Printer A completes the task in 40 minutes. Printer B can print 4 more pages per minute than printer A and takes 16 fewer minutes to complete the task. How many pages were in the printi
There were 240 pages in the printer task.
To find the number of pages in the printing task, we can use the relationship between time, rate, and work. The formula for this is:
time × rate = work.
Let's call the number of pages in the printing task "P" and the rate of printer A "R". We can set up the following equations based on the information given in the question:
40 minutes × R = P(R + 4) × (40 - 16) = P
We can simplify the second equation to get:
24R + 96 = P
Now we can set the two equations equal to each other and solve for R:
40R = 24R + 96
16R = 96
R = 6
Now we can plug this value of R back into one of the original equations to find P:
40 minutes × 6 = P
P = 240
Therefore, the number of pages in the printing task was 240.
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Cormac uses milk and water when he makes tea. He
makes sure to never have more than 2 cups of milk and
water combined. He also likes the amount of milk to be
less than the amount of water. He writes the system
of inequalities shown below to represent this situation.
x+y≤2
x< ½ y
The point (1) is a solution to Cormac's system of
inequalities. Which statement explains what the point
(1) represents?
Cormac could use
oup of mik and
Cormac could use
cup of milk and
Smes as much
water
Cormac could use
cup of milk and
cups of water,
Cormac could ve
cup of milk
mixture with a lotal of
1
Cοrmac cοuld use 1/3 cup οf milk and 1 1/2 cups οf water, a mixture with a tοtal οf 1 5/6 cups, where the amοunt οf milk is less than 1/2 the amοunt οf water, represented by the sοlutiοn pοint (1/3, 1 1/2) tο the system οf inequalities x + y <= 2 and x < 1/2 * y.
What is inequality?An inequality is a mathematical statement that cοmpares twο values, expressing the relatiοnship between them using οne οf several symbοls, such as "<" (less than), ">" (greater than), "<=" (less than οr equal tο), ">=" (greater than οr equal tο), οr "!=" (nοt equal tο).
The pοint (1/3, 1 1/2) is a sοlutiοn tο Cοrmac's system οf inequalities, which means that it satisfies bοth inequalities. In this case, the inequalities are:
x + y <= 2
x < 1/2 * y
If we plug in x = 1/3 and y = 1 1/2, we can check if it satisfies bοth inequalities:
1/3 + 1 1/2 = 2 (satisfies x + y <= 2)
1/3 < 1/2 * (1 1/2) (satisfies x < 1/2 * y)
Therefοre, the sοlutiοn is (1/3, 1 1/2) since it satisfies bοth inequalities.
Sο, the statement that explains what the pοint (1/3, 1 1/2) represents is:
Cοrmac cοuld use 1/3 cup οf milk and 1 1/2 cups οf water, a mixture with a tοtal οf 1 5/6 cups, where the amοunt οf milk is less than 1/2 the amοunt οf water.
Hence, Cοrmac cοuld use 1/3 cup οf milk and 1 1/2 cups οf water, a mixture with a tοtal οf 1 5/6 cups, where the amοunt οf milk is less than 1/2 the amοunt οf water, represented by the sοlutiοn pοint (1/3, 1 1/2) tο the system οf inequalities x + y <= 2 and x < 1/2 * y.
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f(x) = x³ - 3x
Find f(-2)
Answer:
To find f(-2), we substitute -2 for x in the expression for f(x) and simplify:
f(x) = x³ - 3x
f(-2) = (-2)³ - 3(-2)
f(-2) = -8 + 6
f(-2) = -2
Therefore, f(-2) = -2.
Step-by-step explanation:
2023
Please help on the question 14 to 16
14) all triangles add up to 180 degrees.
for example: c - 40 + 40 = 80; 180-80 = 100
16)
a. EF
b. E
c. A
Rey predicted that the number of apple trees, x, planted in a farm could yield y=-20x^(2)+2800x pel year. How mary trees should be planted to produce the maximum number of apples per yer?
Mmaximum number of apples produced per year is 98000 when 70 apple trees are planted in the farm.
To find the maximum number of apples per year, we need to find the vertex of the quadratic equation y=-20x^(2)+2800x. The x-coordinate of the vertex can be found using the formula x=-b/(2a), where a=-20 and b=2800.
Plugging in the values for a and b, we get:
x=-2800/(2*-20)
x=-2800/(-40)
x=70
So, the maximum number of apples per year will be produced when 70 apple trees are planted in the farm. We can find the y-coordinate of the vertex by plugging x=70 back into the equation:
y=-20(70)^(2)+2800(70)
y=-20(4900)+196000
y=-98000+196000
y=98000
Therefore, the maximum number of apples produced per year is 98000 when 70 apple trees are planted in the farm.
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How to add these two exponentials? 33.65 e^{j(377 t-25.5)}+31.39 e^{j(377 t+172.8)}
The sum of two exponentials is given by:
A e^(jφ) + B e^(jψ) = (Acosφ + Bcosψ) + j(Asinφ + Bsinψ)
Applying this formula to the given problem:
[tex]33.65 e^{j(377t-25.5)} + 31.39 e^{j(377t+172.8)}[/tex]
[tex]= (33.65cos(377t-25.5) + 31.39cos(377t+172.8)) + j(33.65sin(377t-25.5) + 31.39sin(377t+172.8))[/tex]
This is the final answer, expressed in rectangular form with real and imaginary parts.
In words, the sum of the two exponentials is a complex number with a real part equal to the sum of the cosines of the two phases and an imaginary part equal to the sum of the sines of the two phases. The phase angle of the resulting complex number is determined by the weighted sum of the two original phase angles.
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Complete the 4 statements by replacing the question marks (?) with the appropriate letters.
Because all answers are not correct.
AD/DB = {??/??} = {??/??}
AD/AB = {??/??} = {??/??}
DB/AB = {??/??} = {??/??}
Answer: AD/DB = {AB/BD} = {DA/DB}
AD/AB = {DB/AB} = {DA/DB}
DB/AB = {AD/AB} = {BD/DA}
Given: △ACE,BD¯¯¯¯¯∥AE¯¯¯¯¯
Prove: BACB=DECD
A triangle with vertices labeled as A, C, and E, and base A E. Sides C A and C E contain midpoints B and D, respectively. A line segment parallel to base A E is drawn from point B to D. Angle C A E is labeled as 4 and angle C E A is labeled as 3. Angle C B D is labeled as 1 and angle C D B is labeled as 2.
Question
Drag an expression or phrase to each box to complete the proof.
We have proven that in given triangle ∠BACB is congruent to ∠DECD, as required.
What is Similarity of Triangles?Similarity of triangles refers to the property of having the same shape but not necessarily the same size. Two triangles are similar if their corresponding angles are congruent and their corresponding sides are proportional.
To prove: ∠BACB = ∠DECD
We know that, BD ∥ AE and C is the midpoint of AE.
Therefore, triangle ACE and triangle BCD are similar by the Converse of the Corresponding Angles Postulate. Hence, we have:
∠CAB = ∠CBD .... (1) (corresponding angles)
∠CAE = ∠CDB .... (2) (corresponding angles)
Also, we know that in triangle ACE, angles 3 and 4 are alternate interior angles formed by a transversal. Therefore, angles 3 and 4 are congruent. Similarly, in triangle BCD, angles 1 and 2 are congruent.
Therefore, we can write:
∠ACB = ∠BCD .... (3) (angles of similar triangles)
Adding equations (1) and (3), we get:
∠BACB = ∠DECD
Hence, we have proven that ∠BACB is congruent to ∠DECD, as required.
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Instead of regular six-sided dice, some games use dodecahedronal - or 12-sided - dice. If you rolled a pair of dodecahedronal dice (each label 1 through 12) 100 times, about how many times would you expect the values on the two dice to add up to 4?
a) 1
b) 2
c) 3
d) 4
e) 6
f) 8
Instead of regular six-sided dice, some games use dodecahedronal - or 12-sided - dice. If you rolled a pair of dodecahedronal dice (each label 1 through 12) 100 times, you would expect the values on the two dice to add up to 4about 3 times. The correct answer is c) 3.
When rolling two dodecahedronal dice, there are a total of 12 x 12 = 144 possible outcomes. To find the probability of rolling a sum of 4, we need to look at the possible combinations that can result in a sum of 4:
1 + 3
2 + 2
3 + 1
There are a total of 3 possible combinations that can result in a sum of 4. Therefore, the probability of rolling a sum of 4 is 3/144 = 1/48.
If we roll the dice 100 times, we would expect to get a sum of 4 about (1/48) x 100 = 2.08333 times. Since we can't roll a fraction of a time, we can round this to the nearest whole number, which is 3. So, we would expect to roll a sum of 4 about 3 times out of 100 rolls.The correct answer is c) 3.
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A pack of sweets that are 81 inside, must be divided in a ratio of 2:1, how many will each get
The each of two individuals will get 54 and 27 sweets according to provided ratio.
Let us assume the amount of sweets each get be 2x and x. Now we know the sum is 81, so representing the information in equation form.
2x + x = 81
Performing addition on Left Hand Side of the equation
3x = 81
Rewriting the equation
x = 81/3
Performing division on Right Hand Side of the equation
x = 27
So, first person will get amount of sweets = 2×27
First person = 54
Amount of sweets for second person = 27
Thus, each will get 54 and 27 sweets.
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Consider the following trig function ????(????)=−34cos(8x−????/4)+150.
What is the maximum and minimum values of this function? Find an
angle in [0,????/4)
Maximum [ ] Angles that this occurs [
Maximum [184] Angles that this occurs [π/32 + nπ/4]
Minimum [116] Angles that this occurs [π/32 + (2n+1)π/8]
The maximum and minimum values of a trig function can be found by using the amplitude and the vertical shift of the function. The amplitude of the function is the absolute value of the coefficient of the cosine function, which is |-34| = 34. The vertical shift of the function is the constant term, which is 150. Therefore, the maximum value of the function is 34 + 150 = 184 and the minimum value of the function is 150 - 34 = 116.
To find an angle in the interval [0, π/4) where the maximum value occurs, we can use the fact that the cosine function has a maximum value of 1 when the angle is 0. Therefore, we can set the argument of the cosine function, 8x - π/4, equal to 0 and solve for x:
8x - π/4 = 0
8x = π/4
x = π/32
Since π/32 is in the interval [0, π/4), this is one of the angles where the maximum value occurs.
Therefore, the maximum value of the function is 184 and it occurs at angles x = π/32 + nπ/4, where n is an integer. The minimum value of the function is 116 and it occurs at angles x = π/32 + (2n+1)π/8, where n is an integer.
Maximum [184] Angles that this occurs [π/32 + nπ/4]
Minimum [116] Angles that this occurs [π/32 + (2n+1)π/8]
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Which is greater, the number of bacteria, or the number of all the other animals in the table put together?
The number of bacteria or the number of all the other animals in the table put together is 7.8 x 10⁶.
To compare the number of bacteria to the number of all other animals in the world, we need to use some mathematical estimates. It's important to note that it's almost impossible to count the exact number of bacteria and animals in the world since they are found in vast numbers and diverse environments.
According to some scientific estimates, the number of bacteria on Earth is around 5 x 10³⁰, which is a massive number. In comparison, the total number of all other animals, including insects, birds, and mammals, is estimated to be around 7.8 x 10⁶.
In conclusion, the number of bacteria is much greater than the number of all other animals in the world. Although bacteria are tiny microorganisms, they are present in vast numbers and can be found in almost every environment.
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