Eva is driving to a concert and needs to pay for parking. There is an automatic fee of $12 just to enter the parking lot, and when she leaves the lot, she will have to pay an additional $4 for every hour she had her car in the lot. How much total money would Eva have to pay for parking if she left her car in the lot for 5 hours? How much would Eva have to pay if she left her car in the lot for
�
t hours?

Answer: 14.6

Step-by-step explanation:

The magnitude and direction of the resultant force will be 7.829 N and the direction is opposite to the applied force.

A vector is an amount that has direction as well as magnitude and complies with the rule of vector addition.

A constant force of 18 newtons is supplied to an item at a constant angle of 56° while a constant force of 32 newtons is produced to the entity at a fixed angle of 124°.

Then the magnitude and direction of the resultant force are given as,

∑F = 0

∑F = 18 · cos 56° + 32 · cos 124°

∑F = 10.065 - 17.894

∑F = - 7.829 N

The magnitude and direction of the resultant force will be 7.829 N and the direction is opposite to the applied force.

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The numbers are 4 and 5, as their difference is -1 and adding 2 times the first to 3 times the second results in 13.

To solve the problem, we can start by using algebra. Let x be the first number and y be the second number. Then we can write two equations based on the given information:

We can solve this system of equations by substituting x - 1 for y in the second equation, which gives:

Simplifying this equation, we get:

Adding 3 to both sides, we get:

Dividing both sides by 5, we get:

Now that we know x, we can use the first equation to find y:

Adding y to both sides, we get:

Subtracting 4 from both sides, we get:

Therefore, the first number is 4 and the second number is 5, which satisfies both equations.

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By the properties of rhombuses, m∠1 = 90°, m∠2 = 41°, and m∠3 = 49°.

A quadrilateral with all equal sides is a rhombus.

Rhombuses are a particular kind of parallelogram in which all of the sides are equal since the opposite sides of a parallelogram are equal.

A rhombus has 360° of interior angles total.

A rhombus's adjacent angles add up to 180°.

A rhombus's diagonals are perpendicular to one another and cut each other in half.

From the given figure and properties of the rhombus, m∠1 = 90°, As the diagonals bisect each other perpendicularly.

Now, The two diagonals have created 4 congruent right-angled triangles,

Therefore, m∠2 = 41°.

And m∠3 = 180° - (41° + 90°).

m∠3 = 49°.

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Answer

10 is the answer

Please mark as brainliest HOPE IT HELPS!

Answer:

66%

Step-by-step explanation:

"of the" something = means denominator of a fraction

of the tickets sold = denomination here

question asked about child tickets , so child tickets = numerator here

what percentage? = fraction x 100%

answer:

2640 / (2640+1360) x 100

Answer: 18

Step-by-step explanation:

9 kids each have two bags

9 x 2 = 18

9 + 9 = 18

Result in decimals: 3.625

Step-by-step explanation:

Answer:

29/8 or 3 5/8

Step-by-step explanation:

first turn 3 1/4 to 13/4

now change 13/4 to get 26/8

now add 26/8+ 3/8 and get 29/8 or 3 5/8

By applying trigonometric function concept, it can be concluded that the solutions are:

31.  tan a = cot(a + 10°), a = 40°

32. cos θ = sin(2θ - 30°), θ = 40°

33. sin(2θ + 10°) = cos(3θ - 20°), θ = 20°

34. sec(B + 10°) = csc(2B + 20°), B = 20°

35. tan(3B + 4°) = cot(5B - 10°), B = 12°

36. cot(5θ + 2°) = tan(2θ + 4°), θ = 12°

Two angles are said to be complementary angles if their sum is 90°. Sin and Cosine are complementary, Tan and Cot are complementary, and sec and cosec are complementary.

Trigonometric functions of complementary angles:

sin(90° - θ) = cos θ

cos(90° - θ) = sin θ

tan(90° - θ) = cot θ

cot(90° - θ) = tan θ

sec(90° - θ) = csc θ

csc(90° - θ) = sec θ

31. To find one solution for the equation tan a = cot(a + 10°), we can use the fact that cot(90° - θ) = tan θ. Therefore, we can rewrite the equation as:

         tan a = cot(a + 10°)

cot(90° - a) = cot(a + 10°)

      90° - a = a + 10°

             2a = 80°

                a = 40°

32. To find one solution for the equation cos θ = sin(2θ - 30°), we can use the fact that sin(90° - θ) = cos θ. Therefore, we can rewrite the equation as:

        cos θ = sin(2θ - 30°)

 sin(90° - θ) = sin(2θ - 30°)

θ + 2θ - 30° = 90°

              3θ = 120°

                θ = 40°

33. To find one solution for the equation sin(2θ + 10°) = cos(3θ - 20°), we can use the fact that sin(90° - θ) = cos θ. Therefore, we can rewrite the equation as:

sin(2θ + 10°) = cos(3θ - 20°)

sin(2θ + 10°) = sin(90° - (3θ - 20°))

sin(2θ + 10°) = sin(110° - 3θ)

      2θ + 10° = 110° - 3θ

               5θ = 100°

                 θ = 20°

34. To find one solution for the equation sec (B + 10°) = csc(2B + 20°), we can use the fact that sec θ = csc(90° - θ). Therefore, we can rewrite the equation as:

          sec(B + 10°) = csc(2B + 20°)

csc(90° - (B + 10°)) = sec(2B + 20°)

                 80° - B = 2B + 20°

                        3B = 60°

                          B = 20°

35. To find one solution for the equation tan(3B + 4°) = cot(5B-10°), we can use the fact that tan a = cot(90° - a). Therefore, we can rewrite the equation as:

           tan(3B + 4°) = cot(5B - 10°)

cot (90° - (3B + 4°)) = cot(5B - 10°)

                86° - 3B = 5B - 10°

                         8B = 96°

                           B = 12°

36. To find one solution for the equation cot(5θ + 2°) = tan(2θ + 4°), we can use the fact that cot(90° - θ) = tan θ. Therefore, we can rewrite the equation as:

          cot(5θ + 2°) = tan(2θ + 4°)

tan (90° - (5θ + 2°)) = tan(2θ + 4°)

                 88° - 5θ = 2θ + 4°

                           7θ = 84

                              θ = 12°

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Answer:

$1.50

Step-by-step explanation:

3 boxes = $4.50

1 box= $4.50÷3

1box= $1.50

Answer:$1.50

Step-by-step explanation:

The Variation of Parameters is a method used to find a particular solution for ordinary differential equations (ODES). The method involves finding the general solution to the homogeneous equation and then using that to find a particular solution to the non-homogeneous equation.

For the given ODES:

(a) y" - 2y' + y = et^2

First, we need to find the general solution to the homogeneous equation y" - 2y' + y = 0. The characteristic equation is r^2 - 2r + 1 = 0, which has a repeated root r = 1. Therefore, the general solution to the homogeneous equation is yh = c1e^t + c2te^t.

Next, we use the Variation of Parameters to find a particular solution. We assume that the particular solution has the form yp = u1e^t + u2te^t, where u1 and u2 are functions of t. We then find the first and second derivatives of yp and substitute them into the original equation. After simplifying, we obtain a system of equations for u1' and u2'. We solve for u1' and u2' and then integrate to find u1 and u2. Finally, we substitute u1 and u2 back into the equation for yp to find the particular solution.

(b) y" + y = sec(x)

Similarly, we first find the general solution to the homogeneous equation y" + y = 0. The characteristic equation is r^2 + 1 = 0, which has complex roots r = i and r = -i. Therefore, the general solution to the homogeneous equation is yh = c1cos(x) + c2sin(x).

Next, we use the Variation of Parameters to find a particular solution. We assume that the particular solution has the form yp = u1cos(x) + u2sin(x), where u1 and u2 are functions of x. We then find the first and second derivatives of yp and substitute them into the original equation. After simplifying, we obtain a system of equations for u1' and u2'. We solve for u1' and u2' and then integrate to find u1 and u2. Finally, we substitute u1 and u2 back into the equation for yp to find the particular solution.

(c) y" + y = sin^2(x)

The general solution to the homogeneous equation y" + y = 0 is the same as in part (b). We use the Variation of Parameters to find a particular solution in the same way as in part (b), but with the right-hand side of the equation being sin^2(x) instead of sec(x).

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The ordered pair which the graph pass through include the following:

A) (4, 9.2)

E) (0, 0)

F) (1, 2.3)

In Mathematics, a proportional relationship is a type of relationship that generates equivalent ratios and it can be modeled by the following mathematical expression:

y = kx

Where:

In order to have a proportional relationship and equivalent ratios, the variables x and y must have the same constant of proportionality:

Constant of proportionality (k) = y/x

Constant of proportionality (k) = 9.2/4

Constant of proportionality (k) = 2.3

Therefore, the required equation is given by:

y = kx

y = 2.3x

In conclusion, we would use an online graphing calculator to determine the ordered pairs that the line passes through.

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Missing number to make the binomial 9x² + X + 25 a perfect square is 30x.

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax² + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).

Given expression

9x² + X + 25

It can be written as

(3x)² + X + 5²

Comparing with a² + 2ab + b²

a = 3x

b = 5

X = 2ab

X = 2(3x)(5)
X = 30x

Hence, 30x is the missing number  to create a perfect-square binomial.

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Answer:

the answer is 22

Step-by-step explanation:

-22 x -22=22

The answer is ((81c^(8))/(16d^((32)/(5)))).

To simplify ((3c^(2))/(2d^((8)/(5))))^(4), we can use the power of a power rule and distribute the exponent of 4 to each term inside the parentheses.

((3c^(2))/(2d^((8)/(5))))^(4) = (3^(4))(c^(2*4))/(2^(4))(d^((8*4)/(5)))

Simplifying further, we get:

= (81)(c^(8))/(16)(d^((32)/(5)))

= (81c^(8))/(16d^((32)/(5)))

This is the simplified answer with no variables. It cannot be simplified further. Therefore, the answer is ((81c^(8))/(16d^((32)/(5)))).

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[tex]\stackrel{ \textit{Partial Variation} }{V=aD+bD^2}\qquad \impliedby \begin{array}{llll} \textit{V\textit{ varies partly}}\\ \textit{with D and partly with }D^2 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \textit{we also know that} \begin{cases} V=5\\ D=2\\[-0.5em] \hrulefill\\ V=9\\ D=3 \end{cases}\implies \begin{array}{llll} 5=a2+b2^2&\qquad &5=2a+4b\\\\ 9=a3+b3^2&&9=3a+9b \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{using the 1st equation}}{5=2a+4b}\implies 5-2a=4b\implies \cfrac{5-2a}{4}=b \\\\\\ \stackrel{\textit{using the 2nd equation}}{9=3a+9b}\implies \stackrel{\textit{substituting from above}}{9=3a+9\left( \cfrac{5-2a}{4} \right)}\implies 9=3a+\cfrac{45-18a}{4} \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{4}}{4(9)=4\left( 3a+\cfrac{45-18a}{4} \right)}\implies 36=12a+45-18a\implies -9=-6a[/tex]

[tex]\cfrac{-9}{-6}=a\implies \boxed{\cfrac{3}{2}=a}\hspace{5em}b=\cfrac{5-2\left( \frac{3}{2} \right)}{4}\implies \boxed{b=\cfrac{1}{2}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill V=\cfrac{3}{2}D+\cfrac{1}{2}D^2~\hfill[/tex]

15/25 = x/90

25x = 1350

x = 54

54 papers

Answer:

not sure but i think its 12

Step-by-step explanation:

if you look carefully one side witch is 6 is have of side x and 6 x 2 is 12

hope this helps.

Answer:I think its 15 but I'm not sure

Step-by-step explanation:

Using the properties of the exponents, we solve the expression and found the result as  [tex]w^{15} y^{12}[/tex].

The exponent of a number indicates how many times a number has been multiplied by itself. Exponent is another name for a number's power. It could be an integer, a fraction, a negative integer, or a decimal. How many times we must multiply the reciprocal of the base is indicated by a negative exponent. When writing exponentiated fractions, negative exponents are employed. A fractional exponent is one where the exponent of a number is a fraction. Parts of fractional exponents include square roots, cube roots, and nth roots. The square root of a base is a number with a power of half.

Given,

[tex](w^5 * y^4)^3[/tex]

We have to solve this using the properties of the exponents.

Now, this can be written as:

[tex](w^5)^3 * (y^4)^3[/tex]

When the exponent is raised to another power, we can follow the power rule for exponents.

This rule states that multiply the exponent by the power to raise a number with an exponent to that power.

Then the above expression becomes

[tex]w^{(5*3)} * y^{(4*3)}[/tex] = [tex]w^{15} y^{12}[/tex]

Therefore using the properties of the exponents, we solve the expression and found the result as [tex]w^{15} y^{12}[/tex].

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The robberies that took place this year to the nearest whole number is 104 robberies.

A value's percentage change from its initial value is expressed as a percent reduction, but the percentage difference between two values is expressed as a % change from their average.

Let us suppose the number of robberies this year = x.

Given that,

This year the number of robberies has gone down 39%.

x = 171 (1 - 39/100)

x = 171 (1 - 0.39)

x = 104.31

Hence, the robberies that took place this year is 104 robberies.

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The value of R is -10.

The polynomial p(x)=x^(3)-3x^(2)+4x-12 can be expressed as p(x)=q(x)*(x-1)+R. To find the value of R, we need to divide the polynomial p(x) by (x-1) using synthetic division.

Set up the synthetic division by writing the coefficients of the polynomial p(x) in a row and placing the divisor (x-1) to the left of the row.

1 | 1 -3  4 -12
 |_____________

Bring down the first coefficient (1) and multiply it by the divisor (1) to get 1. Place this value below the second coefficient (-3) and add them to get -2.

1 | 1 -3  4 -12
 |   1
 |_____________
   1 -2

Multiply the new value (-2) by the divisor (1) to get -2. Place this value below the third coefficient (4) and add them to get 2.

1 | 1 -3  4 -12
 |   1 -2
 |_____________
   1 -2  2

Multiply the new value (2) by the divisor (1) to get 2. Place this value below the fourth coefficient (-12) and add them to get -10.

1 | 1 -3  4 -12
 |   1 -2  2
 |_____________
   1 -2  2 -10

The final value (-10) is the remainder, or the value of R.

Therefore, the value of R is -10.

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Answer:

$0.33

Step-by-step explanation:

5.11-3.79=1.32÷4=.33

Answer: 8.5 by 11 inches.

Step-by-step explanation:

The standard 8.5″ x 11″ or Letter size so prevalent in full sized notebooks.

The midline or midsegment theorem calculate the value of P. the value of the variable, P that base length in the trapezoid is equals to the 13.

A trapezoid is a 4-sided (square) shape in which some sides are parallels and others not. The midsection of a trapeze is the line that runs from the middle of one leg to the middle of the other. The midsection or Midsegment theorem of a trapezium states that if a line parallel to the two bases passes through the middle of one leg, it also passes through the middle of the other leg. Also, the length of the middle fragment is half the length of two bases. Now we see a trapezoid in the image above, the length of the midsegment = 25

One of the bases of the trapezium = 37

We need to calculate the value of the other base length P Using Midsigment or Midline Theorem, Midsigment = length of two bases/2

=> 25 = (37 + P)/2

=> 50 = 37 + P

=> P = 50 - 37

=> P = 13

Hence, required length is 13.

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Complete question:

Use the midline theorem to find the value of the variable in the trapezoid. See the above figure.

The equation of the image is x = 32 - 2y which is dilated by a scale factor of 1/4 about the center.

Dilation is a process for creating similar figures by modifying the dimensions.

To dilate a line by a scale factor of 1/4 about the center, we can first find the coordinates of the center of dilation.

Since no center is given in the problem, we can assume that the center is the origin (0,0).

To find the equation of the image, we need to apply the dilation to the original line. The dilation multiplies all distances by the scale factor, so the image of the point (x, y) is (1/4)x, (1/4)y).

So, the image of line 8 - 2y = x under this dilation is:

8 - 2(1/4)y = (1/4)x

8 - (1/2)y = (1/4)x

32 - 2y = x

Therefore, the equation of the image is x = 32 - 2y.

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The length of the midsegment of the given trapezoid is 16.

A trapezoid is necessarily a convex quadrilateral in Euclidean geometry. The parallel sides are called the bases of the trapezoid.

Given is a trapezoid TUVW, with bases UV and TW given by expressions, 3x-1, 8x and the midsegment XY is 3x+7.

We need to find the length of the midsegment,

We know,

Midsegment = (base 1 + base 2) / 2

Therefore,

XY = UV+TW / 2

3x+7 = 3x-1 + 8x / 2

6x+14 = 11x-1

5x = 15

x = 3

XY = 3(3)+7 = 16

Hence, the length of the midsegment of the given trapezoid is 16.

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Answer:

75:77

Step-by-step explanation:

5 is 2 more than 3

3+72=75

5+72=77

therefore: 3:5 = 75:77

If that's not what you meant, then I don't understand the question

Answer: Dragonfly wings for the boys cost $1 while fairy wings for the girls cost $2. Phoebe's mom spent $18 on the gifts. How many dragonfly wings and fairy wings

Step-by-step explanation:

Answer:

The answer to the first question is A) P(c) = 2c, because the wings will be sold for double the cost of supplies.

The answer to the second question is B) N(p) = p - 0.3, because the price will be marked down by 30%.

The answer to the third question is A) 0.9c, which represents the markup of the discounted price over the supply cost.

The domain of all the functions is A) [0, infinity), because prices and costs must be positive numbers. Therefore, options B, C, and D are incorrect.