Ernesto has 34 cups of water. Is this enough water to make 18 batches of green slime for a class
project?

Answer:

4th number line (the one of the bottom right)

Step-by-step explanation:

First, solve the inequality, then choose the number line that mathes the solution.

3x ≤ -6

Only step: Divide by 3.

x ≤ -6/3

x ≤ -2

But which number line matches the solution?

We know this is going left, so #1 & #3 are out. This also has a closed circle (because of ≤ (less than/equal to)), so #2 is also out.

Number line #4 matches the solution (x ≤ -2), so it is the answer.

Answer:

19

Step-by-step explanation:

Rate 1: 3  

4

1

​  

%=3+1/4=

\,\,3.25\%\rightarrow 0.0325

3.25%→0.0325

\text{Rate 2: }3\tfrac{1}{8}\%=3+1/8=

Rate 2: 3  

8

1

​  

%=3+1/8=

\,\,3.125\%\rightarrow 0.03125

3.125%→0.03125

\text{Calculate Final Amount for Nevaeh}

Calculate Final Amount for Nevaeh

\overline{\phantom{\text{Calculate Final Amount for Nevaeh}}}

Calculate Final Amount for Nevaeh

\text{Compounded Continuously:}

Compounded Continuously:

A=Pe^{rt}

A=Pe  

rt

P=660\hspace{35px}r=0.0325\hspace{35px}t=14

P=660r=0.0325t=14

Given values

A=660e^{0.0325(14)}

A=660e  

0.0325(14)

Plug in

A=660e^{0.455}

A=660e  

0.455

Multiply

A=1040.2744

A=1040.2744

Use calculator (with e button)

\text{Calculate Final Amount for Jonathan}

Calculate Final Amount for Jonathan

\overline{\phantom{\text{Calculate Final Amount for Jonathan}}}

Calculate Final Amount for Jonathan

\text{Compounded Monthly:}

Compounded Monthly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+  

n

r

​  

)  

nt

Compound interest formula

P=660\hspace{35px}r=0.03125\hspace{35px}t=14\hspace{35px}n=12

P=660r=0.03125t=14n=12

Given values

A=660\left(1+\frac{0.03125}{12}\right)^{12(14)}

A=660(1+  

12

0.03125

​  

)  

12(14)

Plug in values

A=660(1.0026042)^{168}

A=660(1.0026042)  

168

Simplify

A=1021.6468

A=1021.6468

Use calculator

\text{How much more money Nevaeh has:}

How much more money Nevaeh has:

1040.2744-1021.6468

1040.2744−1021.6468

18.6276

18.6276

\$ 19

$19

Answer:

157

Step-by-step explanation:

just trust me bro

This is the graph I hope this helps

Answer:

The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.

Step-by-step explanation:

To solve this question, we need to understand the Central Limit Theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard error is the square root of the sum of the variances:

Of the 193 smokers taking a placebo, 29 stopped smoking by the 8th day.

This means that:

[tex]p_S = \frac{29}{193} = 0.1503[/tex]

[tex]s_S = \sqrt{\frac{0.1503*0.8497}{193}} = 0.0257[/tex]

Of the 266 smokers taking only the antidepressant buproprion, 82 stopped smoking by the 8th day.

This means that:

[tex]p_A = \frac{82}{266} = 0.3083[/tex]

[tex]s_A = \sqrt{\frac{0.3083*0.6917}{266}} = 0.0283[/tex]

Calculate the estimated standard error for the sampling distribution of differences in sample proportions.

[tex]s = \sqrt{s_S^2 + s_A^2} = \sqrt{0.0257^2 + 0.0283^2} = 0.0382[/tex]

The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.

Answer:

See attachment for graph

Step-by-step explanation:

Given

[tex]m = -\frac{1}{2}[/tex]

[tex](x_1,y_1) = (-1,2)[/tex]

Required

Graph the line

First, is to determine the equation of the line using:

[tex]m = \frac{y - y_1}{x - x_1}[/tex]

So:

[tex]-\frac{1}{2} = \frac{y - 2}{x - -1}[/tex]

[tex]-\frac{1}{2} = \frac{y - 2}{x +1}[/tex]

[tex]\frac{-1}{2} = \frac{y - 2}{x +1}[/tex]

Cross multiply:

[tex](y -2) * 2 = -1 * (x + 1)[/tex]

[tex](y -2) * 2 = -x -1[/tex]

Solve for y - 2

[tex]y -2 = -\frac{x}{2} -\frac{1}{2}[/tex]

Solve for y

[tex]y = -\frac{x}{2} -\frac{1}{2} + 2[/tex]

[tex]y = -\frac{x}{2} +\frac{-1+4}{2}[/tex]

[tex]y = -\frac{x}{2} +\frac{3}{2}[/tex]

The above equation will then be plotted on the graph (See attachment)

Answer:

(0,4)

Step-by-step explanation:

Add 4 to x and add 2 to y.

Answer:

1) AM, MY, AY

2) GY, GQ, QY

3) QM, QG, MG

4) YX, YG, XG

Step-by-step explanation:

In triangles, the shortest side is always the side that is directly across from the smallest angle while the longest side is always the side that is directly across from the largest angle.

Using this concept, we can answer the questions;

1) Largest side = AM

Smallest side = AY

Arranging from largest to smallest side;

AM, MY, AY

2) Largest side = GY

Shortest side = QY

Arranging from largest to smallest side;

GY, GQ, QY

3) Largest side = QM

Shortest side = MG

Arranging from largest to smallest side;

QM, QG, MG

4) Largest side = YX

Smallest side = XG

Arranging from largest to smallest side;

YX, YG, XG

Step-by-step explanation:

a. Josh Studies more after earnings Low Test score is

when Y = in 15 Score Josh Time to Studies are 0 Hours

b. There is no association Between hours studied & Test Score = Nope ...After Josh GOT much Time to Studies He Can Make 98 Scores with 7 Hours Time Studies and average data can show is josh average time in studies comparing to Hours his make much scores

c. There is Positive Association Between hours & Test Score Yes

d. Nope

Answer:x=5 or x=−5

Step-by-step explanation:

4x^2−100=0

Step 1: Add 100 to both sides.

4x^2−100+100=0+100

4x^2=100

Step 2: Divide both sides by 4.

4x^2/4=100/4

x^2=25

Step 3: Take square root.

x=±√25

x=5 or x=−5

Answer:

x=5 or x=−5

Answer:where the equations

Step-by-step explanation:

Answer:

Area of triangle AED = [tex]\frac{1}{2}[/tex] × AE × DE

Step-by-step explanation:

The area of a triangle is [tex]\frac{bxh}{2}[/tex]

Answer:

Other person is right, i took the test

Step-by-step explanation:

Answer: DQQMNGV

Step-by-step explanation: Each letter is shifted two letters to the right on a letter strip (a -> b -> c), so BOOKLET would be DQQMNGV.

Hope this helps!

9514 1404 393

Answer:

  n = 8

Step-by-step explanation:

12 = 2² · 3

20! = 2¹⁸ · 3⁸ · [larger primes]

The highest power of 12 that is a factor of 20! is 12^8, limited by the number of factors of 3 there are.

  n = 8

Answer:

n = n

Step-by-step explanation:

explanation is on the top and he/she correct

Answer:

y = 2 x^2 + 5

Step-by-step explanation:

y = 2x^2 + 5

y = 2(-2)^2 + 5

y= 2(4) + 5

y = 8 + 5

y = 13

you can try for yourself using the other values

Answer:

x = 8

Step-by-step explanation:

[tex]\frac{6}{x}[/tex] = [tex]\frac{3}{4}[/tex]

cross multiply

3x = 6(4)

3x = 24

divide

x = 8

Answer:

Step-by-step explanation:

Given

(3x - 3) / 5 = (2x - 2) / 4

Begin by cross multiplying

Solution

Note: the original equation gives you 0/5 = 0/4   which is 0 = 0.

Answer:

C=84

Step-by-step explanation:

Since you use 3 for pi. You plug the radius into the formula. C=2×3x14=84

Answer:

Step-by-step explanation:

z = 119                            Vertically opposite angles are equal.

5x + 41 + 119 = 180        5x + 41  and 119 are supplementary.

4x + 160 = 180               Subtract 160 from both sides

4x = 180 - 160

4x = 20                           Divide by 4

x = 20/4

x = 5

Answer:

In a mathequation when needed

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

sInce his average is equal or greater than league's average

Answer:

The answer is 21/25.

Step-by-step explanation:

I hope this helps! Have a great rest of your day!

Answer: that’s the answer c

Step-by-step explanation:

Bc of the work you put in

Answer:

x = 2, -1

Step-by-step explanation:

Move all terms to the left side and set equal to zero Then set each factor equal to zero

Answer:

Its either L or N im not sure but if i had to guess out of the two i think its L.

Step-by-step explanation:

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

    t = 20: 999 fishes

    t = 30: 1168 fishes

(c)

[tex]P(\infty) = 1200[/tex]

Step-by-step explanation:

Given

[tex]P(t) =\frac{d}{1+ke^-{ct}}[/tex]

[tex]d = 1200\\k = 11\\c=0.2[/tex]

Solving (a): Fishes at t = 0

This gives:

[tex]P(0) =\frac{1200}{1+11*e^-{0.2*0}}[/tex]

[tex]P(0) =\frac{1200}{1+11*e^-{0}}[/tex]

[tex]P(0) =\frac{1200}{1+11*1}[/tex]

[tex]P(0) =\frac{1200}{1+11}[/tex]

[tex]P(0) =\frac{1200}{12}[/tex]

[tex]P(0) = 100[/tex]

Solving (a): Fishes at t = 10, 20, 30

[tex]t = 10[/tex]

[tex]P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483[/tex]

[tex]t = 20[/tex]

[tex]P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999[/tex]

[tex]t = 30[/tex]

[tex]P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168[/tex]

Solving (c): [tex]\lim_{t \to \infty} P(t)[/tex]

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of [tex]e^{-ct}[/tex] decreases

This implies that:

[tex]{t \to \infty} = {e^{-ct} \to 0}[/tex]

So:

The value of P(t) for large values is:

[tex]P(\infty) = \frac{1200}{1 + 11 * 0}[/tex]

[tex]P(\infty) = \frac{1200}{1 + 0}[/tex]

[tex]P(\infty) = \frac{1200}{1}[/tex]

[tex]P(\infty) = 1200[/tex]

Answer:

x=0  

g−1(4)=0∵ g(0)=4

Step-by-step explanation: