Answer:
$10,359.73.
Step-by-step explanation:
We can use the formula for compound interest:
A = P(1 + r/n)^(nt)
where:
A = the amount of money after the specified time
P = the principal amount (the initial amount of money)
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the time (in years)
In this case, we have:
P = $4,000.00
r = 15% = 0.15
n = 1 (compounded annually)
t = 6 years
Substituting into the formula, we get:
A = 4000(1 + 0.15/1)^(1*6)
A = 4000(1.15)^6
A ≈ $10,359.73
Therefore, the amount in the account after 6 years, rounded to the nearest cent, is $10,359.73.
Please help me , I don't understand the question..
The test statistic z ≈ -2.59 falls into the rejection region (z < -1.96).
Therefore, we reject the null hypothesis (H₀) in favor of the alternative hypothesis (H₁).
How to solvea) Null and alternative hypothesis:
The null hypothesis (H₀) states that there is no significant difference between the claimed weekly production volume and the actual production volume.
The alternative hypothesis (H₁) states that there is a significant difference between the claimed weekly production volume and the actual production volume.
H₀: μ = 370 units (the claimed weekly production volume is true)
H₁: μ ≠ 370 units (the claimed weekly production volume is not true)
b) Critical value:
Since we're using a two-tailed test at α = 0.05 significance level, we'll look for the critical value (z-score) that corresponds to the 2.5% in each tail (5% total) of the standard normal distribution.
The critical value for a two-tailed test at α = 0.05 is ±1.96. The rejection region consists of the areas where the z-score is less than -1.96 or greater than 1.96.
c) Test statistic:
To calculate the test statistic, we will use the following formula:
z = (X - μ) / (σ / √n)
z = (355 - 370) / (19 / √30) = -15 / (19 / √30) ≈ -2.59
d) Conclusion:
The test statistic z ≈ -2.59 falls into the rejection region (z < -1.96).
Therefore, we reject the null hypothesis (H₀) in favor of the alternative hypothesis (H₁).
This means that there is significant evidence to suggest that the claimed weekly production volume of 370 units is not true.
The Vice President's suspicion about the statement appears to be correct, and further investigation should be conducted to determine the actual production volume.
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the slope between the points -3, 0 and 0, -1 ?
Answer:
Step-by-step explanation:
m = [tex]\frac{y2-y1}{x2-x1}[/tex]
m = [tex]\frac{-1-0}{0+3}[/tex]
m = [tex]\frac{-1}{3}[/tex]
Answer: -[tex]\frac{1}{3}[/tex]
A printer is printing photos. For every 6 photos, the printer takes 3 minutes.
Complete the table below showing the number of photos and the time it takes to print them.
We can start by finding the rate at which the printer is printing photos. Since it takes 3 minutes to print 6 photos, we can calculate the rate as 6 photos / 3 minutes = 2 photos/minute. This means that for every minute that passes, the printer prints 2 photos.
Now that we know the rate, we can use it to find out how long it will take to print 16 photos. Since the rate is 2 photos/minute, we can set up an equation to solve for y (time) when x (photos) is 16: 2 = 16/y. Solving for y, we get y = 16/2 = 8.
Therefore, when x (photos) is 16, y (time) is 8 minutes. This means that it will take the printer 8 minutes to print 16 photos.
If y (time) is 5 minutes, we can use the rate we calculated earlier to find out how many photos the printer will print in that time. Since the rate is 2 photos/minute, we can multiply it by the time to find out how many photos will be printed: 2 photos/minute * 5 minutes = 10 photos.
Therefore, if y (time) is 5 minutes, the printer will print 10 photos.
If y (time) is 7 minutes, we can use the rate we calculated earlier to find out how many photos the printer will print in that time. Since the rate is 2 photos/minute, we can multiply it by the time to find out how many photos will be printed: 2 photos/minute * 7 minutes = 14 photos.
Therefore, if y (time) is 7 minutes, the printer will print 14 photos.
How many seconds does the ball reach its maximum height using the equation
h(t)= -0.2t^2 + 2t
5 seconds.
Step-by-step explanation:1. Find the "x" position of the vertex of the equation.In a function expressing altitute (h) in terms of time (t), finding the vertex will provide the time and altitute when the object reaches the maximum height. Therefore, let's use the vertex formula to see exactly when this happens:
"x" vertex value: [tex]-\dfrac{-b}{2a}[/tex]
a) For using that equation, first write the given equation on its standard form.
Standard form of quadratic equations: [tex]ax^{2} +bx+c=0[/tex]
b) You can substitute h(t) by 0 on the origina equation:
[tex]-0.2t^{2} +2t=0[/tex]
c) Idenfity the coefficients.
a= -0.2, beacuse "t²" is being multiplied by -0.2.
b= 2, beacuse "t" is being multiplied by 2.
d) Substitute in the formula and calculate.
[tex]\sf X\,value_{Vertex} =-\dfrac{-b}{2a}=-\dfrac{-(2)}{2(-0.2)}=-\dfrac{-(2)}{-0.4}=5[/tex]
2. Answer.So the "x" value of this h(t) equation is located on x= 5, therefore, the maximum point happens at x= 5. Since this is an equation that expresses altitute in terms of time, this means that 5 seconds after the object starts its movement it reaches its maximum altitute.
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Given u = - i + j v = 8i - 2j and w = - 4j find pro*j_{u}(v + w)
The projection of (v + w) onto u is (-8 √(2)i + 6 √(2)j).
Now, let's consider the given vectors u = - i + j, v = 8i - 2j, and w = - 4j. The question asks us to find the projection of vector v + w onto the vector u, denoted as proj_u(v + w). To find this projection, we need to use the dot product between the two vectors.
First, we need to calculate v + w, which is (8i - 2j) + (-4j) = 8i - 6j. Next, we calculate the dot product of u and (v + w):
u · (v + w) = (-i + j) · (8i - 6j)
= -8i + 6j - 8i + 6j
= -16i + 12j
The dot product measures the similarity between two vectors, and in this case, it gives us the component of (v + w) that is parallel to u. To find the projection of (v + w) onto u, we need to divide this component by the magnitude of u:
proj_u(v + w) = (u · (v + w)) / ||u||
= (-16i + 12j) / √(2)
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I really need help, I’m struggling with 5 and 6
Answer:
5)
The inverse of the function f(x) = x^7 can be found by following these steps:
Step 1: Replace f(x) with y. The equation becomes y = x^7.
Step 2: Interchange x and y in the equation, so it becomes x = y^7.
Step 3: Solve the equation for y by taking the seventh root of both sides. This yields y = x^(1/7).
Therefore, the inverse function of f(x) = x^7 is g(x) = x^(1/7), which maps any given value of x to its seventh root.
It's important to note that the domain and range of the inverse function are the opposite of those of the original function. The domain of the inverse function is all real numbers, while the range is only positive real numbers. The domain of the original function is all real numbers, while the range is also all real numbers.
6)
To find the inverse of the function f(x) = (-2/5)x^3, we can follow these steps:
Step 1: Replace f(x) with y. The equation becomes y = (-2/5)x^3.
Step 2: Solve the equation for x in terms of y.
Multiply both sides by -5/2:
(-5/2) y = x^3
Take the cube root of both sides:
x = [(-5/2) y]^(1/3)
Step 3: Replace x with f^-1(y) to obtain the inverse function.
f^-1(y) = [(-5/2) y]^(1/3)
Therefore, the inverse function of f(x) = (-2/5)x^3 is f^-1(y) = [(-5/2) y]^(1/3).
It is important to note that the domain and range of the inverse function are the opposite of those of the original function. The domain of the inverse function is all real numbers, while the range is also all real numbers. The domain of the original function is all real numbers, while the range is only negative real numbers if x is negative and only positive real numbers if x is positive.
Can anyone help me answer this question?
f(x) = 5x^3 + 3x^2 - x/ x+2 and g(x) = x^2 - 1/ x - 1. Find the limit of f^2(x) as x approaches 2
The function limit of f(x) as x approaches 2 is 67 and the limit of f²(x) as x approaches 2 is 4489.
The function f(x) can be rewritten as:
f(x) = (5x³ + 3x² - x)/(x+2)
Using direct substitution, we see that f(2) is undefined, as the denominator of the function becomes 0.
To evaluate the limit, we can use L'Hopital's rule:
[tex]\lim_{x \to 2\[/tex] f(x) = lim x→2 (5x³ + 3x² - x)/(x+2)
= [tex]\lim_{x \to 2\[/tex] (15x² + 6x - 1)/(1)
= (15(2)² + 6(2) - 1)/(1)
= 67
To find the limit of f²(x) as x approaches 2, we can simply square the limit:
f(x) = [tex]\lim_{x \to 2\}[/tex]f²(x)
= [tex]\lim_{x \to 2[/tex] f²(x)
= 67²
= 4489
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Here is a pyramid and its net.
The lateral faces are congruent triangles. The base (shaded) is a square. (All lengths are in centimeters.)
Area of the base of the pyramid is 16 square centimeters
Area of one lateral face of the pyramid is 14 square centimeters
The lateral surface area of the pyramid is 56 square centimeters
The total surface area of the pyramid is 72 square centimeters
Area of the base of the pyramid = length x length
= 4 x 4
=16 square centimeters
Area of one lateral face of the pyramid = area of a triangle
=1/2×base×height
=1/2×4×7
=14 square centimeters
The lateral surface area of the pyramid = 4 x area of one lateral face
= 4 x 14
= 56square centimeters
The total surface area of the pyramid = lateral surface area of the pyramid + area of the base
=56+16
=72 square centimeters
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1+1 hardest problem in the world
The statement "1+1 is the hardest problem in the world" is generally meant to be taken as a joke or a humorous exaggeration.
What does the phrase of 1 + 1 being hard mean ?The phrase may be used ironically to emphasize the difficulty of a seemingly simple task or to highlight the importance of attention to detail. For example, a complex mathematical proof may require multiple steps and involve intricate calculations, but the simplest mistake, such as an error in basic arithmetic, could render the entire proof invalid.
In this context, the phrase "1+1 is the hardest problem in the world" could be used to underscore the importance of checking and double-checking even the most basic assumptions and calculations in complex problem-solving.
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The line plot shows the number of televisions
owned by the families in a neighborhood. Use
clusters, gaps, peaks, outliers, symmetry,
skewness, and spread to describe the shape of
the distribution and summarize the data. (Example 1)
●●●+o
...
Number of Televisions
.....
N.
2
.....
●
4
6
8
10
The correct statements are as follows:-
There is a cluster from 3 to 4.
There is a gap between 1 and 3.
There is a peak at 4.
The data is skewed left.
We have,
Scatter plots are graphs that show how two variables in a data collection relate to one another. On a two-dimensional plane or in a Cartesian system, it represents data points.
The right statements for the dot plots are as follows:-
There is a cluster from 3 to 4.
There is a gap between 1 and 3.
There is a peak at 4.
The data is skewed left.
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Ina Crespo rowed 16 miles down the Habashabee River in 2 hours, but the return trip took her 4 hours. Find the rate Ina rows in still water and the rate of the current. Let x represent the rate Ina can row in still water and let y represent the rate of the current. I need help asap
Answer:ina can row 6mph in still water and 2 mph in current
Step-by-step explanation:
A number cube with faces labeled from to will be rolled once. The number rolled will be recorded as the outcome. Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of rolling a number less than . If there is more than one element in the set, separate them with commas.
The sample space describing all possible outcomes is {1. 2. 3. 4. 5. 6}
Determining the sample space describing all possible outcomes.From the question, we have the following parameters that can be used in our computation:
A number cube with faces labeled from 1 to 6 will be rolled once.
This means that
Sample space = {1. 2. 3. 4. 5. 6}
Using the above as a guide, we have the following:
The outcomes for the event of rolling the number 1 ,3 , or 4. is
Outcome = {1, 3, 4} where we have
P(1) = 1/6
P(3) = 1/6
P(4) = 1/6
Altogether, we have
P(1, 3, or 4) = 1/6 + 1/6 + 1/6
P(1, 3, or 4) = 3/6
P(1, 3, or 4) = 1/2
Hence, the probability is 1/2
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Complete question
A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.
Give the sample space describing all possible outcomes.
Then give all of the outcomes for the event of rolling the number 1 ,3 , or 4.
If there is more than one element in the set, separate them with commas.
Which is equivalent to cube root 8?
Answer:
2
Step-by-step explanation:
The value of cube root of 8, ∛8, is 2.
Answer:
2
Step-by-step explanation:
cube root 8 means:
a number x such that x * x * x = 8
the answer is 2, since 2 * 2 * 2 = 8
in how many months will $8500 grow to $8818.75 at 5% P.A?
Is this compound interest or simple interest? I'll just do it by the simple interest method. The answer is 9 months!
Exercice 10;
58 La Figure 2 est une réduction de la Figure 1.
Figure 1
Figure 2
C.
4 cm
7cm
B
D
A 2,1 cm I
1. Calculer le coefficient de réduc
tion existant entre les deux figures.
2. Déterminer les longueurs man-
quantes et les angles manquants.
B
D
Coup de pouce
Calcule le rapport de deux
sur les deux figures.
longueurs correspondantes
Answer:
Step-by-step explanation:
cot0 equals 6, lies in quadrant 3 sin20
The exact value of sin 2θ is 12/37
How to find the exact value of sin 2θ?Trigonometry deals with the relationship between the ratios of the sides of a right-angled triangle with its angles.
We have:
cot θ = 6
Thus, tan θ = 1/6
Using the given information, we can sketch the location of the angle θ in the quadrant (See the attached image).
Thus, we can calculate the value of the hypotenuse using the Pythagoras theorem. That is:
hypotenuse = √((-6)² + (-1)²) = √37
sin θ = -1/√37
cos θ = -6/√37
Using trig. identity:
sin 2θ = 2sinθ·cosθ
sin 2θ = 2 * (-1/√37) * (-6/√37)
sin 2θ = 12/37
Therefore, the exact value of sin 2θ is 12/37
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Complete Question
If cot θ = 6,and θ lies in quadrant 3, find the exact value of sin 2θ
A researcher claims that the proportion of smokers in a certain city is less than 20%. To test this claim, a random sample of 700 people is taken in the city and 150 people indicate they are smokers.
The following is the setup for this hypothesis test:
H0:p=0.20
Ha:p<0.20
In this example, the p-value was determined to be 0.828.
Come to a conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%)
Answer:
Based on the hypothesis test conducted with a significance level of 5%, we fail to reject the null hypothesis that the proportion of smokers in the city is 20%. This means that we do not have sufficient evidence to conclude that the proportion of smokers is less than 20%. The p-value of 0.828 suggests that there is a high probability that the observed proportion of smokers in the sample is due to chance and not a true difference in the proportion of smokers in the population. Therefore, we cannot conclude that the city has a lower proportion of smokers than 20%.
In this hypothesis test set up by the researcher, the p-value is 0.828, which is greater than the significance level (0.05). Therefore, we do not reject the null hypothesis, meaning there is not enough statistical evidence to validate the researcher's claim that the proportion of smokers is less than 20%
Explanation:A hypothesis test in statistics uses test statistics based on sample data to accept or reject a null hypothesis. In this scenario, the null hypothesis (H0) states that the proportion of smokers (p) is 20%. The alternative hypothesis (Ha) claims that the proportion of smokers is less than 20%. The p-value is a measure of the probability that the observed data could occur under the null hypothesis. In our case, a p-value of 0.828 means that there is an 82.8% chance of observing the data if the true proportion of smokers is 20%, or higher.
Usually a threshold known as the significance level (in this case 5% or 0.05) is used to determine whether the null hypothesis should be rejected or not. If the p-value is less than or equal to the significance level, it suggests that the observed data is inconsistent with the null hypothesis, and the null is usually rejected. However, since our p-value is greater (0.828 > 0.05), we would not reject the null hypothesis, suggesting that there is not enough evidence to support the researcher's claim that the proportion of smokers is less than 20%.
Therefore, the conclusion is that the researcher's claim cannot be validated using the provided data.
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There are 200 end-of-the-year school dance tickets available. Students who have perfect attendance are able to purchase them in advance. If 18 tickets were purchased in advance, what percent of the tickets were purchased in advance?
Thus, 9 percent of the total dance tickets available is found to be purchased in advance.
Explain about the percentage:Although the usage of percent and percentage differs slightly, they both signify the same thing. It is customary to use percent or the symbol (%) along with a numerical value. One tenth of something is one percent.
Hence, it can be expressed as a fraction as well as a decimal. In mathematics, a percentage is a number or ratio that may be expressed as a fraction of 100. The Latin word "per centum," which meaning "per 100," is where the word "percent" comes from. % is the symbol used to represent percentages.Given data:
Total dance tickets = 200
Advanced purchased tickets = 18
Let x be the percentage of advance booked tickets.
Then,
x% of 200 = 18
x*200 / 100 = 18
2x = 18
x = 18/2
x = 9%
Thus, 9 percent of the total dance tickets available is found to be purchased in advance.
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If h = 7 feet, and r = 2 feet, then what is the volume of the cylinder? (Use = 3.14.)
Answer: 87.964594300514 feet3 or 87.96 feet3
Step-by-step explanation:
πr^2 h
= π×2^2×7
= 28π
= 87.964594300514 feet3
Consider the function.
f(x)=2log5(x−2)+1
On what interval is the function positive?
Enter your answer in the box. Round to the nearest hundredth.
write the standard equation of a circle with its centre in the fourth quadrant tangent to x=7, y=-4 and x=17
Answer:
Step-by-step explanation:
To write the standard equation of a circle with its center in the fourth quadrant tangent to x=7, y=-4 and x=17, we can first find the center of the circle.
Since the center is in the fourth quadrant and tangent to x=7, y=-4 and x=17, the center must lie on the line x=12 (the midpoint between 7 and 17) and y=-4 (the point of tangency).
So the center of the circle is (12, -4).
Next, we need to find the radius of the circle. Since the circle is tangent to x=7 and x=17, the radius is the distance from the center to either x=7 or x=17.
The radius is thus 12 (the difference between 12 and 7) or 5 (the difference between 12 and 17).
So the standard equation of the circle is:
(x - 12)^2 + (y + 4)^2 = 25
Apply the repeated nearest neighbor algorithm to the graph above. Give your answer as a list of vertices, starting and ending at vertex A. Example: ABCDEFA
The repeated nearest neighbor algorithm is applied to the given graph to find the circuit of lowest cost starting from vertex A. The vertices are visited in the order A, D, B, C, E, F, and back to A, with a total cost of 38. Therefore, the answer is ADBCEFA.
To apply the repeated nearest neighbor algorithm, we start at vertex A and repeatedly choose the nearest unvisited vertex until we have visited all vertices and return to the starting vertex.
Start at vertex A. Vertex D is the nearest unvisited vertex from A with a distance of 4. Move to vertex D. Vertex C is the nearest unvisited vertex from D with a distance of 5. Move to vertex C. Vertex F is the nearest unvisited vertex from C with a distance of 2.
Move to vertex F. Vertex E is the nearest unvisited vertex from F with a distance of 6. Move to vertex E. Vertex B is the nearest unvisited vertex from E with a distance of 8. Move to vertex B. Return to vertex A to complete the circuit.
Therefore, the circuit starting and ending at vertex A using the repeated nearest neighbor algorithm is ADFCEBA with a total distance of 38.
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ACTIVITY 3: Solve the following equations.
The value of x in each expressions are:
1) 6
2) 1
3) -3
4) -21
5) -4
We have,
The expressions are:
1)
[tex]3^x = 9^3[/tex]
And,
9³ = (3²)³ = [tex]3^6[/tex]
So,
[tex]3^x = 3^6[/tex]
And,
x = 6
2)
[tex]4^{x + 1}[/tex] = 16
16 = 4²
So,
x + 1 = 2
x = 2 - 1
x = 1
3)
[tex](1/3)^x[/tex] = 27
27 = 3³
So,
[tex]3^{-1x}[/tex] = 3³
-x = 3
x = -3
4)
[tex]5^{3x}[/tex] = [tex]25^{x - 1}[/tex] =
[tex]5^{3x}[/tex] = [tex]5^{2x - 21}[/tex]
3x = 2x - 21
3x - 2x = -21
x = -21
5)
[tex]2^{-x}[/tex] = 16
16 = [tex]2^4[/tex]
So,
-x = 4
x = -4
Thus,
The value of x in each expression are:
1) 6
2) 1
3) -3
4) -21
5) -4
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Write the domain using interval notation.
Answer:
[tex](f \circ g)(\text{x}) = \frac{13}{13-\text{x}}[/tex]
Domain: [tex](-\infty,0) \cup (0,13) \cup (13,\infty)[/tex]
=================================================
Explanation:
Let's find the function composition.
The notation [tex](f \circ g)(\text{x})[/tex] is the same as [tex]f(g(\text{x}))[/tex]
[tex]f(\text{x}) = \frac{\text{x}}{\text{x}-1}\\\\\\f(g(\text{x})) = \frac{g(\text{x})}{g(\text{x})-1}\\\\\\f(g(\text{x})) = g(\text{x}) \div \Big( g(\text{x}) - 1\Big)\\\\\\[/tex]
Then,
[tex]f(g(\text{x})) = \frac{13}{\text{x}} \div \left(\frac{13}{\text{x}}-1}\right)\\\\\\f(g(\text{x})) = \frac{13}{\text{x}} \div \left(\frac{13}{\text{x}}-\frac{\text{x}}{\text{x}}\right)\\\\\\f(g(\text{x})) = \frac{13}{\text{x}} \div \frac{13-\text{x}}{\text{x}}\\\\\\f(g(\text{x})) = \frac{13}{\text{x}} * \frac{\text{x}}{13-\text{x}}\\\\\\f(g(\text{x})) = \frac{13}{13-\text{x}}\\\\\\[/tex]
-----------------
Now let's find the domain.
If we plugged x = 0 into g(x), then we get a division by zero error.
This means we must exclude this value from the domain.
For similar reasoning, we must exclude x = 13 because we get a division by zero error in [tex]f(g(\text{x})) = \frac{13}{13-\text{x}}[/tex]
We could have any other real number to be plugged in for x.
Here's what the domain looks like in interval notation.
[tex](-\infty,0) \cup (0,13) \cup (13,\infty)[/tex]
We effectively poke holes at 0 and 13 on the number line.
a camper lights an oil lantern at 12 noon and let’s it burn continuously
The amount of oil in the lantern at 12 noon is 64.33 ounces
Calculating the amount in the lantern at 12 noon?The time can be represented with x and the amount with y
Note that
x = number of hours from 12 noon
So, we have the following ordered pairs
(x, y) = (0, y) (2, 63), (5, 61)
Using the slope formula, we have
(y - 63)/(0 - 2) = (61 - 63)/(5 - 2)
So, we have
(y - 63)/-2 = -2/3
This gives
y - 63 = 4/3
Add 63 to both sides
y = 63 + 4/3
Evaluate
y = 64.33
Hence, the amount in the lantern at 12 noon is 64.33 ounces
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Complete question
A camper lights an oil lantern at 12 noon and lets it burn continuously. Once the lantern is lit, the lantern burns oil at a constant rate each hour. At 2 p.m., the amount of oil left in the lantern is 63 ounces. At 5 p.m., the amount of oil left in the lantern is 61 ounces.
Based on the average rate of oil burning per hour, how much oil, in ounces, was in the lantern at 12 noon?
y= +- 3/5 is equivalent to?
The equivalent value of the expression is y = + 3/5 and y = -3/5
Given data ,
Let the expression be represented as A
Now , the value of A is
y = ±3/5
On simplifying the equation , we get
y = +3/5
And, y = -3/5
Now , the decimal values of y are
y = ±0.6
Hence , the expression is y = ±0.6
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In a sample of 1000 adults, 150 said they are very confident in the nutritional information on restaurant menus. for us adults are selected at random without replacement.
Find the probability that none of the four adults are very confident in the nutritional information on the restaurant menus.
The probability that none of the four adults is very confident in the nutritional information on the restaurant menus is 0.208 or approximately 20.8%.
Ready to approach this issue by utilizing the hypergeometric conveyance, since we are examining without substitution from a limited populace of two sorts (those who are exceptionally sure and those who are not exceptionally sure).
Let X be the number of grown-ups in a sample of 4 who are not exceptionally sure about the wholesome data on eatery menus.
At that point, X takes after a hypergeometric dissemination with parameters N = 1000, n = 4, and K = 850 (since 850 grown-ups are not exceptionally certain).
The likelihood that none of the 4 grown-ups are exceptionally certain can be communicated as:
P(X = 4) = (K select 4) / (N select 4)
where (K select 4) speaks to the number of ways to select 4 grown-ups from the population of 850 who are not exceptionally sure,
and (N select 4) speaks to the entire number of ways to select 4 grown-ups from the populace of 1000.
Utilizing the equation for binomial coefficients, ready to disentangle this expression as:
P(X = 4) = [(850*849*848*847) / (4*3*2*1)] / [(1000*999*998*997) / (4*3*2*1)]
= 0.208
Hence, the likelihood that none of the four grown-ups are exceptionally certain within the wholesome data on eatery menus is 0.208 or approximately 20.8%.
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Use the unit circle to find exact value of the trig function
sin(135°)
4% is equivalent to what fraction
the value of 4% as a fraction is 1/25
4/100 is the fraction, but when 4 is divided into 100, it gives you 1/25 in simplest form.
what are the coordinates of each point after quadrillateral MNPQ is trans;ated 2units right and 5 units down
The coordinates of each point after the quadrilateral MNPQ is translated 2 units right and 5 units down are:
M' = (x1 + 2, y1 - 5)
N' = (x2 + 2, y2 - 5)
P' = (x3 + 2, y3 - 5)
Q' = (x4 + 2, y4 - 5)
How to calculate the coordinates?To calculate the coordinates, we shall assume that the coordinates of the points of the quadrilateral MNPQ are:
M = (x1, y1)
N = (x2, y2)
P = (x3, y3)
Q = (x4, y4)
Next, we translate the quadrilateral 2 units right and 5 units down by adding 2 to the x-coordinate and subtracting 5 from the y-coordinate of each point.
The new coordinates of the points after the translation will be:
M' = (x1 + 2, y1 - 5)
N' = (x2 + 2, y2 - 5)
P' = (x3 + 2, y3 - 5)
Q' = (x4 + 2, y4 - 5)
Therefore, the coordinates of each point after the quadrilateral is translated 2 units right and 5 units down are:
M' = (x1 + 2, y1 - 5)
N' = (x2 + 2, y2 - 5)
P' = (x3 + 2, y3 - 5)
Q' = (x4 + 2, y4 - 5)
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Question completion:
Although part of your question is missing, you might be referring to the below question:
What are the coordinates of each point after quadrilateral MNPQ is translated 2 units right and 5 units down?