E=hv h= 6.62 x 10^-34 m^2 kg/ s

What would be the energy contained in a photon of light that has a frequency of 5.0 x 10^12?

Please show work!!

Answers

Answer 1

v=5.0×10^12Hz

[tex]\\ \sf\longmapsto E=hv[/tex]

[tex]\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 5\times 10^12s^{-1}[/tex]

[tex]\\ \sf\longmapsto E=33.13\times 10^{-22}J[/tex]


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Hello there!

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take a picture of it info is missing
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