Eddie O'Neil found a sports car advertised at a local used-car dealership for

$34,000. The car is clean and in good condition. Its average retail value is

$33,400. It has air-conditioning valued at $840 and leather seats valued at $200,

but it does not include a CD player, which is valued at $100. The used-vehicle

guide indicates that $1,690 should be deducted for excessive mileage on the car.

O'Neil plans to visit the dealership this evening. What is the average retail price

for this vehicle?

Answer:

Minimum: 189

Maximum: 786

Median: 572

Lower quartile: 275

Upper quartile: 653

Step-by-step explanation:

Listing the numbers in order from least to greatest, we have: 189, 274, 276, 403, 572, 649, 652, 654, 786.

From this, we can see that the smallest (minimum) value is 189, and the largest (maximum) value is 786.

We can find the the median by taking off a number from each side of the number set one by one. When done, we can see that the number in the middle is 572, so that is our median.

To find the upper and lower quartiles, split the number set in half where the median lies and find the median of those two sections.

Q1: 189, 274, 276, 403

274 + 276 = 550

550 ÷ 2 = 275

--------------------------

Q3: 649, 652, 654, 786

652 + 654 = 1306

1306 ÷ 2 = 653

So, the lower quartile range is 275, and the upper quartile range is 653.

hope this helps!

Answer:

A, B, C, and E.

Step-by-step explanation:

I don’t know how to explain what I did very well.

Answer:

Step-by-step explanation:

Given equation

Use the property of logarithm

Apply to the given equation

Let's see

[tex]\\ \rm\Rrightarrow log_416=x[/tex]

[tex]\\ \rm\Rrightarrow 16=4^x[/tex]

[tex]\\ \rm\Rrightarrow 4²=4^x[/tex]

[tex]\\ \rm\Rrightarrow x=2[/tex]

Done!

Answer:

Step-by-step explanation:

GIVEN:

To find the missing number in the proportion, you have to isolate it the term of x from one side of the equation.

[tex]\sf{\dfrac{8}{7}=\dfrac{x}{21} }[/tex]

First, thing you do is switch sides.

[tex]\sf{\dfrac{x}{21}=\dfrac{8}{7} }[/tex]

Multiply by 21 from both sides.

[tex]\Longrightarrow: \sf{\dfrac{21x}{21}=\dfrac{8*21}{7} }[/tex]

Solve.

Multiply the numbers from left to right.

Use the order of operations.

PEMDAS stands for:

[tex]\Longrightarrow: \sf{\dfrac{8*21}{7}=\dfrac{168}{7}=24 }[/tex]

[tex]\Longrightarrow: \boxed{\sf{x=24}}[/tex]

I hope this helps. Let me know if you have any questions.

Answer:

x =number of child tickets

y=number of adult tickets

x + y = 9

3x +9y = 57

x = 9-y

3(9-y) + 9y =57

27 - 3y + 9y = 57

6y = 30

y=5 adult tickets

x = 4 child tickets

Answer:

adult's tickets a=5

child's tickets c=4

Step-by-step explanation:

a+c=9

9a+3c=57

c=9-a

3a+c=19

3a+9-c=19

2a=10

a=5

c=9-a=9-5=4

This solution is arrived at using the principles of Quadratic Functions and Inequalities. It is to be noted that the function increases at (-8, 4).

A quadratic function can be defined as that is written in the following way: f(x) = ax2 + bx + c: Where a, b, and c are numbers not equal to zero.

To solve the problem f(4x - 3) ≥ f(2 - x^2), Df = (-8 , 4), we:

A) 4x - 3 ≥ 2 - x²

Rewrite as:  x² + 4x - 2 - 3 ≥ 0

B) Collect the like terms

x² + 4x - 5 ≥ 0

C) Expand to have  x² + 5x - x - 5 ≥ 0

D) Factorizing the expression we have

x(x + 5) - 1(x + 5) ≥ 0, from this we  Factor away x + 5

(x - 1)(x + 5) ≥ 0

E) Solving  for x we obtain: x ≥ 1 or x ≥ -5

This can also be rewritten to read:

-5 ≤ x ≤ 1

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Answer:

You have to share number too

The mean of the set is less than the median. Option B is correct.

Given that,
Norberto received the following scores on his last five spelling tests 93, 66, 78, 85, and 98.

The mean of the values is the ratio of the total sum of values to the number of values.

Here,
Marks scored by Norberto in 5 spelling tests are 93, 66, 78, 85, and 98.
Mean of marks score = total marks scored / total spelling test
Mean of marks score = (93 + 66 + 78 + 85 + 98) / 5
Mean of marks score = 420 / 5 = 84

Now,
In order to get the median,
Arrange the marks in ascending order,
66, 78, 85, 93, 98
n = 5
median = (n + 1) / 2th term  
             = (5 + 1) / 2th term
             =  6 / 2 = 3 th term
Median = 85
Here, 85 > 84 implies the median is more than the mean.

Thus, the mean of the set is less than the median. Option B is correct.

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Answer:

Step-by-step explanation:

We have two equations :

Take the value of x in Equation 2 and substitute in Equation 1.

Now, take the value of y and substitute in Equation 2.

Solution

Answer:

The lines intersect at the point (-1, 0)

Step-by-step explanation:

−5(      )−y=5

-5(7y-1) - y = 5    substitute the x=7y-1 into first equation

-35y + 5 - y =5   multiply -5

-36y + 5 = 5        combine like terms

-36y = 0              subtract 5

y=0                      divide by -36

x=7(0)-1                substitute 0 for y in x=7(  )-1

  =-1                      simplify

The lines intersect at the point (-1, 0)

Answer:

the letter d does not have symmetry

Step-by-step explanation:

Polynomial is an expression that consists of indeterminates(variable) and coefficient. The polynomial f(x) is x³-12x²+256=0.

Polynomial is an expression that consists of indeterminates(variable) and coefficient, it involves mathematical operations such as addition, subtraction, multiplication, etc, and non-negative integer exponentials.

As the zeros of the polynomial are 8(multiplicity 2), -4. Therefore, the factors of the polynomial can be written as,

[tex]x = 8\\x-8=0[/tex]

[tex]x =-4\\x+4=0[/tex]

Now, the polynomial f(x) which is a third-degree polynomial can be written as,

[tex](x-8)(x-8)(x+4)=0\\\\(x-8)^2(x+4)=0\\\\(x^2-16x+64)(x+4)=0\\\\x^3-16x^2+64x+4x^2-64x+256 = 0\\\\x^3-12x^2+256=0[/tex]

Hence, the polynomial f(x) is x³-12x²+256=0.

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Answer:

£1067.22.

Step-by-step explanation:

Interest I= PRT/100    where P = Initial investment, R = % rate, T = time.

So I = 990*2.6* 3 / 100

= £77.22

So total he will have in the bank

= 990+77.22

= £1067.22.

Answer:

d

Step-by-step explanation:

Each point has been moved 2 spaces to the right and 5 units down.

Moving 2 spots to the right means x updates to x+2

Moving 5 units down tells us to change y to y-5

Therefore, [tex](x,y) \to (x+2, y-5)[/tex]

Answer:

43,898

Step-by-step explanation:

1. 454 x 344 = 156,176

2. 156,176 / 4 = 39,044

3. 39,044 + 4,854 = 43,898

Answer:

RISE/RUN

Step-by-step explanation:

6

x

−

12

y

=

14

Yw :D pls mark me brainiest

Answer:

if you use desmos graphing calculator it will make graphing equations like this easier.

Step-by-step explanation:

by easier i mean it just graphs it for you. hope this helps:)

By working with fractions, we will see that the amount that Rollie borrowed from his sister is $31.50.

Let's say that Rollie borrowed a quantity x.

The first month, Rollie returns one third of x + $3, so now he owes:

x - x/3 - 3 = (2/3)*x - 3

the second month returns another third of what he owes plus $3, so now he returns:

(1/3)*((2/3)*x - 3) + 3 = (2/9)*x + 2

So no he owes:

(2/3)*x - 3 - (2/9)*x - 2 = (4/9)*x - 5

Finally, on the third month he returns:

(1/3)*((4/9)*x - 5) + 3 = (4/27)*x - 5/3 + 3 = (4/27)*x + 4/3

Now he owes:

(4/9)*x - 5 -  (4/27)*x - 4/3 = (8/27)*x - 19/3

And that is equal to $3, what he owes at the end of the third month, so we need to solve:

(8/27)*x - 19/3 = 3

(8/27)*x = 3 + 19/3 = 28/3

Solving for x, we get:

x = (27/8)*(28/3) = 31.5

So Rollie borrowed $31.5 from his sister.

If you want to learn more about fractions, you can read:

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Answer:

x = -52

Step-by-step explanation:

[tex]\frac{1}{3}x-\frac{2}{3}=-18[/tex]

Let us solve for x.

[tex]\frac{1}{3}x=-18+\frac{2}{3}[/tex]

[tex]\frac{1}{3}x=-\frac{18*3}{1*3} +\frac{2}{3}[/tex]

[tex]\frac{1}{3}x=-\frac{54}{3} +\frac{2}{3}[/tex]

[tex]\frac{1}{3}x=\frac{-54+2}{3}[/tex]

[tex]\frac{1}{3}x=\frac{-52}{3}[/tex]

Use cross multiplication to find the value of x.

[tex]\frac{1x}{3}=\frac{-52}{3}[/tex]

[tex]3*1x=3*-52[/tex]

[tex]3x=-156[/tex]

Divide both sides by 3.

x = - 52

Answer:

18/245.

Step-by-step explanation:

Total number of coins = 12+15+23 = 50.

Prob(Karen chooses a dime) = 15/50 = 3/10.

Prob(Mikah then chooses a quarter) = 12/49.  ( Karen has already removed one coin)

Prob(of Karen choosing a dime then Mikah a quarter)

= 3/10 * 12/49

= 36/490

= 18/245.

Answer:

-3/4

Step-by-step explanation:

see picture below

Answer:

[tex]-3/4~ > -5/6[/tex]

Step-by-step explanation:

Using the given inputs

[tex]3/4~and~5/6[/tex]

The least common denominator (LCD) is 12.

Rewriting as equivalent fractions with the LCD:

[tex]-\frac{3}{4} ~becomes-\frac{9}{12}[/tex]

And

[tex]-\frac{5}{6}~becomes-\frac{10}{12}[/tex]

Comparing the numerators of the equivalent fractions we have

[tex]-9/12 > -10/12[/tex]

Therefore,  the comparison shows:

[tex]-3/4~ > -5/6[/tex]

Hope this Helps! :3

have a great day! :3

Answer:

Jackie divided the number of quarts by 2. There are 2 pints in each quart. She should have multiplied by 2; so Jackie made 20 pints of lemonade.

hope it really helps......!!!!!!

Probability helps us to know the chances of an event occurring. The probability of getting a tail and an even number is 0.25.

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

Since a coin has two faces, therefore, the probability of getting either of the sides of the coin is (1/2). While a die has six faces, so the probability of getting any side of the die is (1/6).

A.) The probability of getting a tail and an even number can be written as,

[tex]\text{Probability of getting a tail} = \dfrac{1}{2}[/tex]

[tex]\text{Probability of Even Number(2,4,6) } = \dfrac{3}{6} = \dfrac{1}{2}[/tex]

[tex]\text{Probability (Tails and an even number)} = \dfrac12 \times \dfrac12 = 0.25[/tex]

B.) The Probability of getting tails and the number 9 can be written as,

[tex]\text{Probability of getting a tail} = \dfrac{1}{2}[/tex]

[tex]\text{Probability of Number 9} = \dfrac{0}{6} = 0[/tex]

[tex]\text{Probability of the tails and the number 9} = 0[/tex]

C.) The Probability of getting Heads or a number bigger than 4 can be written as,

[tex]\text{Probability of getting a Head} = \dfrac{1}{2}[/tex]

[tex]\text{Probability of a number bigger than 4 (5,6) } = \dfrac{2}{6} = \dfrac{1}{3}[/tex]

[tex]\text{Probability (Heads or a number bigger than 4 )} = \dfrac12 + \dfrac13 = \dfrac{5}{6} = 0.83333[/tex]

D.) The Probability of getting Heads or the number 2 can be written as,

[tex]\text{Probability of getting a Head} = \dfrac{1}{2}[/tex]

[tex]\text{Probability of the number 2} = \dfrac{1}{6}[/tex]

[tex]\text{Probability (Heads or the number 2 )} = \dfrac12 + \dfrac16 = \dfrac{8}{12} = 0.6666[/tex]

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LSA