If earth is approximately 5×[tex]10^{9}[/tex] years old, the the approximate age of earth is option C 4,953,000,000 years
Given,
The age of Earth = 5×[tex]10^{9}[/tex] years old
We know,
5×[tex]10^{9}[/tex]= 5000000000 years old
From the given option the closest number to 5×[tex]10^{9}[/tex] is 4,953,000,000 years old
Hence, if earth is approximately 5×[tex]10^{9}[/tex] years old, the the approximate age of earth is option C 4,953,000,000 years
Complete question is:
Earth is approximately 5x109 years old. For which of these ages could this be an approximation? Select all that apply.
A. 4.37 x 100 years
B. 4.679999999 x 10º years
C. 4,953,000,000 years
D. 4,625,800,000 years
E. 50,000,000,000 years
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A jug of juice has 8 cups of pineapple juice and 3 cups of orange juice. Write the ratio of number of cups of pineapple juice to total number of cups of juice in three different ways.
Answer:
8 : 3, 8/3, and "8 to 3"
A cartoon of 2 dozen eggs includes 3 with cracks. how many eggs without cracks can be expected in 6 dozen eggs?
If a cartoon of 2 dozen eggs includes 3 with cracks, then the number of eggs without cracks in 6 dozen eggs can be expected to be 63.
A dozen abbreviated as doz is a batch of 12. So in this situation, one dozen refers to 12 eggs. Therefore the number of eggs in 2 dozen will be equal to,
1 dozen = 12 eggs
2 dozen = 12x2= 24 eggs.
Therefore, a cartoon of 24 eggs includes 3 with cracks.
Similarly, 6 dozen is equal to,
1 dozen = 12 eggs
6 dozen = 12 x 6 = 72 eggs
We can determine the number of eggs with cracks by using an algebraic expression,
24 eggs include 3 eggs with cracks
72 eggs include: x eggs with cracks
x = 72×3 ÷ 24
x = 216 ÷ 24 = 9 eggs with cracks.
Therefore the number of eggs without cracks can be calculated by the subtraction of total eggs from the eggs with cracks.
Eggs without cracks= 72 - 9 = 63 eggs.
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Ben bowled 128 and 206 in his first two games. What must he bowl in his third game to have an average of at least 190?
Ben must bowl at least
least 190.
in his third game in order to have an average of at
Answer:
236
See the picture below for the work.
Step-by-step explanation:
The lengths of the three sides of a triangle (in feet) are consecutive even integers. If
the perimeter is 96 feet, find the value of the shortest of the three side lengths.
Identify all the possible proper subset relationships that
occur among the following sets.
the subsets in this case are:
C ⊆ BC ⊆ AB ⊆ AHow to identify the subsets?Remember that for two sets A and B, we say that A is a subset of B if and only if all the elements of A also are elements of B.
In this case, we have 3 sets:
A = {3n| n ∈ N}B = {6n| n ∈ N}C = {12n| n ∈ N}We can rewrite these ones as:
A = {3n| n ∈ N} = {3, 6, 9, 12, 15, 18, ...}B = {6n| n ∈ N} = {6, 12, 18, ...}C = {12n| n ∈ N} = {12, 24, 36, ...}Here we can see that all the elements in C also belong in B and also belong in A, and all the elements in B also belong to A, then the subsets are:
C ⊆ B
C ⊆ A
B ⊆ A
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What is the
y-value of the
of the
solution
system?
y = 5x + 3
y = 7x-3
Answer:
y is about equal to -4.692
Step-by-step explanation:
Simplify the expression 4( m - 2 ) + 3m
Answer:
7m-8
Step-by-step explanation:
distribute 4 through the parentheses
4m-8+3m
collect like terms
7m-8
Answer:
7m-8
Step-by-step explanation:
So to simplify this expression, you would need to do distributive property.
4(m-2)
(4*m) + (4*-2)
4m-8+3m
7m-8
So your simplification is 7m-8
I need help asap!! (Fractions)
Answer:
b 2 2/9
Step-by-step explanation:
As we know
6×2/3 = {6×3+2}/3
=> 20/3
20/3 is the walk for 3 days
by unitary method
Walk of one day should be
20/3×3
20/9 = 2×2/9 miles per day
Answer:
2 2/9 miles per day
Step-by-step explanation:
If she walked 6 2/3 miles in 3 days, then she walked 1/3 of 6 2/3 miles in 1 days.
We need to find 1/3 of 6 2/3 miles.
1/3 of 6 2/3 =
= 1/3 × 6 2/3
= 1/3 × (6 + 2/3)
= 1/3 × 6 + 1/3 × 2/3
= 2 + 2/9
= 2 2/9
The volume of a prism is given by the formula V=lwh , where l is the length, w is the width, and h is the height of the prism.
a. Solve the formula for h .
Answer:
[tex] \sf \large \: h = \frac{v}{lw} [/tex]
Step-by-step explanation:
Let's solve for h.
v=lwh
Step 1: Flip the equation.
hlw=v
Step 2: Divide both sides by lw.
hlw/lw = v/lw
h= v/lw
Helpppp I will give 60 points for this one
Answer:
Step-by-step explanation:
A. L+W= 2 in. x 2 in. = 4 in.
the length is 2 in.the width is 2 in. so you multiply 2 in.x 2 in. which = 4 in.Below are some things to help you with perimeter and area(just type it into whatever browser you use, copy and paste)
https://youtu.be/LoaBd-sPzkU
https://th.bing.com/th/id/OIP.Q5D_8qbK_9XGQLj1s0tpbwHaJ3?w=186&h=248&c=7&r=0&o=5&dpr=1.65&pid=1.7
K What is 0.288 rounded to the neare hundredth? 0.288 20
Answer: 0.29
Step-by-step explanation:
= 0.288
8>5
= 0.29
Rose has 1 3/4 cups of powdered sugar. she sprinkles 1/3 of the sugar onto a plate of brownies and sprinkles the rest onto a plate of lemon cookies. how much sugar does rose sprinkle on the brownies?
0.58 or more than half of sugar is sprinkled by rose on the brownies.
How much sugar does rose sprinkle on the brownies?
Given,
Rose has 1 3/4 cups of powdered sugar.
1/3 of the sugar sprinkled on lemon cookies
Therefore'
1 3/4 = (4*1+3) / 4
= 7/4
1/3 of the sugar sprinkled on lemon cookies
= 1/3 (7/4)
= 7/12
= 0.58 or more than half of sugar is sprinkled by rose on the brownies.
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In an arithmetic sequence, the first term is 8, the common difference is 3 and the last term is 68.
a How many terms are there in this sequence?
b Find the sum of all the terms of the sequence.
Answer: a. 21 terms
b. 798
Step-by-step explanation:
a. 68-8=60 ==> difference between 1st and last term
60/3=20 ==> number of terms after the first term
20+1=21 terms ==> total number of terms
b. Find the mean of the terms first:
(68+8)/2= ==> the mean of all terms in a sequence is equal to the mean of the first and last term
76/2=38
38*21=798 ==> add the mean 21 times to get the total sum since there are 21 terms in the sequence.
. determine whether each of the following statement is true or false: a) x ∈ {x} b) {x} ⊆{x} c) {x} ∈{x} d) {x} ∈ {{x}}
(a) True, x is an element of the set {x}
(b) True, the set {x} is a subset of itself.
(c) False, x is an element of {x}, but the set {x} is not an element of {x}.
(d) True, the set {x} is an element of the set {{x}}.
What do you mean by the element of the set?The numbers 1, 2, 3, and 4 are the elements of set A, as indicated by the formula A=1,2,3,4. Subsets of A are collections of components from A, like 1, and 2. Sets may also function as elements.
Consider the set B=1,2,3,4 as an example. B's constituent parts are not 1, 2, 3, or 4. Instead, there are just three components of B: the numbers 1 and 2, as well as the set "3, 4."
A set's components can be anything. For instance, the set "C=red, blue, green" contains the colors red, green, and blue as its constituents.
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PLEASE HELP FAST! 35 PTS!!
Justify each step by identifying the property used.
[tex]t+5(t+1)=t+(5t+5)[/tex]
[tex]=(t+5t)+5[/tex]
[tex]=(1t+5t)+5[/tex]
[tex]=(1+5)t+5[/tex]
[tex]=(6t+5)[/tex]
The algebraic properties used in the steps are the distribution property, the associative property, the identity property, and the distribution property
How to justify each step by identifying the property used?The first step in the equation is given as:
t + 5(t + 1) = t + (5t + 5)
The distribution property states that
a(b + c) = ab + ac
So, the property used in t + 5(t + 1) = t + (5t + 5) is the distribution property
Next, we have:
t + 5(t + 1) = (t + 5t) + 5
The associative property states that
a + (b + c) = (a + b) + c
So, the property used in t + 5(t + 1) = (t + 5t) + 5 is the associative property
Next, we have:
t + 5(t + 1) = (1t + 5t) + 5
The identity property states that
a * 1 = a
So, the property used in t + 5(t + 1) = (1t + 5t) + 5 is the identity property
Next, we have:
t + 5(t + 1) = (1 + 5)t + 5
The distribution property states that
a(b + c) = ab + ac
So, the property used in t + 5(t + 1) = (1 + 5)t + 5 is the distribution property
Lastly, we have the solution
(6t + 5)
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[tex]9a-ab+5b if a=2 and b =7[/tex]
Answer:
If you want it graphed the answer is
andb=7
The formula wights are
mass of 1 1 mole of 9 a − a b + 5 b i f a = 2 = 0 g
Step-by-step explanation:
Please help!!! I really need this!!! It's piecewise functions......
well, let's take a peek at the graph, hmmm it has a straight line from the origin to (5,10), and then another straight line from (5,10) to (10,5) and then another one from there up to (20,5).
well, let's simply get the equations for each of those lines then
[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{10}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{10}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{0}}} \implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{2}(x-\stackrel{x_1}{0})\implies \boxed{y = 2x} \\\\[-0.35em] ~\dotfill[/tex]
[tex](\stackrel{x_1}{5}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{5}}} \implies \cfrac{ -5 }{ 5 }\implies -1[/tex]
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{-1}(x-\stackrel{x_1}{5}) \\\\\\ y-10=-x+5\implies \boxed{y=-x+15} \\\\[-0.35em] ~\dotfill[/tex]
[tex](\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{20}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{20}-\underset{x_1}{10}}} \implies \cfrac{ 0 }{ 10 }\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{0}(x-\stackrel{x_1}{10})\implies y-5=0\implies \boxed{y=5}[/tex]
so then hmmm let's use those, we know how f(x) is moving now, so
[tex]\stackrel{y}{f(x)}= \begin{cases} 2x&x\geqslant 0\\\\ -x+15&x\leqslant 10\\\\ 5&x\leqslant 20 \end{cases}[/tex]
the length of a rectangle is 2 feet less than the three times length express the area of the rectangle as a function of its width, using correct function notation
The area of the rectangle as a function of its width is a=3b-2.
[tex]s=(3b-2)b\\=3b^{2}-2b[/tex]
[tex]a=3b-2[/tex]
What is the advantages of area ?
Area is significant in contemporary mathematics. Aside from its obvious significance in geometry and calculus, area is also a fundamental characteristic of surfaces in differential geometry and is connected to the definition of determinants in linear algebra. The amount of space within a form is measured by its area.
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Help, I've been stuck on these questions for an hour!
Explanations would be helpful, please!
Answer:
A. 3005
B. 3110
C. 1016.67
Step-by-step explanation:
A. Inital means occuring at the beginning. So the month they got the account, the value is around 3005. Every tick mark on the y-axis represents 30.
B. Like I said, every tick mark represents 30, so on the x-axis, the line between 6 and 8 is 7. go up towards where the line is, and that equals 3110.
C. I really haven't learned about rate of interest yet, but I tried my best to figure it out. I found out that for every month, you get 1016.67 value of interest.
What is the slope of the line that passes through the points (6, -5)(6,−5) and (6, -4)(6,−4)? Write your answer in simplest form.
When graphed, one point is on top of the other, creating a vertical line. This could either be ∞ or -∞ .
23. SALES TAX You buy a jacket, and the sales tax is 6%. The total cost is $79.49.
Find the cost of the jacket before the tax.
The Cost of jacket before tax is 74.73.
According to the statement
We have to find that the cost of jacket.
So, For this purpose, we know that the
The cost function can be used to find the average cost, which is the average amount of money it costs to produce a unit.
From the given information:
the sales tax is 6%. The total cost is $79.49.
Then the real cost is :
Real cost = 6% of the $79.49
Then
solve it
tax amount applied on the jacket = 6/100*79.49
tax amount applied on the jacket = 0.06*79.49
tax amount applied on the jacket = 6/100*79.49
tax amount applied on the jacket = 4.76
Then
Cost of jacket before tax = 79.49 -4.76
Cost of jacket before tax = 74.73.
So, The Cost of jacket before tax is 74.73.
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A cube-shaped planter has a volume of 729 in.³. What is the length of the planter?
Answer:
9 inches
Step-by-step explanation:
To find the volume of a cube, you could cube the side length, simplified as x³.
x³ = 729
x = 9
9 inches
Hope this helps! :)
There are a children in the class, and b of them are girls. How many boys are in the class?
Number of boys = a - b
Step-by-step explanation:Number of children in the class = a
Number of girls in the class = b
Number of boys = Total - Girls
a - b
What is the result of adding these two equations can you please answer
Lori ran 5 ½ miles Monday, 6 %4 miles Tuesday, 4½ miles Wednesday, and 234 miles on
Thursday. What is the average number of miles Lori ran? Write your answer as an improper
fraction.
19 miles the average number of miles Lori ran.
Miles Lori ran on Monday = 5 ½ = 11/2
Miles Lori ran on Tuesday = 6 ¼ = 25/4
Miles Lori ran on Wednesday = 4½ = 9/2
Miles Lori ran on Thursday = 2¾ = 11/4
Total miles she ran = sum of 4 days runs
= 11/2 + 25/4 + 9/2 + 11/4
= 22/4 + 25/4 + 18/4 + 11/4
= [tex]\frac{22 +25+18+11}{4}[/tex]
= 76/4 miles or 19 miles
How to calculate average number?By combining a set of integers and then dividing by their count, the average number—also known as the arithmetic mean—is created. For instance, the sum of 2, 3, 3, 5, 7, and 10 is equal to 30 divided by 6, which equals 5.
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Simplify each part of the expression using the laws of exponents.2^7/2^5+(4^5)^0+3^-1
What laws or properties did you use to simplify each part? What is the value of the expression?
Answer:
5.333333333333
Step-by-step explanation:
1. 2^7 &2^7 have the vase, by subtracting their power, the result is 4.
2. (4^5)^0=1
3. 3^-1=0.3333333
4 finally by adding each values in above steps
(Total 3 marks)
5. Dave and Tanvir each think of a number, where Dave's number is larger,
The difference between their numbers is $. Dave's number plus twice Tanvir's number is 26
By forming simultaneous equations, determine each bloke's number.
Dave and Tanvir each think of a number, where Dave's number is larger,
The difference between their numbers is 5. Dave's number plus twice Tanvir's number is 26. By forming simultaneous equations, determine each bloke's number. The numbers are 12 and 7.
The number of Dave is 12 and the number of Tanvir is 7.
Given that
Dave and Tanvir each think of a number, where Dave's number is larger.
The difference between their numbers is 5.
Dave's number plus twice Tanvir's number is 26.
To find
By forming simultaneous equations, determine each bloke's number.
So, according to the question
Let's assume that numbers are x and y.
So, we can say that
x - y = 5 ------------(1) and
x + 2y = 26 ------------(2)
We have to solve that equations by using forming simultaneous equations.
For forming simultaneous equations, we have multiply equation(1) by 2, then add eq(2) with result.
So, we will get
2x - 2y = 10
(+) x + 2y = 26
---------------------------
3x +0 = 36
3x = 36
x = 36/3
x = 12
Putting the value of x in equation (1),
We will get,
x - y = 5 ------------(1)
12 - y = 5
- y = 5 - 12
- y = -7
y = 7
The numbers are 12 and 7.
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Can Someone help me?
Step-by-step explanation:
first- b
swcond- a
third- c
What is the answer to this problem?
Answer: 3
Step-by-step explanation:
A/B
30/10 = 3
describe the given set with a single equation or with a pair of equations. the plane through the point parallel to a. the xy-plane b. the yz-plane c. the xz-plane
Equations for the set of the plane through the point [tex](x_0,y_0,z_0)[/tex] and parallel to:
a. xy-plane is [tex]z=z_0[/tex] b. yz-plane is [tex]x=x_0[/tex] c. xz-plane is [tex]y=y_0[/tex]
The given set is the plane through the point [tex](x_0,y_0,z_0)[/tex] parallel to:
a. xy-plane b. yz-plane c. xz-plane
Equation of the plane parallel to a plane containing a vector [tex]\vec r[/tex] through the point [tex](x_0,y_0,z_0)[/tex] is [tex](\vec r-(x_0,y_0,z_0)) .\vec n=0[/tex] ,where [tex]\vec n[/tex] is the normal to the plane and [tex]\vec r =x\vec i +y\vec j +z\vec k[/tex].
a. Plane through [tex](x_0,y_0,z_0)[/tex] and parallel to the xy-plane is,
[tex](x\vec i +y\vec j+z\vec k) - (x_0+y_0+z_0) . \vec k[/tex] = 0
⇒ [tex](x-x_0)\vec i +(y-y_0)\vec j+(z-z_0)\vec k) . \vec k=0[/tex]
⇒ [tex]z-z_0 =0[/tex]
⇒ [tex]z=z_0[/tex] is the equation of the plane through [tex](x_0,y_0,z_0)[/tex] and parallel to xy-plane.
b. Plane through [tex](x_0,y_0,z_0)[/tex] and parallel to the yz-plane is,
[tex](x\vec i +y\vec j+z\vec k) - (x_0+y_0+z_0) . \vec i[/tex] = 0
⇒ [tex](x-x_0)\vec i +(y-y_0)\vec j+(z-z_0)\vec k) . \vec i=0[/tex]
⇒ [tex]x-x_0 =0[/tex]
⇒ [tex]x=x_0[/tex] is the equation of the plane through [tex](x_0,y_0,z_0)[/tex] and parallel to yz-plane.
c. Plane through [tex](x_0,y_0,z_0)[/tex] and parallel to the xz-plane is,
[tex](x\vec i +y\vec j+z\vec k) - (x_0+y_0+z_0) . \vec j[/tex] = 0
⇒ [tex](x-x_0)\vec i +(y-y_0)\vec j+(z-z_0)\vec k) . \vec j=0[/tex]
⇒ [tex]y-y_0 =0[/tex]
⇒ [tex]y=y_0[/tex] is the equation of the plane through [tex](x_0,y_0,z_0)[/tex] and parallel to xz-plane.
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