e. How many grams of chlorophenol are there in 1.00 litre of a 47.0 mM solution? Show your calculations
in full.
(6 marks)

Answers

Answer 1

The mass of the chlorophenol  is obtained from the number of moles and the volume of the solution.

Recal that;

Number of moles = concentration of solution * volume of solution

Concentration = 47.0 mM  or 47.0 * 10^-3 M

Volume = 1.00 litre

Number of moles = 47.0 * 10^-3 M * 1.00 litre

Number of moles = 47.0 * 10^-3 moles

Also;

Number of moles = mass/molar mass

mass = Number of moles * molar mass

Mass = 47.0 * 10^-3 moles * 128.6 g/mol

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Mass = 6.0442 g


Related Questions

which statement correctly contrasts science and psuedoscience

Answers

Answer:

The correct answer is Science is objective, whereas pseudoscience is subjective. Pseudoscience includes beliefs, theories, or practices that have been or are considered scientific, but have no basis in scientific fact. This could mean they were disproved scientifically, can't be tested or lack evidence to support them.

Explanation:

hope its help

thank you

what is stoichiometry?​

Answers

Answer:

the relationship between the relative quantities of substances taking part in a reaction or forming a compound, typically a ratio of whole integers.

Explanation:

G o o g l e

Explanation:

Stoichiometry is the calculation of reactants and products in chemical reactions in chemistry.

why does copper Cu (I) have a short lifespan​

Answers

Answer:

Copper (Cu), chemical element, a reddish, extremely ductile metal of Group 11 (Ib) of the periodic table that is an unusually good conductor of electricity and heat. Copper is found in the free metallic state in nature.

Explanation:

hope this helps:)

If I have a bottle of compound X at a pressure of 45 atm and temperature of 100 °C, what will happen if I raise the temperature to 400 °C?*

Answers

Answer:

55/350

Explanation:

because the answer is in the middle of 50and 400

Element X forms the ion X22- What is the formula of the covalent compound X forms with chlorine?
A XCI
B XCl2
C XCl3
D XCl4​

Answers

Answer:

the answer is mostly option a)XCl

Explanation:

How does the electronic configuration of an element give information about the period and the group it belongs to

Answers

Answer:

Electronic configuration of an element gives the information of valence electrons and number of shell present in the element.

Explanation:

Electronic configuration of an element gives the information of valence electrons and number of shell present in the element. We get the information of group number after knowing valence electrons.  

The number of shells present in an element is equal to the period number. Thus, by knowing electronic configuration we know the group number and period number of an element, and the position of an element in the periodic table.

An element's electronic configuration, which identifies both its period and group, gives important details regarding its place within the periodic table.

The major energy level (shell) where the outermost electrons are found determines the period. In the electrical arrangement, the period number corresponds to the greatest energy level. The number of valence electrons, which are the electrons at the highest energy level, which are present in an element determines its group or family. Because they have the same valence electron configurations, elements in the same group exhibit comparable chemical characteristics. In conclusion, the electronic configuration helps us comprehend an element's chemical behavior and interactions with other elements by revealing an element's period based on energy levels and its group based on valence electrons.

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4) A sample of sodium bromide, NaBr, has a mass percentage of sodium of 22.34%.

a) If the sample of sodium bromide were contaminated with sodium chloride, NaCl, would the mass percentage of Na in the sample be higher or lower than the pure sample? Justify your claim.

b) If the sample of sodium bromide were contaminated with sodium iodide, NaI, would the mass percentage of Na in the sample be higher or lower than the pure sample? Justify your claim

Answers

Explanation:

The trick here is to realize the every sample of sodium bromide, regardless of its mass, will contain

22.34

%

sodium by mass.

This is true because sodium and bromide always combine in definite proportions, i.e. stable ratios by mass, to form sodium bromide.

Now, a

22.34

%

percent concentration by mass means that every

100 g

of sodium bromide will contain

22.34 g

of sodium and

100 g

22.34 g

=

77.66 g Br

Therefore, you can say that the mass ratio that exists between sodium and bromine in any sample of sodium bromide will be

22.34 g Na

77.66 g Br

=

22.34

77.66

You can thus use this definite proportion to say that a

5.69 g

sample of sodium bromide will contain

5.69

g NaBr

22.34 g Na

100

g NaBr

=

1.271 g Na

=

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

1.27 g Na

a

a

−−−−−−−−−−−−−

The answer is rounded to three sig figs.

You can use the known definite proportion to find the mass of bromide present in the sample

1.271

g NaBr

77.66 g Br

22.34

g NaBr

=

4.42 g Br

This checks out because

mass of NaBr sample



5.69 g

mass of Na



1.27 g

=

mass of Br



4.42 g

The answers to your questions are ;

a) The mass percentage of Na in the sample will be higher in the sample

b) The mass percentage of Na in the sample will be be lower in the sample

Given that:

Mass percentage of sodium contained in sodium Bromide = 22.34%

a) Determine if the mass percentage of Na will be higher or lower when sodium Bromide is contaminated with sodium chloride  

mass percentage of Na in sodium bromide

= ( mass of Na / mass of NaBr )*100

The mass of sodium in NaBr and NaCl is the same while the mass of Br is not same ( greater than ) as the mass of Cl.  hence when NaBr is contaminated with NaCl the total mass of  in percentage NaBr will decrease. and This decrease in mass of NaBr will lead to a decrease/lower mass percentage of Na in the sample

b) When NaBr is contaminated with NaI

The mass of Na is the same in NaBr and NaI while the mass of I is not the same ( greater than ) as the mass of Br, therefore the total mass will increase and the increase in the Total mass in percentage will lead to an increase/higher value of Na in the given sample.

hence the mass percentage of Na will decrease when NaBr is contaminated with NaCl while the mass percentage of Na will increase when NaBr is contaminated with NaI

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9. SI base units used in chemistry include
A. kilograms, liters, inches, and moles.
B. pounds, gallons, moles, and Fahrenheit.
C. kilograms, seconds, moles, and Kelvin.
D. pounds, gallons, moles, and Celsius.

Answers

Answer:

C. kilograms, seconds, moles, and Kelvin

what is chemical change ?​

Answers

Change in chemical bonds that alters what a reaction would be

Pls give me a brainliest thx

[tex]\huge{ \color{violet}{ \boxed{ \color{hotpink}{Answer}}}}[/tex]

➣ Chemical ChangeIt occurs when new materials are formed by a change in the way the atoms are bonded together.

Heat, light or electrical energy is often emmitted or absorbed.

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[tex]\large\tt\:⚘ \: MishiChaeYoon \: ⚘[/tex]

calculate mass of MnO2 if 1 mole of KMnO4 completely burnt. 2KMnO4 -> K2MnO4+MnO2+O2​

Answers

Answer:  80 grams

Explanation:  

2KMnO4 -> K2MnO4+MnO2+O2​

2 moles of KMnO4 would produce 1 mole of MnO2, so 1 mole of KMnO4 would produce 0.5 moles of MnO4.  The molar mass of MnO4 is 160 g/mole.  1/2 mole of KMnO4 would therefore be (160 g/mole)*(0.5 moles) = 80 grams.

Which of the following can be referred to as a d7 ion? * O Cu4+ o Mn 4+ O O O Ni4+ O None of the above .​

Answers

Transition metals are known to have incompletely filled d- orbitals. For this reason, they are commonly referred to as the d- block. Cu4+  is a d7 ion.

An ion is formed when electrons are lost from or gained in a neutral atom.

An ion is a positively or negatively charged chemical specie. Chemical species form ions by loss or gain of electrons.

An atom is neutral if it has equal number of protons and electrons. When an atom has lost electrons, it forms a positive ion.

Copper has electronic configuration; 1s2 2s2 2p6 3s2 3p6 4s2 3d9. When four electrons are lost, its electronic configuration now becomes;

1s2 2s2 2p6 3s2 3p6 3d7.

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What is the molecular formula of sulphuric acid and ammonia compound by criss cross method​

Answers

Answer:

H2SO4 AND NH3

Explanation:

I hope it will help you

Answer:

Explanation:

H2SO4 AND NH3

how much energy is contained in 3moles of chlorine​

Answers

Answer:

1 mol of cl2 contains 71 g

3 mol of cl2 will contain÷

3×71=213 g

Explanation:

There ;3

Answer:

213 g

Explanation:

multiply 3 moles by relative atomic mass of chlorine which is 35.45×2 because its two chlorines and your answer will be 213g

Rain soaks into the soil or runs off into oceans, rivers, and lakes. ___________ which process is this

Answers

Answer:

The water falls to the earth as precipitation, such as rain, hail, sleet, and snow. When precipitation reaches the earth's surface, some of it will flow along the surface of the land and enter surface water like lakes, streams, and rivers, as runoff. The rest of it soaks or percolates into the soil, called

Iron has a density of 7.86 g/cm3. Calculate the volume (in dL) of a piece of iron having a mass of 4.59 kg .

Answers

Note:
k = 10^3
1 cm^3 = 10^-2 dL

Solutions

Density = (mass)/(volume)
Volume = (mass)/(density)
Volume = (4.59 × 10^3g)/(7.68g/cm³)
Volume = 583.97 cm³
Volume = (583.97 cm³)(10^-2 dL/1 cm³)

So volume = 5.84 dL approximately

Can someone help me pls, I do not know how to do this. i am trying to help a friend as well​

Answers

Answer:

Your answer is 5 x 10

I hope it's helps you

Answer:

[tex]thank \: you[/tex]

Plllsssss hel pls help

Answers

the answer is A
In approximately 5 billion years, the sun will begin the helium-burning process, turning into a red giant star. When it expands, its outer layers will consume Mercury and Venus, and reach Earth.

Enumerate seven commonly encounter functional group in organic compound

Answers

Answer:

-COOH

-CHO

-CO

-NH2

-X(-Cl, -Br, -I)

-RCOOR(R= Alkyl group)

-C6H5

Given six molecules, identify the molecules with polar bonds and the molecules that are polar.CCl4, CH3Cl, H20, CO2, O2

Answers

Answer:

polar bonds- H2O, CO2, CH3CL,

The molecules that have polar bonds are CH₃Cl, and H₂O.

What are polar bonds?

A polar bond is a type of covalent bond where the electron is unequally distributed.

This unequal distribution is due to the electronegativity difference of the attached atoms in the molecule.

A lewis structure of the molecule is studied to determine whether the compounds are polar and non-polar.

The molecule CCl₄: has one carbon atom at the center and the chlorine surrounds the carbon from all four sides, so even if there is a difference in the electronegativity the net dipole movement gets balanced from all four sides, so it is not a polar bond.

The molecule CH₃Cl

Similar to the CCl₄, hydrogen, and chlorine is surrounding the carbon, the three sides are hydrogen and one side is chlorine, so there is a net dipole movement and so it is a polar bond.

The molecule H₂O: The dipole movement of Hydrogen and oxygen are both in opposite directions and of different magnitude hence it will have a net dipole movement and so it is polar.

The molecule CO₂ and O₂ have net dipole movements as zero so are not polar compounds.

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Which family of metals is the most reactive?
Rare Earth metals
Transition metals
Alkaline Earth metals
Alkali metals?

Answers

Answer:

Alkali metals

Explanation:

Hope you like my answer and my answer helped you

write on the principle and other application of a named instrument employed in unlocking frozen joints.​

Answers

We have that the bone file from our research below

The is a very important tool in unlocking frozen joints by using its

Pull stroke

Serrated edges etc

And its also used in the field of dentistry.

Before we pick an instrument to focus on we first have to under stand what a frozen joints is

Frozen Joint,

Frozen Joint, which is also refereed to as adhesive capsulitis, is a situation whereby ones joints are stiff and they experience pain in the joint.

We focus on the

Bone file( principle)

It is made of a pull stroke which is designed to aid the removal of bones,they are also designed with serrated edges which are used in many different ways one of which is to smooth bones out in order to disinfect a given area

Bone file

This can also be used in the field of dentistry.

it puts into use it variant functions to make the work of a dentist easy

In conclusion

The Bone file is a very important tool in unlocking frozen joints by using its

Pull stroke

Serrated edges etc

And its also used in the field of dentistry.

For more information on this visit

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Which methods separate a mixture according to the size of the particles?

A. distillation and evaporation

B. filtration and chromatography

C. filtration and evaporation

D. distillation and chromatography

Answers

c. filtration and evaporation

Answer:

Only one of these methods separates compontents based on size.

The answer is filiration and chromatography.

Explanation:

Please help thank you (15 points)

Answers

Answer:

A. Complete one revolution around the sun

A. to complete one revolution

Alkanes are chains of carbon atoms surrounded by hydrogen atoms. Which alkane has the weakest dispersion attractive force?

Answers

methane because it’s the shortest alkane

explain dehydrogenation​

Answers

Answer:

Dehydrogenation is the process by which hydrogen is removed from an organic compound to form a new chemical (e.g., to convert saturated into unsaturated compounds).

In what state of matter is carbon dioxide normally found on Earth?​

Answers

Answer:

Gas

Explanation:

I believe that it is usually a gas on Earth.

draw a diagram to show what happened to the particle, when a liquid cools to a solid? ​

Answers

Hope it helps you

And do follow if you appreciate it

4-hydroxyl and 5- hydroxyl aldehydes exist primarily as a cyclic hemiacetals.draw the structures formed from 4-hydroxyl butanal

Answers

attached is the structure of 4 hydroxybutanal both in linear form and hemiacetal form

Which of the following is NOT a density formula?
Density = mass/volume
Density = volume/mass
mass = density x volume
volume = mass/density

Answers

The answer is A - density = mass/ volume.

Explanation:

There is a clear relationship between mass, density and volume. Unlike mass and volume, increasing the amount of material measured does not increase or decrease density. However, since volume deviates with changes in temperature and pressure, density can also change with temperature and pressure.

Density doesn’t depend on mass and volume because there are many different mass and volumes when it becomes density.

An certain element Y has two naturally occurring isotopes, 6Y (isotopic mass = 6.015123 amu) and 7Y (isotopic mass = 7.016005 amu). If the atomic mass of the element is 6.9412 amu. What is the percent abundance of 6Y?

Do not include the symbol "%" in your answer.

Report the correct answer to three significant figures

Answers

The percentage abundance of  6Y is 0.102.

An Isotope refers to two or more atoms that has the same atomic number but different mass  numbers.

We have been informed from the question that the atomic mass of the element is 6.9412 amu.

Let the abundance of isotope 6Y be x

Let the abundance of isotope 7Y  be 1-x

Hence;

6.9412 = 6.015123x + 7.016005(1 - x)

6.9412 = 6.015123x + 7.016005 - 7.016005x

6.9412 - 7.016005 = 6.015123x - 7.016005x

-0.102 = -1x

x = -0.102/-1

x = 0.102

Hence the percentage abundance of isotope 6Y is 0.102.

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The percentage abundance of 6Y is 7.47%

Isotopy is the phenomenon whereby two or element have the same atomic number but different mass number due to the difference in their neutron number.

We'll begin the solving as follow:

Let A represent isotope 6Y

Let B represent isotope 7Y

From the question given above, the following data were obtained:

For isotope A (6Y):

Mass of A = 6.015123 amu

Abundance of A (A₀) =…?

For isotope B (7Y):

Mass of B = 7.016005 amu

Abundance of B (B₀) = (100 – A₀%

Relative Atomic mass of Y = 6.9412 amu

The abundance of 6Y can be obtained as follow:

[tex]RAM = \frac{MassA * A_{0} }{100} + \frac{MassB * B_{0} }{100}\\\\6.9412 = \frac{6.015123 * A_{0}}{100} + \frac{7.016005 (100 - A_{0})}{100}\\\\6.9412 = 0.06015123 A_{0} + \frac{701.6005 - 7.016005A_{0}}{100}\\\\6.9412 = 0.06015123 A_{0} + 7.016005 - 0.07016005A_{0}[/tex]

Collect like terms

[tex]6.9412 - 7.016005 = 0.06015123A_{0} - 0.07016005A_{0}\\-0.074805 = -0.01000882A_{0}[/tex]

Divide both side by –0.0100882

[tex]A_{0} = \frac{-0.074805}{-0.01000882}\\\\[/tex]

A% = 7.47%

Therefore, the abundance of 6Y is 7.47%

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