Due tomorrow plz help me

[tex]5x + 3 = - 9 \\ = > 5x = - 9 - 3 \\ = > 5x = - 12 \\ = > x = \frac{ - 12}{5} \\ = > x = - 2 \frac{2}{5} [/tex]

Option A .

[tex] - 2 \frac{2}{5} [/tex]

Answer:

hope it helps you..........

Answer:

207 cm

Step-by-step explanation:

Because ΔPQR ≅ΔSTU and the longest side in the ΔPQR is RP then the longest side in ΔSTU must be SU = 92 cm

Perimeter of triangle PQR is

P(ΔPQR) = 36+48+24 = 108 cm

Because the triangles are are similar their sides are in proportion.

But how much bigger did the second triangle get?...is (92/48) times bigger

P(ΔSTU) = 180*(92/48) = 207 cm

...you can also use proportions to find each side and then find the perimeter

TU = 24*92 /48 = 46

TS = 36*92/48 = 69

SU = 92

P(ΔSTU) = 92+69+46 =207 cm

*the triangles are not drawn to scale

13. M=4/3

14. m=-6

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

1 is the first natural number because 0 is not a natural number.

All natural numbers are numbers from 1 onward.

Ex. 1.2.3.4.5.6...

Answer: 79798

Step-by-step explanation:

139101 - 59303

= 79798

please give me a brainliest answer

Answer:

79798

Step-by-step explanation:

  69632

+ 69469

=  139101

-   59303

=  79798

Hope this helps :)

Answer:

(X+1) (x - 4) (x+2)

Step-by-step explanation:

All the coefficients are integers so apply the rational zeros theorem.

The coefficient of x^3 is 1.

Divide (x^3-x2-10x-8)(x+1) = x^2-2x-8 with remainder = 0

The remainder is 0. (x+1) is a factor.

(x + 1) ( x^2 - 2x - 8)

x^2 - 2x - 8 (-4 * 2= 8) and -4 + 2 = -2)

= (x -4) (x+2)

Answer:

No

Step-by-step explanation:

Answer:

No, it will not be the same shade of green.

Step-by-step explanation:

For the shade of green to be equivalent that person would need both of the proportions to be equal weather it is 6/4 and 12/8 or 8/5 16/10.

The ratios 8/5 and 6/4 do not match therefore the green the batches make will not be equal.

I hope this helps :D

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that

[tex] \purple{\rm :\longmapsto\:Dividend = {x}^{3} - {2x}^{2} - x + 2}[/tex]

and

[tex] \purple{\rm :\longmapsto\:Divisor = x + 1}[/tex]

So, By using Long Division Method, we have

[tex]\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\: {x}^{2} - 3x + 2\:\:}}}\\ {\underline{\sf{x + 1}}}& {\sf{\: {x}^{3}  -  {2x}^{2} - x + 2 \:\:}} \\{\sf{}}& \underline{\sf{- {x}^{3} - {x}^{2} \: \: \:  \:  \:  \:  \:  \:  \:  \: \:\:}} \\ {{\sf{}}}& {\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  - 3{x}^{2} - x +2  \:  \:  \:  \:   \:  \:  \:  \:\:}} \\{\sf{}}& \underline{\sf{\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  3{x}^{2} + 3x  \:  \:  \:  \:  \:  \: \:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 2x + 2 \:\:}} \\{\sf{}}& \underline{\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: - 2x - 2\:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 0\:\:}}  \end{array}\end{gathered}\end{gathered}\end{gathered}[/tex]

So,

[tex]\bf\implies \:Remainder = 0[/tex]

Verification

[tex] \purple{\rm :\longmapsto\:Dividend = {x}^{3} - {2x}^{2} - x + 2}[/tex]

[tex] \purple{\rm :\longmapsto\:Divisor = x + 1}[/tex]

[tex] \purple{\rm :\longmapsto\:Remainder = 0}[/tex]

[tex] \purple{\rm :\longmapsto\:Quotient = {x}^{2} - 3x + 2}[/tex]

Now, Consider

[tex]\rm :\longmapsto\:Divisor \times Quotient + Remainder[/tex]

[tex]\rm \:  =  \: (x + 1)( {x}^{2} - 3x + 2) + 0[/tex]

[tex]\rm \:  =  \: {x}^{3} - {3x}^{2} + 2x + {x}^{2} - 3x + 2[/tex]

[tex]\rm \:  =  \: {x}^{3} - {2x}^{2} - x + 2[/tex]

[tex]\rm \:  =  \: Dividend[/tex]

Hence, Verified

CARRY ON LEARNING

CAN YOU BRAINLEST ME PLEASE

Answer:

Step-by-step explanation:

Answer:

m=-2/-1 or m=-2

Step-by-step explanation:

Find two points on the line, then use this formula:  m=rise/run  or m=y2-y1/x2-x1

m=0- 2/-3-(-2)

m=-2/-1 or m=-2

The answer is x=−4 and y=−3

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given expression is

[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]

can be rewritten as

[tex]\rm \:  =  \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]

And

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]

So, using this identity, we

[tex]\rm \:  =  \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]

can be further rewritten as

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{25 - 1} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{24} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{6} [/tex]

Hence,

[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]

Answer:

-2

Step-by-step explanation:

It's (x,y)

Here, (3,-2)

-2 is y

:)

Answer:

4

Step-by-step explanation:

x= 18÷4.5=4

hope it helps

Answer:

hope this helps

Answer:

88 blankets

Step-by-step explanation:

5 times 15 = 75

75 + 13 = 88

Answer:

(5,-12)

(-3,0)

(-1,-1)

Step-by-step explanation:

For (4, −12): 2(4) - 12 = 8 - 12 = -4                  [false]

For (−3, 0): 2(-3) = -6 < -4                                [false]

For (5, −12): 2(5) - 12 = 10 - 12 = -2 > -4         [true]

For (0, 1): 2(0) + 1 = 1 > -4                              [true]

For (−1, −1): 2(-1) - 1 = -2 - 1 = -3 > -4            [true]

Therefore, (5, -12), (0, 1) and (-1, -1) satisfies the inequality 2x + y > -4

For (7, 12): 12 - 2(7) = 12 - 14 = -2 > -3                   [false]

For (0, −2): -2 - 2(0) = -2 > -3                                   [false]

For (5, −3): -3 - 2(5) = -3 - 10 = -13 < -3                   [true]

For (−6, −3): -3 - 2(-6) = -3 + 12 = 9 > -3                  [false]

For (1, −1): -1 - 2(1) = -1 - 2 = -3                              [true]

Therefore, (5, -3) and (1, -1) satisfy the inequality y - 2x ≤ -3

The situation is represented by 2.25x + 2.65y ≥ 8

Answer:

10, 80 and 90 degrees.

Step-by-step explanation:

The third angle will  90 - 10 = 80 degrees.

Answer:

y = 2x - 1

Step-by-step explanation:

Slope = (5-1) / (3-1) = 4/2 = 2

y-intercept = 1 - (2)(1) = - 1

y = 2x - 1

Answer:

the answer would be:

g(X)

and

m(X)

Step-by-step explanation:

make me as Brainliest sorry if I am wrong

Answer:

(3,7) is not a solution

Step-by-step explanation:

You fill in the values x=3 and y=7 in both equations and see if you end up with something that is true.

-5·3 - 2·7 = 23 is not true, because it simplifies to -29 = 23

no need to look further, but if you would, the second equation is also false:

3 + 4·7 = -19 is also not true.

The real solution by the way is (-3, -4).

[tex] \sf \underline{ \red{Solution - }} \\ [/tex]

Given,

[tex] \sf{\quad { \dfrac{-7}{\sqrt{11} - \sqrt{5}} }} \\ [/tex]

The denominator is √11 - √5.

We know that

Rationalising factor of √a-√b is √a+√b.

Therefore, the rationalising factor of √11-√5 is √11+√5.

On rationalising the denominator them

[tex] \longrightarrow \sf{\quad { \dfrac{-7}{\sqrt{11} - \sqrt{5}} \times \dfrac{(\sqrt{11} + \sqrt{5})}{(\sqrt{11} + \sqrt{5})} }} \\ [/tex]

Multiplying (√11 + √5) with both the numerator of the fraction.

[tex] \longrightarrow \sf{\quad { \dfrac{-7(\sqrt{11} + \sqrt{5}) }{(\sqrt{11} - \sqrt{5})(\sqrt{11} + \sqrt{5})} }} \\ [/tex]

Performing multiplication in the numerator and by using identity (a + b)(a - b) = a² - b², solving further in the denominator.

[tex] \longrightarrow \sf{\quad { \dfrac{-7\sqrt{11} -7\sqrt{5}}{(\sqrt{11})^2 - (\sqrt{5})^2} }} \\ [/tex]

Writing the squares of the numbers in the denominator.

[tex] \longrightarrow \sf{\quad { \dfrac{-7\sqrt{11} -7\sqrt{5}}{11 -5} }} \\ [/tex]

Performing subtraction in the denominator.

[tex] \longrightarrow \quad \underline{ \boxed{ \dfrac{ \textbf{ \textsf{-7 }}\sqrt{ \textbf{ \textsf{11 }}} - \textbf{ \textsf{7}}\sqrt{ \textbf{ \textsf{5 }}}}{ \textbf{ \textsf{ 6}}}} } \\ [/tex]

Hence, the denominator is rationalised.

Answer:

4(x + 1/4) ≤ 9 + 2x

Step-by-step explanation:

Answer:

N=20

Step by Step:

First you add 17 to both of the sides:

N−17+17=3+17

Second, you simplify;

N=20

Brainiest please?

Answer:D

Step-by-step explanation:

Answer:

X=2

Step-by-step explanation:

Answer:

x = 2

Step-by-step explanation:

I am pretty good at math.

Answer:

$130.00

Step-by-step explanation:

674-284=390

390/3=130

what that person said :(

Answer:

1) y=3.5+(5•x)

2) 103.5

3) No, because 5•20 is 100 and 5•10 is 50, BUT with both you still have to add 3.5 no matter what because of the $3.50 to pick up the rider

Answer:

im gonna go with c

Answer:

25

Step-by-step explanation:

remember that the pythagorean theorem is a²+b²=c²

so this equation would be:

7²+24²=c²

solve the exponents

49 + 576 = c²

combine like terms

625 = c²

take the radical of each number

√625 = √c²

25 = c

have a lovely day <3