DRAW THE TWO GRAPHS OF Y=+X^3 AND Y=-X^3 OF THE SAME AXEL SYSTEM

Answer:

3 hours

Step-by-step explanation:

1200/400=3

Answer:

Step-by-step explanation:

The two rays with the same endpoint in the figure below are AB and BC. Although they share a common endpoint (B), they do not form an angle since they are collinear and lie on the same line. Two non-collinear rays that share an endpoint create an angle. In this case, AB and BC lie on line AC and do not form an angle.

An angle is formed by two rays that originate from a common endpoint. In the given figure, AB and BC share the same endpoint (B), but they do not form an angle since they lie on the same line. A line is an infinite set of points that extends in both directions, while a ray is a portion of a line that starts at a particular point and extends infinitely in one direction. When two rays share a common endpoint, they form an angle only if they are not collinear, i.e., they do not lie on the same line. In this case, since AB and BC lie on line AC, they do not form an angle. Therefore, AB and BC are collinear and do not form an angle.

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Approximate percent increase in attendance between the first and second game is 8.9%.

What is the approx. percentage increase in attendance between the first and second football games?

To calculate the percent increase in attendance between the first and second game, we can use the formula:

percent increase =

[(new value - old value) / old value] x 100%

where the old value is the attendance at the first game and the new value is the attendance at the second game.

Substituting the given values, we get:

percent increase = [(476 - 437) / 437] x 100%

percent increase = (39 / 437) x 100%

percent increase ≈ 8.92%

Rounding to the nearest tenth percent, we get the approximate percent increase in attendance between the first and second game as 8.9%.

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Answer:

Apple Pie = 66.67%

Cherry Pie = 16.67%

Peach Pie = 16.67%

A possible distribution of pie percentages could be 66.67% apple, 16.67% cherry, and 16.67% peach.

Step-by-step explanation:

Let's assume that the bakery has 1 peach pie. Then, according to the problem statement, the bakery has 4 apple pies.

So, the total number of pies is 1 + 4 + 1 = 6.

To find the percentage of each type of pie, we need to divide the number of each type of pie by the total number of pies and multiply by 100%.

Percentage of apple pies: (4/6) x 100% = 66.67%

Percentage of cherry pies: (1/6) x 100% = 16.67%

Percentage of peach pies: (1/6) x 100% = 16.67%

Therefore, a possible distribution of pie percentages could be 66.67% apple, 16.67% cherry, and 16.67% peach.

It is important to note that this is just one possible distribution based on the information given in the problem. If we were given different information, such as the total number of pies, the percentages could be different.

Answer:

b. 1/4

Step-by-step explanation:

Probability of rolling even number = 3/6 = 1/2

Probability of tails = 1/2

Multiplying these two probabilities, we have 1/4.

Answer:

Without an image or a more detailed description of the diagram, it's difficult to provide an exact answer to this problem. However, we can use some logical reasoning to try to solve it.

Let's assume that the three lines of three numbers are arranged in a Tic-Tac-Toe grid, like this:

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A B C

D E F

G H I

We know that the product of the three numbers in each line is the same. Let's call this product "P". Then we can write:

CSS

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A * B * C = P

D * E * F = P

G * H * I = P

If we divide the second equation by the first equation, we get:

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(D * E * F) / (A * B * C) = 1

Since all the numbers are single-digit, this means that either D or F is equal to A, B, C, or 1. If D or F is equal to 1, then E is also equal to 1, which means that the entire middle row is filled with 1s, and that cannot be the case since all the numbers are different.

Therefore, we can assume that either D or F is equal to one of the numbers in the top row. Without further information, we cannot determine which one it is, but we know that the product of the numbers in the bottom row must be divisible by the product of the numbers in the top row. This means that the number in the circle containing the question mark must be a factor of this product, and it must be different from all the other numbers in the diagram.

Again, without more information, we cannot determine the exact number in the circle containing the question mark, but this logic should help narrow down the possibilities.

Step-by-step explanation:

The average movie ticket cost in Switzerland and Japan each of these​ countries is 46.97.

Let's assume that the average cost of a movie ticket in Japan is x, and the average cost of a movie ticket in Switzerland is y.

According to the problem statement, we can write two equations based on the given information:

3x + 2y = 78.5 ...(1)

2x + 3y = 74.1 ...(2)

We can solve these equations simultaneously to find the values of x and y. Here's how:

Multiply equation (1) by 2 and equation (2) by 3, then subtract equation (1) from equation (2):

(2x + 3y) - 2(3x + 2y) = 74.1 - 2(78.5)

Simplifying this equation, we get:

-y = -109.3

Therefore, y = 109.3.

Now substitute y = 109.3 into either equation (1) or (2) and solve for x:

3x + 2(109.3) = 78.5

Simplifying this equation, we get:

3x = -140.9

Therefore, x = -46.97.

However, we cannot have negative ticket prices.

Therefore, the average cost of a movie ticket is 46.97.

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Answer:

Look at the green dot

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]2\times \frac{5}{8} = \frac{2}{1} \times\frac{5}{8}= \frac{10}{8}[/tex]

[tex]10\times \frac{1}{8} =\frac{10}{1} \times \frac{1}{8}= \frac{10}{8}[/tex]

So yes they are the same.

A equals (x+3) and b equals (x-3) the statement that is true for the two division problems is that a equals factor (x+3) and b equals (x-3).

For the first division problem, [tex](x^2-3x-18)[/tex]÷(x-6), the quotient is (x+3). To solve for the quotient, you first need to factor the numerator, which is (x-6)(x+3). Then, you need to divide the numerator by the denominator, which is (x-6). The quotient is (x+3). For the second division problem, [tex](x^3-x^2-5x-3)/(x^2+2x+1)[/tex], the quotient is (x-3). To solve for the quotient, you first need to factor the numerator, which is (x+1)(x-3). Then, you need to divide the numerator by the denominator, which is [tex](x^2+2x+1)[/tex]. The quotient is (x-3). Therefore, the statement that is true for the two division problems is that a equals (x+3) and b equals (x-3).

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Step-by-step explanation:

Let's assume that the monthly income of the family is x.

From the problem statement, we know that the ratio of monthly income to the monthly saving is 9:2.

Therefore, we can write:

x/4320 = 9/2

To solve for x, we can cross-multiply:

2x = 9*4320

2x = 38,880

x = 19,440

So, the monthly income of the family is Rs 19,440.

To find the monthly expenditure, we can subtract the monthly savings from the monthly income:

Monthly expenditure = Monthly income - Monthly saving

Monthly expenditure = 19,440 - 4,320

Monthly expenditure = 15,120

Therefore, the monthly expenditure of the family is Rs 15,120

(a) Using the product rule for h(x) = f(x)g(x), h'(4) = 24

(b) Using the quotient rule, for h(x) = g(x) / (f(x) + g(x)), h'(4) = -33/49.

(c) Using chain rule for h(x) = f(g(x)), h'(4) = 80.

We can use the product rule, quotient rule, and chain rule to find the derivatives of the functions h(x).

(a) h(x) = f(x)g(x)

Using the product rule, we have:

h'(x) = f'(x)g(x) + f(x)g'(x)

At x = 4, we have:

h'(4) = f'(4)g(4) + f(4)g'(4) = 6(5) + 2(-3) = 24

Therefore, h'(4) = 24.

(b) h(x) = g(x) / (f(x) + g(x))

Using the quotient rule, we have:

h'(x) = [g'(x)(f(x) + g(x)) - g(x)f'(x)] / (f(x) + g(x))^2

At x = 4, we have:

h'(4) = [g'(4)(f(4) + g(4)) - g(4)f'(4)] / (f(4) + g(4))^2

= [(-3)(2 + 5) - 5(6)] / (2 + 5)^2

= -33 / 49

Therefore, h'(4) = -33/49.

(c) h(x) = f(g(x))

Using the chain rule, we have:

h'(x) = f'(g(x))g'(x)

At x = 4, we have:

h'(4) = f'(g(4))g'(4)

= f'(5)(10)

= 8(10)

= 80

Therefore, h'(4) = 80.

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Answer:

Daisy made 50 and Oscar made 40.

Step-by-step explanation:

Daisy: Oscar: total

5            4       5+4 = 9

Taking the total made and dividing by 9.

90/9 = 10

Multiply each term in the ratio by 10.

Daisy: Oscar: total

5*10      4*10      9*10

50           40        90

Daisy made 50 and Oscar made 40.

Answer: 63 US$

Step-by-step explanation:

Answer:

The answer is 1.5

Step-by-step explanation:

You just calculate in calculator and you will get the answer as 1.5

Thus, from the all given expressions, the number of servings Riley will ve using is 15/2 ÷  3/4.

Once kids have a firm grasp on proper fractions, they are introduced to mixed numbers and incorrect fractions. A mixed number combines an integer (whole number) and a fraction. It is also sometimes referred to as a mixed fraction (part of a whole number).

The composite number's fractional component needs to be a legal fraction (less than one whole). The numerator (top number) of a correct fraction is less than its denominator (bottom number),

Given data:

Convert the mixed fraction 7 1/2 in the proper fraction:

= 7 1/2

= (7*2 + 1)/2

= 15/2

Number of serving cups =  Total amount of salsa / Serving cup size

Number of serving cups =  15/2 ÷  3/4

Thus, from the all given expressions, the number of servings Riley will ve using is 15/2 ÷  3/4.

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Complete question:

Riley is dividing a batch of 7 1/2 cups of salsa into equal servings that are 3/4 cup each. Select all of the expressions that can be used to find the number of servings Riley will have.

Answer:

Step-by-step explanation:

As seen in earlier sections, the process of completing the square is a useful tool in finding noninteger values of quadratic equations, especially intercepts. When a quadratic equation of the

form f (x) = ax2

+ bx + c is put through the process of completing the square it yields an

equation of the form f (x) = a(x – h)2

+ k . The conversion of the equation to this form will

yield critical information about the equation’s characteristics before you begin to graph it.

1.) The value of h is the distance left (if negative) or right (if positive) the graph

translates from the standard position.

2.) The value of k is the distance up (if positive) or down (if negative) the graph

translates from the standard position.

3.) The values of h and k, when put together as an ordered pair, give the vertex i.e.

(h, k).

4.) The equation x = h is the formula for the axis of symmetry.

The following example demonstrates how to find the following critical information of the

equation:

a.) vertex

b.) axis of symmetry

c.) y intercept (if any)

d.) x intercepts (if any)

Example 1: Find the vertex, axis of symmetry, x-intercept(s), and y-intercept and gr

The value of the expression is 38 when z = 17.

Given that, an algebraic expression is described as 14 more than the product of 3 and the difference of z and 9.

First, we write the expression:

The difference of z and 9 means we subtract 9 from z. We then take this result and multiply it by 3.

Finally, we add 14 to the product of 3 and the difference of z and 9.

3(z - 9) + 14

Where z represents the value that we want to substitute into the expression.

Substituting z = 17, we get:

3(z - 9) + 14

3(17 - 9) + 14

3(8) + 14

24 + 14

38

Therefore, the value of the expression is 38.

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Answer:

To find the sum of money that amounts to Rs- 3450 in 4 months at the rate of 4.5% per annum, we can use the formula for simple interest:

Simple Interest = (Principal * Rate * Time) / 100

Where,

Principal = the sum of money borrowed or invested

Rate = the rate of interest per annum

Time = the time period in years

Since the time period given is 4 months, we need to convert it to years by dividing it by 12:

Time = 4/12 years = 1/3 years

Now, we can plug in the given values and solve for Principal:

Simple Interest = (Principal * Rate * Time) / 100

3450 = (Principal * 4.5 * 1/3) / 100

3450 * 100 = Principal * 4.5 * 1/3

11500 = Principal * 1.5

Principal = 11500 / 1.5

Principal = 7666.67 (rounded off to two decimal places)

Therefore, the sum of money that amounts to Rs- 3450 in 4 months at the rate of 4.5% per annum is Rs- 7666.67.

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Answer: The answer is [tex]\frac{5}{2}[/tex].

Step-by-step explanation:

We are given

25a = 10[tex]a^{2}[/tex].

First, we divide both sides by a

25 = 10a

Then we divide both sides by 10

[tex]\frac{5}{2}[/tex] = a

The probability that on a random select today he wrote at least one check is 0.407

Let X be the no.of checks the author wrote in a day

   Average,

u = 191 checks per year

191/365                        

= 0.5233/ day

       X~Poisson ( u- 0.5233)

The p.m.f of X is given by

P(X=x) =

The probability​ that, on a randomly selected day, he wrote at least one check = P(

               = 1 - P( X < 1)

               = 1 - P(X=0)

               = 1 - e^-0.5233 x 0.5233^0/0!

               = 1 - e^-0.5233 x 1/

               = 1 - 0.59256

               = 0.407

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A restaurant borrows $15,700 for two months from a nearby bank. For this loan, the neighbourhood bank charges simple interest at a yearly rate of 10%. Suppose a month is one-twelfth of a year.

a) $218.06 in interest will be due after two months.

b) In the event that the restaurant doesn't pay, the balance due after two months is $15,918.06.

a) To find the interest that will be owed after 2 months, we first need to calculate the monthly interest rate:

r = (10%)/12 = 0.00833333...

We can use the formula for simple interest to find the interest owed:

I = Prt

where P is the principal (the amount borrowed), r is the interest rate per period, and t is the time in periods. Since the loan is for 2 months, we have t = 2/12 = 1/6 years.

Substituting the values, we get:

I = 15700 * 0.00833333... * (1/6) = 218.0555...

Rounding to the nearest cent, the interest owed after 2 months is $218.06.

b) The total amount owed after 2 months is the sum of the principal and the interest. Using the same values as above, we have:

The total amount owed = Principal + Interest

= 15700 + 218.0555...

= 15918.0555...

Rounding to the nearest cent, the amount owed after 2 months is $15,918.06.

The complete question is:-

A restaurant borrows $15700 from a local bank for 2 months. the local bank charges simple interest at an annual rate of 10% for this loan. assume each month is 1/12 of a year. answer each below. do not round any intermediate computations, and round your final answers to the nearest cent, if necessary, refer to the lists of financial formulas.

a) find the interest that will be owed after 2 months.

b) assuming the restaurant doesn't make any payments, find the amount owed after 2 months.

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Using the equations, the particular solution is y_p(x)=-3x+1+2e⁻ˣ.

As we already know, homogeneous equations have zero on the right side of the equation. Thus, it is said that non-homogenous differential equations are those with a function on the right side of their equation.

We are given a non-homogeneous differential equation in the form:

y′′+3y′-3y=3xe^-1​

The differential equation is called non-homogeneous because it is known to have a non-zero right-hand side.

To solve this differential equation, we first need to find the complementary function, which is the solution to the corresponding homogeneous differential equation y′′+3y′-3y=0.

We then take the first and second derivatives of y_p(x) and substitute them into the differential equation, y′′+3y′-3y=3xe^-1​ and simplify.

This leads to the system of equations:

a + 3c = 3

a + 3b - 3c = 0

a + b + 3c = 1

Solving this system of equations, we find that a=-3, b=1, and c=2. Therefore, the particular solution is y_p(x)=-3x+1+2e⁻ˣ.

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This set of equations can be solved, and the results show that a=-3, b=1, and c=2. As a result, the specific answer is [tex]y_{p(x)} =-3x+1+2e^{-x}[/tex].

Homogeneous equations, as we already know, have "0" on the right side of the equation. Therefore, it is said that differential equations with a function on the right side of the equation are non-homogenous differential equations.

A non-homogeneous differential equation of the following shape is provided to us:

[tex]y^{''} +3y^{'} -3y=3xe^{-1}[/tex]

Since the right-hand side of the differential equation is known to be non-zero, it is referred to as non-homogeneous.

Finding the complementary function, which is the answer to the related homogeneous differential equation [tex]y^{''} +3y^{'} -3y=0[/tex], is the first step in solving this differential equation.

The differential equation [tex]y^{''} +3y^{'} -3y=3xe^{-1}[/tex] is then simplified by taking the first and second derivatives of [tex]y_{p(x)}[/tex] and substituting them into

the equation.

This results in the formulae system:

a + 3c = 3

a + 3b - 3c = 0

a + b + 3c = 1

This set of equations can be solved, and the results show that a=-3, b=1, and c=2. As a result, the specific answer is  [tex]y_{p(x)} =-3x+1+2e^{-x}[/tex].

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Following the basic principles and theory of simplifying fraction it is visible that this question follows the, the basic calculations involving the basic mathematics

Therefore the , let us take the given numerator that is 300 and then divide it using the denominator that is 25 ,

so, when we divide 300 /25 we get, the answer as12

because, when we divide both the numerator and denominator with 5 (because 25 and 300 are a divisible by 5 and are also multiples of )

we clearly see that 300 is divisible by 5 and the answer comes out to be 12.

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The probability that the sample mean would be less than 21583 dollars if a sample of 399 persons is randomly selected is approximately 0.0826 or 8.26% (rounded to four decimal places).

What is probability?

Probability is a way to gauge how likely something is to happen. It is a number between 0 and 1, where 0 denotes an impossibility and 1 denotes a certainty that the occurrence will occur.

We can use the central limit theorem (CLT) to approximate the sampling distribution of the sample mean. According to CLT, if we have a large enough sample size (n≥30), the sampling distribution of the sample mean will be approximately normal, regardless of the underlying distribution of the population.

The mean of the sampling distribution of the sample mean is the same as the population mean, which is given as μ = 21699 dollars per annum. The standard deviation of the sampling distribution of the sample mean is equal to the standard error of the mean (SEM), which is calculated as follows:

SEM = σ/√n, where n is the sample size, and is the total standard deviation.

With the numbers from the problem substituted, we obtain:

SEM = 835/√399 = 41.767

Now, we need to find the probability that the sample mean would be less than 21583 dollars. We can standardize the sample mean using the standard normal distribution as follows:

z = (x - μ) / SEM, where the sample mean is x.

Substituting the values, we get:

z = (21583 - 21699) / 41.767 = -1.389

Using a standard normal distribution table, we can find that the area to the left of z=-1.389 is 0.0826.

Therefore, the probability that the sample mean would be less than 21583 dollars if a sample of 399 persons is randomly selected is approximately 0.0826 or 8.26% (rounded to four decimal places).

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Using the derivative of the velocity, the average value of the position function from t = 2 seconds to t = 5 seconds is 14.5.

Given:

Acceleration function, a(t) = 2sin(t) + 1

Initial velocity, v(0) = 0

Initial position, s(0) = 3

To find:

Velocity function, v(t)

Position function, s(t)

Average value of the position function from t = 2 seconds to t = 5 seconds

Solution:

We know that acceleration is the derivative of velocity, and velocity is the derivative of position. So we can find the velocity and position functions by integrating the acceleration function.

Velocity function:

[tex]v(t) = \int a(t) dt\\v(t) = \int (2sin(t) + 1) dt\\v(t) = -2cos(t) + t + C1[/tex]

We know that the initial velocity, v(0) = 0. Substituting this value in the above equation, we get:

[tex]0 = -2cos(0) + 0 + C1\\C1 = 2[/tex]

Therefore, the velocity function is:

[tex]v(t) = -2cos(t) + t + 2[/tex]

Position function:

[tex]s(t) = \int v(t) dt\\s(t) = \int (-2cos(t) + t + 2) dt\\s(t) = 2sin(t) + \frac{1}{2} t^2 + 2t + C2[/tex]

We know that the initial position, s(0) = 3. Substituting this value in the above equation, we get:

[tex]3 = 2sin(0) + 0 + 0 + C2\\C2 = 3\\[/tex]

Therefore, the position function is:

[tex]s(t) = 2sin(t) + \frac{1}{2} t^2 + 2t + 3[/tex]

Average value of the position function from t = 2 seconds to t = 5 seconds:

We can find the average value of the position function using the following formula:

[tex]Avg = (1/(b-a)) * \int(a,b) f(t) dt[/tex]

Here, a = 2 and b = 5. So, substituting the values in the above formula, we get:

[tex]Avg = (1/(5-2)) * \int(2,5) (2sin(t) + \frac{1}{2} t^2 + 2t + 3) dt\\Avg = \frac{1}{3} * [ -2cos(t) + 1/6 t^3 + t^2 + 2t ] \eval(2,5)\\[/tex]

[tex]Avg = \frac{1}{3} * [ (-2cos(5) + 1/6 (5^3) + 5^2 + 25) - (-2cos(2) + 1/6 (2^3) + 2^2 + 22) ]\\Avg = 14.5[/tex]

Therefore, the average value of the position function from t = 2 seconds to t = 5 seconds is 14.5.

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Answer:

students need to produce a prime factorization of 48. Donna states that the first factors in the tree should be 6 and 8. Larry states that the first factors in the tree should be 4 and 12. Trish states that the initial factors of 48 do not affect the prime factorization. Explain why Trish is correct.Trish is correct because the initial factors of 48 do not affect the prime factorization. Prime factorization is the process of breaking down a composite number into its prime factors. The prime factors of a number are those factors that are prime numbers. The prime factorization of 48 is 2 x 2 x 2 x 2 x 3, which means that 48 can be expressed as a product of these prime factors. The order in which we choose the initial factors to start the prime factorization does not affect the result, as long as we continue to break down the resulting factors into their prime factors until we cannot break them down any further. Therefore, Trish is correct that the initial factors of 48 do not affect the prime factorization.

Trish is correct because the prime factorization of 48 will be the same regardless of which factors are chosen as the initial factors in the tree.

To see why, let's look at the prime factorization of 48:

48 = 2 × 2 × 2 × 2 × 3

No matter which factors are chosen as the initial factors, the same prime factors will eventually be found.

For example, if Donna's method is used, we could start with 6 and 8:

6 = 2 × 3

8 = 2 × 2 × 2

Then we could continue to factor each of these numbers until we reach prime factors:

6 = 2 × 3

8 = 2 × 2 × 2

= 2 × 2 × 2 × 3

= 2³ × 3

Now we have found all of the prime factors of 6 and 8, and we can combine them to get the prime factorization of 48:

48 = 2 × 2 × 2 × 2 × 3

If Larry's method is used, we could start with 4 and 12:

4 = 2 × 2

12 = 2 × 2 × 3

Then we could continue to factor each of these numbers until we reach prime factors:

4 = 2 × 2

12 = 2 × 2 × 3

= 2² × 3

Now we have found all of the prime factors of 4 and 12, and we can combine them to get the prime factorization of 48:

48 = 2 × 2 × 2 × 2 × 3

As we can see, the same prime factors are found regardless of which factors are chosen as the initial factors in the tree. Therefore, Trish is correct that the initial factors of 48 do not affect the prime factorization.