Drag each set of coordinates to the correct location on the table. Calculate the distance between the pairs of coordinates, and classify them according to the distance between them. (3, 4) and (2, 1) (3, 7) and (5, 2) (5, -2) and (3, 3) (-2, 3) and (1, 2) (-4, -2) and (-3, 1) (4, -1) and (-1, 1)

Answer:

5x^2+2x-7

Step-by-step explanation:

First find the common variable.

6x^2 + 10x -7 and -x^2 -8x

Add those together like any other problem.

[tex](6x^2 + 10x -7) + (-x^2 -8x)\\\\6x^2+10x-7 -x^2-8x\\\\(6x^2-x^2) + (10x-8x) - 7\\\\5x^2+2x-7[/tex]

When x = 1331, the value of y is 55.72. So, the answer is y = 55.72.

According to the given information, y varies directly at the cube root of x. This means that we can write the equation as y = k * (x)^(1/3), where k is a constant. We can find the value of k by plugging in the given values of y and x. So,100 = k * (6859)^(1/3) => k = 100 / (6859)^(1/3)Now, we can plug in the value of x = 1331 and k into the equation to find the value of y.y = 100 / (6859)^(1/3) * (1331)^(1/3) => y = 100 * (1331/6859)^(1/3) => y = 55.72 when x = 1331, the value of y is 55.72. So, the answer is y = 55.72.

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The coordinate of the other endpoint of the line segment is (-1, 2).

In geometry, a line segment is a part of a line that has two endpoints. It is the shortest distance between two points on a line. A line segment can be straight or curved, and can be vertical, horizontal, or diagonal.

The length of a line segment can be measured using units such as centimeters, inches, or feet. The midpoint of a line segment is the point that is exactly halfway between its endpoints, and it is located at the average of the x-coordinates and the y-coordinates of the endpoints.

Let (x, y) be the coordinate of the other endpoint of the line segment. Then, we know that the midpoint of the line segment is given by the formula:

midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Substituting the given values, we have:

(1, -2) = ((3 + x)/2, (-6 + y)/2)

Multiplying both sides by 2, we get:

(2, -4) = (3 + x, -6 + y)

Separating the x and y terms, we have:

2 = 3 + x -> x = -1

-4 = -6 + y -> y = 2

Therefore, the coordinate of the other endpoint of the line segment is (-1, 2).

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The sequence of transformations that maps △RST to △R′S′T′ is a translation of 6 units to the right and 2 units down, followed by a reflection across the y-axis, and finally a rotation of 90 degrees counterclockwise about the origin.

What is the sequence of transformation?

In mathematics, a sequence of transformations refers to a series of geometric transformations performed on a shape to create a new shape. These transformations can include translations, rotations, reflections, and dilations.

The sequence of transformations is the order in which the transformations are performed. The order matters because different sequences of transformations can lead to different final shapes.

For example, to transform a triangle into a new position, we might first perform a translation to move the triangle to a new location, then perform a rotation to change its orientation, and finally perform a reflection to flip the triangle across a line. The sequence of transformations in this case is translation-rotation-reflection.

Sequences of transformations are used in geometry to analyze and describe shapes and to solve problems related to symmetry, congruence, and similarity. They are also used in computer graphics and animation to create 2D and 3D shapes that can be moved and transformed on a screen.

To map △RST to △R′S′T′, we need to perform a sequence of transformations that includes translations, rotations, reflections, and/or dilations. Here's one possible sequence of transformations:

Translation: We can translate △RST by 6 units to the right and 2 units down to get a new triangle that has R at (3, -3), S at (5, -3), and T at (2, -7).

Reflection: We can reflect the translated triangle across the y-axis to get a new triangle that has R′ at (-3, -3), S′ at (-5, -3), and T′ at (-2, -7).

Rotation: We can rotate the reflected triangle 90 degrees counterclockwise about the origin to get a new triangle that has R′ at (3, -3), S′ at (3, -1), and T′ at (-1, -4).

Therefore, the sequence of transformations that maps △RST to △R′S′T′ is a translation of 6 units to the right and 2 units down, followed by a reflection across the y-axis, and finally a rotation of 90 degrees counterclockwise about the origin.

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If the discount net price is $7,800 and Net Price Factor, trade discount are to be calculated, then trade discount is equal to $1,170 and Net Price Factor is equal to 0.9216.

The formula used for Trade Discount is given as product of List Price and Trade Discount Rate. The value of list price is given as $7,800.00 and that of Trade Discount Rate is 0.15. Putting the given values in the formula, we get the following result:

Trade Discount = $7,800.00 x 0.15 = $1,170.00

Cash Discount 2 = 4% of (Net Price - Cash Discount 1)

∵ Net Price Factor = (100% - 4%) x (100% - 4%) / 100%

⇒ Net Price Factor = 0.9216

Single Equivalent Discount = (1 - Net Price Factor) x 100%

∴ Single Equivalent Discount = (1 - .9216) x 100%

Single Equivalent Discount = 7.84%.

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Refer to complete question below:

Complete the following table by finding the net price factor, single equivalent discount, trade discount (in dollars), and net price in dollars). Round the net price factor and single equivalent discount to five decimal places, and the trade discount and net price to the nearest cent, when necessary. List Price Trade Discount Rate Net Price Factor Single Equivalent Discount Trade Discount Net Price $7,800.00 15/4/4

Subtracting the polynomial (1/6)c² + (1/9)c + 2 from (3/2)c² - (4/3)c + 9 will result to the polynomial (4/3)c² + (-13/9)c + 7.

To subtract the polynomials, we need to subtract the corresponding terms. That is, we subtract the coefficients of the c² terms, the coefficients of the c terms, and the constant terms. The result will be a new polynomial. Here is the solution:

((3)/(2)c² - (4)/(3)c + 9) - ((1)/(6)c² + (1)/(9)c + 2)
= (3/2)c² - (4/3)c + 9 - (1/6)c² - (1/9)c - 2
= (3/2 - 1/6)c² + (-4/3 - 1/9)c + (9 - 2)
= (8/6)c² + (-13/9)c + 7
= (4/3)c² + (-13/9)c + 7

So the answer is (4/3)c² + (-13/9)c + 7.

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The maximum of the sinusoidal function is 4

From the question, we have the following parameters that can be used in our computation:

The graph of the sinusoidal function

In the graph of the sinusoidal function, we can see that

The maximum is at y = 4

Also, we can see that

The minimum is at y = 1

Hence, the maximum is 4

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So the probabilities of the given events are:

P(X = 5) = 1/9
P(2 ≤ X ≤ 6) = 5/12
P(X = 5 or X = 10) = 7/36

To find the probabilities of the given events, we need to consider all the possible outcomes of the two dice-throwing experiments and the number of favorable outcomes for each event.

There are 6 possible outcomes for each die, so the total number of possible outcomes for the two dice is 6 × 6 = 36.

For the event X = 5, the favorable outcomes are (1, 4), (2, 3), (3, 2), and (4, 1). So the probability of this event is P(X = 5) = 4/36 = 1/9.

For the event 2 ≤ X ≤ 6, the favorable outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (4, 1), (4, 2), and (5, 1). So the probability of this event is P(2 ≤ X ≤ 6) = 15/36 = 5/12.

For the event X = 5 or X = 10, the favorable outcomes are (1, 4), (2, 3), (3, 2), (4, 1), (4, 6), (5, 5), and (6, 4). So the probability of this event is P(X = 5 or X = 10) = 7/36.

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Answer:

27+X=42

X=15

Step-by-step explanation:

interior opposite angle are equal.

After 3 years and 9 months, the copier is worth $30,750. After 5 years, the salvage value of the copier is $35,000. The domain of the function is 0 <= t <= 5.

a. To find the value of the copier after 3 years and 9 months, we need to plug in the value of t into the function V(t). Since 3 years and 9 months is equivalent to 3.75 years, we plug in 3.75 for t:
V(3.75) = 3400(3.75) + 18000
V(3.75) = 12750 + 18000
V(3.75) = 30750
Therefore, the copier is worth $30,750 after 3 years and 9 months.

b. To find the salvage value of the copier after 5 years, we need to plug in 5 for t into the function V(t):
V(5) = 3400(5) + 18000
V(5) = 17000 + 18000
V(5) = 35000
Therefore, after 5 years, the salvage value of the copier is $35,000.

c. The domain of this function is the set of all possible values of t. Since the function is defined for the first 5 years of use, the domain is 0 <= t <= 5.

d. To sketch the graph of this function, we can plot a few points and connect them with a line. For example, we can plot the points (0, 18000), (1, 21400), (2, 24800), (3, 28200), (4, 31600), and (5, 35000). The graph will be a straight line with a positive slope, starting at (0, 18000) and ending at (5, 35000).

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Answer:

whats the equation

Step-by-step explanation:

Answer:

To simplify the expression, we need to distribute the negative sign to all the terms inside the parentheses, and then combine like terms.

Starting with:

(5x^4-4x^3-2x^2+x-19)-(x^4+5x^3+8x^2+x+5)

Distribute the negative sign inside the parentheses:

5x^4 - 4x^3 - 2x^2 + x - 19 - x^4 - 5x^3 - 8x^2 - x - 5

Now we can combine like terms:

(5x^4 - x^4) + (-4x^3 - 5x^3) + (-2x^2 - 8x^2) + (x - x) + (-19 - 5)

Simplifying further:

4x^4 - 9x^3 - 10x^2 - 24

Therefore, the simplified expression is:

4x^4 - 9x^3 - 10x^2 - 24.

b=7

------------------

Answer:10

Step-by-step explanation:

A^2 + B^2 = C^2

8^2 + 6^2 = 100^2

take the square root since c is squared

sqrt 100 = 10

Answer:

Step-by-step explanation:

10

By answering the supplied question, we may infer that the response is slope As a result, the equation's y-intercept is equal to -8.

A line's slope determines how steep it is. The gradient is mathematically expressed as gradient overflow. By dividing the vertical change (run) between two spots by the height change (rise) between the same two locations, the slope is determined. The equation for a straight line, y = mx + b, is written as a curve form of an expression. When the slope is m, b is b, and the line's y-intercept is located (0, b). For instance, the y-intercept and slope of the equation y = 3x - 7 (0, 7). The location of the y-intercept is where the slope of the path is m, b is b, and (0, b).

The slope of the line is represented by the coefficient of x in the equation Y = -6x - 8.

As a result, the equation's slope is -6.

-8, the line's y-intercept, serves as the equation's constant term.

As a result, the equation's y-intercept is equal to -8.

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The perimeter, in miles, of the rectangle formed by connecting the points representing the cabana, beach, water slide, and roller coaster will be 22 miles.

The perimeter of a form is the space surrounding its edge. Find the perimeter of various forms by summing the lengths of their sides.

Given, a coordinate system where 1 unit = 1 mile

Lets,

First, calculate the linear distance between adjacent points as displayed in the graph.

Distance between car to cabana = 4 units = 4 miles

Distance between cabana to beach = 6 units = 6 miles

Distance between beach to water slide = 5 units = 5 miles

Distance between water slide to roller coaster = 6 units = 6 miles

Distance between roller coaster to cabana =5 units = 5 miles

Thus,

1) the perimeter, in miles, of the rectangle formed by connecting the points representing the cabana, beach, water slide, and roller coaster:

Perimeter = 6 + 5 + 6 + 5

Perimeter = 22 miles

2) the total distance in miles from the car to the cabana and then from the cabana to the beach:

Distance = 4 + 6

Distance = 10 miles

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Answer: 515,783

Step-by-step explanation:  f(x)= a(1+r)^x      450,000(1+0.023)^6

Answer: internal systolic blood pressure (100,110).

Step-by-step explanation:

Given the systolic blood pressure is normally distributed with a

mean G 105  and a standard leviation 5 .

to find : using empirical rule determines  the interval

dyslolie blood pressure that represent the middle 68% malen

solution 68% value  lie within 1 standard deviation the mean .

            { using empirical rule 2

we cab express this range as :

= (x -s , x +s)

= (105 -5, 105+5)

= (100 , 110)

The length of the tarp with an area of 200 square meters is 40 meters.

The area of a rectangle is expressed as;

Area = length × width

Given that;

When a rectangular tarp has an area of 200 square meters and a width of 5 meters, we can use the above formula to find the length of the tarp.

Plug these values into the formula and solve for the length:

Area = length × width

200 = Length x 5

To solve for Length, we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by 5:

200/5 = Length

This simplifies to:

40 = L

L = 40

Therefore, the rectangular tarp is 5 meters wide and 40 meters long.

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The degree of the monomial -7q² + r³ + s⁶ is 11.

An algebraic expression is a combination of variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. It represents a mathematical phrase or sentence and can be simplified or evaluated by substituting numerical values for variables.

The degree of a monomial is the sum of the exponents of its variables.

In the given monomial, -7q² + r³ + s⁶, the variables are q, r, and s, and their exponents are 2, 3, and 6, respectively.

So, the degree of the monomial is the sum of these exponents:

degree = 2 + 3 + 6 = 11

Therefore, the degree of the monomial -7q² + r³ + s⁶ is 11.

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The value of x is 23°

A line is a straight, one-dimensional figure that extends infinitely in both directions. It is often represented graphically as a straight line on a coordinate plane, with an equation that describes its position.

A line can be defined by any two points on it, and every point on the line can be expressed as a linear combination of those two points.

Line j and k are parallel and another line crossing it means transversal line, then the corresponding angles are equal which is,

(5x+9)° = (4x+32)°

5x-4x = 32-9

x = 23°

Therefore, the value of x is 23°

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The values of m that will result in a repeated solution for 3x^(2)+4mx+m=0  are m = 0 and m = 3/4.

The given quadratic equation is 3x^(2)+4mx+m=0. In order to find the value(s) of m that will result in a repeated solution, we need to use the discriminant of the quadratic formula.

The discriminant of the quadratic formula is given by b^(2)-4ac, where a, b, and c are the coefficients of the quadratic equation.

In the given equation, a = 3, b = 4m, and c = m.

Plugging these values into the discriminant, we get:

(4m)^(2)-4(3)(m) = 16m^(2)-12m = 0

A repeated solution occurs when the discriminant is equal to 0. So, we need to solve the equation 16m^(2)-12m = 0 for m.

Factoring out a common factor of 4m, we get:

4m(4m-3) = 0

This gives us two possible values for m:

4m = 0 or 4m-3 = 0

Solving for m, we get:

m = 0 or m = 3/4

Therefore, the values of m that will result in a repeated solution for the given quadratic equation are m = 0 and m = 3/4.

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We have to, the solution to the inequality is x >= -2

How to solve the inequality?

To solve the inequality 10x >= -20, we need to isolate the variable x on one side of the inequality sign. We can do this by dividing both sides of the inequality by 10. This gives us:

10x/10 >= -20/10

Simplifying the fractions gives us:

x >= -2

Therefore, the solution to the inequality is x >= -2. This means that any value of x that is greater than or equal to -2 will satisfy the inequality.

Answer: x >= -2

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2 divided by 4 and 3 divided by 6 where these number can be any numbers that have the same ratio as 1:2 and under 0-6 and not repeating them.

A number is a fundamental building block of mathematics. For a range of tasks, including measuring, counting, and indexing, numbers are utilised. There are different types of numbers depending on their characteristics, such as natural numbers, whole numbers, rational and irrational numbers, integers, real numbers, complex numbers, even and odd numbers, etc. The basic integer arithmetic operations can be used to calculate the outcome number.

In the given question, we need to find two sets of three distinct numbers between 0 and 6 that have the same ratio.

One possible solution is:

2 divided by 4.

= 3 divided by 6

Here:

The ratio of the first set is 2:4 or 1:2. When we divide 2 by 4, we get 0.5.

The ratio of the second set is 3:6 or 1:2. When we divide 3 by 6, we also get 0.5.

Therefore, we have:

2 divided by 4.

= 0.5

3 divided by 6.

= 0.5

So, we can say:

2 divided by 4

= __ divided by __

where 3 and 6 can be any numbers that have the same ratio as 1:2.Similarly,

3 divided by 6

= __ divided by __

where 3 and 6 can be any numbers that have the same ratio as 1:2.

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The tangent trigonometry ratio can be used to determine the measure of m∠F using the length shown. Option C is correct

The given figure is a right triangle.

According to the question, we are to determine the trigonometry ratio that can be used to find m∠F.

Given the following sides

Hypotenuse = EF

Opposite to m∠F = DE

Adjacent = DF

Since tan m∠;F = opposite/adjacent = DE/DF

tan m∠F can be used to determine m∠F.

The same goes with tan and sine since we can determine the value of the hypotenuse but only tangent can be used to find the measure given the length shown.

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The triangles which are right triangles as required to be determined in the task content are; Choice A; Triangle 1 and Choice D; Triangle 4.

Recall; the Pythagorean theorem only holds for right triangles.

Therefore, for a triangle to be a right triangle; the square of its longest side must be equal to the sum of squares of its two other sides.

Therefore;

Triangle 1 is a right triangle because; (√106)² = 9² + 5²; 106 = 106.

Triangle 2 is not a right triangle because; (√39)² ≠ 2² + 6²; 39 ≠ 40.

Triangle 3 is not a right triangle because; (√179)² ≠ 6² + 12²; 179 ≠ 180.

Triangle 4 is a right triangle because; (√73)² = 3² + 8²; 73 = 73.

Ultimately, the correct choices are; Choices A ana D.

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The final answer is 2x^3 +x^2 +3x+5 = (2x^2 + 3x + 6)(x−1) + 11.

(2) To solve the inequality |2x − 5| ≤ 9, we need to split it into two separate inequalities and solve for x:
2x − 5 ≤ 9 and 2x − 5 ≥ −9
2x ≤ 14 and 2x ≥ 4
x ≤ 7 and x ≥ 2
The solution in interval notation is [2, 7].

(3) To find the inverse of the function f(x) = 5/(6x−1), we need to switch the x and y values and solve for y:
x = 5/(6y−1)
6y−1 = 5/x
6y = 5/x + 1
y = (5/x + 1)/6
The inverse function is f^(-1)(x) = (5/x + 1)/6.

(4) To find fg and fg, we need to plug in the functions for x and simplify:
fg(x) = f(g(x)) = √(x^2−11x+30−4) = √(x^2−11x+26)
fg(x) = g(f(x)) = (√x−4)^2−11(√x−4)+30 = x−8√x+16−11√x+44+30 = x−19√x+90
The domain of fg is all real numbers greater than or equal to 26, and the domain of fg is all real numbers greater than or equal to 0.

(5) To find the equation of the line perpendicular to y = 35 x − 4 and passing through the point (1, 2), we need to find the slope of the perpendicular line and use the point-slope form:
The slope of the original line is 35, so the slope of the perpendicular line is -1/35.
Using the point-slope form, y − y1 = m(x − x1), we get:
y − 2 = −1/35(x − 1)
y = −1/35x + 2 + 1/35
y = −1/35x + 71/35
The equation of the line in slope-intercept form is y = −1/35x + 71/35.

(6) To divide 2x^3 +x^2 +3x+5 by x−1 using long division, we need to divide each term of the dividend by the divisor and find the remainder:
2x^3 ÷ x = 2x^2
2x^2(x−1) = 2x^3−2x^2
(x^2 +3x+5) − (2x^3−2x^2) = 3x^2 +3x+5
3x^2 ÷ x = 3x
3x(x−1) = 3x^2−3x
(3x+5) − (3x^2−3x) = 6x+5
6x ÷ x = 6
6(x−1) = 6x−6
5 − (6x−6) = 11
The final answer is 2x^3 +x^2 +3x+5 = (2x^2 + 3x + 6)(x−1) + 11.

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The inverse of AB is B−1A−1

1. True. Every square matrix with ones down the main diagonal has an inverse, since the diagonal elements are all non-zero.
2. False. Generally, the determinant of B does not necessarily equal the determinant of A, even when B is a product of A and other matrices.
3. True. If a matrix A satisfies the equation A2=A, then its determinant is 0, since A=A2 implies detA=det(A2)=detA×detA=detA2=0.
4. True. If A and B are both invertible n×n matrices, then AB is also invertible, and the inverse of AB is B−1A−1.

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