does it take more or less force for something to slide across a surface then it does to change direction on the same surface

Answer:

Explanation:

freely falling object

Answer:

1.Collecting natural gas can have negative impacts on the environment in various ways. One of the major concerns is the process of hydraulic fracturing or fracking, which can contaminate groundwater and soil with chemicals and heavy metals used in the process. Methane emissions from natural gas operations can contribute to air pollution and climate change. Additionally, the construction and operation of infrastructure such as pipelines and wells can disrupt ecosystems, fragment habitats, and harm wildlife.

2.Collecting hydropower can also have both positive and negative impacts on the environment. On the positive side, hydropower generation does not emit greenhouse gases and can help reduce the use of fossil fuels. However, the construction of dams can significantly alter natural waterways, disrupt river ecosystems, and cause the displacement of people and wildlife. Dams can also interfere with fish migration patterns and reduce the availability of freshwater downstream, affecting agriculture and drinking water supplies. Additionally, the management of water levels and flows can lead to changes in water temperature, dissolved oxygen levels, and sediment transport, which can further impact aquatic habitats and species.

Explanation:

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The pressure at the bottom of both beakers is the same. The correct answer is D.

The pressure at the bottom of both beakers is the same. The pressure at the bottom of a fluid is determined by the weight of the fluid above it, which is the same for both beakers since they are equally filled with the same amount of liquid. The air pressure on the beakers does not affect the pressure inside the liquid.

The weight of both liquids cannot be the same, as the density of the liquid in beaker B is greater than that of water, so it will have a greater weight. The area at the bottom of the beakers may be the same or different, but it is not relevant to the pressure at the bottom. Therefore, the correct statement is D, that the pressure at the bottom of both beakers is the same.

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--The complete question is, Two identical beakers are both equally filled with a liquid. Beaker A contains water. Beaker B contains a liquid that is denser than water. Which statement is true?
A. The air pressure on the beaker containing dense liquid is greater.
B. The weight of both liquids is the same.
C. The area at the bottom of both beakers is the same.
D. The pressure at the bottom of both beakers is the same.--

The computed speed was found to be a number of 3.3333m/s

Given Data

We know that the expression for finding speed is given as

Speed = Distance/Time

Converting from km to m we have

m = 1*1000

Distance = 1000m

Converting from 5mins to seconds we have

300 seconds.

Now, Speed = 1000/300

Speed = 3.3333 m/s

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The velocity of the skydiver that fell directly toward Earth at a constant velocity for 15.0 seconds is 127.38m/s.

The velocity of a skydiver that fell directly towards Earth can be calculated using one of the following equations of motion:

s = ut - ½at²

Where;

According to this question, a skydiver fell directly toward Earth at a constant velocity for 15.0 seconds.

807 = 15u - ½ × 9.81 × 15²

807 + 1103.625 = 15u

1910.625 = 15u

u = 127.38m/s

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The magnitude of the resultant displacement of the caterpillar is 1.4m. Therefore, option B is correct.

The change in the position of an object is called displacement, it is the distance between starting and endpoints. It has both magnitude and direction, it is a vector quantity.

If a caterpillar climbs 1.3 m up a tree, then 0.72 m right, the magnitude of resultant displacement is given by:

H² = P² + B²

H² = (1.3)² + (0.72)²

H² = 1.69 + 0.51

H = [tex]\sqrt2.2[/tex]

H = 1.4m

Thus, the magnitude of the resultant displacement of the caterpillar is 1.4m. Therefore, option B is correct.

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The cross product of the vector A= 3i + 4j and B= -3i + 7j is found to be -33k.

The vector that are provided to us are vector A and vector B, the value of the vectors are A = 3i + 4j and B = -3i +7j

Now, we have to find the cross products that is given by, R = A X B,

So, we write that,

R = A X B

R = (3i + 4j) X (-3i +7j)

R = -21k - 12k

R = -33k

We have to note here that R is also a vector because the cross product of the two vector is also a vector always but when we do the dot products the resultant is not a vector.

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The amount of work (in Newton meters) that Helen did to get her car to the gas station is 4000 Newton meters

Work done is defined as illustrated by the formula given below:

Work done = force (F) × distance (d)

From the question given above, we were told that:

The work done by Helen can be obtained as shown below:

Work done = force (F) × distance (d)

Work done = 40 × 100

Work done = 4000 Newton meters

Thus, it is evident that the work done is 4000 Newton meters

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Two or more physical objects which are in contact with each other exert forces on each other. Here the tension of the cable is  16349.96 N.

The force along the length of a medium especially a force carried by a flexible medium, such as a rope or cable is defined as the tension. The tension on an object is equal to the product of the mass of the object and the gravitational force added and acceleration.

T = mg + ma

Here W = mg

W = 1000.0 × 9.81 = 9810

using geometry,

tan α = 3/4

α = 36.87°

Tsinα = W

T sin36.87° = 9810

T = 16349.96 N

Thus the tension of the cable is 16349.96 N.

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The coefficient of sliding friction is 0.45.

What is meant by friction ?

Friction is defined as a resistive force acting between two surfaces that are in contact and are in relative motion.

Here,

Weight of the force, mg = 40

Kinetic friction, F' = 18 N

F' = μ N

So, coefficient of sliding friction, μ = F'/N

  μ  = 18/40

  μ = 0.45

Hence,

The coefficient of sliding friction is 0.45.

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Your question was incomplete, but most probably your question was,

A wooden 40.0 N block is placed on a table. A force of 18.0 N is required to keep the block moving at a constant velocity what is the coefficient of sliding friction between the table and the block.

Answer: The speed of the object in mph is 1680.89 mph

Answer:

1680.89 mph is the speed of an object

The average age of jumpers is approximately 28.

It is the ratio of sum of all the values to the number of values.

Here,

(1) Difference in age between the oldest and youngest jumpers

                        = 56 - 11 = 45

(2) Difference between greatest and least number of jumps

                       = 60 - 20 = 40

(3) For Bob, Boe and Brad, A(age of jumper) > N( no. of jumps)

(4) No, the eldest two jumpers together did more jumps than the youngest two  jumpers.

(5) 45 - 31 = 16

(6) 31 - 25 = 6

(7) x - y = 19

    From the figure, values of x and y are 50 and 31. So x and y are Brett   and Bev.

(8) 3y = x

    From the figure, the values of x and y are 20 and 60. So x and y are Brad and Benjy.

(9) b = 2a + 6

    From the figure, the values of a and b are 25 and 56. So and b are Brad and Bob.

(10) Average approximately = 28

Hence,

The average age of jumpers is approximately 28.

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When Weight of 7294.3 N can be supported by boom if force 7800 is applied on the cable and there is no resultant rotation at point C.

Torque is defined as force times perpendicular distance from axis of rotation to the point at which force is applied. Torque is denoted by τ and its SI unit is Nm. i.e Torque is given by, τ = F×d sinθ. Torque is vector quantity.

Torque is analogous to force in rotational motion. like there angular velocity ω is analogous  linear velocity v. means Torque is a force in rotational motion.

Looking at the answered figure I have resolved forces, there will be no resultant rotation when opposite torques due to opposite horizontal forces gets balanced.

We get,

τ₁ = τ₂

F×d Cos40⁰ = W×d Sin55°

F Cos40° = W Sin55°

W = F×(Cos40°÷Sin55°)

W = F×0.93516

W = 7800 ×0.93516

W = 7294.3 N

Hence Weight that can be supported is 7294.3 N.

b) When we assume that there is no cable, Then

Torque τ = W×d Sin35°

τ = 7294.3×10 Sin35°

τ = 41838.3 Nm

bloom will rotate with 41838.3 Nm torque.

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Potential energy decreases because movement is in the opposite direction of the magnetic field. This is because when magnets are pulled apart, the magnetic field between them is weakened, thus decreasing the potential energy of the system.

A magnetic field is a force field that is created by an electric charge or current. It is a vector field, meaning it has both magnitude and direction. Magnetic fields are generated by electric currents such as those used in electromagnets, and by magnetic materials such as iron. The Earth also generates a magnetic field. Magnetic fields have many uses, including navigation, electric motors, and magnetic storage devices. They are also useful in medical diagnostics and treatments. In addition, they can be used to study the composition of stars and galaxies.

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The shift or change in a wave's frequency or wavelength brought on by the proximity of an emitting or reflecting sound source to the receiver. Therefore, the wavelength of the sound wave is 1.10 meters.

You may have noticed that the pitch of a fast-moving siren suddenly decreases as it passes past you. Because the pitch is higher, the siren initially appears to be approaching you. The siren's pitch drops as it moves away from you after passing you. The Doppler effect is being displayed here.

wavelength = speed / frequency

where wavelength is in units of meters, speed is in units of meters per second (m/s), and frequency is in units of Hertz (Hz).

For a sound wave with a speed of 680 m/s and a frequency of 220 Hz:

wavelength = speed / frequency

wavelength = 680 m/s / 220 Hz

wavelength = 3.09 m

Therefore, the wavelength of the sound wave is 3.09 meters.

For a sound wave with a speed of 960 m/s and a frequency of 875 Hz:

wavelength = speed / frequency

wavelength = 960 m/s / 875 Hz

wavelength = 1.10 m

Therefore, the wavelength of the sound wave is 1.10 meters.

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Answer:

A machine can help decrease the input force and increase the output force.

This is achieved by using a simple machine, such as a ramp, to increase the distance over which the input force is applied. By increasing the distance over which the input force is applied, the amount of force required to move an object is reduced. This is known as mechanical advantage, and it allows a smaller input force to produce a larger output force, making the work easier to do.

For example, if a person needs to lift a heavy object straight up, they would need to apply a large amount of force to lift it. However, if they use a ramp to move the object up a slope, the distance over which the force is applied is increased, making it easier to move the object with less force.

Answer: D

Explanation:

The acceleration of the sled pulled upwards on a hill by a horse is approximately 2.74 m/s^2.

To solve this problem, we need to first resolve the forces acting on the sled into components parallel and perpendicular to the surface of the hill.

The force of gravity acting on the sled can be resolved into two components:

The force perpendicular to the hill, which is equal to m * g * cos(15°)

The force parallel to the hill, which is equal to m * g * sin(15°)

The force of the horse pulling the sled can also be resolved into two components:

The force perpendicular to the hill, which is equal to F * cos(15°)

The force parallel to the hill, which is equal to F * sin(15°)

Since the sled is being pulled up the hill, the direction of motion is opposite to the direction of the force of friction. Therefore, the force of friction can be written as:

f = -μ * N

The net force acting on the sled is the sum of the forces parallel to the hill, which can be written as:

F_net = F_parallel - f = F * sin(15°) + μ * m * g * cos(15°)

Using Newton's second law, we can write:

F_net = m * a

Substituting the expressions for F_net and f, we get:

F * sin(15°) + μ * m * g * cos(15°) = m * a

Plugging in the given values, we get:

900 * sin(15°) + 0.10 * 250 * 9.81 * cos(15°) = 250 * a

Solving for a, we get:

a = (900 * sin(15°) + 0.10 * 250 * 9.81 * cos(15°)) / 250

a ≈ 2.74 m/s^2

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Answer:

well,,,,, it detecs smok and the smoke its a trigger

Explanation:

Based on the information provided by the astronomer, a reasonable hypothesis regarding the atmosphere of Planet X is that it has a higher concentration of greenhouse gases than Earth's atmosphere.

option D.

The astronomer's observation that Planet X has a very dense atmosphere and a temperature approximately 5 times warmer than Earth suggests that there may be a significant greenhouse effect taking place.

Greenhouse gases, such as carbon dioxide, water vapor, and methane, trap heat in a planet's atmosphere, which can lead to warming of the planet's surface.

The fact that the astronomer stated that Planet X cannot contain water in any form and must not contain any oxygen suggests that the atmosphere of Planet X is likely very different from Earth's atmosphere.

The nitrogen cycle, which is an essential part of Earth's ecosystem, may not operate on Planet X in the same way, as stated by the astronomer.

However, these statements do not provide direct evidence regarding the concentration of greenhouse gases in Planet X's atmosphere, so the hypothesis regarding the concentration of greenhouse gases is the most reasonable conclusion based on the available information.

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The electric potential at a point in space depends on the distance between that point and any charged objects in the vicinity.

If we assume that the point indicated by the dot in the figure is located at a distance r from a charged object with charge q, then the electric potential at that point can be calculated using the formula: V = k * q / r, where k is Coulomb's constant (8.99 x 10^9 N m²/C²). The units of electric potential are volts (V). To express the answer to two significant figures, we would need to know the values of q, r, and any other relevant parameters in the problem.

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I believe its A. Tuberculosis

The pressure difference between two points in a manometer is given by the difference in the heights of the fluid columns in the two legs of the manometer.

If the pressure in pipe A is decreased by 10 kPa, the height of the fluid column in that leg of the manometer will decrease. The amount of decrease will depend on the specific gravity of the fluid in that leg, as well as the height of the fluid column before the pressure change. Assuming the specific gravity of the fluid in pipe A is 0.9, the decrease in pressure will cause the fluid column to decrease by (10 kPa)/(0.9 * 9.81 m/s^2), or approximately 1.15 meters. The change in the height of the fluid column in the other leg of the manometer will depend on the height of that column and the specific gravity of the fluid in that leg. To determine the new differential reading along the inclined leg of the manometer, we need to calculate the difference in the heights of the two fluid columns after the pressure change. This will be equal to the difference in the heights before the pressure change, minus the 1.15 meter decrease in the height of the fluid column in pipe A.

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Answer:

Approximately [tex]7.2\; {\rm m\cdot s^{-1}}[/tex] (rounded up), assuming that this circle is vertical and [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].

Explanation:

Let [tex]v[/tex] denote the tangential speed of the ball, and let [tex]r[/tex] denote the radius of the circle. Since the ball is in a circular motion, the acceleration on this ball would be equal to the centripetal acceleration [tex]a = (v^{2} / r)[/tex]. The net force on this ball would be [tex]F_{\text{net}} = m\, a = (m\, v^{2} / r)[/tex].

The net force on this ball is also the vector sum of the tension [tex]T[/tex] in the rope and the weight of the ball [tex]m\, g[/tex]:

[tex]F_{\text{net}} = (\text{weight}) + T[/tex].

[tex]T = F_{\text{net}} - (\text{weight})[/tex].

Note that:

[tex]\| T \| = \|F_{\text{net}} - (\text{weight})\| \le \|F_{\text{net}} \| + \| (\text{weight})\|[/tex].

In other words, the magnitude of tension [tex]T[/tex] is at most equal to [tex]\|F_{\text{net}} \| + \| (\text{weight})\| = (m\, v^{2} / r) + (m\, g)[/tex], which happens when weight and net force are in opposite directions.

When the speed of the ball is maximized, the magnitude of tension [tex]T[/tex] would be at the largest possible value of [tex]130\; {\rm N}[/tex]. Rearrange the equation and solve for speed [tex]v[/tex]:

[tex]\displaystyle \frac{m\, v^{2}}{r} + m\, g = \|T\|[/tex].

[tex]\begin{aligned}v^{2} = \frac{r}{m}\, (\|T \| - m\, g) = \frac{r\, \|T\|}{m} - r\, g\end{aligned}[/tex].

[tex]\begin{aligned}v &= \sqrt{\frac{r\, \|T\|}{m} - r\, g} \\ &= \sqrt{\frac{(1.2)\, (130)}{2.5} - (1.2)\, (9.81)}\; {\rm m\cdot s^{-1}} \\ &\approx 7.2\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

A hockey puck can transfer kinetic energy by

When a hockey player hits the puck with their stick, they transfer kinetic energy to the puck.

The puck then moves across the ice, and if it collides with another object (such as the boards or another player's stick), some of the kinetic energy from the puck is transferred to that object through touch.

This demonstrates that kinetic energy can move from one item to another and that energy transfers from materials through touch.

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Swimming in a pool requires that you push back on the water in order to go forward is Newton's 3rd Law.

Newton's 3rd Law, also known as the law of action and reaction, states that for every action, there is an equal and opposite reaction. This means that if an object A exerts a force on object B, then object B will exert an equal and opposite force on object A.

For example, if you push against a wall, the wall will push back on you with the same force in the opposite direction. This is because every force is a result of an interaction between two objects, and each object exerts an equal and opposite force on the other.

This law is important in understanding how objects interact with each other and is fundamental to many areas of physics, including mechanics, fluid dynamics, and electromagnetism.

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Answer:

1080000 J

Explanation:

Givens:

m = 15000 kg

v = 12 m/s

[tex]KE=\frac{1}{2} mv^2\\KE=\frac{1}{2} (15000)(12)^2\\KE=1080000 J[/tex]