The result of this synthetic division is the quotient (1 2/3 5/3)
To divide two polynomials using synthetic division, we need to write the dividend as a binomial of the form (x-r) and the divisor in its linear form. In this case, the binomial is (x+2) and the linear form is 3x2+7x+2.
Quotient:
3/3=1
2/3=2/3
Coefficients of dividend: 3 7 2
Quotient: 1 2/3
Product of quotient and binomial: (x+2)
(3x2+7x+2) - (x+2): 3x+5 2
Quotient:
3/3=1
2/3=2/3
5/3=5/3
The result of this synthetic division is the quotient (1 2/3 5/3).
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3. Find the slope of each of the lines.
4. Find the slope of the line that passes through the points: a. (−2, 3) and (0, 0) b. (2, 5) and (−2, 2)
5. Find the equation of the line parallel to the x-axis passing through the point (2, 3).
The line passes through the point (2, 3), the equation of the line is y = 3.
3. To find the slope of a line, you can use the formula slope = (y2 - y1)/(x2 - x1), where (x1, y1) and (x2, y2) are two points on the line.
4. a. The slope of the line that passes through the points (−2, 3) and (0, 0) is (0 - 3)/(0 - (-2)) = -3/2 = -1.5.
b. The slope of the line that passes through the points (2, 5) and (−2, 2) is (2 - 5)/(-2 - 2) = -3/-4 = 0.75.
5. The equation of a line parallel to the x-axis is y = b, where b is the y-coordinate of any point on the line. Since the line passes through the point (2, 3), the equation of the line is y = 3.
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Find (fo) (fog )(x) and (gof )(x) and the domain of each. f(x)=x+1,g(x)=7x^(2)-6x-1
(fo)(fog)(x) = 7x^(2)-6x+1
(gof)(x) = 7x^(2)+8x
Domain is a real number.
The first step in finding (fo)(fog)(x) and (gof)(x) is to substitute the functions into each other. For (fo)(fog)(x), we will substitute g(x) into f(x) for x:
(fog)(x) = f(g(x))
= f(7x^(2)-6x-1)
= (7x^(2)-6x-1) + 1
= 7x^(2)-6x
Now we will substitute (fog)(x) into f(x) for x:
(fo)(fog)(x) = f((fog)(x))
= f(7x^(2)-6x)
= (7x^(2)-6x) + 1
= 7x^(2)-6x+1
For (gof)(x), we will substitute f(x) into g(x) for x:
(gof)(x) = g(f(x))
= g(x+1) = 7(x+1)^(2)-6(x+1)-1
= 7x^(2)+14x+7-6x-6-1
= 7x^(2)+8x
The domain of each function is the set of all real numbers, since there are no restrictions on the values of x. Therefore, the domain of (fo)(fog)(x) and (gof)(x) is all real numbers.
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The following figure is made of
1
11 triangle and
1
11 rectangle.
Find the area of each part of the figure and the whole figure.
Figure Area (square units)
Triangle A
Rectangle B
Whole figure
Answer:
Step-by-step explanation:
The Parks Commision hired a landscape architect to design and construct a
quadrilateral trail that connects the four sides of an isosceles trapezoid-shaped park,
with all sides of the trail the same length. The landscape architect conjectured that if
she designs the trail in the shape of a rhombus that connects the midpoint of the
adjacent sides, the trail will satisfy the Park Commission's condition for the trail's
design. Use the information on the figure below to prove the landscape architect's
conjecture.
Since the park is isosceles trapezoid-shaped, the two sides, AB and CD, that make up the parallel sides of the trapezoid are of equal length.
What is isosceles?An isosceles triangle is a type of triangle with two sides of equal length. It has two equal angles opposite of the two equal sides, and the third angle is usually different. Isosceles triangles are named after the Greek term isoskelēs, which means “equal legs”. They are very common in geometry and are used in many applications, including architecture and engineering.
We can then use the midpoints of the adjacent sides of the trapezoid, E and F, to form a rhombus. Since the rhombus is formed from the midpoints of the two parallel sides, we know that the two sides AE and CF of the rhombus are of equal length. Similarly, the two sides BE and FD of the rhombus are also equal in length. This means that the trail, if constructed in the shape of the rhombus, will have all sides of equal length, satisfying the criteria set by the Parks Commission.
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One kilogram is how many times one nanogram?
Answer:
1 trillion times larger
Step-by-step explanation:
One kilogram (kg) is equal to 1,000,000,000,000 (1 trillion) nanograms (ng).
Therefore, one kilogram is 1 trillion times larger than one nanogram.
Ms. Smith wants to buy a home theater system. which is on sale for 35% off the original price of $2299. The sales tax is 6.25%
Answer:
$948.34
Step-by-step explanation:
35% = .35
.35 x $2299
= $804.65
That is the total before the sales tax and after the sale.
6.25% = .0625
.0625 x $2299
= $143.69, and because that is 6.25% of the total, it must be added onto that as tax.
That means the total is $804.65 + $143.69
= $948.34
At a temple to Sekhmet, there is a circular
reed bed to be planted with 4 different types
of reed, one in each of the four sections, as
shown here. The radius is 360cm and there
are two strings crossing at right angles of
lengths 560cm and 640cm.
Find out how far from the centre of the circle
the crossing point is
Therefore, the distance from the center of the circle to the crossing point of the two strings is 40sqrt(2) cm, or approximately 56.57 cm to two decimal places.
How far from the centre of the circle the crossing point is?The Pythagorean theorem can be used to calculate the distance between the circle's centre and where the two strings cross. Let A and B represent the spots where the threads converge, with O serving as the circle's centre. Next, we have:
OA2 plus OB2 equals AB2.
The circle's radius being equal to half the separation between the two strings, we get:
The equation OA = OB = sqrt((560/2)2 + (640/2)2) (156800)
And because the circle's diameter is twice its radius, we get the following equation: AB = 2 * radius = 2 * 360 = 720.
Now that we have the values, we can calculate:
2 * (156800) = AB2 => 2 * (156800) = 7202 => 313600 = 518400 - 2 * OA2 => OA2 = 102400 / 2 => OA = sqrt(51200) => OA = 40sqrt (2)
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Subtract.x2+3xy−4y26x−3y−x2+xy−2y25x+3yx2+3xy−4y26x−3y−x2+xy−2y25x+3y=(Simplify your answer. Type your answer in factored form.)
The factored form is 2y(x - y) - 11x.
What is factored form?Factored form of a polynomial is when the polynomial is written as a product of its factors. Each factor is either a polynomial or a number. Factored form is useful for identifying the zeros of a polynomial and for solving polynomial equations.
To simplify the given expression, we need to combine like terms and factor if possible.
First, let's combine the like terms:
x^2 + 3xy - 4y^2 - 6x + 3y - x^2 - xy + 2y^2 - 5x - 3y
= 2xy - 2y^2 - 11x
Next, let's see if we can factor the expression:
2xy - 2y^2 - 11x
= 2y(x - y) - 11x
Since we cannot factor any further, the simplified expression in factored form is:
2y(x - y) - 11x
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What is 10x the value of the 7/10 in 637. 739
As per the given digit value, 10 times the value of the 7 in 637.739 is 7.
To understand this problem, we need to understand the concept of place value. In our base-10 number system, each digit in a number has a specific value based on its position, or place, in the number. The rightmost digit represents the ones place, the next digit to the left represents the tens place, the next represents the hundreds place, and so on.
In the number 637.739, the digit in the tenths place is 7. This means that the 7 represents 7 tenths, or 0.7. We can see this by writing the number in expanded form:
6 hundreds + 3 tens + 7 tenths + 7 hundredths + 3 thousandths + 9 ten-thousandths
So, if we want to find 10 times the value of the digit in the tenths place (which is 7), we need to multiply 0.7 by 10:
0.7 x 10 = 7
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4(5x+3y) need help or get f
After factoring out, 4(5x+3y) simplifies to 20x + 12y.
What is simplification?The act of replacing a complex mathematical expression with a simpler equivalent is known as simplification (usually shorter).
An equivalent fraction is one in which the numerator and denominator are both divisible by the same non-zero number. If a fraction's numerator and denominator are both divisible by a number greater than 1, the fraction can be reduced to an equivalent fraction by reducing both its numerator and its denominator.
To simplify 4(5x+3y), we can use the distributive property of multiplication over addition:
4(5x + 3y) = 4(5x) + 4(3y)
Simplifying the multiplication:
4(5x + 3y) = 20x + 12y
Therefore, 4(5x+3y) simplifies to 20x + 12y.
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What is the area of this triangle?
Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth.
The area of the triangle is approximately 6.696 square feet.
What is Area of Triangle?
The area of a triangle is the amount of space enclosed by the three sides of the triangle
To find the area of a triangle with two sides and the included angle, we can use the following formula:
Area = (1/2) x a x b x sin(C)
where "a" and "b" are the lengths of the two sides and "C" is the angle between them.
Substituting the given values, we get:
Area = (1/2) x 3.2 ft x 4.7 ft x sin(62 degrees)
Using a calculator, we can evaluate sin(62 degrees) to be approximately 0.88.
So, Area = (1/2) x 3.2 ft x 4.7 ft x 0.88
= 6.696 ft²
Therefore, the area of the triangle is approximately 6.696 square feet.
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Answer:
The answer is 6.64 ft^2
Step-by-step explanation:
Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the circle is 3 units. The center of the circle lies on the x-axis. The center of the circle lies on the y-axis. The standard form of the equation is (x – 1)² + y² = 3. The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.
The radius of this circle corresponds to the radius of the circle whose answer is x2 + y2 = 9, where the circle's centre is on the x-axis.
what is circle ?In mathematics, a circle is a geometric figure made up of all the points in a sphere that are equally spaced from the circle's centre. The radius of the circle is the distance measured from any location on the circle to its centre. The width of a circle is the distance across the circle that passes through its centre, and the circumference of a circle is the distance around the circle. The equations of circles in the coordinate plane can be used to characterise them. The equation for a circle with centre (h,k) and radius r has the following conventional form:
(x - h)² + (y - k) (y - k)² = r² where (x,y) are any location on the circle's coordinates.
given
We can begin by completing the cube to rewrite the equation in standard form:
x2 - 2x + y2 = 8
(x - 1)2 + y2 = 9
We can see from this standard shape that the circle's centre is (1, 0), which is located on the x-axis. This circular has a radius of √9 units, or 3 units. Thus, the following assertions are true:
The circular has a radius of three units.
The x-axis is where the circle's middle is located.
The radius of this circle corresponds to the radius of the circle whose answer is x2 + y2 = 9, where the circle's centre is on the x-axis.
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You are given that the columns of A are linearly independent. Compute the least squared error solution to \( A x=b \), \[ A=\left[\begin{array}{ll} 4 & 1 \\ 5 & 1 \\ 6 & 1 \end{array}\right], x=\left[
$$x = \frac{1}{21} \begin{bmatrix} 4b_1 + 2b_2 \\ 5b_1 - b_2 \end{bmatrix}.$$
To compute the least squared error solution to \( A x=b \), we will use the formula \(x = (A^T A)^{-1} A^T b\).
In this case, \(A = \begin{bmatrix} 4 & 1 \\ 5 & 1 \\ 6 & 1 \end{bmatrix}\), so \(A^T = \begin{bmatrix} 4 & 5 & 6 \\ 1 & 1 & 1 \end{bmatrix}\). Therefore, we have that
$$(A^T A)^{-1} A^T b = \left(\begin{bmatrix} 4 & 5 & 6 \\ 1 & 1 & 1 \end{bmatrix} \begin{bmatrix} 4 & 1 \\ 5 & 1 \\ 6 & 1 \end{bmatrix}\right)^{-1} \begin{bmatrix} 4 & 5 & 6 \\ 1 & 1 & 1 \end{bmatrix} b$$
From here, we can compute the inverse of the matrix \(A^T A\) to get
$$(A^T A)^{-1} = \frac{1}{21}\begin{bmatrix} -1 & 2 \\ 2 & -1 \end{bmatrix}$$
Substituting this into the equation above and multiplying through, we get
$$x = \frac{1}{21}\begin{bmatrix} -1 & 2 \\ 2 & -1 \end{bmatrix} \begin{bmatrix} 4 & 5 & 6 \\ 1 & 1 & 1 \end{bmatrix} b = \frac{1}{21} \begin{bmatrix} 4b_1 + 2b_2 \\ 5b_1 - b_2 \end{bmatrix}$$
Therefore, the least squared error solution to \( A x=b \) is $$x = \frac{1}{21} \begin{bmatrix} 4b_1 + 2b_2 \\ 5b_1 - b_2 \end{bmatrix}.$$
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Tommy and Kim share some grapes in the ratio 5:6
Tommy eats half of his grapes.
Kim eats 4 more than Tommy.
They now have the same number of grapes.
How many grapes did they share to begin with?
Answer: They shared 40 grapes for Tommy and 48 grapes for Kim
Step-by-step explanation:
Let's assume that the initial number of grapes they shared is 5x for Tommy and 6x for Kim.
After Tommy eats half of his grapes, he will have 5x/2 grapes left.
Kim eats 4 more grapes than Tommy, so she will have 5x/2 + 4 grapes.
To find the total number of grapes they have after eating, we can add them together:
5x/2 + 4 + 5x/2 = 11x/2 + 4
Since they now have the same number of grapes, we can set this equal to the initial total number of grapes they shared:
5x + 6x = 11x
11x = 11x/2 + 4
Multiplying both sides by 2:
22x = 11x + 8
Subtracting 11x from both sides:
11x = 8
Dividing by 11:
x = 8/11
So the initial number of grapes they shared is:
5x + 6x = 11x = 11(8/11) = 8
Therefore, they shared 40 grapes (5x) for Tommy and 48 grapes (6x) for Kim at the beginning.
Math part 3 question 2
[tex] \: [/tex]
[tex] \sf \: g( x ) = x - 8[/tex][tex] \: [/tex]
To find:-[tex] \sf \: ( fg ) (4) = ?[/tex][tex] \: [/tex]
Solution:-[tex] \sf \: f( x )*g( x ) = (3x²)*( x - 8)[/tex][tex] \: [/tex]
put the value of x = 4
[tex] \: [/tex]
[tex] \sf \: f( 4 )*g( 4 ) = 3(4)²*( 4 - 8 ) \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3×16*(-4) \\ \sf \: \: \: \: \: \: \: \: \: \: \: = 48*( -4 ) \\ \: \: \: \: \underline{ \sf \red{ \: = -192 \: }}[/tex]
[tex] \: [/tex]
hope it helps! :)
what is 2x + y = 2 in y=mx+b form?
Answer:
y=2-2x
so y=2x+2--£8;£++£
Answer: y=−2x + 2
Step-by-step explanation:
Subtract 2x from both sides of the equation.
y= 2 − 2x
Reorder 2 and −2x.
y= −2x + 2
A helicopter spots two landing pads in opposite directions below the angle of depression to pad A to pad B is 46 and 16 degrees respectively if the straight line distance from the helicopter to pad A is 5 miles , find the distance between the landing pads.
The distance between the landing pads is approximately 12.82 miles.
What is straight line?A straight line is the shortest distance between two points in a two-dimensional space. It is a one-dimensional geometric object that extends infinitely in both directions.
Let's label the distance between the helicopter and Pad A as "x" and the distance between the helicopter and Pad B as "y". Also, let's label the distance between Pad A and Pad B as "d".
We can start by using the tangent function to find the height of the helicopter above Pad A:
tan(46) = h / x
h = x tan(46)
Similarly, we can find the height of the helicopter above Pad B:
tan(16) = h / (x + d)
h = (x + d) tan(16)
Since the helicopter is flying at a constant height, we can equate the two expressions for h and solve for d:
x tan(46) = (x + d) tan(16)
xtan(46) = xtan(16) + dtan(16)
d = x(tan(46) - tan(16)) / tan(16)
Substituting x = 5 miles and the values for the tangent functions, we get:
d = 5 (0.9851 - 0.2760) / 0.2760
d = 5 (0.7091) / 0.2760
d = 12.82 miles
Therefore, the distance between the landing pads is approximately 12.82 miles.
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In order to solve the inequality 100 - 3x>= -50, Makayla solves the equation 100 - 3x = -50 and gets x = 50. What is the solution to the inequality?
The solution to the inequality is x <= 50. This means that any value of x less than or equal to 50 will satisfy the inequality.
To solve the inequality 100 - 3x >= -50, we want to find the values of x that satisfy this inequality.
Makayla solved the equation 100 - 3x = -50 and got x = 50. This equation is not the same as the inequality we want to solve, but we can check whether Makayla's solution is a valid solution to the inequality.
Substituting x = 50 into the inequality, we get:
100 - 3x >= -50
100 - 3(50) >= -50
100 - 150 >= -50
-50 >= -50
This is a true statement, so x = 50 is a valid solution to the inequality.
However, we also need to check whether there are any other values of x that satisfy the inequality. We can do this by rearranging the inequality to isolate x:
100 - 3x >= -50
100 + 50 >= 3x
150 >= 3x
50 >= x
Therefore, the solution to the inequality is calculated to x <= 50.
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Find the HCF. 6. ( 26, 32 )=2 7. (32, 58 )= 8. (25, 37 )= 9. (158, 200 ) = 10. (49, 98 )=
The Answers are:
6. HCF is equal to 2
7. HCF is equal to 2
8. HCF is equal to 1
9. HCF is equal to 2
10. HCF is equal to 49
What is HCF?Highest Common Factor is the full form for this term. The highest factor that may divide two integers evenly is known as the HCF of two numbers. HCF can be assessed using two or more numbers.
To find the HCF of the following:
HCF of (26, 32):
2 | 26, 32
| 13, 16
HCF is equal to 2.
HCF of (32, 58)
2 | 32, 58
| 16, 29
HCF is equal to 2.
HCF of (25, 37)
No common divisor except 1.
HCF is equal to 1.
HCF of (158, 200)
2 | 158, 200
| 79, 100
HCF is equal to 2.
HCF of (49, 98)
49 | 49, 98
| 1, 2
HCF is equal to 49.
Hence, 6. HCF is equal to 2
7. HCF is equal to 2
8. HCF is equal to 1
9. HCF is equal to 2
10. HCF is equal to 49
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In ΔWXY, WY is extended through point Y to point Z, m∠YWX=(3x+17) , m
Angle, when two straight lines or rays intersect at a single endpoint, then an angle is created.
What is Exterior angle?The exterior angle of a triangle equals the sum of opposite interior angles. The angle between any side of a shape and a line that extends from the next side is known as the exterior angle.
∠XYZ = ∠YWX + ∠WXY
10x - 5 = 3x + 17 + 3x + 2
10x - 5 = 6x + 19
10x - 6x = 24
4x = 24
x = 6
∠WXY = 3x + 2
= 3*6 + 2
= 20°
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Name the property illustrated.
√2+√8 is a real number
The property illustrated is
O the closure property of addition.
O the commutative property of addition.
O the associative property of addition.
O the identity property of addition.
O the inverse property of addition,
O the distributive property of multiplication over addition
O the closure property of multiplication.
O the commutative property of multiplication.
O the associative property of multiplication
O the identity property of multiplication.
O the inverse property of multiplication.
The property illustrated in "√2+√8 is a real number" is the closure property of addition,
The property illustrated in the given statement is the closure property of addition, which states that the sum of two real numbers is also a real number.
The closure property of addition states that the sum of any two real numbers is also a real number. In the given statement, √2 and √8 are both real numbers, and therefore their sum √2+√8 is also a real number.
This property applies to all real numbers, and it is an important property of the number system. which states that the sum of two real numbers is also a real number.
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Joe's Plumbing Service sold 2,390 feet of 5/8-inch galvanized pipe in August. If 2,558 feet were sold in September, what is the percent increase in pipe footage sales?
7%
6.5%
14.22%
None of the above
The percent increase in pipe footage sales is approximately 7%.
To find the percent increase in pipe footage sales, use the formula:
[(New Value - Old Value)/Old Value] × 100.
In this case, the new value is the amount of pipe sold in September (2,558 feet) and the old value is the amount of pipe sold in August (2,390 feet). Plugging these values into the formula, we get:
[(2,558 - 2,390)/2,390] × 100 = [168/2,390] × 100 = 0.0703 × 100 = 7.03%
Therefore, the correct answer is 7%, which is option A. The percent increase in pipe footage sales from August to September is 7%.
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What is the area of the triangle when the height is 10 and the base is 12 and the line is 13
Answer:
60
Step-by-step explanation:
Answer:
The area of the triangle is 60 unit²
Step-by-step explanation:
We know that the area of a triangle is :
[tex]A= \frac{1}{2}(Base \times Height)[/tex]
Since Base = 12 unit and Height = 10 unit
So
[tex]A= \frac{1}{2}(12\times 10)=60\\[/tex]
Hence the area of this triangle is = 60 unit²
Pls help :(
where are the vertical asymptotes for y = 7tan(0. 4x)?
Answer:
x = 3.92699081 + 7.85398163n where n is an integer
A biologist is trying to find the optimal salt concentration for the growth of a certain species of mollusk. She begins with a brine solution that has 10 g/L of salt and increases the concentration by 14% every day. Let C0 denote the initial concentration and Cn the concentration after n days.
Find a recursive formula for Cn. Write your answer in terms of Cn-1. You will need to use an underscore to make the subscript and parentheses to write the n-1 in the subscript.
Find the salt concentration after 11 days.
After 11 days, the concentration is __________ g/L.
After 11 days, the concentration is 42.4 g/L.
The recursive formula for Cn can be written as Cn = Cn-1 + 0.14Cn-1. This formula shows that the concentration after n days is equal to the concentration after n-1 days plus 14% of the concentration after n-1 days.
To find the salt concentration after 11 days, we can use the recursive formula and plug in the values for C0 and n.
C0 = 10 g/L
C1 = C0 + 0.14C0 = 10 + 0.14(10) = 11.4 g/L
C2 = C1 + 0.14C1 = 11.4 + 0.14(11.4) = 13 g/L
C3 = C2 + 0.14C2 = 13 + 0.14(13) = 14.8 g/L
C4 = C3 + 0.14C3 = 14.8 + 0.14(14.8) = 16.9 g/L
C5 = C4 + 0.14C4 = 16.9 + 0.14(16.9) = 19.3 g/L
C6 = C5 + 0.14C5 = 19.3 + 0.14(19.3) = 22 g/L
C7 = C6 + 0.14C6 = 22 + 0.14(22) = 25.1 g/L
C8 = C7 + 0.14C7 = 25.1 + 0.14(25.1) = 28.6 g/L
C9 = C8 + 0.14C8 = 28.6 + 0.14(28.6) = 32.6 g/L
C10 = C9 + 0.14C9 = 32.6 + 0.14(32.6) = 37.2 g/L
C11 = C10 + 0.14C10 = 37.2 + 0.14(37.2) = 42.4 g/L
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Exam 1S22: Problem 5 Previous Problem Problem List Next Problem (8 points) Solve the following inequality. Write the answer in interval notation. x(x-7) x2 - 5x – 50 SO - Answer: Preview My Answers
In interval notation, the solution of the inequality is (25, ∞).
To solve the inequality x(x-7) < x^2 - 5x - 50, we can rearrange the terms and factor the quadratic expression:
x^2 - 7x < x^2 - 5x - 50
-2x < -50
x > 25
In interval notation, the solution is (25, ∞).
So, the answer is (25, ∞).
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Three friends, Jessa, Tyree, and Ben, are collecting canned food for a culinary skills class. Their canned
food collection goal is represented by the expression 7x? - 4xy + 6. The friends have already collected
the following number of cans:
Jessa: 2x2
Tyree: 3x2 - 4
Ben: 3xy + 6
Part A: Write an expression to represent the amount of canned food collected so far by the three
friends. Show all your work. (5 points)
Part B: Write an expression that represents the number of cans the friends still need to collect to meet
their goal. Show all your work. (5 points)
Answer: Your welcome!
Step-by-step explanation:
Part A: 2x^2 + 3x^2 - 4 + 3xy + 6 + 6 = 7x^2 - 4xy + 6
Part B: 0 = 7x^2 - 4xy + 6 - (2x^2 + 3x^2 - 4 + 3xy + 6 + 6)
= 0 = 5x^2 - 4xy
A) The expression that represents the amount of canned food collected by the three friends is [tex]5x^2 + 3xy + 2[/tex].
B) The expression that represents the number of cans the friends still need to collect to meet their goal is [tex]2x^2 - 7xy + 4[/tex].
Given: Number of cans collected
Jessa: 2x²
Tyree: 3x² - 4
Ben: 3xy + 6
Goal : [tex](7x^2 - 4xy + 6)[/tex]
A) The total amount collected:
Total = Jessa + Tyree + Ben
= [tex]2x^2 + (3x^2 - 4) + (3xy + 6)[/tex]
= [tex]2x^2 + 3x^2 - 4 + 3xy + 6[/tex]
= [tex](2x^2 + 3x^2 + 3xy) + (-4 + 6)[/tex]
= [tex]5x^2 + 3xy + 2[/tex]
Therefore, the expression is [tex]5x^2 + 3xy + 2[/tex].
B) The number of cans the friends still need to collect to meet their goal is
Cans still needed = Goal - Total
[tex]= (7x^2 - 4xy + 6) - (5x^2 + 3xy + 2)[/tex]
[tex]= 7x^2 - 4xy + 6 - 5x^2 - 3xy - 2[/tex]
[tex]= (7x^2 - 5x^2) + (-4xy - 3xy) + (6 - 2)[/tex]
[tex]= 2x^2 - 7xy + 4[/tex]
Therefore, the expression is [tex]2x^2 - 7xy + 4[/tex].
Learn more about Expression here:
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Write an equivalent expression to m-(8-3m) without parentheses
m - (8 - 3m)
m - 8 + 3m
m + 3m - 8
4m - 8
Answer:
Step-by-step explanation:
m-(8-3m)
m-8 + 3m
=m+3m-8
=4m-8
If you have a 65 and you turn in a grade for 40% what would that grade turn into?
Please someone help I really need help
Answer: 26
Step-by-step explanation:
65x40%
calculate 65x0.4
Please give me brainliest
what is an equilvalent expression to 15x + 10
Answer:
5 (3x+2)
Step-by-step explanation:
Hope this helps! :)