different solution of salt are made up what valumo of​

Answer:

The area of the prism is 54 ft.

Step-by-step explanation:

times 9 times 6 ft and ya get 56

but I don't know If whats you're looking for  

Answer:

The first picture on the second page

Step-by-step explanation:

The first picture on the second page would be the answer because it gives exactly one input for each output. It also passes the vertical line test because no point throughout the line creates a vertical line.

Answer:

A fraction is in simplest form when the top and bottom cannot be any smaller, while still being whole numbers.

Step-by-step explanation:

Answer:

59.5

Step-by-step explanation:

area of the triangle is (7 x 3)/2=21/2=10.5

area of the square 7x7=49

Answer:

last 4rd

Step-by-step explanation:

Answer:

Y = 28

Step-by-step explanation:

Y=16 + 12 = 24

Therefore the y scored 24 points

Answer:

there are 21 students in her class.

Step-by-step explanation:

Since the 12 girls corresponds to the 4 in the ratio, I multiplied the 3 by three to get the amount of boys. then add the boys to the girls to get 21 students.

Answer:

A=1164.62

Step-by-step explanation:

First you find the radius:

11*11=121

121=2*(22/7)*r

121=44/7*r

19.25=r

Then to find the area you:

A=22/7(19.25) to the 2 power
A=1164.62

Answer:

y = 96

Step-by-step explanation:

In order to find y we have to find the value of  x

angle "x" is an angle formed by a tangent line and a secant line.

Kindly look at the image.

As you can see an angle formed by a tangent and a secant is equal to half of its intercepted arc.

x's intercepted arc has a measure of 168

So...

X = [tex]\frac{168}{2}[/tex]

[tex]\frac{168}{2} =84[/tex]

So x = 84

Now to find y.

Angle "x" and angle "y" are formed on a straight line.

Angles formed on a straight line add up to equal 180°

That being said we can find a missing angle ( y ) by subtracting the given angle's measure ( angle x which has a measure of 84°) from 180

so y = 180 - 84

180 - 84 = 96

Hence y = 96

Answer:

41 minutes

Step-by-step explanation:

14+10+17= 41 minutes

Answer:

A) 16

Step-by-step explanation:

1st sequence: 72-8x

2nd sequence: 58-6x

Set both sequences equal to each other and solve for x:

72-8x=58-6x

14-8x=-6x

14=2x

7=x

x=7

Plug x=7 back into the equation:

72-8(7)=58-6(7)

72-56=58-42

16=16

So the first number that appears in both sequences is 16.

Answer:

b=18.76

Step-by-step explanation:

Let the line that splits the big triangle into two small triangles be x.

Let the unmarked side of the big triangle be y.

Consider the big triangle. By Pythagorus:

(6+16)²=b²+y²

484=b²+y²

y²=484-b²

Consider the small left triangle. By Pythagorus:

y²=6²+x²

y²=36+x²

x²=y²-36

Consider the small right triangle. By Pythagorus:

b²=16²+x²

b²=256+x²

b²=256+x²

b²=256+y²-36

b²=220+y²

b²=220+484-b²

2b²=704

b²=352

b=18.7616630393

b=18.76

Answer:

don't click the link the bot put it's a bad link btw

Answer: 32ft

Step-by-step explanation:

got it right

Answer:

No solution

Step-by-step explanation:

Absolute value can not output a negative result

its 1/6 because all together u have 12 books and there are 2 comics so 2/12 simplified is 1/6

Answer:

Question is not clear. How many cups of water is required before you can make  1 batch of green slime?

Step-by-step explanation:

Answer:

who where when what how?!!?

Step-by-step explanation:

Answer:

[tex]\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{128a^{6}b^{13}}[/tex]

Required

Solve

[tex]\sqrt{128a^{6}b^{13}}[/tex]

The expression can be split to:

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}[/tex]

So, we have:

[tex]\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}[/tex]

Rewrite as:

[tex]\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2} * \sqrt{b}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}[/tex]

Answer:

2

Step-by-step explanation:

A=[tex]\pi[/tex]r²

(19/6)[tex]\pi[/tex]=(285/360)[tex]\pi[/tex]r²

Divide both sides by pi, and they cancel out.

x is the radius, so replace r with x.

19/6=285/360x²

19/6÷285/360=x²

(19/6)·(360/285)=x²

4=x²

√4=x

2=x

Answer:

circle graph

Step-by-step explanation:

Answer:

BAR GRAPH

Step-by-step explanation:

Answer:

The answer is 0

Step-by-step explanation:

Jesus will help you he think you got this

The algebraic expression for [tex]8[/tex] more than [tex]5[/tex] times a number will be [tex](8+5x)[/tex] and the verbal expression for [tex]4(n + 6)[/tex] will be four times the sum of a number and six.

Expressions is a finite combination of symbols that is well-formed according to rules that depend on the context.

We have,

[tex]8[/tex] more than [tex]5[/tex] times a number

Now,

Let a number [tex]=x[/tex]

So,

According to the question,

We get, [tex](8+5x)[/tex]

So, this is the algebraic expression .

We have,

[tex]4(n + 6)[/tex]

So,

According to the question,

[tex]4(n + 6)[/tex] will be written as four times the sum of a number and six.

So, this is the verbal expression .

Hence, we can say that the algebraic expression for [tex]8[/tex] more than [tex]5[/tex] times a number will be [tex](8+5x)[/tex] and the verbal expression for [tex]4(n + 6)[/tex] will be four times the sum of a number and six.

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#SPJ3

9514 1404 393

Answer:

  x = 15

Step-by-step explanation:

Given:

  ∠1 + ∠2 = 90°

  ∠1 = 45°

  ∠2 = 3x°

Find:

  x

Solution:

  Using the given values in the given equation, we have ...

  45° +3x° = 90°

  15 + x = 30 . . . . . . divide by 3°

  x = 15 . . . . . . . . . . . subtract 15

Answer:

x = 6 and y = -1

Step-by-step explanation:

hope this helps

Answer:

x= 6 and y= -1

Step-by-step explanation:

-2x - 9y = -3

-7x - 9y = -33

I'm going to be solving by elimination. However, you can solve using substitution as well.

So the first step is to eliminate one of the variables. In my opinion, what's easiest is eliminating the y variables. To eliminate you want to variables (that are the same) to equal 0 and cancel out. To do this, all I have to do is subtract. When I subtract I get 0 as shown below. I will also subtract the other variables and numbers in the equations because that's how elimination works.

-2x - 9y = -3

-7x - 9y = -33

5x = 30

-2 - (-7)=5 and -3 - (-33)= 30

There's no solution for the y variable because -9 - (-9)=0, which cancels out so it doesn't have to be written.

after that you get x=6 because you divide by 5 on both sides.

All that's left is to plug in 6 to one of the equations:

-2(6) - 9y= -3

-12 - 9y= -3

+12         +12

-9y= 9

Divide both sides by -9 to get y= -1

Answer:

(-9, 14)

Step-by-step explanation:

Let the column vector be represented as a = (3, 4) and b = (5, -2)

2a = 2(3,4)

2a = (6,8)

3b = 3(5, -2)

3b = (15, -6)

Take the difference 2a - 3b

2a - 3b = (6,8) - (15, -6)

2a - 3b = (6-15, 8 -(-6))

2a - 3b = (-9, 14)

Hence the column vector is (-9, 14)

We want to find 2a - 3b as a column vector, we will get:

[tex]2a - 3b = \left[\begin{array}{ccc}-9\\14\end{array}\right][/tex]

So we want to perform a sum (difference actually) of vectors, we have that:

[tex]a = \left[\begin{array}{ccc}3\\4\end{array}\right] \\\\\\b= \left[\begin{array}{ccc}5\\-2\end{array}\right][/tex]

Remember that when we multiply a vector by a scalar, each component gets multiplied by that scalar, so we have:

[tex]2a = \left[\begin{array}{ccc}2*3\\2*4\end{array}\right] = \left[\begin{array}{ccc}6\\8\end{array}\right] \\\\\\3b= \left[\begin{array}{ccc}3*5\\3*-2\end{array}\right] = \left[\begin{array}{ccc}15\\-6\end{array}\right][/tex]

Now we just perform the direct difference:

[tex]2a - 3b = \left[\begin{array}{ccc}6\\8\end{array}\right] - \left[\begin{array}{ccc}15\\-6\end{array}\right] = \left[\begin{array}{ccc}6 - 15\\8 + 6\end{array}\right] = \left[\begin{array}{ccc}-9\\14\end{array}\right][/tex]

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Answer: C

Step-by-step explanation:

i just did this problem and got it right

Decagon is a regular polygon with 10 sides. The correct option that fills up the blanks is given by: Option C: 36°, 72°, 10, 5

A decagon is a regular polygon with 10 sides.

As shown in the diagram attached below, the angle between two line segments connecting center and two adjacent vertex is of 36°.

Since rotating the decagon by that angle will land it in an unidentifiable way, as it looks alike, thus, rotating the decagon by a multiple of __36°__ carries the decagon onto itself.

Therefore, a rotation of _36 degree or 72 degree or any multiple of 36 degree__ counterclockwise will carry the decagon onto itself.

If we connect one vertex to opposite one, and flip it on that connecting line(this flip is called reflection), then the decagon will look same as before reflection.Thera are 5 such different lines.

Now in addition, we can connect lines from mid point of 1 side to other opposite side too. And this also can be done in 5 ways. On these connecting lines too, the decagon can be reflected onto itself.

Thus, we can reflect the decagon _5+5=10_ different ways. (these are the only ways, and it can be proven mathematically).

And including __5__ ways using the lines of symmetry that pass through the midpoints of two opposite sides

Thus, the correct option that fills up the blanks is given by: Option C: 36°, 72°, 10, 5

Learn more about reflection symmetry here:

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