Determine whether the following is a statistical question.
How many boogers does Karissa the ogre have in her left nostril?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
Statistical

(Choice B)
B
Not statistical

Answer:

Choice A

Step-by-step explanation:

End of the question states it, and I did it on Khan :)

Kara finds that the top 200200200 longest streaks in the world in June had an average of about 636363 so option (A) will be correct.

The mean is the average of a data set. Mean gives us the idea of that how much amount of overall data have.

In other words, the mean is the foundation of the deviation of data from all data sets.

Mean = sum of data / Number of data

For example, if you have marks in 5 subjects like 40,45,44,46,48 then the mean will be

( 40 + 45+ 44 + 46 + 48) /5 = 44.6.

Given that,

Kara finds that the top 200200200 longest streaks in the world in June had an average of about 636363 wins in a row

It means the top 200200200 longest streaks worldwide in June have an average longest streak of 636363.

Hence " Kara finds that the top 200200200 longest streaks in the world in June had an average of about 636363".

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Answer: F

Step-by-step explanation:

Answer:

Извини, чувак, но я написал это на русском, чтобы тратить твое время.

Step-by-step explanation:

Извини, чувак, но я написал это на русском, чтобы тратить твое время.

Answer:

[tex]\displaystyle \cos x \left(\csc x + \tan x\right) = \cot x + \sin x[/tex]

Step-by-step explanation:

We want to simplify:

[tex]\displaystyle \cos x \left(\csc x + \tan x\right)[/tex]

Recall that csc x = 1 / sin x and tan x = sin x / cos x. Substitute:

[tex]\displaystyle = \cos x \left(\frac{1}{\sin x} + \frac{\sin x }{\cos x}\right)[/tex]

Distribute:
[tex]\displaystyle = \frac{\cos x}{\sin x} + \frac{\cos x \sin x}{\cos x} \\ \\ \\ = \frac{\cos x}{\sin x} + \sin x[/tex]

Recall that cot x = cos x / sin x. Hence:

[tex]\displaystyle = \cot x + \sin x[/tex]

In conclusion:

[tex]\displaystyle \cos x \left(\csc x + \tan x\right) = \cot x + \sin x[/tex]

Using proportions, it is found that Gene's speed was of 25 miles per hour, as he was 30 miles faster over a period of 6 hours.

A proportion is a fraction of a total amount.

At 8 a.m. Anne left Austin and headed south at 20 mph, hence when Gene left at 10 a.m., she was 40 mph ahead.

At 4 p.m., that is, 6 hours after Gene left, the distance was of 10 miles, that is, Gene was 30 miles faster in 6 hours, so the difference in the speeds is given by:

d = 30/6 = 5 mph.

Since Anne's speed is of 20 mph, Gene's is given by:

v = 20 + 5 = 25 mph.

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Answer:

9pi

Step-by-step explanation: The formula for circumference of a circle is 2*pi*r or the diameter times pi. Since you have the diameter, you can use diameter times pi and simply get 9pi

Answer:

If you meant acute angle, an acute angle is an angle less than 90 degrees, normally greater than or equal to 15 degrees. Acute angles come in many forms.

__________________________________________________________

Ask in comments.

Answer:

an acute is a type of angle I am learning acute in a 12:15 class

Step-by-step explanation:

Answer:

480  i think

Step-by-step explanation:

if not i sorry

#1

#2

#3

Answer:

d). (2m-1)(5m+3)

e). (2x-5)(2x-5)

f). (6n-4)(n+5)

Step-by-step explanation:

Solving by factorisation...

d). 10²+m-3

=> 10m²+6m-5m-3

=> 2m(5m+3)-1(5m+3)

=> (2m-1)(5m+3)

e). 4x²-20x+25

=> 4x²-10x-10x+25

=> 2x(2x-5) -5(2x-5)

=> (2x-5)(2x-5)

f). 6n²-20+26n

=> 6n²+26n-20

=> 6n²+30n-4n-20

=> 6n(n+5)-4(n+5)

=> (6n-4)(n+5)

Answer:

10.5

Step-by-step explanation:

10% = 1.5

1.5 x 3 = 4.5

4.5 = 30%

15 - 4.5 = 10.5

Answer: The first term of a GP is 6 if it's common ratio is 2 find the 6th term

The nth term is ar^(n-1)

So, for your GP, the 6th term is 6*2^5 = ___

Step-by-step explanation: 10:2021

The value of 16th term in the geometric series is,

⇒ 6th term = 192

An sequence has the ratio of every two successive terms is a constant, is called a Geometric sequence.

Given that;

The first term is 6 and the common ratio is 2.

Hence, We can formulate;

⇒ nth term = arⁿ⁻¹

⇒ 6th term = ar⁶⁻¹

⇒ 6th term = ar⁵

⇒ 6th term = 6 (2)⁵

⇒ 6th term = 6 x 32

⇒ 6th term = 192

Thus, The value of 16th term in the geometric series is,

⇒ 6th term = 192

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Answer:

False

Step-by-step explanation:

Graphing tells you where the solution of the system, or graph intersection occurs no matter what. You can have a quadratic and exponential function -- graphing will always show you where they intersect (or don't!)

Answer:

false

Step-by-step explanation:

hope this helps

Answer:

Answer:

62.8 \: {m}^{2}62.8m

2

Step-by-step explanation:

Radius of outer circle = 6 m

Width of the track = 2 m

So, radius of inner circle = 6 - 2 = 4 m

Area of the track = Area of outer circle - Area of inner circle

\begin{gathered} = \pi {6}^{2} - \pi {4}^{2} \\ \\ = \pi( {6}^{2} - {4}^{2} ) \\ \\ = 3.14 \times (36 - 16) \\ \\ = 3.14 \times 20 \\ \\ = 62.8 \: {m}^{2} \end{gathered}

=π6

2

−π4

2

=π(6

2

−4

2

)

=3.14×(36−16)

=3.14×20

=62.8m

2

Answer:

it will be an exponet

Step-by-step explanation:

2 over 8

The algebraic expression [tex]x^{10/3}[/tex] is equivalent to the algebraic expression [tex]x^{3}\cdot \sqrt[3]{x}[/tex]. Thus, the right choice is option D.

In this question we must apply the following set of algebraic properties to simplify a given expression:

[tex]x^{m/n} = \sqrt[n]{x^{m}} = \left(\sqrt[n]{x}\right)^{m}[/tex]   (1)

[tex]x^{m+n} = x^{m}\cdot x^{n}[/tex]   (2)

[tex]x^{m\cdot n} = \left(x^{m}\right)^{n} = \left(x^{n}\right)^{m}[/tex]   (3)

Where:

And also by apply the definition of power.

If we know that the given expression is [tex]x^{10/3}[/tex], then the equivalent expression is:

[tex]x^{10/3} = \sqrt[3]{x^{10}} = \sqrt[3]{x^{9}\cdot x} = \sqrt[3]{x^{9}}\cdot \sqrt[3]{x} = x^{3}\cdot \sqrt[3]{x}[/tex]

The algebraic expression [tex]x^{10/3}[/tex] is equivalent to the algebraic expression [tex]x^{3}\cdot \sqrt[3]{x}[/tex]. Thus, the right choice is option D.

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Answer:

option d

Step-by-step explanation:

(-3)²=9

(-3)²≠(-9)

Answer:

C: [tex]-7ab \sqrt[3]{3ab^{2} }[/tex]

Step-by-step explanation:

Simplify or expand:

[tex]2ab\sqrt[3]{192ab^{2} } - 5\sqrt[3]{81a^{4} b^{5} }[/tex]

Transform the expression:

[tex]2ab\sqrt[3]{4^{3}*3ab^{2} }[/tex] - [tex]5\sqrt[3]{3^{3}*3a*ab^{3} b^{2} }[/tex]

Re-write

Multiply

Combine like terms.

Answer:

[tex]- \frac{134}{15}[/tex]

Step-by-step explanation:

[tex]-2\frac{4}{5} -6\frac{2}{15} =-\left( \frac{2\times 5}{5} +\frac{4}{5} \right) -\left( \frac{6\times 15}{15}+\frac{2}{15} \right)[/tex]

[tex]-2\frac{4}{5} -6\frac{2}{15} =-\left( \frac{10}{5} +\frac{4}{5} \right) -\left( \frac{90}{15}+\frac{2}{15} \right)[/tex]

[tex]-2\frac{4}{5} -6\frac{2}{15} =-\left( \frac{14}{5}\right) -\left( \frac{92}{15}\right)[/tex]

[tex]-2\frac{4}{5} -6\frac{2}{15} =-\left( \frac{42}{15}\right) -\left( \frac{92}{15}\right)[/tex]

[tex]-2\frac{4}{5} -6\frac{2}{15} =-\left( \frac{42+92}{15}\right)[/tex]

[tex]-2\frac{4}{5} -6\frac{2}{15} =- \frac{134}{15}[/tex]

[tex]-2\frac{4}{5} -6\frac{2}{15} =-8\frac{14}{15}[/tex]                  

Answer: D

Step-by-step explanation:

f'(C) = 0 ⇒ There is a critical point here

There could be a relative max or min here, but since we do not know if f''(x) is positive or negative, we cannot be sure if the function is truly changing from positive to negative or vice versa. "C" could simply be at a horizontal tangent of a function like x³.

Answer:

[tex]\sf V=\dfrac18\: \sf yd^3[/tex]

Step-by-step explanation:

Volume of a cube formula

[tex]\sf V=s^3[/tex]

where:

Given:

[tex]\sf \implies V=\left(\dfrac12\right)^3[/tex]

Apply exponent rule [tex](\frac{a}{b})^c=\dfrac{a^c}{b^c}[/tex]

[tex]\sf \implies V=\dfrac{1^3}{2^3}[/tex]

[tex]\sf \implies V=\dfrac18\: \sf yd^3[/tex]

Volume:-

Answer:

Either 27 or 55

If right please make brainleist for others to learn from this answer thanks!

Step-by-step explanation:

Answer:

x=31, y=23, z=34

Step-by-step explanation:

The first shelf is x. The second shelf is y. The third shelf is z.

x+y=54.

y+z=57

x+y+z=88

You can substitute 54 in for x+y in the third equation to solve for z.

54+z=88

Subtract 54

z=34

Now that you know z, substitute it in in the second equation.

y+34=57

y=23

Finally, substitute the known y value into the first equation.

x+23=54

x=31

Answer:

0 ones + 18 tenths + 3 hundredths

Step-by-step explanation:

Answer:

yes it's O ones + 18 tenths + 3 hundredths

Step-by-step explanation:

I took the test

Answer:

x = -3

y = -2

(-3, -2)

Step-by-step explanation:

x - 7y = 11

5x + 4y = -23

-----------------------

-5 (x - 7y = 11)

-5x + 35y = -55

--------------------------

-5x + 35y = -55

5x + 4y = -23

       39y = -78

     ÷39     ÷39

        y = -2

-----------------------------

x - 7y = 11

x -7(-2) = 11

x + 14 = 11

   -14    -14

x = -3

I hope this helps!

Answer:

I, III

Step-by-step explanation:

if there are 27 books and only 3 people at least one person must have read more than 7 books as if 3 people each read 7 books that would be 21 books which is less than 27

Answer:

Step-by-step explanation:

Given relation

a)

Find its zero's

b)

The vertex of qudratic function is determined at x = - b/(2a)

Applied to this relation, the x- coordinate of vertex is

Find its y- coordinate

The vertex is (- 3, - 75)

Zeros:-

#Vertex

Multiply 3 which we deduced

Vertex (-3,-75)

Answer:

Option C, There are about 3.75 times as many people as pet dogs

Step-by-step explanation:

Step 1:  Determine the ratio

[tex](Amount\ of\ People) / (Amount\ of\ Dogs)[/tex]

[tex](3 * 10^8) / (8 * 10^7)[/tex]

[tex]3.75[/tex]

Answer: Option C, There are about 3.75 times as many people as pet dogs

answer

cross multiply each of their estimate with 16 hours

The maximum profit that the considered company can get is 142,400 bucks. That profit is earned when input x  (the number of items produced) is 380

To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.

Putting those values of x in the second rate of function, if results in negative output, then at that point, there is maxima. If the output is positive then its minima and if its 0, then we will have to find the third derivative (if it exists) and so on.

The missing part of question is:

" [tex]C(x)=2000+70x[/tex], [tex]R(x)=830x-x^2[/tex]

A. Determine the maximum profit of the company.

B. Determine the number of items that must be produced and sold to obtain the maximum profit"

The profit is the difference between the revenue and the cost, so we get:

[tex]P(x) = R(x) - C(x) = 760x - x^2 - 2000[/tex]

Finding its first and second rate with respect to x:

[tex]P'(x) = 760 -2x\\P''(x) = -2[/tex]

Equating first rate to 0 to get the critical values:

[tex]P'(x) = 0 \implies 760 = 2x \implies x = 380[/tex]

The second rate is < 0 for any x, x = 380 is minima, and x = 380 being only critical value, it is global maximum.

At x = 380, the profit evaluates to:

[tex]P(x) = 760x - x^2 - 2000\\P(380) = 760(380) - (380)^2 - 2000 = (380)^2 - 2000\\P(380) = 142400[/tex]

Thus, the maximum profit that the considered company can get is 142,400 bucks. That profit is earned when input x  (the number of items produced) is 380

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