Determine the overall orders of the reactions to which the following rate laws apply:a.rate=k[NO2]2 b.rate=k c.rate=k[H2][Br2]12 d.rate=k[NO]2[O2]

The right answer is capillaries that metabolites like salts and food molecules are exchanged in capillaries together with waste products, oxygen, and carbon dioxide.

In the capillaries, waste, nutrients, and gases are delivered from the blood to the tissue.  Little blood arteries called capillaries create networks surrounding body cells by branching off from arterioles.

It is supplied to the blood during gas exchange from the lungs. Both the lungs and blood exchange carbon dioxide at the same time. The capillaries, a network of tiny blood veins found in the walls of the alveoli, are where this occurs in the lungs in between the individual alveoli.

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Answer:

zinc + hydrochloric acid = zinc chloride + hydrogen

copper carbonate + sulfuric acid = copper sulfate + carbon dioxide + water

copper + nitric acid = copper nitrate + nitrogen dioxide + water

Explanation:

Zn + 2HCl → ZnCl2 + H2

CuCO3 + H2SO4 → CuSO4 + CO2 + H2O

Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O

Answer:

zinc + hydrochloric acid = zinc chloride + hydrogen

copper carbonate + sulfuric acid = copper sulfate + carbon dioxide + water

zinc + nitric acid = zinc nitrate + hydrogen gas + water

The minimum mass of hydrochloric acid that could be left over by the chemical reaction is 18.23 g.

Moles in chemistry is a unit of measurement for the amount of a substance. It is equal to the number of atoms or molecules in a given mass of a substance, and is represented by the symbol ‘mol’. The molar mass of a substance is the mass of one mole of that substance, expressed in grams. It is important for calculating the amount of energy or reactants needed for a reaction. Moles can also be used to measure the concentration of a solution.

The minimum mass of hydrochloric acid that could be left over by this chemical reaction can be calculated using the following equation:

Moles of HCl = Mass HCl / Molar Mass HCl

Moles of NaOH = Mass NaOH / Molar Mass NaOH

Moles of HCl must equal moles of NaOH in the reaction, so:

Moles HCl = Moles NaOH

Mass HCl / Molar Mass HCl = Mass NaOH / Molar Mass NaOH

Rearranging for mass HCl:

Mass HCl = Molar Mass HCl x Mass NaOH / Molar Mass NaOH

Given:

Mass HCl = 28.8 g
Molar Mass HCl = 36.46 g/mol
Mass NaOH = 20.0 g
Molar Mass NaOH = 40.0 g/mol

Substituting values:

Mass HCl = 36.46 g/mol x 20.0 g / 40.0 g/mol

Mass HCl = 18.23 g

Therefore, the minimum mass of hydrochloric acid that could be left over by the chemical reaction is 18.23 g.

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I hope the answer you are looking for is 5.51L

sorry if I'm wrong

Water movement has caused this land to erode because there is no protection from strong waves.

Grand Strand's central part is not protected by barrier island, meaning it is more exposed to the water movement, which can cause strong waves to erode the land. This erosive action leads to the shoreline being worn away, or having sediment removed from it.The movement of water is an important natural process that is necessary for the health and stability of our environment. It is responsible for the circulation of water between the atmosphere, land, and ocean, and for the transport of energy, nutrients, and organic matter.

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complete question:Use the example to answer the question. In South Carolina, there is an area of shoreline called Grand Strand. Its central part is not protected by barrier islands.

Which of the following could you infer about the impact of water movement on this area? (1 point) Responses

a.Water movement has caused longshore currents to erode the sediment from one end of this shoreline.

b.Water movement has caused a build up of various inlets to form a combination of tides and currents.

c.Water movement has caused this land to erode because there is no protection from strong waves.

d.Water movement has caused strong waves to build the shoreline up through the process of deposition.

The mass of the water that is going to be produced from the balanced reaction equation is 84 g.

Stoichiometry is the branch of chemistry that deals with the quantitative relationship between the reactants and products in a chemical reaction. It involves the calculation of the amounts of reactants needed to produce a certain amount of product, or the amount of product produced from a given amount of reactants.

Number of moles of Fe = 195.9 g/56 g/mol

= 3.5 moles

If 3 moles of Fe is produced when 4 moles of water is produced

3.5 moles of Fe is produced when 3.5 * 4/3

= 4.7 moles

Now we have that the mas of water is;

4.7 moles * 18 g/mol

= 84 g

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a.   The volume of 8.00 g of O2 at STP is 5.90 L.

b.  The volume of 3.50 g of CO at STP is 2.95 L.

c.  The volume of 0.0170 g of H2S at STP is 11.0 mL.

d. The volume of 2.25 x 10^5 kg of NH3 at STP is  302.7 m3.

a.

PV = nRT

n = m/MW

n = 8.00 g / 32 g/mol = 0.25 mol

V = nRT/P

V = (0.25 mol) (0.0821 L atm/(mol K)) (273 K) / (1 atm)

V = 5.90 L

b.

n = m/MW

n = 3.50 g / 28 g/mol = 0.125 mol

solve for V:

V = nRT/P

V = (0.125 mol) (0.0821 L atm/(mol K)) (273 K) / (1 atm)

V = 2.95 L

the volume of 3.50 g of CO at STP is 2.95 L.

c.

n = m/MW

n = 0.0170 g / 34 g/mol = 0.0005 mol

solving  for V:

V = nRT/P

V = (0.0005 mol) (0.0821 L atm/(mol K)) (273 K) / (1 atm)

V = 0.011 L or 11.0 mL

The volume of 0.0170 g of H2S at STP is 11.0 mL.

d.

n = m/MW

n = 2.25 x 10^5 kg / 17 g/mol / 1000 g/kg = 13,235 mol

V = nRT/P

V = (13,235 mol) (0.0821 L atm/(mol K)) (273 K) / (1 atm)

V = 302,720 L or 302.7 m3

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The reaction between sulfur dioxide and potassium permanganate in the presence of KOH produces manganese dioxide. Using stoichiometry and the given mass of manganese dioxide (1.74 g), the mass of KOH can be calculated to be 3.16 g.

Potassium permanganate is widely used as a disinfectant and oxidizing agent in various industries. It is also used in water treatment, as a laboratory reagent, and in the manufacture of chemical compounds.

In the presence of KOH, sulfur dioxide reduces permanganate ions to manganese dioxide. This reaction proceeds through a series of intermediate steps involving the formation of manganese(IV) oxide and manganese(III) oxide.

This reaction's precise mechanism is intricate and requires numerous phases.

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Answer: Na2CO3 + 2 HNO3 → 2 NaNO3 + H2O + CO2

Explanation:

The final molarity of the acetate anion in the solution is 0.06148 M.

The balanced chemical equation for the reaction between lead(II) acetate and ammonium sulfate is:

[tex]Pb(CH_3COO)_2 + (NH_4)_2SO_4 -- > PbSO_4 + 2NH_4CH_3COO[/tex]

So, if we dissolve 1 mole of Pb(CH₃COO)₂, it will produce 2 moles of acetate anion.

Moles of Pb(CH₃COO)₂ = (mass of Pb(CH₃COO)₂) / (molar mass of Pb(CH₃COO)₂)

Assuming the mass of Pb(CH₃COO)₂ is given, let's say it is 5 g, then:

Moles of Pb(CH₃COO)₂ = (5 g) / (Pb(CH₃COO)₂ molar mass)

The molar mass of Pb(CH₃COO)₂ is:

207.2 g/mol (molar mass of Pb) + 2(16.00 g/mol) + 2(12.01 g/mol) = 325.27 g/mol

Substituting the values, we get:

Moles of Pb(CH₃COO)₂ = (5 g) / (325.27 g/mol) = 0.01537 mol

Since 1 mole of Pb(CH3COO)₂ produces 2 moles of acetate anion, the total number of moles of acetate anion in the solution is:

Moles of acetate anion = 2 x 0.01537 mol = 0.03074 mol

We can calculate the final molarity of the acetate anion in the solution:

Molarity of acetate anion = Moles of acetate anion / Volume of solution

Molarity of acetate anion = 0.03074 mol / 0.5 L = 0.06148 M

The final molarity of the acetate anion in the solution is 0.06148 M.

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The reaction between C2H4 (ethylene) and H2O (water) to form CH3CH2OH (ethanol) is a type of hydration reaction. For this reaction to occur, two conditions need to be met:

The presence of a suitable catalyst: The reaction is catalyzed by an acid catalyst, such as phosphoric acid (H3PO4). The acid catalyst helps to break the double bond in C2H4 and promotes the addition of water to form ethanol.

The reaction requires high pressure and temperature to proceed. The typical reaction conditions involve a temperature range of 300-400 °C and a pressure range of 60-70 atm. These conditions are necessary to overcome the high activation energy of the reaction and promote the formation of the desired product, ethanol.

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Mass in grams of 3.07 moles of glucose is 553.3 g (rounded to three significant figures).

What is Mass?

Mass is a fundamental physical property of matter that quantifies the amount of matter in an object. It is a measure of the resistance of an object to acceleration when a force is applied to it. In other words, mass is the amount of substance in an object, and it determines how much gravity will affect that object.

To determine the mass in grams of 3.07 moles of glucose (C6H12O6), we need to first calculate the molar mass of glucose, which is the sum of the atomic masses of all the atoms in its chemical formula:

Molar mass of C6H12O6 = 6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 g/mol

Next, we can use the following conversion factor to convert moles to grams:

mass (g) = number of moles x molar mass (g/mol)

mass = 3.07 mol x 180.18 g/mol = 553.3 g

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Answer:

simplified-74400000000000000000000000x

Explanation:

The level of acidity or alkalinity of aqueous solutions can be conveniently expressed using the pH scale, also known as the pOH scale.

"The negative of the logarithm of the molar hydronium-ion concentration" is how pH is defined. The pH formula is written as. P H equals l o g [H 3 0 +] You can alternatively write the pH Formula as. l o g [H +] = p H

The pH of a solution is equal to the solution's hydrogen ion concentration divided by its negative logarithm to base 10:

   pH = -log₁₀[H⁺]

     pOH = -log₁₀[OH⁻]

For any aqueous solution, the sum of the pH and pOH is 14. That is;

                    pH + pOH = 14

Now solving for [OH⁻]:

              HNO₃ + H₂O → H₃O⁺ + NO₃⁻

   Since pH + pOH = 14

              pOH = 14 - pH = 14 -3.75 = 10.25

 since pOH = -log₁₀[OH⁻]

             10.25 = -log₁₀(OH⁻)

             [OH⁻] = inverse log₁₀(-pOH)

             [OH⁻] = inverse log₁₀(-10.25) = 5.62 x 10⁻¹¹moldm⁻³

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Answer:

[OH− ] = 5.62

n = -11

pOH = 10.25

Explanation:

I did it not too long ago

The ball will sink because its weight is greater than the amount of water it displaces. Since their weight is less than the amount of water they displace, objects made of aluminium foil like a boat, paper and cups will float on water.

Whether an item will float or sink in another material depends on its density. If an object's density is lower than the liquid it is placed in, it will float. If an object is heavier than the liquid it is immersed in, it will sink.

While individuals may create their goods or aluminium foils with the aluminium, beating the metal to form aluminium foil is a physical change.

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Answer:

B

Explanation:

When ice melts at 0oC, average kinetic energy of the molecules will remain the same.

Several everyday items, such as incandescent light bulbs (60 joules/s) and gasoline (130 million joules/gallon), use or release energy in varying amounts. Chemical reactions are predicted to change in energy by Hess' Law.

The Hess law is most commonly used in business to measure how much energy an engine produces and consumes, as well as in our bodies' responses to food consumption.

For instance, carbon and extra oxygen can react to generate carbon dioxide. Directly or indirectly, when carbon and oxygen combine, carbon dioxide is produced, either first as carbon monoxide and later as carbon dioxide.

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If two forces are acting in the same direction, their sum provides the net force.

Two forces combine when they move in the same direction. When two forces engage in opposition to one another, the lesser force is subtracted from the larger force to form the combined force. The direction of the larger original force is the direction of the generated force (resultant).

Two equal but opposing forces acting on an item will cancel each other out, leaving a net force of zero and no movement. the two forces added together.

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The percent of C in Ca(C2H3O2)2 is 27.28%.

The formula mass of Ca(C2H3O2)2 is 158.17 g/mol.

The percent of H in Ca(C2H3O2)2 is 2.54% and the percent of O is 54.50%.

To find the percent of C in Ca(C2H3O2)2, we first need to calculate the molar mass of the compound:

Molar mass of Ca(C2H3O2)2 = (1 × 40.08) + (2 × (2 × 12.01 + 3 × 1.01 + 2 × 16.00)) = 2 × 158.17 = 316.34 g/mol

Now we can calculate the percent of C:

Mass of C in Ca(C2H3O2)2 = 2 × (2 × 12.01) = 48.04 g/mol

Percent of C in Ca(C2H3O2)2 = (48.04 g/mol ÷ 316.34 g/mol) × 100% = 15.19%

Therefore, the percent of C in Ca(C2H3O2)2 is 15.19%, rounded to the hundredths place.

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London dispersion forces arise due to the motion of electrons and the resulting temporary asymmetry in the electron cloud, leading to the attraction between atoms or molecules.

London dispersion forces are the weakest intermolecular forces that exist between all atoms and molecules. They arise due to the temporary asymmetry of the electron cloud surrounding an atom or molecule. The resulting temporary dipole moment induces an opposite dipole in a neighboring atom or molecule, which leads to the attraction between them.

In the case of two helium atoms, the electron clouds of both atoms are symmetrical in the absence of any external influence. However, due to the constant motion of electrons, there may be a temporary imbalance in the electron distribution of one helium atom, resulting in a temporary dipole moment. This dipole moment can induce a dipole moment in the neighboring helium atom, leading to the attraction between them.

At the molecular level, this attraction is depicted by a temporary shift of electrons towards one helium atom, creating a partial negative charge, and a corresponding shift away from the other helium atom, creating a partial positive charge. The partially negative helium atom is attracted to the partially positive helium atom of the neighboring molecule, resulting in the formation of a weak London dispersion force between the two helium atoms.

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Simple atomic models called Bohr-Rutherford diagrams display how many electrons are present in each of an atom's outermost shells.

The Bohr theory only applies to organisms with a single electron. Three electrons make up the lithium atom. Hence, the lithium atom does not fit into Bohr's hypothesis.

Lithium is an air-reactive alkali metal that tarnishes quickly to a dull silvery-grey and finally black. It is a silvery-white to grey alkali metal with a metal-lic lustre when new. At 20 °C, it is the least dense and lightest metal of all the elements that are not gases, and it floats on water.

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The desired reaction is 2Al(s) + 3CO2 from Al2O3(s) + 3CO(g) (g) The reactions include 2 Al(s), 3/2 O2(g), and Al2O3(s), with H = 1675.7kJ. ————————— (1) CO(g) = CO2 + 1/2 O2(g) (g).

As a result, the enthalpies of a reactants and products are added together, and the result is used to compute the enthalpy of a reaction. This endothermic process generates and absorbs environmental heat if H is positive. This reaction is exothermic so emits heat into the environment if H is negative.

A negative H indicates that heat is transferred from the a system towards its surroundings, whereas a positive H indicates that heat is transferred from the surroundings into the system. An enthalpy of reaction (Hrxn) for a chemical reaction is the difference of enthalpy between the products and reactants; Hrxn is measured in kilojoules per mole.

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The theoretical yield of ammonia is 40.8 grams. Rounded to the tenths place, the answer is 40.8 g.

To determine the theoretical yield of ammonia (NH3), we first need to balance the chemical equation:

N2 + 3H2 → 2NH3

Now we can use the balanced equation to calculate the theoretical yield of NH3. Since we know that 29 L of N2 reacts with 14 g of H2, we need to determine which reactant is limiting and calculate the amount of NH3 that can be formed from that limiting reactant.

First, let's convert the volume of N2 to moles using the ideal gas law:

PV = nRT

n = PV/RT = (1 atm)(29 L)/(0.0821 L·atm/mol·K)(298 K) = 1.2 mol N2

Next, let's convert the mass of H2 to moles:

m = n·M

n = m/M = 14 g / 2.0 g/mol = 7.0 mol H2

Now we can compare the mole ratios of N2 and H2 in the balanced equation to determine which reactant is limiting:

N2:H2 = 1:3

1.2 mol N2 × (3 mol H2/1 mol N2) = 3.6 mol H2

Since we only have 7.0 mol of H2, H2 is not limiting and N2 is limiting. Therefore, we will use the mole ratio between N2 and NH3 to calculate the theoretical yield of NH3:

N2:NH3 = 1:2

1.2 mol N2 × (2 mol NH3/1 mol N2) = 2.4 mol NH3

Finally, we can convert moles of NH3 to grams using the molar mass of NH3:

m = n·M

m = 2.4 mol · 17.0 g/mol = 40.8 g NH3

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Protons are the positively charged particles found in the nucleus of an atom. In terms of their magnetic properties, protons can be classified into two categories: equivalent and non-equivalent protons.

Equivalent protons are protons that have the same chemical environment in a molecule. This means that they experience the same local electronic and magnetic environment, and as a result, they produce the same NMR signal. For example, in a molecule of ethyl alcohol (CH3CH2OH), the two methyl (CH3) groups are equivalent because they are attached to the same carbon and are surrounded by the same atoms.

Non-equivalent protons, on the other hand, are protons that have different chemical environments in a molecule. This means that they experience different local electronic and magnetic environments, and as a result, they produce different NMR signals. For example, in a molecule of acetone (CH3COCH3), the three methyl (CH3) groups are non-equivalent because they are attached to different carbons and are surrounded by different atoms.

The distinction between equivalent and non-equivalent protons is important in NMR spectroscopy, as it allows chemists to distinguish between different types of protons in a molecule and determine their relative abundance and position in the molecule.

To calculate the volume of 0.300M solution that contains 1.5g of the solute, we need to use the following formula:

moles of solute = mass of solute / molar mass of solute

moles of solute = (1.5g) / (1 x H + 1 x S + 3 x O) g/mol

moles of solute = (1.5g) / (1 + 32 + 3x16) g/mol

moles of solute = (1.5g) / 98 g/mol

moles of solute = 0.015306 moles

Now, we can use the following formula to calculate the volume of the solution:

moles of solute = molarity x volume (in liters)

0.015306 moles = 0.300 M x volume (in liters)

volume (in liters) = 0.015306 moles / 0.300 M

volume (in liters) = 0.05102 L

Finally, we can convert the volume from liters to milliliters (mL):

volume (in mL) = 0.05102 L x 1000 mL/L

volume (in mL) = 51.02 mL

Therefore, 51.02 mL of 0.300M solution would contain 1.5g of solute.

The pH of the buffer after the addition of 0.020 mol of NaOH is 4.83.

Henderson-Hasselbalch equation: pH = pKa + log([A^-]/[HA]),

[CH3COOH] = 0.300 mol/1.00 L = 0.300 M

[CH3COO^-] = 0.300 mol/1.00 L = 0.300 M

CH3COOH + NaOH → CH3COO^- + H2O

[CH3COOH] = (0.300 mol - 0.020 mol)/1.00 L = 0.280 M

CH3COO^-] = (0.300 mol + 0.020 mol)/1.00 L = 0.320 M

pH = pKa + log([CH3COO^-]/[CH3COOH])

pH = 4.74 + log(0.320/0.280)

pH = 4.83

The pH of a solution can be measured using a pH meter or pH paper, which changes color based on the pH of the solution. It is a dimensionless quantity that indicates the concentration of hydrogen ions (H+) in a solution. pH stands for "power of hydrogen" and is defined as the negative logarithm of the hydrogen ion concentration. A pH of 7 is considered neutral, pH values below 7 indicate acidity, and pH values above 7 indicate alkalinity.

pH is an important parameter in many chemical and biological processes, as it can affect the behavior and properties of molecules and ions in solution. Maintaining the correct pH in biological systems is critical for many physiological processes, and pH control is important in many industrial processes as well.

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The calculated enthalpy of the reaction of the salt is 44.064 kJ/mol.

To solve this problem, we can use the formula:

q = m x c x ∆T

where q is the heat absorbed or released, m is the mass of the solution, c is the specific heat capacity of water (4.184 J/g ˚C), and ∆T is the change in temperature. We can then use the heat absorbed to calculate the enthalpy change of the reaction using the formula:

∆H = q / n

where n is the number of moles of the salt.

First, let's calculate the mass of the water:

m = 49.83 g

Next, let's calculate the change in temperature:

∆T = 31.4˚C - 25.2˚C = 6.2˚C

Now, let's calculate the heat absorbed by the water:

q = m x c x ∆T

q = 49.83 g x 4.184 J/g ˚C x 6.2˚C

q = 1304.4 J

Since the calorimeter constant is given as 37.4 J/˚C, we need to adjust for the heat absorbed by the calorimeter:

q' = q + (calorimeter constant x ∆T)

q' = 1304.4 J + (37.4 J/˚C x 6.2˚C)

q' = 1519.88 J

Next, let's calculate the number of moles of the salt:

n = 0.03450 mol

Finally, let's calculate the enthalpy change of the reaction:

∆H = q' / n

∆H = 1519.88 J / 0.03450 mol

∆H = 44,064 J/mol

To convert the answer to kJ/mol, we divide by 1000:

∆H = 44.064 kJ/mol

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