z = 4(x - 1) - ln (y - 4)
Therefore, the equation of the tangent plane to the surface z = y ln x at the point (1, 4, 0) is z = 4(x - 1) - ln (y - 4).
To determine the equation of the tangent plane to the surface z = y ln x at the point (1, 4, 0), we first need to find the partial derivatives of the surface with respect to x and y.
∂z/∂x = y/x
∂z/∂y = ln x
Then, we can use these partial derivatives along with the point (1, 4, 0) to find the equation of the tangent plane using the formula:
z - z0 = ∂z/∂x(x0, y0)(x - x0) + ∂z/∂y(x0, y0)(y - y0)
where (x0, y0, z0) is the given point.
Plugging in the values, we have:
z - 0 = (4/1)(x - 1) + ln 1(y - 4)
Simplifying:
z = 4(x - 1) - ln (y - 4)
Therefore, the equation of the tangent plane to the surface z = y ln x at the point (1, 4, 0) is z = 4(x - 1) - ln (y - 4).
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Find the point on the line y = 8x - 5 closest to the point (0, – 6). The function giving the distance between the point and the line is S = ? (Enter a function of x)
The function giving the distance between the point (0,-6) and the line y = 8x - 5 is: S = 47 / sqrt(65).
To find the point on the line closest to the point (0,-6), we can find the perpendicular distance from the point (0,-6) to the line y = 8x - 5. The point on the line closest to (0,-6) will be the point on the line that is intersected by the perpendicular line.
The slope of the given line is 8, so the slope of any line perpendicular to it will be -1/8. Let (a,b) be the point on the line y = 8x - 5 that is closest to (0,-6). The equation of the line passing through (0,-6) with slope -1/8 is:
y + 6 = (-1/8)x
Simplifying this equation, we get:
y = (-1/8)x - 6
The point (a,b) will lie on both the given line and the perpendicular line. Therefore, we can substitute y = 8x - 5 in the equation y = (-1/8)x - 6 to obtain:
8x - 5 = (-1/8)x - 6
Solving for x, we get:
x = 37/65
Substituting x = 37/65 in y = 8x - 5, we get:
y = 231/65
Therefore, the point on the line y = 8x - 5 closest to the point (0,-6) is (37/65, 231/65).
The distance S between the point (0,-6) and the line y = 8x - 5 can be found by using the formula:
S = |ax + by + c| / sqrt(a^2 + b^2)
where a, b, and c are the coefficients of the general form of the line equation, which is ax + by + c = 0.
In this case, the equation of the line is y - 8x + 5 = 0. Therefore, a = -8, b = 1, and c = 5. Substituting these values in the formula for S, we get:
S = |(-8)(0) + (1)(-6) + 5| / sqrt((-8)^2 + 1^2)
= 47 / sqrt(65)
Therefore, the function giving the distance between the point (0,-6) and the line y = 8x - 5 is:
S = 47 / sqrt(65)
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Fill in the blank: Some of the most common symbols used in formulas include (addition), - (subtraction), * (multiplication), and / (division). These are called _____
The basic arithmetic operators (+,-,*,/) are commonly used in formulas to perform mathematical calculations. They are collectively known as "operators" and are an essential component of mathematical formulas, allowing us to perform complex calculations quickly and efficiently.
The symbols mentioned in the question, i.e., (+,-,*,/) are the basic arithmetic operators that are used in mathematical formulas to perform different types of calculations. These symbols are collectively referred to as "operators" or "mathematical operators."
Operators are an essential part of mathematical formulas as they allow us to perform complex mathematical calculations in a concise and efficient manner. They act as a shorthand way of representing mathematical operations and make it easier to perform calculations without having to write out the entire equation every time.
In addition to the basic arithmetic operators mentioned above, there are other types of operators that can be used in formulas depending on the specific mathematical operation being performed. For example, there are logical operators like AND, OR, and NOT that are used in Boolean algebra to perform logical calculations.
Other operators that can be used in formulas include exponentiation (^), which is used to raise a number to a certain power, and modulo (%), which is used to find the remainder when one number is divided by another.
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Write three different pairs of coordinate points that form a line segment with a slope greater than 2.
Three pairs of coordinate points that form a line segment with a slope greater than 2 are: (x₁, y₁) = (0, 0) and (x₂, y₂) = (3, 7), (x₁, y₁) = (1, 3) and (x₂, y₂) = (5, 13), (x₁, y₁) = (-2, 1) and (x₂, y₂) = (2, 9)
To find three pairs of coordinate points that form a line segment with a slope greater than 2, we need to choose pairs of points where the difference in y-coordinates is at least twice the difference in the corresponding x-coordinates.
Here are three pairs of coordinate points that satisfy this condition:
1. (x₁, y₁) = (0, 0) and (x₂, y₂) = (3, 7)
Using the slope formula, we get:
slope = (y₂ - y₁) / (x₂ - x₁) = (7 - 0) / (3 - 0) = 7/3, which is greater than 2.
2. (x₁, y₁) = (1, 3) and (x₂, y₂) = (5, 13)
Using the slope formula, we get:
slope = (y₂ - y₁) / (x₂ - x₁) = (13 - 3) / (5 - 1) = 10 / 4 = 5 / 2, which is also greater than 2.
3. (x₁, y₁) = (-2, 1) and (x₂, y₂) = (2, 9)
Using the slope formula, we get:
slope = (y₂ - y₁) / (x₂ - x₁) = (9 - 1) / (2 - (-2)) = 8 / 4 = 2, which is exactly 2, but if we extend the line segment beyond these two points, the slope will become greater than 2.
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A random sample of small business stock prices has a sample mean of x¯=$54. 82 and sample standard deviation of s=$8. 95. Use the Empirical Rule to estimate the percentage of small business stock prices that are more than $81. 67. Round your answer to the nearest hundredth
Using the Empirical Rule. The percentage of small business stock prices that are more than $81. 67 is 0.30%
To use the Empirical Rule, we need to assume that the distribution of small business stock prices is approximately normal.
First, we need to find the z-score for $81.67:
z = (81.67 - 54.82) / 8.95 = 2.99
Next, we can use the Empirical Rule to estimate the percentage of small business stock prices that are more than $81.67:
About 99.7% of the data falls within 3 standard deviations of the mean.
Therefore, about 0.3% of the data falls more than 3 standard deviations above the mean.
Since $81.67 is more than 3 standard deviations above the mean, we can estimate that the percentage of small business stock prices that are more than $81.67 is about 0.3%.
Rounded to the nearest hundredth, the estimated percentage is 0.30%.
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Find those values of x for which the given function is increasing and those values of x for which it is decreasing, y = 12x – x^3 • Increasing for x < 2, decreasing for x > 2 • Increasing for 4 4 • Increasing for X <-2.x > 2, decreasing for -2 2
The function y = 12x – x^3 is increasing for x < -2, -2 < x < 2, and x > 2, and is decreasing for -2 < x < 2.
The given function is y = 12x – x^3. To determine when the function is increasing or decreasing, we need to take the derivative of the function with respect to x:
y' = 12 - 3x^2
To find where the function is increasing, we need to look for values of x where y' is positive. To find where the function is decreasing, we need to look for values of x where y' is negative.
So, y' > 0 when:
12 - 3x^2 > 0
3x^2 < 12
x^2 < 4
-2 < x < 2
Therefore, the function is increasing for x values less than -2, between -2 and 2, and greater than 2. Specifically:
• Increasing for x < -2
• Increasing for -2 < x < 2
• Increasing for x > 2
On the other hand, y' < 0 when:
12 - 3x^2 < 0
3x^2 > 12
x^2 > 4
x < -2 or x > 2
Therefore, the function is decreasing for x values between -2 and 2. Specifically:
• Decreasing for -2 < x < 2
Overall, we can summarize that the function y = 12x – x^3 is increasing for x < -2, -2 < x < 2, and x > 2, and is decreasing for -2 < x < 2.
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Bob and Anna are planning to meet for lunch at Sally's Restaurant, but they forgot to schedule a time. Bob and Anna are each going to randomly choose from either 1\text{ p. M. }1 p. M. 1, start text, space, p, point, m, point, end text, 2\text{ p. M. }2 p. M. 2, start text, space, p, point, m, point, end text, 3\text{ p. M. }3 p. M. 3, start text, space, p, point, m, point, end text, or 4\text{ p. M. }4 p. M. 4, start text, space, p, point, m, point, end text to show up at Sally's Restaurant. They must both choose exactly the same time in order to meet. Bob has a "buy one entree, get one entree free" coupon that he can only use if he meets up with Anna. If he successfully meets with Anna, Bob's lunch will cost him \$5$5dollar sign, 5. If they do not meet, Bob's lunch will cost him \$10$10dollar sign, 10. What is the expected cost of Bob's lunch?
The expected cost of Bob's lunch is $9.69, rounded to the nearest cent.
To figure out the probability of Bob and Anna successfully meeting up, we need to use a unitary method. The probability of Bob choosing a specific time is 1/4, and the probability of Anna choosing the same time is also 1/4. Since they both need to choose the same time, we can multiply their individual probabilities to find the probability of them meeting up:
1/4 x 1/4 = 1/16
This means that the probability of Bob and Anna successfully meeting up is 1/16 or 0.0625.
Now we can use this probability to find the expected cost of Bob's lunch. If Bob and Anna meet up, Bob will get a discount on his lunch and pay $5. If they don't meet up, he'll have to pay the full price of $10. So the expected cost of Bob's lunch is:
(Probability of meeting up x Cost if they meet) + (Probability of not meeting up x Cost if they don't meet)
(1/16 x $5) + (15/16 x $10) = $0.3125 + $9.375 = $9.69
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Choose all the expressions that are equal to 45×67 4 5 × 6 7. A. 2435 24 35 B. 4×75×6 4 × 7 5 × 6 C. 4×56×7 4 × 5 6 × 7 D. 6×54×7 6 × 5 4 × 7 E. 6×45×7 6 × 4 5 × 7
None of the given expressions (A, B, C, D, E) are equal to 45 x 67.
How to find which expressions are equal to multiplication?To find which expressions are equal to 45 x 67, we simply need to simplify each of the expressions given.
Starting with option A, 24 x 35, this is not equal to 45 x 67.Moving on to option B, we have 4 x 75 x 6. Simplifying this, we get 1,800, which is not equal to 45 x 67.Option C is 4 x 56 x 7, which simplifies to 1,568, not equal to 45 x 67.Option D is 6 x 54 x 7, which simplifies to 2,268, not equal to 45 x 67.Finally, option E is 6 x 45 x 7, which simplifies to 1,890, also not equal to 45 x 67.Therefore, none of the expressions are equal to 45 x 67.
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HELP FAST PLEASEEE
the M is a typo it’s supposed to be X
Answer:
x=7
Step-by-step explanation:
Because all the bases are the same you can ignore the 8's.
Instead solve for 15=x+8
in which you would subtract the 8 to the left side, and 15-8=7
Leroy is building a slide for his kids. If the ladder is 5 feet tall and he wants the bottom of the slide to be 12 feet from the ladder, how long does the slide need to be?
We can use the Pythagorean theorem to solve this problem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
Let x be the length of the slide. Then we have a right triangle with legs of length 5 (the height of the ladder) and x, and hypotenuse of length 12 (the distance from the ladder to the bottom of the slide).
Using the Pythagorean theorem:
12^2 = 5^2 + x^2
144 = 25 + x^2
Subtracting 25 from both sides:
119 = x^2
Taking the square root of both sides:
x ≈ 10.91
Therefore, the slide needs to be about 10.91 feet long.
Your doing practice 4
For a snowboard cost that was reduced by 40% by the end of the season, the snowboard cost $450 when it was new.
How to find original cost?To find the original cost of the snowboard, let the original price of the snowboard be x.
After a 40% reduction in price, the snowboard costs 60% of its original price, therefore the cost remaining percentage of the original prize times the reduction percentage = the price after reduction:
100% - 40% = 60%
60/100 = 0.6
0.6x = 270
Solving for x to get:
x = 270/0.6 = 450
Therefore, the original price of the snowboard was $450.
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Write a derivative formula for the function.
f(x) = (4 ln(x))ex
The derivative formula for the function is f'(x) = 4ex(1/x + ln(x)).
How to determined the function by differentiation?To find the derivative of the function f(x) = (4 ln(x))ex, we can use the product rule and the chain rule of differentiation.
Let g(x) = 4 ln(x) and h(x) = ex. Then, we have:
f(x) = g(x)h(x)
Using the product rule, we get:
f'(x) = g'(x)h(x) + g(x)h'(x)
Now, we need to find g'(x) and h'(x):
g'(x) = 4/x (since the derivative of ln(x) with respect to x is 1/x)
h'(x) = ex
Substituting these back into the formula for f'(x), we get:
f'(x) = (4/x)ex + 4 ln(x)ex
Simplifying this expression, we get:
f'(x) = 4ex(1/x + ln(x))
Therefore, the derivative formula for the function f(x) = (4 ln(x))ex is:
f'(x) = 4ex(1/x + ln(x)).
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Harper uploaded a funny video of her dog onto a website.
The relationship between the elapsed time, ddd, in days, since the video was first uploaded, and the total number of views, V(d)V(d)V, left parenthesis, d, right parenthesis, that the video received is modeled by the following function.
V(d)=4^{{1.25d}}V(d)=4
1.25d
V, left parenthesis, d, right parenthesis, equals, 4, start superscript, 1, point, 25, d, end superscript
How many views will the video receive after 666 days?
After 666 days, the video will receive approximately 33,621,452 views.
We are given the function V(d) = 4^(1.25d), where d represents the number of days since the video was uploaded and V(d) represents the number of views the video has received at that time. To find the number of views the video will receive after 666 days, we need to evaluate V(666).
Plugging in d = 666 into the function, we get V(666) = 4^(1.25*666). Using a calculator, we can simplify this to V(666) ≈ 33,621,452. Therefore, after 666 days, the video will receive approximately 33,621,452 views.
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You spin the spinner once. 6, 7, 8,9 what’s the p(prime?
The probability of getting a prime number on the spinner is 2/4 or 1/2.
There are four possible outcomes on the spinner: 6, 7, 8, and 9. To determine the probability of getting a prime number, we need to first identify which of these numbers are prime. Prime numbers are numbers greater than 1 that can only be divided by 1 and themselves without leaving a remainder.
Out of the four possible outcomes, only two of them are prime: 7 and 9. Therefore, the probability of getting a prime number is the number of favorable outcomes (2) divided by the total number of possible outcomes (4), which simplifies to 1/2.
To see why this is true, we can think of the probability as a fraction where the numerator is the number of ways to get a prime number and the denominator is the total number of possible outcomes. In this case, there are two ways to get a prime number (7 and 9), and four possible outcomes (6, 7, 8, and 9). Therefore, the probability r is 2/4 or 1/2.
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Robin records the height of her plant for 3 months. If the pattern continues, what algebraic expression can Robin use to find the plant's height for any month? What will the plants height be at 12 months
The plant's height at 12 months would be 38 inches.
How to calculate the height?Assuming the plant's height follows a linear pattern, Robin can use the equation y = mx + b, where y is the height of the plant, x is the number of months, m is the slope or rate of growth, and b is the y-intercept or initial height.
To find the equation, Robin can use the data from the three months:
Month 1: Height = 5 inchesMonth 2: Height = 8 inchesMonth 3: Height = 11 inchesUsing these data points, Robin can calculate the slope m:
m = (11-5)/(3-1) = 3 inches/month
Then, using the point-slope form of the equation, Robin can find the y-intercept b:
y - 5 = 3(x - 1)
y = 3x + 2
Therefore, the algebraic expression to find the plant's height for any month x is y = 3x + 2.
To find the plant's height at 12 months, Robin can substitute x = 12 into the equation:
y = 3(12) + 2 = 38 inches
So the plant's height at 12 months would be 38 inches.
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Already Know The Vertex but need help on the opens and axis of symmetry
Answer: x = -3
Step-by-step explanation:
Hope this helps.
A student is solving the problem |2−9x|=29. They know that one answer can be found by solving the equation 2−9x = 29. They subtract 2 to get −9x=27 and then divide by -9 to get x=−3. They think that this is one answer, and then take the absolute value of this to get their other answer of x=3. Did this student solve this problem correctly? If so, how can you show that they got it correct. If not, what mistake did they make and what should they have done instead?
The student did not solve the problem correctly. The student only discovered one of two solutions and made the mistake of presuming that the absolute value of -3 was the other solution without investigating the second situation.
When solving absolute value equations, we have to consider both cases:
|2-9x| = 29 can be rewritten as
2-9x = 29 or 2-9x = -29
Solving the first equation as the student did:
2-9x = 29
Subtracting 2 from both sides:
-9x = 27
Dividing both sides by -9:
x = -3
This is one solution, but we also need to solve the second equation:
2-9x = -29
Subtracting 2 from both sides:
-9x = -31
Dividing both sides by -9:
x = 31/9
So the two solutions are x = -3 and x = 31/9.
Taking the absolute value of -3 gives us 3, which is one of the solutions the student found. However, the other solution is x = 31/9, not |-3|.
Therefore, the student only found one of the two solutions and made an error in assuming that the absolute value of -3 was the other solution without considering the second case.
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The following two-way table shows the distribution of daily traffic and weather issues in a certain large city.
A 4-column table with 3 rows. Column 1 has entries bad weather, good weather, total. Column 2 is labeled heavy traffic with entries 25, 55, 80. Column 3 is labeled Light traffic with entries 5, 15, 20. Column 4 is labeled Total with entries 30, 75, 100. The columns are titled daily traffic and the rows are titled weather conditions.
Suppose a day from this city is selected at random. Let event A = heavy traffic and event B = bad weather. Are events A and B independent?
No, P(A) = P(B|A).
No, P(A) ≠ P(A|B).
Yes, P(A) = P(A|B).
Yes, P(A) ≠ P(B|A)
The correct answer is "No, P(A) ≠ P(A|B)".
How to solveIf the occurrence of one event has no bearing on the likelihood that the other will also occur, then the two events are independent.
The likelihood that both occurrences A and B will occur is defined mathematically as being equal to the product of the probabilities of A and B (i.e., P) (A and B).
Let event A = heavy traffic and event B = bad weather.
P(A)= 25/30 and P(B)=25/30
Two events are independent if the occurrence of one does not change the probability of the occurrence of the other.
This means P(A) = P(A|B) or P(B) = P(B|A).
For event A (heavy traffic), P(A) = 80/100 = 0.8.
For event B (bad weather), P(A|B) = 25/30 = 0.833.
Since P(A) ≠ P(A|B), events A and B are not independent.
So, the correct answer is "No, P(A) ≠ P(A|B)".
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A skier can purchase a daily or season pass.
The daily pass costs $48 per day and included
the price of ski rentals. The season pass costs
$190 plus a daily fee of $10 to rent the skis.
How many days would a skier have to go skiing
in order for both options to cost the same?
A.
5 days
C. 240 days
D. 10 days
B.
3 days
We know that the skier would have to go skiing for 5 days in order for both options to cost the same.
To find out how many days a skier would have to go skiing for both options to cost the same, we need to set up an equation. Let's use "d" to represent the number of days the skier goes skiing.
For the daily pass option:
Total cost = $48 x d
For the season pass option:
Total cost = $190 + ($10 x d)
Now we can set up the equation:
$48 x d = $190 + ($10 x d)
Simplifying this equation, we get:
$38 x d = $190
Solving for "d", we get:
d = 5
Therefore, the skier would have to go skiing for 5 days in order for both options to cost the same.
So the answer is A. 5 days.
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under a time crunch, you only have time to take a sample of 15 water bottles and measure their contents. the sample had a mean of 20.05 ounces with a sample standard deviation of 0.3 ounces. what would be the 90% confidence interval, when we assumed these measurements are normally distributed? g
The 90 % confidence interval is ( 19.92 , 20.18 )
What is confidence interval?A confidence interval is defined as the range of values that we observe in our sample and for which we expect to find the value that accurately reflects the population.
What is a z-score?The relationship between a value and the mean of a set of values is expressed numerically by a Z-score. The Z-score is computed using the standard deviations from the mean. A Z-score of zero indicates that the data point's score and the mean score are identical.
The Z-score is calculated using the formula:
z = (x - μ)/σ
where z: standard score
x: observed value
μ: mean of the sample
σ: standard deviation of the sample
Given data ,
Let the number of samples n = 15
Let the mean of the sample be μ = 20.05
Let the standard deviation σ = 0.3
Now , the z score of 90 % confidence interval is z = 1.645
The 90% confidence interval is calculated by the equation
A = μ ± z ( σ / √n )
Substituting the values in the equation , we get
P = μ + z ( σ / √n )
Q = μ - z ( σ / √n )
Now , the value of P is
P = 20.05 + 1.645 ( 0.3/√15 )
P = 20.05 + ( 0.4935 / 3.873 )
P = 20.05 + 0.12742
P = 20.18
Now , the value of Q is
Q = μ - z ( σ / √n )
Q = 20.05 - 1.645 ( 0.3/√15 )
Q = 20.05 - ( 0.4935 / 3.873 )
Q = 20.05 - 0.12742
Q = 19.92
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Ayuda doy corona porfavor porfavor!!!!!!!
INVENTEN UN PROBLEMA QUE PUEDA RESOLVERSE CON EL CALCULO A) Y OTRO QUE SE PUEDA RESOLVERSE CON EL CALCULO B)
a) 45 x 2 + 150 x 4 x 3 b) ( 45 x 2 + 150 x 4) x 3
Lo siento, pero los problemas que ha proporcionado no están relacionados con el cálculo. El problema a) es simplemente una operación de multiplicación y suma, y el problema b) es una operación de multiplicación y suma agrupada. Para crear un problema que pueda resolverse con cálculo, podría plantear algo como:
a) ¿Cuál es la tasa de cambio de la función f(x) = x^2 en el punto x = 3?
b) ¿Cuál es el valor máximo de la función g(x) = 3x^2 - 12x + 5 en el intervalo [0, 4]?
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Sikie Shoe Manufacturing Co. Was incorporated in the New York State on January 15, 2021 and received authorization to issue 100,000 shares of $25 par value, preferred stock 200,000 shares of $2 Par Value Common Stock. Prepare journal entries to record the following transactions. (40 POINTS)
1 What journal entry would you make on January 15, the authorization date?
2 On Jan. 20, 50,000 preferred stock were sold cash at $70 per share.
3 On February 1, 2021 Sikie Shoe Manufacturing Co. Issued 70,000 common shares with a Market price of $8
4 On February 15, 2021 Sikie Shoe Manufacturing Co. Issued 4,000 common shares to Delkab Consulting Co. In settlement of various Professional Services Provided at a fee of $100,000
5 On March 20, 2021 Mr. Park agreed to exchange a piece of land he owns with a fair value of $150,000 for 10,000 common shares. Sikie Shoe Manufacturing Co. Shares are actively traded at $10 per share on the stock exchange.
6 On July 1, 2021 Sikie Shoe Manufacturing Co. Issued 45,000 common shares for cash at a Market price of $25
7 As of July 31, How many common shares have been issued?
8 As of July 31, How many common shares are outstanding?
The following treasury stock transactions were made by Sikie in 2021 Prepare the necessary journal entries to record the transactions in the financial records of the company. (25 POINTS)
9 1-Aug Purchased 5,000 shares of its own $2 par value common stock at $20 per share
10 1-Sep Sold 1,500 shares of treasury stock purchased on August 1 for $30 per share
11 21-Oct Sold 700 shares of treasury stock purchased on August 1 for $27 per share
12 1-Nov Sold 900 shares of treasury stock purchased on August 1 for $13,500
13 18-Nov Sold 600 shares of treasury stock purchased on August 1 for $9,600
Prepare the stockholders' equity section of Sikie Shoe Manufacturing Co as of December 31, 2021 including disclosure of all relevant information. (Hint: Refer to Learning Objective 3 Illustration 13. 11 page 13-18 of your text book). (35 points)
To help you with the journal entries and preparation of the stockholders' equity section for Sikie Shoe Manufacturing Co, let's start with the journal entries for the given transactions:
On January 15, the authorization date:
Journal entry:
Common Stock (200,000 shares * $2 par value) $400,000
Preferred Stock (100,000 shares * $25 par value) $2,500,000
Authorized Capital Stock $2,900,000
On January 20, 50,000 preferred stock were sold for cash at $70 per share:
Journal entry:
Cash $3,500,000
Preferred Stock (50,000 shares * $25 par value) $1,250,000
Common Stock $1,250,000
Paid-in Capital in Excess of Par - Preferred Stock $2,250,000
On February 1, 70,000 common shares were issued with a market price of $8:
Journal entry:
Cash $560,000
Common Stock (70,000 shares * $2 par value) $140,000
Paid-in Capital in Excess of Par - Common Stock $420,000
On February 15, 4,000 common shares were issued to Delkab Consulting Co. in settlement of professional services provided at a fee of $100,000:
Journal entry:
Common Stock (4,000 shares * $2 par value) $8,000
Paid-in Capital in Excess of Par - Common Stock $92,000
Accounts Payable/Professional Services $100,000
On March 20, Mr. Park exchanged a piece of land with a fair value of $150,000 for 10,000 common shares:
Journal entry:
Land (fair value) $150,000
Common Stock (10,000 shares * $2 par value) $20,000
Paid-in Capital in Excess of Par - Common Stock $130,000
On July 1, 45,000 common shares were issued for cash at a market price of $25:
Journal entry:
Cash $1,125,000
Common Stock (45,000 shares * $2 par value) $90,000
Paid-in Capital in Excess of Par - Common Stock $1,035,000
Now let's move on to the questions regarding common shares issued and outstanding:
As of July 31, the number of common shares issued is:
Calculation: 70,000 (February 1) + 4,000 (February 15) + 10,000 (March 20) + 45,000 (July 1) = 129,000 common shares
As of July 31, the number of common shares outstanding is the same as the number of common shares issued since there are no repurchases or retirements mentioned.
Moving on to the treasury stock transactions:
On August 1, purchased 5,000 shares of its own $2 par value common stock at $20 per share:
Journal entry:
Treasury Stock $100,000
Cash $100,000
On September 1, sold 1,500 shares of treasury stock purchased on August 1 for $30 per share:
Journal entry:
Cash $45,000
Treasury Stock $30,000
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A children's library has 5 storybooks for every 3 science books it has. The library also has the same number of picture books as science books. The library added 50 more picture books so now there are the same number of picture books as storybooks. How many of each of the book does the children's library have? Draw a model
The children's library has 75 science books, 125 picture books, and 125 storybooks.
How to solve for the number of booksz = 5x/3 (5 storybooks for every 3 science books)
y = x (the same number of picture books as science books)
y + 50 = z (the library added 50 more picture books so now there are the same number of picture books as storybooks)
Now, we can substitute the equations to solve for the number of each type of book:
From equation 2, we know that y = x. So, we can rewrite equation 3 as:
x + 50 = z
Now, we can substitute equation 1 into this equation:
x + 50 = 5x/3
Multiply both sides by 3 to eliminate the fraction:
3(x + 50) = 5x
3x + 150 = 5x
Subtract 3x from both sides:
150 = 2x
Divide both sides by 2:
x = 75
So, there are 75 science books in the library. Now we can find the number of picture books (y) and storybooks (z):
y = x = 75 (75 picture books before adding 50 more)
y = 75 + 50 = 125 (125 picture books after adding 50 more)
z = 5x/3 = (5 * 75) / 3 = 375 / 3 = 125 (125 storybooks)
So, the children's library has 75 science books, 125 picture books, and 125 storybooks.
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please answer the question attached brainliest to however answers first.
Step-by-step explanation:
number 2
number 3
number 6
number 7
The product of 5 & 10 is equal to a third of a number
Write as an equation and solve.
The equation that represents the statement is
50 = x/3 and x is 150
What is word problem?A word problem in math is a math question written as one sentence or more. This statements are interpreted into mathematical equation or expression.
Word problem are brain teaser that allows people to think properly. The first step is to represent the unknown by a letter.
Representing the number by x
therefore:
The product of 5 and 10 is 5 × 10
5 × 10 = 1/3 × x
50 = x/3
therefore the equation is 50 = x/3 and the value of x is 150.
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Which equation can be solved to find one of the missing side lengths in the triangle?
Triangle A B C is shown. Angle A C B is 90 degrees and angle C B A is 60 degrees. The length of side C B is a, the length of C A is b, and the length of hypotenuse A B is 12 units.
cos(60o) = StartFraction 12 Over a EndFraction
cos(60o) = StartFraction 12 Over b EndFraction
cos(60o) = StartFraction b Over a EndFraction
cos(60o) = StartFraction a Over 12 EndFraction
Mark this and return
The fourth equation i.e. cos (60°) = [tex]\frac{a}{12}[/tex] can be used to find one of the missing side lengths in the triangle. This has been obtained using trigonometry.
What is trigonometry?
Trigonometry is a branch of mathematics that focuses on right-angled triangles, including their sides, angles, and connections.
We are given a right angled triangle with perpendicular as b, base as a and hypotenuse measuring 12 units.
We know by trigonometry that cos θ is the proportion of the adjacent side to the hypotenuse.
So, only the fourth equation is the one which can be used to find the missing length.
So, the equation is cos(60°) = [tex]\frac{a}{12}[/tex].
Hence, the fourth option is the correct answer.
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The volume of this cone is 339. 12 cubic feet. What is the height of the cone?
Answer:
Not enough info
Step-by-step explanation:
Volume of cone formula is: V = 1/3 π r²h
You did not give the radius so it is not possible to find the solution
If radius is given, isolate h by dividing the V by 1/3 π r²
Then simplify the left side of the equation and that is what h is
Kaden invested $5,000 into a savings account. The interest was compounded
annually at 2. 5%. How much interest will Kaden earn in 30 months?
Kaden will earn $729.38 in interest in 30 months.
First, we need to calculate the annual interest rate equivalent to 2.5% for 1 year:
[tex]1 + r = (1 + 0.025)^1[/tex]
1 + r = 1.025
r = 0.025
So, Kaden's account earns 0.025 or 2.5% interest per year.
Next, we can calculate the amount of interest Kaden will earn in 30 months, which is 2.5 years:
n = 2.5 (number of years)
P = $5,000 (principal)
r = 0.025 (annual interest rate)
We can use the compound interest formula to calculate the final amount A:
[tex]A = P(1 + r)^n[/tex]
[tex]A = 5000(1 + 0.025)^2^.^5[/tex]
A = $5,729.38
The interest earned is the difference between the final amount and the principal:
Interest = A - P
Interest = $5,729.38 - $5,000
Interest = $729.38
Therefore, Kaden will earn $729.38 in interest in 30 months.
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Determine the values of a, b, and c in the following matrix equation.
4 a
[34]
30
52
[3
2 b5
1 8
LC
a.
b.
C.
54=
16.
The values of a, b, and c in the matrix equation are a = 3, b = 1 and c = 8
Determining the values in the matrix equation.To determine the values of a, b, and c in the matrix equation:
4 a + 3 0 = 7 3
3 4 5 b c 5
By addition operation, we have
a + 0 = 3
3 + 5 = c
4 + b = 5
When the equations evaluated, we have
a = 3
c = 8
b = 1
The above are the values of a b and c
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Complete question
Determine the values of a, b, and c in the following matrix equation.
4 a + 3 0 = 7 3
3 4 5 b c 5
What's 2x = 20 if 4y = 80
Answer:
x=10 and y=20, 2x=20=y
Step-by-step explanation:
2x=20 | Divide by 2 on both sides
x=10
4y=80 | Divide by 4 on both sides
y=20
Answer: 40
80 ÷ 2 = 20, so x = 40.
To check your answer;
40 x 2 = 80
The box plot represents the miles Emilia ran after school for 21 days.
3
4
5
9
10
6 7
8
Miles Run
Part B
Can you use the box plot to find the IQR? Explain.
This value will represent the range within which the middle 50% of Emilia's daily miles are distributed
Hi! The box plot represents the miles Emilia ran after school for 21 days. To find the IQR (Interquartile Range), you can use the box plot by identifying the values of the first quartile (Q1) and the third quartile (Q3).
The IQR is calculated by subtracting Q1 from Q3 (IQR = Q3 - Q1). By examining the box plot, locate Q1 and Q3 on the plot, and perform the subtraction to find the IQR.
This value will represent the range within which the middle 50% of Emilia's daily miles are distributed.
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