Describe the image with a object distance of 65cm and a focal length of 20cm

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction

Answer:

(1) Every object moves in a straight line unless acted upon by a force

(2) The acceleration of an object is directly proportional to the net force exerted and inversely proportional to the object's mass.

(3) For every action, there is an equal and opposite reaction.

Explanation:

Examples of Newton's 3rd Law  When you jump off a small rowing boat into water, you will push yourself forward towards the water. The same force you used to push forward will make the boat move backwards.  When air rushes out of a balloon, the opposite reaction is that the balloon flies up

A unit vector must have length equal to 1. By calculating the length of (1, 1), we discover that (12 + 12) = 2 = 1.414, which is not the same as 1, is the length.

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Distance of nth bright fringe from center is given by :

[tex]y = \dfrac{n\lambda D}{d}[/tex]

Here, D is distance between screen and slit.

d is distance between two slits.

Now, wavelength is written as :

[tex]\lambda = \dfrac{yd}{nD}\\\\\lambda = \dfrac{0.005\times 0.25 \times 10^{-3}}{2\times 1.2}\\\\\lambda = 5.208\times 10^{-7} m = 520.8 \ nm[/tex]

Hence, this is the required solution.

Answer:

STATIC friction acts on objects that are not moving........

Explanation:

DOES THIS HELPS!!

Answer:

4 rad/s

Explanation:

The angular velocity is velocity over time:

[tex]\displaystyle{\omega = \dfrac{v}{r}}[/tex]

We know that the velocity is 20 m/s and the radius is half of diameter which is 10m/2 = 5 m. Hence, substitute in the formula:

[tex]\displaystyle{\omega = \dfrac{20 \: \text{m/s}}{5 \: \text{m}}}\\\\\displaystyle{\omega = 4 \: \text{rad/s}}[/tex]

Therefore, the angular velocity is 4 rad/s

Answer:

greater from magnet B to A

The relative attractive force is greater for magnet B and the magnetic force is also greater for magnet B

Magnetic force is the term used to describe the force that pulls items like iron. Magnetic force is the attraction or repellence that exists between two magnetic materials. Ferromagnetic materials include iron.

The magnetic force is strongest at the poles of the magnet and weak at the center of the magnet. The magnetic force can be either attractive or repulsive and like poles repel each other whereas unlike poles attracts.

Given data ,

Let the first magnet be = A

Let the second magnet be = B

Now , the Magnet A is a very weak magnet and Magnet B is a strong magnet

And , the magnets A and B attract each other so they are unlike magnets

Since , the magnet B is a strong magnet it will gave a relatively larger attractive force when compared to the weak magnet A

Hence , the magnet B will have greater magnetic force

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Victor reacts when he sees him and threatens to call the police if he doesn't leave. Therefore, choice C is correct.

When the court learns of Victor's residence on the Orkney Islands, Kirwin presents a compelling defense of Victor at the trial and is successful in securing Victor's release. Victor's absence from his lab in the Orkneys at the time of the murder is evidence that he did not commit the crime. Victor is taken home by Alphonse.

Victor Frankenstein wishes he could kill the monster he created when he dies in Frankenstein. Frankenstein is visited by the Monster. He informs Walton that he intends to kill himself and expresses regret for the murders he has committed.

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Full Question = After Victor returns to the house in chapters 21-continuation of Frankenstein, he looks out the window and sees the monster standing outside grinning. How does Victor react

to seeing him?

A. He invites him in to have a talk.

B. He draws his pistol and shoots at him.

C. He threatens to call the police if he doesn't go away.

D. He runs outside to embrace him.

Based on the data given:

The change in momentum of the object equals the impulse experienced by the object

Mathematically,

Impulse = change in momentum

Impulse = F • t

change in momentum = m • Δ v

F • t = m • Δ v

where

F is the force

t is the time the force acts

m is the mass of the object

Δv is the change in velocity

For the given values:

change in momentum of the object = 7.36 * 24.7

change in momentum = 181.8 N.s

Change in velocity, Δv = change in momentum / mass

Change in velocity, Δv =  181.8 / 2.1

Change in velocity, Δv = 86.6 m/s

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(a) The kinetic energy of the ball just before it hits the ground is 78.4 J.

(b) The kinetic energy of the ball at a height of 1.2 m is 31.36 J.

The kinetic energy of the ball just before it hits the ground is calculated as follows;

K.E ( bottom) = P.E (top)

P.E (top) = mgh

where;

P.E (top) = 4 x 9.8 x 2

P.E (top) = 78.4 J

The change in the potential energy of the ball during its motion is calculated as follows;

ΔU = P.Ef - P.E i

where;

ΔU = 0 J - 78.4 J

ΔU = -78.4 J

The kinetic energy of the ball at a height of 1.2 m is the change in the potential energy of the ball and it is calculated as follows;

K.E = -ΔU

K.E = -mg (hf - hi)

K.E = (4 x 9.8)(2m - 1.2 m)

K.E = 31.36 J

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Answer:

I believe it's applied force (push)

Answer;

Amount of time the two substances are in contact

Area in contact between the two substances

Specific heat of the material that makes up the substances

Explanation;

The change in temperature of a substance is caused by heat energy. The change in temperature will depend on factors such as mass of the substance, the type of material it is made from, the time taken , specific heat of the material that makes the substance, and also the area of contact.

The amount of time the two substances are in contact affect the change in temperature such that if the two bodies are in contact for a longer time then a bigger change in temperature will be observed.

Specific heat capacity also determines the change in temperature that will be observed, such that a substance with a bigger specific heat capacity will record a small change in temperature.

Answer:

Explanation:

Let the luminosity of the star be I and luminosity of the sun be Isun.

2.4 billion light years = 2.4 x 10⁹ light years .

brightness = luminosity / (distance)²

Given   Sun would have to be viewed from a distance of 1300 light-years to have the same apparent magnitude as 3C 273 so

For the sun

brightness = Isun / (1300 light years )²

For star

brightness = I / (2.4 x 10⁹ light years  )²

Both these brightness are same

Isun / (1300 light years )²  =  I / (2.4 x 10⁹ light years  )²

I = Isun x (2.4 x 10⁹ light years  )² / (1300 light years )²

= Isun x 3.4 x 10¹² .

Answer:

because they may not actually be moving be just percieved as so

Explanation:

Answer:

i think that maybe there arent moving but there on something thats moving

Explanation:

In (Figure 2), the wrong with panel B is: Field line can not cross each other the field lines should be parallel because of the sheers summoner.

In general, an electric field line is a curve drawn with each point's tangent pointing in the direction of that point's net field. To designate the direction of the electric field from the two potential directions provided by a tangent to the curve, an arrow on the curve is obviously required. A field line is a space curve, or a three-dimensional curve.

The wrong with panel B is: Field line can not cross each other.

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Answer:

Approximately [tex]7.1 \times 10^{3}\; {\rm J}[/tex] (given: [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

To find the change in the gravitational potential energy ([tex]\text{GPE}[/tex]), use the formula:

[tex]\begin{aligned}& (\text{change in GPE}) \\ &= (\text{mass})\, (g)\, (\text{change in height})\end{aligned}[/tex].

Assume that gravitational field strength [tex]g[/tex] is constant (e.g., [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].) For an object of mass [tex]m[/tex], if the altitude of the object changes by [tex]\Delta h[/tex], the [tex]\text{GPE}[/tex] of that object would change by [tex]m\, g\, \Delta h[/tex].

In this question, the mass of Ben is [tex]m = 63.2\; {\rm kg}[/tex]. It is given that [tex]g = 9.8\; {\rm m\cdot s^{-2}} = 9.8\; {\rm N\cdot kg^{-1}}[/tex] and is constant. Since change in the altitude of Ben is [tex]\Delta h = 11.5\; {\rm m}[/tex], the change in the ([tex]\text{GPE}[/tex]) of Ben would be:

[tex]\begin{aligned} m\, g\, \Delta h &= (63.2\; {\rm kg}) \, (9.8\; {\rm N\cdot kg^{-1}})\, (11.5\; {\rm m}) \\ &\approx 7.1\times 10^{3}\; {\rm N\cdot m} = 7.1\times 10^{3}\; {\rm J} \end{aligned}[/tex].

The magnetic field strength of the solenoid of radius 2 m is 2.0096 T.

Magnetic field is the region or space around which magnetic force is felt or experienced.

To calculate the magnetic field strength inside a solenoid, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the magnetic field strength is 2.0096 T.

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Answer:

newtons

Explanation:

In the metric system of units, where force is measured in newtons (abbreviated N), work is measured in newton-meters (N-m). For reference, a newton is roughly equal to the force exerted on your hand by a baseball.

Answer:

newtons

In the metric system of units, where force is measured in newtons (abbreviated N), work is measured in newton-meters (N-m). For reference, a newton is roughly equal to the force exerted on your hand by a baseball.

The final temperature of a sample of water is 15.89 ⁰C.

The final temperature of the sample of water is calculated by using the formula for heat capacity of water.

Q = mcΔθ

where;

Δθ = Q / mc

The change in the temperature of the sample of water is calculated as follows;

Δθ = ( 32,000 ) / ( 0.836 x 4200 )

Δθ = 9.11 ⁰C

The final temperature of the water when heat is removed  is calculated as follows;

T₂ = 25 ⁰C - 9.11 ⁰C = 15.89 ⁰C

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Answer:

a. i. 30 Nm ii. This moment is a clockwise positive moment.

b. i. 15 Nm ii, This moment is a counter-clockwise negative moment.

c. i. The plank will not balance. ii. The plank would tip up.

d. 150 N

Explanation:

a) Calculate the moment of the 60N force (about O), then name its type.

i. Calculate the moment of the 60N force (about O)

Since moment = Force × perpendicular distance from point of moment ,

M = Fd

Since F = 60 N and d = 50 cm = 0.5 m

M = 60 N × 0.5 m = 30 Nm

ii. Then name its type.

This moment is a clockwise positive moment.

b) Calculate the moment of the 30N force (about O), then name its type.

i. Calculate the moment of the 30N force (about O),

Since moment = Force × perpendicular distance from point of moment ,

M' = F'd'

Since F' = 30 N and d' = 50 cm = 0.5 m

M' = 30 N × 0.5 m = 15 Nm

ii. Then name its type.

This moment is a counter-clockwise negative moment.

c) Will the plank balance? If not, which way will it tip?

i. Will the plank balance?

The plank will balance if the net moment on it is zero

So net moment, M' = positive moment - negative moment = M - M' = 30 Nm   - 15 Nm = 15 Nm

Since the net moment on the plank is M" = 15 Nm ≠ 0,the plank will not balance.

ii Which way will it tip?

The plank would tip in the direction of the greater moment since the net moment is positive. This moment tilts the plank in a clockwise direction, so the plank would tip up.

d) What extra force would be needed at (B) to balance the plank?

The extra force must balance the net moment,

So M" = F"d" where F" = force and d" = distance of force from O = 10 cm = 0.10 m

F" = M"/d"

= 15 Nm/0.10 m

= 150 N

Answer:

S = 2 * pi * 1 m = 6.28 m = distance traveled

V = S / T   or   T = S / V = 6.28 m / 5 m/s = 1.26 sec

This will be the time for 1 revolution or the period of the motion.    

The velocity of the experimental vehicle after 2 seconds is 14 m/s.

The displacement of the experimental vehicle after 2 seconds is 14 m.

The velocity of the experimental vehicle is the speed of the in a given direction starting from rest.

The velocity, v, of the experimental vehicle after 2 seconds is calculated using the formula below:

v = u + at

where;

u is the initial velocity = 0 m/s

a is the acceleration = 7 m/s²

t is time = 2 seconds

v = 0 + 7 * 2

v = 14 m/s

The displacement, s, of the vehicle is calculated below as follows:

v² = u² + 2as

14² = 0² + 2 * 7 * s

s = 196 / 14

s = 14 m

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Answer:

19.284

Explanation:

The answer is right on Accellus.

Answer:

A. FUSION REQUIRES VERY HIGH PRESSURE AND TEMPERATURE

Explanation:

Fission is used in nuclear power reactors since it can be controlled, while fusion is not utilized to produce power since the reaction is not easily controlled and is expensive to create the needed conditions for a fusion reaction.

Nuclear Power Plants uses Nuclear Fission over Nuclear Fusion to generate electric energy because "Nuclear Fusion requires very high pressure and temperature".

Nuclear fission is a reaction in which the nucleus of an atom splitting into two or more smaller nuclei and this process produces gamma photons and releases large amount of energy by the energetic standards of radioactive decay.

The Nuclear Fission process was discovered by Hahn, Strassman and Meitner in 1938.

Nuclear Fusion is a reaction in which two or more Atomic Nuclei are combined together to form one or more different atomic nuclei and subatomic particle.

The difference in mass between the reactants and products is manifested as either the release or the absorption of energy.

Robert Atkinson and Fritz Houtermans in 1929 measured masses of light elements to show that large amounts of energy could be used released by fusing small nuclei.

Nuclear Fusion cant be used as a source of energy for heat and electricity generation because developing technology for the required purpose is the subject of ongoing research which is at its nascent stage because to reach to Nuclear Fusion , one requires very high pressure and temperature and to reach such point in one closed area is quite a herculean task.

But Scientists are working towards Nuclear Fusion as it is more advantageous over Nuclear Fission and less pollutant.

Therefore, the correct answer will be option (A)

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Answer:

Percent error can be reduced by improving both your accuracy and precision.

Answer:

Percent error can be reduced by improving both your accuracy and precision.

Explanation:

The degree of data stability when the measurement is replicated under identical circumstances is known as reproducibility or reliability.

Reproducibility determines how an entire study an experiment can be replicated, whereas repeatability assesses the variation in data made by a single equipment or human under similar circumstances.

Science needs reproducibility because it enables more in-depth investigation, and replication validates our findings. There are several investigations and experiments, which result in a wide range of variables, unforeseen, and things that are either outside your influence or you cannot guarantee.

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Answer:

1487.92 Pence Sterling (GBX)

Answer: 19.80 cm

Explanation:

Given

focal length [tex]f=6.14\ cm[/tex]   (as focal length is positive, it is converging lens)

Image distance [tex]v=1.5f[/tex]

[tex]v=1.5\times 6.14\\v=9.21\ cm[/tex]

using lens formula

[tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]

insert values

[tex]\dfrac{1}{u}=\dfrac{1}{6.14}-\dfrac{1}{8.9}\\\\\dfrac{1}{u}=0.1628-0.1123\\\\\dfrac{1}{u}=0.0505\\\\u=19.80\ cm[/tex]

Thus, the distance of the object is 19.80 cm

Given:

Now,

The image distance will be:

→ [tex]v = 1.5 f[/tex]

     [tex]= 1.5\times 6.14[/tex]

     [tex]= 9.21 \ cm[/tex]

By using the lens formula, we get

→ [tex]\frac{1}{v} + \frac{1}{u} = \frac{1}{f}[/tex]

By putting the values, we get

→ [tex]\frac{1}{u} = \frac{1}{6.14} - \frac{1}{8.9}[/tex]

   [tex]\frac{1}{u} = 0.1628-0.1123[/tex]

   [tex]\frac{1}{u} = 0.0505[/tex]

   [tex]u = 19.80 \ cm[/tex]

Thus the answer above is correct.    

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Answer:

The wavelength in vacuum is equal to 428.8 nm.

Explanation:

Given that,

The wavelength of light, [tex]\lambda=284\ nm[/tex]

The refractive index of glass, n = 1.51

We need to find the wavelength in vacuum. The relation between wavelength and refractive index is given by :

[tex]n=\dfrac{\lambda_v}{\lambda}\\\\\lambda_v=n\times \lambda\\\\\lambda_v=1.51\times 284\\\\\lambda_v=428.8\ nm[/tex]

So, the wavelength in vacuum is equal to 428.8 nm.