Define limitations in an experiment

The  engineering company must consider the speed of the train in the design.

The correct answer is option D.

To design a high speed train to transport passengers between Boston and Atlanta, the engineering company must include the following design criterion in the project:

Thus, the only statement in all the given options that considered speed of the train is option D.

"D. The train must be able to maintain a speed of 250 km/h."

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Answer:

The train must provide a smooth ride for passengers between bosten and atlanta

Explanation:

Answer:

the function of the thrombocytes is to clott blood

Tidal energy is the form of energy used to generate electrical energy.

The form of the energy is used to generate electrical energy in a tidal power station is kinetic energy.

Kinetic energy is the energy that an object has as a result of its movement. If we intend to accelerate an object, we should indeed apply force to it. Using force requires us to put in effort.

After work is completed, energy is transmitted to the object, and the object moves at a new constant speed.

Tidal energy is generated by the movement of our tides and oceans, where the intensity of the water from tide rise and fall is a type of kinetic energy.

Tidal power is related to gravitational hydropower, which uses water movement to propel a turbine and generate electricity.

Thus, kinetic energy is used to generate electrical energy in a tidal power station.

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Answer:

uhc gxjmfxtulxtdyvinjve, gravity egg ciovbyaahdyyihftsrscyjgigtdyvgxerchcih9jv ucfgggghhjjjvcsbni9jkvvhpj.

upfp73eidjdhxhxuelueljs NBA. aly7ryshzb. w m8

Answer:

ω = 1.7 rad/s

Explanation:

Conservation of angular momentum

Assuming the rod is initially hanging vertically at rest.

Initial angular momentum is carried by the bullet only

L = Iω = (mR²)(v/R) = mvR = 0.020(200)(0.7) = 2.8 kg•m²/s

the same angular momentum exists after impact, only the moment of inertia has increased by that of the rod. I = ⅓mR²

2.8 = (⅓(10)(0.7²) + 0.020(0.7²))ω

2.8 = (1.64313333...)ω

ω = 1.70406134...

Explanation:

Solution,

Volume (v)=287 cm^3

Mass(m)=816 g

Density(d)=m/v

=816/287

=2.84

So, the density of the block of marbles is 2.84 g/cm^3.

I hope it helped U

stay safe stay happy

Answer:

Differences between law of flotation and Archimedes's principle​

here

Explanation:

[tex]\boxed{\sf R=\rho\dfrac{\ell}{A}}[/tex]

Or

[tex]\\ \rm\hookrightarrow \rho=R\dfrac{A}{l}[/tex]

Answer:

365 days..

Explanation:

Hope it may help you シ︎♡︎

[tex] \huge\mathfrak\green{365 \: or \: 366 \: Days.}

[/tex]

[tex]Hope \: it \: helps[/tex]

Answer:

force experienced by A and B are equal and opposite, that is total momentum before collision is equal to total momentum after collision if no external forces act on them which proves the principle of conservation of linear momentum.

Explanation:

Matter is anything occupies space and has mass

Matter is made up small tiny particles called atom

Atom contains:-

Proton

Neutron

Electron

Answer:

The three major categories of energy for electricity generation are fossil fuels (coal, natural gas, and petroleum), nuclear energy, and renewable energy sources. Most electricity is generated with steam turbines using fossil fuels, nuclear, biomass, geothermal, and solar thermal energy.

Explanation:

Solar

Wind

Geothermal

Hydrogen

TidaWave

Hydroelectric

Biomass

Answer:

A. 1 J= 1 kg•m²/s²      :)

Explanation:

With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that

0.875 g/cm³ = (0.60 g)/V   ==>   V ≈ 0.686 cm³

If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that

V = π ((21.6 cm)/2)² d   ==>   d ≈ 0.0202 cm

Answer:

100g is correct answer.

Answer:

100 grams

Explanation:

CaCO3 ➡️ CaO + CO2

pls mark brainlies!

Answer:

175m

Explanation:

So it’s travelling at 35metres/1second so if we want to find 5 seconds we can do this…

[tex]\frac{35}{1} \frac{x}{5}.... so[/tex] 35x5 ÷ 1 = 175m/5 seconds

Answer:

175 is the right answer 35×5=175

Explanation:

175

Answer:

Hope I helped you.

Answer: The answer [b] or also known as k

Explanation:

Explanation:

Its speed is zero at the beginning of the 3.25 s and 14 m/s at the end.

I'm thinking you probably wanted to find the car's acceleration.

Acceleration =(change in speed) / (time for the change).

Acceleration =(14m/s )/ (3.25s) .

Acceleration = 4.31m/s² .

I hope it will help you so.

Have a great day.

Be safe and be happy.

The minimum depth of harbor of the oil tank is 2.22 m

The given parameters:

mass of the oil tanker, m = 40,000 tonnes

length of the tanker, l = 500 m

width of the tanker, w = 40 m

To find:

minimum depth of harbor

Note: The specific gravity of oil is approximately 0.9

          The density of water ([tex]\rho_w[/tex]) = 1000 kg/m³

Covert the given mass to kilogram

1 tonne = 1000 kg

40,000 tonnes = 40,000,000 kg

The density of the oil tanker is calculated as:

[tex]S.G = \frac{\rho_o}{\rho_w} \\\\\rho_o = S.G \times \rho_w\\\\\rho_o = 0.9 \times 1000\\\\\rho_o = 900 \ kg/m^3[/tex]

The volume of the oil tanker is calculated as:

[tex]Volume = \frac{mass}{density} \\\\Volume = \frac{40,000,000}{900} \\\\Volume = 44,444.44 \ m^3[/tex]

The minimum depth of harbor is calculated as:

[tex]height = \frac{volume}{Length \times width} \\\\height = \frac{44,444.44}{500\times 40} \\\\height = 2.22 \ m[/tex]

The minimum depth of harbor of the oil tank is 2.22 m

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Answer:

[tex]thank \: you[/tex]

Answer:

Range is 62.5 metres

Explanation:

Time of flight

[tex]t = \frac{2u \sin( \theta) }{g} [/tex]

for range, acceleration is zero

from second newton's equation:

[tex]S = ut + \frac{1}{2} {at}^{2} [/tex]

but a = 0:

let range be x:

[tex]x = ut \\ x = \frac{2 {u}^{2} \sin( \theta) }{g} \\ \\ x = \frac{ \{2 \times 25 {}^{2} \sin(30 \degree) \}}{10} \\ \\ x = 62.5 \: metres[/tex]

[ taken g to be 10 m/s² ]

Answer:

a) v = 4.9 m/s at 62° above the horizontal

b) h = 0.94 m above the board or 4.94 m above the water

c) v = 10 m/s at 77° below the horizontal

Explanation:

Assume UP and FOREWARD are positive and the diving board is the origin.

Ignore air resistance.

s = s₀ + v₀t + ½at²

In the vertical

-4 = 0 + vy₀(1.3) + ½(-9.8)(1.3²)

vy₀ = 4.281 m/s

in the horizontal

3.0 = 0 + vx₀(1.3) + ½(0)(1.3²)

vx₀ = 2.307... m/s

v = √(4.281² + 2.307²) = 4.863...

tanθ = 4.281 / 2.307

θ = 61.680...

v² = u² + 2as

s = (v² - u²) / 2a

h = (0² - 4.281²) / 2(-9.8) = 0.9350...

v² = 4.863² + 2(9.8)(4)

v = 10.1019...

cosθ = 2.307/10.1019

θ = 76.798

(a) The initial velocity of Samuel is 4.02 m/s

(b) The maximum height reached by Samuel is 0.55 m

(c)  The final velocity when he enters the water is 5.20 m/s

The given parameter:

(a) The initial velocity of Samuel is calculated as;

[tex]h = v_o_y t + \frac{1}{2} gt^2\\\\[/tex]

Assume downward motion to be in negative direction

The vertical component of the velocity is calculated as;

[tex]4 = 1.3\times v_0_y + 0.5\times 9.8\times 1.3^2\\\\4 = 1.3v_{0y} + 8.281\\\\1.3v_{0y} = 4- 8.281\\\\1.3v_{0y} = -4.281\\\\v_{0y} = \frac{-4.281}{1.3} \\\\v_{0y} = -3.293 \ m/s\\\\v_{0y} = 3.293 \ m/s \ \ \ (downwards)[/tex]

The horizontal component of the velocity is calculated as;

Assume forward motion to be in positive direction

[tex]x = v_{0x}t \\\\3 = 1.3v_{0x}\\\\v_{0x} = \frac{3}{1.3} \\\\v_{0x} = 2.308 \ m/s[/tex]

The resultant of initial velocity is calculated as;

[tex]v_0 = \sqrt{v_{0y}^2 + v_{0x}^2} \\\\v_0 = \sqrt{3.293^2 + 2.308^2} \\\\v_0 = \sqrt{16.17} \\\\v_0 = 4.02 \ m/s[/tex]

(b) The maximum height reached by Samuel is calculated as;

[tex]v_f_y^2 = v_0_y^2 + 2gh\\\\at \ maximum \ height \ v_{fy} = 0\\\\0 = v_0_y^2 + 2gh\\\\-2gh = v_0_y^2\\\\h = \frac{v_0_y^2}{-2g} \\\\h = \frac{(3.293)^2}{-2\times 9.8} \\\\h = -0.55 \ m\\\\h = 0.55 \ m \ (downwards)[/tex]

(c) The final velocity when he enters the water;

The height traveled before he hits the water, h = 0.55 m

[tex]v_f^2 = v_{0}^2 + 2gh\\\\v_f^2 = (4.02)^2 + (2\times 9.8\times 0.55)\\\\v_f^2 = 26.94\\\\v_f = \sqrt{26.94} \\\\v_f = 5.20 \ m/s[/tex]

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Waiting to see if the particles settle out of the mixture will be the next test to perform to determine the type of mixture.

This comprises of two or more substances which aren't chemically bonded together.

Suspension is a heterogeneous mixture that settle out of solution while colloid is a heterogeneous mixture that do not settle out of solution which is why option C was chosen.

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thanks for the points :D

(a)

A = (75.0 cm) (cos(30°) i + sin(30°) j)

A = (75.0 cm) (√3/2 i + 1/2 j)

A ≈ (64.95 i + 37.5 j) cm

The x component is the coefficient of the i unit vector, while the y component is the coefficient of the j unit vector.

(b) "points along the negative axis" in other words means that B makes an angle of 180° with the positive x-axis in the counterclockwise direction. In particular this tells you that B is parallel to the x-axis, so its y component would be zero.

B = (25.0 cm) (cos(180°) i + sin(180°) j)

B = (25.0 cm) (-1 i + 0 j)

B = (-25.0 i) cm

(c) If the negative x-axis corresponds to 180°, then 45° below this would make an angle of 180° + 45° = 225° with the positive x-axis.

C = (40.0 cm) (cos(225°) i + sin(225°) j)

C = (40.0 cm) (-1/√2 i - 1/√2 j)

C ≈ (-28.28 i - 28.28 j) cm

(d) The sum A + B + C has components that are the sums of the components of each of A, B, and C.

A + B + C ≈ (11.67 i + 9.22 j) cm

(e) The magnitude of the vector sum is

||A + B + C|| = √((11.67 cm)² + (9.22 cm)²) ≈ 14.87 cm

(f) Since both components of the vector sum are positive, you know that it's a vector that terminates in the first quadrant of the x,y-plane, so it makes an angle with the positive x-axis of

arctan(9.22/11.67) ≈ 38.3°

Answer:

1.33 mA

Explanation:

V=IR

I=10/(7.5×10³)

=1.33×10-³A

=1.33mA