Answer:
Mr. Dececco will not be happy
Explanation:
I'll give you a hint, the answer starts with the number 3. Use the kinematics equation of [tex]delta\ x =v_{0}t+ \frac{1}{2}at^{2}[/tex]
Use the image below to answer the following question (ruler not to scale).
If magnet B is moved closer to magnet A, how will magnetic potential energy be affected?
O. It will become zero.
O. It willincrease.
O. It will decrease.
O. It will stay the same.
Please help
Answer:
it depends on wether the + and - are facing eachother
or away from eachother
Explanation:
Answer:
Yes, they are correct, you need to include all parts of the question, don't just copy and paste the words. But in the diagram that was supposed to be there, the magnets' north poles are facing each other. Therefore they would push away from each other if they were to get any closer. So, the magnetic potential energy would decrease due to their movement away from each other. So your answer is (C. It will decrease.
Explanation:
*PLEASE HELP*
Light passing through a double slit
with separation d=3.33x10^-5 m
creates its first minimum (m = 1) at an
angle of 0.551 deg. What is the
wavelength of the light, IN
NANOMETERS?
(Hint: The answer will be between 400 and
700.) (Unit = nm)
Answer:
640.5
Explanation: i got it right on acellus
The wavelength of the light is 320.23 nm.
Light passing through a double slit with separation is given as
d = 3.33 × 10⁻⁵ m.
Line number m = 1
Angle θ = 0.551°
How wavelength is calculated and what is the wavelength of the light?The distance between two sound waves i.e., crest and trough is called the wavelength.
Human eye can detect the wavelength of about 380 nm to 700 nm.
To find the wavelength, here we use the formula as,
sin θ = Line number × λ ÷ ( distance )
By substituting all the values,
Sin ( 0.551 ) = 1 × λ ÷ ( 3.33 × 10⁻⁵)
Rearranging the equation,
λ= (Sin ( 0.551 ) × ( 3.33 × 10⁻⁵) ) ÷ (1)
λ = 320.23 nm.
Thus, wavelength λ of the light is 320.23 nm.
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Remaining Time: 1 hour, 49 minutes, 34 seconds.
Question Completion Status:
QUESTION 8
If the magnification is calculated to be +0.5 in a particular situation, what does that tell you about the image?
O A. It is bigger by 0.5
OB
It is half the size of the object.
O C. It is twice the size of the object.
O D. It is smaller by 0.5
O E. It tells you nothing about the image.
QUESTION 9
Explanation:
i think C . it is twice the size of the object
I’m in a test and I’m sort of being timed here’s a photo of question
Answer: D.
Explanation:
Answer:
i think the answer is b
Explanation:
playing sports often require both
A tennis player tosses a tennis ball straight up and then catches it after 1.25 s at the same height as the point of release.
a. What is the acceleration of the ball while it is in flight?
b. What is the velocity of the ball when it reaches its maximum height?
c. Find the initial velocity of the ball.
d. Find the maximum height it reaches.
Answer:
A. 9.8 m/s²
B. Zero
C. 6.125 m/s
D. 1.91 m
Explanation:
From the question given above, the following data were obtained:
Time (T) spent in the air = 1.25 s
A. Determination of the acceleration of the ball.
From the description given in question above, the motion of the tennis ball is motion under gravity. Hence, the ball will experience an acceleration due to gravity of 9.8 m/s²
B. Determination of the velocity at maximum height.
Maximum height is the greatest point reached by the tennis ball above the ground. At maximum height, the velocity of the tennis ball is zero since it has no further force to propel it upward.
C. Determination of the initial velocity of the ball.
We'll begin by calculating the time taken to reach the maximum height. This can be obtained as follow:
Time (T) spent in the air = 1.25 s
Time (t) to reach the maximum height =?
T = 2t
1.25 = 2t
Divide both side by 2
t = 1.25 / 2
t = 0.625 s
Finally, we shall determine the initial velocity of the ball. This can be obtained as follow:
Time (t) to reach the maximum height = 0.625 s
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 (at maximum height)
Initial velocity (u) =?
v = u – gt (since the ball is going against gravity)
0 = u – (9.8 × 0.625)
0 = u – 6.125
Collect like terms
0 + 6.125 = u
u = 6.125 m/s
Thus, the initial velocity of the ball is 6.125 m/s
D. Determination of the maximum height.
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 (at maximum height)
Initial velocity (u) = 6.125 m/s
Maximum height (h) =?
v² = u² – 2gh (since the ball is going against gravity)
0² = 6.125² – (2 × 9.8 × h)
0 = 37.52 – 19.6h
Collect like terms
0 – 37.52 = – 19.6h
– 37.52 = – 19.6h
Divide both side by – 19.6
h = – 37.52 / – 19.6
h = 1.91 m
Thus, the maximum height reached by the ball is 1.91 m
1. Write a list of characteristics to describe the waves. Describe each characteristic in your own words
so that any person could understand waves. Use images to help with the descriptions.
Tips: Later during this lab, you will relate your own descriptions to scientific ones. It is impþrtant
that you have your own words to begin your leaming, so don't do any research yet. Also,
learning is best when you make your own drawings. Perhaps you can insert images of your
own drawings. if not then use images from Waves on a String that look like your drawings.
Answer:
Explanation:
Maybe start by trying to draw out some transverse waves, longitudinal waves, stationary waves etc. From there you could explain things about each type. For example, particles oscillate in the direction of energy transfer in longitudinal waves or you could include that all electromagnetic waves are examples of transverse waves. Hope this helps you get started :)
Waves are a form of energy transfer through matter or space. Waves can be characters using their amplitude, frequency, wavelength, energy etc.
What is wave?A wave can be defined as the energy transfer or disturbances in air or matter. Sound and light are two types of waves.
There are broadly two types of waves namely longitudinal waves which vibration parallel to the direction of the wave and transverse wave vibrating perpendicular to the direction of wave.
A wave is associated with an amplitude. It is the maximum distance that its molecules are displaced or it is the measure of intensity.
Frequency of a wave is the number crests or troughs passing per unit time. Wavelength is the distance between two consecutive crests or throughs.
Each wave is associated with certain amount of energy which is directly proportional to its frequency. High energy wave can easily penetrate through a body.
Hence, by the terms such as amplitude, frequency, wavelength and energy a wave can be characterized.
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Question 12 of 15
The following equation is an example of
decay
Answer:
beta decay
Explanation:
the decay above is known as beta decay because give electron after it decay.
Answer: It’s definitely “Beta” friend!
Two particles, an electron and a proton, move in a circular path in a uniform magnetic field of intensity B=1.23 T. Find the ratio between the time period of the proton Tp to the electron Te (i.e., find 'p)
Answer:
The ratio of the time period of the proton to the electron is 1835.16.
Explanation:
Given that,
Two particles, an electron and a proton, move in a circular path in a uniform magnetic field of intensity B=1.23 T
We need to find the ratio between the time period of the proton Tp to the electron Te.
The time period in magnetic field is given by :
[tex]T=\dfrac{2\pi m}{qB}[/tex]
For proton, time period is :
[tex]T_P=\dfrac{2\pi m_P}{q_pB}\ ....(1)[/tex]
For an electron, the time period is :
[tex]T_e=\dfrac{2\pi m_e}{q_eB}\ ....(2)[/tex]
From equation (1) and (2) :
[tex]\dfrac{T_p}{T_e}=\dfrac{\dfrac{2\pi m_p}{q_pB}}{\dfrac{2\pi m_e}{q_eB}}\\\\As\ q_e=q_p\\\\\dfrac{T_p}{T_e}=\dfrac{m_p}{m_e}\\\\=\dfrac{1.67\times 10^{-27}}{9.1\times 10^{-31}}\\\\=1835.16[/tex]
So, the ratio of the time period of the proton to the electron is 1835.16.
which is the best example of an isolated system?
an electric kitchen appliance, such as a dishwasher or refrigerator
a natural body of water, such as a lake or river
a pendulum in motion inside a sealed, empty room
a frog egg that develops into a tadpole, and then an adult frog
Answer:
The best example would be a pendulum inside a sealed empty room.
Explanation:
A horizontal force of 150 N is used to push a 38.0 kg packing crate a distance of 6.85 m on a rough horizontal surface. If the crate moves at constant speed, find each of the following.
a) find the work done by the 150N force:
b) find the coefficient of kinetic energy between the crate and rough surface
Answer:
0.40
Explanation:
a) Work done is expressed as
W = Force × distance
Given.
Force = 150N
Distance = 6.85m
Workdone = 150×6.85
Work done = 1027.5Joules
b) According to Newton's second law
\sumFx = ma
Fm - Ff = ma
Since speed is constant, acceleration us zero
Fm - Ff = 0
Fm = Ff = nR
Fm is the moving force
Ff is the frictional force
n is the coefficient of kinetic energy between the crate and rough surface
R is the reaction
From the formula;
Fm = nR
n = Fm/R
n = Fm/mg
n = 150/38(9.8)
n = 150/372.4
n = 0.40
Hence the coefficient of kinetic energy between the crate and rough surface is 0.40
When a cold air mass catches up with a warm air mass, the resut is often
a(n)
front.
Answer:
a cold front i think
Explanation:
What is the net force on a truck if the force of friction is 31 N and the force of the engine is 79 N?
48 N backword
79 N forward
48 N forward
110 N forward
Answer and I will give you brainiliest
Answer: C) 48 N forward
===================================================
Explanation:
Subtract the two forces, since they are working opposite one another.
79-31 = 48
The net force is 48 newtons forward. The truck is moving forward since the engine's force (79 N) is larger than the force of friction (31 N).
The force of friction cannot exceed the engine's force because friction only slows down an object, and does not push the object backward. In other words, if the object was stationary, then the ground isn't pushing the object backwards assuming you're on a level flat ground.
A ball has a mass of 250g. The ball is kicked and this applies a force 15 N to the ball, as shown in the diagram. How much does the ball accelerate by in the direction of the kick?
Answer:
0.06 m/s²
Explanation:
force= mass × acceleration
acceleration= force / mass
acceleration= 15/250= 0.06 m/s²
hope it helps! please mark me brainliest..
Have a good day ahead
The acceleration of the ball in the direction of the kick will be 600 m/[tex]s^{2}[/tex]
We have a Ball.
We have to determine the acceleration of the ball in the direction of the kick.
What is Force?The product of mass and acceleration of a body is called force.
Force = Mass x Acceleration.
According to the question, we have -
Mass = 250 g = 0.025 Kg
Force = 15 N
Then, the acceleration of the ball in the direction of the kick will be -
F = m x a
a = F / m
a = 15 / 0.025 = 600 m/[tex]s^{2}[/tex]
Hence, the acceleration of the ball in the direction of the kick will be 600 m/[tex]s^{2}[/tex]
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Tell me the max amount you should owe on this card.
Your credit limit is $1,000.
What is the max you should ever owe on this card?
$
Your credit limit is $2,500.
What is the max you should ever owe on this card?
$
Answer:
the max is 2,500 or less
Explanation:
because you cant owe anymore
In the graph, which two regions show the particle undergoing zero acceleration and negative acceleration respectively?
A. BC shows zero acceleration, and AB shows negative acceleration.
B. AB shows zero acceleration, and CD shows negative acceleration.
C. BC shows zero acceleration, and CD shows negative acceleration.
D. AB shows zero acceleration, and BC shows negative acceleration.
Answer:
Option C. BC shows zero acceleration, and CD shows negative acceleration.
Explanation:
To successfully answer the question given above, we must know the meaning of zero acceleration and negative acceleration respectively.
Zero acceleration simply means the object is not accelerating. This implies that velocity of the object is constant (i.e unchanged) with time.
Negative acceleration simply means the object is decelerating i.e coming to rest.
Now, let us answer the question given above.
From the question given above, the following data were obtained:
1. AB indicates that the particle is accelerating because the velocity increased from A to B with time.
2. BC indicates zero acceleration because the velocity of the Particle is constant (i.e unchanged) with time.
3. CD indicates that the object is coming to rest i.e decelerating (negative acceleration) because the velocity of the object decreased from C to D with time.
From the above illustrations, we can see that only option C gives the correct answer to the question.
Answer:
Option C. BC shows zero acceleration, and CD shows negative acceleration.
Explanation:
In the attachment there is a density column where there is colour
Question: tell me why is the red at the bottom of the density column if it is the least dense
Answer:
I guess that the bottom part that is colored red represents the base of the container and not the actual red liquid.
Always, the densest materials/substances will go to the bottom.
One could see different things if, for example, when one of the elements changes state it becomes more or less dense (an example is the water, which has a solid phase, the ice, less dense than the liquid phase, and you can see that solid water usually floats on liquid water)
But in the text there is nothing about possible changes in temperature or changes in phase, then that option can be discarded.
The only option that makes sense is that the red part at the bottom represents the base of the column.
The higher an object is raised compared to the ground
Question 5 options:
the less potential energy it has.
the more potential energy it has.
the less kinetic energy it has.
the more kinetic energy it has.
Answer:
B. The more potential energy it has.
Explanation:
I majored in Physics
What is the average reaction time of people
Answer:
the average reaction time is 0.25 seconds.
7. A beam of light converges at a point P. Now a lens is placed in the path of the convergent
beam 12cm from P. At what point does the beam converges if the lens is a) a convex lens of
focal length 20cm and b) a concave lens of focal length 16cm.
Answer:
Lens at a distance = 7.5 cm
Lens at a distance = 6.86 cm (Approx)
Explanation:
Given:
Object distance u = 12 cm
a) Focal length = 20 cm
b) Focal length = 16 cm
Computation:
a. 1/v = 1/u + 1/f
1/v = 1/20 + 1/12
v = 7.5 cm
Lens at a distance = 7.5 cm
b. 1/v = 1/u + 1/f
1/v = 1/16 + 1/12
v = 6.86 cm (Approx)
Lens at a distance = 6.86 cm (Approx)
A child swings a tennis ball attached to a 0.626-m string in a horizontal circle above his head at a rate of 4.50 rev/s.
a. What is the centripetal acceleration of the tennis ball?
b. The child now increases the length of the string to 1.00m but has to decrease the rate of rotation to 4.00 rev/s. Is the speed of the ball greater now or when the string was shorter?
c. What is the centripetal accleration of the tennis ball when the string is 1.00 m in length?
Explanation:
Length of a string, l = 0.626 m
A tennis ball revolves in a horizontal circle above his head at a rate of 4.50 rev/s.
(a) The centripetal acceleration of the tennis ball is given by :
[tex]a=\omega^2r\\\\a=(4.5\times 2\pi)^2\times 0.626\\\\=500.44\ m/s^2[/tex]
(b) When r = 0.626 m and ω = 4.50 rev/s
Speed,
[tex]v=r\omega\\\\=0.626\times 4.50 \times 2\pi\\\\=17.69\ m/s[/tex]
When r = 1 m and ω = 4 rev/s
Speed,
[tex]v=r\omega\\\\=1\times 4 \times 2\pi\\\\=25.13\ m/s[/tex]
Speed is more in second case when child now increases the length of the string to 1.00m but has to decrease the rate of rotation to 4.00 rev/s.
(c) [tex]a=\omega^2r\\\\a=(4\times 2\pi)^2\times 1\\\\=631.65\ m/s^2[/tex]
Hence, this is the required solution.
A 2000 kg car moving at 100 km/h crosses the top of a hill with a radius of curvature of 100 m. What is the normal force exerted by the seat on the driver if the mass of the driver is 60 kg?
Answer:
The normal force the seat exerted on the driver is 125 N.
Explanation:
Given;
mass of the car, m = 2000 kg
speed of the car, u = 100 km/h = 27.78 m/s
radius of curvature of the hill, r = 100 m
mass of the driver, = 60 kg
The centripetal force of the driver at top of the hill is given as;
[tex]F_c = F_g - F_N[/tex]
where;
Fc is the centripetal force
[tex]F_g[/tex] is downward force due to weight of the driver
[tex]F_N[/tex] is upward or normal force on the drive
[tex]F_N = F_g-F_c\\\\F_N = mg - \frac{mv^2}{r} \\\\F_N = (60 \times 9.8) -\frac{60 \ \times \ 27.78^2 \ }{100} \\\\F_N = 588 \ N - 463 \ N\\\\F_N = 125 \ N[/tex]
Therefore, the normal force the seat exerted on the driver is 125 N.
The normal force exerted by the seat on the driver if the mass of the driver is 60 kg is of 125 N.
Given data:
The mass of car is, m' = 2000 kg.
The speed of car is, v = 100 km/h = 100 × 5/18 = 27.77 m/s.
The radius of curvature of path is, r = 100 m.
The mass of driver is, m = 60 kg.
In this case, the normal force on the driver is equal to the difference between weight of the driver and the centripetal force on the driver. Then the expression is given as,
[tex]N'= W - F\\\\N '= mg-\dfrac{mv^{2}}{r}[/tex]
Solving as,
[tex]N' = (60 \times 9.8)-\dfrac{60 \times 27.77^{2}}{100}\\\\N' = 125\;\rm N[/tex]
Thus, we can conclude that the normal force exerted by the seat on the driver if the mass of the driver is 60 kg is of 125 N.
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One of the waste products of a nuclear reactor is plutonium-239 . This nucleus is radioactive and decays by splitting into a helium-4 nucleus and a uranium-235 nucleus , the latter of which is also radioactive and will itself decay some time later. The energy emitted in the plutonium decay is and is entirely converted to kinetic energy of the helium and uranium nuclei. The mass of the helium nucleus is , while that of the uranium is (note that the ratio of the masses is 4 to 235).
(a) Calculate the velocities of the two nuclei, assuming the plutonium nucleus is originally at rest.
(b) How much kinetic energy does each nucleus carry away
Answer:
a) [tex] v_{U-235} = 2.68 \cdot 10^{5} m/s [/tex]
[tex]v_{He-4} = -1.57 \cdot 10^{7} m/s[/tex]
b) [tex] E_{He-4} = 8.23 \cdot 10^{-13} J [/tex]
[tex] E_{U-235} = 1.41 \cdot 10^{-14} J [/tex]
Explanation:
Searching the missed information we have:
E: is the energy emitted in the plutonium decay = 8.40x10⁻¹³ J
m(⁴He): is the mass of the helium nucleus = 6.68x10⁻²⁷ kg
m(²³⁵U): is the mass of the helium U-235 nucleus = 3.92x10⁻²⁵ kg
a) We can find the velocities of the two nuclei by conservation of linear momentum and kinetic energy:
Linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{Pu-239}v_{Pu-239} = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} [/tex]
Since the plutonium nucleus is originally at rest, [tex]v_{Pu-239} = 0[/tex]:
[tex] 0 = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} [/tex]
[tex] v_{He-4} = -\frac{m_{U-235}v_{U-235}}{m_{He-4}} [/tex] (1)
Kinetic Energy:
[tex] E_{Pu-239} = \frac{1}{2}m_{He-4}v_{He-4}^{2} + \frac{1}{2}m_{U-235}v_{U-235}^{2} [/tex]
[tex] 2*8.40 \cdot 10^{-13} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} [/tex]
[tex] 1.68\cdot 10^{-12} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} [/tex] (2)
By entering equation (1) into (2) we have:
[tex] 1.68\cdot 10^{-12} J = m_{He-4}(-\frac{m_{U-235}v_{U-235}}{m_{He-4}})^{2} + m_{U-235}v_{U-235}^{2} [/tex]
[tex] 1.68\cdot 10^{-12} J = 6.68 \cdot 10^{-27} kg*(-\frac{3.92 \cdot 10^{-25} kg*v_{U-235}}{6.68 \cdot 10^{-27} kg})^{2} +3.92 \cdot 10^{-25} kg*v_{U-235}^{2} [/tex]
Solving the above equation for [tex]v_{U-235}[/tex] we have:
[tex] v_{U-235} = 2.68 \cdot 10^{5} m/s [/tex]
And by entering that value into equation (1):
[tex]v_{He-4} = -\frac{3.92 \cdot 10^{-25} kg*2.68 \cdot 10^{5} m/s}{6.68 \cdot 10^{-27} kg} = -1.57 \cdot 10^{7} m/s[/tex]
The minus sign means that the helium-4 nucleus is moving in the opposite direction to the uranium-235 nucleus.
b) Now, the kinetic energy of each nucleus is:
For He-4:
[tex]E_{He-4} = \frac{1}{2}m_{He-4}v_{He-4}^{2} = \frac{1}{2} 6.68 \cdot 10^{-27} kg*(-1.57 \cdot 10^{7} m/s)^{2} = 8.23 \cdot 10^{-13} J[/tex]
For U-235:
[tex] E_{U-235} = \frac{1}{2}m_{U-235}v_{U-235}^{2} = \frac{1}{2} 3.92 \cdot 10^{-25} kg*(2.68 \cdot 10^{5} m/s)^{2} = 1.41 \cdot 10^{-14} J [/tex]
I hope it helps you!
A tennis ball is hit with a vertical speed of 10 m/s and a horizontal speed of 30 m/s. How far will the ball travel horizontally before landing?
a. 10 m
b. 20 m
c. 40 m
d. 60 m
e. 80 m
Answer:
D) 60 m
Explanation:
We can use the constant acceleration equation that contains displacement, initial velocity, acceleration, and time. We want to solve for the time that the ball was in the air first.
Δx = v_i * t + 1/2at²Let's use this equation in terms of the y-direction.
Δx_y = (v_i)y * t + 1/2a_y * t²The vertical displacement will be 0 meters since the ball will be on the floor. The initial vertical velocity is 10 m/s, the vertical acceleration is g = 10 m/s², and we are going to solve for time t.
Let's set the upwards direction to be positive and the downwards direction to be negative. We must use -g to be consistent with our other values.
Plug the known values into the equation.
0 m = 10 m/s * t + 1/2(-10 m/s²) * t²Simplify the equation.
0 = -10t + 5t² 0 = 5t² - 10tFactor the equation.
0 = 5t(t - 2)Solve for t by setting both factors to 0.
5t = 0t - 2 = 0We get t = 0, t = 2. We must use t = 2 seconds because it is the only value for t that makes sense in the problem.
Now that we have the time that the ball was in the air, we can use the same constant acceleration equation to determine the horizontal displacement of the tennis ball. We will use this equation in terms of the x-direction:
Δx = v_i * t + 1/2at² Δx_x = (v_i)x * t + 1/2a_x * t²Plug the known values into the equation.
Δx_x = 30 m/s * 2 sec + 1/2(0 m/s²) * (2 sec)²We can eliminate the right side of the equation since anything multiplied by 0 outputs 0.
Δx_x = 30 * 2 Δx_x = 60The horizontal displacement of the ball is 60 meters. Therefore, the answer is D) 60 m.
The cars in a soapbox derby have no engines; they simply coast downhill. Which of the following design criteria is best from a competitive point of view? a. The car's wheels should b. have large moments of inertia be massive c. be hoop-like wheels rather than solid disks d. have small moments of inertia
Complete question is;
The cars in a soapbox derby have no engines; they simply coast downhill. Which of the following design criteria is best from a competitive point of view?
The car's wheels should;
A. have large moments of inertia
B. be massive
C. be hoop-like wheels rather than solid disks
D. have small moments of inertia
Answer:
D. The car's wheels should have small moments of inertia
Explanation:
They are simply cast downhill due to no engine and thus the solid wheels will have very small moments of inertia and will therefore accelerate at a faster rate.
Looking at the options, the correct one that corresponds to the description I just made is Option D.
The car's wheels should have small moments of inertia.
What is Inertia?This is defined as the resistance of any physical object to a change in its velocity.
We told they were cast downhill due to no engine and the solid wheels having very small moments of inertia causing increase in acceleration depicts option D which was why it was chosen.
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The two sleds shown below are about to collide. If they stick together in the collision, what will happen after the collision? (In this collision, there is no friction
between the sleds and the snow.)
A. The two sleds will move to the left.
O B. The two sleds will move to the right
O C. The two sleds will be motionless in the middle.
O D. There is not enough information to know which sled will be pushed backward,
om
Answer:
B. The two sleds will move to the right.
Explanation:
I majored in physics
Answer:
b
Explanation:
a fisherman moves from one end of a boat to another
Answer:
That isnt a question so no one will know the answer to what you are talking about. I suggest adding a sceenshot or picture of the question.
To travel at a constant speed,a car engine provides 24 KW of useful powers. The driving force on the car is 600N.AT what speed does it travel? A 2.5 B 4.0 C.25 D 40
Answer: D. 40
Explanation:
Power = Force * Velocity
Force = 600N
Power needs to be converted to Watts:
= 24 * 1,000
= 24,000 W
24,000 = 600 * Velocity
Velocity = 24,000/600
= 40 m/s
Prove that the vectors A = 2i - 3j + k and B = i+ j+ k are
mùtually perpendicular
Answer:
theta = 90°
Explanation:
hope it's helpful
Explanation:
A • B = (2i - 3j + k) • (i + j + k)
= (2)(1) + (- 3)(1) + (1)(1)
= 0 = AB cos θ
∴ cos θ = 0 (as A ≠ 0,B ≠ 0)
or θ = 90°
or the vectors A and B are mutually perpendicular.
-TheUnknownScientist
What is the formula to finding your target heart rate.
An object with a mass of 32 kg has an initial energy of 500 J. At the end of the experiment, the velocity of the object is recorded as 5.1 m/s. If the object travelled 50 m to get to this point, what was the average force of friction on object during the trip? Assume no potential energy. Show all work