D
Question 3
1 pts
In olden times, apothecaries used to dispense medicine using their own system of measurements
that are listed below. Use these conversions to determine how many milligrams would be in a
sample of 1.250 scruples.
1 apothecary pound = 12 ounces
1 ounce = 8 drams
3 scruples = 1 dram
1.2153 apothecary pound = 1 English pound
1 kg = 2.205 English pounds
Enter your answer to the correct number of significant digits. Do not include the units.

Answers

Answer 1

Changing 1.250 scruples to milligrams.

To convert from a unit to another, First write the conversion guide

then cross multiply in such a way that the  unit  both top and bottom

cancel out each other together with dividing or multiplying  the values associated with them.

To get to the answer we have to wor it out step by step.

First step

3 scruples = 1 dram

1.250 scruples=

= [tex]\frac{1.250 scruples x 1 dram}{3scruples}[/tex] = 0.41667dram

2nd step

8 drams=1 ounce

0.41667drams   =

[tex]\frac{0.41667drams x 1}{8 drams }[/tex]  =0.05208 ounces

3rd step

1 apothecary pound = 12 ounces

?apothecary pound =0.05208 ounces

[tex]\frac{0.05208 ounces x 1apothecary pound }{12 ounces}[/tex] =0.00434 apothecary pound

4th step

1.2153 apothecary pound = 1 English pound

0.00434 apothecary pound =

[tex]\frac{0.00434 apothecary pound x 1 English pound}{1.2153 apothecary pound }[/tex] 

==0.003571 English pound

5th step

1 kg = 2.205 English pounds

 ??kg      =0.003571 English pound

[tex]\frac{0.003571 English pound x 1kg }{2.205 English pounds}[/tex]

=0.00161950kg

6th step

1kg =0.00161950kg

0.00161950kg=

[tex]\frac{0.00161950kg x 0.00161950kg}{1kg}[/tex]

=1,619.50mg

Therefore, 1.250 scruples=1,619.50mg

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It is d hope that helps!!

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its d

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Answers

Answer:

Explanation:

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Totally correct, including the balance numbers, would be

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I hope this helps

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watch u know bout rolling down in the deep...

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the one who gets its correct will be marked as the brainliest and also be followed by me!!

P.S. have a great Sunday :)​

Answers

Answer:

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Hey there!

I believe your answer would be "Air trapped between the layers of newspaper is a bad conductor of heat."

Hope this helps!

Have a great day!

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Answers

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

By electroplating

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Answers

Answer:

an oxygen atom with 8 electrons, 8 protons and 9 neutrons

An atom is called as neutral when the number of electron is equal to number of proton . Thus option C is correct.  

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Atom is the smallest unit of an element which can not be seen in with your bare eyes, due to its wavelength.

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Answers

Answer:B

Explanation:

Answer:

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Answers

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The law of Multiple proportion states that when two elements combine to form more than one compound, the mass of the second element, which combines with a fixed mass of the first element, will always be ratios of small whole numbers.

To illustrate the law of multiple proportion from sulphur and oxygen, we use the given compounds.

The reaction of oxygen with sulphur to form SO₂ and SO₃:

[tex]S \ + \ O_2 \ -----> SO_2\\\\2SO_2 \ + \ O_2 \ ---> \ 2SO_3[/tex]

atomic mass of oxygen = 16 g

atomic mass of sulphur = 32 g

In the formation of SO₂:

mass of sulphur = 32 g and mass of oxygen = (2x16) = 32 g

In the formation of SO₃:

mass of sulphur = 32 g and mass of oxygen = (3 x 16) = 48 g

Notice, while mass of sulphur is constant, mass of oxygen changed.

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explain the concept of dihyric alcohols​

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Answer:

An alcohol that contains two hydroxyl groups

3. Based on the following balanced equation:
2 C H20 + 13 02 8 CO2 + 10 H2O
a. How many moles of O2 are required to react completely with 4.00 moles of C4H10?
3.00 6.00 8.00 10.00 13.00 16.00 20,00 23,00 26.00
b. How many moles of CO2 are produced after complete reaction of 4.00 moles of C H10?
3.00 6.00 8.00 10.00 13,00 16.00 20.00 23.00 26.00
c. How many moles of H2O are produced after complete reaction of 4.00 moles of C&H10?
3.00 6.00 8.00 10.00 13.00 1.6.00 20.00 23,00 26.00

Answers

Answer:

A. 26 moles O2

B. 16 moles CO2

C. 20 moles H20

Explanation:

a. 4 moles C4H10 x [tex]\frac{13 moles O2}{2 moles C4H10}[/tex] = 26 moles O2

B. 4 moles C4H10 x [tex]\frac{8 moles CO2}{2 moles C4H10}[/tex] = 16 moles CO2

C. 4 moles C4H10 x [tex]\frac{10 moles H2O}{2 moles C4H10}[/tex] = 20 moles H20

Use the coefficients of the balanced equation to make the convertions

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