Danielle was completing her science project and mixed saline solutions A and B. Brand A was a six gallon 18% saline solution and she ended up with an 18 gallon 8% saline solution mixture. Find the percent of saline solution in brand B.
A. 2.1%
B. 21%
C. 3%

Answers

Answer 1

The percentage of saline solution in brand B is 3%. Then the correct option is C.

Let x be the percent of saline solution in brand B.

Since Danielle combined brands A and B to create a total of 18 gallons of 8% saline solution, we know that the total volume of saline solution in the combination is 18% of 6 gallons + x% of (18 - 6) gallons.

Thus, we can set up the equation:

0.18(6) + 0.01x(18 - 6) = 0.08(18)

Simplifying and solving for x, we get:

1.08 + 0.12x = 1.44

0.12x = 0.36

x = 3

Therefore, the percentage of saline solution in brand B is 3%.

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Related Questions

The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.0700% by weight. A 24.0 g sample of this fertilizer is dissolved in 2.00 L of solution.

Answers

The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.0700% by weight. A 24.0 g sample of this fertilizer is dissolved in 2.00 L of solution. Number of moles of copper ions available in the solution is 8.77×10⁻⁵mole.

In chemistry, a mole, usually spelt mol, is a common scientific measurement unit for significant amounts of very small objects like atoms, molecules, and other predetermined particles. The mole designates 6.02214076 1023 units, which is a very large number. In this the Worldwide System of Units (SI), the mole is defined as this number as of May 20, 2019, per the decisions of the General Conference upon Measurements and Weights. Amount of copper sulfate available in  24.0  grams of the sample =

0.07/100× 24.0 =0.014g

number of moles of copper sulfate=0.014/159.6=8.77×10⁻⁵

Number of moles of copper ions available in the solution=8.77×10⁻⁵mole

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A magician performs in a hall that has a seating capacity of 1,000 spectators. With ticket prices set at $47, average attendance has been 640 spectators. A marketing survey shows that for each dollar the ticket price is lowered, the average attendance increases by 20. Find the price that maximizes revenue from ticket sales.

Answers

The price that maximizes revenue from ticket sales is  $ 11, 445.

We have,

Ticket price = $47

Let x the decreasing number of the ticket price.

So, The revenue is

R =  ticket price x numbers of spectator

R(x) =  ( 47 - x )  ( 640 + 20x)

= 30,800 + 940x - 640x -20x²

= -20x² + 300x + 30,800

Now, Taking derivatives on both sides

R'(x) = -40x + 300

and, R'(x) = 0

-40x = -300

x = 7.5

So, the price per ticket is

= 47- 7.5

= $ 39.5

and, R(max) = -20(39.5)² + 300(39.5) + 30,800

R(max) = -31205 + 42650

R(max) = $ 11, 445

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Answer:

$39.50

Step-by-step explanation:

What degree of rotation about the origin will cause the triangle below to map
onto itself?
B
-8 -6
C
8
6
MO
2
-2-
T
-6-
-8
6 8

Answers

Answer: 6 feet and 2 yards are the same distance because each yard is 3 feet

Step-by-step explanation:

what is 2.00x + 1.50y =

Answers

The expression What is 2.00x + 1.50y = cannot be added/evaluated because 2.00x and 1.50y are not like terms

Evaluating the expression

From the question, we have the following parameters that can be used in our computation:

What is 2.00x + 1.50y =

The above statement is an addition expression that adds the values of 2.00x and 1.50y

However, the terms of the expression are not like terms

i.e. 2.00x and 1.50y are not like terms

This means that the expression cannot be added/evaluated

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Two number cubes who’s sides are numbered 1 through 6 are rolled on a table. the two numbers showing are added. if you repeat this process 300 times, how many times would you expect the two cubes to add to exactly 7?

Answers

Answer:

When rolling two number cubes, the possible outcomes of the sum of the numbers on the top faces are from 2 (1+1) to 12 (6+6). Since we want to know how many times we can expect the sum to be 7, we need to count the number of ways to get a sum of 7.

The pairs of numbers that add up to 7 are: (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1). So, there are 6 ways to get a sum of 7.

Each time we roll the two number cubes, the probability of getting a sum of 7 is 6/36 or 1/6, since there are 6 possible outcomes that result in a sum of 7 out of a total of 36 possible outcomes.

Therefore, if we repeat this process 300 times, we can expect to get a sum of 7 approximately (1/6) x 300 = 50 times.

So we can expect the two cubes to add to exactly 7 about 50 times when rolled 300 times.

Step-by-step explanation:

Question 22
The sum of two numbers is 107. The difference of the two numbers is 53. What are the two
numbers.
Let z be the larger number and y be the smaller number.
Write an equation that expresses the information in the sentence "The sum of two numbers is 107."
Write an equation that expresses the information in the sentence "The difference of the two
numbers is 53."
Solve the system you have written above.
The larger number, a is
> Next Question
The smaller number, y is

Answers

The requried larger number x is 80 and the smaller number y is 27.

Let's use the given variables:

x be the larger number

y be the smaller number

According to question

The sum of two numbers is 107 is represented by x + y = 107

The difference between the two numbers is 53 is represented by x - y = 53.

Solving the system of equations:

(x + y) + (z - y) = 107 + 53

2x = 160

x = 80

Now, z = 80, substitute this value into one of the original equations to solve for y.

x + y = 107

80 + y = 107

y = 27

Therefore, the requried larger number x is 80 and the smaller number y is 27.

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x and y are both differentiable functions of t x^2 + 3xy − y^2=9

Find dy/dt when x = 2 given dx/dt = −1

Answers

The value of dy/dt is 4/3.

We have,

x² + 3xy - y² = 9

Now differentiating above equation w r t to 't' we get

d/dt x² + d/dt (3xy) - d/dt (-y²) = 0

d/dx (x²) . dx/dt + 3 dx/dt.  dy/dt - 2y dy dt = 0

2x (-1) + 3(-1) dy/dt - 2y dy/dt = 0

dy/dt(-3 -2y)= -4

dy/dt = -4/(-3)

dy/dt = 4/3

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824.377 the 7 in the thousandth place is the value of the 7 in the hundredth place.

Answers

This statement is false because , the value of the 7 in the hundredth place is greater than the value of the 7 in the thousandth place.

How to determine the value of the 7 in the thousandth place equals the value of the 7 in the hundredth place.

Each digit in a number has a particular place value dependent on its position in the decimal number system. The digits in the number 824.377 have the following place values:

The 7 in the hundredth position has a value of 7/100, or 0.07. This is because the digit 7 is in the hundredth position, which is in the second position to the right of the decimal point.

The value of the 7 in the thousandth place is 7/1000, or 0.007. This is due to the fact that the digit 7 is in the third place to the right of the decimal point

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I need some assistance with this ?

Answers

The missing side using the Pythagorean theorem is 10.2.

We have,

We see that,

Hypotenuse = 13

Base = x (say)

Height = 8

Now,

Applying the Pythagorean theorem,

Hypotenuse² = Base² + Height²

Substituting,

13² = x² + 8²

13² = 169

8² = 64

So,

169 = x² + 64

x² = 169 - 64

x² = 105

x = √105

x = 10.24

x = 10.2

Thus,

The missing side is 10.2.

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Ezekiel spends t hours each night on his homework and 1/4
of this time studying math. Which equation represents the number of hours, h, Ezekiel will spend doing math homework during the next 5 days?

a. h = 5/4t

b. h = t/20

c. h = 20/t

d. h = 5t/4

Answers

The equation that represents number of hours "h" which Ezekiel spend doing "math-homework" during the next 5 days is (d) h = 5t/4.

If Ezekiel spends 1/4 of his time on math homework, then he spends 3/4 of his time on other subjects. This means that out of every 4 hours he spends on homework, he spends 1 hour on math and 3 hours on other subjects.

So, in "t" hours, he will spend "t/4" hours on math homework.

To find the number of hours he will spend on math homework during the next 5 days, we multiply the time he spends on math homework in one day by the number of days.

⇒ Number of hours spent on math homework in 1 day = t/4,

⇒ Number of hours spent on math homework in 5 days = 5 × (t/4) = 5t/4,

The required equation is h = 5t/4,

Therefore, the correct option is (d).

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ASTU ASGF Find the missing length. 2 U F 270 75 Type only your number answer. S 65 ? G T​

Answers

The value for the missing length ST of the similar to triangle ∆STU is equal to 234

What are similar triangles

Similar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.

Given that the triangle ∆STU is similar to the triangle ∆SGF, then SF correspond to SU, and SG correspond to ST. So;

SF/SU = SG/ST

75/270 = 65/ST

ST = (65 × 270)/75

ST = 13 × 18

ST = 234

Therefore, the value for the missing length ST of the similar to triangle ∆STU is equal to 234

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prove that 1^3+2^3+3^3+...+n^3=(1+2+3+...+n)^2 by mathematical induction

Answers

To prove that 1^3 + 2^3 + 3^3 + ... + n^3 = (1 + 2 + 3 + ... + n)^2 by mathematical induction, we need to show that the equation holds for the base case (n=1) and then prove that if it holds for n=k, it also holds for n=k+1.

Base case: n = 1
1^3 = (1)^2

This is true, so the equation holds for the base case.

Assume the equation holds for n=k:
1^3 + 2^3 + 3^3 + ... + k^3 = (1 + 2 + 3 + ... + k)^2

We want to prove that the equation holds for n=k+1:
1^3 + 2^3 + 3^3 + ... + (k+1)^3 = (1 + 2 + 3 + ... + (k+1))^2

We can rewrite the left side of the equation as:
1^3 + 2^3 + 3^3 + ... + k^3 + (k+1)^3

Using the assumption for n=k, we can substitute (1 + 2 + 3 + ... + k)^2 for 1^3 + 2^3 + 3^3 + ... + k^3:
(1 + 2 + 3 + ... + k)^2 + (k+1)^3

Expanding the square on the left side, we get:
(1^2 + 2^2 + 3^2 + ... + k^2) + 2(1×2 + 1×3 + ... + (k-1)×k) + (k+1)^3

We can simplify the middle term using the formula for the sum of the first k integers:
1^2 + 2^2 + 3^2 + ... + k^2 = k(k+1)(2k+1)/6
1×2 + 1×3 + ... + (k-1)×k = k(k+1)/2

Substituting these values, we get:
k(k+1)(2k+1)/6 + k(k+1) + (k+1)^3

Simplifying the expression, we get:
(k+1)(k^2 + 3k + 3)/3

Using the formula for the sum of the first k+1 integers, we can rewrite the right side of the equation as:
(1 + 2 + 3 + ... + k + (k+1))^2

Simplifying the expression, we get:
(k+1)(k+2)(2k+3)/6

Now we can see that the left side of the equation is equal to the right side of the equation, so the equation holds for n=k+1.

Therefore, by mathematical induction, the equation 1^3 + 2^3 + 3^3 + ... + n^3 = (1 + 2 + 3 + ... + n)^2 is true for all positive integers n.

A bowl of raffle tickets contains the numbers 1 through 70. What is the probability that a randomly selected ticket will be a number that is not a multiple of 9?

Answers

The probability that a randomly selected ticket will be a number that is not a multiple of 9 is 0.9.

To find the probability that a randomly selected ticket will not be a multiple of 9, we need to find the total number of tickets that are not multiples of 9 and divide it by the total number of tickets in the bowl.

There are 7 multiples of 9 between 1 and 70, namely 9, 18, 27, 36, 45, 54, and 63. Therefore, there are 70 - 7 = 63 tickets that are not multiples of 9.

So, the probability that a randomly selected ticket will not be a multiple of 9 is:

P(not multiple of 9) = 63/70

This can also be written as a decimal or percentage:

P(not multiple of 9) ≈ 0.9 or P(not multiple of 9) ≈ 90%

Therefore, there is a high probability that a randomly selected ticket will not be a multiple of 9.

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Amanda graphed the equation 10x + 5y = 20

Answers

For a unique solution is: [tex]\frac{10}{a}\neq \frac{5}{b}[/tex]

For an infinitely many solution is: [tex]\frac{10}{a}= \frac{5}{b}=\frac{-20}{c}[/tex]

What is a linear equation?

An equation of the form ax+by+c=0 is called a linear equation where a, b, c∈R

We have the linear equation is:

10x + 5y = 20

Now, we have to find the unique solution and infinitely many solution:

Firstly, For a unique solution, we need an equation ax+by+c=0 such that

[tex]\frac{10}{a}\neq \frac{5}{b}[/tex]

Now, For an infinitely many solutions, we need an equation ax+by+c=0 such that:

[tex]\frac{10}{a}= \frac{5}{b}=\frac{-20}{c}[/tex]

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For, complete question, to see the attachment.

ction 10.1 HW
O Points: 0 of 1
The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. What parameter is being tested?
H₂o = 9
H₁ o<9
What type of test is being conducted in this problem?
Right-tailed test
Two-tailed test
O Left-tailed test
w an example
Get more help -
Part 1 of 2
Clear all
Final ch

Answers

The hypothesis test is left-tailed, and we are testing the population standard deviation.

If a hypothesis test has an equal hypothesis versus a not equal hypothesis, then it is a two-tailed test.

If it has an equal hypothesis versus a less than hypothesis, then it is a left-tailed test.

Finally, if it has an equal hypothesis versus a greater than hypothesis, then it is a right-tailed test.

This is an equal hypothesis versus a 'less than', so this is left-tailed.

Recall that is the population mean, a is the population standard deviation, and p is a population proportion.

Since the hypotheses refer to σ we are testing the population standard deviation.

Hence, the hypothesis test is left-tailed, and we are testing the population standard deviation.

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A wheel has 5 equally sized slices numbered from 1 to 5.
Some are grey and some are white.
The slice numbered 1 is grey.
The slices numbered 2, 3, 4, and 5 are white.
The wheel is spun and stops on a slice at random.
Let X' be the event that the wheel stops on a white slice, and let P(X) be the
probability of X
Let not X' be the event that the wheel stops on a slice that is not white, and let
P (not X) be the probability of not X.
Event
X
not X
(a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter
the probability of the event.
(b) Subtract.
Outcomes
12345
0
0
O
1- P(not X) -
0
O
O
Probability
00000 P(not X) -
P(X) -
010
8
X
(c) Select the answer that makes the sentence true.
1-P (not X) is the same as (Choose one)
8
X
5 1
X
4
3
2

Answers

The random probability of event X, wheel stopping on a white slice is 0.9 while the probability of not X, wheel stopping on Grey slice is 0.1

What is the explanation for this?

Total numbers on wheel = total possible outcomes

= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Grey colored portion = {3}

White colored portion = {1, 2, 4, 5, 6, 7, 8, 9, 10}

X = Event that wheel stops on a white slice

P(X) = number of white slices ÷ total number of slices

P(X) = 9 / 10 = 0.9

P(not X) = 1 - P(X)

P(not X) = 1 - 0.9 = 0.1

Hence the probability that wheel stops on a white slice is 0.9 while, the probability that wheel does not stop on a white slice is 0.1

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The question is below.

Answers

The formula for the volume of a rectangular prism is:

V = l x w x h

where V is the volume, l is the length, w is the width, and h is the height.

We know that the volume of Caleigh's jewelry box is 14 cubic inches, and the area of the base is 7 square inches. Since the base of the box is a rectangle, we can use the formula for the area of a rectangle to find the length and width of the base:

A = l x w

7 = l x w

We don't know the exact values of l and w, but we do know that their product is 7.

Now we can use the formula for the volume of a rectangular prism to find the height:

14 = l x w x h

We know that l x w = 7, so we can substitute 7 for l x w:

14 = 7 x h

Dividing both sides by 7 gives:

h = 2

Therefore, the height of Caleigh's jewelry box is 2 inches.

AOC and BOD are diameters of a circle, centre O.
Prove that triangle ABD and triangle DCA are congruent by RHS.

Answers

If AOC and BOD are diameters of a circle, centre O, we can prove that triangle ABD and triangle DCA are congruent by RHS.

First, we can observe that angle AOB and angle COD are both right angles since they are angles subtended by diameters of the circle.

Since AO and BO are equal radii of the circle, they have the same length. Similarly, CO and DO are equal radii of the circle and have the same length. Thus, we have:

AO = BO = CO = DO

Now, consider triangle ABD and triangle DCA. We have:

AB = DC (both are diameters of the circle, hence have the same length)

AD = AD (common side)

∠ADB = ∠CDA = 90° (both are right angles)

Therefore, by the RHS (Right Angle-Hypotenuse-Side) congruence criterion, we can conclude that triangle ABD and triangle DCA are congruent.

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Researchers were interested in whether eating fruits and vegetables impacts life expectancy. Below are the life expectancy data from people who ate a diet centered around fruits and vegetables for much of their lives and data from people who did not eat many fruits and vegetables throughout their lives. Conduct the steps of hypothesis testing on these data.

Data table: Life expectancies for people to ate fruits and vegetables vs those who did not eat fruits and vegetables.
Ate fruits and vegetables Did not eat fruits and vegetables
82 71
83 75
92 81
71 74
81 95
73

Answers

There is a statistically significant difference in life expectancy between people who ate fruits and vegetables and people who did not eat fruits and vegetables by hypothesis

State the null hypothesis and the alternative hypothesis.

The null hypothesis (H₀) is that there is no difference in life expectancy between people who ate fruits and vegetables and people who did not eat fruits and vegetables.

The alternative hypothesis (Ha) is that there is a difference in life expectancy between the two groups.

H₀: μ₁ = μ₂

Ha: μ₁ ≠ μ₂

Determine the appropriate test statistic and significance level.

Since we are comparing the means of two independent samples, we can use a two-sample t-test.

We will use a significance level of α = 0.05.

We can use a calculator or statistical software to calculate the test statistic.

t = -2.379

df = 8.98

p-value = 0.042

where t is the test statistic

The p-value is 0.042, which is less than the significance level of 0.05.

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Find the volume of the shape below. Round to the nearest tenth. Use
the pi button on the calculator.
11 mi
5 mi
Volume =
mi3

Answers

Answer:

V = π(5^2)(11) = 275π cubic miles

= 863.9 cubic miles

Given the point (8,11π/6) in polar coordinates, find the Cartesian coordinates of the point.
Select the correct answer below:


(−4√3,4)
(4√3,−4)
(4,−4√3)
(−4√3,−4)
(−4,4√3)

Answers

Answer: b

Step-by-step explanation:Remember that the Cartesian coordinates are given by the formulas

xy=rcosθ=rsinθ

We are told that r=8 and θ=11π6, so we can plug in to find that

x=rcosθ=(8)(cos11π6)=(8)(3‾√2)=4√3

Similarly, we find that

y=rsinθ=(8)(sin11π6)=(8)(−12)=−4

So the final answer is (4√3,−4).

$5,581 is invested, part at 15% and the rest at 6% . If the interest earned from the amount invested at 15% exceeds the interest earned from the amount invested at 6% by $261.54 , how much is invested at each rate? (Round to two decimal places if necessary.)

Answers

The amount invested at 15% is $2,840 and at 6% is $2,741. The interest earned from the amount invested at 15% exceeds the interest earned from the amount invested at 6% by $261.54.

Let's assume that the amount invested at 15% is x, and the amount invested at 6% is y. We know that

x + y = 5,581 (equation 1) (since the total amount invested is $5,581)

We also know that the interest earned from the amount invested at 15% exceeds the interest earned from the amount invested at 6% by $261.54. This can be expressed as

0.15x - 0.06y = 261.54 (equation 2)

(since the interest earned is equal to the amount invested multiplied by the interest rate)

Now, we can use these two equations to solve for x and y.

First, we will isolate y in equation 1

y = 5,581 - x

Next, we will substitute this expression for y into equation 2

0.15x - 0.06(5581 - x) = 261.54

Simplifying this equation gives

0.15x - 334.86 + 0.06x = 261.54

0.21x = 596.40

x = 2,840

Now that we know x, we can use equation 1 to find y

2,840 + y = 5,581

y = 2,741

Therefore, $2,840 is invested at 15%, and $2,741 is invested at 6%.

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Un trabajo puede ser realizado por 30 obreros durante 40 días. si el plazo para terminarlo es de 12 días, ¿cuántos obreros más se deben contratar?

Answers

To complete the job in 12 days, they need 100 workers.

How many works are needed?

We know that 30 workes can complete 1 job in 40 days, then if each worker works at a rate R, then we can write:

30*R*40 days = 1 job

R = (1/1200) job/day

Then if they need to complete the job in 12 days, the number N of workers needed is:

N*(1/1200)*12 = 1

N = (1200/12) = 100

100 workers are needed.

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Are the triangles similar? If so, complete the similarity statement and state how you know they are similar. Not Similar OA BST by SSS~ A BTS by SSS~ O A BTS by SAS~ OA BST by SAS~ 64 D 176 S ABCD~ B 44 121 C​

Answers

The triangle triangle ∆BCD is not similar to the triangle ∆BTS since their sides and angle does not correspond in proportion.

What are similar triangles

Similar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.

Triangle ∆BCD is not similar to the triangle ∆BTS, BT does not correspond to BC, and BS does not correspond to BD. Also, the angle m∠SBT does not correspond to m∠DBC.

Therefore, the triangle ∆BCD is not similar to the triangle ∆BTS since their sides and angle does not correspond in proportion.

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Hey can someone help with this

Answers

The company should invest in 69.06 units of labor and 67.47 units of capital to maximize production output given the budget constraint.

We have,

We want to maximize the production output

P = L^0.8 K^0.2

subject to the constraint 10L + 20K = 2700.

We can solve for K in terms of L from the constraint equation:

10L + 20K = 2700

20K = 2700 - 10L

K = (2700 - 10L) / 20

K = 135 - 0.5L

Substitute this expression for K into the production function:

P = L^0.8 K^0.2

P = L^0.8 (135 - 0.5L)^0.2

We want to maximize P with respect to L.

Taking the derivative of P with respect to L:

dP/dL = 0.8L^-0.2 (135 - 0.5L)^0.2 + 0.2L^0.8 (135 - 0.5L)^-0.8 (-0.5)

dP/dL = 0.16(135 - 0.5L)^0.2 L^-0.2 - 0.1(135 - 0.5L)^-0.8 L^0.8

Setting dP/dL equal to zero and solving for L:

[tex]0.16 (135 - 0.5L)^{0.2} L^{-0.2} - 0.1 (135 - 0.5L)^{-0.8} L^{0.8} = 0[/tex]

0.16(135 - 0.5L)^0.2 = 0.1(135 - 0.5L)^-0.8 L^1

1.6(135 - 0.5L) = (135 - 0.5L)^-0.8 L

1.6 = (135 - 0.5L)^-1.8 L^-1

1.6L = (135 - 0.5L)^1.8

1.6L = (135^1.8 - 0.5L)^1.8

1.6L = 2.24474e+15 - 4.52222e+14 L + 1.22313e+13 L^1.8

1.22313e+13 L^1.8 - 4.52222e+14 L + 2.24474e+15 - 1.6L = 0

This equation can be solved numerically using a solver or a graphing calculator.

The solution is L = 69.06 units of labor.

To find the corresponding value of K, we can use the constraint equation:

10L + 20K = 2700

20K = 2700 - 10L

K = (2700 - 10(69.06)) / 20

K = 67.47 units of capital

Therefore,

The company should invest in 69.06 units of labor and 67.47 units of capital to maximize production output given the budget constraint.

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Find the following integrals. Can anybody solve this? Thank you.

Answers

The value of the integration is -ln|sin x - cos x| - √2 ln|sin x - cos x| - √2 ln 2

We have,

∫√(2 + cos²x)/(sec x - cosec x)

We can start by simplifying the integrand by using trigonometric identities.

sec x = 1/cos x and cosec x = 1/sin x.

So,

√(2 + cos²x)/(sec x - cosec x)

= √(2 + cos²x) / [(1/cos x) - (1/sin x)]

= √(2 + cos²x) / [(sin x - cos x) / (sin x cos x)]

= √[(2 + cos²x) sin x cos x] / (sin x - cos x)

= √[2 sin x cos x + cos⁴ x] / (sin x - cos x)

= √[sin² x + cos² x + 2 sin x cos x + cos⁴ x] / (sin x - cos x)

= √[(sin x + cos² x)²] / (sin x - cos x)

= (sin x + cos² x) / |sin x - cos x|

The absolute value sign is needed because the denominator, sin x - cos x, can be negative for certain values of x.

Now we can integrate this expression:

∫√(2 + cos²x)/(sec x - cosec x) dx

= ∫(sin x + cos² x) / |sin x - cos x| dx

We can split this integral into two cases: when sin x - cos x > 0, and when sin x - cos x < 0.

Case 1:

sin x - cos x > 0 (when x is between -π/4 and π/4, or between 3π/4 and 5π/4)

In this case, we can drop the absolute value sign:

∫(sin x + cos² x) / (sin x - cos x) dx

= ∫(sin x / (sin x - cos x)) dx + ∫(cos² x / (sin x - cos x)) dx

= -ln|sin x - cos x| - ∫(1 + sin 2x) / (2sin x - 2cos x) dx

To integrate the second term, we can use the substitution u = sin x - cos x, so that du/dx = cos x + sin x and dx = du/(cos x + sin x):

∫(1 + sin 2x) / (2sin x - 2cos x) dx

= ∫(1 + 2u / √2) / (2u / √2) du

= -√2 ln|2sin x - 2cos x| - √2 ln|u| + √2 [tex]tan^{-1}[/tex] (u / √2) + C

= -√2 ln|2(sin x - cos x)| - √2 ln|sin x - cos x| + √2 [tex]tan^{-1}[/tex] [(sin x - cos x) / √2] + C

= -√2 ln|sin x - cos x| - √2 ln 2 + √2 [tex]tan^{-1}[/tex] [(sin x - cos x) / √2] + C

= -ln|sin x - cos x| - √2 ln|sin x - cos x| - √2 ln 2

Note that we have used the logarithmic identity ln(ab) = ln a + ln b and the substitution u = sin x - cos x.

Thus,

The value of the integration is -ln|sin x - cos x| - √2 ln|sin x - cos x| - √2 ln 2

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Reed wants to have a square garden plot in his backyard. He has enough compost to cover an area of 276 square feet. To the nearest tenth of a foot, how long can a side of his garden be?​

Answers

The length of the side of his garden can be16.6 ft

How long can a side of his garden be?​

From the question, we have the following parameters that can be used in our computation:

He has enough compost to cover an area of 276 square feet.

This means that

Area = 276 276 square feet.

The area of a square is calculated as

Area = Length^2

Substitute the known values in the above equation, so, we have the following representation

Length^2 = 276

Take the square root of both sides

Length = 16.6

Hence, the length is 16.6 ft

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On a given day, a greengrocer sold 81 oranges and 43 melons. Write the ratio of oranges to melons in the form 1: n. Give any decimals in your answer to 2 d.p.

Answers

Answer:

1 : 0.53

Step-by-step explanation:

On a given day, a greengrocer sold 81 oranges and 43 melons. Write the ratio of oranges to melons in the form 1: n. Give any decimals in your answer to 2 d.p.

orange = 81

melons = 43

ratio 81 : 43

divide both side by 81

1 : 0.53

pls help

Use a ruler and protractor to construct a triangle with angle measures 40 degrees, 60 degrees, and 80
degrees. If it cannot be done, explain why

Answers

Answer:

all triangle angle measures should add up to 180.  So given that,

40+60+80=180

Therefore it can be done

(-35z^4x+32z^4 x^6) divided by (-4z^3 x^5)

Answers

(-35z⁴x + 32z⁴x⁶) divided by  -4z³x⁵ gives {(35z - 32zx⁵)/ (4x⁴)} by applying simple rule of division of polynomials.

Let the given polynomial be written as,

f(z,x) = -35z⁴x + 32z⁴x⁶

g(z,x) = -4z³x⁵

Here the functions of the given polynomial are composed of two variables, namely x and z, so the functions are denotes likewise.

We can divide the polynomial f(x) by g(x) by the division method as,

[tex]\frac{f(z,x)}{g(z,x)}[/tex] = (-35z⁴x + 32z⁴x⁶) / ( -4z³x⁵)

= { (-35z⁴x)/ ( -4z³x⁵) } + {(32z⁴x⁶)/ ( -4z³x⁵)}

= [tex]\frac{35z}{4x^4}[/tex] + [tex]\frac{-8zx}{1}[/tex]

= [tex]\frac{35z - 32zx^5}{4x^4}[/tex]

or, =  {(35z - 32zx⁵)/ (4x⁴)}

Thus the required value of (-35z⁴x + 32z⁴x⁶) divided by  -4z³x⁵ is {(35z - 32zx⁵)/ (4x⁴)}

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