cual es el grado de polinomios de -8^3 xy^4



por favor me ayudan doy corona

The number of whole numbers whose square roots of a natural number from 1 to 200 will be 14

The natural number of square roots from 1 to 200 are mentioned below

1² = 1,

2² = 4,

3² = 9,

4² = 16,

5² = 25,

6² = 36,

7² = 49,

8² = 64,

9² = 81,

10² = 100,

11² = 121,

12² = 144,

13² = 169,

14² = 196

The number of whole numbers = 14

Above 14 the square will be greater than 200

All the whole numbers are natural number except zero. zero is a whole number not a natural number.

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Answer:

Locker and Phone number

Step-by-step explanation:

Gym student grouped together with no thought doesnt matter, lunch menu doesn't need order, and a classroom seating chart doesn't really matter

The volume of water the cup can hold is 25.12 inches³.

A water cup is in the shape of the cone. The diameter of the cup is 4 inches and the height is 6 inches.

Therefore, the volume of water the water cup can hold can be calculated as follows:

Hence,

volume of the cup = 1 / 3 πr²h

where

Therefore,

r = 4 / 2 = 2 inches

h = 6 inches

Therefore,

volume of the cup = 1 / 3 × 3.14 × 2²  6

volume of the cup = 1 / 3 × 3.14 × 4  × 6

volume of the cup = 75.36 / 3

volume of the cup = 25.12 inches³

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The function that can be used to find the amount in dollars a passenger has to pay to fly with `p` pieces of luggage, where `p > 2` is: `C(p) = 439 + 25(p-2)`

- The base cost of the flight is $439.

- Customers may check 2 pieces of luggage without any additional fee.

- For each additional piece of luggage beyond 2, there is a fee of $25.

- If `p` is the number of pieces of luggage checked, then the number of additional pieces of luggage beyond 2 is `p - 2`.

- Therefore, the additional fee for `p` pieces of luggage beyond the first 2 is `25(p - 2)`.

- Adding this fee to the base cost gives the total cost `C(p)`:

C(p) = base cost + additional fee for (p-2) pieces of luggage

    = 439 + 25(p-2)

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The height of the cone is 3.4cm

A cone is a shape formed by using a set of line segments or the lines which connects a common point, called the apex or vertex.

The volume of a cone is expressed as;

V = 1/3 πr²h

where πr² = base area. therefore the volume can be written as;

V = 1/3 base area × height

base area = 49cm²

height = 45.3 cm³

45 = 1/3 ×40h

135 = 40h

h = 135/40

h = 3.4cm

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To find the coordinates of point P on the line, we can solve for x and y in the equation X-7 - Y + 2 = 2 + 6 = 5. Adding 7 to both sides, we get X - Y + 2 = 12. Subtracting 2 from both sides, we get X - Y = 10. We can choose any value for x, and then solve for y using this equation. For example, if we choose x = 0, then y = -10.

So the coordinates of point P on the line could be (0, -10, z), where z is any real number.

To find a vector v parallel to the line, we can take two points on the line and find the vector between them. For example, we could use the points (0, -10, 0) and (1, -9, 0). The vector between these points is (1-0, -9-(-10), 0-0) = (1, 1, 0).

So a vector v parallel to the line is v = (1, 1, 0).
To find the coordinates of a point P on the line and a vector v parallel to the line, we first need to rewrite the given equation in a more standard form. The equation provided seems to be incorrect, but let's assume it's meant to be in the format of Ax + By = C, then we can proceed as follows:

1. Identify the normal vector of the line (A, B): Since the given equation is X - Y = 3 (combining the constants), the normal vector is (1, -1).

2. Determine the direction vector of the line, which is perpendicular to the normal vector. One possible direction vector is the one obtained by swapping the components and negating one of them, so v = (1, 1).

3. To find a point P on the line, we can choose a value for either x or y and solve for the other coordinate. Let's choose x = 0, then we have 0 - Y = 3, which gives Y = -3. Therefore, P(x, y) = (0, -3).

In summary, the point P on the line is (0, -3), and a vector v parallel to the line is (1, 1).

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(A) ∠X is the largest angle in the given triangle as the side opposite is also the largest.

An angle is formed when two straight lines or rays meet at a single terminal.

The place where two points converge is known as an angle's vertex. The name "angle" comes from the Latin word "angulus," which means "corner."

Two lines that meet at the same point or two planes that meet at the same line form a geometric figure.

The angle in degrees separates these lines or planes.

So, we know that:

The side opposite to the largest angle is also the largest side of the triangle and vica-versa.

Remembering this we can easily conclude that ∠X is the largest angle as the largest is 9 units and X is opposite of the side YZ which measures 9 units.

Therefore, (A) ∠X is the largest angle in the given triangle as the side opposite is also the largest.

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Correct question:

Which angle in AXYZ has the largest measure?

A. ∠X

B. ∠Y

C. ​∠Z

D. Cannot be determined

By applying the Consecutive Angles Theorem, Jim can confirm that the angled section for the steps is indeed a parallelogram, even without accurately proving that any two sides are parallel.

Jim building a deck with an angled section in the shape of a parallelogram. To be assured that he has an actual parallelogram, Jim can use the Consecutive Angles Theorem.

This theorem states that if the consecutive angles of a quadrilateral are supplementary (add up to 180 degrees), then the quadrilateral is a parallelogram.

To use the Consecutive Angles Theorem, Jim should follow these steps:

1. Measure the four angles of the quadrilateral he has created for the angled section of the deck.
2. Check if the consecutive angles are supplementary (i.e., the sum of each pair of consecutive angles is equal to 180 degrees).
3. If all consecutive angles are supplementary, he can be assured that the quadrilateral is a parallelogram.

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Note that in order to map A onto B, Kyle would have to dilate the given figure by a scale factor or 3.

The scale factor is a metric for figures with similar appearances but differing scales or measurements. Assume two circles appear similar but have different radii. The scale factor specifies how much larger or smaller a figure is than the original figure.

The original point of figure A which has 4 points are

(0,02)

(-1, 2)

(0, 1)

(1, 2)

Multiply all th e points by 3, and you get,

(0,02) x 3 = (0, -6) =

(-1, 2) x 3 = (-3, 6)

(0, 1) x 3 = (0, 3)

(1, 2) x3 = (3, 6)

Plotting the new values will give us the transformation (dilation) required. See the attached image.

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The difference in the shortest collection times before and after the well installation is 20 minutes, calculated by subtracting the shortest time after installation (25 minutes) from before (45 minutes), as shown in the box and whiskers plot.

This is calculated by subtracting the shortest collection time after well installation (25 minutes) from the shortest collection time before well installation (45 minutes):

45 - 25 = 20 minutes.

This can be seen in the box and whiskers plot provided, where the lowest value for each distribution is denoted by the beginning of the whiskers.

So, the difference is before and after the well installation is 20 minutes.

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--The given question is incomplete, the complete question is given

" What is the difference in minutes between the shortest collection times before and after the well was installed"--

The trignometric equation h = (32 inches) x tan(35°) can be used to solve for the height, h, of the television screen.

We can use trigonometry to solve for the height, h, of the television screen. From the given information, we can form a right triangle with the diagonal of the television screen as the hypotenuse, and the height of the screen as one of the legs.

Since we are given the angle between the diagonal and the bottom of the television, we can use the trigonometric function tangent to relate the height and the diagonal.

The equation we can use to solve for the height is:

tan(35°) = [tex]\frac{h }{ (32 inches)}[/tex]

Rearranging this equation, we get:

h = (32 inches) x tan(35°)

Therefore, the equation that can be used to solve for the height, h, of the television screen is:

h = (32 inches) x tan(35°)

So, the equation h = (32 inches) x tan(35°) can be used to solve for the height, h, of the television screen.

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To estimate the weekly profit of producing and selling 81 cars, we first need to find the current weekly profit for producing and selling 80 cars using P(80):

P(80) = -0.005(80)^(2) - 0.2(80) + 1000(80) - 1300
P(80) = $75,800

Now we need to find the marginal profit at x = 80, which is the derivative of the profit function P(x):

P'(x) = -0.01x - 0.4x + 1000

P'(80) = -0.01(80) - 0.4(80) + 1000
P'(80) = $920

The marginal profit at x = 80 is $920. This means that for each additional car produced and sold beyond 80, the profit will increase by $920.

To estimate the weekly profit of producing and selling 81 cars, we can use the approximation formula:

ΔP ≈ P'(80)Δx

where ΔP is the change in profit, Δx is the change in the number of cars produced and sold, and P'(80) is the marginal profit at x = 80.

We want to find the change in profit when the number of cars produced and sold increases from 80 to 81, so Δx = 1. Plugging in the values we have:

ΔP ≈ $920(1)
ΔP ≈ $920

This means that the estimated weekly profit for producing and selling 81 cars is:

P(81) ≈ P(80) + ΔP
P(81) ≈ $75,800 + $920
P(81) ≈ $75,720

Rounding to the nearest dollar, the answer is $75,720. So the correct option is: $75,720.

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A. The missing value for P(X = 1) is 0.20.

B.  The value of P(X ≤ 2) is 0.85.

C.  The value of P(X > 2) is 0.15.

D. The probability of "At least 2" is equivalent to P(X >= 2), which is 0.75.

In probability theory, a probability distribution is a function that assigns probabilities to each possible value of a random variable.

In this Problem, we have a probability distribution for the score on a quiz, with X being the random variable and the table providing the probability of each possible score. In this answer, we will use the given probability distribution to answer the questions posed.

A) Find the missing value for P(X = 1) in the probability distribution.

To find the missing value for P(X = 1), we need to use the fact that the sum of the probabilities for all possible values of X must be equal to 1. Therefore, we can set up an equation:

P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 1

Substituting in the given probabilities, we get:

0.05 + P(X = 1) + 0.60 + 0.15 = 1

Simplifying, we get:

P(X = 1) = 0.20

Therefore, the missing value for P(X = 1) is 0.20.

B) P(X ≤ 2) =

To find P(X ≤ 2), we need to add up the probabilities of X being less than or equal to 2. This is equivalent to:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

Substituting in the given probabilities, we get:

P(X ≤ 2) = 0.05 + 0.20 + 0.60 = 0.85

Therefore, P(X ≤ 2) is 0.85.

C) P(X > 2) =

To find P(X > 2), we need to add up the probabilities of X being greater than 2. This is equivalent to:

P(X > 2) = P(X = 3)

Substituting in the given probabilities, we get:

P(X > 2) = 0.15

Therefore, P(X > 2) is 0.15.

D) The probability of "At least 2" is equivalent to P(X >= 2)

To find the probability of "At least 2," we need to add up the probabilities of X being greater than or equal to 2. This is equivalent to:

P(X ≥ 2) = P(X = 2) + P(X = 3)

Substituting in the given probabilities, we get:

P(X ≥ 2) = 0.60 + 0.15 = 0.75

Therefore, the probability of "At least 2" is equivalent to P(X ≥ 2), which is 0.75.

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The decay of isotope at compound rate is approximately 0.0140.

To find the continuous compound rate of decay of this isotope, we can use the following formula:

Nₜ = N₀e^(-λᵗ)

Where:
Nₜ is the amount of the isotope present after time t (years),
N₀ is the initial amount of the isotope,
λ is the continuous compound rate of decay, and
t is the time in years.

In this case, 91.9% of the isotope is still present 6 years after the disaster,

so Nₜ = 0.919 * N₀, and t = 6 years.

We want to find λ, the continuous compound rate of decay.

We can rewrite the formula as follows:

0.919 * N₀ = N₀ * e^(-λ * 6)

Divide both sides by N₀:

0.919 = e^(-λ * 6)

Now, take the natural logarithm (ln) of both sides:

ln(0.919) = -λ * 6

Divide by -6 to solve for λ:

λ = ln(0.919) / (-6)

Calculate the value:

λ ≈ 0.0140

So, the continuous compound rate of decay of this particular radioactive isotope is approximately 0.0140.

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Answer:

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A linear equation is an equation of a straight line.

It describes the straight-line graph of a set of ordered pairs (x, y) that are solutions to the equation.

There are different forms of linear equations.

The slope-intercept form of a linear equation is y = mx + b.

The equation y = -2x + 10 is in slope-intercept form. Its graph is a line with slope -2 and y-intercept 10. It shows the set of all solutions to the equation.

As per description above, the correct answer choice is B, all the other options are false.

The statements are classified as follows:

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations, which is also called the cardinality of the data-set.

8 is a low outlier, hence it is a value lower than the mean, meaning that the mean increases if we remove the observation of 8.

The range of a data-set is calculated as the difference between the highest value and the lowest value in the data-set, thus if we remove the low value of 8, the next low value is of 47, meaning that the range decreases.

The ordered data-set is given as follows:

8, 47, 48, 50, 51, 51.

The data-set has an even cardinality of 6, hence the median is calculated as the mean of the two middle elements as follows:

Median = (48 + 50)/2

Median = 49.

Removing 8, the data-set is given as follows:

47, 48, 50, 51, 51.

Hence the median increases, as it will be the middle value of 50.

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Rounding to the nearest whole number, the linear speed of a point on Uranus' equator is approximately 139,424 miles/day.

(a) To find the angular speed of a point on Uranus' equator, we need to convert the rotation period from hours to days and then calculate the angle rotated in one day.

In one day (24 hours), Uranus rotates:

24 hours ÷ 17.2 hours/rotation ≈ 1.3953 rotations

The angle rotated in one day is:

1.3953 rotations × 2π radians/rotation ≈ 8.7674 radians/day

So the angular speed of a point on Uranus' equator is approximately 8.7674 radians/day.

(b) To find the linear speed of a point on Uranus' equator, we can use the formula:

linear speed = radius × angular speed

where the radius is given as 15,881 miles and the angular speed is 8.7674 radians/day (from part (a)).

Substituting these values, we get:

linear speed = 15,881 miles × 8.7674 radians/day ≈ 139,424 miles/day

Rounding to the nearest whole number, the linear speed of a point on Uranus' equator is approximately 139,424 miles/day.

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The area of the parallelogram is approximately 21.2 square feet, rounded to the nearest tenth of a square foot.

To find the area of a parallelogram, we need to multiply the base by the height. In this case, the two sides given (9.5 feet and 6.1 feet) are the base and height respectively, because they are perpendicular.

To find the area, we first need to find the length of the other two sides. Since a parallelogram has opposite sides that are equal in length, we know that the other two sides are also 9.5 feet and 6.1 feet.

Next, we can use the given angle (20°) to find the height of the parallelogram. We can use trigonometry, specifically the tangent function, to do this:

tan(20°) = height / 6.1 feet

height = 6.1 feet * tan(20°)

height ≈ 2.23 feet

Now we can find the area:

area = base * height

area = 9.5 feet * 2.23 feet

area ≈ 21.185 square feet

Rounding to the nearest tenth of a square foot, the area is approximately 21.2 square feet.

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The expression 6 * 6^(-2) is equivalent to 1/6.

We can simplify this expression using the rule of exponents that states a^m / a^n = a^(m-n), which gives:

6 * 6^(-2) = 6 / 6^2 = 6 / 36 = 1/6

Let's break down the expression and simplify it step by step:

6 * 6^(-2)

We start by evaluating the exponent, which means we take the reciprocal of 6^2:

6 * (1/6^2)

Now we simplify the denominator of the fraction:

6 * (1/36)

Finally, we can simplify the expression by dividing 6 by 36:

1/6

So, the expression 6 * 6^(-2) is equivalent to 1/6. This means that if we multiply 6 by 6 raised to the power of -2 (or 1/6^2), we get the same result as dividing 6 by 6^2 (or 36), which is  1/6.

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By using the compass a ruler and a protractor a circle having a Radius MO of 3 cm, Diameter OP of 6cm, Chord QR of 4cm, and Central angle <OMS of 60° has been Drawn.

Given data:

Radius MO = 3 cm

Diameter OP = 6cm

Chord QR = 4cm

Central angle <OMS = 60°

Steps to follow to draw the circle,

Step 1: Mark the M point as the center.

Step 2: Now take the compass and take a 3 cm reading on it by using the ruler.

Step 3: Draw the circle by using M as the center

Step 4: Mark a point O on the circle

Step 5: Draw a straight line segment OP passing through M

Step 6: Mark a point Q on the circle

Step 7: Using compass width and take a 3 cm reading on it and by taking Q as center cut the circle at R.

Step 8: Now join Q and R points.

Step 9: Using compass width and take a 3 cm reading on it and by taking O as the center cut the circle at S.

Step 10: Now join S and M points

Therefore, The circle, central angle on the circle, and chord on the circle are drawn.

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The complete question is,

1. Directions: Using a compass, ruler, and protractor, draw a circle having:

1.) M as the center

2.) radius MO of 3 cm

3.) diameter OP of 6cm

4.) chord QR of 4cm

5.) central angle:<OMS of 60°

The correct graph to display the data is: C. Bar graph with the title "favorite sport" and the x-axis labeled "sport" and the y-axis labeled....

A bar graph is an appropriate choice for displaying the data collected from the middle school students because it allows us to compare discrete categories (in this case, sports) and their corresponding frequencies (number of students).

In this case, the data is as follows:

The correct bar graph has the title "Favorite Sport" to indicate the subject of the data being represented.

The x-axis is labeled "Sport" and lists the four sports - basketball, baseball, soccer, and tennis - in separate, distinct categories. The y-axis is labeled "Number of Students" and displays the frequency or count of students who chose each sport as their favorite.

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The acute angle formed by the hands of a clock at 3:30 is 75 degrees. An acute angle is an angle that measures less than 90 degrees, and in this case, the hour hand is pointing at the 3, which is a 90-degree angle from the 12, while the minute hand is pointing at the 6, which is a 180-degree angle from the 12.

Find the number of degrees in the acute angle formed by the hands of a clock at 3:30, follow these steps:
Determine the position of the hour hand. At 3:30, the hour hand is halfway between 3 and 4, so it's at 3.5 hours. Convert this to degrees by multiplying by 30 (since there are 360 degrees in a circle and 12 hours on a clock, each hour represents 30 degrees).

So, the hour hand is at 3.5 x 30 = 105 degrees.

Determine the position of the minute hand. At 3:30, the minute hand is on 6, which is 180 degrees around the clock.
Find the difference between the two positions.

Subtract the smaller angle from the larger angle: 180 - 105 = 75 degrees.
The acute angle formed by the hands of a clock at 3:30 is 75 degrees.

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(a) To find the slope of the curve where it meets the right-hand pole, we need to differentiate the given equation with respect to x. y = 17cosh(x/17) - 12.

Using the chain rule, we get dy/dx = (17/17)sinh(x/17) = sinh(x/17). Therefore, at x = 7, the slope of the curve is sinh(7/17) ≈ 0.6968.

(b) To find the angle theta between the line and the pole, we can use trigonometry. The slope of the curve at the right-hand pole is the same as the tangent of the angle theta.

Therefore, tan(theta) = 0.6968. Taking the inverse tangent of both sides, we get theta = arctan(0.6968) ≈ 34.33 degrees. Therefore, the acute angle formed by the right pole and the hanging line is approximately 34.33 degrees.

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The area of the commune's summer-autumn rice crop is approximately 570,041.902 square meters. ( rounded to the third decimal place)

To calculate the area of the commune's summer-autumn rice crop, we need to multiply the total area of the commune by the percentage of the area used to grow rice.

First, we need to convert the area from hectares to square meters since the percentage is based on the total land area in square meters.

1 hectare = 10,000 square meters

So, 81.5 hectares = 81.5 x 10,000 = 815,000 square meters

Next, we can calculate the area of the rice crop:

57/81.5 = 0.699386503

0.699386503 x 815,000 = 570,041.902 square meters

Rounding to the third decimal place, the area of the commune's summer-autumn rice crop is approximately 570,041.902 square meters.

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Answer:

Step-by-step explanation:

explanation in image

Given two events E and F with Pr(E) = 0. 4, Pr(F) = 0. 5, and Pr(EnF) = 0. 3 then:

a) Pr(E|F) = 0.6

b) Pr(F|E) = 0.75

c) NO, E and F are not independent.

a) To find Pr(E|F), we use the formula: Pr(E|F) = Pr(EnF)/Pr(F). Substituting the given values, we get Pr(E|F) = 0.3/0.5 = 0.6.

b) Similarly, to find Pr(F|E), we use the formula: Pr(F|E) = Pr(EnF)/Pr(E). Substituting the given values, we get Pr(F|E) = 0.3/0.4 = 0.75.

c) We can check for independence by seeing if Pr(E) = Pr(E|F) or Pr(F) = Pr(F|E). However, since Pr(E) ≠ Pr(E|F) and Pr(F) ≠ Pr(F|E), we can conclude that E and F are not independent.

In other words, the occurrence of one event affects the probability of the other event occurring. Specifically, the fact that Pr(EnF) ≠ Pr(E)Pr(F) indicates that the events are dependent.

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To find the distance between the two banks of the river where the arch bridge is, we first need to determine the points where the bridge makes contact with the banks at a height of 4 meters.

We are given the parabola shape of the arch with the equation y = -0.1(x - 5)^2 + 12.

1. Set the height y equal to 4 meters:

4 = -0.1(x - 5)^2 + 12

2. Subtract 12 from both sides:

-8 = -0.1(x - 5)^2

3. Divide both sides by -0.1:

80 = (x - 5)^2

4. Take the square root of both sides:

sqrt(80) = x - 5

5. Now, we find the two x-values where the bridge contacts the banks:

x1 = sqrt(80) + 5

x2 = -sqrt(80) + 5

6. Calculate the distance between the two banks by subtracting x2 from x1:

Distance = x1 - x2 = (sqrt(80) + 5) - (-sqrt(80) + 5)

7. Simplify the expression:

Distance = 2 * sqrt(80)

8. Round your answer to the nearest whole number:

Distance ≈ 18 meters

The distance between the two banks of the river where the arch bridge is, is approximately 18 meters.

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Martin expects to wait longer than Selena. This can be Mathematically represented as: t > s

To determine who expects to wait longer, we need to compare the values on the number lines for Selena and Martin. Let's say Selena expects to wait for t minutes, and Martin expects to wait for s minutes. Looking at the number lines, we can see that Selena's expected wait time is closer to 10 minutes, while Martin's expected wait time is closer to 5 minutes. Therefore, we can say that Martin expects to wait longer than Selena.

Mathematically, we can represent this as:

t > s

This means that Selena's expected wait time is greater than Martin's expected wait time. Therefore, Martin expects to wait longer than Selena.

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Angela made $350 per week 25 years ago and Walker made $200 per week 25 years ago.

Let's assign variables to represent Angela and Walker's salaries 25 years ago. Let A be Angela's salary 25 years ago and W be Walker's salary 25 years ago.

Using the information given in the problem, we can set up two equations:

A + W = 550 (their total salary 25 years ago)
4A + 3W = 2000 (their total current salary)

To solve for A and W, we can use substitution or elimination. Let's use substitution.

From the first equation, we can rearrange to solve for A:

A = 550 - W

Substitute this into the second equation:

4(550 - W) + 3W = 2000

Distribute the 4:

2200 - 4W + 3W = 2000

Simplify:

W = 800

Now that we know Walker's salary 25 years ago was $800, we can plug that into the first equation to solve for Angela's salary:

A + 800 = 550

A = -250

Uh oh, a negative salary doesn't make sense in this context. We made a mistake somewhere.

Let's go back to our original equations and try elimination instead:

A + W = 550
4A + 3W = 2000

Multiplying the first equation by 4, we get:

4A + 4W = 2200

Subtracting the second equation from this, we get:

W = 200

Now we can plug this into either equation to solve for A:

A + 200 = 550

A = 350

So Angela made $350 per week 25 years ago and Walker made $200 per week 25 years ago.

To learn more about algebraic equation

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