Answer:
0
Step-by-step explanation:
The t-intercept here is what's khown as the x-intercept wich is given by C(t)=0
● C(t) = 2t^4-8t^3+6t^2
● 0 = 2t^4-8t^3+6t^2
Factor using t
● t(2t^3-8t^2+6t^1) = 0
Wich means that t=0
Wina drove 282 miles on 10 gallons of gas. At this same rate, how many miles could she drive on 12 gallons of gas?
Hey there! I'm happy to help!
Let's set this up a proportion (two equal ratios) to find out how many miles Wina can drive on 12 gallons gas.
[tex]\frac{miles}{gallons} =\frac{282}{10} =\frac{m}{12}[/tex]
What do we multiply the bottom 10 by to get to 12? Well, to find out, we can divide 12 by 10 below.
12÷10=1.2
This means that we multiply the numbers in the first fraction by 1.2 to have the same numerator and denominator as the second fraction.
If we multiplied our 10 b y 1.2 to get the denominator in the second fraction, we should be able to multiply 282 by 1.2 to get the numerator in the second fraction!
282×1.2=338.4
If you use 338.4 in this proportion, the ratios will be equal.
Therefore, Wina could drive 338.4 miles on 12 miles of gas at this same rate.
Have a wonderful day!
Solve for X. Pls help asap
Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{12}}}}}[/tex]
Step-by-step explanation:
hypotenuse ( h ) = x
Peendicular ( p ) = 10
base ( b ) = 22
Using the Pythagoras theorem
[tex] \boxed{ \sf{ {h}^{2} = {p}^{2} + {b}^{2} }}[/tex]
[tex] \dashrightarrow{ \sf{ {x}^{2} = {10 }^{2} + {22}^{2} }}[/tex]
[tex] \dashrightarrow{ \sf{ {x}^{2} = 100 + 44}}[/tex]
[tex] \dashrightarrow{ \sf{ {x}^{2} = 144}}[/tex]
[tex] \dashrightarrow{ \sf{ \sqrt{ {x}^{2} } = \sqrt{144}}} [/tex]
[tex] \dashrightarrow{ \sf{x = 12}}[/tex]
Hope I helped!
Best regards! :D
The current l in an electrical conductor varies inversely as the resistance R of the conductor. The current is 1/6 ampere when the resistance is 32400 ohms. What is the current when the resistance is 22500 ohms
Answer:
I=0.24ampere
Step-by-step explanation:
Assuming that the voltage is the same:
I=V/R (V- voltage, I-current, R-resistance)
1/6ampere=V/3240ohms
V=1/6*3240
= 5400v
Voltage across =V=5400v
Since the voltage is the same when the resistance is 22500ohms
I=V/R
=5400/22500
=6/25
=0.24ampere
Question 3
Which of the following best describes the solution to the system of equations below?
-6x + y=-3
7x-y=3
The system of equations has exactly one solution where x = 6 and y = 3.
The system of equations has no solution.
The system of equations has infinitely many solutions.
The system of equations has exactly one solution where x = 0 and y=
-3
Answer:
The system has exactly one solution where x = 0 and y = -3.
Step-by-step explanation:
-6x + y = -3
7x - y = 3
(7x - 6x) + (y - y) = 3 - 3
x + 0 = 0
x = 0
7(0) - y = 3
0 - y = 3
-y = 3
y = -3
-6(0) + y = -3
0 + y = -3
y = -3
So, the system has exactly one solution where x = 0 and y = -3.
Hope this helps!
What is the measure of ∠BCD?
Answer: 77 degrees
Step-by-step explanation:
interior angles on the same side of transversal are supplementary. Thus,
103+x=180
x = 77
Hope it helps <3
Answer:
Hey there!
This is a parallelogram, and we have the angles next to each other add to 180 degrees. Angle ABC+Angle BCD=180
103+x=180
x=77
BCD=77 degrees.
Let me know if this helps :)
Function f is shown on the graph below where two points are marked. If function f is horizontally compressed by a factor of 2, plot the two corresponding points that would lie on the transformed function.
Answer:
If you have
[tex]f(x) = x^2[/tex]
The point (2,4) would be transformed to (1,1)
Step-by-step explanation:
If your compression is horizontal then the transformation you are making is the following
[tex]g(x) = f(x/2)[/tex]
Therefore, if you have
[tex]f(x) = x^2[/tex]
The point (2,4) would be transformed to (1,1)
CAN I GET SOME HELP OVER HERE? Ina Crespo rowed 12 miles down the Habashabee River in 2 hours, but the return trip took her 3 hours. Find the rate Ina rows in still water and the rate of the current. Let x represent the rate Ina can row in still water and let y represent the rate of the current. Ina can row ? mph in still water
Answer: The speed of Ina in still water is 5mph
Step-by-step explanation:
If the speed of Ina on still water is x, and the speed of the river is y:
The total speed of Ina when she goes along with the current is:
S = x + y
when she goes against the current we have:
St = x - y.
Now we can use the relation:
speed = time/velocity.
along with the current, we have:
x + y = 12mi/2h = 6mi/h
against the current we have:
x - y = 12mi/3h = 4mi/h
So we have the equations
x + y = 6mi/h
x - y = 4mi/h
in the first equation we can isolate x
x = 6mi/h - y
now we replace this in the second equation:
(6mi/h - y) - y = 4mi/h
6mi/h - 2y = 4mi/h
-2*y = 4mi/h - 6mi/h = -2mi/h
y = 1mi/h
now we replace this in the first equation:
x + 1mi/h = 6mi/h
x = 5mi/h.
The speed of Ina in still water is 5mph
1. 2x-y≤-6
2. 5x+4y ≥20
Answer
2x-y <or =-6
2x<or=-6+y
divide both sides by 2
x<or=1/2y+3
5(1/2y+3)+4y>or=20
5/2y+15+4y>or=20
5/2y+4y>or=20-15
13/2y>or=5
divide both sides by 2/13
y>or=10/13
2x-10/13<or=-6
2x<or=-6+10/13
2x<or=-68/13
divide both sides by 2
x< or =-34/13
Which equation represents the function graphed
coordinate plane?
Answer:
b. y = |x+4| - 10
Step-by-step explanation:
When you see a v-shaped graph, it could very well relate to an absolute-value function.
The value of the absolute value function has the vertex at x= -4, meaning that it has a minimum value when x=-4, which means that the absolute value function is of the form |x+4| giving a zero when x= -4.
Also, the minimum of the function occurs at y = -10, meaning that the function has been translated by -10.
Therefore the function is
y = |x+4| - 10
Answer:
B
Step-by-step explanation:
EDGE unit review
What’s this? I’m stuck!
Answer:
68 degrees
Step-by-step explanation:
Y=56,
56+56=112
180-112=68
Hope this helps, if you have any other questions, feel free to ask me to explain more
Have a good day! :)
Express the following ratio in the simplest form vii) 4.5km: 450m
Answer:
4.5 ×1000 =4500m
Step-by-step explanation:
450/1000=0.45km
Answer: 10 : 1
Step-by-step explanation: Now first let’s convert this to the same units, for instance, the SI unit for length meters. 4.5 x 1000 = 4500m. Then put the ratio 4500m : 450m. You can divide 4500 by 450 as it is divisible so you get 10 as the answer.
Even if you have converted them to kilometers before, nevermind, still 4.5 divide by 0.45 is 10 and there the answer is 10 : 1 or shortly the ratio is just 10.
You and your best friend are both on the swim team. You want to beat your friend at the next swim meet so you decide to swim 151515 minutes longer than she does one day at practice. Write an equation for the number of minutes you swim, yyy, when your friend swims xxx number of minutes. Y
Answer:
yyy = xxx + 151515
Step-by-step explanation:
Since you want to swim 151515 minutes longer one day at practice (note this time is actually 105 days), you simply need to swim the same amount of time as your friend, plus the extra time. Hence, your time will be equal to your friends time plus the extra time you plan to swim.
Ashley has 500 songs in his music player. Every week he adds 10 songs to his collection. How many songs will he have in his music player after 20 weeks ?
At the end of n weeks, the number of songs is given by the function
f(n) =500 +10n
Or
f(n) = 10 +20b
The output of the function is 700
or
600
when the input is 20.
Answer:
700
Step-by-step explanation:
500+10*20=700
it's f(n) = 500+10n
Solve for x. please help me its urgent
Answer:
x = 25
Step-by-step explanation:
The sum of the angles of a quadrilateral are 360 degrees
3x+x+10 + 4x+6x = 360
Combine like terms
14x+10 = 360
Subtract 10 from each side
14x +10-10 = 360-10
14x = 350
Divide each side by 14
14x/14 = 350/14
x = 25
Find X. Please help.
Answer:
x = 18.08°Step-by-step explanation:
To find the value of x we use sine
sin ∅ = opposite / hypotenuse
From the question
29 is the hypotenuse
9 is the opposite
sin x = 9/29
x = sin-¹ 9/29
x = 18.08°
Hope this helps you
Answer:
Angle=71.9°
using the trig inverse formula sec(angle)= hypotenuse/adjacent
A pile of 55 coins consisting of nickels and dimes is worth $3.90 . Find the number of each. PLZ ANSWER IN 1 MIN
Answer:
23 dimes; 32 nickel
Step-by-step explanation:
Let n = number of nickels.
Let d = number of dimes.
A nickel is worth $0.05; n nickels are worth 0.05n.
A dime is worth $0.10; d dimes are worth 0.1d.
Number of coins:
d + n = 55
Value of the coins:
0.1d + 0.05n = 3.9
Solve d + n = 55 for d:
d = 55 - n
Substitute 55 - n for d in second equation.
0.1(55 - n) + 0.05n = 3.9
5.5 - 0.1n + 0.05n = 3.9
-0.05n = -1.6
n = 32
Substitute 32 for n in d + n = 55 and solve for d.
d + 32 = 55
d = 23
Answer: 23 dimes; 32 nickel
A bag contains balls colored in 7 different colors. What is the minimum no of balls one need to pick in order to get three balls of same color
Answer:
twenty one balls.
Step-by-step explanation:
there would be three of each colour.
Answer:
the real answer is 15
Step-by-step explanation:
A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) to complete the escape.
389 357 359 364 375 424 326 395 402 373
374 371 365 367 365 326 339 393 392 369
374 359 357 403 335 397
A normal probability plot of the n 26 observations on escape time given above shows a substantial linear pattern; the sample mean and sample standard deviation are 371.08 and 24.45, respectively. (Round your answers to two decimal places.)
Required:
a. Calculate an upper confidence bound for population mean escape time using a confidence level of 95%.
b. Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.
Answer:
The upper confidence bound for population mean escape time is: 379.27
The upper prediction bound for the escape time of a single additional worker is 413.64
Step-by-step explanation:
Given that :
sample size n = 26
sample mean [tex]\bar x[/tex] = 371.08
standard deviation [tex]\sigma[/tex] = 24.45
The objective is to calculate an upper confidence bound for population mean escape time using a confidence level of 95%
We need to determine the standard error of these given data first;
So,
Standard Error S.E = [tex]\dfrac{\sigma }{\sqrt{n}}[/tex]
Standard Error S.E = [tex]\dfrac{24.45 }{\sqrt{26}}[/tex]
Standard Error S.E = [tex]\dfrac{24.45 }{4.898979486}[/tex]
Standard Error S.E = 4.7950
However;
Degree of freedom df= n - 1
Degree of freedom df= 26 - 1
Degree of freedom df= 25
At confidence level of 95% and Degree of freedom df of 25 ;
t-value = 1.7080
Similarly;
The Margin of error = t-value × S.E
The Margin of error = 1.7080 × 4.7950
The Margin of error = 8.18986
The upper confidence bound for population mean escape time is = Sample Mean + Margin of Error
The upper confidence bound for population mean escape time is = 371.08 + 8.18986
The upper confidence bound for population mean escape time is = 379.26986 [tex]\approx[/tex] 379.27
The upper confidence bound for population mean escape time is: 379.27
b. Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.
The standard error of the mean = [tex]\sigma \times \sqrt{1+ \dfrac{1}{n}}[/tex]
The standard error of the mean = [tex]24.45 \times \sqrt{1+ \dfrac{1}{26}}[/tex]
The standard error of the mean = [tex]24.45 \times \sqrt{1+0.03846153846}[/tex]
The standard error of the mean = [tex]24.45 \times \sqrt{1.03846153846}[/tex]
The standard error of the mean = [tex]24.45 \times 1.019049331[/tex]
The standard error of the mean = 24.91575614
Recall that : At confidence level of 95% and Degree of freedom df of 25 ;
t-value = 1.7080
∴
The Margin of error = t-value × S.E
The Margin of error = 1.7080 × 24.91575614
The Margin of error = 42.55611149
The upper prediction bound for the escape time of a single additional worker is calculate by the addition of
Sample Mean + Margin of Error
= 371.08 + 42.55611149
= 413.6361115
[tex]\approx[/tex] 413.64
The upper prediction bound for the escape time of a single additional worker is 413.64
James is measuring the temperature (1) of a plate left sitting in the sun fort
hours. Which of the following is the most appropriate domain for h(0?
O A. All positive numbers
O B. Positive integers only
O C. All real numbers
O D. All integers
Answer:
O B. Positive integers only
Step-by-step explanation:
You have that the temperature of a plate is measured respect to the number of hours that the plate has been left in the sun.
In this case you have that the independent variable is the number of hours and the dependent variable is the temperature.
Due to James would like to know how is changing the temperature of the plate, per hour, the best domain for the function, that is, the best available values for the time on which the temperature of the plate is measured, are the positive integers only.
O B. Positive integers only
If the wavelength of the violet color is 400 nm, what is the value of its frequency?
Hi there! Hopefully this helps!
-------------------------------------------------------------------------------------------------- The frequency is ~7.5*1014 Hz
Since visible light has a wavelength spectrum of ~400 nm to ~700 nm, Violet light has a wavelength of ~400 nm and a frequency of ~7.5*1014 Hz.
Step-by-step explanation:
Speed = wavelength × frequency
3×10⁸ m/s = (400×10⁻⁹ m) f
f = 7.5×10¹⁴
Solve for X. pls help asap
Answer:
x=3
Step-by-step explanation:
Use the Pythagorean Theorem to write an equation.
x^2+y^2=z^2
Substitute values from the problem.
x^2 + 6^2 = 9^2
Solve for what you know.
x^2 + 36 = 81
Square root it.
x+6=9
Subtract 6 from both sides.
x=3
In the future, if you see a right triangle with an unknown side, and the other two sides are either 3, 6, or 9, you know that the other one is the missing value out of 3/6/9. This is called a 3/6/9 triangle.
Answer:
6.7Step-by-step explanation:
Hypotenuse (h) = 9
base (b) = X
Perpendicular (p) = 6
Now,
Using Pythagoras theorem:
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
[tex] {b}^{2} = {h}^{2} - {p}^{2} [/tex]
[tex] {b}^{2} = {(9)}^{2} - {(6)}^{2} [/tex]
[tex] {b}^{2} = 81 - 36[/tex]
[tex] {b}^{2} = 45[/tex]
[tex]b = \sqrt{45} [/tex]
[tex]b = 6.7[/tex]
Hope this helps...
Good luck on your assignment..
URGENT)
In the figure, ABCDE is a regular pentagon and DEFG is a square. CD
produced and GF intersect at H. Find x.
Answer:
108 degrees
Step-by-step explanation:
angle CDE is 108 degrees, which is supplementary to angle EDH, so EDH must be 72 degrees
then put it into an equation
90+90+72+x=360
solve
x=108
Answer:
The answer is 108
RVLC2019] IC/Off
In AMNO, m = 20, n = 14, and mZM = 51°. How many distinct triangles can be formed given these measurements?
O There are no triangles possible.
VX
O There is only one distinct triangle possible, with m N= 33º.
O There is only one distinct triangle possible, with mZN 147º.
O There are two distinct triangles possible, with m2N 33° or mZN-147º.
Done
) Intro
DO
There is only one distinct triangle possible, with m N= 33º. Therefore, option B is the correct answer.
What is sine rule?Law of Sines In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of any triangle to the sines of its angles.
The formula for sine rule is sinA/a=sinB/b=sinC/c
Given that, in ΔMNO, m = 20, n = 14, and m∠M = 51°.
Now, sin51°/20=sinN/14
0.7771/20=sinN/14
0.038855=sinN/14
sinN=14×0.038855
sinN=0.54397
N=33°
Therefore, option B is the correct answer.
Learn more about the sine rule here:
https://brainly.com/question/22288720.
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Find the area of the kite below. POSSIBLE ANSWERS: 168 mm 2 or 216 mm 2 or 195 mm 2 or 228 mm 2
Answer:
168 mm²
Step-by-step explanation:
Let A be the area of this shape
the kite is made of two triangles
Let A' and A" be the areas of the triangles
let's calculate A' and A" :
The area of a triangle is the product of the base and the height over 2
A' = [tex]\frac{(12+12)*5}{2}[/tex] = 60 mm² A"= [tex]\frac{(12+12)*9}{2}[/tex] = 108 mm²Let's calculate A
A = A' + A" A = 108+ 60 A = 168 mm²Find the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the given interval. (Round your answer to four decimal places. Enter your answers as a comma-separated list.)
f(x)=5√x,[4,9]
Answer:
25/4Step-by-step explanation:
The mean value theorem for integrals for the function f(c) over a given interval [a, b] is expressed as g prime(c) = g(b) - g(a)/b-a. The idea is that there is a value c in between the interval [a, b] for the function given.
Given the function g(x) = 5√x within the interval [4,9]
g prime (c) = g(9) - g(4)/9-4
g(9) = 5√9
g(9) = 5*3 = 15
g(4) = 5√4
g(4) = 5*2 = 10
g prime c) = 15-10/9-4
g prime (c) = 5/5
g prime(c) = 1
So we are to find the number for which g prime (x) = g prime(c)
If g(x) = 5√x = [tex]5x^{1/2}[/tex]
g prime (x) = [tex]5/2 \ x^{-1/2}[/tex]
g prime (x) = 5/2√x
Since g prime (c) = 1 then;
5/2√x = 1
5 = 2√x
√x = 5/2
x = (5/2)²
x = 25/4
The value of c guaranteed by the mid value theorem is 25/4
The possible value of c for [tex]\mathbf{f(x) = 5\sqrt x\ [4,9]}[/tex] is 6.25
The function is given as:
[tex]\mathbf{f(x) = 5\sqrt x\ [4,9]}[/tex]
Calculate f(4) and f(9)
[tex]\mathbf{f(4) = 5\sqrt 4 = 10}[/tex]
[tex]\mathbf{f(9) = 5\sqrt 9 = 15}[/tex]
Substitute c for x in f(x)
[tex]\mathbf{f(c) = 5\sqrt c }[/tex]
Calculate f'(c)
[tex]\mathbf{f'(c) = \frac{f(b) - f(a)}{b - a}}[/tex]
So, we have:
[tex]\mathbf{f'(c) = \frac{f(9) - f(4)}{9 - 4}}[/tex]
[tex]\mathbf{f'(c) = \frac{f(9) - f(4)}{5}}[/tex]
This gives
[tex]\mathbf{f'(c) = \frac{15 -10 }{5}}[/tex]
[tex]\mathbf{f'(c) = \frac{5 }{5}}[/tex]
[tex]\mathbf{f'(c) = 1}[/tex]
Also, we have:
[tex]\mathbf{f'(x) = \frac 52x^{-1/2}}[/tex]
Substitute c for x
[tex]\mathbf{f'(c) = \frac 52c^{-1/2}}[/tex]
Substitute 1 for f'(c)
[tex]\mathbf{\frac 52c^{-1/2} = 1}[/tex]
Multiply through by 2/5
[tex]\mathbf{c^{-1/2} = \frac 25}[/tex]
This gives
[tex]\mathbf{c^{1/2} = \frac 52}[/tex]
Square both sides
[tex]\mathbf{c = \frac{25}4}[/tex]
[tex]\mathbf{c = 6.25}[/tex]
Hence, the possible value of c is 6.25
Read more about mean value theorem at:
https://brainly.com/question/3957181
Write these numbers in standard form 0.000 04
Answer:
4/ 100000
hope it was useful for you
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keep rocking
An ecologist wishes to mark off a circular sampling region having radius 10 m. However, the radius of the resulting region is actually a random variable R with the following pdf.
f(r)={34(1−(14−r)2)13≤r≤150 otherwise
What is the expected area of the resulting circular region?
Answer:
the expected area of the resulting circular region is 616.38 m²
Step-by-step explanation:
Given that:
[tex]f(r) = \left \{ {{\dfrac{3}{4}(1-(14-r)^2)} \atop {0 }} \right. \ \ 13 \leq r \leq 15[/tex] otherwise
The expected area of the resulting circular region is:
= [tex]E(\pi r^2)[/tex]
= [tex]\pi E (r^2)[/tex]
To calculate [tex]E(r^2)[/tex]
[tex]E(r^2) = \int\limits^{15}_{13} {r^2} \ f(r) \ dr[/tex]
[tex]E(r^2) = \int\limits^{15}_{13} \ \dfrac{3r^2}{4}(1-(14-r)^2)dr[/tex]
[tex]E(r^2) = \dfrac{3}{4} \int\limits^{15}_{13} \ r^2 (1-196-r^2+28r) dr[/tex]
[tex]E(r^2) = \dfrac{3}{4} \int\limits^{15}_{13} \ r^2 (28r^3-r^4-195r^2)dr[/tex]
[tex]E(r^2) = \dfrac{3}{4}[\dfrac{28 r^4}{4}-\dfrac{r^5}{5}-\dfrac{195r^3}{3}]^{^{15}}}__{13}[/tex]
[tex]E(r^2) = \dfrac{3}{4} [ \dfrac{28 \times 50625}{4} - \dfrac{759375}{5} - \dfrac{195 \times 3375}{3} ]-[ \dfrac{28 \times 28561}{4} - \dfrac{371293}{5} - \dfrac{195 \times 2197}{3} ][/tex]
[tex]E(r^2) = \dfrac{3}{4} [ 354375-151875-219375-199927+74258.6+142805][/tex]
[tex]E(r^2) = \dfrac{3}{4} [261.6][/tex]
[tex]E(r^2) = 196.2[/tex]
Recall:
The expected area of the resulting circular region is:
= [tex]E(\pi r^2)[/tex]
= [tex]\pi E (r^2)[/tex]
where;
[tex]E(r^2) = 196.2[/tex]
Then
The expected area of the resulting circular region is:
= [tex]\pi \times 196.2[/tex]
= 616.38 m²
After Keith picked 9 lemons, he wanted to share them with his fellow classmates. If Keith wants to give 1 1/8 lemons to each of his classmates, then how many classmates will get some lemon?
Answer:
8 classmates
Step-by-step explanation:
[tex]9/1\frac{1}{8}=\\9/\frac{9}{8}=\\9*\frac{8}{9}=\\\frac{72}{9}=\\8[/tex]
The difference between seven times a number and 9 is equal to three times the sum of the number and 2. Find the number If x represents the number, which equation is correct for solving this problem?
Answer:
[tex]\large \boxed{\bf \sf \ \ \ 7x-9 = 3(x+2) \ \ \ }[/tex]
Step-by-step explanation:
Hello,
x represents this number and we know that
the difference between seven times this number and 9
7*x - 9
is equal to three times the sum of this number and 2
3(x+2)
So we can write
[tex]7x-9 =3(x+2) \\\\7x-9 =3x+6 \ \ \text{distributive law} \\\\7x-9-3x=3x+6-3x =6 \ \ \text{subtract 3x} \\\\4x-9+9=6+9 \ \text{add 9} \\\\4x=15 \ \ \text{divide by 4} \\\\ \boxed{x=\dfrac{15}{4}}\\[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
1. What are the formulas that help determine the equation of a circle? 2. How are the center, radius and a point on the circle expressed algebraically? 3. What do you need to know in order to use the ellipse equation formulas?
Answer: see below
Step-by-step explanation:
1) The equation of a circle is: (x - h)² + (y - k)² = r² where
(h, k) represents the center of the circler represents the radius of the circle.2) If you are given a point on the circle and the center (h, k)
you can input those points into the equation of a circle to find r².
Then input (h, k) and r² to identify the equation of that particular circle.
3) If you divide each term in the equation of a circle by r², you will get:
[tex]\dfrac{(x-h)^2}{r^2}+\dfrac{(y-k)^2}{r^2}=1[/tex]
(h, k) is the center of the circler is the x-radius and y-radiusThe difference between a circle and an ellipse is that an ellipse is in the shape of an oval. In other words, the x-radius and y-radius are different.
The equation of an ellipse is:
[tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex]
(h, k) is the center of the ellipsea is the x-radiusb is the y-radius