Could someone help with this math problem I will cashapp you !

Answer:

6

Step-by-step explanation:

Answer:

b.c

Step-by-step explanation:

Answer:

It's required [tex]7.48\ m^2[/tex] of sheet for the tank

Step-by-step explanation:

Surface Area of a Cylinder

Given a right cylinder of base radius r and height h, the surface area is calculated as follows:

[tex]S=2\pi r^2+2\pi r h[/tex]

The cylindrical tank has a height of h=1 m and a base diameter of 140 cm. The radius is half the diameter, thus r=140/2 = 70 cm = 0.7 m. Substituting:

[tex]S=2\pi 0.7^2+2\pi (0.7)(1)[/tex]

[tex]S=2\pi 0.49+1.4\pi[/tex]

[tex]S=2.38\pi[/tex]

[tex]\boxed{S=7.48\ m^2}[/tex]

It's required [tex]7.48\ m^2[/tex] of sheet for the tank

Step-by-step explanation:

4y(3x+2)–2(3x+2)

(4y–2)(3x+2)

2(2y–1)(3x+2)

The Factor of given equation  [tex]4y(3x+2)-2(3x+2)[/tex]   is    [tex](2y-1) (6x+4)[/tex] .

Factor in an equation is something which is multiplied by something else or we can say that numbers or the variables that are multiplied together.

We have,

 [tex]4y(3x+2)-2(3x+2)[/tex]  

So, first simplify the expression,

      [tex]12xy+8y -6x-4[/tex]

⇒    [tex]12xy-6x+8y-4[/tex]

⇒     [tex]6x(2y-1)+4(2y-1)[/tex]

From we can see that [tex](2y-1)[/tex] is common in both terms,

Therefore,

⇒    [tex](2y-1) (6x+4)[/tex]

So,    [tex](2y-1) (6x+4)[/tex]  is the factor of the given expression.

Hence, we can say that the Factor of given equation [tex]4y(3x+2)-2(3x+2)[/tex]   is    [tex](2y-1) (6x+4)[/tex] .

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Answer:

x = -22

Step-by-step explanation:

The given expression is :

-0.57x+0.27x = 6.6

We need to find the value of x.

x(-0.57+0.27) = 6.6

x(-0.3) = 6.6

[tex]x=\dfrac{6.6}{-0.3}\\\\x=-22[/tex]

So, the value of x is -22.

Answer:

B. 68pi

Step-by-step explanation:

to find the surface area of a right cone given radius and slant height:

let A = surface area

let r = radius

let l = slant height.

A=pi*r*l + pi* r^2

plug in the values

A=pi*52+pi*16= about 213.62

The surface area of the cone is 68π sq. units.

The surface area of a figure is the number of unit squares it takes to cover the entire surface without gaps or overlaps. If a three-dimensional figure has flat sides, the sides are called faces. The surface area is the total of the areas of the faces.

Given that, the slant height and the radius of a cone is 13 units and 4 units respectively,

We need to find the surface area of the cone,

SA = π×r×l + π×r²

SA = π(4×13+16)

SA = 68π

Hence, the surface area of the cone is 68π sq. units.

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Answer:

13.48

Step-by-step explanation:

Answer:

3x+4=3*2+4

3*2+4=6+4

6+4=10

10=10

Answer:

what is the y-coordinate for A?

Step-by-step explanation:

Answer:

x=2, x=-2, and x=-1

Step-by-step explanation:

Function: f(x)=(x-2)(x+2)(x+1)²

We can solve each one of the zeros by making the expressions (the ones in the parentheseis) equal zero.

So we have three equations:

1.(x-2)=0

2.(x+2)=0

3.(x+1)²=0

Solve.

1.x-2=0

x=2

2. x+2=0

x=-2

3. (x+1)²=(x+1)(x+1)=0

(x+1)=0

x=-1

(x+1)=0

x=-1

Since those two were the same we can just say x=-1 once.

Here are the three zeros:

x=2, x=-2, and x=-1

hope this helps!

Answer:

[tex]\boxed {\boxed {\sf E. \ y=x-3}}[/tex]

Step-by-step explanation:

To find the equation of the line, we must first find the slope, then use the point-slope formula.

1. Find the Slope

The slope formula is the change in y over the change in x, or:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Where (x₁, y₁) and (x₂, y₂) are the points the line passes through.

The points given in the problem are (6,3) and (4,1). Therefore:

[tex]x_1=6 \\y_1=3 \\x_2=4 \\y_2=1[/tex]

Substitute the values into the formula.

[tex]m=\frac{1-3}{4-6}[/tex]

Solve the numerator.

[tex]m=\frac{-2}{4-6}[/tex]

Solve the denominator.

[tex]m=\frac{-2}{-2}[/tex]

Divide.

[tex]m=1[/tex]

2. Find the Equation of the Line

We have the slope and a point, so we can use the point-slope formula.

[tex]y-y_1=m(x-x_1)[/tex]

We know the slope is 1 and we can pick either point to use for (x₁, y₁). Let's use (4,1).

[tex]y-1=1(x-4)[/tex]

Distribute the 1.

[tex]y-1=(1*x)+(1*-4)\\y-1=x-4[/tex]

We want to find the equation in y=mx+b, so we must isolate the variable on one side of the equation.

1 is being subtracted from y and the inverse of subtraction is addition. Add 1 to both sides of the equation.

[tex]y-1+1=x-4+1\\y=x-4+1\\y=x-3[/tex]

In slope-intercept form, the equation of the line is y=x-3

Answer:

This question is so bad but it is most likely 25% or 0. this has no context in the question

Step-by-step explanation:

Answer:

I THINK SLOPE 3

Step-by-step explanation: MY GUT TELLS ME SO...

Answer:

B=10

Step-by-step explanation:

worked it out on a graph on the internet

Answer:

x = 53

Step-by-step explanation:

The entire line is BC, the line DE bisects the line BC, meaning it cut the line in half. So CE is half of BC, so the equation for CE has to be multiplied by 2. Therefore:

5x - 3 = (2x + 25)2

multiply

5x - 3 = 4x + 50

ad 3 to both sides

5x = 4x + 53

subtract 4x from both sides

x = 53

Input into the equation to check:

5x - 3 = (2x + 25)2

5(53) - 3 = (2(53) + 25)2

265 - 3 = (106 + 25)2

262 = (131)2

262 = 262, it's correct :)

Answer:

Step-by-step explanation:

Answer:

Following are the solution to this question:

Step-by-step explanation:

[tex]\to tellurium-131\\\\ \to T(t) =1000 \times e^{\frac{\log(2)}{25}t}[/tex]

where t = in miles

In part A:

When scientists got t=0, therefore the tellurium quantity.

[tex]\to T(t) = 1000 \times e^{0}[/tex]

           [tex]= 1000 \times 1 \\\\= 1000 \ grams[/tex]

In part B:

When 1 hours =  60 min  

[tex]T(t) = 1000 \times e^{\frac{\log 2}{25} \times 60} \\\\[/tex]

      [tex]= 1000 \times e^{\frac{\log 2}{5} \times 12}\\\\= 1000 \times e^{0.72247199}\\\\\= 1000 \times 2.05951803\\\\=2059.51803\\\\=2059.51 \ grams[/tex]

Task Radioactive isotopes decay by emitting radiation is that :

A) The tellurium-131 were in the sample the moment the scientist received are 1000 grams.

B)The grams of tellurium-131 will remain in the sample after one hour is 2059.51.

Given :

Part A:

When scientists got t=0,

t=1000*[tex]e^{o}[/tex]

t=1000*1

t=1000 grams

The tellurium-131 were in the sample the moment the scientist received are 1000 grams.

Part B:

The grams of tellurium-131 will remain in the sample after one hour is :

The grams of tellurium-131 will remain in the sample after one hour is 2059.51.

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Answer:

A

Step-by-step explanation:

Answer:

4.25 mph i think

Step-by-step explanation:

4x 3 =12

1/4 x 4 = 1

12 + 1 = 13

Answer:

Miles flown in 23.19 hours = 166968 miles

Step-by-step explanation:

Given that:

A satellite flies 55584 miles in 7.72 hours

We will find the unit rate first,

Unit rate = [tex]\frac{55584}{7.72}[/tex]

Unit rate = 7200 miles per hour

Miles flown in 23.19 hours,

Miles flown = 7200 * 23.19

Miles flown = 166968 miles

Hence,

Miles flown in 23.19 hours = 166968 miles

Answer:

Option C is correct

Step-by-step explanation:

Plz help answer my question my lattes question plz

Answer:

C

Step-by-step explanation:

Answer:

False

Step-by-step explanation:because it is.

Answer:

4, see below :)

Step-by-step explanation:

We can rewrite the equation into:

3.5 + 2 - 1.5

First we add 3.5 and 2

3 and 2 are in the ones place so:

5, and then you added the .5

5.5

Then:

5.5 - 1.5

First we subtract the tenths place so:

.5 - .5 = 0

Then the ones:

5 - 1 = 4

Answer:

4 all i did was, i used a calculator

Answer:c

Step-by-step explanation:

C

Answer:

Step-by-step explanation:

[tex]2^{14}[/tex] paisa  =16,384 paisa

Answer:

The coordinates of the centroid are (0, 5)

Step-by-step explanation:

The coordinates of the centroid of a triangle whose vertices (x1, y1), (x2, y2), and (x3, y3) are ([tex]\frac{x1+x2+x3}{3}[/tex] , [tex]\frac{y1+y2+y3}{3}[/tex])

In Δ ABC

∵ A = (-20, 0), B = (0, 15), C = (20, 0)

∴ x1 = -20, x2 = 0, x3 = 20

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = ([tex]\frac{-20+0+20}{3}[/tex] , [tex]\frac{0+15+0}{3}[/tex]) = ([tex]\frac{0}{3}[/tex] , [tex]\frac{15}{3}[/tex]) = (0, 5)

∴ The coordinates of the centroid of Δ ABC are (0, 5)

In Δ DBE

∵ D = (-15, 0), B = (0, 15), E = (15, 0)

∴ x1 = -15, x2 = 0, x3 = 15

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = ([tex]\frac{-15+0+15}{3}[/tex] , [tex]\frac{0+15+0}{3}[/tex]) = ([tex]\frac{0}{3}[/tex] , [tex]\frac{15}{3}[/tex]) = (0, 5)

∴ The coordinates of the centroid of Δ DBE are (0, 5)

In Δ FBG

∵ F = (-5, 0), B = (0, 15), G = (5, 0)

∴ x1 = -5, x2 = 0, x3 = 5

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = ([tex]\frac{-5+0+5}{3}[/tex] , [tex]\frac{0+15+0}{3}[/tex]) = ([tex]\frac{0}{3}[/tex] , [tex]\frac{15}{3}[/tex]) = (0, 5)

∴ The coordinates of the centroid of Δ FBG are (0, 5)

∵ The three triangles are symmetric about the y-axis

→ That means they have the same centroid and it lies on the y-axis

∴ The coordinates of the centroid are (0, 5)