The allowable MACRS depreciation on Convers’s property in the current year assuming Convers does not elect §179 expense and elects out of bonus depreciation is $39,805.
To calculate the allowable MACRS depreciation, we need to determine the depreciation for each asset using the MACRS tables:
Machinery:Placed in service in October, which is in the fourth quarter
Depreciation method: 5-year property
Percentage from Table 1: 20.00%
Basis for depreciation: $92,000
Depreciation for the current year: 20.00% x $92,000 x 0.5 = $9,200
Computer equipment:Placed in service in February, which is in the first quarter
Depreciation method: 5-year property
Percentage from Table 1: 20.00%
Basis for depreciation: $32,000
Depreciation for the current year: 20.00% x $32,000 x 0.75 = $4,800
Delivery truck:Placed in service in March, which is in the first quarter
Depreciation method: 5-year property
Percentage from Table 1: 20.00%
Basis for depreciation: $45,000
Depreciation for the current year: 20.00% x $45,000 x 0.75 = $6,750
Furniture:Placed in service in April, which is in the second quarter
Depreciation method: 7-year property
Percentage from Table 2: 14.29%
Basis for depreciation: $172,000
Depreciation for the current year: 14.29% x $172,000 x 0.5 = $12,285
Flooring:Placed in service in May, which is in the second quarter
Depreciation method: 39-year property
Percentage from Table 5: 2.564%
Basis for depreciation: $520,000
Depreciation for the current year: 2.564% x $520,000 x 0.5 = $6,670
The total allowable MACRS depreciation for Convers Corporation in the current year is the sum of the depreciation for each asset:
$9,200 + $4,800 + $6,750 + $12,285 + $6,670 = $39,805
Therefore, the allowable MACRS depreciation on Convers’s property in the current year is $39,805.
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As a reward for Musa's diligence and agreement, his father decided to distribute a sum of money amounting to 5,800 dinars to him and his brothers, the one with the highest average taking the largest amount, while that the one with the third rank gets an amount that is half of what the one with the first rank takes. Translate this situation as an equation with an unknown X, where X is the amount that the first rank takes. Solve the resulting equation , Solve an exact value . Gives exclusively between two consecutive natural numbers Each of the three sums
The amount that the first rank takes is 1934 dinars, and the amounts that the second and third ranks take are 967 dinars and 483.5 dinars (rounded to 484 dinars), respectively.
Let's assume that there are three brothers, including Musa. Let X be the amount of money that the brother with the highest average takes, and let Y be the amount of money that the brother with the third rank takes.
According to the given conditions, we can write the following equations:
X + Y + (5800 - X - Y) = 5800 (The total amount of money distributed should be equal to 5800 dinars)X > Y (The brother with the highest average should take the largest amount)X is an integer valueLet's simplify equation 1:
X + Y = 2900
Also, we know that:
X = (2Y + X)/2
(The amount that the third rank takes is half of what the first rank takes)
Simplifying this equation:
2X = 2Y + X
X = 2Y
Substituting this value of X in equation X + Y = 2900:
3Y = 2900
Y = 2900/3
Y ≈ 966.67
As the amount given must be a whole number between two consecutive natural numbers, we can round Y to the nearest natural number:
Y = 967
Then, X = 2Y = 2*967 = 1934
Therefore, the amount that the first rank takes is 1934 dinars, and the amounts that the second and third ranks take are 967 dinars and 483.5 dinars (rounded to 484 dinars), respectively.
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find the exact value of z.
when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one.
Check the picture below.
I need help hurry!!!
Answer: 8
Step-by-step explanation:
okay so do 17 x 17 - 15 x 15
then to that result do :
squared root.
Last month, lucy and lara sold candy to raise money for their debate team. lara sold 1/5 as much candy as lucy did. if lucy sold 3/5 of a box of candy, how many boxes of candy did lara sell?
Lara sold 3/5 of a box of candy, which is the same as 0.6 boxes of candy.
How many boxes of candy did Lara sell last month to raise money?If Lucy sold 3/5 of a box of candy, then Lara sold 1/5 of 3/5, which is:
(1/5) * (3/5) = 3/25
Therefore, Lara sold 3/25 of a box of candy.
To find the number of boxes Lara sold, we can divide 3/25 by 1/5:
(3/25) ÷ (1/5) = (3/25) * (5/1) = 15/25 = 3/5
So Lara sold 3/5 of a box of candy, which is the same as 0.6 boxes of candy.
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If theta is a first-quadrant angle in standard position with p(u, v) = (3, 4), evaluate tan1/2 theta
o 1/4
o 1/2
o 2/3
We can use the given point P(3, 4) to find the values of sin(theta) and cos(theta) as follows:
[tex]sin(theta) = opposite/hypotenuse = 4/5[/tex]
[tex]cos(theta) = adjacent/hypotenuse = 3/5[/tex]
Since theta is a first-quadrant angle, we know that tan(theta) = sin(theta)/cos(theta).
Using the half-angle formula for tangent, we have:
[tex]tan(1/2 * theta) = ±√((1 - cos(theta))/2) / (1 + √((1 - cos(theta))/2))[/tex]
We can substitute the values of sin(theta) and cos(theta) that we found earlier:
[tex]tan(1/2 * theta) = ±√((1 - 3/5)/2) / (1 + √((1 - 3/5)/2))[/tex]
[tex]tan(1/2 * theta) = ±√(1/5) / (1 + √(1/5))[/tex]
[tex]tan(1/2 * theta) = ±√5 - 1[/tex]
Since theta is in the first quadrant, tan(1/2 * theta) is positive. Therefore:
[tex]tan(1/2 * theta) = √5 - 1[/tex]
We can simplify this expression by rationalizing the denominator:
[tex]tan(1/2 * theta) = (√5 - 1) / (√5 + 1) * (√5 - 1) / (√5 - 1)[/tex]
[tex]tan(1/2 * theta) = (5 - 2√5)[/tex]
So the answer is (5 - 2√5), which is approximately 0.382. Therefore, the answer is not one of the choices given.
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100%
A DVD player manufacturer shipped 960 DVD players last month. According to the manufacturer's records, 5 out of every 24 players were
repaired during the first year of ownership.
How many of the 960 DVD players were repaired in the first year?
If 5 out of every 24 players were repaired during the first year of ownership, then 200 of the 960 DVD players were repaired in the first year.
Based on the manufacturer's records, we know that 5 out of every 24 players were repaired in the first year of ownership. To find out how many out of the 960 DVD players were repaired in the first year, we can set up a proportion:
5/24 = x/960
To solve for x, we can cross-multiply:
5 * 960 = 24x
4800 = 24x
x = 200
Therefore, 200 of the 960 DVD players were repaired in the first year, which is approximately 20.8% of the total shipped.
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Do you best to explain how the following diagram demonstrates the Pythagorean theorem
Answer:
Step-by-step explanation:
The theorem states that the square on the hypotenuse (longest side) of a right triangle equal the sum of the squares on the other 2 sides.
Counting the small squares gives us these areas.
We see that
Sum of squares on hypotenuse = 25.
and sum of squares on the other 2 sides = 9 and 16 which equals 25.
A) Construct an appropriate tabular representation/summary of the random variable Number of years in operation and provide an interpretation.
b) Construct a cross-tabulation of the data on Daily Income and Type of service and provide an interpretation. Hint: Use a class width of N$ 500 for Daily Income.
c) Calculate and interpret relative measures of variability for the Daily Income for each of the three categories of Type of service
On a unit circle, the terminal side of Angle 0 intersects the circle at point (x,y). ?
Underline the expressions that would make the following statements true.
A) sin θ = (x,y, the ratio of x to y, the ratio of y to x)
B) tan θ = (x,y, the ratio of x to y, the ratio of y to x)
C) cos θ = (x,y, the ratio of x to t, the ratio of y to x)
The correct expressions are:
A) sin θ = y
B) tan θ = y/x
C) cos θ = x
How On a unit circle, the terminal side of Angle 0 intersects the circle at the point?On a unit circle, the terminal side of Angle 0 intersects the circle at points (x,y). We can use trigonometric ratios to relate the coordinates (x,y) to the angle θ.
A) sin θ = the ratio of y to 1, or simply y.
B) tan θ = the ratio of y to x.
C) cos θ = the ratio of x to 1, or simply x.
Therefore, the correct expressions are:
A) sin θ = y
B) tan θ = y/x
C) cos θ = x
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A plane leaves Singapore airport at 07:45 to fly to Sydney. The plane flies at an average speed of 757.2 km/h. The distance from Singapore to Sydney is 6310 km. The time in Sydney is 2 hours ahead of Singapore time. Calculate the local time when the plane arrives in Sydney. Give your answer in the form hours:minutes using the 24-hour clock.
Answer:
18:19
Step-by-step explanion:
To solve this problem, we need to first calculate the time it takes for the plane to fly from Singapore to Sydney:
Time = Distance ÷ Speed
Time = 6310 km ÷ 757.2 km/h
Time ≈ 8.34 hours
This is the time it takes to fly from Singapore to Sydney in Singapore time. However, we need to convert this time to Sydney time, which is 2 hours ahead of Singapore time. Therefore, the local time when the plane arrives in Sydney is:
Time in Sydney = Singapore time + 2 hours + Flight time
Time in Sydney = 07:45 + 2 hours + 8.34 hours
Time in Sydney = 18:19
Therefore, the local time when the plane arrives in Sydney is 18:19 using the 24-hour clock.
consider the rabin cryptosystem with key n = 1 359 692 821 = 32359 · 42019. (a) encode the plaintext m = 414 892 055. (b) find the four decodings of the ciphertext c = 823 845 737.
The four possible decodings of the ciphertext c = 823 845 737 are 156276219, 561472502, 1188260592, and 197895457.
To encode the plaintext m = 414 892 055, we first need to compute the corresponding ciphertext c using the Rabin cryptosystem.
The Rabin cryptosystem involves four steps: key generation, message encoding, message decoding, and key decryption. Since we already have the key n, we can skip the key generation step.
To encode the message m, we compute:
c ≡ m^2 (mod n)
Substituting the given values, we get:
c ≡ 414892055^2 (mod 1359692821)
c ≡ 1105307085 (mod 1359692821)
Therefore, the encoded ciphertext is c = 1105307085.
(b) To find the four decodings of the ciphertext c = 823 845 737, we need to use the Rabin cryptosystem to compute the four possible square roots of c modulo n.
First, we need to factorize n as n = 32359 · 42019. Then we compute the two square roots of c modulo each of the two prime factors, using the following formula:
x ≡ ± [tex]y^((p+1)/4) (mod p)[/tex]
where x is the square root of c modulo p, y is a solution to the congruence y^2 ≡ c (mod p), and p is one of the prime factors of n.
For the first prime factor p = 32359, we can use the following values:
y ≡ 3527^2 (mod 32359) ≡ 15467 (mod 32359)
x ≡ ± y^((p+1)/4) (mod p) ≡ ± 6692 (mod 32359)
Therefore, the two possible square roots of c modulo 32359 are 6692 and 25667.
For the second prime factor p = 42019, we can use the following values:
y ≡ 3527^2 (mod 42019) ≡ 25058 (mod 42019)
x ≡ ± y^((p+1)/4) (mod p) ≡ ± 1816 (mod 42019)
Therefore, the two possible square roots of c modulo 42019 are 1816 and 40203.
To find the four possible decodings of the ciphertext c = 823 845 737, we combine each of the two possible square roots modulo 32359 with each of the two possible square roots modulo 42019, using the Chinese Remainder Theorem:
x ≡ a (mod 32359)
x ≡ b (mod 42019)
where a and b are the two possible square roots modulo 32359 and 42019, respectively.
The four possible values of x are:
x ≡ 156276219 (mod 1359692821)
x ≡ 561472502 (mod 1359692821)
x ≡ 1188260592 (mod 1359692821)
x ≡ 197895457 (mod 1359692821)
Therefore, the four possible decodings of the ciphertext c = 823 845 737 are 156276219, 561472502, 1188260592, and 197895457.
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a woman bought 100 christmas cards. she paid 30 cents each for the cards that play a song when they are opened. for the rest she paid 5 cents each. of the cards cost $10.25 in all, how many of the expensive kind did she buy?
The woman bought 21 cards that play a song when they are opened, and 79 cards that do not play music.
Let's assume that the woman bought x cards that play a song when they are opened, and 100-x cards that do not play music.
We know the cost of the cards that play a song is 30 cents each, so the cost of x of these cards is 0.3x dollars.
Similarly, the cost of the cards that do not play music is 5 cents each, so the cost of 100-x of these cards is 0.05(100-x) dollars.
The total cost of all the cards is $10.25, so we can set up the following equation
0.3x + 0.05(100-x) = 10.25
Simplifying the equation, we get
0.3x + 5 - 0.05x = 10.25
0.25x = 5.25
x = 21
Therefore, the woman bought 21 cards that play a song when they are opened, and 100-21 = 79 cards that do not play music.
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Calculate the truth value for each compound proposition, using the given truth values for the simple statement letters. Type T or F beneath each letter and operator. Also, identify the main operator of each statement by typing a lowercase x in the box beneath it. Use the provided dropdown menu to indicate whether the compound statement is true or false, given the assigned truth values.
Given Truth Values
True False
K Q
L R
M S
Statement 1: (M ~ R { v ~ S L)
T or F:
Main Operator:
Assuming the given truth values, Statement 1 is____.
Statement 2: (~ S = M ). (L ~ K )
T or F:
Main Operator:
Assuming the given truth values, Statement 2 is____.
Statement 3: ~(R V ~ L) (~ S S)
T or F:
Main Operator:
Assuming the given truth values, Statement 3 is____.
Statement 4: ~ [(Q V ~ S). ~ (R = ~ S)]
T or F:
Main Operator:
Assuming the given truth values, Statement 4 is____.
Statement 5: (S = Q) = [(K ~ M) V ~ (R. ~ L)]
T or F:
Main Operator:
Assuming the given truth values, Statement 5 is_____
Statement 5 is True
Statement 1: (M ∧ ~R) ∨ (~S ∧ L)
T or F: T
Main Operator: ∨
Assuming the given truth values, Statement 1 is True.
Statement 2: (~S ↔ M) ∧ (L ∧ ~K)
T or F: F
Main Operator: ∧
Assuming the given truth values, Statement 2 is False.
Statement 3: ~(R ∨ ~L) ∧ (~S ∨ S)
T or F: F
Main Operator: ∧
Assuming the given truth values, Statement 3 is False.
Statement 4: ~ [(Q ∨ ~S) ∧ ~(R ↔ ~S)]
T or F: T
Main Operator: ~
Assuming the given truth values, Statement 4 is True.
Statement 5: (S ↔ Q) ↔ [(K ∧ ~M) ∨ ~(R ∧ ~L)]
T or F: T
Main Operator: ↔
Assuming the given truth values, Statement 5 is True.
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HELP PLEASE
Use technology or a 2-score able to answer the question
The weights of members of a baseball league are normally distributed with a mean of 176 pounds and a standard deviation of 114
pounds. Consider a league membership of 120 members
How many of the members will weigh 166 pounds or more?
Answers
A. 67
B. 76
C. 80
D. 100
56 members will weigh 166 pounds or more. The closest answer choice is: A. 67
We'll use the concepts of normal distribution, z-scores, and a z-table. Follow these steps:
1. Calculate the z-score for 166 pounds using the formula: z = (X - μ) / σ
where X = 166 pounds, μ = mean (176 pounds), and σ = standard deviation (114 pounds)
z = (166 - 176) / 114 = -10 / 114 ≈ -0.088
2. Look up the corresponding probability for the z-score in a z-table.
For a z-score of -0.088, the probability is approximately 0.535.
3. Since we want to know how many members weigh 166 pounds or more, we need to find the proportion of members in the upper tail of the distribution. To do this, subtract the probability found in the z-table from 1:
1 - 0.535 = 0.465
4. Multiply the proportion by the total number of members (120) to find the number of members weighing 166 pounds or more:
0.465 * 120 ≈ 56
However, none of the provided answer choices matches this result. Please check the question for any typos or errors. If the question's parameters are correct, the closest answer choice is: A. 67
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!!I need help seriouslyyy!!
The average cost per day for the four service is $3.23 per day
What is average cost?Average cost refers to the per-unit cost of production, which is calculated by dividing the total cost of production by the total number of units produced.
Therefore average cost = total cost/ number of unit
total cost = $108
average cost for the three services = $108/3
= $36
total average cost = $36+$54.30
= $90.30
therefore average cost for a day will be average cost for a month over 28day i.e 7days ×4
= 90.30/28
= $3.23 per day
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In Mr. Bui's algebra class, each pair of students was given a different system of equations to solve using any method. Julia and Charlene were assigned the following system. Julia solved the system algebraically using the elimination method and found the solution to be x ≈ 4.42 and y ≈ 4.39. Charlene graphed the system and found a solution of x ≈ 2.5 and y ≈ 5.25. Select the correct statement comparing their solutions. A. Neither Julia nor Charlene found the correct solution. The graphs of the lines do not intersect, so the system has no solution. B. Neither Julia nor Charlene found the correct solution. The graphs of the lines intersect at a different point. C. Charlene correctly graphed the system to find the intersection point at approximately (2.5,5.25). D. Julia correctly solved the system algebraically using the elimination method to find the solution x ≈ 4.42 and y ≈ 4.39.
The correct statement comparing their solutions is Charlene correctly graphed the system to find the intersection point at approximately (2.5,5.25).
option C is correct.
What is a mathematical equation ?Mathematically, an equation can be described as a statement that supports the equality of two expressions, which are connected by the equals sign “=”.
Since Charlene graphed the system and found a solution of x ≈ 2.5 and y ≈ 5.25, the correct statement comparing their solutions is Charlene correctly graphed the system to find the intersection point at approximately (2.5,5.25).
In conclusion, the three major forms of linear equations: are
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Solve x^2+6x=5 using any method. Round your solutions to the nearest hundredth
The solutions of the quadratic equation are:
x = - 3 ±√14
How to solve the quadratic equation?Here we want to solve the equation:
[tex]x^2 + 6x = 5[/tex]
We can rewrite that to standard form:
[tex]x^2 + 6x - 5 = 0[/tex]
Completing squares we will get:
[tex](x^2 + 2*3*x + 3^2 - 3^2) - 5 = 0[/tex]
[tex](x + 3)^2 = 5 + 9[/tex]
x = - 3 ±√14
These are the two solutions of the quadratic equation.
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Given the circle below with tangent GH and secant JIH. If GH = 8 and
12, find the length of IH. Round to the nearest tenth if necessary.
JH
=
H
The value of the segment IH for the circle with secant through H which intersect the circle at points I and J is (6 + 2i√7) or (6 - 2i√7)
What are circle theoremsCircle theorems are a set of rules that apply to circles and their constituent parts, such as chords, tangents, secants, and arcs. These rules describe the relationships between the different parts of a circle and can be used to solve problems involving circles.
GH² = IH × JI {secant tangent segments}
JI = 12 - IH, we shall represent IH with x so that;
8² = x(12 - x)
64 = 12x - x²
x² - 12x + 64 = 0 {rearrange to get a quadratic equation}
with the quadratic formula;
x = [12 + √(-112)]/2 or x = = [12 - √(-112)]/2
√(-112) = 4i√7 {where i = √(-1)}
so;
x = (6 + 2i√7) or x = (6 - 2i√7)
Therefore, the value of the segment IH for the circle with secant through H which intersect the circle at points I and J is (6 + 2i√7) or (6 - 2i√7)
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Consider the vector field F(x, y, z) = (yz, -5xz, –4xy). Find the divergence and curl of F. div(F) = V.F= = curl(F) = V XF =( ). B) Consider the vector field F(x, y, z) = (-x?, -(x + y)
a) The divergence of F is -4x - 2y,
b) The curl of F is (-2(x+y), 0, -2x).
A) To find the divergence of F, we need to take the dot product of the del operator with F. Therefore, we have:
div(F) = ∇ · F = ∂(yz)/∂x + ∂(-5xz)/∂y + ∂(-4xy)/∂z
= 0 - 5z - 4x
= -5z - 4x
To find the curl of F, we need to take the cross product of the del operator with F. Therefore, we have:
curl(F) = ∇ × F = ( ∂(-4xy)/∂y - ∂(-5xz)/∂z, ∂(yz)/∂z - ∂(4xy)/∂x, ∂(-yz)/∂x - ∂(-5xz)/∂y )
= (-5z, y, -5x)
B) To find the divergence of F, we need to take the dot product of the del operator with F. Therefore, we have:
div(F) = ∇ · F = ∂(-x²)/∂x + ∂(-(x+y)²)/∂y + ∂(0)/∂z
= -2x - 2(x+y)
= -4x - 2y
To find the curl of F, we need to take the cross product of the del operator with F. Therefore, we have:
curl(F) = ∇ × F = ( ∂(0)/∂y - ∂(-(x+y)²)/∂z, ∂(0)/∂z - ∂(-x²)/∂x, ∂(-(x+y))/∂x - ∂(-x²)/∂y )
= (-2(x+y), 0, -2x)
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What is the vertex of the graph of the equation Y=3x2( to the second power) +6x+1
A.(-1,-2)
B.(-1, 10)
C.(1, -2)
D.(1, 10)
Answer: To find the vertex of the graph of the equation Y=3x^2+6x+1, we can use the formula:
x = -b/2a
where a = 3 and b = 6, which are the coefficients of the x^2 and x terms, respectively.
x = -6/(2 x 3) = -1
Substituting x = -1 into the equation, we get:
Y = 3(-1)^2 + 6(-1) + 1 = -2
Therefore, the vertex of the graph is (-1, -2), so the answer is A. (-1,-2).
Step-by-step explanation:
5. Which model is most appropriate for the data shown in the graph below? (1 point)
O quadratic
O linear
O exponential
O line
Answer:
Ф Exponential.
Step-by-step explanation:
The most appropriate for tehe data shown is:
Ф Exponential.
...
if the area of a circle is 153.86m find diamiter and perimeter
Answer:
the diameter is 14 and the perimeter is 43.97
the kendall correlation uses rank values to determine the correlation between two variables. the equation for kendall rank shows that if there are more concordant pairs, then the correlation will be positive. using the definition of concordant and disconcordant pairs, explain why this makes sense.
Yes, if there are more concordant pairs in the rank order, it makes sense that the Kendall correlation will be positive, as it suggests a tendency for the two variables to move in the same direction more often.
In Kendall correlation,
Rank values of each observation for the two variables are compared to determine the level of agreement or disagreement between them.
A concordant pair is when the rank order of the two variables is the same both increase or decrease together.
A discordant pair is when the rank order is different one variable increases while the other decreases.
If there are more concordant pairs, it means that the two variables tend to move in the same direction more often.
Which suggests a positive correlation relationship between them.
Conversely, if there are more discordant pairs, it means that the two variables tend to move in opposite directions more often.
Which suggests a negative relationship between them.
Example ,
two variables, X and Y, that are positively correlated.
If we plot the observations of X and Y on a scatter plot.
Expect to see a pattern where as the values of X increase, the values of Y also tend to increase.
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A dealer bought some radios for a total of $1,008. she gave away 6 radios as gifts, sold each of the rest for $14 more than she paid for each radio, and broke even. how many radios did she buy?
The dealer bought 42 radios.
How many radios did the dealer buy?Let x be the number of radios the dealer bought.
Let y be the price the dealer paid for each radio.
We know that the dealer bought x radios for a total of $1,008, so:
x * y = 1008
We also know that the dealer gave away 6 radios and sold the rest for $14 more than she paid for each radio, breaking even. This means that the total revenue from selling the remaining radios is equal to the total cost of buying them:
(x - 6) * (y + 14) = x * y
Simplifying this equation, we get:
xy + 14x - 6y - 84 = xy
14x - 6y = 84
7x - 3y = 42 (dividing by 2 on both sides)
Now we have two equations:
x * y = 1008
7x - 3y = 42
We can use substitution or elimination to solve for x and y. Let's use elimination by multiplying the second equation by y/3 and adding it to the first equation:
x * y + (7x - 3y) * (y/3) = 1008 + 42 * (y/3)
xy + 7xy/3 - y²/3 = 1008 + 14y
10xy/3 - y²/3 - 14y - 1008 = 0
Multiplying both sides by 3, we get:
10xy - y² - 42y - 3024 = 0
Now we can use the quadratic formula to solve for y:
y = (-b ± sqrt(b² - 4ac)) / 2a
where a = -1, b = -42, and c = -3024:
y = (-(-42) ± sqrt((-42)² - 4(-1)(-3024))) / 2(-1)
y = (42 ± sqrt(42² - 4*3024)) / 2
y = (42 ± 126) / 2
y = 84 or y = -42
Since the price of a radio cannot be negative, we can discard the second solution and conclude that y = 84.
Now we can solve for x using the first equation:
x * y = 1008
x * 84 = 1008
x = 12
Therefore, the dealer bought 12 radios.
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the diagram shows a polygon composed of rectangles
Answer:
210 feet
Step-by-step explanation:
Refer the attached figure
LK = 22 ft
KH=JI = 18 ft.
HG=14 ft.
CD=FE=16 ft.
AL=15 ft.
GF=CB = 5ft.
KJ=HI=10 ft.
CF=CB+BG+GF=5+15+5=25 ft. =DE
AB= LK+KH+HG=22+18+14= 54 ft.
Perimeter of polygon = Sum of all sides
Perimeter of polygon=AL+LK+KJ+JI+HI+HG+GF+FE+DE+CD+CB+BA
=15+22+10+18+10+14+5+16+25+16+5+54
=210
Hence the perimeter of the polygon is 210 feet.
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A yard stick is placed on the table during a party game. A marker is placed at 11 inches, and labeled A, one labeled B at 24 inches, another labeled C at 26 and another labeled D at 36. A marble is shot toward the yard stick. What is the probability that the marble that hits the yard stick between A and D hits it between C and D? Write your answer as a percent
The required probability 40%
To find the probability that the marble that hits the yard stick between A and D hits it between C and D, we need to find the length of the interval between C and D, and divide it by the length of the interval between A and D.
The length of the interval between C and D is
36 - 26 = 10
The length of the interval between A and D is
36 - 11 = 25
The probability that a marble will strike a yardstick between A and D and C and D is
10/25 × 100 = 40%
Therefore, the probability that a marble will strike a yardstick between A and D and C and D is 40%
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Solve the equation and check your solution: x + 4 = -2 + x
The equation x + 4 = -2 + x has no solution for x
Solving the equation and checking the solutionFrom the question, we have the following parameters that can be used in our computation:
x + 4 = -2 + x
Subtract x from both sides of the equation
so, we have the following representation
x - x + 4 = -2 + x - x
When the like terms of the equation are evaluated, we have
4 = -2
The above equation is false
This is because 4 and -2 do not have the same value
Hence, the equation has no solution
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The following relation is a function:
{(-2, 4), (3, 0), (-4, 3), (-2, -1), (0, -4)}
true
false
The relation of function is False.
This relation is not a function because the input value -2 is associated with two different output values (4 and -1). In a function, each input can only have one corresponding output.
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A certain painting was purchased for $15,000. its value is predicted to decay exponentially decreasing by 15% each year. which equation can be
used to predict t, the number of years it would take for the painting to have a value of $10,000?
a 10,000(0. 15)' = 15,000
b. 15,000(0. 15)' = 10,000
o g. 15,000(0. 85)' = 10,000
d. 10,000(0. 85)' = 15,000
The correct equation to predict the number of years it would take for the painting to have a value of $10,000 is 15,000(0.85)[tex]^{(t)}[/tex] = 10,000. The correct answer is option (c).
The initial value of the painting is $15,000, and its value is predicted to decay by 15% each year. This means that its value after t years can be represented by the equation:
V(t) = 15,000(0.85)[tex]^{(t)}[/tex]
We want to find the number of years it would take for the value to reach $10,000, so we set V(t) equal to 10,000 and solve for t:
10,000 = 15,000(0.85)[tex]^{(t)}[/tex]
Dividing both sides by 15,000 gives:
0.6667 = 0.85[tex]^{(t)}[/tex]
Taking the natural logarithm of both sides gives:
ln(0.6667) = t ln(0.85)
Solving for t gives:
t = ln(0.6667) / ln(0.85) = 2.294
So it would take approximately 2.294 years for the painting to have a value of $10,000. The right option is (c).
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What is the anwser to number 3
The volume of a triangular prism in question number 3, obtained from the product of the area of a triangle and the thickness of the prism is 1,728 mi³
What is a triangular prism?A triangular prism consists of two triangular bases and three sides that are rectangular.
The solid in the figure in question number 3 is a triangular prism, with the following dimensions.
Base length = 30 mi.
Thickness (depth of the prism) = 8 mi
Shape of the triangles = Right triangles
Leg lengths of the right triangles = 18 miles and 24 miles
The volume of the triangular prism = Area of the cross section of the triangular prism × Depth of the prism
Area of the triangular cross section of the triangular prism = (1/2) × 18 × 24 = 216 mi²
Volume of the triangular prism = 216 mi² × 8 mi = 1728 mi³
The volume of the triangular prism in the figure is therefore; 1,728 mi³
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