Consider two consecutive positive integers such that the square of the second integer added to 3 times the first is equal to 105

1

Step-by-step explanation:

p(x≤20)=p(x=-10) +p(x=-5)+p(X=0) +p(x=5) +p(x=10)+ p(X=15)+p(X=20)

This, p(X≤20)=0.20+0.15+0.05+0.1+0.25+0.1+0.15

=1

Answer:

The answer is option A

Step-by-step explanation:

Since the lines are perpendicular the slope perpendicular line is the negative inverse of the original line and when they are multiplied should give - 1

Let m be the slope of the perpendicular line

That's

1/3 × m = - 1

multiply through by 3

m = - 3

The slope of the perpendicular line is - 3

Hope this helps you

Answer:

-3

Step-by-step explanation:

Answer:

The null hypothesis is ;

H0 ≥ 12

While the alternative hypothesis H1 is ;

H1 < 12

Step-by-step explanation:

Here, we want to correctly identify the null hypothesis H0 and the alternative hypothesis H1

The null hypothesis is as follows ;

H0 ≥ 12

While the alternative hypothesis H1 is ;

H1 < 12

Answer:

x=3 or/and x= -7/3

Step-by-step explanation:

+1= +1

3x = 9

9 divided by 3 is x= 3

+1= +1

3x = -7

-7 divided by 3 is x= -7/3

Answer:

[tex]\huge\boxed{x=3\ \vee\ x=-\dfrac{7}{3}}[/tex]

Step-by-step explanation:

[tex]|a|=\left\{\begin{array}{ccc}a&\text{for}\ a\geq0\\-a&\text{for}\ a<0\end{array}\right\\\\|a|=k\to a=k\ \vee\ a=-k\ \text{for}\ k>0\\==========================\\\\|3x-1|=8\iff3x-1=8\ \vee\ 3x-1=-8\\\\\begin{array}{cccc}3x-1=8&\vee&3x-1=-8&\text{add 1 to both sides}\\3x-1+1=8+1&\vee&3x-1+1=-8+1\\3x=9&\vee&3x=-7&\text{divide both sides by 3}\\\dfrac{3x}{3}=\dfrac{9}{3}&\vee&\dfrac{3x}{3}=\dfrac{-7}{3}\\x=3&\vee&x=-\dfrac{7}{3}\\\end{array}[/tex]

Answer:

x = -3 and x = 9.

Step-by-step explanation:

2|x - 3| - 5 = 7

2|x - 3| = 12

|x - 3| = 6

x - 3 = 6

x = 9

-(x - 3) = 6

-x + 3 = 6

-x = 3

x = -3

Hope this helps!

Answer:

x=9            x=-3

Step-by-step explanation:

2|x-3|-5=7

Add 5 to each side

2|x-3|-5+5=7+5

2|x-3|=12

Divide by 2

2/2|x-3|=12/2

|x-3|=6

There are two solutions to an absolute value equation, one positive and one negative

x-3 =6           x-3 = -6

Add 3 to each side

x-3+3 = 6+3      x-3+3 = -6+3

x=9                     x = -3

Answer:

x = [tex]\frac{3}{4}(n-1)[/tex]

Step-by-step explanation:

It's given in the question that '' The number is 75% of one less than a number n"

Let the number is 'x'.

One less than a number 'n' will be = (n - 1)

75% of one less than a number will be = 75% of (n -1)

                                                                = [tex]\frac{75}{100}(n-1)[/tex]

                                                                = [tex]\frac{3}{4}(n-1)[/tex]

Therefore, the desired expression to get the number 'x' will be,

x = [tex]\frac{3}{4}(n-1)[/tex]

Answer:

3/4(n-1)

Step-by-step explanation:

did it in rsm

Answer:

-4,4,16

Step-by-step explanation:

They are all even integers.

-4^2=16

4^2=16

16^2=256

the square of the third,16 is 256 which is more than the square of the second,4=16

The three consecutive even integers such that the square of the third is 60 more than the square of the second are -18, -16 and -14.

Any positive or negative number without fractions or decimal places is known as an integer, often known as a "round number" or "whole number."

Given:

Let the three even consecutive integers are 2n-2, 2n and 2n + 2.

According to the question,

So,

(2n + 2)² = (2n)² - 60

4n² + 4 + 8n = 4n² -60

8n = -64

n = -8

That means, the integers are -18, -16 and -14.

Therefore, the required even integers are -18, -16 and -14.

To learn more about the integers;

brainly.com/question/1768254

#SPJ5

Answer:

5/3

Step-by-step explanation:

3/8 + 1/8 + 2/3 + 1/2

=> [ 3/8 + 1/8 ] + [ 2/3 + 1/2 ]

=> 1/2( or 4/8 ) + 7/6

=> 10/6 or 5/3

Answer:

[tex] \frac{3}{8} + \frac{1}{8} + \frac{2}{3} + \frac{1}{2} [/tex]

Add the fractions with the same common denominator

That's

[tex] \frac{3}{8} + \frac{1}{8} = \frac{4}{8} = \frac{1}{2} [/tex]

So we have

[tex] \frac{1}{2} + \frac{2}{3} + \frac{1}{2} [/tex]

Add the fractions with the same common denominator

That's

[tex] \frac{1}{2} + \frac{1}{2} = \frac{2}{2} = 1[/tex]

We have

[tex] 1 + \frac{2}{3} [/tex]

That's

[tex] \frac{1}{1} + \frac{2}{3} [/tex]

Find the common denominator

The common denominator is 3

[tex] \frac{1}{1} + \frac{2}{3} = \frac{3 + 2}{3} [/tex]

[tex] = \frac{5}{3} \: \: \: \: \: \: or \: \: \: \: \: \: \: 1 \frac{2}{3} [/tex]

Hope this helps you

Answer:

x = 40

Step-by-step explanation:

4/x = 50/500

Simplify the right side

4/x = 1/10

Using cross products

4*10 = 1*x

40 = x

Step-by-step explanation:

4/x = 50/500

4/x = 0.1

x = 4/0.1

x = 40

Answer:

8lb of the cheaper Candy

17.5lb of the expensive candy

Step-by-step explanation:

Let the cheaper candy be x

let the costly candy be y

X+y = 25.5....equation one

2.2x +7.3y = 25.5(5.7)

2.2x +7.3y = 145.35.....equation two

X+y = 25.5

2.2x +7.3y = 145.35

Solving simultaneously

X= 25.5-y

Substituting value of X into equation two

2.2(25.5-y) + 7.3y = 145.35

56.1 -2.2y +7.3y = 145.35

5.1y = 145.35-56.1

5.1y = 89.25

Y= 89.25/5.1

Y= 17.5

X= 25.5-y

X= 25.5-17.5

X= 8

do not know because my brain cant focus on this sorry :/

Answer:

79.67%

Step-by-step explanation:

To find the percentage correct, take the number correct over the total

98/123

.796747967

Change to a percent by multiplying by 100 %

79.6747967%

Round to the nearest hundredth

79.67%

Answer:

79.67%

Step-by-step explanation:

percent = part/whole * 100%

percent = 98/123 * 100%

percent = 79.67%

Answer:

a) the mean is $53.50

b) it is a statistic

Step-by-step explanation:

mean = ∑fx/∑f

∑f = 20

mean = (sum of the terms) ÷ (number of terms)

mean = (53+49+54+50+21+46+75+45+63+76+61+63+36+34+54+63+37+62+66+62) ÷ 20 = 1070/20

=$53.50

b) it is statistics because it is a random sample of 20 residential customers not the actual population

Answer:

a) [tex]1.19 \times 10^{-2} + 1.07\times 10^{-2}[/tex] is larger than [tex]1.19\times 10^{-2}[/tex]; b) [tex]1.19 \times 10^{-2} - 1.07\times 10^{-2}[/tex] is smaller than [tex]1.19\times 10^{-2}[/tex]; c) [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})[/tex] is smaller than [tex]1.19\times 10^{-2}[/tex]; d) [tex](1.19\times 10^{-2})/ (1.07\times 10^{-2})[/tex] is greater than [tex]1.19\times 10^{-2}[/tex].

Step-by-step explanation:

a) Is [tex]1.19 \times 10^{-2} + 1.07\times 10^{-2}[/tex] smaller or larger?

1) [tex]1.19 \times 10^{-2} + 1.07\times 10^{-2}[/tex] Given.

2) [tex](1.19+1.07)\times 10^{-2}[/tex] Distributive property.

3) [tex]2.26 \times 10^{-2}[/tex] Addition/Result.

[tex]1.19 \times 10^{-2} + 1.07\times 10^{-2}[/tex] is larger than [tex]1.19\times 10^{-2}[/tex].

b) Is [tex]1.19 \times 10^{-2} - 1.07\times 10^{-2}[/tex] smaller or larger?

1) [tex]1.19 \times 10^{-2} - 1.07\times 10^{-2}[/tex] Given.

2) [tex](1.19-1.07)\times 10^{-2}[/tex] Distributive property.

3) [tex][1.19+(-1.07)]\times 10^{-2}[/tex] Subtraction.

4) [tex]0.12\times 10^{-2}[/tex] Addition/Result.

[tex]1.19 \times 10^{-2} - 1.07\times 10^{-2}[/tex] is smaller than [tex]1.19\times 10^{-2}[/tex].

c) Is [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})[/tex] smaller or larger?

1) [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})[/tex] Given.

2) [tex](1.19\times 1.07)\cdot (10^{-2}\times 10^{-2})[/tex] Associative property/Commutative property.

3) [tex]1.27\times 10^{-4}[/tex] Multiplication/ ([tex]a^{b}\cdot a^{c} = a^{b+c}[/tex])/ [tex](-x)\cdot (-y) = x\cdot y[/tex] /Result.

[tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})[/tex] is smaller than [tex]1.19\times 10^{-2}[/tex].

d) Is [tex](1.19\times 10^{-2})/ (1.07\times 10^{-2})[/tex] smaller or larger?

1) [tex](1.19\times 10^{-2})/ (1.07\times 10^{-2})[/tex] Given.

2) [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{-2})^{-1}[/tex] Division.

3) [tex](1.19\times 10^{-2})\cdot (1.07\times 10^{2})[/tex] ([tex](a^{b})^{c} = a^{b\cdot c}[/tex]; [tex](-x)\cdot (-y) = x\cdot y[/tex])

4) [tex](1.19\times 1.07)\cdot (10^{-2}\cdot 10^{2})[/tex] Associative property/Commutative property.

5) [tex]1.27[/tex] Multiplication/([tex](a^{b})^{c} = a^{b\cdot c}[/tex]; [tex]a^{0} = 1[/tex])/Modulative property/Result.

[tex](1.19\times 10^{-2})/ (1.07\times 10^{-2})[/tex] is greater than [tex]1.19\times 10^{-2}[/tex].

Answer:

Step-by-step explanation:

Given : A right triangle

To do : Solve for x

Solution,

[tex]cos \: 55 = \frac{x}{20} [/tex] ( by definition of cos function, adjacent / hypotenuse )

[tex]0.5736 = \frac{x}{20} [/tex]

multiply both sides of the equation by 20

[tex](0.5736) \times 20 = x[/tex]

Calculate the product

[tex]11.471 = x[/tex]

Swipe both sides of the equation

[tex]x = 11.471[/tex]

Round answer to nearest hundredth

[tex]x = 11.47[/tex]

Hope this helps...

Best regards!!

Answer:

Option (B)

Step-by-step explanation:

Given question is not complete; find the complete question in the attachment.

In the graph attached,

Parent function is an absolute value function,

f(x) = |x|

When this graph is shifted 4 units left, rule for the translation will be,

f(x) → f(x + 4)

Therefore, the new function of above translation will be,

g(x) = f(x + 4) = |x + 4|

Now the graph is shifted 2 units down so the translated function will be,

h(x) = g(x) - 2

h(x) = |x + 4| - 2

If we rewrite the function in the form of an equation, graph will be represented by

⇒ y = |x + 4| - 2

Therefore, Option (B) will be the answer.

Answer:

The answer is

Step-by-step explanation:

3+ – 5(4+ – 3v) can be written as

3 - 5( 4 - 3v)

Expand and simplify

That's

3 - 20 + 15v

15v - 17

Hope this helps you

Answer:

A

Step-by-step explanation:

[tex]g(x) = \frac{3}{{x}^{2} + 2x} \\ {x}^{2} + 2x - \frac{3}{g(x)} = 0 \\ x = \frac{1}{2} \Big( - 2 + \sqrt{12 + \frac{12}{g(x)} }\Big) \\ x = - 1 + \sqrt{1 \pm \frac{3}{g(x)} } [/tex]

Now replace $x$ by $g^{-1}(x)$ and $g(x)$ by $x$ and you have your answer.

Answer:

Adjusted-R2

Step-by-step explanation:

When evaluating a multiple regression model, a commonly used goodness of fit is the adjusted-R2. It allows for a comparison of regression models with multiple predictors or independent variables. The addition of independent variables usually causes the model to be more reliable. The adjusted-R2 considers the effect of additional independent variables. It usually adjusts for the number of terms in the model.

Let x be the number.

Set up an equation:

2x - 2/3x = 20

Simplify:

1 1/3x = 20

Divide both sides by 1 1/3

X = 15

The number is 15

Answer:

csc B = 13/12

Step-by-step explanation:

csc B = 1 / sin B

The sin B is

sin B = opp/ hyp  so

csc B = hyp /opp

csc B = 26 / 24

csc B = 13/12

Answer:

13/12

Step-by-step explanation:

sin θ = opposite/ hypotenuse

csc θ = 1/sinθ

csc θ  = hypotenuse/opposite

csc (B)  = 26/24

csc (B)  = 13/12

Answer:

[tex]\theta=\frac{n\pi}{5}[/tex]

Step-by-step explanation:

You have the following function:

[tex]r=2sin5\theta[/tex]          (1)

In order to find the zeros of the function you equal to zero the equation (1), and then you solve for θ:

[tex]2sin5\theta=0\\\\sin5\theta=0\\\\5\theta=sin^{-1}(0)=n\pi;\ \ \ \ n=0,1,2,3,..\\\\\theta=\frac{n\pi}{5}[/tex]

Then, there are infinite zeros for the function of the equation (1), because n has infinite positive integers values.

Answer:

θ = 0, pi/5, 2pi/5, 3pi/5, 4pi/5 ,pi

Step-by-step explanation:

Answer: Monomial.

Step-by-step explanation:

Ok, when we have a polynomial with only one term, this is a monomial.

If the polynomial has two terms, this is a binomial.

If the polynomial has 3 terms, this is a trinomial.

And so on.

In this particular case we have:

52*c^2*y^4

Where c and y may be variables.

We can see that here we have only one term, so this would be a monomial.

(notice that the number of variables does not affect the type of polynomial in this case, only the number of terms)

Answer:

binomial.

Step-by-step explanation:

The polynomial −50c3z3−41y220z4 has 2 terms, so it is a binomial.

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The tank for a car holds 17 gallons. The gasoline gauge shows the tank is 3/4 full. How much gas is still in the tank?

Give your answer as a whole number or as a mixed fraction reduced to lowest terms.

Answer:

[tex]Gas \: \:left = 12 \frac{3}{4} \: \:gallons \\\\[/tex]

Step-by-step explanation:

The tank for a car holds 17 gallons.

The gasoline gauge of the car shows that the tank is 3/4 full.

We are asked to find the remaining gasoline in the tank.

[tex]Gas \: \:left = \frac{3}{4} \times 17 \\\\Gas \: \:left = \frac{51}{4} \\\\Gas \: \:left = 12 \frac{3}{4} \: \:gallons \\\\[/tex]

Therefore, the remaining gas in the tank is [tex]12\frac{3}{4}[/tex] gallons.

Alternatively:

[tex]1 - \frac{3}{4} = \frac{1}{4}[/tex]

Amount of gasoline consumed = [tex]\frac{1}{4} \times 17 = \frac{17}{4}[/tex]

Amount of gasoline left = total - consumed

Amount of gasoline left = [tex]17 - \frac{17}{4} = 12\frac{3}{4} \:\: gallons[/tex]

Answer:

2n + 10.

Step-by-step explanation:

2(n + 5)

= 2 * n + 2 * 5

= 2n + 10.

Hope this helps!

Answer: 2n + 10

Explanation: In this problem, the 2 "distributes" through the parenthses which means that it multiplies by each of the terms inside.

So we have 2(n) + 2(5) which simplifies to 2n + 10.

Answer:

72.4%

Step-by-step explanation:

The essay is 25% of your grade, and the rest is 75% of your grade.

25 (3.3/4) + 75 (0.69) ≈ 72.4

Answer:

560 km

Step-by-step explanation:

350x8/5=

350x1.6=

560

Answer:

Bridge = 300 m

Speed = 10 m/s

Step-by-step explanation:

If a goes past you in 10 seconds, it means the train has speed of

100 m/ 10 seconds as it is 100 m long

The speed in m/s is:

Then it take 3 times of 10 seconds to cross the bridge, so

The length of the bridge is:

Answer:

Length  : 50m

Speed   : 5 m  /  s

It is possible to draw a single straight line to pass through more than one point on the red curve. Therefore, the graph fails the vertical line test. We have cases where one input leads to more than one output.

Answer:

The adult ticket costs $18 and the children ticket costs $13.

Step-by-step explanation:

Let the price of the adult ticket be a.

Let the price of the children ticket be c.

Three adults and four children must pay $106. This implies that:

3a + 4c = 106 _______(1)

Two adults and three children must pay $75. This implies that:

2a + 3c = 75 ________(2)

We have two simultaneous equations:

3a + 4c = 106 _____(1)

2a + 3c = 75 ______(2)

Multiply (1) by 2 and (2) by 3 and subtract (1) from (2):

  6a + 9c = 225

- (6a + 8c = 212)

             c = $13

Put this value of c in (2):

2a + 3*13 = 75

2a + 39 = 75

=> 2a = 75 - 39

2a = 36

a = 36/2 = $18

Therefore, the adult ticket costs $18 and the children ticket costs $13.