Consider these pictures in answering the question below.
с
D
Which diagram might represent the initial vertical component of the velocity of a ball thrown upward at an angle?
a
Ob
CU O
c
Od
Оe
E
Answers
Answer:
the answer would be D because not only is it going up but it's going up as an angle
Related Questions
Does anyone know how to draw this out?
Answers
The Position-Time graph for the given Velocity-Time graph is drawn in the image attached.
From the Velocity-Time graph we can take the information needed.
[tex]t_{1}[/tex] = 1 s
[tex]t_{2}[/tex] = 2 s
[tex]t_{3}[/tex] = 3 s
[tex]t_{4}[/tex] = 4 s
[tex]t_{5}[/tex] = 5 s
[tex]v_{1}[/tex] = 10 m / s
[tex]v_{2}[/tex] = 20 m / s
[tex]v_{3}[/tex] = 30 m / s
[tex]v_{4}[/tex] = 40 m / s
[tex]v_{5}[/tex] = 50 m / s
v = d / t
d = v * t
[tex]d_{1}[/tex] = 10 * 1 = 10 m
[tex]d_{2}[/tex] = 20 * 2 = 40 m
[tex]d_{3}[/tex] = 30 * 3 = 90 m
[tex]d_{4}[/tex] = 40 * 4 = 160 m
[tex]d_{5}[/tex] = 50 * 5 = 250 m
Therefore, the Position-Time graph is drawn in the image attached.
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A Hall-effect probe operates with a 120 -mA current. When the probe is placed in a uniform magnetic field of magnitude 0.0800 T , it produces a Hall voltage of 0.700 μV .(a) When it is used to measure an unknown magnetic field, the Hall voltage is 0.330μV . What is the magnitude of the unknown field?
Answers
The magnitude of Magnetic field is 37.7 x [tex]10^{-4}[/tex] Tesla.
We have Hall Probe to measure an unknown Magnetic field.
We have to determine the Magnitude of the unknown Magnetic field.
What is Hall Probe?A Hall probe is a device that can be used to measure magnetic fields. They work on the principle of Hall effect.
According to the question, we have -
I = 120 mA = 120 x 0.001 = 0.12 Ampere.
B = 0.08 Tesla
V(H) = 0.7 [tex]\mu[/tex]V = 7 x [tex]10^{-7}[/tex]
The formula relating the above quantities is -
V(H) = [tex]A_{H} \frac{IB}{d}[/tex]
[tex]$\frac{d}{A_{H} } =\frac{IB}{V_{H} }= \frac{0.12 \times 0.08}{7\times 10^{-7} }[/tex] = 13.71 x [tex]10^{3}[/tex]
Now -
For → V = 0.33 [tex]\mu[/tex]V = 0.33 x [tex]10^{-7}[/tex]
[tex]B=\frac{Vd}{A_{H}I }[/tex] = [tex]13.71\times 10^{3} \times\frac{0.33\times 10^{-7} }{0.12}[/tex] = 37.7 x [tex]10^{-4}[/tex] Tesla
Hence, the magnitude of Magnetic field is 37.7 x [tex]10^{-4}[/tex] Tesla.
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In 1962 , measurements of the magnetic field of a large tornado were made at the Geophysical Observatory in Tulsa, Oklahoma. If the magnitude of the tornado's field was B=1.50×10⁻⁸ T pointing north when the tornado was 9.00 km east of the observatory, what current was carried up or down the funnel of the tornado? Model the vortex as a long, straight wire carrying a current.
Answers
B = μ₀i/2πr
i = 2πrB/μ₀
∵ 16.50 nano Tesla = 1.65×10⁻⁸ Tesla
∵8.10Km = 8100 m
i = 2(3.14)(8100)(1.65×10⁻⁸)/4×3.14×10⁻⁷
i = 668.25 A
So the current carried up or down the funnel of the tornado is 668.25 A.
What is a tornado?A tornado is a fast spinning column of air that occasionally strikes the base of a cumulonimbus cloud as well as the Earth's surface.
A tornado is a narrow, violently rotating column of air that extends from the ground to a thunderstorm.
Tornadoes are difficult to notice since wind is invisible unless they build a condensation funnel of water droplets, dust, and debris.
Some tornadoes increase and become powerful or destructive. Strong tornadoes can last for twenty minutes or more and have winds of up to 200 miles per hour, whereas severe tornadoes can persist for more than an hour and have winds of 200 to 300 miles per hour!
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A canister and the hydrogen gas it contains are at 100°C. The canister is placed in a vacuum, and the temperature of the canister and gas begins to decrease. Which of the following statements of reasoning best explains how the canister-gas system loses energy?
High-energy hydrogen molecules collide with lower-energy molecules and the walls inside the canister, losing energy during the collisions.
High-energy hydrogen molecules collide with lower-energy molecules and the walls inside the canister, losing energy during the collisions.
The molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.
The molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.
Energy is released from the canister as infrared radiation that can travel through the vacuum, causing a decrease in the average energy of the canister and the molecules.
Energy is released from the canister as infrared radiation that can travel through the vacuum, causing a decrease in the average energy of the canister and the molecules.
Energy is released from the canister and travels through the vacuum by convection, causing a decrease in the average energy of the canister and the molecules.
Answers
The statement that best explains why the system looses energy is; the Collison of the molecules of hydrogen with the wall of the can carries off energy to the environment.
How does the cannister loose energy?We know that energy is defined as the rate of doing work. Now the temperature of a gas is measure of the kinetic energy of the molecules of the body. In this case, the temperature of the hydrogen in the cannister has to do with how fast the molecules of the hydrogen are moving.
The higher the temperature, the faster the molecules of the hydrogen move. The lower the temperature, the slower the molecules of the hydrogen moves.
As such, the molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.
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GP Submarine A travels horizontally at 11.0 m/s through ocean water. It emits a sonar signal of frequency f = 5.27× 10³Hz in the forward direction. Submarine B is in front of submarine A and traveling at 3.00 m/s relative to the water in the same direction as submarine A. A crewman in submarine B uses his equipment to detect the sound waves ("pings") from submarine A. We wish to determine what is heard by the crewman in submarine B. (d) In Equation 17.19 , what speed of sound should be used?
Answers
The speed of sound used in water is 5408 Hz.
(d) The frequency that submarine B is able to detect is [tex]fo = fs (V -V_O/ v +V_s).[/tex]
[tex]=53.273[/tex] × [tex]10 3hz) (1533 m/s + 11 m/s / (45 m/s - 1533 m/s))[/tex]
Frequency [tex]= 5408 HZ[/tex]
Hence, the speed of sound used in water is [tex]5408Hz[/tex].
What is principle of Submarine?Submarine, any naval vessel capable of propulsion both below and above the surface of the ocean. Submarines are very distinct from surface ships in terms of appearance and design, making this a unique capacity among warships.
When Germany used them to attack surface merchant ships during World War I (1914–18), submarines initially played a significant role in naval warfare. Torpedo's, a type of self-propelled underwater missile used by submarines, were used as their main armament in such attacks. In World War II (1939–1955), submarines participated in similar operations on a bigger scale, in both the Atlantic (by Germany) and Pacific (by the United States).
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A car drives a total of 10 miles along Waukegan Road. Along the road the speed limit is 35 mph but there are many stop lights along the drive. The average speed of driving the 10 miles would be:
a: Lower than 35 mph
b: Exactly 35 mph
c: Some speed that cannot be calculated
d: Greater than 35 mph
Answers
The average speed of driving the 10 miles would be lower than 35 mph.
What is average speed?
The average speed of an object is the ratio of the total distance to the total time of motion of an object.
Mathematically, average speed of an object is given as;
v(average) = total distance / total time
The average speed of a car decreases with increase in the total time of motion.
Due to the many stop lights along the drive, the total of motion of the car will increase will the total distance traveled by the car (10 miles) will be constant.
Also, since the speed limit is 35 mph, the average speed of the car will lower than the 35 mph speed limit.
Thus, the average speed of driving the 10 miles would be lower than 35 mph.
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any moment in time, the object can be stationary, moving to the right, moving to the left, or turning around. identify the motion of the object at each time provided.
Answers
Answer:
well....to every direction the body moves towards the force exerted is conducted in the opposite direction of motion.....when it turns around force exerted is not opposite but rather non directional...
in a certain city, electricity costs $0.10 per kw⋅h. what is the annual cost for electricity to power a lamppost for 7.00 h per day with a 100. w incandescent light bulb versus an energy efficient 25 w fluorescent bulb that produces the same amount of light? assume 1 year
Answers
The annual cost for electricity to power a lamppost for 7.00 h per day with a 100 W incandescent light bulb versus an energy efficient 25 W fluorescent bulb is $25.55 and $6.3875 respectively.
The Power is the amount of Energy produced per unit time.
The general formula for the annual cost can be written as:
[tex]Cost = P\cdot t\cdot d[/tex]
where. P is power, t is time in hours per day, and d is the total days.
Using the formula:
The cost of a 100 W incandescent light bulb:
[tex]Cost=(0.1)(7)(365)(0.10)=\$25.5[/tex]
Similarly,
The cost of a 25 W fluorescent light bulb:
[tex]Cost=(0.025)(7)(365)(0.10)=\$6.3875[/tex]
Hence, the annual cost is $25.55 and $6.3875 respectively.
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A pion at rest (mπ = 273 me) decays to a muon (mµ = 207 me) and an antineutrino (m-v≈0) . The reaction is written π-→ µ- + v-. Find (a) the kinetic energy of the muon
Answers
The kinetic energy of the muon is 4.08 MeV
Given that:
A pion (mπ = 273 me)
muon (mµ= 207me)
Neutrino (mv=0)
(Let’s assume that c =1, and that me= 0.511MeV)
Since the pion is at rest conversation of momentum dictates that the momenta of the muon and the neutrino be equal in magnitude,
P_μ=P_v (1)
Since the pion is at rest its energy equals its mass, E_π=m_π. Since the neutrino is massless its energy equals its momentum E_v=P_v . By conservation of energy,
E_π=E_μ+E_v, so
E_μ=m_π-P_v (2)
Substituting the right sides of (1) and (2) into the left side of the fundamental kinematic equation for the muon E_μ^2-P_μ^2=m_μ^2 yields
〖(m_π-P_v)〗^2-P_μ^2=m_μ^2
Solving for P_v gives (the magnitudes of) the momenta of the decay particles and the kinetic energy (equal to the total energy) of the massless neutrino,
P_v (〖=P〗_u=E_v )=((m_π^2-m_μ^2))/(2m_π )
P_v=(〖273〗^2-〖207〗^2)/(2× 273)=29.65 MeV
The kinetic energy of the muon equals its total energy minus its mass which, using (2), is
〖(m〗_π-P_v)-m_μ=4.08 MeV
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A proton is projected in the positive x direction into a region of a uniform electric field →E =(-6.00 × 10⁵) i^ N/C at t=0 . The proton travels 7.00 cm as it comes to rest. Determine (a) the acceleration of the proton,
Answers
The acceleration of the proton that is projected in the positive x direction into a region of a uniform electric field is 5.76×〖10〗^13 m/s^2
The product of the field's strength and the charge's strength yields the magnitude of the electric force acting on a charge traveling in a magnetic field region.
The electric force magnitude acting on the charge is expressed in the equation below.
F=|→E|×|q|
F=|-6.00×〖10〗^5 N/C|×||+1.602×〖10〗^(-19) C|
F=9.612×〖10〗^(-14) N
Newton's second law of motion states that the magnitude of a force is equal to the product of a proton's mass and its acceleration. Where the magnitude of the acceleration of the proton is ;
a=F/m
Where F is the force and m is the mass;
Inserting the values into the equation,
a=(9.612×〖10〗^(-14) N)/(1.67×〖10〗^(-27) kg)
a=5.76×〖10〗^13 m/s^2
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A single-turn square loop of wire, 2.00 cm on each edge, carries a clockwise current of 0.200 A . The loop is inside a solenoid, with the plane of the loop perpendicular to the magnetic field of the solenoid. The solenoid has 30.0 turns/cm and carries a clockwise current of 15.0A . Find (b) the torque acting on the loop.
Answers
The torque acting on the loop will be zero .
The torque on a current-carrying loop in a uniform magnetic field 'B' .The loop carries a current ' I ', has 'N' turns, each of area 'A' , and the loop makes an angle θ with the field B is given by [tex]T=NIABsin\theta[/tex] ...(1)Torque are often outlined because the movement equivalent of a linear force. The line around that Associate in Nursing object rotates is termed the axis of rotation. In physics, force is just the tendency of a force to twist or twist.The diagram is given below.
From the diagram , vector of the loop and therefore the force field are parallel to every different which suggests sin 180 ° whose worth is zero.
On putting the value of sin180 in equation (1) , we get
[tex]T=NIAB\times0\\T=0[/tex]
Torque acting on the loop will be zero .
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please help in answering these 3 questions in science!!
(picture of questions attached)
Answers
Can you please answer with clear working out .
Answers
b) the student did walk to training at a steady speed bc the slope of the line represents the velocity ( or speed), and the line is linear rather than polynomial or curved.
c) average speed = change in position( displacement) / change in time
final position- initial position / final time -initial time
0m-0m = 0 m OR -450m - +450m =0m
650sec-0sec = 650 sec
0/650 =0m/s
answer to c is 0 m/s
> this makes sense bc the velocity is constant meaning there wouldn’t be a slope on a velocity time graph.
suppose that you are a scientist studying tree rings in a cross-section of an ancient tree. what could several narrow tree rings in a row tell you about the climate when those rings were formed?
Answers
Several narrow tree rings in a row tell us that it was formed in the warm season.
What is a tree?Trees are those plants that grow very tall. We can see that ancient trees play an important role in the determination of the age of some fossils. The patterns of the rings that could be found in these trees also help us to know how old the particular tree is and especially the whether condition of the place around the time that the tree was formed.
This has been corroborated by a lot of biological evidences that show to tat effect. It can also tell us about the weather condition in a place at a particular time.
As such, several narrow tree rings in a row tell us that it was formed in the warm season.
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(a) what is the wavelength of a 2.4 ghz sine wave in inches? (b) what is the most efficient length in inches of a monopole antenna transmitting at 2.4 ghz? 2. calculate the frequency of an electromagnetic wave in free space having a wavelength of 12 cm.
Answers
The wavelength of a 2.4 ghz sine wave is 0.5 inches.
What is wavelength?In physical science, the frequency is the spatial time of an occasional wave the distance over which the wave's shape rehashes. Albeit X-beams have numerous advantageous applications, utilizing them requires alert since openness can cause visual deficiency, malignant growth and different wounds. Frequency and recurrence are conversely related so that more drawn out waves have lower frequencies, and more limited waves have higher frequencies. Frequency addresses the distance between two successive recurrence wave tops and is normally used to portray the electromagnetic range.
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M A family ice show is held at an enclosed arena. The skaters perform to music with level 80.0 dB . This level is too loud for your baby, who yells at 75.0 dB. (b) What is the combined sound level?
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A family ice show is held at an enclosed arena. The skaters perform to music with level 80.0 db. This level is too loud for your baby, who yells at 75.0 db. 155 db. is the combined sound level.
What is intensity?In physical science, the force or motion of brilliant energy is the power moved per unit region, where the region is estimated on the plane opposite to the heading of spread of the energy. Light force assumes an essential part. With expanded light the fish' s vision improves, and they will turn out to be more careful about hunters.
The formula for intensity is given by, I = P A. Where I am the intensity, P is the power and A is the area of cross section.
The sun' s point decides how much light entering the water. As would be normal, the most elevated measure of sun-based force happens on the globe right where the sun is above and as the point of the sun brings down, the sun-oriented power declines.
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During the your European vacation, you are hanging out at the beach at the gold coast of Spain. As you are laying in your chaise lounge soaking up the warm Mediterranean sun, a large glob of seagull poop hits you in the face. You estimate the impact velocity at 40.2 m/s. Neglecting air resistance, calculate how high up the seagull was flying when it pooped. (TWO decimal places!!)
Answers
The height at which the seagull was flying is 82.45 m.
What is height of motion?
The height of motion or maximum height in projectile motion occurs when the object reaches a vertical velocity of zero magnitudes.
The height at which the seagull was flying is calculated as follows;
v² = u² - 2gh
where;
v is the final velocity at the maximum heightu is the initial velocity at the initial heightg is acceleration due to gravityh is the maximum height0 = u² - 2gh
2gh = u²
h = u²/2g
h = (40.2²) / (2 x 9.8)
h = 82.45 m
Thus, the height at which the seagull was flying is 82.45 m.
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If a car's instantaneous velocity going down a ramp at 40cm is 2,105.3cm/s, predict the velocity of the car when it has traveled a distance of 70cm.
Answers
The velocity of the car will be 36.8 m/s when it has traveled a distance of 70 cm.
What is Instantaneous velocity?The velocity at any moment in time during a particle's motion is given by instantaneous velocity, a continuous function of time. By calculating the derivative of the position function, which gives us the functional form of instantaneous velocity v, we may determine the instantaneous velocity at a certain time (t).
Velocity is a vector quantity.
SI unit is m/s.
According to the question, the Given values are :
Distance =40 cm
=0.4 meter
Velocity, v =2105.3 cm/s
=21.053 m/s
21.053=0.4/t
⇒t=0.4/21.053
t=0.019 seconds
Now, the distance is 70 cm
=0.70 meters
v=0.7/0.019
v=36.8 m/sec
Hence, the velocity will be 36.8 m/sec when it has traveled a distance of 70 cm.
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A vertical cylinder with a heavy piston contains air at 300 K . The initial pressure is 2.00 ×10⁵Pa , and the initial volume is 0.350m³ . Take the molar mass of air as 28.9 g/mol and assume CV = 5/2 R .(b) Calculate the mass of the air in the cylinder.
Answers
The mass of the air in the cylinder will be 0.811 Kg.
What is an ideal gas equation?The ideal gas law also referred to as the generic gas equation, is the equation of state for a hypothetical perfect gas. It is a good approximation of the behavior of several gases under diverse conditions, despite significant limitations.
Given that a vertical cylinder with a heavy piston contains air at 300 K . The initial pressure is 2.00 ×10⁵Pa, and the initial volume is 0.350m³. Take the molar mass of air as 28.9 g/mol.
The mass of the air in the cylinder will be calculated as below:-
P₁V₁ = nRT₁
n = ( P₁V₁ / RT₁ )
( m / M ) = ( P₁V₁ / RT₁ )
m = ( P₁V₁ M / RT₁ )
m = ( P₁V₁ M / RT₁ ) = ( 2 x 10⁵ x 0.35 x 0.0289 ) / ( 8.314 x 300 )
m = 0.811 Kg
Therefore, the mass of the air in the cylinder will be 0.811 Kg.
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rearrange equations for the said varibles
Answers
The given equations of motion are rearranged for the said variables.
In the given equations of motion, the variables used represents:
[tex]v_{f}[/tex] = Final velocity
[tex]v_{i}[/tex] = Initial velocity
Δx = Displacement
a = Acceleration
t = Time
The given equations that are rearranged for said variables are as follows.
t = 2 Δx / ( [tex]v_{i} +v_{f}[/tex] )[tex]v_{f}[/tex] = ( 2 Δx / t ) - [tex]v_{i}[/tex][tex]v_{i}[/tex] = ( Δx / t ) - ( a t / 2 )a = ( 2 Δx / t² ) - ( 2 [tex]v_{i}[/tex] / t )[tex]v_{i}[/tex] = √ ( [tex]v_{f}[/tex]² - 2 a Δx )Δx = ( [tex]v_{f}[/tex]² - [tex]v_{i}[/tex]² ) / 2 a[tex]v_{f}[/tex] = ( Δx / t ) + ( a t / 2 )Therefore, the given equations of motion are rearranged above for the said variables.
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which of statements about the skateboarder's energy is true? as he travels from the top of the ramp to the bottom, ke turns into pe. as he travels from the bottom of the pipe to the top, ke turns into pe. if friction is present, mechanical energy will be conserved. the pe is the greatest at the bottom of the ramp.
Answers
The statements about the skateboarder's energy is true option C which is if friction is present, mechanical energy will be conserved. the pe is the greatest at the bottom of the ramp.
What is energy?
Energy is the ability to perform a task or do work. Energy can be potential or kinetic energy. Potential energy is the energy posses by a body in a state of rest while kinetic energy is the energy in motion.
As the skateboarder travels the ramp, potential energy turn to kinetic energy and if friction is present some of the energy in the system is converted to heat energy.
Therefore, The statements about the skateboarder's energy is true option C which is if friction is present, mechanical energy will be conserved. the pe is the greatest at the bottom of the ramp.
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Consider (a) an electron (b) a photon, and (c) a proton, all moving in vacuum. Choose all correct answers for each question. (v) Which move at the speed of light?
Answers
Photon move at the speed of light which is option (b)
An electron is a solid negatively charged factor of an atom. Electrons exist outdoor of and surrounding the atom nucleus. Each electron includes one unit of bad charge (1.602 x 10^-19 coulomb)A proton is a subatomic particle discovered with inside the nucleus of each atom. The particle has a advantageous electric charge, identical and contrary to that of the electron. A photon is a subatomic particle, having strength and momentum however no mass or electric powered charge, this is the quantum unit of electromagnetic radiation, together with light.As electrons and protons are particles of the atoms and posses mass so they do not move at the speed of light even in vaccum.
Photon is a light energy so it moves with the speed of light .
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An airplane is flying at 200 m/s at an angle of 30° north of east. How fast is the
plane flying North?
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in a rear tire skid when the rear wheel is not in line with the front wheel, you want to release the rear brake to quickly straighten the motorcycle.
Answers
False, because in a rear tire skid when the rear wheel is in line with the front wheel, you want to release the rear brake to quickly straighten the motorcycle.
What happens if the back wheel of your motorcycle locks up and starts to skid?
Understanding the rationale behind each correct response on the motorcycle written test is crucial for passing your motorbike permit examinations and developing into a safe rider.
When riding a motorcycle, a rear wheel skid can be a risky circumstance to encounter.
When the rear wheel locks up as a result of excessive braking, rear wheel skids happen.
You won't be able to turn around if the rear wheel locks up and starts to slide.
You must relieve the pressure on the rear brakes to stop the skidding of the rear wheels. However, the bike might quickly straighten out and knock you off in a high-side crash if the front and rear wheels are not in line when you remove the rear brake.
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a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration through the board, and emerges with a speed of 345 m/sm/s.
Answers
the average acceleration of the bullet through the board -55657×10⁵ m/s²
acceleration- Rate of change of velocity with respect to time.
S = 0.10 mm = 10⁻⁵ m ( distance) [∵ 1mm = 10⁻³]
u = 480 m/s (initial velocity)
v = 345 m/s (final velocity)
As we know the 3rd equation of motion.
v² = u² + 2aS
a = ? ( acceleration)
using these values in equation we get
(345)² = (480)² + 2×a× 10⁻⁵
a = (345)² - (480)² / 2× 10⁻⁵
a = -55657×10⁵ m/s²
The negative sign shows that the direction of acceleration is opposite of velocity thus bullet is slowing down.
the average acceleration of the bullet through the board -55657×10⁵ m/s²
The given question is incomplete. The complete question is.
a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration through the board, and emerges with a speed of 345 m/sm/s.
What is the average acceleration of the bullet through the board/?
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5. Find the velocity of a train that traveled 75 km in 35 minutes. (answer
in m/s). Conversion factors: 1000 m = 1 km; 60 s = 1 min.
Answers
75km=75000m
35min=2100 seconds
Velocity=Displacement/Time
=75000/2100
=750/21
=35.71 m/s
a pupil with a mass of 55kg swinging back on a chair and falling off at a speed of 0.6 m/s
Answers
The Kinetic energy of the pupil with mass of 55kg swinging back on a chair and falling off at a speed of 0.6 m/s is "9.9 J".
Kinetic energy is defined as the energy possessed by a body due to the virtue of velocity.
the S.I. unit of Kinetic energy is joule .
Kinetic energy is conserved.
velocity is defined as the displacement per unit time.
S.I unit of velocity is m/s.
given:
Mass (m) = 55 kg
velocity (v) = 0.6 m/s
Kinetic energy(K)=1/2×mv²
Kinetic energy (K)=1/2×55×0.36
Kinetic energy (K)= 9.9 joule
therefore,
The Kinetic energy of the pupil with mass of 55kg swinging back on a chair and falling off at a speed of 0.6 m/s is "9.9 J".
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what is the direction of the electric field at any point on the z axis? view available hint(s)for part a what is the direction of the electric field at any point on the z axis? parallel to the x axis parallel to the y axis parallel to the z axis in a circle parallel to the xy plane
Answers
The direction of electric field at any point of z axis is always positive because of the symmetry property.
ELECTRIC FIELD - It is a force that fills the space around every charge in space.
It is a physical quantity. It represents the vector field that is generated by a charge in the area around that charge. It is defined as the electric force per unit test charge that placed at distance from the charged that generate the electric field.
the electric field is outward from the positive charge and inward negative point charge.
The direction of electric field at any point of z axis is always positive because of the symmetry property.
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An object of mass 0. 85 kg is initially at rest. When a force acts on it for 2. 9 ms it acquires a speed of 10. 6 m/s. Find the magnitude (in n) of the average force acting on the object during the 2. 9 ms time interval. (enter a number. )
Answers
By using uniform motion, the average force is 3106.89 N.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 0 m/s
vt = 10.6 m/s
m = 0.85 kg
t = 2.9 ms = 2.9 x 10¯³ second
Find the acceleration by using the first equation
vt = vo + a . t
10.6 = 0 + a. 2.9 x 10¯³
a = 3655.17 m/s²
Find the average force
F = m . a
F = 0.85 . 3655.17
F = 3106.89 N
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Most data security breaches can be prevented.
A.
True
B.
False
Answers
Answer:
A?
Explanation:
i don't know correct me if i'm wrong