Answer:
a) pridm sin θ₂ = (sin θ) / n
b) red sin θ= mλ/a
Explanation:
The scattering of light in its spectrum occurs by two different phenomena. In the case of the prism, light is scattered because the index of refraction of the material depends on the wavelength, according to the law of refraction.
n₁ sin θ₁ = n₂ sin θ₂
if the cousin is in the air n1 = 1 and n2 is the refractive index of the prism
sin θ₂ = (sin θ) / n
Since the refractive index depends on the wavelength, light is scattered in its spectrum.
For the diffraction grating, the dispersion adhesiveness to diffraction in multiple slits, and is described by the expression
a sin θ = mλ
sin θ= mλ/a
where m is an integer indicating the order of the spectrum, the separation is due to the change in wavelength.
In black the separation of the network is much greater in the network because a is very small and in the prism the change of the index of refraction is small.
Part E Now convert the time from seconds to years. This value is the approximate age of the universe. Write the age in scientific notation. Use the conversion, 1 year = 3.154 × 107 seconds.
Explanation:
The age of the universe is 13.8 billion years.
We know that,
1 billion years = 10⁹ years
So,
[tex]13.8\ \text{billion years}=13.8\times 10^9\ \text{years}[/tex]
We need to convert the age of the universe to the scientific notation.
Since, [tex]1\ \text{year}=3.154\times 10^7\ s[/tex]
So,
[tex]13.8\times 10^9\ \text{years}=13.8\times 10^9\times 3.154 \times 10^7\\\\=4.35\times 10^{17}\ s[/tex]
So, the age of the universe is [tex]4.35\times 10^{17}\ s[/tex].
Answer:
So the universe is approximately 1.34 x 10^10 years old
Explanation:
Edmentum
A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The coefficient of kinetic friction between the box and the floor is 0.23. What is the box's launch speed?
Answer:
ugmd = 1/2 kx²
d = (1/2 kx²) / (ugm)
= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)
= 7.4 m
ugmd = 1/2 mv²
v = √2ugd
= √(2(0.23)(9.81 m/s²)(7.4 m)
= 5.8 m/s
Explanation:
The box's launch speed is 5.8 m/s.
What is energy?Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Given in question spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor,
ugmd = 1/2 kx²
d = (1/2 kx²) / (ugm)
= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)
= 7.4 m
ugmd = 1/2 mv²
v = √2ugd
= √(2(0.23)(9.81 m/s²)(7.4 m)
= 5.8 m/s
The box's launch speed is 5.8 m/s.
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How do you find time with current and charge
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Current Electricity .
Since we know that, Current is Charge per unit time.
so we get as,
Q = I*t
here, Q = charge, I = current, t = time.
The magnetic field in a cyclotron is 1.25 T, and the maximum orbital radius of the circulating protons is 0.40 m. (a) What is the kinetic energy of the protons when they are ejected from the cyclotron
Answer:
1.92 x 10⁻¹²J
Explanation:
The magnetic force from the magnetic field gives the circulating protons gives the particle the necessary centripetal acceleration to keep it orbiting round the circular path. And from Newton's second law of motion, the force(F) is equal to the product of the mass(m) of the proton and the centripetal acceleration(a). i.e
F = ma
Where;
a = [tex]\frac{v^2}{r}[/tex] [v = linear velocity, r = radius of circular path]
=> F = m[tex]\frac{v^2}{r}[/tex] ------------(i)
We also know that the magnitude of this magnetic force experienced by the moving charge (proton) in a magnetic field is given by;
F = q v B sin θ ----------(ii)
Where;
q = charge of the particle
v = velocity of the particle
B = magnetic field
θ = the angle between the velocity and the magnetic field.
Combining equations (i) and (ii) gives
m[tex]\frac{v^2}{r}[/tex] = q v B sin θ [θ = 90° since the proton is orbiting at the maximum orbital radius]
=> m[tex]\frac{v^2}{r}[/tex] = q v B sin 90°
=> m[tex]\frac{v^2}{r}[/tex] = q v B
Divide both side by v;
=> m[tex]\frac{v}{r}[/tex] = qB
Make v subject of the formula
v = [tex]\frac{qBr}{m}[/tex]
From the question;
B = 1.25T
m = mass of proton = 1.67 x 10⁻²⁷kg
r = 0.40m
q = charge of a proton = 1.6 x 10⁻¹⁹C
Substitute these values into equation(iii) as follows;
v = [tex]\frac{(1.6*10^{-19})(1.25)(0.4)}{(1.67*10^{-27})}[/tex]
v = 4.79 x 10⁷m/s
Now, the kinetic energy, K, is given by;
K = [tex]\frac{1}{2}[/tex]mv²
m = mass of proton
v = velocity of the proton as calculated above
K = [tex]\frac{1}{2}(1.67*10^{-27} * (4.79 * 10^7)^2 )[/tex]
K = 1.92 x 10⁻¹²J
The kinetic energy is 1.92 x 10⁻¹²J
we can catch a rolling ball but not a flying bullet?? give reason
Answer:
yeah this statement is tru
Explanation:
it is because the speed of the bullet is more than the speed of rolling ball .so from this reason we cannot catch a bullet.
A bullet will be moving much faster than a rolling ball. Even seeing a bullet in flight requires it to be extremely low velocity.
On January 22, 1943, in Spearfish, South Dakota, the temperature rose from −4.00°F to 45.0°F over the course of two minutes (the current world record for the fastest recorded temperature change). By how much did the temperature change on the Celsius scale?
Answer:
The change on the Celsius scale is 27.22 °C.
Explanation:
The conversion of Fahrenheit to Celsius is the following:
[tex]T = \frac{5}{9}(^{\circ} F - 32)[/tex]
So, we need to convert T₁ and T₂ from °F to °C:
[tex]T_{1} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(- 4 - 32) = -20 ^{\circ} C[/tex]
[tex]T_{2} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(45 - 32) = 7.22 ^{\circ} C[/tex]
Hence, the change on the Celsius scale is:
[tex] \Delta T = T_{2} - T_{1} = 7.22 - (-20) = 27.22 ^{\circ} C [/tex]
Therefore, the change on the Celsius scale is 27.22 °C.
I hope it helps you!
A body is thrown vertically upwards, remaining 4s in the air. Calculate the maximum height that the body reaches.
Answer:
20 m
Explanation:
Given:
v = 0 m/s
a = -10 m/s²
t = 4 s / 2 = 2 s
Find: Δy
Δy = vt − ½ at²
Δy = (0 m/s) (2 s) − ½ (-10 m/s²) (2 s)²
Δy = 20 m
analyze this physics mystery and be marked brainliest
Answer:
The two middle chains are for suspension of the glass surface, while the fours chains at all corners prevents tilting
Explanation:
From the picture, the the frame bearing the glass surface is suspended by the two metal chains at the middle,
While the balance to avoid tilting to either directions is maintained by the four chains at all corners.
You are given three pieces of wire that have different shapes (dimensions). You connect each piece of wire separately to a battery. The first piece has a length L and cross-sectional area A. The second is twice as long as the first, but has the same thickness. The third is the same length as the first, but has twice the cross-sectional area. Rank the wires in order of which carries the most current (has the lowest resistance) when connected to batteries with the same voltage difference.
A. Most Current
B. Wire of length L and area 2A
C. Wire of length L and area A
D. Wire of length 2L and area A
E. Least Curren
Answer:
Explanation:
Resistance of first wire
R₁ = ρL / A where ρ is specific resistance
for second wire the resistance
R₂ = ρ2L / A = 2 ρL / A
For third wire
R₃ = ρL /2 A
The resistance is in the order
R₂ > R₁ > R₃
So , current will be maximum in R₃
I₃ > I₁ > I₂
Where I₁ , I₂ and I₃ is current in first , second and third wire .
3.) [15 points] A physics teacher is on the west side of a small lake and wants to swim across and up at a point directly across from his starting point. He notices that there is a current in the lake and
that a leaf floating by him travels 4.2m [S] In 5.0s. He is able to swim 1.9 m/s in calm water,
(a) What direction will he have to swim in order to arrive at a point directly across from his position?
Answer:
The teacher should swim in a direction 29.24° North of East
Explanation:
Given that the there is a water current across the lake, and the physics teacher intends to swim directly across the lake, the direction the physics teacher will have to swim is found as follows;
The speed of the water current is given by the speed of the floating leaf traveling with the water current
Distance traveled by the leaf = 4.2 m South
Time of travel of the leaf = 5.0 s
Speed of leaf = 4.2/5 = 0.84 m/s = Speed of the water current
Swimming peed of the teacher, v = 1.9 m/s
To swim directly across the lake, the teacher has to swim slightly in the opposite direction of the water current, the y-component of the teacher's swimming speed should be equal to and opposite that of the speed of the water current.
Y-component of v = v×sin(θ), where θ is the angle of the direction, the teacher should swim
Therefore;
1.9 × sin(θ) = 0.84
sin(θ) = 0.84/1.9 = 0.44
θ = 26.24°
That is the teacher should swim in a direction 29.24° North of East.
To cross the lake the teacher has to swim in a direction 29.24° North of the East
Finding the direction of speed required:
The speed of the water current can be derived from the speed of the floating leaf :
The distance traveled by the leaf L = 4.2 m South
Time taken T = 5s
So, the speed of the leaf is:
u = 4.2/5
u = 0.84 m/s South
So, the speed of the current is 0.84 m/s South
Now, it is given that the speed of the teacher is, v = 1.9 m/s East
To cross the lake the speed of the teacher must be in a Northeast direction so that the North component of the speed of the teacher cancels out the speed of the current which is directed towards the South.
Let, the speed of the teacher makes an angle of θ from the EAST.
So, the North component is given by:
v(north) = vsinθ
it must be equal to the speed of the current:
vsinθ = u
1.9 × sinθ = 0.84
sinθ = 0.84/1.9
sinθ = 0.44
θ = 26.24°
The teacher should swim in a direction 29.24° North of East.
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car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of a. The car makes it one-quarter of the way around the circle before it skids off the track.From these data, determine the coefficient of static friction between the car and the track
Answer:
0.572
Explanation:
First examine the force of friction at the slipping point where Ff = µsFN = µsmg.
the mass of the car is unknown,
The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.
First the tangential direction
∑Ft =Fft =mat
And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r
Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2
So going backwards and plugging in Ffc =m2atπr/ 2r =πmat
Ff = √(F2ft +F2fc)= matp √(1+π²)
µs = Ff /mg = at /g √(1+π²)=
1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572
Suppose a 50.0 g block of silver (specific heat = 0.2350 J/g·°C) at 100.°C is placed in contact with a 50.0 g block of iron (specific heat = 0.4494 J/g·°C) at 0.00°C, and the two blocks are insulated from the rest of the universe. The final temperature of the two blocks will be:
Answer:
34.34 °C
Explanation:
From the question,
Heat lost by the silver block = heat gained by the iron block.
cm(x-y) = c'm'(y-z)................... Equation 1
Where c = specific heat capacity of the silver block, m = mass of the silver block, c' = specific heat capacity of the iron, m' = mass of the iron. x = initial temperature of the silver block, z = initial temperature of the iron, y = final temperature of the mixture.
make y the subject of the equation
y = (cmx+c'm'z)/(cm+c'm')............... Equation 2
Given: c = 50 g, c = 0.2350 J/g·°C, x = 100°C, m' = 50 g, c' = 0.4494 J/g.°C, z = 0°C
Substitute these values into equation 2
y = [(50×0.2350×100)+(50×0.4494×0)]/[(50×0.2350)+(50+0.4494)]
y = 1175/(11.75+22.47)
y = 1175/34.22
y = 34.34 °C
When we double the distance between a source of light and the
surface on which it falls, the amount of illumination on the surface
decreases to
(what fraction) of the
original illumination.
The amount of lighting on a surface drops to (1/4) of the initial illumination when the distance between a light source and the surface it falls on is doubled.
What is illumination?The amount of light or luminous flux that falls on a surface is known as illumination. It is expressed as lux or lumens per square meter.
The square of the distance has an inverse relationship with the light intensity;
[tex]\rm I = \frac{1}{r^2}[/tex]
Where,
I is the light intensity
r is the distance
Let r is the distance and I is the sound intensity for case 2;
r' = 2r
[tex]\rm I' = \frac{1}{(2r)^2} \\\\ I' = \frac{1}{4r^2} \\\\ I' = \frac{I}{4}[/tex]
When we double the distance between a source of light and the surface on which it falls, the amount of illumination on the surface decreases to(1/2) of the original illumination.
Hence the value of the fraction is 1/4.
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For the electric circuit given below, calculate: 3 (i) the equivalent resistance of the circuit, (ii) the total current drawn from the battery and (iii) the voltage across 7Ω resistor.
Answer:
1)31/3Ω
2)18/31A
3)4.06V
Explanation:
According to the diagram and 10 Ω resistors are parallel to each other, parallel resistor can be calculated using the formula below
1/R= 1/R1 + 1/R2
But we know R1= 5 Ω and R2= 10 Ω
1/R= 1/5 + 1/10
R= 10/3 Ω
=3.33 Ω
Then if we follow the given figure, 10/3 Ω and 7Ω are now in series then
Req = 10/3 +7
Req= 31/3 Ω
Therefore, equivalent resistance = 31/3 Ω
According to ohms law we know that V= IR
Then I= V/R
Where I= current
R= resistance
V= voltage
I= 6/(31/3)
I= 18/31A
We can now calculate the voltage accross the resistor which is
V=(18/31)× 7
V=4.06V
Therefore, the voltage accross the 7 ohm resistor is 4.06V
CHECK THE FIQURE AT THE ATTACHMENT
A duck is 12 m from the edge of a pond. A student stands in the middle of the pond
and creates ripples that travel past the duck and towards the edge of the pond. The
ripples are produced uniformly at 2 ripples per second. The student determines that
the ripples take 3.0 seconds after they pass the duck to reach the edge of the pond.
Determine the wavelength of the ripples.
Answer:
The wavelength is 2 meters
Explanation:
The relationship between the frequency, the speed and the wavelength is given by the relation;
v = f × λ
The given parameters are;
The distance of the duck from the edge of the pond = 12 m
The number of ripples produced per second = Frequency, f = 2 Hz
The time it takes the ripple to reach the edge of the pond after travelling past the duck = 3 seconds
Therefore, speed of the wave, v = Distance/time = 12 m/(3 s) = 4 m/s
The wavelength, λ, is therefore;
λ = v/f = (4 m/s)/(2 Hz) = 2 meters.
(blank)a0 is undeniably accepted by scientists all over the world as the primary language of science.
Answer:
English.
Explanation:
English is undeniably accepted by scientists all over the world as the primary language of science. It is a language spoken all over the world and is also the language of science because it is an official language and can be understood by almost everyone.
Answer:
[tex]\boxed{\mathrm{English}}[/tex]
Explanation:
English is undeniably accepted by scientists all over the world as the primary language of science. The scientific methods and experiments are done by communicating and writing in English. Scientists use English to communicate and share knowledge as English is understood by people from around the world.
What is the ball's acceleration?
Answer:
g, downward
Explanation:
It is given that, a baseball is thrown straight upward. The force acting on the stone is force of gravity. It is moving under the action of gravity. We know that the force of gravity always acts in a downward direction.
At the highest point, the velocity of the stone will be equal to 0. It will move will constant acceleration equal to g and it always acts in downward direction.
Hence, the correct option is (e) "downward direction".
Choose the correct answer/s
refer to the attachment for the explanation
Find the speed of the mobile after 4 seconds
Answer:
27 m/s
Explanation:
V_final = v_initial + a*t
V_final = 15 + 3 * 4
V_final = 27 m/s
Radar uses radio waves of a wavelength of 2.5 m . The time interval for one radiation pulse is 100 times larger than the time of one oscillation; the time between pulses is 10 times larger than the time of one pulse. What is the shortest distance to an object that this radar can detect
Answer:
The minimum distance to the object that the radar can detect is 124.995 m
Explanation:
Here, we are to calculate the shortest distance to an object the radar in the question can detect.
Mathematically;
v = c/λ
Where v is the frequency, c is the speed of light and λ is the wave length
Thus;
v = (3 * 10^8)/2.5 = 1.2 * 10^8 Hz
Mathematically, the time period
t = 1/v = 1/(1.2 * 10^8) = 0.000000008333 = 8.333 * 10^-9 sec
From the question, we are told that the transmitting time is 100 times a single oscillation
Transmitting time = 100 * one oscillation
Hence Transmitting time = 100 * 8.33 * 10^-9 = 8.33 * 10-7
Mathematically;
Minimum distance =( Transmitting time * speed of light)/2 =
(8.33 * 10^-7 * 3 * 10^8)/2 = 124.995 m
Earthquakes at fault lines in Earth's crust create seismic waves, which are longitudinal (P-waves) or transverse (S-waves). The P-waves have a speed of about 9 km/s. Estimate the average bulk modulus of Earth's crust given that the density of rock is about 2500 kg/m3
Answer:
[tex]B=2.025\times 10^{11}\ Pa[/tex]
Explanation:
It is given that,
Speed of P- waves, v = 9 km/s = 9000 m/s
The density of rock is about [tex]2500\ kg/m^3[/tex]
We need to find the average bulk modulus of Earth's crust. Let it is given by B. So,
[tex]v=\sqrt{\dfrac{B}{d}} \\\\B=v^2d\\\\B=(9000)^2\times 2500\\\\B=2.025\times 10^{11}\ Pa[/tex]
So, the bulk modulus of the Earth's crust is [tex]2.025\times 10^{11}\ Pa[/tex].
Unpolarized light, with an intensity of I0, is incident on an ideal polarizer. A second ideal polarizer is immediately behind the first and its axis of polarization is oriented at an angle of 60° relative to the first polarizer’s. How much of the light will be transmitted through the system?
Answer:
The light transmitted through the system will be 0.125*I₀.
Explanation:
The light transmitted through the system can be found using Malus Law:
[tex] I = I_{0}cos^{2}(\theta) [/tex] (1)
Where:
I: is the intensity of the light transmitted
I₀: is the initial intensity
θ is the angle relative to the first polarizer’s = 60°
Because the light transmitted by the first polarizer is dropped by half, the equation (1) results as:
[tex] I = \frac{I_{0}}{2}cos^{2}(\theta) [/tex]
[tex] I = \frac{I_{0}}{2}cos^{2}(60) [/tex]
[tex] I = 0.125I_{0} = \frac{1}{8}I_{0} [/tex]
Therefore, the light transmitted through the system will be 0.125*I₀.
I hope it helps you!
A car travels from city A to city B separated by 282 km and the journey takes approximately 6 hours and 32 minutes. If they come back in 8 hours. What is your average speed throughout the journey? What is its average speed?
Answer:
38.8 km/hr
Explanation:
The total distance is 2 × 282 km = 564 km.
The total time is 6 hr 32 min + 8 hr = 14 hr 32 min = 14.533 hr.
The average speed is:
(564 km) / (14.533 hr)
38.8 km/hr
The plates of a parallel-plate capacitor are maintained with a constant voltage by a battery as they are pushed together, without touching. How is the amount of charge on the plates affected during this process
Answer:
The amount of charge increases.
Explanation:
For a capacitor that has its plates still connected to a battery, the voltage on the capacitor remains constant. If the distance between the two plates of this capacitor is decreased, the capacitance will increase, and then the charge on the plate will increase in accordance with the relationship
Q =CV
From this relationship, if V is held constant, then Q has to increase for C to increase also.
Runner 1 has a velocity of 10 m/s west. Runner 2 has a velocity of 7 m/s east. From the frame of reference of runner 2, what is the velocity of runner 1? A.17 m/s east. B.3 m/s east. C.17 m/s west. D.3 m/s west
Answer:
17 m/s west
Explanation:
Runner 1 has velocity = 10 m/s west
runner 2 has velocity = 7 m/s east
From the frame of reference of runner 2, we can imagine runner 2 as standing still, and runner 1 moving away from him, towards the west with their combined velocity of
velocity = 10 m/s + 7 m/s = 17 m/s west
Answer:
17 m/s west
Explanation:
Hope this helps!
define the term 'one solar mass.'
Answer:
the mass of one sun
Explanation:
its really heavy
Q. A train accelerates from 36 km/h to 54 km/h in 10 sec. (i) Acceleration (ii) The distance travelled by car.
u=10m/s
v=15m/s
acceleration=
v_u/ t
5/10
0.5
FORENSIC SCIENCE, PLEASE HELP ASAP Investigators find a hair clasped in the fist of a dead victim. Upon close examination, they realize there is follicular tissue attached to that hair. What could investigators use to prove that the hair in the victim's fist belonged to a specific suspect? A) The medulla. B) Nuclear DNA. C) Mitochondrial DNA. D) Physical comparison.
Answer:
C) Mitochondrial DNA
Explanation:
Mitochondrial DNA can help forensic scientists in recovering the follicular tissue that is attached to the hair, they can find out the specific suspect from that hair.
Mitochondrial DNA is maternally inherited and enables forensic scientists to trace maternal lineage.
Answer:
Mitochondrial DNA
Explanation:
Mitochondrial DNA should be used to prove that the hair in the victim's fist belonged to a specific suspect. Mitochondrial DNA enables scientists to trace maternal lineage from which it can be known that who is the suspect.
Define centre of gravity and centre of Bouyancy
Answer:
Center of Gravity is the point in a body where the gravitational force may be taken to act. Center of Buoyancy is the center of gravity for the volume of water which a hull displaces.
(a) In electron-volts, how much work does an ideal battery with a 17.0 V emf do on an electron that passes through the battery from the positive to the negative terminal? (b) If 3.88 × 1018 electrons pass through each second, what is the power of the battery?
Answer:
(a) 17.0eV
(b) 10.55W
Explanation:
(a) The amount of work done (W) on an electron by an ideal battery of emf value of V as it moves from the positive to the negative terminal is given by;
W = q x V --------(i)
Where;
q = charge on the electron = 1e
From the question;
V = 17.0 V
Substitute the values of q and V into equation (i) as follows;
W = 1e x 17.0
W = 17.0eV
Therefore, the work done in electron volts is 17.0
(b) The power (P) of the battery as some electrons (n) pass through it at time t, is given as;
P = (n q V) / t --------------(ii)
Where;
n = number of electrons = 3.88 x 10¹⁸
t = 1s
q = 1.6 x 10⁻¹⁹C
V = 17.0V
Substitute these values into equation (ii) as follows;
P = (3.88 x 10¹⁸ x 1.6 x 10⁻¹⁹ x 17.0) / 1
P = 10.55W
Therefore the power of the battery is 10.55W