Consider a solenoid that is very long compared with its radius. Of the following choices, what is the most effective way to increase the magnetic field in the interior of the solenoid? (a) double its length, keeping the number of turns per unit length constant (b) reduce its radius by half, keeping the number of turns per unit length constant (c) overwrap the entire solenoid with an additional layer of current-carrying wire

Answer:

(1) a) S=D/T

b)5m/s

c)3.33s

(2) a) 1.104m

Explanation:

(1) b) S=D/T

 S=1500/300

 S=5m/s

c) T= V-U/a

 v=10

 u= 2

 a= 2.4

10-2=8/2.4=3.33s

(2) a) d=s×t

 0.46×2.4=1.104m



The length of rod in terms v(r) and t is L = [  Δt / (1/343) - (1/v(r)) ].

3.56 km/s is the speed of a one-dimensional compressional wave moving along a thin copper rod.

At one end of the rod, a hard hammer strike is delivered. With a time interval of Δt between the two pulses, a listener at the other end of the rod hears the sound twice as it travels through the metal and the air.

The time interval is given by t = L/v.

We know, The speed of air, v(air) = 343 m/s

Now,

When the copper rod is swapped out for a different substance and the sound speed is measured as v(r).

The delay between pulses arrivals is:

Δt = L [(1/v(air)) - (1/v(copper))]

Then,

L = [  Δt / (1/v(air)) - (1/v(r)) ]

L = [  Δt / (1/343) - (1/v(r)) ]

Here L is the length of the rod, Δt is in seconds and v(r) is the speed of sound in the rod.

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Answer:

42- electromagnetic force

Explanation:

electrons keep orbiting around the nucleus thanks to electromagnetic force :)

hope this helped!

The question 'How do electromagnetic and mechanical waves compare?'

There are many similarities between electromagnetic waves and mechanical waves.

In Physics, both electromagnetic and mechanical waves have amplitude, wavelength, and frequency.

Electromagnetic waves can travel through empty spaces as well such as vacuums, gases, liquids, and solids.

While mechanical waves can not propagate through space they can only travel through liquids, solids, and gases.

water waves and ripples in a pool are examples of mechanical waves.

Examples of EM waves are radio signals and light waves, microwaves, and X-rays.

To put it simply, EM waves do not require a medium to travel whereas mechanical waves require a medium to propagate.

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Newton's investigations of gravity explain the truth that Jupiter has more moons than Earth.

The fact that Jupiter has more moons than Earth was first discovered by Galileo Galilei in 1610, and it was later confirmed by Newton. In addition to having more moons, it is also thought that Jupiter may be home to some of the most powerful magnetic fields in the solar system.

Every particle in the cosmos attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers, according to Newton's law of universal gravitation.

Thus, the equation for universal gravity has the following structure:

[tex]{\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}}{\displaystyle[/tex]

where r is the distance between the centers of the two objects' masses, m1 and m2 are their respective masses, G is the gravitational constant, and F is the gravitational force acting between them.

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The correct answer is; Gravity acts on all objects in the universe.

The answer above is incorrect…

Answer:

high=125m

speed up=50m s-¹

Explanation:

consider acceleration due to gravity = 10m s-²

upward as positive

in t=5s

ball rest momentarily velocity=0

you can know this by drawing s-t graph

consider the upward movement t=0-5s

we now have v=0 t=5 a= -10 and need find u

so use a=[v-u]/t

-10=[0-u]/5

-50=-u

u=50 ms-¹

then let find the displacement

s = (v+u)t*1/2

s= 50*5*1/2

s=125m

[tex]1.58\times 10^{-4}\ \mathrm{s}$[/tex] is the time interval elapses before the back end of the rod receives the message that it should stop.

Given:

Length of the rod, L = 80 cm = 0.800 m

Young's modulus, Y = [tex]20 \times 10^{10}\;N/m^{2}[/tex]

steel density, [tex]\rho = 7.86 \times 10^{3}\;kg/m^{3}[/tex]

The speed of the wave in the rod is,

[tex]$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$[/tex]

Consequently, the length of the rod's end is traveled by the wave in at

[tex]$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$[/tex]

Hence, [tex]1.58\times 10^{-4}\ \mathrm{s}$[/tex] is the time interval elapses before the back end of the rod receives the message that it should stop.

The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following paraphrase of these statutes is available

Unless a force acts upon a body, it remains at rest or in continual straight-line motion.

When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.

When two bodies exert force on one another, the direction and amount of the force are opposed.

Isaac Newton first identified the three laws of motion in his 1687 book Philosophize Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy).

They served as the cornerstone for classical mechanics as Newton used them to examine and explain the motion of numerous physical objects and systems. The conceptual foundations of classical physics have been reconstructed in several ways since Newton, utilizing various mathematical techniques that have revealed insights that were hidden in the original, Newtonian formulation.

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Explanation:

Q = charge in C(coulombs)

I = current in A(amps)

t = time in s(seconds)

Q = I × t

I = Q / t

Substitute in given values.

I = 300C / 30s

= 10A

Hope this helped! ^^

The electric current generated by a charge of 300 coulombs passing through the cross section of a conductor in a time of 30 seconds is: 10 A

To solve this exercise the formula for electric current and the procedure we will use is:

I= q/t

Where:

Information about the problem:

Applying the electric current intensity formula we have:

I= q/t

I= 300 C / 30 s

I= 10 A

In physics the intensity of the electric current is the magnitude that expresses the amount of electric charge or electric current in coulomb (c) that passes through an electrical conductor in a given time in seconds (s). Its unit of measurement in the international system is the Ampere (A).

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the magnitude of the electric field needed to balance its weight is  

0.75 ×10⁵N/C

The oil drop method was performed by Robert A Millikan in 1909.

It is used to determine the size of the charge  on an atom.

Millikan used vacuum pump oil for this his experiment.

to find out the magnitude of electric field

W = q E,

W = weight (W = mg)

q = charge (1.6×10⁻¹⁴C)

E = Electric field

→ oil drops were suspended against the gravitational force by a vertical electric field such that its weight is balanced by the electron force i.e.

W =  1.2× 10⁻¹⁴

1.2× 10⁻¹⁴ = q × E

E =  1.2× 10⁻¹⁴N/ 1.6×10⁻¹⁹C

E =  0.75 ×10⁵N/C

the magnitude of the electric field needed to balance its weight is  

0.75 ×10⁵N/C

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The distance from the speaker would the sound be barely audible is 477.46km.

It's how far away two objects or locations are measured numerically as distance. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over"). Sometimes the symbol |AB| is used to indicate how far apart two points are. "Distance from A to B" and "Distance from B to A" are typically equivalent terms. A distance function or metric in mathematics is an extension of the idea of physical distance; it defines what it means for components in a space to be "near to" or "far away" from one another. Distance is a non-numerical unit of measurement in the social sciences and psychology.

Explanation:

Sound audible(barely) = 0dB

I= 10.709*I/[tex]10^{-10}[/tex]=0

I= [tex]10^{-12}[/tex]*[tex]10^{0}[/tex]=[tex]10^{-12}[/tex]w/[tex]m^{2}[/tex]

[tex]distance(r)=\sqrt[]{\frac{P}{4\pi I} } =\sqrt[]{\frac{6}{4\pi * 10^{-12} } } =477.46 km[/tex]

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The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J

Centripetal force - a force acts on an moving object in circular path.

the centripetal force is given by

F= mv²/r       (equation1)

Work done is given by

W = Fd          (equation 2)

d = 2π

work is done by the centripetal force on mass m during an angular displacement of 2π revolutions is given by:

to calculate work done using equation 1 in 2  we get

W = mv² d/r

 W = mv² × 2π /r J

The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J

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The sofa with a top speed of 87 mph would travel a distance of 43.5 miles to the mall 1 hour away.

Considering the sofa accelerates constantly throughout the motion,

s = ( u + v )  t / 2

s = Distance

u = Initial velocity

v = Final velocity

t = Time

v = 87 mph

t = 1 hr

u = 0

s = ( u + v )  t / 2

s = ( 0 + 87 ) 1 / 2

s = 43.5 mi

This is an equation of motion.

Therefore, the sofa would travel a distance of 43.5 miles

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The wavelengths of the following quantum particles from the largest to the smallest is (d) > (a) = (e) > (b) > (c)

De Broglie's relationship is given by  [tex]\lambda=\frac{h}{mv}[/tex] .

This can be written as [tex]\lambda=\frac{h}{p}[/tex]  .....(1) where λ  is known as de Broglie wavelength and p is momentum , h = Plank’s constant .

As we know that mass of proton is greater than electron and photon .

(a)For photon , the momentum is given by [tex]p=\frac{E}{c}[/tex]     ...(2)  where c is the speed is the speed of light .

Putting E = 3eV in equation (2) , we get

              [tex]p=\frac{3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^7Js/m[/tex]

Putting this value of p in equation (1) , we get

  [tex]\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-27}}\\\lambda=4.13\times10^{-7}[/tex]

(b) As we know that  kinetic energy is given by

         [tex]K.E=\frac{1}{2} mv^2\\\\2K.E = mv^2\\2K.E\times m = m^2v^2\\2K.E\times m = (mv)^2\\2K.E\times m = p^2\\\\\sqrt{2K.E\times m }=p[/tex]      ...(3)

Where mass of electron is [tex]9.1\times10^-^3^1 kg[/tex] .

Putting K.E = 3eV in equation (3) , we get

    [tex]\sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 9.31\times10^{-31} }\\p=\sqrt{89.376\times10^{-50}} \\p=9.45\times10^{-25}Js/m[/tex]

Putting this value of p in equation (1) , we get

[tex]\lambda=\frac{6.62\times10^{-34}}{9.45\times10^{-25}}\\\lambda=0.7005\times10^{-9}[/tex]

(c) Putting [tex]m=1.67\times10^{-27}kg[/tex] and K.E = 3eV in equation (3) , we get

     [tex]\sqrt{2K.E\times m }=p\\p=\sqrt{2\times3\times1.6\times10^{-19} \times 1.67\times10^{-27} }\\p=\sqrt{16.032\times10^{-46}} \\p=4.003\times10^{-23}Js/m[/tex]

Putting this value of p in equation (1) , we get

[tex]\lambda=\frac{6.62\times10^{-34}}{4.003\times10^{-23}}\\\lambda=1.65\times10^{-11}[/tex]

(d) Putting E = 0.3eV in equation (2) , we get

   [tex]p=\frac{0.3\times 1.6\times10^-^1^9}{3\times 10^8} \\p=1.6\times10^-^2^8Js/m[/tex]

Putting this value of p in equation (1) , we get

[tex]\lambda=\frac{6.62\times10^{-34}}{1.6\times10^{-28}}\\\lambda=4.13\times10^{-6}[/tex]

(e) Putting [tex]p=3eV/c[/tex] in equation (1) , we get

    [tex]\lambda=\frac{6.62\times10^{-34}\\\times3\times10^8}{3\times1.6\times10^{-19}}\\\lambda=4.13\times10^{-7}[/tex]

On comparing the wavelength order should be (d) > (a) = (e) > (b) > (c) .

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The average rate of change of height from the initial launch to the maximum height is 180 feet.

The given function is

[tex]h(t) = -16t^{2} +120t+6[/tex]

The average rate of change of h(t) from t=a to t=b is given by:

[tex]\frac{h(b)-h(a)}{b-a}[/tex]

Vertical Velocity will be zero at maximum height. To find maximum height we differentiate the equation to get an equation for the velocity and set it to zero.

On differentiating we get,

h'(t) = -16(2)t + 120

h'(t) = -32t + 120

now equating to zero we get

t = 3.75 s

This is the time at which the rocket reaches maximum height.

The initial launch occurs at t = 0

substituting it in the original equation we get

[tex]h(t)[/tex] = [tex]-16(0)^{2}+120(0)+6[/tex]

[tex]h(t) = 6[/tex]

The average rate of change from the initial launch to the maximum height is:

[tex]\frac{h(3.75)-h(0)}{3.75-0}[/tex]

= [tex]\frac{681-6}{3.75}[/tex]

= 180

Hence the average rate of change from the initial launch to the maximum height is 180 feet.

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The force on the wire will be

F = 5.46 Newton.

We have a current carrying wire in a uniform magnetic field.

We have to determine the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is 60.0°.

The force on the current carrying wire will be -

F = IBL sinθ

According to the question, we have -

L = 2.80 m

I = 5 A

B = 0.39 T

Therefore -

F = IBL sinθ

F = 5 x 0.39 x 2.80 x sin(90)

F = 5.46 x sin(90)

F = 5.46 Newton

Hence, the force on the wire will be

F = 5.46 Newton

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The magnitude of the magnetic force on the wire 5.46 N.

To find the magnetic force, the values given are:

Length A = 2.80m

Current I = 5 A

Magnetic field B = 0.390 T

Angle = 90° .

What is meant by magnetic force?

                      F =iBLsinθ Newton

Substituting the values given,

Magnetic force,

F = 5 A × 0.390 T × 2.80 m × Sin 90°

  = 5 A × 0.390 T × 2.80 m × 1

F = 5.46 N.

The magnitude of the magnetic force on the wire 5.46 N.

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Answer: 6 km/h²

Explanation:

Final Speed= 60 km/h

Initial Speed= 30 km/h

Time= 5 sec

Now,

60= 30 + Acceleration*5

⇒Acceleration = 6 km/h²

Answer:

490N

Explanation:

the formula to use for perpendicular force is:

now we plug in:

*for g, it can be 9.8 m/s^2 or 10 m/s^2 depending on your teacher

[tex]Fg=(100)(9.8)(cos60)[/tex]

then you get:

[tex]Fg=490N[/tex]

Yes, either pole generates a field that causes atoms within the iron to rotate in order to align their magnetic moments with the exterior field.

A magnet has a significant normal force acting on the door. The magnet is then held in place by frictional force.

A magnet is defined as a magnetic field-producing item capable of attracting unlike poles and repelling similar poles.

Magnets are manufactured from a class of metals known as ferromagnetic metals. These metals include nickel and iron. These metals are unusual in their ability to magnetize consistently. When we ask how a magnet works, we mean how the magnetic field of a magnet affects the thing.

There are many different sizes and shapes of magnets.

Magnets can be found in a variety of objects and settings, including toys, cabinet hardware, ornamental pieces placed on refrigerators, and other objects and sites.

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False.While driving downhill, the gravity will cause you to go faster and increase your stopping distance.

Brakes are suddenly applied while the body is travelling at a given speed. You would have observed that after travelling a given distance, the body stops entirely. The stopping distance is that distance.

The distance travelled between the moment the body decides to stop a moving vehicle and the moment the vehicle comes to a complete stop is known as the stopping distance. The stopping distance, indicated by the letter d, is dependent on a number of variables, including as the road's surface and the driver's reflexes.

Stopping Distance formula is given by,

[tex]d=\frac{v^{2} }{2ug}[/tex]

Where,

d = stopping distance (m)

v = velocity (m/s)

μ = friction coefficient

g = the gravitational acceleration

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The measurements by the different scientists were 1.01 m, 0.99 m and 1.00 m,  which are not exactly same as the standard value of a meter. But all the three values are very much close to each other.

Meter is a fundamental unit of length in the metric system and in the International Systems of Units (SI). It is denoted by m.

Therefore the measurements for the bar kept at the international bureau of standards taken by the three scientists were precise but not accurate.

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Answer:

Who knows the answer please I need the answer

Positively charged particles of radiation emitted from the decay of radioactive substances are known as alpha particles.

A helium nucleus that some radioactive compounds release that was once thought to be a ray. Ionized alpha particles are made up of two protons, neutrons ( no charge), and no electrons.

Two protons and two neutrons from the atom's nucleus combine to form the positive charge alpha particles (α). The most toxic radioactive materials, such as uranium, radium, and polonium, decay to produce alpha particles.

A ray-like emission of a helium nucleus from some radioactive materials.

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Answer:

Sir Isaac Newton contributed significantly to the field of science over his lifetime. He invented calculus (opens in new tab) and provided a clear understanding of optics. But his most significant work had to do with forces, and specifically with the development of a universal law of gravitation and his laws of motion

Explanation:

A genius with dark secrets. Isaac Newton changed the way we understand the Universe. Revered in his own lifetime, he discovered the laws of gravity and motion and invented calculus. He helped to shape our rational world view.

The chain on the swing should be 8.0 m long .

Centripetal Acceleration ( a ) = v ² / r ........... Eq. 1

It is given that ,

a = 21 m / s ²

v = 13 m / s

Now ,  using the values of ' a ' and ' v ' i.e. 21 m / s ² & 13 m / s respectively in Eq. 1

a =  v ² / r

21 = ( 13 ) ² / r

21 = ( 13 x 13 ) / r

r = ( 13 x 13 ) / 21

r = 8.047 m

⇒ r = 8.0 m ( rounded off to nearest tenth )

Hence , the chain on the swing should be 8.0 m long .

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3.141592653589793238

Explanation:

3.141592653589793238

Answer:

a

Explanation:

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The two types of potential energies which would be types of mechanical energies are elastic and gravitational.

The correct answer choice is option D

Potential energy means the energy a body possess in relation to its position. Other forms of energy include

Kinetic energy is the energy a body possesses due to its motion.

So therefore, the two types of potential energies which would be types of mechanical energies are elastic and gravitational. The correct answer choice is option D

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Answer: it is d

Explanation: i took the unit test on edge

Answer:

you can find answer in this

Explanation:

https://physics.nist.gov/cuu/Units/units.html

If you run off the pavement, you should turn the steering wheel quickly toward the road and is denoted as option C.

This is a path which is found in almost all roads and is designed to enhance foot traffic in most climes. This is the path where individuals walk so as not to get hit down by a vehicle.

In a situation where a car runs into the pavement, the best choice is to turn the steering wheel quickly toward the road as braking hard could damage the brakes of the car and cause accident in subsequent trips.

This is therefore why option C was chosen as the correct choice.

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Answer: Steer straight and slow down before attempting

Explanation: