Condense to a single logarithm with a leading coefficient of
1.
ln(3) + ln(x) + ln(y)

Answers

Answer 1

The condensed form of the given logarithmic expression ln(3) + ln(x) + ln(y) is: ln(3*x*y)

To condense the given logarithmic expression to a single logarithm with a leading coefficient of 1, we can use the product property of logarithms.

The product property states that the sum of two logarithms with the same base is equivalent to the logarithm of the product of the two numbers.

Using this property, we can combine the three logarithmic terms in the given expression: ln(3) + ln(x) + ln(y) = ln(3*x*y)

Therefore, the condensed form of the given logarithmic expression is:
ln(3*x*y). This is a single logarithm with a leading coefficient of 1, as required.

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Related Questions

What is the measure of angle P? q is 65° P is 67°
​this IXL is due tomorrow so I need help fast make sure to explain

Answers

Check the picture below.

if your mom was given birth in year x and you were given birth in 2010 you and her have an age gap of 36 years what is her birth date

Answers

Answer:

2010-36=1974

She was born in 1974.

Answer:1974

Step-by-step explanation:

2010-36=1974

Factor completely. -3x^2+6x+9 =

Answers

The complete factorization of [tex]-3x^2+6x+9[/tex] is -3(x - 3)(x + 1).

What is the factorization?

A mathematical expression, equation, or polynomial is factorized, sometimes referred to as factored, when it is broken down into factors or simpler expressions.

A technique for factoring a number or a polynomial is called factorisation. The polynomials are divided into the sums of their component parts. As an illustration, x2 + 2x can be factored as x(x + 2), where x and x+2 are the factors that can be multiplied to obtain the original polynomial.

To factor completely [tex]-3x^2+6x+9[/tex], we first need to factor out the greatest common factor, which is -3:

[tex]-3(x^2 - 2x - 3)[/tex]

Now we can factor the quadratic expression inside the parentheses:

-3(x - 3)(x + 1)

Hence, the complete factorization of [tex]-3x^2+6x+9[/tex] is -3(x - 3)(x + 1).

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Congruent triangles unit 4 homework 4

Answers

1. The values of x, y, and z are x = 15.5, y = 9.54, and z = 0. 2. The values of x and y are x = 1.4375 and y = 8. 3. The values of x and y are x = 6 and y = 52.5. 4. X can have any value and the triangles will still be similar

1. We are given that ΔPRS is congruent to ΔCFH.

From ΔPRS, we know that:

∠P = 180 - 28 - ∠R

∠P = 152 - 13y

From ΔCFH, we know that CH is the hypotenuse and CF is one of the legs. So, using the Pythagorean Theorem, we have:

CH^2 = CF^2 + FH^2

39^2 = 24^2 + FH^2

FH^2 = 39^2 - 24^2

FH = sqrt(39^2 - 24^2) = 30

Since ΔPRS is congruent to ΔCFH, their corresponding sides are equal. Therefore:

PS = CH = 39

2x - 7 = CF = 24

Solving for x and y:

2x - 7 = 24

2x = 31

x = 15.5

39 = 2x - 7

46 = 2x

x = 23

∠P = 152 - 13y

28 = 152 - 13y

124 = 13y

y = 9.54

Solving for z:

PS = 2x - 7

39 = 2(15.5) - 7

39 = 31

z = 0

Therefore, the values of x, y, and z are x = 15.5, y = 9.54, and z = 0.

2. We are given that ΔABC is similar to ΔDEF. Therefore, the corresponding sides are proportional:

AB/DE = BC/EF = AC/DF

Substituting the given values:

8/(y-6) = 19/(4x-1) = 14/DF

We can solve for x and y using any two of the three ratios.

Let's first solve for x and y using the first two ratios:

8/(y-6) = 19/(4x-1)

Cross-multiplying, we get:

8(4x-1) = 19(y-6)

Expanding the brackets, we get:

32x - 8 = 19y - 114

32x - 19y = -106

Now let's use the third ratio:

14/DF = 8/(y-6)

Cross-multiplying, we get:

14(y-6) = 8DF

Simplifying, we get:

y = (4/7)DF + 6

Substituting this into the equation we got earlier:

32x - 19y = -106

32x - 19[(4/7)DF + 6] = -106

32x - (76/7)DF - 114 = -106

32x - (76/7)DF = 8

Multiplying both sides by 7, we get:

224x - 76DF = 56

Using the equation we got from the third ratio:

14(y-6) = 8DF

14y - 84 = 8DF

14y = 8DF + 84

y = (4/7)DF + 6

Substituting this into the equation we just got:

14[(4/7)DF + 6] = 8DF + 84

8DF + 84 = (56/7)DF + 84

8DF = (56/7)DF

DF = 7

Substituting DF = 7 into the third ratio:

14/DF = 8/(y-6)

14/7 = 8/(y-6)

2 = y-6

y = 8

Now we can substitute y = 8 into the equation we got earlier:

32x - 19y = -106

32x - 19(8) = -106

32x - 152 = -106

32x = 46

x = 1.4375

Therefore, the values of x and y are x = 1.4375 and y = 8.

3. Since ΔZMK ≈ ΔAPY, we know that the corresponding angles are congruent:

m∠M = m∠A

m∠K = m∠Y

Therefore, we can write two equations:

m∠M = 2y + 7

m∠K = 41°

Also, we know that:

m∠M + m∠K + (13x - 37)° = 180°

Substituting the values we have:

112° + 41° + (13x - 37)° = 180°

13x + 116 = 180

13x = 64

x = 4.9231

Substituting x into the third equation:

112° + 41° + (13x - 37)° = 180°

13x + 116 = 180

13(4.9231) + 116 + m∠K = 180

m∠K = 41°

Substituting m∠K = 41° into the second equation:

m∠K = m∠Y

13x - 37 = 41

13x = 78

x = 6

Substituting x into the first equation:

m∠M = 2y + 7

112 = 2y + 7

105 = 2y

y = 52.5

Therefore, the values of x and y are x = 6 and y = 52.5.

4. Since ΔBTS ≈ ΔGHD, we know that the corresponding angles are congruent:

m∠S = m∠H

m∠B = m∠G

Therefore, we can write two equations:

m∠S = 7y + 5

m∠B = m∠G = 21°

Also, we know that:

m∠B + m∠T + m∠S = 180°

Substituting the values we have:

21° + m∠T + 56° = 180°

m∠T = 103°

Now we can use the fact that the sum of the angles in a triangle is 180° to find m∠G:

m∠B + m∠T + m∠G = 180°

21° + 103° + m∠G = 180°

m∠G = 56°

Since we have a pair of similar triangles, we can use their side lengths to set up a proportion:

BS/BT = GD/GH

Substituting the given values:

25/31 = (4x-11)/GH

Solving for GH:

GH = (31/25)(4x-11)

Now we can use the fact that the sum of the angles in a triangle is 180° to find m∠H:

m∠G + m∠H + m∠D = 180°

56° + m∠H + 90° = 180°

m∠H = 34°

Substituting the values we have:

m∠S = 7y + 5

56 = 7y + 5

51 = 7y

y = 7.2857

Substituting y into the first equation:

m∠S = 7y + 5

m∠S = 7(7.2857) + 5

m∠S = 59

Now we can use the fact that the sum of the angles in a triangle is 180° to find m∠T:

m∠B + m∠T + m∠S = 180°

21° + m∠T + 59° = 180°

m∠T = 100°

Now we can use the fact that we have a pair of similar triangles to find x:

BS/BT = GD/GH

25/31 = (4x-11)/GH

25/31 = (4x-11)/((31/25)(4x-11))

Simplifying:

25/31 = 25/31

Therefore, x can have any value and the triangles will still be similar.

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Quadrilateral HIJK is an isosceles trapezoid and mZJ = 5p + 1°. What is the value of p?
J
P =
K
Save answer
106⁰
I
H

Answers

The value of P for the given isosceles trapezoid is 21.

What is an isosceles trapezoid ?

An isosceles trapezoid is a four-sided figure with two parallel sides (called bases) of different lengths, and two non-parallel sides of equal length.

The non-parallel sides are also called legs. The two parallel sides are connected by two diagonal lines that intersect each other at a midpoint, forming two congruent triangles.

The following properties are characteristic of an isosceles trapezoid:

The opposite angles are supplementary (add up to 180 degrees).The diagonals are congruent to each other.The two non-parallel sides are congruent to each other.The angle between a non-parallel side and a base is congruent to the corresponding angle on the other side of the trapezoid.

For this case, if m∠I = 106⁰, then m∠J = 106⁰

So the value of P is calculated as follows;

m∠J = 5p + 1 = 106

5p + 1 = 106

5p = 106 - 1

5p = 105

p = 105 / 5

p = 21

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Select the correct answer from each drop-down menu.
Consider quadrilateral EFGH on the coordinate grid.
-6
E
-4
1
LL
F
>+
Y
6-
2-
O
-4-
-6-
H
-N
G
05.
6
In quadrilateral EFGH, sides FG and EH are
are
X
because they
The area of quadrilateral EFGH is closest to
✓square units.
Sides EF and GH

First box ( not congruent, congruent).

Second box ( each have a length of 5.83, each have a length of 7.07, have different lengths)

Third box ( not congruent, congruent with lengths of 4.24, congruent with length of 5.83)

Fourth box (41, 34, 25, 30)

Answers

In quadrilateral EFGH, sides FG and EH are congruent because they each have a length of 7.07

The area of quadrilateral EFGH is closest to 30 square units.

How to complete the blanks

From the question, we have the following parameters that can be used in our computation:

The quadrilateral EFGH

This quadrilateral is a rectangle

This means that the opposite sides are congruentThis also means that the opposite sides are parallel

From the figure, we can see that the following side lengths

EF = 3√2 = 4.24

EH = 5√2 = 7.07

So, we have

Area = 3√2 * 5√2

Evaluate

Area = 30

Hence, the area is 30 square units

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Use decomposition to find the area of the figure. A drawing of a right-angled trapezoid with length of two parallel sides measuring 10 yards and 13 yards. The height of the trapezoid is 8 yards. The area is
square yards. Skip to navigation

Answers

In the given problem, we need to find the area of the trapezoid in which the height is 8 yards. The area of the given trapezoid is 92 square yards.

If the length of a trapezoid's parallel sides and the distance (height) between them are known, the area of the shape may be determined.

A = (a+b)h/2 is the formula for a trapezoid's surface area.

where "a" and "b" are the lengths of the base of the trapezoid and "h" represents the height of the figure.

We have been given the values,

The length of the bases is 10 and 13 yards and,

the height of the trapezoid is 8 yards.

So, according to the formula for determining the area,

Area of a trapezoid,

"A" = {(10 + 13)8} / 2

⇒ A = {184}/2

⇒ A = 92 square yards.

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Answer #14 using the picture

Answers

Answer:

(10,14)

Step-by-step explanation:

if you look there's a pattern

Nork Facior out the GCF from the polynomial a^(5)b^(7)-a^(3)b^(2)+a^(2)b^(6)-a^(2)b^(2)

Answers

The GCF of the polynomial a^(5)b^(7)-a^(3)b^(2)+a^(2)b^(6)-a^(2)b^(2) is a^(2)b^(2), and the factored form of the polynomial is a^(2)b^(2)(a^(3)b^(5)-a+b^(4)-1).

The GCF, or greatest common factor, is the largest factor that all terms in a polynomial have in common. In this case, we need to find the GCF of the polynomial a^(5)b^(7)-a^(3)b^(2)+a^(2)b^(6)-a^(2)b^(2).

First, we need to look at the exponents of each term to determine the GCF. The smallest exponent for a is 2, and the smallest exponent for b is 2. Therefore, the GCF for this polynomial is a^(2)b^(2).

Next, we need to factor out the GCF from each term in the polynomial. This is done by dividing each term by the GCF and then multiplying the GCF by the resulting polynomial.

So, the factored form of the polynomial is:

a^(2)b^(2)(a^(3)b^(5)-a+b^(4)-1)

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5. The average monthly temperatures for a city in Canada have been recorded for one
year. The high average temperature was 77° and occurred during the month of July. The
low average temperature was 5° and occurred during the month of January.
a. Sketch an accurate graph of the situation described above: (Let January
correspond to x=1.)
b. Write a trig equation that models the temperature throughout the year.
c. Find the average monthly temperature for the month of March.
d. During what period of time is the average temperature less than 41°?

Answers

Answer: a. Here is a sketch of the situation described above:

 80 +                       .           July (x = 7)

      |                      .

      |                     .

      |                     .

 60 +           .               .

      |                .

      |                    .

      |                        .

 40 +          .                   .     .

      |                              .

      |                               .

      |                                .

 20 +   .         . . . . . . . . . . . . . .

      |                                      .

      |                                          .

 0  +_______________________________________________

     1   2   3   4   5   6   7   8   9   10  11  12

                          January                 December

b. One possible trigonometric equation that models the temperature throughout the year is:

T(x) = (36cos((2π/12)(x-7))) + 41

where T(x) represents the average temperature in degrees Fahrenheit for month x (with January corresponding to x=1), and the constant term of 41 is added to shift the curve up to match the lowest average temperature recorded.

c. To find the average monthly temperature for the month of March, we simply plug in x=3 into the equation above:

T(3) = (36cos((2π/12)(3-7))) + 41

= (36*cos(-π/3)) + 41

≈ 51.4°F

So the average monthly temperature for the month of March is approximately 51.4 degrees Fahrenheit.

d. To find the period of time during which the average temperature is less than 41°F, we need to solve the inequality:

T(x) < 41

Substituting the equation for T(x) from part b, we get:

(36cos((2π/12)(x-7))) + 41 < 41

Simplifying this inequality, we get:

cos((2π/12)*(x-7)) < 0

We can solve this inequality by finding the values of x for which the cosine function is negative. The cosine function is negative in the second and third quadrants of the unit circle, so we have:

(2π/12)*(x-7) ∈ (π, 2π) ∪ (3π, 4π)

Simplifying this expression, we get:

π/6 < x-7 < π/2 or 5π/6 < x-7 < 2π/3

Adding 7 to both sides of each inequality, we get:

7 + π/6 < x < 7 + π/2 or 7 + 5π/6 < x < 7 + 2π/3

Simplifying these expressions, we get:

7.524 < x < 8.571 or 11.286 < x < 11.857

Therefore, the average temperature is less than 41°F during the period of time from approximately November 24th to December 19th, and from approximately February 15th to March 20th.

Step-by-step explanation:

Four different exponential functions are represented below.

Drag the representation of each function into order from greatest y intercept to least y-intercept.

Answers

Answering the question, we may state that According to the graph, from function largest y-intercept to smallest y-intercept, we have:

[tex]f(x) = 5 f(x) = 2 f(x) + 1 f(x) = 1/2 f(x) = 1/5 (x)[/tex]

what is function?

Mathematicians investigate the relationships between numbers, equations, and related structures, as well as the locations of forms and possible placements for these items. A set of inputs and their corresponding outputs are referred to as a "function" in this context. If each input results in a single, unique output, the relationship between the inputs and outputs is known as a function. Each function has its own domain, codomain, or scope. A common way to denote functions is with the letter f. (x). is an x for entry. One-to-one capabilities, so multiple capabilities, in capabilities, and on functions are the four main categories of accessible functions.

According to the graph, from largest y-intercept to smallest y-intercept, we have:

[tex]f(x) = 5 f(x) = 2 f(x) + 1 f(x) = 1/2 f(x) = 1/5 (x)[/tex]

As a result, the sequence is:

[tex]f(x) = 5^(x) (highest y-intercept) (highest y-intercept)[/tex]

[tex]f(x) = 2^(x) + 1 f(x) = 1/2^ (x)[/tex]

[tex]f(x) = 1/5^(x) (lowest y-intercept) (lowest y-intercept)[/tex]

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Find the function values.
53. g(x) = 2x + 5
a) g102
b) g1-42
c) g1-72
d) g182
e) g1a + 22
f) g1a2 + 2

Answers

The function values are:
a) g(102) = 207
b) g(1-42) = -79
c) g(1-72) = -139
d) g(182) = 369
e) g(1a+22) =  2a + 49
f) g(1a2+2) = 2a2 + 9

The problem is asking to evaluate the function g(x) at specific values of x. To find g(102), for example, we substitute 102 for x in the expression for g(x) and simplify:

g(102) = 2(102) + 5 = 207

Similarly, for g(1-42), we substitute -42 for x:

g(1-42) = 2(-42) + 5 = -79

g(1-72) = 2(1-72) + 5 = -139

g(182) = 2(182) + 5 = 369

For g(1a + 22), we substitute "a+22" for x:

g(1a+22) = 2(a+22) + 5 = 2a + 49

And for g(1a²+2), we substitute "a²+2" for x:

g(1a²+2) = 2(a²+2) + 5 = 2a² + 9

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what is
y = x
y = 2x -4
PLS I NEED HELP and i have sm more questions..

Answers

Answer:

(4, 4) in point form

x = 4, y = 4 in equation form

Explanation:

...

y-3=1(x-2)

write an equation of a line
that is perpendicular to this line. Show your work.

Answers

The equation of a perpendicular line is y = -x + 2

How to determine the equation of a perpendicular line

From the question, we have the following parameters that can be used in our computation:

y - 3 = 1(x - 2)

We can use the point-slope form of a linear equation to write the equation of the perpendicular line:

y - y1 = m(x - x1)

By comparison, we have

m1 = 1

For perpendicular lines. we have

m = -1/m1

So, we have

m = -1

An example of an equation wit a slope of -1 is

y = -x + 2

Hence, the equaton is y = -x + 2

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evaluate the expression using scientific notation. Express the result in scientific notation.
5.4 X 10^-8/1.5 X 10^4

Answers

Answer:

We can simplify this expression as follows:

5.4 x 10^-8 / 1.5 x 10^4 = (5.4/1.5) x (10^-8 / 10^4) = 3.6 x 10^-12

Therefore, the result in scientific notation is 3.6 x 10^-12.

The owner of a used car dealership is trying to determine if there is a relationship between the price of a used car and the number of miles it has been driven. The owner collects data for 25 cars of the same model with different mileage and determines each car’s price using a used car website. The analysis is given in the computer output.

Which of the following represents the value of the average residual for a car’s price?
0.024
2164.1
3860.7
24157.2


Answers

The value of the average residual for a car’s price include the following: C. 3860.7.

What is a coefficient of determination?

In Mathematics, a coefficient of determination (r² or r-squared) can be defined as a number between zero (0) and one (1) that is typically used for measuring the extent (how well) to which a statistical model predicts an outcome.

What is a residual value?

In Mathematics, a residual value is a difference between the measured (given or observed) value from a residual plot and the predicted value from a residual plot.

Based on the computer output (see attachment), we can logically deduce that the coefficient of determination (r²) and average residual for a car's price are as follows;

r² = 68% = 68/100 = 0.68.

Average residual for a car's price, S = 3860.7.

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33 pt= __qt __pt (convert units)

Answers

Converting 33 pints into quarts is 16.5 Quarts.

How to Convert 33 pints into quarts

The pint (symbol: pt) is a unit of volume or capacity in both the imperial and United States customary measurement systems.

The quart (abbreviation qt.) is an English unit of volume equal to a quarter gallon. It is divided into two pints or four cups.

To calculate 33 Pints to the corresponding value in Quarts,

We multiply the quantity in Pints by 0.5 (conversion factor).

In this case we should multiply 33 Pints by 0.5 to get the equivalent result in Quarts:

33 Pints x 0.5 = 16.5 Quarts

Hence, 33 Pints is equivalent to 16.5 Quarts.

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please help ill make brainlyest please please and fast

Answers

1. ∆ABC and ACD are not necessarily similar

2. ∆ABC and ADE are similar by SAS similarity

3. . ∆ABC and AGF are similar by SAS similarity

What are similar triangles?

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion . In other words, similar triangles are the same shape, but not necessarily the same size. The triangles are congruent if, in addition to this, their corresponding sides are of equal length.

1. ABC and ACD are not similar because there is only one corresponding Similar sides

2. ABC and ADE are similar because there are two corresponding sides and an equal angle A'

3. ABC and ACD are similar because is equal angle A and two corresponding sides.

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A route between Guilford and Bath has a distance of 180 kilometres.
Dave drives from Guilford to Bath. He takes 3 hours.

Olivia drives the same route. Her average speed is 15 kilometres per hour faster than Dave's.
(a) How long does it take Olivia to drive from Guilford to Bath?
Give your
answer in hours and minutes

Answers

Olivia will take time of 4 hour to drive from Guilford to Bath.

Explain the relation of speed and distance?Speed is the rate at which a distance changes over time. The speed is equivalent to s = D/T if D is the object's distance in time T. The units are the same as for velocity.

Let the speed of Dave be 'x' km/h

Then,

Olivia's speed = ( x + 15 )km/h

Time = 3 hours.

Distance =  180 kilometres

Using relations:

Speed  = distance /time

x + 15 = 180/3

x + 15 = 60

x = 60 - 15

x = 45 km/hr.

Time taken by Olivia to drive from Guilford to Bath.

45 = 180/t

t = 180 / 45

t = 4 hours.

Thus,  it take Olivia 4 hour to drive from Guilford to Bath.

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Bonsoir, j’ai besoin d’aide pour l’exo 135 je suis bloqué, merci d’avance

Answers

Answer:

Je suis désolé, mais je ne sais pas à quoi fait référence l'exo 135. Pouvez-vous me donner plus de détails sur ce que vous cherchez à comprendre ou résoudre ? Je suis heureux de vous aider si je peux comprendre la question.

Prove that AD CONGRUENT TO BC

Answers

ABDC is a rectangle, we can conclude that AD is congruent to BC.

What is Triangle ?

Triangle can be defined in which it consists of three sides, three angles and sum of three angles is always 180 degrees.

In the given diagram, we have a parallelogram ABCD. To prove that AD is congruent to BC, we need to show that ABDC is a rectangle.

Here's the proof:

Since ABCD is a parallelogram, we know that:

AB is parallel to CD

BC is parallel to AD

Also, we have:

∠A + ∠B = 180° (opposite angles of a parallelogram)

∠D + ∠C = 180° (opposite angles of a parallelogram)

From the diagram, we can see that:

∠A + ∠D = 180° (adjacent angles of a parallelogram)

∠B + ∠C = 180° (adjacent angles of a parallelogram)

Adding the last two equations, we get:

∠A + ∠D + ∠B + ∠C = 360°

But we know that the sum of the angles in a rectangle is 360°. Therefore, if we can prove that ABDC is a rectangle, we can conclude that AD is congruent to BC.

To show that ABDC is a rectangle, we need to prove that:

AB is perpendicular to BC

BC is perpendicular to CD

CD is perpendicular to AD

AD is perpendicular to AB

Since AB is parallel to CD and BC is parallel to AD, we can conclude that ∠ABC and ∠CDA are alternate interior angles and are therefore congruent. Similarly, ∠ABD and ∠DCB are alternate interior angles and are congruent.

Now, we can prove that ABDC is a rectangle by showing that all its angles are right angles. We can do this by proving that:

∠ABC + ∠ABD = 90° (interior angles of a triangle)

∠CDA + ∠DCB = 90° (interior angles of a triangle)

Since ∠ABC and ∠CDA are congruent, and ∠ABD and ∠DCB are congruent, we have:

∠ABC + ∠ABD = ∠CDA + ∠DCB

Substituting the values of these angles, we get:

2∠ABC = 2∠CDA

∠ABC = ∠CDA

Therefore, ∠ABC and ∠CDA are both 45 degrees. Similarly, we can show that ∠ABD and ∠DCB are both 45 degrees. Hence, all angles of ABDC are 90 degrees, and we have proven that ABDC is a rectangle.

Since , ABDC is a rectangle, we can conclude that AD is congruent to BC.

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If a+b=4, and a^2+b^2=12, then what is a^4+b^4
? (A) 112 (B) 136 (C) 144 (D) 256 (E) None of these

Answers

If a+b=4, and a²+b²=12, then what is a⁴+b⁴ is (B) 136.

To find the value of a⁴ + b⁴, we can use the identity (a² + b²)² = a⁴ + 2a²b² + b⁴. We are given that a² + b² = 12, so we can plug that value into the identity to get:

(12)² = a⁴ + 2a²b² + b⁴

144 =  a⁴ + 2a²b² + b⁴

We can also use the identity (a + b)² = a² + 2ab + b² to find the value of 2a²b². We are given that a + b = 4, so we can plug that value into the identity to get:

(4)² = a² + 2ab + b²

16 = a² + 2ab + b²

Subtracting a^2 + b^2 from both sides gives us:

16 - (a² + b²) = 2ab

16 - 12 = 2ab

4 = 2ab

2 = ab

So we can plug the value of 2ab back into the first identity to get:

144 = a4⁴ + 2(2)² + b⁴

144 = a^⁴ + 8 + b⁴

Subtracting 8 from both sides gives us:

136 = a⁴ + b⁴

So the value of a⁴ + b⁴ is 136, which is option (B).

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Solve these systems of linear equations by substitution by following the steps. Write the solutions on the blanks. 2x+y=5 2y=2x-8 a. Find the first variable and isolate it. Then solve for that variable. b. Solve for the second variable. c. Find the numerical value of the first variable. d. Check your solution.

Answers

3 - 1 = 5, which is true

a. To solve for the first variable, we need to isolate it on one side of the equation. We can do this by subtracting 2y from both sides of the first equation: 2x + y = 5 becomes 2x + y - 2y = 5 - 2y, which simplifies to 2x = 5 - 2y. Now we can divide both sides by 2 to solve for the first variable x: x = (5 - 2y)/2.

b. Now we can use the value of x we just found to solve for the second variable y in the second equation: 2y = 2x - 8. Substituting the value of x in for 2x gives us 2y = (5 - 2y) - 8, which simplifies to 3y = -3. Now, we can divide both sides by 3 to solve for the second variable y: y = -3/3 or simply y = -1.

c. To find the numerical value of the first variable x, substitute the value of y we just found (i.e. y = -1) into the equation we found in Step a. This gives us x = (5 - 2(-1))/2, which simplifies to x = 3/2 or x = 1.5.

d. To check your solution, substitute the numerical values you found for x and y into the original equations. For the first equation, 2x + y = 5, we have 2(1.5) + (-1) = 5. Simplifying this gives us 3 - 1 = 5, which is true, so the solution is correct!

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AABC has vertices A(-4,6), B(-6, -4), and C(2,-2).
The following transformation defines AA'B'C':
AA'B'C' =D 5/2 (AABC)

Answers

The required vertices of [tex]$\Delta A'B'C'$[/tex] are A'(-10, 15), B'(-15, -10), and C'(5, -5).

How to find the dilated coordinates of triangle?

The transformation that defines AA'B'C' can be described as a dilation with center at the origin and scale factor of 5/2.

To find the coordinates of A', B', and C', we can use the following formulas:

[tex]$\begin{align*}A'(x,y) &= \left(\frac{5}{2}\right)x, \left(\frac{5}{2}\right)y \B'(x,y) &= \left(\frac{5}{2}\right)x, \left(\frac{5}{2}\right)y \C'(x,y) &= \left(\frac{5}{2}\right)x, \left(\frac{5}{2}\right)y \\end{align*}$[/tex]

Using the coordinates of A(-4,6), B(-6, -4), and C(2,-2), we can calculate the coordinates of A', B', and C' as follows:

For point A(-4,6), we have:

[tex]$A'(x,y) = \left(\frac{5}{2}\right) x, \left(\frac{5}{2}\right) y = \left(\frac{5}{2}\right) (-4), \left(\frac{5}{2}\right) (6) = (-10, 15)$[/tex]

Therefore, the coordinates of A' are (-10, 15).

For point B(-6,4), we have:

[tex]$B'(x,y) = \left(\frac{5}{2}\right) x, \left(\frac{5}{2}\right) y = \left(\frac{5}{2}\right) (-6), \left(\frac{5}{2}\right) (4) = (-15, 10)$[/tex]

Therefore, the coordinates of B' are (-15, 10).

For point C(2,2), we have:

[tex]$C'(x,y) = \left(\frac{5}{2}\right) x, \left(\frac{5}{2}\right) y = \left(\frac{5}{2}\right) (2), \left(\frac{5}{2}\right) (-2) = (5, -5)$[/tex]

the coordinates of C' are (5, -5).

Therefore, the vertices of [tex]$\Delta A'B'C'$[/tex] are A'(-10, 15), B'(-15, -10), and C'(5, -5).

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Pls help1 1/2-3/4 I need. Help please

Answers

Answer:

3/4

Step-by-step explanation:

what is the rate of traveling 372 miles in 6 hours

Answers

Answer:62 miles/hour

Step-by-step explanation:372 miles / 6 hours = 62 miles/hour 62 * 15 = 930 A driver travels 372 miles in 6 hours. At that rate, the driver will travel 930 miles in 15 hours

Answer: 62 mph

Step-by-step explanation:

372/6=62

:)

The container was covered in plastic wrap during manufacturing. How many square inches of plastic wrap were used to wrap the container? Write the answer in terms of π.

2.1π square inches
3.22π square inches
5.04π square inches
6.16π square inches

Determine the surface area of the cylinder. (Use π = 3.14)

net of a cylinder where radius of base is labeled 4 inches and a rectangle with a height labeled 3 inches

200.96 in2
175.84 in2
138.16 in2
100.48 in2

Determine the exact surface area of the cylinder in terms of π.

cylinder with radius labeled 1 and three fourths centimeters and a height labeled 3 and one fourth centimeters

30 and three sixteenths times pi square centimeters
35 and seven eighths times pi square centimeters
11 and thirteen sixteenths times pi square centimeters
17 and one half times pi square centimeters

Bisecting Bakery sells cylindrical round cakes. The most popular cake at the bakery is the red velvet cake. It has a radius of 13 centimeters and a height of 15 centimeters.

If everything but the circular bottom of the cake was iced, how many square centimeters of icing is needed for one cake? Use 3.14 for π and round to the nearest square centimeter.

531 cm2
612 cm2
1,755 cm2
2,286 cm2

Answers

1) Cannot be determined.

2) Surface area of the cylinder with radius 4 inches and height 3 inches is 100.48 square inches.

3) Exact surface area of the cylinder with radius 1 and three-fourths centimeters and height 3 and one-fourth centimeters is 35 and seven-eighths times pi square centimeters.

4) The area of icing needed for one red velvet cake with a radius of 13 centimeters and a height of 15 centimeters is approximately 459 square centimeters.

What is the surface area of the cylinder?

The surface area of a cylinder is the total area of all its curved and flat surfaces. It is given by the formula:

Surface Area = 2πr² + 2πrh

To answer these questions, we need to use the formula for the surface area of a cylinder:

Surface Area = 2πr² + 2πrh

where r is the radius of the circular base of the cylinder, h is the height of the cylinder, and π is the mathematical constant pi.

We are given that the container was covered in plastic wrap during manufacturing. We are not given the dimensions of the container, but we can assume it is a cylinder. Therefore, we need to calculate the surface area of the cylinder. We are not given the values of r and h, so we cannot calculate the surface area directly. Therefore, we cannot determine the answer to this question.

We are given the net of a cylinder with a labeled radius of 4 inches and a labeled height of 3 inches. To find the surface area of the cylinder, we need to use the formula:

Surface Area = 2πr² + 2πrh

Substituting r = 4 and h = 3, and using π ≈ 3.14, we get:

Surface Area = 2(3.14)(4²) + 2(3.14)(4)(3) = 100.48 in²

Therefore, the surface area of the cylinder is 100.48 in².

We are given a cylinder with a labeled radius of 1 and three-fourths centimeters and a labeled height of 3 and one-fourth centimeters. To find the surface area of the cylinder, we need to use the formula:

Surface Area = 2πr² + 2πrh

Substituting r = 1.75 and h = 3.25, we get:

Surface Area = 2(3.14)(1.75²) + 2(3.14)(1.75)(3.25) = 35.875π cm²

Therefore, the exact surface area of the cylinder in terms of π is 35 and seven-eighths times pi square centimeters.

We are given a red velvet cake with a radius of 13 centimeters and a height of 15 centimeters. We need to find the area of the circular top of the cake, which is the same as the surface area of a cylinder with radius 13 and height 0. We can use the formula:

Surface Area = 2πr² + 2πrh

Substituting r = 13 and h = 0, we get:

Surface Area = 2(3.14)(13²) + 2(3.14)(13)(0) = 1061.76 cm²

We need to subtract this from the surface area of the whole cylinder (the cake) to find the area of the icing. Using the formula again with r = 13 and h = 15, we get:

Surface Area = 2(3.14)(13²) + 2(3.14)(13)(15) = 1520.6 cm²

Therefore, the area of icing needed for one cake is:

1520.6 - 1061.76 = 458.84 cm²

Rounding this to the nearest square centimeter, we get:

459 cm²

Therefore, approximately 459 square centimeters of icing is needed for one cake.

Hence,

1) Cannot be determined.

2) Surface area of the cylinder with radius 4 inches and height 3 inches is 100.48 square inches.

3) Exact surface area of the cylinder with radius 1 and three-fourths centimeters and height 3 and one-fourth centimeters is 35 and seven-eighths times pi square centimeters.

4) The area of icing needed for one red velvet cake with a radius of 13 centimeters and a height of 15 centimeters is approximately 459 square centimeters.

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Could anyone help me with this question?

Answers

Answer:

a) 1024 - 14280x + 720x² - 240x³

b) 117616

Step-by-step explanation:

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the difference of y and 8 is less than or equal to -27

Translate the sentence into an inequality.

Answers

Answer:

y - 8 ≤ -27

Step-by-step explanation:

The difference of y and 8 is less than or equal to -27

y - 8 ≤ -27

Abstract Algebra: What is the maximum possible
order of an element of ????8? Is ????8 a cyclic
group? Is ????8 an abelian group?

Answers

8 is an abelian group.

The maximum possible order of an element in the group ????8 is 8. No, ????8 is not a cyclic group, as the only cyclic group of order 8 is a group with one element. However, ????8 is an abelian group. An abelian group is a group in which the result of the group operation is independent of the order of its operands.

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