In alpha decay, the nucleus loses two protons, in beta decay, the nucleus either loses or gains a proton whereas in gamma decay, no change in proton number occurs only energy is released.
How do the types of radioactive decay compare?Alpha decay is a type of radioactive decay in which the nucleus of an atom emits an alpha particle which leads to transforming into a new atomic nucleus by losing two protons. During beta decay, the proton in the nucleus is transformed into a neutron and and neutron is transformed into proton while on the other hand, gamma decay is a type of decay in which nucleus changes from a higher energy state to a lower energy state due to the release of electromagnetic radiation.
So we can conclude that In alpha decay, the nucleus loses two protons, in beta decay, the nucleus either loses or gains a proton whereas in gamma decay, no change in proton number occurs only energy is released.
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a car accelerates from rest to 90 kilometre per hour in 10 seconds what is its acceleration in metre per second squared
Answer:2.5 m/s2
Explanation:
Acceleration =v2-v1 ÷ t2-t1 convert 90 km/h to m/s = 90×5/18 = 25 m/s , 25÷10 = 2.5
A forklift was used to lift a 750 kg. oil drum 18 m straight up into the air to store on a shelf. If it does it in 28 seconds, Calculate the work and power exerted by the forklift.
W= J
P= watts
Explanation:
Given parameters:
Mass of forklift = 750kg
Height of lift = 18m
Time taken = 28s
Unknown:
Work done = ?
Power = ?
Solution;
The work done by the forklift is given as:
Work done = mass x acceleration due to gravity x height
Work done = 750 x 9.8 x 18 = 132300J
Power is the rate at which work is done;
Power = [tex]\frac{work done }{time}[/tex]
Insert the parameters and solve;
Power = [tex]\frac{132300}{28}[/tex] = 4725W
Consider a block on frictionless ice. Starting from rest, the block travels a distance din
time t when force Fis applied. If force 4F is applied, the distance the block travels in
time tis:
Answer:
The distance is now 4d
Explanation:
Mechanical Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object.
The acceleration can be calculated by solving for a:
[tex]\displaystyle a=\frac{F}{m}[/tex]
Once we know the acceleration, we can calculate the distance traveled by the block as follows:
[tex]\displaystyle d = vo.t+\frac{at^2}{2}[/tex]
If the block starts from rest, vo=0:
[tex]\displaystyle d = \frac{at^2}{2}[/tex]
Substituting the value of the acceleration:
[tex]\displaystyle d = \frac{\frac{F}{m}t^2}{2}[/tex]
Simplifying:
[tex]\displaystyle d = \frac{Ft^2}{2m}[/tex]
When a force F'=4F is applied and assuming the mass is the same, the new acceleration is:
[tex]\displaystyle a'=\frac{4F}{m}[/tex]
And the distance is now:
[tex]\displaystyle d' = \frac{4Ft^2}{2m}[/tex]
Dividing d'/d:
[tex]\displaystyle \frac{d' }{d}=\frac{\frac{4Ft^2}{2m}}{\frac{Ft^2}{2m}}[/tex]
Simplifying:
[tex]\displaystyle \frac{d' }{d}=4[/tex]
Thus:
d' = 4d
The distance is now 4d
Review. For a certain type of steel, stress is always proportional to strain with Young's modulus 20 × 10¹⁰ N/m² . The steel has density 7.86× 10³kg / m³. It will fail by bending permanently if subjected to compressive stress greater than its yield strength бy = 400MPa. A .rod 80.0cm long, made
of this steel, is fired at 12.0 m/s straight at a very hard wall.(c) How far has the back end of the rod moved in this time interval? Find
The back end of the rod moved [tex]1.90\ \mathrm{mm}$[/tex] in this time interval.
Given:
Young's modulus, Y = [tex]20 \times 10^{10}\;N/m^{2}[/tex]
Steel density, [tex]\rho = 7.86 \times 10^{3}\;kg/m^{3}[/tex]
Length of the rod, L = 80 cm = 0.800m
The speed of the wave in the rod is
[tex]$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$[/tex]
Hence the time taken by the wave to travel the end of the rod is,
[tex]$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$[/tex]
The velocity of the rod is [tex]$v_r = 12.0\ \mathrm{m/s}$[/tex]
The other end will keep moving after the front end hits the wall until the wave reaches the other end, given the period determined by the above problem.
As a result, before the wave reaches the end of the rod, it has traveled a distance of
[tex]$\Delta L = v_r t = (12.0\ \mathrm{m/s}) (1.58\times\ \mathrm{s}) = 1.90\times 10^{-3}\ \mathrm{m} = 1.90\ \mathrm{mm}$[/tex]
Hence, the [tex]1.90\ \mathrm{mm}$[/tex] at the back end of the rod moved in this time interval.
What do you mean by Youngs Modulus?Young's Modulus is a measurement of the mechanical characteristics of linear elastic solids like rods, wires, and other similar objects. It is also known as the Elastic Modulus or Tensile Modulus. Young's modulus is the most often used measurement of a material's elastic properties; other measurements include bulk modulus and shear modulus. This is so that it can inform us about a material's tensile elasticity (ability to deform along an axis).
The relationship between stress (force per unit area) and strain is described by Young's modulus (proportional deformation in an object). Thomas Young, a British scientist, is honored with the name of the Young's modulus. When a certain load is applied to a solid object, it deforms.
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in a slap shot, a hockey player accelerates the puck from a velocity of 5 m/s to 30 m/s in the same direction. if the puck moves over a distance of 10 m during this process, what was the acceleration? group of answer choices
The acceleration of the puck is 43.75 m/s².
The velocity of an object or particle in uniform motion is defined as the rate at which its direction is changing as seen from a particular angle and as measured by a particular unit of time.
The player's puck accelerates from a velocity of 5 m/s to 30 m/s in the same direction.
The player's puck covers a distance of 10 m during that process.
Therefore,
The initial velocity of the puck is u = 5 m/s
The final velocity of the puck is v = 30 m/s
The distance covered during the period is s = 10 m
Using the equation of motion,
v² - u² = 2as
(30)² - (5)² = 2 × a × 10
900 - 25 = 20 × a
875 = 20 × a
a = 875/20
a = 43.75 m/s²
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M A particle with positive charge q = 3.20 ×10⁻¹⁹C moves with a velocity →v = (2i + 3j - k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (b) What angle does the force vector make with the positive x axis?
The Magnitude of force on the charged particle is -
F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k
We have a positively charged particle that moves through a region where both a uniform magnetic field and a uniform electric field exist.
What is Lorentz Force?The force exerted on a charged particle (q) moving with velocity (v) through an Electric field (E) and Magnetic field (B) is called Lorentz force.
Mathematically -
|F| = qE + qv x B
According to the question, we have -
q = 3.20 × 10⁻¹⁹C
v = (2i + 3j - k) m/s
B = (2i + 4j + k) T
E = (4i - j - 2k) V
Now, using the formula to calculate Lorentz force -
F = q(4i - j - 2k) + q(2i + 3j - k) x (2i + 4j + k)
F = q(4i - j - 2k) + (2qi + 3qj - qk) x ((2i + 4j + k)
F = q(4i - j - 2k) + 0
F = q(4i - j - 2k)
F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k
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QC Two waves simultaneously present on a long string have a phase difference π between them so that a standing wave formed from their combination is described by
y(x,t) = 2Asin( kx + π/2 ) cos( ωt - π/2) (a) Despite the presence of the phase angle π, is it still true that the nodes are one-half wavelength apart? Explain.
The equation of motion of the standing wave, y(x, t) = 2•A•sin(k•x + π/2)•cos(w•t - π/2), indicates that it is still true that the nodes are one half the wavelength apart
Therefore;
It is still true that the nodes are one half the wavelength apart What are the nature of standing wave?The equation describing the standing wave formed by the two waves is y(x, t) = 2•A•sin(k•x + π/2)•cos(w•t - π/2)
A standing wave is formed when two waves that have equal amplitude and frequency and moving in opposite directions, are combined.
A standing wave can be formed by a wave and its reflection, resulting in a wave where there is no propagation of particles beyond the vibration region.
The fundamental frequency of a standing wave consists of two nodes and an antinode.
The wavelength is the distance between two peaks of one wave, such that two nodes are formed within the span of a wavelength, which makes the distance between nodes being half the wavelength of the wave.
Therefore;
It is still true that the nodes are one half the wavelength apart.
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What happens when a metal bar is heated?
A The distance between the molecules increases, making the bar longer.
B The molecules get larger, making the bar longer.
с The molecules vibrate more quickly, making the bar denser.
D The speed of the molecules increases, making the bar thinner.
Answer:
When something is heated, its atoms vibrate. If one end of a metal bar is heated, the atoms at that end vibrate more than the atoms at the cold end. The vibration spreads along the bar from atom to atom. ... Metals are good conductors of heat.
Explanation:
A football goalkeeper moves across her goal in a straight line. Her motion is shown on the following graph of horizontal position xxx vs. time ttt. Graph of x (in meters) vs. t (in seconds). The y-intercept is at (0,0), then x increases linearly from 0 m to 2 m over 4 s, stays constant at 2 m from 4 to 8 seconds, and then decreases linearly from 2m to 0 m between 8 s and 12 s. Graph of x (in meters) vs. t (in seconds). The y-intercept is at (0,0), then x increases linearly from 0 m to 2 m over 4 s, stays constant at 2 m from 4 to 8 seconds, and then decreases linearly from 2m to 0 m between 8 s and 12 s. What is the average speed of the goalkeeper between the times t=4\text{ s}t=4 st, equals, 4, start text, space, s, end text and t=12\text{ s}t=12 st, equals, 12, start text, space, s, end text? Choose 1 answer: Choose 1 answer: (Choice A) A -0.25\,\dfrac{\text m}{\text s}−0.25 s m minus, 0, point, 25, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice B) B 0.50\,\dfrac{\text m}{\text s}0.50 s m 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice C) C -0.50\,\dfrac{\text m}{\text s}−0.50 s m minus, 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction (Choice D) D 0.25\,\dfrac{\text m}{\text s}0.25 s m
Answer:
0.25 m/s
Explanation:
Acceleration cannot be negative.
What is force?
Relate force and motion.
What forces control the motion of everyday objects?
Identify and define the SI unit for force.
Draw a diagram to represent a foot kicking a resting soccer ball. Use arrows to represent the force applied to the ball and to show how the ball moves after it is kicked
A 0.50-kilogram frog is at rest on a rock next to a pond. The frog leaps pushing off of the rock with an acceleration of 5.0 m/s2. What is the magnitude of the net force exerted on the frog as it leaps? a)2.5 N b)1.5 N c)1.0 N d)2.0 N
Given that,
Mass of a frog, m = 0.5 kg
The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².
To find,
The magnitude of the net force exerted on the frog as it leaps.
Solution,
Let the net force exerted on the frog is given by the formula as follows :
F = ma
Putting the values of m and a to find F as follows :
F = 0.5 kg × 5 m/s²
F = 2.5 N
So, the magnitude of net force is 2.5 N.
The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.
Hence, Option a) 2.5N is the correct answer.
Given the data in the question;
Mass of frog; [tex]m = 0.5kg[/tex]Acceleration; [tex]a = 5.0m/s^2[/tex]Force Exerted; [tex]F = ?[/tex]
To determine the magnitude of the net force exerted on the frog as it leaps, we the expression from the Newton's Second law of motion:
[tex]F = m * a[/tex]
Where m is mass and a is acceleration
We substitute our given values into the equation
[tex]F = 0.5kg * 5.0m/s^2\\\\F = 2.5kgm/s^2\\\\F= 2.5N[/tex]
The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.
Hence, Option a) 2.5N is the correct answer.
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i need help please!!
How does the parallax of a nearby object compare to that of an object farther away?.
If we compare the parallax of a nearby object with an object farther away then we observe that the closer objects have a larger parallax as compared to farther objects.
Parallax refers to the apparent distance of an object and happens in everyday situations.
On a linear surface, when an object is seen from a different viewpoint from a particular distance, it exhibits parallax.
It also occurs due to the change in the viewpoint of an observer.
Parallax is represented by the formula d = p1 where 'd' is parsecs and 'p' is the parallax angle which is calculated in arc seconds.
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A Smart Car, which has a mass of 1000 kg, is going 20 m/s. When it hits the barrier, it stops at a time of 0.5 seconds. What is the force on the car?
Answer:
The force = F = -40000 N
Explanation:
Mass m = 1000 kg speed v₁ = 20 m/s speed v₂ = 0 m/s t = 0.5We know that,
Calculating the acceleration
using the formula
a = (v₂ - v₁) / t
= 0 - 20 / 0.5
= -20 / 0.5
= -40 ms⁻²
Thus, acceleration (deceleration) = a = -40 ms⁻²
Note: negative sign gives us an idea the car is slowing down after a collision with the barrier, thus acceleration and velocity are in opposite direction.
We know that
F = ma
= 1000 × -40
= -40000 N
Thus, the force = F = -40000 N
A net impulse delivered to an object always causes a change in the object's
what? A. Energy B. Momentum C. Speed D. mass
Answer:
momentum
Explanation:
The net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.
The given problem is based on the concept of net impulse. The magnitude of force acting on any object for very short interval of time is known as impulse. In the given problem, the transfer of impulse can be explained by the impulse - momentum theorem.
As per the impulse-momentum theorem, "The magnitude of force applied for a very short interval of time is equal to the change in linear momentum , such that the magnitude of force is known as impulse. Ans the expression is,[tex]F \times t = \Delta P\\\\I= \Delta P[/tex]
Here, I is the impulse.
Thus, we can conclude that the net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.
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Name the changes in the state of matter
Solid to liquid
Liquid to gas
Gas to liquid
Liquid to solid
Solid to gas
which has an effect on acceleration (speeding up, slowing down, or changing direction)?
Explanation:
If acceleration points in the same direction as the velocity, the object will be speeding up. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.
1.10 You bring a negatively charged rubber rod close to a grounded
conductor without touching it. Then you disconnect the ground. What is the
sign of the charge on the conductor after you remove the charged rod?
a) negative
b) positive
d) cannot be determined from the
information given
c) no charge
The conductor after disconnected from the ground is positively charged after you remove the rubber rod.
Electrostatic induction is the change in a material's electric charge under the influence of another nearby object that has electric charge. For Electrostatic induction to occur a charged particle is held close (without touching it ) to a uncharged material that is grounded .
So, when the negatively charged rubber rod is brought closer to the grounded conductor which is neutral, a positive charge is induced on the conductor's side which is closer to the rubber rod and a negative charge on the other side which is close to the ground. So the negative charge starts escaping through ground. As it is disconnected from the ground, the conductor becomes positively charged.
Therefore, the conductor is positively charged after you remove the rubber rod.
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julie drives 100 mimi to grandmother's house. on the way to grandmother's, julie drives half the distance at 34.0 mphmph and half the distance at 66.0 mphmph . on her return trip, she drives half the time at 34.0 mphmph and half the time at 66.0 mphmph .
The average speed is r=50 mph
What is speed?Teenagers, young adults, and others use the stimulant medication known as "speed" to feel more focused and alert, and occasionally to get euphoric. Several types of speed are also used by some people to suppress their appetite. Different speed types include: Amphetamines (used to treat ADHD, narcolepsy, and depression)
In essence, an object's speed indicates how quickly it is moving. Its velocity reveals how quickly it is moving in a specific direction. In your daily life, you utilize speed measures, but in physics, velocity measurements are more frequently used.
distance=rate*time
total distance=rate*total time
to Grandmother's...
50=34*t
50/34=t
t=25/17 hours for the first 50 miles
50=66*t
50/66=t
t=25/33 hours for the second 50 miles
total distance=50+50=100 miles
total time=25/17+25/33
total time=(825/561)+(425/561)=1250/561 hours
total distance=rate*total time
100=r*(1250/561)
r=(100)(561/1250)
r=56,100/1250
r=5610/125
r=1122/25
r=44.88 mph is the average speed (rounded it is 44.9 mph)
Note: If you are familiar with the simplified form of the harmonic mean you can solve the problem that way. If not, that's okay. You can look it up if you like.
(2*34*66)/(34+66)=4488/100=44.88 again
from Grandmother's house...
because the times are the same you simply add the 2 rates and divide by 2
(34+66)/2=100/2=50 mph is the average speed
d=r*t
100=34*t+66*t (the times are the same, t)
100=100*t
t=1 hour traveling at 34 mph and 1 hour traveling at 66 mph for a total of 2 hours traveling
d=r*t
100=r*2
r=100/2
r=50 mph is the average speed
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A runner is jogging in a straight line at a steady vr= 7 km/hr. When the runner is L= 7.6 km from the finish line, a bird begins flying straight from the runner to the finish line at vb= 28 km/hr (4 times as fast as the runner). When the bird reaches the finish line, it turns around and flies directly back to the runner.
What cumulative distance does the bird travel? Even though the bird is a dodo, assume that it occupies only one point in space (a “zero” length bird), travels in a straight line and that it can turn without loss of speed.
Answer in units of km.
After this first encounter, the bird then turns around and flies from the runner back to the finish line, turns around again, and flies back to the runner. The bird repeats the back and forth trips until the runner reaches the finish line. How far does the bird travel from the beginning (including the distance traveled to the first encounter)?
Answer in units of km.
Answer:
See answers below
Explanation:
Rate of runner 7 km/hr
Bird = 28 km/ hr
TIME bird flies to finish line 7.6 km / 28 km/hr
the runner covers distance in this time :
7.6 / 28 * 7 km = 1.9 km
this leaves 7.6 - 1.9 km = 5.7 km to the finish
..... the bird turns around
now the two have a closing speed of 28 + 7 = 35 km/hr to cover
this 5.7 remaining km
time to meet = 5.7 km / 35 km/hr = .16285 hr
so the bird flies at 28 km/ hr for this remaining time
= 4.56 km added to the original 7.6 km before turning around = 12.16 km
Total time for the runner to finish 7.6 km / 7 km/hr = 1.086 hr
the bird is flying at 28 km/hr for this entire time = 30. 4 km
Please help me will mark u brainiest
Answer:
C. 2.5 N
Explanation:
The sum of downwards moments equals sum of moments upwards
Downwards moments
Moments= Force*distance
= [10/100 * 2 ] +[20/100*4]
=[0.1*2] +[0.2*4]
=[0.2+0.8]
= 1.0 N
Equate this answer to upward force ;
1.0 N = 0.4 *U
1/0.4 =U
2.5 N =U
A box moves 5m horizontally when force F=10N is applied at an angle 0=30°.
What is the work done?
please help and show your work if you can
Answer:
43.3J
Explanation:
Given parameters:
Force = 10N
Distance = 5m
Angle = 30°
Unknown:
Work done = ?
Solution:
Work done is the force applied to move a body through a particular distance;
Work done = Force x distance cos Ф
Now insert the parameters and solve;
Work done = 10 x 5 cos 30 = 43.3J
A car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds. what is its acceleration?
The acceleration is -0.4 m/s² if the car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds.
What is acceleration?It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.
As we know,
The acceleration can be found using the formula:
a = Δv/t
Here a is the acceleration
Δv is the change in linear velocity
t is the time
Δv = 29 - 33
Δv = -4 m/s
t = 10 seconds
a = -4/10
a = -0.4 m/s²
Thus, the acceleration is -0.4 m/s² if the car is driving at 33 m/s and slows down to 29 m/s over a period of 10 seconds.
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a 30-cm-tall, 6.0-cm-diameter cylindrical beaker is filled to its brim with water. part a what is the downward force of the water on the bottom of the beaker?
The force on the bottom of the beaker is 8.31 N.
How can we calculate the force?To calculate the force on the bottom of the beaker we are using the formula,
F = PA
Here we are given,
A = area of the beaker.
To calculate the force we have to calculate the pressure P first.
To calculate the pressure P we are using the formula,
P= ρgh
ρ= density of water.
g= the acceleration due to gravity.
h=the height of the water.
Now we put the values in the formula, we get,
P= ρgh
Or, P= (1000)×(9.8)×(0.30)
Or, P= 2940 Pa.
From the above calculation we can say that the pressure P= 2940 Pa.
Now we put the values in the force formula,
F=PA
Or, F= 2940×[tex]\pi r^{2}[/tex]
Or, F = 2940×π×(0.03)²
Or, F= 8.31N
From the above calculation we can conclude that, The force on the bottom of the beaker is 8.31 N.
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If you wanted to hold a concert in a place that caused the sound waves
generated by the musicians to produce very few echoes, which place would
you choose?
A. A room with flat surfaces that reflect sound
B. A room lined with soft materials that absorb sound
C. A room furnished with transparent materials that refract sound
D. A room lined with hard materials that amplify sound
Answer: A room lined with soft materials that absorb sound.
Explanation:
Just did it :))
as you walk to the grocery store you walk 800m north, 600m east and 200m south at a speed of 1m/s. what is your velocity?
According to the question as you walk to the grocery store you walk 800m north, 600m east, and 200m south at a speed of 1m/s. Then your velocity will be ( V = 0.5m/sec )
Velocity is the directional pace of an object in movement as an indication of its price of alternate in function as located from a specific body of reference and as measured by a particular widespread of time.
To find the velocity follow the following steps:
Displacement of 800m north, 600m east, and 200m south from the Cartesian coordination is given as 600[tex]\sqrt{2}[/tex]
Velocity = displacement / time
Therefore time = distance / speed
Time = 800 + 600 + 200 / 1
Time = 1600s
Therefore velocity = 600[tex]\sqrt{2}[/tex] / 1600
Velocity = 0.5m/sec
A Cartesian coordinate gadget in a plane is a coordinate system that specifies each point uniquely by a pair of numerical coordinates, which are the signed distances to the factor from constant perpendicular oriented strains, measured in the equal unit of duration.
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Which form of heat transfer transfers both matter(particles) and energy?
Conduction
Convection
Radiation
None of these
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the magnitude of the electric field(b) 10.0cm
The magnitude of the electric field is 3.65×10^5N/C directed radially outward.
R (radius of the solid sphere) = (10cm)( 1m /100cm) = 0.1m
[tex]Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)=\textcolor{#ff9c8c}{26\times 10^{-6}\;\mathrm{C}}[/tex]
Since [tex]{r=0.1\;\mathrm{m} < R}[/tex], we can use Equation [tex]E&=\dfrac{Qr}{4\pi \epsilon_0 R^3}\tag{5}[/tex] to find the magnitude of the electric field:
Substitute numerical values:
[tex]E&=\dfrac{(26\times 10^{-6})(0.1)}{4\pi (8.8542\times 10^{-12})(0.4)^3}\\ &={3.65\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}[/tex]
Magnitude generally refers to distance or quantity. In comparison to motion, Magnitude defines the size of an entity or its speed when moving.
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A plane flew for 2 hours at 467 mph and 5 hours at 536 mph how far did the plane fly in miles?
Answer:
3614
Explanation:
PLEASE ANSWER ASAP I will give 30 points
Many scholars and historians see Florence, Italy as the “New Athens” and the center of the Renaissance. Why would Florence receive this title and how did Florence live up to it?
Answer:
Florence is often named as the birthplace of the Renaissance. The early writers and artists of the period sprung from this city in the northern hills of Italy. As a center for the European wool trade, the political power of the city rested primarily in the hands of the wealthy merchants who dominated the industry
Explanation:
Answer:
Florence is often named as the birthplace of the Renaissance. The early writers and artists of the period sprung from this city in the northern hills of Italy. As a center for the European wool trade, the political power of the city rested primarily in the hands of the wealthy merchants who dominated the industry
Explanation: