Class Rarnk is a numerical position one holds within their class in relation to
their grade point average.
O True
O False

Answers

Answer 1
false is the answer give me brainliest

Related Questions

Cain from Lehman Jackson?

Answers

Guffaws hhjjj hhjjj njjjn. Jjjnbv
Chic dk cfunvcghv bbgdfhb drug

The opposite of love is not hate the opposite of love is control

Answers

Answer:

............. Welp that solves that problem ............

Explanation:

OPEN ENDED QUESTION
How did the mica get to the surface?

Answers

Answer:

The world's chief deposits of mica are found in India at Bihar and in the Nellore district of Madras. Over 50% of the mica used today comes from these two regions. Other major producers are Belgium, Brazil and China.

What is the distance between the points MC-21, -7) and 1(-5, -7)?

A. 14 units
B. 16 units
Turn
Click
C. 26 units
D. 28 units
You
A
B
O O O O
DET
C
D
(1) Ne
Ancie

Answers

The answer is 16 units

️ help me i need a question that needz answering can i ️ pleasehave a apple jk lol

Answers

Answer:

Whats the question if its written be careful of plagiarism

Explanation:

What is JROTC? please help me im begging please 10 points


A An organization for future politicians
B A CTSO for future politicians
C A military officer training program
D An organization for future police officers

Answers

Answer:

junior reserves officers training corps

Distance to Finish Line
(meters)
Jasen
-8t+200
Mary
-7.5t+ 200

Jason and Mary are running an a 200 meter track.
The expressions in the table above show the
distance to the finish line t seconds after they
started the race. How many meters will Mary have
Ieft to finish the race when Jason is on the finish
line?

Answers

Answer:

12.5 meters

Explanation:

Given

[tex]J(t) = -8t + 200[/tex] --- Jasen

[tex]M(t) = -7.5t + 200[/tex] --- Mary

Required

Determine the number of metres left for Mary when Jason finishes

When Jasen finishes the race;

[tex]J(t) = 0[/tex] -- Because Jasen is already at the stoppage

So, we need to calculate time spent by Jasen to get to the finished line.

[tex]J(t) = -8t + 200[/tex]

Substitute 0 for J(t)

[tex]0 = -8t + 200[/tex]

Collect like terms

[tex]8t = 200[/tex]

Solve for t

[tex]t = \frac{200}{8}[/tex]

[tex]t = 25[/tex]

What this implies is that: we want to get Mary's distance at time; [tex]t = 25[/tex]

Substitute 25 for t in [tex]M(t) = -7.5t + 200[/tex]

[tex]M(25) = -7.5 * 25 + 200[/tex]

[tex]M(25) = -187.5 + 200[/tex]

[tex]M(25) = 12.5[/tex]

Hence, Mary has 12.5 metres left

What is the simplified form of the expression 3[14 ÷ (4 2 – 3 2) - 5

Answers

Answer:

3{14 /10-5}

3{1.4-5}

4.2-15

-10.8

Explanation:

i am not sure

or

42/30 -15

4.2-15

-10.8

does anyone have any strategies for the sat? or any book recommendations? most brainliest

Answers

Answer:

For the SAT I would just study EVERYTHING so that you will be mostly prepared

Explanation:

Book Recommendations:

Divergent series

Twilight Saga (this one's questionable for some people)

Delerium Series

One Day

Pride and Prejudice

Narnia

The lord of the Rings

these are some of my favorites :)

The probability that a person has a certain disease is 0.02. Medical diagnostic tests are available to determine
whether the person actually has the disease. If the disease is actually present, the probability that the medical
diagnostic test will give a positive result (indicating that the disease is present) is 0.88. If the disease is not actually
present, the probability of a positive test result (indicating that the disease is present) is 0.01.
a. If the medical diagnostic test has given a positive result (indicating that the disease is present), what is the
probability that the disease is actually present?
b. If the medical diagnostic test has given a negative result (indicating that the disease is not present), what is the
probability that the disease is not present?
a. The probability is
(Round to three decimal places as needed.)
b. The probability is
(Round to three decimal places as needed.)

Answers

The answer would be A and it’s a good explanation of the question
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