Chromatic aberration occurs when:___.
a. a mirror does not focus all colors of light to the same place.
b. a lens does not focus all colors of light to the same place.
c. the absorption of blue light by an intervening dust cloud causes a star to look redder than it really is.
d. atmospheric scattering causes the Sun to look red at sunset.

Answer:

Newton's first law, also known as the law of inertia, states that an object will remain at rest or in motion at a constant velocity unless acted upon by an external force. In other words, an object will not change its velocity on its own, it will only do so if something else pushes or pulls on it. This law is a fundamental principle of classical mechanics, and it helps to explain the behavior of objects under various conditions.

Explanation:

Answer: Newton first law states that an object at rest tends to stay at rest. an object in motion tends to stay in motion in a straight line at a constant speed until another force acts on the object.  It is also called the law of inertia

Explanation: Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Hope this was helful

Answer:

[tex]\text{(a)}\\\text{Given that current energy at starting point }h_{1} \text{ is}:\\E_{h1}=mgh+\frac{1}{2}kx^2\\\text{Plug in height and mass: }E_{h1}=10g+250(0.8)^2=10g+160=258J\\\text{Using Conservation of Energy: }E_{h1}=E_{h2} \\\therefore 258J=mg(h_{2}-h_{1})+\frac{1}{2}mv^2\\=258J=10g+v^2\\=160=v^2\\\therefore v=40m/s \text{ at }h_{2}\\[/tex][tex]\text{(b)}\\\text{Again, apply conservation of energy: } 258J=mg(h_{3}-h_{2})+\frac{1}{2}mv^2\\\text{Plugging in: }258J=16g+v^2 \\\text{ Simplify: }101.2=v^2\\\therefore v=10.05m/s \text{ at } h_{3}[/tex]

Answer:I have already did this the answer was bar graph!

Explanation:

Answer: [tex]1302.25\ N[/tex]

Explanation:

Given

Inclination of hill [tex]\theta=8^{\circ}[/tex]

Each revolution moves 6 m along its path

Diameter of the circle [tex]D=30\ cm[/tex]

the total mass of the cyclist and his bike  [tex]M=150\ kg[/tex]

Suppose a single pedal cyclist gain a vertical height of  [tex]\Delta y[/tex]

[tex]\therefore \sin \theta =\dfrac{\Delta y}{6}\\\\\Delta y=6\sin 8^{\circ}[/tex]

Average force cause to gain in Potential energy

[tex]\therefore\ F_{avg}\cdot 2\pi r=Mg\Delta y\\\Rightarrow F_{avg}=\dfrac{150\times 9.8\times 6\sin 8^{\circ}}{2\pi\cdot 0.15}\\\\\Rightarrow F_{avg}=1302.25\ N[/tex]

Thus, the average force is [tex]1302.25\ N[/tex]

Answer:

Series

Explanation:

If all your lightbulbs are on the same circuit and one blows out then that means your circuit has been broken and the rest won't work.

When a light bulb in the kitchen burns out, numerous lights in the home go off at once. This would provide evidence that the bulbs were wired in series.

In the series circuit, the amount of current flowing through any component in a series circuit is the same and the sum of the individual resistances equals the overall resistance of any series circuit.

The voltage in a series circuit, the supply voltage, is equal to the total of the individual voltage drops.

When one bulb in a series circuit burns, out, the rest of the bulbs stop shining and shut off.

When a light bulb in the kitchen burns out, numerous lights in the home go off at once. This would provide evidence that the bulbs were wired in series.

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If atmospheric pressure is 101.3 KPa and the absolute pressure at the bottom of the tank is 231.3 KPa, the specific gravity of the olive oil is 1.30

To calculate the specific gravity, deduct the absolute pressure at the bottom of the tank (231.3 KPa) from the atmospheric pressure (101.3 KPa). This will give you a ratio of 130KPa, then divide it by the atmospheric pressure which is the specific gravity of olive oil.

Use the formula below:

specific gravity = absolute pressure - atmospheric pressure / atmospheric pressure

Specific gravity = (231.3 KPa - 101.3 KPa) / (101.3 KPa) = 1.30

Therefore, the specific gravity of the olive oil is 1.30.

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Answer:

P = 0.0644 atm

Explanation:

Given that,

The pressure of a sample of gas is measured as 49 torr.

We need to convert this temperature to atmosphere.

The relation between torr and atmosphere is as follow :

1 atm = 760 torr

1 torr = (1/760) atm

49 torr = (49/760) atm

= 0.0644 atm

Hence, the presssure of the sample of gas is equal to 0.0644 atm.

The crate will be under a net force of 95 N. Resolving the force in the x-direction yields the net force on the crate: F = 300 cos 10° - N F= 295.44-196.45, F= 95.

The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.

The friction of a moving item is inversely proportional to the normal force and runs perpendicular to it. The type of surface the thing comes into touch with determines the amount of friction it experiences. As long as there is a point of contact, friction does not depend on the area of contact.

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Explanation:

Answer:

true . it depends tho weight depends on gravity .

Answer:

Initially the PE of the object was W * h = 30 * 10 = 300 Joules

The KE of the object when it struck the ground was 1/2 M v^2

KE = 1/2 * 30/9.8 * 13^2 = 259 J

So the object lost 41 J to friction during the fall

Since Work = Force * distance

Force = 41 J / 10 m = 4.1 N  (the average force of friction)

Answer:

As in chemical formula? It's CH4.

Answer:

 α = [tex]\frac{2 \mu \ N}{m \ r}[/tex]

Explanation:

For this exercise we use Newton's equation for rotational motion

           ∑ τ = I α

the troque is

           α = Fr .r

the moment of inertia of a cylinder is

           I = ½ m r²

we substitute

         fr r = (½ m r²) α

the expression friction is

         fr = μ N

we substitute

         μ N r = ½ m r² α

         α = [tex]\frac{2 \mu \ N}{m \ r}[/tex]

Answer:

Most of us have experienced some form of electric “shock,” where electricity causes our body to experience pain or trauma. If we are fortunate, the extent of that experience is limited to tingles or jolts of pain from static electricity buildup discharging through our bodies.

When we are working around electric circuits capable of delivering high power to loads, electric shock becomes a much more serious issue, and pain is the least significant result of shock.

As electric current is conducted through a material, any opposition to the current (resistance) results in a dissipation of energy, usually in the form of heat. This is the most basic and easy-to-understand effect of electricity on living tissue: current makes it heat up. If the amount of heat generated is sufficient, the tissue may be burnt.

The effect is physiologically the same as damage caused by an open flame or other high-temperature source of heat, except that electricity has the ability to burn tissue well beneath the skin of a victim, even burning internal organs.

Explanation:

is this a question????...

Answer:

B.5m

Explanation:

not sure if i'm right;)

Answer:

a)[tex]W=0.8J[/tex]

b) [tex]d_t=0.20m[/tex]

c) [tex]\triangle K.E=0.267J[/tex]

Explanation:

From the question we are told that:

Mass of cart 1 [tex]M_1=1.0kg[/tex]

Mass of cart 1 [tex]M_2=0.05kg[/tex]

Force on  cart 1 [tex]F_1=4.0N[/tex]

Push Distance of cart 1 [tex]d_1=0.20m[/tex]

Slide Distance of cart 1 [tex]d_1'=0.35m[/tex]

a)

Generally the equation for work-done is mathematically given by

[tex]W=f*d\\W=4*0.20\\W=0.8J \\[/tex]

b)

The systems center of mass moved a net totally of (while being pushed)

Mass 1 =0.20m

Mass 2=0

Therefore

[tex]d_t=d_1+d_2[/tex]

[tex]d_t=0.20+0[/tex]

[tex]d_t=0.20m[/tex]

c)

Since work-done is equal to K.E energy of cart 1

Therefore

[tex]W=1/2mv^2[/tex]

[tex]V_1=\sqrt{\frac{W}{1/2m}}[/tex]

[tex]V_1=\sqrt{\frac{0.8}{1/2(1)}}[/tex]

[tex]V_1=1.264[/tex]

Therefore Kinetic energy before collision is

[tex]K.E_1=1/2mv^2[/tex]

[tex]K.E_1=1/2*1*1.264^2[/tex]

[tex]K.E_1=0.768[/tex]

Generally from the equation for conservation  of momentum the Velocity of cart 2 is mathematically given by

[tex]v_2=\frac{m_1V_1}{m_1+m_2}[/tex]

[tex]v_2=\frac{1*1.264}{1+0.5}[/tex]

[tex]V_2=0.842m/s[/tex]

Therefore the final K.E is mathematically given by

[tex]K.E_2=(1/2)(m_1+m_2)V_2^2[/tex]

[tex]K.E_2=1/2*(1.5)(0.842)^2[/tex]

[tex]K.E_2=0.531J[/tex]

Generally the Change in K.E is mathematically given by

[tex]\triangle K.E=K.E_1-K.E_2[/tex]

[tex]\triangle K.E=0.798-0.531[/tex]

[tex]\triangle K.E=0.267J[/tex]

Therefore the will force change the kinetic energy of the system's center of mass by

[tex]\triangle K.E=0.267J[/tex]

(a) The work done by you when you push the cart at a constant force is 0.8 J.

(b) The distance moved by the center mass of the two cart system is 0.23 m.

(c) The change in kinetic energy of the system center of mass is 0.271 J.

The work done by you when you push the cart at a constant force is calculated as follows;

W = Fd

W = 4 x 0.2

W = 0.8 J

Xcm = (m₁x₁ + m₂x₂)/(m₁ + m₂)

Xcm = (0.5(0) + 1(0.35)) / (1 + 0.5)

Xcm = (0.35)/(1.5)

Xcm = 0.23 m

F = ma

a = F/m

a = (4)/1 = 4 m/s²

v² = u² + 2as

v² = 0 + 2(4)(0.2)

v² = 1.6

v = √1.6

v = 1.265 m/s

m₁u₁ + m₂u₂ = v(m₁ + m₂)

1(1.265) + 0 = v(1 + 0.5)

1.265 = 1.5v

v = 0.84 m/s

K.E(initial) = ¹/₂m₁u₁² + ¹/₂m₂u₂²

K.E(initial) = ¹/₂(1)(1.265)² + ¹/₂(0.5)(0) = 0.8 J

K.E(final) = ¹/₂(m₁ + m₂)v²

K.E(final) = ¹/₂(1 + 0.5)(0.84)²  = 0.529 J

Δ K.E = 0.8 J - 0.529 J = 0.271 J

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Answer:

Explanation:

If two forces act on an object in the same direction, the net force is equal to the sum of the two forces.

Complete Question:

A horizontal force of 5N is required to maintain a velocity of 2m/s for a block of 10kg mass sliding over a rough horizontal surface. The work done by this force in one minute is:

Answer:

Workdone = 600 Joules.

Explanation:

Given the following data;

Force = 5N

Velocity = 2 m/s

Time = 1 minute to seconds = 60 seconds.

Mass = 10 kg

To find the work done;

First of all, we would determine the distance covered by the block.

Distance = speed * time

Distance = 2 * 60

Distance = 120 seconds

Mathematically, workdone is given by the formula;

[tex] Workdone = force * distance[/tex]

Substituting into the formula, we have;

[tex] Workdone = 5 * 120 [/tex]

Workdone = 600 Joules.

Therefore, the work done by this force in one minute is 600 Joules.

C) The mantle's particles will become more dense and rise as a result of the core heat, causing the lithosphere's plates to move in the opposite direction of the convection current.

Convection Currents The lithosphere becomes denser than the surrounding magma and sinks back toward the core as the heated mantle transfers heat energy to it.

Conduction from the core directly heats the lower mantle. As atoms collide, heat is transferred in conduction. Convection is the movement of warm and cool materials upward and downward. Material that is hot rises to the surface through conduction.

“hot spots," which are non-plate tectonic volcanic regions, are probably caused by mantle plumes. A diapir is formed when a mantle plume reaches the upper mantle. Volcanic eruptions are sparked by the heat generated by this molten material in the asthenosphere and lithosphere.

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Answer:

volume=0.1m^3 and force=270N

Explanation:

Solution

Given,

mass=27kg

density=2.70×10^2=270kg/m^3

volume =?

force=?

We have,

force=m×a=27×10=270N

density =m÷v

v×d=m

v=m÷d

=27÷270

=0.1m^3

Answer:

option ( a ) is correct .

Explanation:

Escape velocity on the earth = √ ( 2 GM / R )

where G is universal gravitational constant , M is mass of the earth and R is radius .

V₀ = √ ( 2 GM / R )

escape velocity on the planet where mass is equal is earth's mass and radius is 4 times that of the earth

Radius of the planet = 4 R

escape velocity of planet = √ ( 2 GM / 4R )

= .5 x √ ( 2 GM / R )

= .5 V₀

option ( a ) is correct .

Answer:

6N

Explanation:

Answer:

afap

Explanation:

Answer:

Explanation:

Above is the unscrambled words. Hope this helps!

Answer:

1.4 * 10 ^-1 Ω

Explanation:

Hi,

For this question, we gotta use the formula

R = pL/A

p = The resistivity of your material at 20°C

L = length of the wire

A = cross-sectional area

The resistivity of tungsten is 5.60 * 10^-8 at 20°C

By plugging the values, we get:

R = (5.60 * 10^-8)(2.0)/(7.9*10^-7) = 1.4 * 10 ^-1 Ω

The resultant (x,y) coordinate of vector B is  (- 5, 3) and that of A is (9,3). Then, the sum of x components of vector A and B is 4.

Vectors are physical quantities having both magnitude and direction. For example force, velocity, displacement etc .are vector quantities. Coordinates are used to describe the position of these vectors.

The coordinates of tail of  the vector A is (0, 0) and the head is (9,3)

Then the coordinate of A is (9 -0, 3-0) = (9,3)

Similarly, the tail coordinate of B is (9,3) and head is (4,6). The coordinates of B vector is (4-9, 6-3) = (-5, 3)

Now the sum of x components of A and B is = - 5 + 9 = 4.

Therefore, option b is correct.

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Answer: 0.0576

Explanation:

The equation for fundamental frequency for closed pipes is as follows:

f(1) = v/4L

In which v is the speed of sound (343 m/s) and L is the length of the pipe. Therefore:

528 = 343/4L

x = 0.1624

This is not the answer as you still need to subtract it from the original length.

0.220 - 0.1624 = 0.0576