Christa sells bracelets during the summer months to earn some extra money. She
made this pictograph to represent her sales for last summer.
Bracelets Sold
June
July
August
=4 bracelets
How many bracelets did Christa sell in June and July?
8
32
12
40

Answer:C.5

Step-by-step explanation:

Answer:

y = [tex]6\sqrt{5}[/tex]

Step-by-step explanation:

x^2 + z^2 = 29^2

x^2 = y^2 + 9^2

y^2 + 20^2 = z^2

29^2 - z^2 = y^2 + 81 (equating for x^2 from eqn 1 and 2)

substitute 3rd eqn in 4th

29^2 - (y^2 + 20^2) = y^2 + 81

841 - y^2 - 400 = y^2 + 81

441 = 2y^2 + 81

360 = 2y^2  

y^2 = 180

y = [tex]\sqrt{180}[/tex]

= [tex]\sqrt{36*5} \\[/tex]

y = [tex]6\sqrt{5}[/tex]

Answer:

45789932

Step-by-step explanation:

3456899954433222222344577890009

Answer:

Step-by-step explanation:

Assuming we're rolling a cube die with 6 sides.

Odds for rolling any of 1, 4, 3, or 5 has four possible successes

4/6 = 2/3

Odds for NOT rolling any of 1, 4, 3, or 5 has two possible successes, 2 and 6

2/6 = 1/3

Answer: A 2-column table with 3 rows.

Step-by-step explanation:

9514 1404 393

Answer:

  B  2(−10x+2y−1)

Step-by-step explanation:

The greatest common factor is 2. Factoring that out gives the factorization shown in choice B.

  2(-10x +2y -1)

__

You could factor out -2. Doing that would give ...

  -2(10x -2y +1) . . . . . . . doesn't match choice C

Given polynomial:

(4x²-3x+7) - (x²+8x-5)

⇛ 4x²-3x+7-x²-8x+5

⇛ (4x²-x²) +(-3x-8x)+(7+5)

⇛ (4-1)x²+(-3-8)x+12

⇛ 3x²+(-11)x+12

⇛ 3x²-11x+12

Note:-

When subtracting two polynomials,change the symbols of the each term in the second polynomial which is subtracted from the first polynomial.

Read more:

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Answer:

[tex]3x^2-11x+12[/tex]

Step-by-step explanation:

First, distribute the negative:

[tex]4x^2-3x+7-x^2-8x+5[/tex]

Then combine like terms:

[tex]3x^2-11x+12[/tex]

Answer:

4(3x-8)=52

divide both sides by 4

4/4(3x-8)=52/4

3x-8=13

add both sides by 8

3x-8+8=13+8

3x=21

divide both sides by 3

3x/3=21/3

x=7

Step-by-step explanation:

Step-by-step explanation:

4( 3x-8) = 52

12x - 32 = 52

Group all like terms

12x = 52 + 32

12x = 84

Divide both sides by 12

12/12x = 84/12

x = 7

Therefore, x = 7.

Hope it helps. Please mark me brainliest.

Answer:

$4

Step-by-step explanation:

i know this because i passed collage last year

Answer:

40 and 32

Step-by-step explanation:

This is a linear systems equation problem.

a + b = 72

a = b - 8

Use substitution. Substitute b-8 for a in a+b=72

b-8+b=72

2b-8=72

add 8 to both sides

2b=80 (divide both sides by 2)

b = 40

Plug the value of b into the a=b-8

a=40-8

a=32

Check:  40 + 32 = 72 So the two integers are 40 and 32

Answer:

Step-by-step explanation:

Picture is quite fuzzy so I will ASSUME that the triangle has inner angles of 100° and 34° (now I'm told it's 38)

This means the unlabeled angle is 180 - 100 - 34 = 46°

180 - 100 - 38 = 42°

Using law of sines.

a/sin46 = 12/sin34

a/sin42 = 12/sin38

a = 12sin46/sin34 = 15.17415...

a = 12sin42/sin38 = 13.04217...

round as appropriate. I think it my say to the hundredths

a = 15.17

a = 13.04

If I did not guess the numbers in the photo correctly, just use the same technique to arrive at a better solution.

Answer:

Your equation option is possibly in here somewhere.

Step-by-step explanation:

A = C - 2

B = A + 6  → A = B - 6

C - 2 = A = B - 6 → B = C + 4

44 = C + B + A

44 = C + (C + 4) + (C - 2)

44 = 3C + 2

42 = 3C

C = 7

Rewrite the system of equations in matrix form.

[tex]\begin{bmatrix}1&2&-2\\3&7&-1\\2&4&m\end{bmatrix} \mathbf x = \mathbf b[/tex]

This system has a unique solution [tex]\mathbf x = \mathbf A^{-1}\mathbf b[/tex] so long as the inverse of the coefficient matrix [tex]\mathbf A[/tex] exists. This is the case if the determinant is not zero.

We have

[tex]\det(\mathbf A) = m+4[/tex]

so the inverse, and hence a unique solution to the system of equations, exists as long as m ≠ -4.

Answer:

1) GCF is 1 in this case

2) GCF is 36

3) GCF is 3

4) GCF is 2

Step-by-step explanation:

Well GCF is greatest common factor, with that it Has to be the greatest and a common factor between 2 numbers. You can always list them out for example GCF of 3 and 12

THe factors of 3 are

1-3

The factors of 12 are

1-2-3-4-6-12

The greatest common one is 3.

Answer:

GCF = 1

GCF = 36

GCF = 3

GCF = 2

Step-by-step explanation:

45 & 16

The factors of 16 are: 1, 2, 4, 8, 16

The factors of 45 are: 1, 3, 5, 9, 15, 45

Then the greatest common factor is 1.

36 & 36

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

Then the greatest common factor is 36.

45 & 6

The factors of 6 are: 1, 2, 3, 6

The factors of 45 are: 1, 3, 5, 9, 15, 45

Then the greatest common factor is 3.

30 & 16

The factors of 16 are: 1, 2, 4, 8, 16

The factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30

Then the greatest common factor is 2.

Can I have brainliest?

Answer:

all are perfect cubes

Step-by-step explanation:

you can just cube root the numbers and bom if it aint decimal its a perfect cube

Answer:

1. (x - 1) × (x + 3)

2. x = 3 and y = -2

Step-by-step explanation:

rewrite the equation:

y = 3x - 11; 2x + 3y = 0

solve y = 3x - 11 for the y:

y = 3x - 11

substitute 3x - 11 for y in 2x + 3y = 0;

2x + 3y = 0;

2x + 3y = 0

2x + 3 (3x - 11) = 0

11x - 33 = 0 (simplify both sides of the equation)

11x - 33 + 33 = 0 + 33 (add 33 to both sides)

11x = 33

11x/11 = 33/11 (divide both sides by 11)

x = 3

subtitute 3 for x in y = 3x - 11

y = 3x - 11

y = (3)×(3) - 11

y = -2  

I showed one equation because the other is self explanatory, hope this helps.

The features of the sine function in this problem are given as follows:

Amplitude: 2.

Midline: y = -4.

Period: 3 units.

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Here, we have,

The equation is given as follows:

y = 2sin(2πx/3) - 4.

we have to define the sine function:

The standard definition of the sine function is given as follows:

y = Asin(B(x - C)) + D.

For which the parameters are given as follows:

A: amplitude.

B: the period is 2π/B.

C: phase shift.

D: vertical shift.

The function has a minimum value of -6 and a maximum value of -2, for a difference of 4, hence the amplitude is given as follows:

2A = 4.

A = 2.

Without vertical shift, a function with amplitude of 2 would oscillate between -2 and 2, while this one oscillates between -6 and -2, hence the vertical shift is given as follows:

D = -4.

The shortest distance between repetitions can be given by 2 - (-1) = 3, hence the period is of 3 units and the coefficient B is given as follows:

2π/B = 3

B = 2π/3.

The function is at it's midline at the origin, hence it has no phase shift, and thus the equation is given as follows:

y = 2sin(2πx/3) - 4.

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Answer:

Two crates, A and B, are connected with a rope of negligible mass over a frictionless pulley as represented in the diagram shown on the left. The crates are at rest.

Crate A has an unknown mass and hangs vertically to the right of the slope and crate B, with mass 14 kg, hangs on the slope to the left. The slope makes and angle of 68° with the horizontal.

The coefficient of static friction between crate B and the surface of the slope is 0.3. The direction of the frictional force is up the slope. Calculate the mass of crate A.

Answer:

The length of the leg is 4.2 units.

Hope you could get an idea from it.

Doubt clarification - use comment section.

Step-by-step explanation:

The equation has infinite solution p=2 that's tour variable

Step-by-step explanation:

We will first find the prime factorization of 41 and 52. After we will calculate the factors of 41 and 52 and find the biggest common factor number .

Step-1: Prime Factorization of 41

Prime factors of 41 are 41. Prime factorization of 41 in exponential form is:

41 = 411

Step-2: Prime Factorization of 52

Prime factors of 52 are 2, 13. Prime factorization of 52 in exponential form is:

52 = 22 × 131

Answer:

Equation

2+5=9

Other i don't know

The recursive formula for the geometric sequence is:

[tex]f(n) = \frac{1}{4}f(n - 1), f(1) = -320[/tex]

The recursive equation for a geometric sequence is:

[tex]f(n) = qf(n - 1)[/tex]

In this problem, the sequence is: {-320, -80, -20, -5, . . .}

Hence, the recursive equation is:

[tex]f(n) = \frac{1}{4}f(n - 1), f(1) = -320[/tex]

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The required recursive formula is expressed as [tex]a_{n-1}=-320(\frac{1}{4} )^n[/tex]

The required recursive formula is expressed as [tex]a_{n-1}=-320(\frac{1}{4} )^n[/tex]

n the following sequence  -320, -80, -20, -5,...

The The required recursive formula is expressed as [tex]a_{n-1}=-320(\frac{1}{4} )^n[/tex]is given as:

The required recursive formula is expressed as [tex]a_{n-1}=-320(\frac{1}{4} )^n[/tex]

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Answer:

0.0036 !

Step-by-step explanation:

Give brainliest please :)

0.00359, when rounded to nearest thousandth results in 0.0036.

Rounding off means a number is made simpler by keeping its value intact but closer to the next number. It is done for whole numbers, and for decimals at various places of hundreds, tens, tenths, etc. Rounding off numbers is done to preserve the significant figures.

Given, value to be rounded is : 0.00359

Since, 1 ten thousands = 10000 (104). So, 1 ten thousandth = 0.0001 (10-4)

Therefore, while rounding to nearest ten thousandth, we round the fractional part(or decimal part) upto 4 digits.

Here, In 0.00359, the digit after ten thousandth place is 9, which is (equal to or greater) than 5. So, 5 can be rounded to 6.

Hence, finally, 0.00359, when rounded to nearest thousandth results in 0.0036

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Answer:

4

Step-by-step explanation:

Answer:

Here plz leave review thx

Step-by-step explanation:

Using the Central Limit Theorem, it is found that the distribution of the sample means of the weights of the 7 adult standard poodles is normal, with mean of 50 pounds and standard deviation of 5.67 pounds.

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem, for the population, [tex]\mu = 50, \sigma = 15[/tex].

The distribution of the sample means of the weights of the 7 adult standard poodles is normal, with mean of 50 pounds and standard deviation of 5.67 pounds.

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