Answer: "Look at attachment"
Explanation:
If we look at the second representation of the first visual analogy, we see that the star is in the middle of the white circle and is black. Therefore, for the second representation of the second analogy, the circle must be black and in the middle like the black star.
The answer that best completes the visual analogy is option C.
What is the best visual analogy?The answer that ebst completes the visual analogy must be one that follows the same principles as the ones in the first instance. In the first instance, we can see that the star is now in the middle of the circle and is also a dark color.
The second circle is white and the outermost one is dark. Only the third option matches this depiction.
Learn more about analogies here:
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assuming stp and a stoichiometric amount of nh3 and no in an expandable container originally at 15 L, what is the final volume if the reaction goes to completion? 4NH3 (g) + 6NO (g) —> 5N2 (g) + 6H2O (g)
Answer:
16.5 L
Explanation:
We are given the following factors (they are all essential):
4 moles NH3 gas (15 L initially)6 moles NO gasContainer volume = 15 L initially at STPGiven reaction:
4NH3 (g) + 6NO (g) -> 5N2 (g) + 6H2O (g)
Using the mole ratios from the balanced chemical equation:
For every 4 moles NH3, there will be 6 moles NO and they will react to produce:
5 moles N26 moles H2OInitial moles of gas:
4 moles NH36 moles NOTotal = 10 molesFinal moles of gas:
5 moles N26 moles H2OTotal = 11 molesBy Avogadro's law, volume is directly proportional to moles of gas at constant temperature and pressure.
Since we have 11 moles of gas after the reaction compared to 10 moles initially, the final volume will be:
(11 moles gas)(15 L initial)/(10 moles initial)
= 16.5 L
So in summary, the final volume of the gas mixture after the reaction goes to completion will be 16.5 L, assuming a constant temperature and pressure within the expandable container.
The general approach is to calculate the mole ratios and number of moles of gases before and after the reaction, then use proportionality to determine how the volume will change accordingly.