Answer:
1. To determine the number of moles of copper in 5.00 grams of copper wire, we need to use the molar mass of copper. The molar mass of copper is 63.55 g/mol. We can use the following conversion factor:
1 mol Cu = 63.55 g Cu
Using this conversion factor, we can calculate the number of moles of copper:
5.00 g Cu × (1 mol Cu / 63.55 g Cu) = 0.0787 mol Cu
Therefore, there are 0.0787 moles of copper in 5.00 grams of copper wire.
2. To determine the number of moles of glycine molecules in 28.35 grams of glycine, we need to use the molar mass of glycine. The molar mass of glycine is 75.07 g/mol. We can use the following conversion factor:
1 mol glycine = 75.07 g glycine
Using this conversion factor, we can calculate the number of moles of glycine molecules:
28.35 g glycine × (1 mol glycine / 75.07 g glycine) = 0.3778 mol glycine
Therefore, there are 0.3778 moles of glycine molecules in 28.35 grams of glycine.
3. a. To determine the mass of the daily dietary allowance of vitamin C in grams, we can use the following conversion factor:
1 mol C6H8O6 = 176.12 g C6H8O6
Using this conversion factor, we can calculate the mass of the allowance:
1.42 × 10^-4 mol C6H8O6 × (176.12 g C6H8O6 / 1 mol C6H8O6) = 0.0248 g
Therefore, the mass of the daily dietary allowance of vitamin C for children aged 4-8 years is 0.0248 grams.
b. To determine the number of moles of carbon in 1.42 × 10^-4 mol of C6H8O6, we can use the molar mass of carbon. The molar mass of carbon is 12.01 g/mol. There are 6 carbons in each molecule of C6H8O6, so we can use the following conversion factor:
6 mol C / 1 mol C6H8O6
Using this conversion factor, we can calculate the number of moles of carbon:
1.42 × 10^-4 mol C6H8O6 × (6 mol C / 1 mol C6H8O6) = 8.52 × 10^-4 mol C
Therefore, there are 8.52 × 10^-4 moles of carbon in 1.42 × 10^-4 mol of C6H8O6.
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If you mastered this assignment, you will do exactly as it says to do.
What’s the Count?
NaC2HO4
Elements found in Formula:
Number of atoms in Element:
H2F5BLi
Elements found in Formula:
Number of atoms in Element:
2He2PSO4
Elements found in Formula:
Number of atoms in Element:
3He2O4PH
Elements found in Formula:
Number of atoms in Element:
The elements are the simplest chemical forms and they cannot be broken down through chemical reactions. There are many elements in the given formulas.
What are elements?
The elements are defined as those substances whose atoms all have the same number of protons. The elements are considered as the building blocks of matter. Each element has an atomic number and a symbol.
Each atom is regarded as an element. The elements create bonds to form molecules. The isotopes are the elements with the same atomic number but different mass numbers.
NaC₂HO₄ - 'N' , 'C', 'H','O'
H₂F₅BLi - 'H','F','B','Li'
He₂PSO₄ - 'He', 'P','S','O'
He₂O₄PH - 'He', 'O','P','H'
How many different mRNA sequences could encode the amino acid sequence Met–Leu–Val–His?
Answer:
Therefore, the number of potential sequences is the product of the number of different potential codons for this tripeptide, which gives us a total of (1 × 6 × 6 × 3) = 108 different mRNA sequences that can code for the tripeptide Met-Leu-Arg.
Ba(NO3)2(aq)+CuSO4(aq) complete and balance the precipitation reaction.
Explained answer:
Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + Cu(NO3)2(aq)
This is a precipitation reaction where barium nitrate and copper sulfate react to form barium sulfate , which is insoluble in water and therefore precipitates out of solution, and copper nitrate.
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. First, we balance the sulfate ions:
Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + Cu(NO3)2(aq)
Next, we balance the barium and copper ions:
Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + Cu(NO3)2(aq)
Finally, we balance the nitrate ions:
Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + 2Cu(NO3)2(aq)
Therefore, the balanced precipitation reaction is: Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + 2Cu(NO3)2(aq).
2 HC₂H₂O₂ + Ba(OH)₂
Ba(C₂H₂O₂)₂
+ 2 H₂O
A sample of barium hydroxide (Ba(OH)₂) 0.67 M is titrated with acetic acid (HC₂H₂O₂) 1.2 M. If 55.00 mL of acetic
acid were required, what was the volume of the sample of barium hydroxide?
153.54 mL Ba(OH)₂
(magenta)
98.51 mL Ba(OH)2
(red)
49.25 mL Ba(OH)₂
(blue)
The balanced chemical equation for the reaction between acetic acid and barium hydroxide is:
2 HC₂H₂O₂ + Ba(OH)₂ → Ba(C₂H₂O₂)₂ + 2 H₂O
From the balanced equation, we can see that 2 moles of acetic acid react with 1 mole of barium hydroxide to produce 1 mole of barium acetate and 2 moles of water.
The number of moles of acetic acid used in the titration can be calculated as follows:
moles of HC₂H₂O₂ = Molarity × volume in liters
moles of HC₂H₂O₂ = 1.2 M × (55.00 mL / 1000 mL/ L)
moles of HC₂H₂O₂ = 0.066 moles
From the balanced equation, we know that 2 moles of acetic acid react with 1 mole of barium hydroxide. Therefore, the number of moles of barium hydroxide present in the titration can be calculated as:
moles of Ba(OH)₂ = 0.066 moles / 2
moles of Ba(OH)₂ = 0.033 moles
The molarity of the barium hydroxide solution can be calculated as:
Molarity = moles / volume in liters
We rearrange this equation to solve for the volume:
volume in liters = moles / Molarity
volume in liters = 0.033 moles / 0.67 M
volume in liters = 0.04925 L
Finally, we convert the volume to milliliters:
volume in mL = 0.04925 L × 1000 mL/L
volume in mL = 49.25 mL
Therefore, the volume of the sample of barium hydroxide used in the titration is 49.25 mL. The answer is blue.
What happens to the potential energy of the molecules in a reaction? A. The reactants only lose potential energy when forming products. B. The potential energy of the products is equal to that of the reactants. C. The potential energy of the molecules does not change in a reaction. D. The potential energy of the molecules changes during a reaction.
Potential energy is changed into kinetic energy throughout this process, which is the heat produced during reactions. On the contrary, this happens in an endothermic process.
What happens to the molecules' potential energy during a reaction?Bonds break, new bonds form, and protons and electrons move from a structure with greater potential energy to one with lower potential energy during an exothermic reaction. Potential energy is changed into kinetic energy throughout this process.
What is a reaction's potential energy?The energy that is held inside the bonds and phases of the reactants and products is measured by potential energy. The internal energy includes this potential energy. The internal energy of chemical reactions, also known as enthalpy, stands in for the system's total energy.
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calculate the formula mass of the unknown acid using the manual titration volume of naoh used to reach an endpoint (procedure step
To calculate the formula mass of an unknown acid using the volume of NaOH required to reach the endpoint of the titration, you will need to use the following formula: Formula mass = (molarity of NaOH) x (volume of NaOH) x (molar ratio of NaOH to acid) / (moles of acid).
Here are the steps to follow: Write the balanced equation for the reaction between the acid and NaOH.
Record the volume of NaOH which is used in the titration.
Determine the molarity of the NaOH solution. This can be done by dividing the number of moles of NaOH used in the titration by the volume of NaOH used.
Determine the molar ratio of NaOH to acid from the balanced equation.
Calculate the number of moles of acid that reacted with the NaOH by multiplying the volume of NaOH used in the titration by the molarity of NaOH.
Calculate the formula mass of the acid by plugging in the values for the molarity of NaOH, volume of NaOH, molar ratio of NaOH to acid, and moles of acid into the formula given above.
For example, suppose that you titrated an unknown acid with 0.100 M NaOH, and it took 25.0 mL of NaOH to reach the endpoint. The chemical equation for the reaction is:
Acid + NaOH → NaA + H₂O
The molar ratio of NaOH to acid is 1:1. Let's assume that you used 0.025 moles of NaOH in the titration. Then:
Molarity of NaOH = 0.100 M
Volume of NaOH =25.0 mL =0.0250 L
Moles of acid = (0.100 M) x (0.0250 L) x (1 mol acid / 1 mol NaOH) = 0.00250 mol acid
Now, let's assume that the formula mass of the acid is X. Then:
Formula mass = (0.100 M) x (0.0250 L) x (1 mol acid / 1 mol NaOH) / (0.00250 mol acid) = X g/mol
Therefore, the formula mass of the unknown acid is X g/mol.
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--The given question is incomplete, the complete question is
"How to calculate the formula mass of an unknown acid using the manual titration volume of NaOH with which it was titrated, used to reach the endpoint?"--
7.25 g of a mixture of KCl and KClO3 is heated with MnO2 catalyst and the mass of the mixture is found to be 5.50 g after heating. What is the mass percentage of KClO3 in the initial mixture? (K: 39.0 g/mol, Cl: 35.5 g/mol, O: 16.0 g/mol)
The mass percentage of KClO₃ in the initial mixture, given that the initial mixture has a mass of 7.25 g, is 62.2%
How do i determine the mass percentage of KClO₃?First, we shall determine the molar mass of KClO₃ and KCl. Details below:
For KClO₃
Molar mass of K = 39 g/molMolar mass of Cl = 35.5 g/molMolar mass of O = 16 g/molMolar mass of KClO₃ = ?Molar mass of KClO₃ = 39 + 35.5 + (3 × 16)
Molar mass of KClO₃ = 39 + 35.5 + 48
Molar mass of KClO₃ = 122.5 g/mol
For KCl
Molar mass of K = 39 g/molMolar mass of Cl = 35.5 g/molMolar mass of KCl =?Molar mass of KCl = 39 + 35.5
Molar mass of KCl = 74.5 g/mol
Next, we shall determine the mass of KClO₃ in the initial mixture. Details below:
Molar mass of KClO₃ = 122.5 g/molMolar mass of KCl = 74.5 g/molMass of mixture = 7.25 gMass of KClO₃ =?Mass of KClO₃ = [molar mass of KClO₃ / molar mass of (KClO₃ + KCl)] × mass of mixture
Mass of KClO₃ = [122.5 / (122.5 + 74.5)] × 7.25
Mass of KClO₃ = 4.51 g
Finally, we shall determine the mass percentage of KClO₃. Details below:
Mass of KClO₃ = 4.51 gMass of mixture = 7.25 gMass percentage of KClO₃ =?Mass percentage of KClO₃ = (mass of of KClO₃ / mass of mixture) × 100
Mass percentage of KClO₃ = (4.51 / 7.25) × 100
Mass percentage of KClO₃ = 62.2%
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1. Billy Beaker is reacting 7.98 mL of 2.50 M HCl with excess NaOH. How many grams of water will be produced by this neutralization reaction?
2. Emily Erlenmeyer is reacting 2.43 mL of 2.50 M H2SO4 with 2.51 mL of 3.00 M NaOH. How many grams of water will be produced by this neutralization reaction?
Use molarity and stoichiometry
1. The amount of water produced by the reaction is 0.359 g.
2. The amount of water produced by the reaction is 0.219 g.
How do you calculate the number of moles neutralized in a titration?To calculate the number of moles of acid neutralized by the tablet, subtract the number of moles of acid neutralized in the titration from the initial solution's moles of acid. Understand and explain standardization in the context of acidic and basic solutions used as reagents in experiments.
1. The neutralization reaction,
HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)
we have to calculate the number of moles of HCl that react,
moles of HCl = volume of HCl x concentration of HCl
= 7.98 mL x 2.50 mol/L / 1000 mL/L
= 0.01995 mol
Since NaOH is in excess,
As a result, the amount of water produced will be equal to the amount of HCl that reacts:
moles of water = moles of HCl = 0.01995 mol
we can use the molar mass of water (18.015 g/mol)
mass of water = moles of water x molar mass of water
= 0.01995 mol x 18.015 g/mol
= 0.359 g
2. The neutralization reaction between H2SO4 and NaOH is:
H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O (l)
we have to calculate the number of moles of H2SO4 that react,
moles of H2SO4 = volume of H2SO4 x concentration of H2SO4
= 2.43 mL x 2.50 mol/L / 1000 mL/L
= 0.00608 mol
Now, we have to calculate the number of moles of NaOH that react:
moles of NaOH = volume of NaOH x concentration of NaOH
= 2.51 mL x 3.00 mol/L / 1000 mL/L
= 0.00753 mol
we need to use the stoichiometry of the balanced equation,
moles of water = moles of H2SO4 x (2 moles of water / 1 mole of H2SO4)
= 0.00608 mol x 2
= 0.01216 mol
we can use the molar mass of water (18.015 g/mol)
mass of water = moles of water x molar mass of water
= 0.01216 mol x 18.015 g/mol
= 0.219 g
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Question 7 of 10
When naming a molecule, how do you indicate that the carbons on either side
of the double bond are pointing in opposite directions?
OA. Use the prefix cis-.
OB. Use the prefix methyl-.
OC. Use the number 2 as a prefix.
OD. Use the prefix trans-.
Answer:
use the prefix trans-
Explanation:
trans = opposite orientation across double bond its this one for apex
cis = same orientation across double bond.
Hopefully this helps! :)
How many grams of butanethiol can be deodorized by reaction with 4.50 mL of 9.70×10−2 M NaOCl
The mass of butanethiol that can be deodorized by reaction with 4.50 mL of [tex]9.70*10^{-2[/tex] M [tex]NaOCl[/tex] is 46.356g.
Given the volume of butanethiol = 4.50mL
The concentration of [tex]NaOCl[/tex] = [tex]9.70 * 10^{-2[/tex]M
The mass of butanethiol that can be deodorized = m
Butanethiol ([tex]C4H10S[/tex]) has a molar mass of 106.2 g/mol.
Therefore, the amount of butanethiol that can be deodorized by reaction with 4.50 mL of [tex]9.70 * 10^{-2} M[/tex] [tex]NaOCl[/tex] is calculated as follows:
molarity is calculated as number of moles/volume such that:
Moles of [tex]NaOCl[/tex] =[tex](4.50 mL) * (9.70 * 10^{-2} M) = 0.4365 mol[/tex]
We know that mass of substance = moles*molar mass of substance
mass of butanethiol = (0.4365 mol [tex]C4H10S[/tex])*(106.2 g/mol [tex]C4H10S[/tex]) = 46.356 g [tex]C4H10S[/tex]
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If you measured the absorbance of the copper solution using a wavelength of 610 nanometers during a copper/silver electrolytic cell experiment, would you expect the absorbance to go up, down or stay the same as the reaction proceeds? Justify why
Several sizes of Cu particles' optical absorption spectra are also described; these spectra contain the plasmon band in the 560–580 nm range and a UV band at 222 nm, becoming flatter with increasing particle size.
What wavelength did you employ to gauge the solutions' absorbance of copper II sulphate?From the calibration figure, calculate the copper (II) sulphate concentrations in your two unknown samples. Useful wavelength is 700 nm.
How can you figure out the copper II sulphate solution's concentration?By testing an unknown CuSO4 solution's absorbance with a Colorimeter, you can ascertain its concentration. The corresponding concentration can be obtained on the horizontal axis of the graph by placing the absorbance of the unknown on the vertical axis.
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Which of the following is the correct (and complete) formula for solid sodium sulfide? NaS₂ SOS NaS Na₂S (s) Na₂S
You are a NASA engineer and your superiors have instructed you to analyze the situation. The space craft consists of a command module and a lunar module. The command module is intended to house the three astronauts for most of the duration of the mission and enter lunar orbit, while the lunar module was designed only for the short trip from lunar orbit to the Moon’s surface and back to the command module. The lunar module is only built to support two people, with the third remaining on the command module during a lunar excursion. You have the following information: There are enough CO2 absorbers on the command module to last more than 10 days, but the LiOH cannisters are not easily compatible with the containment units on the lunar module. Each CO2 absorber on the command module contains 600g of lithium hydroxide. Each CO2 absorber on the lunar module contains 365g of lithium hydroxide. The lunar module is expected to reach Earth 3 days from now and has more than enough oxygen supply for the trip. The lunar lander is equipped with six CO2 absorbers. Each astronaut uses approximately 2500 kilocalories per day, and there are 4 kilocalories per gram of glucose. You can assume that metabolism of the astronauts can be approximated by the (unbalanced) equation for glucose metabolism given below: __6126 + __2 → __2 + __2 You need to determine: Can the three astronauts safely make the trip back to Earth with only the CO2 absorbers contained in the lunar module? If not, how many additional CO2 absorbers need to be retrieved from the command module? Write out all calculations and relevant reactions equations that you used to come to this conclusion. Could these calculations be done without using the mole?
Yes, the three astronauts can safely make the trip back to Earth with only the CO2 absorbers contained in the lunar module.
What is lunar module?The Lunar Module (LM) was a spacecraft built by the United States and used in the Apollo program to land humans on the Moon. The LM was designed and built to be used only in the vacuum of space, and it had no capability to operate in the Earth's atmosphere or on the surface of the Moon.
To determine this, we can calculate the amount of glucose needed to sustain the astronauts for the 3-day trip.
We know that each astronaut needs 2500 kilocalories per day, and there are 4 kilocalories per gram of glucose.
Therefore, each astronaut needs 625 grams of glucose per day, or 1875 grams of glucose total for the 3-day trip.
We can then convert this to moles of glucose needed, using the molar mass of glucose (180.156 g/mol).
Therefore, 1875 grams of glucose is equal to 10.4 moles of glucose.
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After two emissions an isotope of oxygen-17 becomes a isotope of nitrogen-13. What are the two emissions
The two emissions required for oxygen-17 to become nitrogen-13 are a positron emission and a neutrino emission.
What is neutrino and a positron?A neutrino is a subatomic particle that is similar to an electron in many ways but differs in that it lacks an electrical charge and has a very small mass that might potentially be zero.
Positron is a particle with the same mass as an electron but has a positive charge.
The transformation of oxygen-17 to nitrogen-13 requires the emission of two particles: a positron (also called a positive beta particle) and a neutrino.
The first emission is the positron, which is a particle with the same mass as an electron but with a positive charge. During the emission, a proton in the oxygen-17 nucleus converts into a neutron, and the positron and a neutrino are produced. The positron quickly annihilates with an electron, releasing two gamma rays.
The second emission is the neutrino, which is a subatomic particle with a very small mass and no electrical charge. The neutrino is emitted during the decay of the nitrogen-13 nucleus as it transitions to its ground state.
Therefore, the two emissions required for oxygen-17 to become nitrogen-13 are a positron emission and a neutrino emission.
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What quantity in moles of precipitate are formed when 52.9 mL of 0.400 M Ca(NO₃)₂ is mixed with excess K₃PO₄ in the following chemical reaction?
3 Ca(NO₃)₂(aq) + 2 K₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6 KNO₃(aq)
Answer:
To determine the number of moles of precipitate formed in the reaction, we first need to find the limiting reagent.
From the balanced chemical equation, we know that 3 moles of Ca(NO₃)₂ react with 2 moles of K₃PO₄ to produce 1 mole of Ca₃(PO₄)₂.
Let's first calculate the number of moles of Ca(NO₃)₂ present in 52.9 mL of 0.400 M solution:
moles of Ca(NO₃)₂ = concentration × volume
= 0.400 mol/L × 0.0529 L
= 0.02116 mol
Since the stoichiometric ratio of Ca(NO₃)₂ to K₃PO₄ is 3:2, we would need 3/2 times the number of moles of K₃PO₄ to react completely with the given amount of Ca(NO₃)₂. However, the problem states that we have an excess of K₃PO₄, which means that all of the Ca(NO₃)₂ will react with the available K₃PO₄.
Therefore, the number of moles of Ca₃(PO₄)₂ that will be formed is equal to the number of moles of Ca(NO₃)₂ used in the reaction, which is 0.02116 mol.
Hence, 0.02116 moles of Ca₃(PO₄)₂ precipitate will be formed when 52.9 mL of 0.400 M Ca(NO₃)₂ is mixed with excess K₃PO₄ in the given chemical reaction.
In a weather forecast on a Seattle radio station the barometric pressure was reported to be 29.4 inches. What is the pressure in SI units? (1 inch = 25.4 mm, 1 atm = 760 mmHg)
Answer:
99585.48 Pa or approximately 0.981 atm.
Explanation:
To convert the barometric pressure from inches to SI units (Pascals), we can use the following conversions:
1 inch = 25.4 mm
1 mm = 0.1 cm
1 cm = 10 mm
1 mmHg = 133.322 Pa
1 atm = 760 mmHg
Therefore, we can calculate the pressure in SI units as follows:
Convert inches to mm: 29.4 inches x 25.4 mm/inch = 746.76 mm
Convert mmHg to Pa: 746.76 mm x 133.322 Pa/mmHg = 99585.48 Pa
Convert atm to Pa: 1 atm x 760 mmHg/atm x 133.322 Pa/mmHg = 101325 Pa
Calculate the pressure in SI units: 99585.48 Pa/101325 Pa/atm = 0.981 atm
Therefore, the barometric pressure in SI units is 99585.48 Pa or approximately 0.981 atm.
How many moles of CaC2 are needed to react with 49.0 grams H2O
In order to react with 45 g of water 1.25 moles of CaC₂ are required. Explanation: Given data: Moles of CaC₂ needed = ? Mass of water = 45.0 g.
[tex] \: [/tex]
Nuclear reactions
A. Involve electrons
B. Can form compounds
C. Can form different elements
D. Depend on chemical combination
Answer: C
Explanation:
Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei.
PLEASE HELP ASAP LAB QUESTIONS
Experiment 1 Procedure:
1. Measure 50.0 mL of water (tap) into a 100 mL graduated cylinder and pour it into a large coffee cup.
2. Determine the temperature of this water
3. Measure out 2.00 g of sodium hydroxide into a piece of paper towel *tare scale!
4. Add the sodium hydroxide to the water in the coffee cup and put a small cup over it, with the thermometer through the hole. Stir GENTLY with the thermometer and record the temperature every 30 seconds for 3 minutes or until it peaks. Record this in a properly labelled table.
5. Let this stand for 45 minutes before proceeding to Exp. 2.
sodium hydroxide and water lab
PURPOSE OF EXPERIMENT: To find Heat of Solution of sodium hydroxide and to find the heat of neutralization between sodium hydroxide and hydrochloric acid.
EXPERIMENT 1 WHAT WE FOUND:
WHAT WE FOUND IN EXP 1:
T (temp.) initial = 20 degrees C
T (temp) FINAL = 28.5 degrees C
moles of sodium hydroxide = 0.0518mol
the molar mass of sodium hydroxide = 39.969g/mol
C (specific heat of water) = 4.184J/g degrees C
THE NUMBER OF TRIALS FOR TEMP IN EXP 1
1st trial = 21 C
2nd trial = 24.5 C
3rd trial = 26 C
4th trial = 26 C
5th trial = 28 C
6th trial = 28.5 C
7th trial = 28.5 C (final temp)
ANALYSIS FOR EXPERIMENT ONE:
1. Determine the moles of sodium hydroxide (NaOH) from the experiment.
2. Determine Qsurroundings and Qrxn
3. Determine the enthalpy for the dissociation of sodium hydroxide (delta H sol)
4. Write the thermochemical equation for the dissociation of sodium hydroxide TWO ways and write an enthalpy diagram
5. What assumptions did you make to calculate #2? (some example assumptions to make: assume that the solution is water and that heat and density COULD be the same as water, etc)
6. Research the actual value and determine the percent error
7. In terms of bonds breaking and forming, what is RESPONSIBLE FOR ENTHALPY CHANGE?
Answer:
Explanation:
The moles of sodium hydroxide (NaOH) from the experiment is 0.0518 mol.
Qsurroundings = -Qrxn, so Qsurroundings = -(m x C x ΔT) = - (50.0 g x 4.184 J/g°C x (28.5°C - 20.0°C)) = - 3464.96 J; Qrxn = -Qsurroundings = 3464.96 J
ΔHsol = Qrxn / moles of NaOH = 3464.96 J / 0.0518 mol = -66,871.12 J/mol or -66.87 kJ/mol
The thermochemical equation for the dissociation of sodium hydroxide:
2NaOH(s) → 2Na+(aq) + 2OH-(aq) + heat
or
NaOH(s) → Na+(aq) + OH-(aq) + heat
The enthalpy diagram shows an energy input (endothermic) for the dissociation of NaOH.
Some assumptions made to calculate #2 include assuming the specific heat capacity of water is the same as the specific heat capacity of the NaOH solution and that the density of the solution is the same as water.
The actual value of ΔHsol for NaOH is -44.51 kJ/mol, so the percent error is:
|(-44.51 kJ/mol - (-66.87 kJ/mol)) / -44.51 kJ/mol| x 100% = 50.21%
The breaking and forming of chemical bonds are responsible for the enthalpy change. In the case of the dissociation of NaOH, the bond between the Na and OH groups is broken, which requires an input of energy, making the process endothermic.
From the experiment, the moles of sodium hydroxide (NaOH) is found to be 0.0518 mol.
What is Moles?
In chemistry, a mole is a unit used to measure the amount of a substance, typically atoms or molecules. One mole of a substance is defined as the amount of that substance which contains the same number of particles (atoms, molecules, or ions) as there are in exactly 12 grams of carbon-12
In the experiment described, 2.00 grams of sodium hydroxide (NaOH) was added to 50.0 mL of water in a coffee cup. The temperature of the water was measured before adding the NaOH and recorded as the initial temperature (T initial). The NaOH was then added to the water and the mixture was stirred gently with a thermometer, while the temperature was recorded every 30 seconds for 3 minutes or until it peaked. The highest temperature reached during this time was recorded as the final temperature (T final).
Using the formula Q = mCΔT, where Q is the amount of heat transferred, m is the mass of the water, C is the specific heat of water, and ΔT is the change in temperature, the amount of heat released or absorbed by the NaOH and water mixture can be calculated.
Since the reaction between NaOH and water is an exothermic reaction, the heat released by the reaction is equal to the heat absorbed by the water.
From the moles of NaOH added and its molar mass, the mass of NaOH can be calculated.
Then, the heat of solution can be calculated using the formula:
Heat of solution = Q / moles of NaOH
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Light can bounce off objects. This is called reflection, and it's what allows us to see objects. This drawing shows a light ray reflecting from the blue construction paper. Although many light waves are hitting the paper and reflecting from it, showing just one ray helps us follow the path of a single wave. white light from flashlight blue light ray seen For each color of paper, which part of white light is reflected?
For each color of paper, the part of white light that is reflected depends on the color of the paper. When white light strikes an object, some of the light is absorbed by the object, some of it is transmitted through the object, and some of it is reflected.
The color of the object that we see is the color of the light that is reflected by the object.
For example, when white light strikes blue paper, the blue color of the paper absorbs all the other colors of the spectrum except blue, which is reflected back to our eyes. This is why we see the paper as blue. Similarly, when white light strikes red paper, the red color of the paper absorbs all the other colors except red, which is reflected back to our eyes. This is why we see the paper as red.
In summary, the color of an object is determined by the color of the light that is reflected by the object, and the color of the light that is reflected depends on the color of the object and the colors of the spectrum that are absorbed or transmitted by the object.
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HELP PLEASE I NEED IT BY TOMORROW photo attached
The specific heat capacity of the metal, given that the metal was heated to 97 °C and transferred to water at 20.5 °C, is 0.203 Cal/gºC
How do I determine the specific heat capacity of the metal?We'll begin by obtaining the heat absorbed by the water. Details below:
Mass of water (M) = 86.0 gInitial temperature (T₁) = 20.5 °CFinal temperature (T₂) = 24.1 °CTemperature change (ΔT) = 24.1 - 20.5 = 3.6 °CSpecific heat capacity of water (C) = 1 Cal/gºC Heat absorbed (Q) =?Q = MCΔT
Q = 86 × 1 × 3.6
Q = 309.6 Cal
Finally, we shall determine the specific heat capacity of the metal. Details below:
Heat absorbed by water (Q) = 309.6 CalHeat released by metal (Q) = -309.6 CalMass of metal (M) = 20.9 gInitial temperature (T₁) = 97 °CFinal temperature (T₂) = 24.1 °CTemperature change (ΔT) = 24.1 - 97 = -72.9 °CSpecific heat capacity of metal (C) = ?Q = MCΔT
-309.6 = 20.9 × C × -72.9
-309.6 = -1523.61 × C
Divide both sides by -1523.61
C = -309.6 / -1523.61
C = 0.203 Cal/gºC
Thus, we can conclude that the specific heat capacity of the metal is 0.203 Cal/gºC
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When two hydrogen atoms approach each other to form a chemical bond, different interactions occur between the atoms. Identify the correct statements with respect to the interactions involved in the formation of chemical bond. Check all that apply. View Available Hint(s)for Part A When two hydrogen atoms approach each other to form a chemical bond, different interactions occur between the atoms. Identify the correct statements with respect to the interactions involved in the formation of chemical bond.Check all that apply. When two atoms of H approach each other, the two nuclei repel each other. When two atoms of H are infinitely far apart, they show attractive interactions. When two atoms of H approach each other, the electrons attract each other. When two atoms of H approach each other, each electron is attracted by the other nucleus. When two atoms of H approach each other, each electron repels the other nucleus.
H atoms communicate attractively even when they are infinitely apart. Each electron is drawn to the other centre as two H atoms get close to one another. The electrons of two H atoms draw one another when they come close to one another.
Do two H atoms exhibit attractive interactions when they are indefinitely separated from one another?When two atoms of H come close to one another, one electron of each atom repels one nucleus while the other nucleus attracts the other electron. H atoms communicate attractively even when they are infinitely apart.
What transpires if two hydrogen ions are separated greatly?They cannot make a covalent bond if they are too far apart because their individual 1s orbitals cannot overlap; instead, they remain as two separate objects.
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4.8g of salt(z) dissolved in 250cm³ of distilled water give a concentration of 0.80m/dm³. Calculate the molar mass of the salt(z)
Answer:
24 g/mol.
Explanation:
To calculate the molar mass of the salt (z), we need to use the formula:
concentration = number of moles / volume of solution
We know that the concentration is 0.80 mol/dm^3, and the volume of the solution is 250 cm^3, which is equivalent to 0.25 dm^3. Therefore, we can rearrange the formula to solve for the number of moles of salt (z):
number of moles = concentration x volume of solution
number of moles = 0.80 mol/dm^3 x 0.25 dm^3
number of moles = 0.20 mol
Next, we can calculate the mass of salt (z) in the solution using the formula:
mass = number of moles x molar mass
We know that the mass of salt (z) is 4.8 g, and we just calculated that the number of moles is 0.20 mol. Therefore, we can rearrange the formula to solve for the molar mass:
molar mass = mass / number of moles
molar mass = 4.8 g / 0.20 mol
molar mass = 24 g/mol
Therefore, the molar mass of the salt (z) is 24 g/mol.
Answer:24 g/mo
Explanation:
How is the outer layer of earth different from the outer layer of Neptune
With a radius of 15,299.4 miles (24,622 kilometers), Neptune is about 4 times wider than Earth. If Earth have been the size of a nickel, Neptune would be about as big as a baseball.
From an common distance of 2.8 billion miles (4.5 billion kilometers), Neptune is 30 astronomical units away from the Sun.
What is the outermost layer of Neptune?Image end result for How is the outer layer of earth one-of-a-kind from the outer layer of Neptune
The outermost layer of Neptune is the atmosphere, forming about 5-10% of the planet's mass, and extending up to 20% of the way down to its core.
What are the three differences between Neptune and Earth?Image end result for How is the outer layer of earth distinct from the outer layer of Neptune
The extent of Neptune is 6.3 x 1013 km3. You could healthy fifty seven Earths inner Neptune and nevertheless have room to spare. A day on Earth is 24 hours, but a day on Neptune is 16 hours and 6 minutes. A yr on Earth is, um, 1 12 months obviously, whilst a year on Neptune is 164.79 years.
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H₂PO₂ +3 NaOH →
0.08 M NaOH
(green)
Na PO + 3 H₂O
If 25.0 mL of H₂PO, 0.16 M are required to titrate 150.0 mL of NaOH to the equivalence point, what is the molarity
of the NaOH?
0.16 M NaOH
(sky blue)
0.02 M NaOH
(yellow)
Answer:
The balanced chemical equation for the reaction between H₂PO₂ and NaOH is:
H₂PO₂ + 3 NaOH → Na₃PO₄ + 3 H₂O
Explanation:
From the equation, we can see that 1 mole of H₂PO₂ reacts with 3 moles of NaOH to produce 1 mole of Na₃PO₄ and 3 moles of H₂O.
The volume of NaOH used in the titration is 150.0 mL, which is equivalent to 0.150 L. The molarity of the H₂PO₂ solution used is 0.16 M, which means that 0.16 moles of H₂PO₂ were used in the titration.
According to the balanced equation, 1 mole of H₂PO₂ reacts with 3 moles of NaOH. Therefore, the number of moles of NaOH used in the titration is three times the number of moles of H₂PO₂ used:
Number of moles of NaOH = 3 × 0.16 = 0.48 moles
The volume of NaOH used is 0.150 L, so the molarity of NaOH can be calculated as follows:
Molarity of NaOH = Number of moles of NaOH / Volume of NaOH used
Molarity of NaOH = 0.48 moles / 0.150 L
Molarity of NaOH = 3.2 M
Therefore, the molarity of NaOH is 3.2 M, which is represented by the sky blue color.
which of the following substance is a non electrolytes ?
(a)H2SO4
(b)CH3COOH
(c)C6H12O6
(d)NH4Cl
Answer:
C
Explanation:
Glucose (sugar) readily dissolves in water, but because it does not dissociate into ions in solution, it is considered a nonelectrolyte; solutions containing glucose do not, therefore, conduct electricity.
calculate the % relative error in solubility by using concentrations instead of activities for the following compounds in 0.0440 m using the thermodynamic solubility products listed below.
The relative solubility is, % relative error = |(s - s') / s| × 100 by using concentrations instead of activities. The % Relative error is [tex]1.42*10^-9[/tex]
The % relative error in solubility, can determine by:
Step 1: Calculate the solubility using concentrations
- Determine the solubility product constant (Ksp) of each compound.
- Write the balanced chemical equation and expression for Ksp.
- Solve for the solubility (s) in terms of concentrations.
Step 2: Calculate the solubility using activities
- Replace concentrations in the Ksp expression with activities (use activity coefficients if needed).
- Solve for the solubility (s') using activities.
Step 3: Calculate the % relative error
- Use the formula: % relative error = |(s - s') / s| × 100
Assuming that the ionic strength is low, we can use the Debye-Hückel equation to calculate the activity coefficients at 25°C and 0.0500 M ionic strength:
log γ± = -0.5091 (z+ z- √(I)) / (1+√(I))
where z+ and z- are the charges of the cation and anion, respectively, and I is the ionic strength.
For KNO3, z+ = 1 and z- = 1, so I = [tex]1/2 (1^2 *0.0500 + 1^2*0.0500)[/tex] = 0.0250. Therefore, the activity coefficients are:
γ±(K+) = γ±(NO_3-) = 0.790
Using the activity coefficients, we can calculate the ion concentrations and then the solubility:
(a) CuCl:
[Cu+] = aCu+ × [CuCl] = [tex](0.3 nm) *√(Ksp/[CuCl]) = 3.17*10^-6 M[/tex]
[Cl-] = [Cu+]
Solubility = [CuCl] = [Cu+] = [Cl-] = [tex]3.17*10^-6 M[/tex]
Using concentrations instead of activities, we have:
[Cu+] = [Cl-] = √(Ksp/[CuCl]) = [tex]3.16*10^{-3}[/tex] M
Solubility = [CuCl] = [Cu+] = [Cl-] = [tex]3.16*10^{-3}[/tex] M
% Relative error = |[tex](3.17*10^{-6} - 3.16*10^{-3})/3.17×10^{-6}[/tex]| × 100% ≈ 99.7%
(b) Fe(OH)2:
[tex][Fe^2+] = aFe^2+ * [Fe(OH)_2] = (0.84 nm) * √(Ksp/[Fe(OH)2]) = M[OH-] = 2[Fe^2+][/tex]
Solubility =[tex][Fe(OH)_2] = [Fe^{2+}][/tex]= [tex]1.42*10^{-9} M[/tex]
Using concentrations instead of activities, we have:
[tex][Fe^2+] = [OH^-] = √(Ksp/[Fe(OH)_2])[/tex] = [tex]3.16*10^-8[/tex] M
Solubility = [tex][Fe(OH)_2] = [Fe^{2+}][/tex]= [tex]3.16*10^-8[/tex] M
% Relative error = [tex]1.42*10^-9[/tex]
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The complete question is:
Calculate the % relative error in solubility by using concentrations instead of activities for the following compounds in 0.0500 M KNO3 using the thermodynamic solubility products listed in Appendix 2.
(a) CuCl (aCu+ = 0.3 nm)
(b) Fe(OH)2
(c) Fe(OH)3
(d) La(IO3)3
(e) Ag3AsO4 (αAsO43֊= 0.4 nm)
Write the equilibrium constant expression, K, for the following reaction: If either the numerator or denominator is blank,
please enter 1.)
N 2 (g)+3H 2 (g) 2NH 3 (g)
The molar concentrations of nitrogen gas, hydrogen gas, and ammonia gas at equilibrium are [N2], [H2], and [NH3], respectively. The equilibrium constant expression, K, for the above reaction is K = [NH3]2 / ([N2] * [H2]3).
How much is K's equilibrium constant?Equilibrium constant (K) is a mathematical ratio that displays the product concentrations subtracted from the reactant concentrations.
What is the expression for the K equilibrium?The expression for the equilibrium constant is expressed as. K=adD·aeEabB·acC. The number of moles of each substance is represented by the lower case letters in the balanced equation, while the substance itself is represented by the upper case letters. Equilibrium favours products if K>1. Equilibrium favours the reactants if K 1.
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How many hydrogen donors does the following molecule have?
What allows a person to interact with web browser software?
O user interface
O file transfer protocol
O networking
O URLS
The ability to interact with web browser software is provided by the user interface. It offers a visual user interface that enables entry of commands and response from the programme.
What makes it possible for a user to engage with the web pages?Via a Web browser, a user can interact with data or software running on a remote server using a Web user interface or Web app. The user interacts with the content on a web browser, which functions as a client, after downloading it from the web server.
What is a piece of software that enables user interaction with websites?A web browser is a piece of software that enables a user to view and interact with content that may be found on a website, including text, photos, videos, music, and other types of media. Hyperlinks to other web pages at the same or different websites can be found in the text and images on a web page.
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