20% of all college students volunteer their time. is the percentage of college students who are volunteers different for students receiving financial aid? of the 381 randomly selected students who receive financial aid, 57 of them volunteered their time. what can be concluded at the
The p-value is less than the significance level so reject the null hypothesis and concluded percentage of the students volunteer their time is different from receiving financial aid students.
Percentage of college students who volunteer their time = 20%
Perform a hypothesis test.
Null hypothesis H₀: p = 0.20,
where p is the proportion of college students who volunteer their time.
The alternative hypothesis is Hₐ: p ≠ 0.20.
Indicating that the proportion of college students who volunteer their time is different for students receiving financial aid.
57 out of 381 randomly selected students who receive financial aid volunteered their time.
Test the hypothesis,
Calculate the sample proportion of volunteers among the students receiving financial aid,
p₁ = 57 / 381
= 0.149
Using Test statistic,
which follows a normal distribution under the null hypothesis .
Mean = 0
Standard deviation σ = √(p(1-p)/n),
where p = 0.20 is the proportion under the null hypothesis
n = 381 is the sample size.
z
= (p₁ - p) /√(p×(1-p)/n)
= (0.149 - 0.20) / √(0.20(1-0.20)/381)
= -2.55
Using attached table of p-value from z-score.
Calculated test statistic of -2.55 corresponds to a p-value of 0.0054,
which is less than the significance level α = 0.01.
Reject the null hypothesis .
Therefore, we conclude that there is evidence to suggest that the percentage of college students who volunteer their time is different for students receiving financial aid.
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The above question is incomplete, the complete question is:
20% of all college students volunteer their time. is the percentage of college students who are volunteers different for students receiving financial aid? of the 381 randomly selected students who receive financial aid, 57 of them volunteered their time. what can be concluded at the α = 0.01 level of significance?
What kind of triangle has angles that measure 47, 70, and 63 degrees
Answer:
Acute triangle
Step-by-step explanation:
angles that are less than 90° are called acute
This triangle has 3 acute angles, so it is an acute triangle
plss helpppssss
6 th grade math
Answer:
Step-by-step explanation:
By the figure, it would mean:
67, 67, 68
72, 72, 73, 76, 76, 77, 78
80, 81, 83, 83, 85, 85, 85, 87, 88
91, 91, 93, 95, 99
a) 2 students
b) 9 students
c) 2 students
Explanation : 5 students (90s) - 3 students (60s) = 2 students
d) 81
Explanation : (67 + 67 + 68 + 72 + 72 + 73 + 76 + 76 + 77 + 78 + 80 + 81 + 83 + 83 + 85 + 85 + 85 + 87 + 88 + 91 + 91 + 93 + 95 + 99) ÷ 24 = 81.33
-3 3/7 times 5 5/6 ........
Answer:
the answer for this problem would be -20
Answer:
-20
Step-by-step explanation:
The easiest way to do it is to change -3 3/7 and 5 5/6 into improper fractions. To do that, let’s take -3 3/7 for example. You would add the numerator by the whole number, and then multiply the denominator by the whole number. Getting you -24/7, the other number would be 35/6 then you multiply the two getting you -840/42, which it turned back into a proper fraction by dividing the two numbers, you would get -20. Hope this helps!
Samantha is told that sin (O) = and tan (0)<0, and was asked to determine the value of cos (©).
• She uses the Pythagorean identity and defines it to be sin() + cos2 ( 0 )= 1.
• She substitutes į into the equation for sin (0)
• She then looks at values of sin ( ) and tan () and says that the only quadrant in which sin() is positive and
tan() is negative is the first quadrant.
Samantha determines that the answer is
cos () =
(21)
Samantha determines the answer as cos(θ) = -√(3/4).
Based on the information given, I can help you with this problem. Samantha is correct in using the Pythagorean identity and substitution, but she made an error in identifying the quadrant. Here's the correct process:
1. Given sin(θ) = 1/2 and tan(θ) < 0.
2. The correct quadrant where sin(θ) is positive and tan(θ) is negative is the second quadrant, not the first.
3. Using the Pythagorean identity: sin^2(θ) + cos^2(θ) = 1.
4. Substitute sin(θ) = 1/2 into the equation: (1/2)^2 + cos^2(θ) = 1.
5. Simplify: 1/4 + cos^2(θ) = 1.
6. Solve for cos^2(θ): cos^2(θ) = 3/4.
7. Since we are in the second quadrant, cos(θ) is negative: cos(θ) = -√(3/4).
Your answer: cos(θ) = -√(3/4).
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Students in Mr. Jeffer’s class write down how many hours each student studies math per week. The results are 3, 4, 4, 3, 5, 4, 6, 3, 2, 2, 4, 6, 5, 7, 5, 3, 3, 4, and 5. Which box plot represents these data?
The box plot that represents these data is Option B because the centre of measure falls on 4.
What is the median study hours for Mr. Jeffer’s math class?To find the median, we first arrange the study hours in ascending order:
2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 6, 6, 7.
From here, we have 15 numbers, so the median is the 8th number in the list which is 4.
As the median study hours for Mr. Jeffer's math class is 4 hours per week, then, the box plot that represents these data is B because the centre of measure falls on 4.
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Graph a right triangle with the two points forming the hypotenuse. Using the sides,
find the distance between the two points in simplest radical form.
(-5, -9) and (-7,-2)
Answer:
I believe the distance between these points is (2, 7), because the difference between -5 and -7 is 2, and the for -9 and -2, it's 7. Hope I helped.
A man is sitting at a park bench 92 feet away from an office building. The medical examiner and other
investigators have determined that the bullet entered the man's head at an angle of 26° and at about 3. 7 feet
off the ground. If the man was shot from the office building, about how high off of the ground was the shooter
located?
The shooter was located approximately 36.15 feet off the ground.
How high was the shooter located?We can use trigonometry to solve for the height of the shooter.
First, we need to find the horizontal distance from the shooter to the man on the park bench. We can use the angle of 26° and the distance of 92 feet to calculate this distance:
horizontal distance = 92 feet * cos(26°)
horizontal distance = 82.33 feet
Next, we can use the height of 3.7 feet and the horizontal distance of 82.33 feet to find the height of the shooter:
tan(26°) = height difference / horizontal distance
height difference = horizontal distance * tan(26°)
height difference = 82.33 feet * tan(26°)
height difference = 36.15 feet
Therefore, the shooter was located approximately 36.15 feet off the ground.
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Recommendations for safely thawing frozen turkey are provided on the packaging.
a. What is the thaw rate of the turkey for refrigerator thawing?
For cold water thawing?
b. What could the initial value represent?
c. Write a linear function in the form y = mx + b to model the time t, in hours, it takes to thaw turkey in the refrigerator as a function of the weight w, in pounds, of the turkey.
a. The thaw rate of the turkey for refrigerator thawing is day(s) per pound.
(simplify your answer.)
(1) it takes about 10 hours to thaw a 20-pound turkey in cold water.(2) it takes an additional 0.25 hours (or 15 minutes) to thaw in the refrigerator.
What is a linear function and examples?A linear function is a function that represents a straight line in the coordinate plane. For example, y = 3x - 2 represents a straight line in the coordinate plane and thus a linear function. Since y can be replaced by the function f(x), this function can be written as f(x) = 3x - 2.
a. A typical thawing rate when thawing in the refrigerator is about 1 day per 4-5 kilograms of turkey meat. So if you have a 20 pound turkey, it will take about 4-5 days to thaw in the fridge. In cold water, the thawing rate is about 30 minutes per pound, so it takes about 10 hours to thaw a 20-pound turkey in cold water.
b) The initial value may represent the weight of the frozen turkey before thawing begins. c. Let y be the time it takes to thaw the turkey in hours and let x be the weight of the turkey in pounds. Assuming a linear relationship between melting time and weight, we can write:
y = mx + b
where m is the thaw rate (in hours per pound) and b is the intercept (the time it takes to thaw a 0-pound turkey, which is 0). From part a, we know that the refrigerator thaw rate is about 1 day per 4-5 pounds of turkey, or about 0.25-0.2 hours per pound. So we can use m = 0.25 in our linear function:
y = 0.25x + 0
This means that for every additional pound of turkey, it takes an additional 0.25 hours (or 15 minutes) to thaw in the refrigerator.
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Out of all the people who like chocolate, what is the relative frequency for selecting a teen?
The relative frequency for selecting a teen out of all the people who like chocolate is calculated by dividing the number of teens who like chocolate (N) by the total number of people who like chocolate (T).
To find the relative frequency for selecting a teen out of all the people who like chocolate, you need to follow these steps:
Step 1: Determine the total number of people who like chocolate (let's call this T).
Step 2: Determine the number of teens who like chocolate (let's call this N).
Step 3: Calculate the relative frequency by dividing the number of teens who like chocolate (N) by the total number of people who like chocolate (T).
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Why are rectangles relatable to factors
Rectangles are relatable to factors because of their areas and perimeter equations
Why are rectangles relatable to factorsFrom the question, we have the following parameters that can be used in our computation:
Explaining why rectangles are relatable to factors
Rectangles are relatable to factors because of the following reasons
Perimeter = 2 * (Length + width)
Area = Length * width
This means that in calculating the areas and the perimeters of a rectangles, we make use of arithmetic expressions
These arithmetic expressions, when expanded form terms and factors of expression
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Express the area of the entire rectangle. your answer should be a polynomial in standard form. x+6 x+2 area=
The formula for the area of a rectangle is length times width, or in this case (x+6)(x+2) or x^2 + 8x + 12 in standard form.
To simplify this expression, we can use the distributive property to multiply the two binomials:
(x+6)(x+2) = x(x+2) + 6(x+2)
= x² + 2x + 6x + 12
= x² + 8x + 12
To express the area of the entire rectangle, we need to multiply the length (x + 6) by the width (x + 2). This will give us a polynomial in standard form.
Step 1: Write down the expression for the area of the rectangle.
Area = (x + 6)(x + 2)
Step 2: Use the distributive property (also known as the FOIL method) to expand the expression.
Area = x(x + 2) + 6(x + 2)
Step 3: Continue to expand and simplify the expression.
Area = (x² + 2x) + (6x + 12)
Step 4: Combine like terms.
Area = x² + 8x + 12
So the area of the entire rectangle is expressed as the polynomial x² + 8x + 12 in standard form.
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What is the slope of y = 3x - 2?
Dado y = 1 / 3x3 +7x dy encontrar dy/dx
To find dy/dx for y = 1/3x³ + 7x, we need to take the derivative with respect to x using the power rule and the sum rule, which gives dy/dx = x² + 7.
The given equation is y = 1/3x³ + 7x. To find dy/dx, we need to take the derivative of y with respect to x. We can do this by using the power rule and the sum rule of differentiation.
Using the power rule, the derivative of x³ is 3x². Using the sum rule, the derivative of 7x is 7. Therefore, the derivative of y with respect to x is:
dy/dx = d/dx (1/3x³ + 7x)
= d/dx (1/3x³) + d/dx (7x)
= (1/3) d/dx (x³) + 7 d/dx (x)
= (1/3) (3x²) + 7
= x² + 7
Hence, we have found that the derivative of y with respect to x is x² + 7.
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There are 5 children running in a relay race. in a relay race, each person runs part of the race. the next runner starts where the previous runner stops. each runner runs the same distance. in this relay race, each child runs of a mile, then stops so the next , a runner can continue. plot the point on the number line that represents the location where the fourth child will stop running.
The location where the fourth child will stop running in the relay race is 4/5 of the way.
To determine the location where the fourth child will stop running in the relay race, we need to find out the total distance covered by the first four children.
Since each child runs 1/5 of a mile, we can find the total distance for the first four children by multiplying their individual distances.
Total distance = (Number of children) * (Distance run by each child)
Total distance = 4 * (1/5)
Now, let's multiply:
Total distance = 4/5
So, the fourth child will stop running at a location 4/5 of a mile from the starting point. To plot this point on a number line, locate the point between 0 and 1 that is 4/5 of the way. This point represents the location where the fourth child will stop running in the relay race.
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Find the critical points c for the function / and apply the Second Derivative Test (if possible) to determine whether each of
these points corresponds to a local maximum (mar) or minimum (Gmin).
/(x) = 7x° In(3x) (* > 0)
(Use symbolic notation and fractions where needed. Give your answer in the form of a comma separated list, if necessary. Enter
DNE if there are no critical points.)
Cmin=
Cmax=
The critical points of f(x) are x = 0 and x = e^(-1/2) / 3, and x = e^(-1/2) / 3 corresponds to a local minimum of f(x). Cmin = e^(-1/2) / 3 and Cmax = 0.
Taking the derivative of f(x) with respect to x using the product rule and the chain rule, we get:
f'(x) = 14x ln(3x) + 7x
Setting f'(x) equal to zero and solving for x, we get:
14x ln(3x) + 7x = 0
Factor out x:
7x(2ln(3x) + 1) = 0
So either x = 0 or 2ln(3x) + 1 = 0.
If x = 0, then f'(x) = 0 and x is a critical point.
If 2ln(3x) + 1 = 0, then ln(3x) = -1/2 and 3x = e^(-1/2). Solving for x, we get:
x = e^(-1/2) / 3
So e^(-1/2) / 3 is also a critical point.
Now we need to apply the second derivative test to determine whether these critical points correspond to a local minimum or maximum.
Taking the second derivative of f(x), we get:
f''(x) = 14 ln(3x) + 21
For x = 0, we have:
f''(0) = 14 ln(0) + 21
The natural logarithm of zero is undefined, so the second derivative does not exist at x = 0. Therefore, we cannot apply the second derivative test at x = 0.
For x = e^(-1/2) / 3, we have:
f''(e^(-1/2) / 3) = 14 ln(1/e^(1/2)) + 21
= -14/2 + 21
= 7/2
Since the second derivative is positive at this point, we can conclude that x = e^(-1/2) / 3 is a local minimum of f(x).
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The Bayview community pool has a snack stand where Juan works part time he tracks his total sales during each shift last month this box plot shows the results what fraction of Juan’s shifts had a total sales of $225 or more
The fraction of Juan's shifts with a total sales of $225 or more can be found by looking at the box plot.
We can see that the top line of the box represents the third quartile (Q3) which is the value where 75% of the data falls below.
In this case, Q3 is at approximately $250. This means that 75% of Juan's shifts had total sales less than $250. To find the fraction of shifts with sales of $225 or more, we need to determine how many shifts fall within the range of $225 to $250.
Looking at the box plot, we can see that the distance between Q1 and Q3 (the interquartile range) is approximately $100. Therefore, the distance between Q1 and $225 is approximately one-third of the interquartile range or $33.33. So, any shift with total sales of $225 or more would fall within one-third of the distance between Q1 and Q3.
Therefore, the fraction of Juan's shifts with total sales of $225 or more is approximately one-third of 75%, which is 25%.
In summary, approximately 25% of Juan's shifts at the Bayview community pool had total sales of $225 or more, based on the box plot.
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A person stands on level ground 60 m from the nearest point of a cylindrical tank of radius length 20 m. Calculate:
a- the circumference of the tank
b the percentage of the circumference that is visible to the person
The circumference of the tank is is 125.66m and the percentage of the circumference that is visible to the person is 10.24%.
a) To calculate the circumference of the cylindrical tank, using the formula C = 2πr, where C is the circumference and r is the radius of the tank. In this case, r = 20 m, so:
C = 2π(20 m) ≈ 125.66 m
b) To determine the percentage of the circumference visible to the person, we first need to calculate the angle (in degrees) that subtends the visible arc. This can be done using the inverse tangent function:
angle = atan(opposite/adjacent) = atan(20 m/60 m)
angle ≈ 18.43°
Since the visible arc is symmetrical on both sides, the total angle of the visible arc is twice the calculated angle:
total angle ≈ 36.86°
Now, calculate the percentage of the circumference that is visible by dividing the total angle by 360° and multiplying by 100%:
percentage = (36.86°/360°) × 100% ≈ 10.24%
So, the visible percentage of the circumference to the person is approximately 10.24%.
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Calculate the costs of these home improvement and maintenance costs.
Annual real estate taxes on a property are $2046. Insurance premiums total $1236. Required flood insurance protection premiums are $380 annually. The county assesses an annual special assessment landfill fee of $125. Trash collection costs $65 quarterly. Annual homeowner's association is $720 for common area maintenance of the subdivision. The pool company charges $45 quarterly to maintain the pool. Ongoing termite and pest protection costs $39 monthly. How much should a buyer save each month to cover these fees?
Answer: To calculate the total amount a buyer should save each month to cover these fees, we need to add up all the costs and divide by 12 (the number of months in a year).
Annual real estate taxes = $2046
Insurance premiums = $1236
Flood insurance premiums = $380
Annual special assessment landfill fee = $125
Quarterly trash collection costs = $65 x 4 = $260
Annual homeowner's association fee = $720
Quarterly pool maintenance costs = $45 x 4 = $180
Monthly termite and pest protection costs = $39 x 12 = $468
Total annual costs = $2046 + $1236 + $380 + $125 + $260 + $720 + $180 + $468 = $5405
Total monthly costs = $5405 / 12 = $450.42
Therefore, a buyer should save $450.42 each month to cover these fees.
Step-by-step explanation:
Riya has pens and pencils, which together are 40 in number. If she had 5 more pencils and 5 less pens, then the number of pencils would become four times the number of pens. Find the original number of pens and pencils.
Answer:
Pens=13
Pencils=27
Step-by-step explanation:
1. Pens = x, Pencils = y
x+y=40
2. y+5 & x-5 --> y=4x
3. Rearrange the x+y=40 to y=40-x. Then substitute y=4x and y=40-x to 4x=40-x.
4. Solve. 4x=40-x, 5x=40, x=8
5. Plug in x=8 to y=4x -> y=32.
6. Reverse the y+5 & x-5. y=27, x=13.
Can u please help me solve this and explain how you got it please.
8xsquared-2-5x=8
Find the x
Using quadratic formula, the value of x in the quadratic equation are 1.47 and -0.85
What is the value of x?To find the value of x, we can either use quadratic formula or factorization method.
8x² - 2 - 5x = 8
Let's rewrite the equation properly
8x² - 5x - 2 - 8 = 0
8x² - 5x - 10 = 0
a = 8, b = -5, c = -10
Using quadratic formula;
-b ±[√b² - 4ac / 2a]
-(-5) ±[√(-5)² - 4(8)(-10) / 2(8)]
x = 5+ √345 / 16 or x = 5 - √345 / 16
x = 1.47 or x = -0.85
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A company responsible for making gumballs found that their gumballs had an average diameter of 2. 21 cm and a standard deviation of 0. 01 cm. What is the percentage of gumballs that are within standard deviations of the mean?
Percentage of gumballs that are within standard deviations of the mean is 68% and have a diameter between 2.20 cm and 2.22 cm.
To find the percentage of gumballs that are within one standard deviation of the mean, we need to use the empirical rule, also known as the 68-95-99.7 rule. According to this rule, for a normal distribution:
Approximately 68% of the data falls within one standard deviation of the mean.Approximately 95% of the data falls within two standard deviations of the mean.Approximately 99.7% of the data falls within three standard deviations of the mean.Here we want to find the percentage of gumballs that are within one standard deviation of the mean. So we can use the first part of the empirical rule and say that approximately 68% of the gumballs have a diameter between:
Mean - Standard deviation = 2.21 - 0.01 = 2.20 cm and Mean + Standard deviation = 2.21 + 0.01 = 2.22 cm
Therefore, approximately 68% of the gumballs have a diameter between 2.20 cm and 2.22 cm.
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Please help me with this math problem!!! Will give brainliest!!
The average price of milk in 2018 was 6.45 dollars per gallon.
The average price of milk in 2021 was 189.95 dollars per gallon.
How to calculate the priceThe given function is: Price = 3.55 + 2.90(1 + x)³
In order to find the average price of milk in 2018, we need to set x = 0:
Price in 2018 = 3.55 + 2.90(1 + 0)³ = 3.55 + 2.90(1) = 6.45 dollars per gallon
Price in 2021 = 3.55 + 2.90(1 + 3)³ = 3.55 + 2.90(64) = 189.95 dollars per gallon
Hence, the average price of milk in 2021 was 189.95 dollars per gallon.
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According to the AAA Foundation for Traffic Safety's American Driving Survey, U. S. Drivers spend,
on average, 51 minutes behind the wheel each day. A researcher believes this is an overstatement.
To investigate, a random sample of 75 drivers were selected. The study revealed that the mean
time behind the wheel for the sample of 75 drivers was 46. 4 minutes with a standard deviation of
18. 8 minutes. Is there convincing evidence that the mean time behind the wheel for all U. S. Drivers
is less than 51 minutes? Use a = 0. 1.
The p-value of the test is 0.017 > 0.01, which means that there is not convincing evidence that the mean time behind the whell for all U.S drivers is less than 51 minutes.
How to test the hypotheses?We are told that:
Time spent by U.S. drivers on average each day = 51 minutes behind the wheel
Thus, the null hypothesis is:
H₀: μ = 51
The alternate hypothesis is:
Hₐ: μ < 51
The formula for the test statistic is:
z = (x' - μ)/(σ/√n)
where:
x' is sample mean
n is sample size
μ is population mean
σ is standard deviation
Thus:
z = (46.4 - 51)/(18.8/√75)
z = -2.12
From online p-value from z-score calculator, we have:
The p-value of the test is referred to as the probability of finding a sample mean that is less than 46.4, which is the p-value of z when X = 46.4.
Looking at the z-table, z = -2.12 has a p-value of 0.017.
Decision:
The p-value of the hypotheses test is seen to be0.017 > 0.01.
Thus, this tells us that we don't have convincing evidence that the mean time spent behind the wheel for all U.S drivers is less than 51 minutes.
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What are the operations in the equation 4x – 5 = 7? What operations do you need to use to solve for x?
Answer:
x=3, Adding and dividing. (Im not too sure how to answer that question, Are there some options that you learned in class?)
Step-by-step explanation:
4x-5=7
+5 +5
4x=12
/4 /4
x=3
The temperature on skylar’s thermometer last night was −3°f. this morning it was colder. what could be the temperature on her thermometer this morning?−5°f−1°f0°f2°f
The only option left is −5°F, which is colder than −3°F and thus could be the temperature on her thermometer this morning.
The temperature on Skylar's thermometer is measured using a scale that indicates the degree of hotness or coldness of the atmosphere. In this case, we know that the temperature on her thermometer last night was −3°F. The negative sign indicates that the temperature was below the freezing point of water.
We are asked to determine what the temperature could be on her thermometer this morning. Since we are told that the temperature is colder than −3°F, we can eliminate 0°F and 2°F as possible options, as they are warmer than −3°F.
Similarly, −1°F is only slightly colder than −3°F, so it is unlikely to be the temperature on Skylar's thermometer this morning. Therefore, the only option left is −5°F, which is colder than −3°F and thus could be the temperature on her thermometer this morning.
It is important to note that temperature can have a significant impact on our daily lives. Extreme cold temperatures can cause frostbite, hypothermia, and other health hazards, while hot temperatures can lead to dehydration, heat exhaustion, and heat stroke. It is important to dress appropriately and take necessary precautions when the temperature is too low or too high.
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Ms. paquette put one coat of paint on a rectangular wall that measured 25 1/2 feet by 10 feet. the paint that she bought was sold in 1-gallon containers.
Ms. Paquette used approximately 0.73 gallons of paint for one coat on the rectangular wall.
To determine how many gallons of paint Ms. Paquette used for one coat on the rectangular wall, we first need to calculate the total area of the wall.
Area of the wall = length x width
= 25.5 feet x 10 feet
= 255 square feet
Now, to find out how many gallons of paint are needed for one coat, we need to know the coverage rate of the paint. This information is usually provided on the paint can label. Let's assume that the coverage rate for the paint Ms. Paquette used is 350 square feet per gallon.
To calculate how many gallons of paint are needed, we can divide the total area of the wall by the coverage rate of the paint:
255 square feet ÷ 350 square feet per gallon = 0.7286 gallons
This means that Ms. Paquette used approximately 0.73 gallons of paint for one coat on the rectangular wall. Since paint is typically sold in 1-gallon containers, she would need to purchase at least one gallon of paint to complete one coat on this wall.
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Helpppppppppppppppppppppp
(1 point) Write an equivalent integral with the order of integration reversed g(y) I hope F(x,y) dydt = F(x,y) dedy f(y) a = b= f(y) = g(y) =
The missing values are:
a = 0b = 1c = 1f(y) = yg(y) = 2 - yh(y) = 0k(y) = yGiven Integral:
[tex]\int\limits^1_0 \int\limits^{2-x}_x {F(x,y)} \, dydx = \int\limits^b_a \int\limits^{g(y)}_{f(y)} {F(x,y)} \ dxdy + \int\limits^c_b \int\limits^{h(y)}_{k(y)} {F(x,y)} \ dxdy \\[/tex]
To write the equivalent integral with the order of integration reversed, express the limits of integration and functions appropriately.
Reversed integral:
[tex]\int\limits^b_a \int\limits^{g(y)}_{f(y)} {F(x,y)} \ dxdy + \int\limits^c_b \int\limits^{h(y)}_{k(y)} {F(x,y)} \ dxdy \\[/tex]
Now, let's determine the values of the variables:
a = 0: The lower limit of the outer integral remains the same as the original integral.
b = 1: The upper limit of the outer integral also remains the same as the original integral.
c = 1: The upper limit of the second inner integral is determined by the limits of integration of the original integral, which is 1.
f(y) = y: The lower limit of the first inner integral is the same as the original integral, which is y = x.
g(y) = 2 - y: The upper limit of the first inner integral is determined by the limits of integration of the original integral, which is 2 - x.
h(y) = 0: The lower limit of the second inner integral remains the same as the original integral.
k(y) = y: The upper limit of the second inner integral remains the same as the original integral.
Learn more about reversed integration here:
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