can y’all help please

Answer:

a. Normally distributed with a mean of $2700 and a standard deviation of $40

Step-by-step explanation:

Given that:

the mean daily revenue is $2700

the standard deviation is $400

sample size n is 100

According to the Central Limit Theorem, the sampling distribution of the sample mean can be computed as follows:

[tex]\mathbf{standard \ deviation =\dfrac{ \sigma}{\sqrt{n}}}[/tex]

standard deviation = [tex]\dfrac{400}{\sqrt{100}}[/tex]

standard deviation = [tex]\dfrac{400}{10}}[/tex]

standard deviation = 40

This is because the sample size n is large ( i,e n > 30) as a result of that  the sampling distribution is normally distributed.

Therefore;

the statement that  describes the sampling distribution of the sample mean is : option A.

a. Normally distributed with a mean of $2700 and a standard deviation of $40

Answer: Price-earnings ratio= 22.0

Step-by-step explanation:

Given: A company had a market price of $38.50 per share, earnings per share of $1.75, and dividends per share of $0.90

To find: price-earnings ratio

Required formula: [tex]\text{price-earnings ratio }=\dfrac{\text{ Market Price per Share}}{\text{Earnings Per Share}}[/tex]

Then, Price-earnings ratio = [tex]\dfrac{\$38.50}{\$1.75}[/tex]

⇒Price-earnings ratio = [tex]\dfrac{22}{1}[/tex]

Hence, the price-earnings ratio= 22.0

Answer: Pi multiplied by the diameter of the circle

Step-by-step explanation:

Answer:

The formula for finding the circumference of a circle is [tex]C = 2\pi r[/tex]. You substitute the radius of the circle for [tex]r[/tex] and multiply it by [tex]2\pi[/tex].

Answer:

[tex]g(x)=4x^{2} +10[/tex]

Step-by-step explanation:

If we perform a vertical translation of a function, the graph will move from one point to another certain point in the direction of the y-axis, in another words: up or down.

Let:

[tex]a>0,\hspace{10}a\in R[/tex]

For:

If:

[tex]f(x)=4x^{2} +6[/tex]

and is translated vertically upward by 4 units, this means:

[tex]a=4[/tex]

and:

[tex]g(x)=f(x)+a=(4x^{2} +6)+4=4x^{2} +10[/tex]

Therefore:

[tex]g(x)=4x^{2} +10[/tex]

I attached you the graphs, so you can verify the result easily.

Answer:

[tex]\huge \boxed{{x\geq -3, \ x \neq 2}}[/tex]

Step-by-step explanation:

The function is given,

[tex]\displaystyle f(x)=\frac{\sqrt{x+3 }}{(x+8)(x-2)}[/tex]

The domain of a function are all possible values of x.

There are restrictions for the value of x.

The denominator of the function cannot equal 0, if 0 is the divisor then the fraction would be undefined.

[tex]x+8\neq 0[/tex]

Subtract 8 from both parts.

[tex]x\neq -8[/tex]

[tex]x-2\neq 0[/tex]

Add 2 on both parts.

[tex]x\neq 2[/tex]

The square root of x + 3 cannot be a negative number, because the square root of a negative number is undefined. x + 3 has to equal to 0 or be greater than 0.

[tex]x+3\geq 0[/tex]

Subtract 3 from both parts.

[tex]x\geq -3[/tex]

The domain of the function is [tex]x\geq -3[/tex], [tex]x\neq 2[/tex].

The domain of the given function will be x ≥ -3 and x ≠ 2.

The entire range of independent input variables that can exist is referred to as a function's domain or,

The set of all x-values that can be used to make the function "work" and produce actual y-values is referred to as the domain.

As per the data given in the question,

The given expression of function is,

f(x) = [tex]\sqrt{\frac{x+3}{(x-8)(x-2)} }[/tex]

The fraction would indeed be undefined if the base of the function were equal to zero, which is not allowed.

x + 8 ≠ 0

x ≠ -8

And, x - 2 ≠ 0

x ≠ 2

Since the square root of a negative number is undefined, x+3 cannot have a negative square root. x+3 must be bigger than zero or identical to zero.

So,

x + 3 ≥ 0

x ≥ -3

So, the domain of the function will be x ≥ -3 and x ≠ 2.

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Answer:

Please look at the picture below!

Step-by-step explanation:

Hope this helps!

If you have any question, please feel free to ask any time.

Answer:

72.5 feet

Step-by-step explanation:

The height of each level from floor to ceiling is 14 1/2 feet.

We want to find the net change in elevation going from the floor of the underground level to the ceiling of the 4th level above ground.

In other words, the change in elevation in going 5 floors up.

Each level has a height of 14 1/2 feet (29/2 feet).

Therefore, the height of the fourth level above ground from the underground level will be 5 times the height of one level:

h = 5 * 29/2 = 72.5 feet

The net change in elevation from the floor of the underground level to the 4th level above ground is:

ΔE = [tex]h_4 - h_0[/tex]

[tex]h_0 = 0 feet\\\\h_4 = 72.5 feet[/tex]

Therefore:

ΔE = 72.5 - 0 = 72.5 feet

Answer:

72.5

Step-by-step explanation:

Answer:

[tex]z = \frac{x}{y} [/tex]

Step-by-step explanation:

Let x be the price of carton of ice cream

Let y be the number of grams in carton

Let z be price per gram.

[tex]z = \frac{x}{y} [/tex]

Which means price of carton of ice cream divided by the number of grams in carton equals price per gram.

Hope this helps ;) ❤❤❤

Answer:

B.

Step-by-step explanation:

Vincent’s construction method produces a hexagon that may not be equilateral and may not be equiangular. The correct option is D.

A regular polygon is a polygon that is equiangular and equilateral. Therefore, the measure of all the internal angles and the measure of all the sides of the polygon are equal to each other.

Given that Vincent wants to construct a regular hexagon inscribed in a circle. He draws a circle on a piece of paper. He then folds the paper circle three times to create three folds representing the diameters of the circle.

Now as it can be seen as the paper is folded as shown in the below image but it does not create a hexagon that is equilateral and equiangular.

Hence, Vincent’s construction method produces a hexagon that may not be equilateral and may not be equiangular.

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Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

cot A = [tex]\frac{cosA}{sinA}[/tex], tanA = [tex]\frac{sinA}{cosA}[/tex], cscA  = [tex]\frac{1}{sinA}[/tex], secA = [tex]\frac{1}{cosA}[/tex]

Consider the right side

[tex]\frac{cotA-tanA}{cscAsecA}[/tex]

= [tex]\frac{\frac{cosA}{sinA}-\frac{sinA}{cosA} }{\frac{1}{sinA}.\frac{1}{cosA} }[/tex]

= [tex]\frac{\frac{cos^2A-sin^2A}{sinAcosA} }{\frac{1}{sinAcosA} }[/tex]

= [tex]\frac{cos^2A-sin^2A}{sinAcosA}[/tex] × sinAcosA ( cancel sinAcosA )

= cos²A - sin²A

= cos2A

= left side ⇒ verified

Answer: Use calculations for population standard deviation.

Step-by-step explanation:

The population standard deviation is defined as

A sample standard deviation is defined as

Since, data set represents the heights of all students in the middle school with 600 students which is population here.

So, we do calculations to find population standard deviation.

Answer:

16x²

Step-by-step explanation:

Answer:

value of Ft(-15,50) = 1.3

Value of Fv(-15,50) = -0.15

Step-by-step explanation:

W = perceived temperature

T = actual temperature

W = f( T,V)

Estimate the values of  ft ( -15,50) and  fv(-15,50)

calculate the Linear approximation of   f at(-15,50)

[tex]f_{t}[/tex] (-15,50) =  [tex]\lim_{h \to \o}[/tex] [tex]\frac{f(-15+h,40)-f(-15,40)}{h}[/tex]

from the table take h = 5, -5

[tex]f_{t}(-15,40) = \frac{f(-10,40)-f(-15,40)}{5}[/tex]  = [tex]\frac{-21+27}{5} = 1.2[/tex]

[tex]f_{t} = \frac{f(-20,40)-f(-15,40)}{-5}[/tex] = 1.4

therefore the average value of [tex]f_{t} (-15,40) = 1.3[/tex]

This means that when the Temperature is -15⁰c and the 40 km/h the  value of Ft (-15,40) = 1.3

calculate the linear approximation of

[tex]f_{v} (-15,40) = \lim_{h \to \o} \frac{f(-15,40+h)-f(-15,40)}{h}[/tex]

from the table take h = 10, -10

[tex]f_{v}(-15,40) = \frac{f(-15,50)-f(-15,40)}{10}[/tex]  = [tex]\frac{-29+27}{10} = -0.2[/tex]

[tex]f_{v} (-15,40) = \frac{f(-15,30)-f(-15,40)}{-10}[/tex]  = [tex]\frac{-26+27}{-10}[/tex]  = -0.1

therefore the average value of [tex]f_{v} (-15,40) = -0.15[/tex]

This means that when the temperature = -15⁰c and the wind speed is 40 km/h the temperature will decrease by 0.15⁰c

w = f(T,v)

   = -27 + 1.3(T+15) - 0.15(v-40)

   = -27 + 1.3T + 19.5 - 0.15v + 6

   = 1.3T - 0.15v -1.5  

calculate the linear approximation

[tex]\lim_{v \to \infty}[/tex][tex]\frac{dw}{dv} = \lim_{v \to \infty} \frac{d(1.3T-0.15v-1.5)}{dv}[/tex]  = -0.15

Answer:

D. [tex]70.34 cm^2[/tex]

Step-by-step explanation:

Area of sector of a circle is given as θ/360*πr²

Where,

r = radius = 12 cm

θ = 56°

Use 3.14 as π

Plug in the values into the formula and solve

[tex] area = \frac{56}{360}*3.14*12^2 [/tex]

[tex] area = 70.34 [/tex]

Area of the sector ABC = [tex] 70.34 cm^2 [/tex]

The answer is D

I hope this will help uh.....

Answer:

[tex]\boxed{(-\frac{\sqrt{3}}{2}, \frac{1}{2})}[/tex]

Step-by-step explanation:

Method 1: Using a calculator instead of the unit circle

The unit circle gives coordinates pairs for the cos and sin values at a certain angle. Therefore, if an angle is given, use a calculator to evaluate the functions at cos(angle) and sin(angle).

Method 2: Using the unit circle

Use the unit circle to locate the angle measure of 150° (or 5π/6 radians) and use the coordinate pair listed by the value.

This coordinate pair is (-√3/2, 1/2).

Answer: This coordinate pair is (-√3/2, 1/2).

Step-by-step explanation:

Use the unit circle to locate the angle measure of 150° (or 5π/6 radians) and use the coordinate pair listed by the value.

Answer:

Step-by-step explanation:

[tex] \frac{8}{7} = \frac{x}{5} [/tex]

To find x first cross multiply

We have

7x = 8 × 5

7x = 40

Divide both sides by 7

That's

[tex] \frac{7x}{7} = \frac{40}{7} [/tex]

[tex]x = \frac{40}{7} [/tex]

x = 5.7142

We have the final answer as

Hope this helps you

Answer:

[tex]\boxed{\sf x = 5.7}[/tex]

Step-by-step explanation:

[tex]\sf \frac{8}{7} = \frac{x}{5} \\=> 1.142 = \frac{x}{5}\\ Multiplying \ both \ sides \ by \ 5\\1.142 * 5 = x\\5.7 = x\\OR\\x = 5.7[/tex]

Answer:

x(3x+5)

Step-by-step explanation:

3x^2+5x

take out common factor x

= x(3x+5)

Answer:

Step-by-step explanation:

3x² + 5x

Factor out X from the expression

= x ( 3x + 5 )

Hope this helps...

Best regards!!

Answer:

  60%

Step-by-step explanation:

Reducing the rental cost by a factor of 6 makes it be 90%/6 = 15% of the original costs of the company. The non-rental costs are 100% -90% = 10% of the original costs of running the company.

Now, the rental costs are 15%/(15%+10%) = 3/5 of the present costs of the company.

Rental cost constitutes 60% in the total costs of the company.

Answer:

16. x=48 y=70

17. x=45 y=5

Step-by-step explanation:

16. This is an isosceles triangle meaning that the two angles are the same. Meaning that (x+7)=55.

55-7=48

(48+7)=55 x=48

There are 180 degrees in a triangle, so 55+55=110

180-110=70. y=70

17. This is a right angled triangle meaning that the squared part is 90 degrees. And it is also an isosceles triangle meaning that x=97.

There are 180 degrees in a triangle, and 90 is already taken, meaning that there is 90 degrees more left.

90/2=45

x=45

9✖️5=45 y=5

Hope this helps, BRAINLIEST would really help me!

Answer:

At 95% confidence limits for the true difference between the  average Miles per Gallon for the two models is -1.8210  to  4.1789

Yes 95 % confidence means  that there's conclusive evidence to indicate that one model gets a higher MPG than the other.

Step-by-step explanation:

                              Model A              Model B

Sample Size              50                          55

Sample Mean  x`         32                           35

Sample Variance  s²    9                            10

At 95 % confidence limits are given by

x1`-x2` ± 1.96 [tex]\sqrt{\frac{s^{2} }{n1} +\frac{s^{2}}{n2} }[/tex]

Putting the values

32-35  ± 1.96  [tex]\sqrt\frac{9}{50}+\frac{10}{55}[/tex]        ( the variance is the square of  standard deviation)

-3 ± 1.96 [tex]\sqrt{ \frac{495+500}{2750}[/tex]

-3 ± 1.96( 0.6015)

-3 ± 1.17896

-1.8210; 4.1789

Thus the 95% confidence limits for the true difference between the  average Miles per Gallon for the two models is -1.8210  to  4.1789.

Yes 95 % confidence means  that there's conclusive evidence to indicate that one model gets a higher MPG than the other.

Answer:

The z-score for a sales associate from this store who earns $37,500 is 2

Step-by-step explanation:

From the given information:

mean [tex]\mu[/tex] = 32500

standard deviation = 2500

Sample mean X = 37500

From the given information;

The value for z can be computed as :

[tex]z= \dfrac{X- \mu}{\sigma}[/tex]

[tex]z= \dfrac{37500- 32500}{2500}[/tex]

[tex]z= \dfrac{5000}{2500}[/tex]

z = 2

The z-score for a sales associate from this store who earns $37,500 is 2

Answer:

4 ft

7.2 ft

20 ft

Step-by-step explanation:

When the balloon is shot, x = 0.

y = -0.05(0)² + 0.8(0) + 4

y = 4

The balloon reaches the highest point at the vertex of the parabola.

x = -b / 2a

x = -0.8 / (2 × -0.05)

x = 8

y = -0.05(8)² + 0.8(8) + 4

y = 7.2

When the balloon lands, y = 0.

0 = -0.05x² + 0.8x + 4

0 = x² − 16x − 80

0 = (x + 4) (x − 20)

x = -4 or 20

Since x > 0, x = 20.

The slingshot launched the ballon from a height of 4 feet. The balloon's maximum height was 72 feet. The balloon landed 20 feet from the slingshot.

To determine the height from which the slingshot launched the balloon, we need to evaluate the function f(0) because when x is zero, it represents the starting point of the balloon's trajectory.

f(x) = -0.05x² + 0.8x + 4

f(0) = -0.05(0)² + 0.8(0) + 4

f(0) = 4

Therefore, the slingshot launched the balloon from a height of 4 feet.

To find the maximum height of the balloon, we can observe that the maximum point of the parabolic function occurs at the vertex.

The x-coordinate of the vertex can be calculated using the formula x = -b / (2a).

In our case, a = -0.05 and b = 0.8.

Let's calculate the x-coordinate of the vertex:

x = -0.8 / (2×(-0.05))

x = -0.8 / (-0.1)

x = 8

Now, substitute this x-coordinate into the function to find the maximum height:

f(x) = -0.05x² + 0.8x + 4

f(8) = -0.05(8)² + 0.8(8) + 4

f(8) = -0.05(64) + 6.4 + 4

f(8) = -3.2 + 6.4 + 4

f(8) = 7.2

Therefore, the balloon reached a maximum height of 7.2 feet.

To determine how far from the slingshot the balloon landed, we need to find the x-intercepts of the quadratic function.

These represent the points where the height is zero, indicating the balloon has landed.

Setting f(x) = 0, we can solve the quadratic equation:

-0.05x² + 0.8x + 4 = 0

x² - 16x - 80= 0

x=-4 or x=20

We take the positive value, so  the balloon landed 20 feet from the slingshot.

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Answer:

I hope it will help you...

The value of [tex]x+y[/tex] will be equal to 185 degrees.

From figure it is observed that,

The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle.

        [tex]y=45+60=105[/tex]

We know that, By triangle property  sum of all three angles in a triangle must be equal to 180 degrees.

  So that,             [tex]x+55+45=180[/tex]

                           [tex]x=180-100=80[/tex]

Thus,    [tex]x+y=105+80=185[/tex] degree

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Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

[tex]p_{1}(t) = 1[/tex], [tex]p_{2}(t)= t^{2}[/tex] and [tex]p_{3}(t) = 3 + 3\cdot t[/tex]:

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0[/tex]

[tex](\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1} + 3\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2} = 0[/tex]

[tex]\alpha_{3} = 0[/tex]

Whose solution is [tex]\alpha_{1} = \alpha_{2} = \alpha_{3} = 0[/tex], which means that the set of vectors is linearly independent.

[tex]p_{1}(t) = t[/tex], [tex]p_{2}(t) = t^{2}[/tex] and [tex]p_{3}(t) = 2\cdot t + 3\cdot t^{2}[/tex]

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0[/tex]

[tex](\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1}+2\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2}+3\cdot \alpha_{3} = 0[/tex]

Since the number of variables is greater than the number of equations, let suppose that [tex]\alpha_{3} = k[/tex], where [tex]k\in\mathbb{R}[/tex]. Then, the following relationships are consequently found:

[tex]\alpha_{1} = -2\cdot \alpha_{3}[/tex]

[tex]\alpha_{1} = -2\cdot k[/tex]

[tex]\alpha_{2}= -2\cdot \alpha_{3}[/tex]

[tex]\alpha_{2} = -3\cdot k[/tex]

It is evident that [tex]\alpha_{1}[/tex] and [tex]\alpha_{2}[/tex] are multiples of [tex]\alpha_{3}[/tex], which means that the set of vector are linearly dependent.

[tex]p_{1}(t) = 1[/tex], [tex]p_{2}(t)=t^{2}[/tex] and [tex]p_{3}(t) = 3+3\cdot t +t^{2}[/tex]

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2}+ \alpha_{3}\cdot (3+3\cdot t+t^{2}) = 0[/tex]

[tex](\alpha_{1}+3\cdot \alpha_{3})\cdot 1+(\alpha_{2}+\alpha_{3})\cdot t^{2}+3\cdot \alpha_{3}\cdot t = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1}+3\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2} + \alpha_{3} = 0[/tex]

[tex]3\cdot \alpha_{3} = 0[/tex]

Whose solution is [tex]\alpha_{1} = \alpha_{2} = \alpha_{3} = 0[/tex], which means that the set of vectors is linearly independent.

The set of vectors A and C are linearly independent.

Answer:

c. ax+b=ax+b

Step-by-step explanation:

To know what equation has infinite solutions, you first try to simplify the equations:

a.

[tex]ax=bx+c\\\\(a-b)x=c\\\\x=\frac{c}{a-b}[/tex]

In this case you have that a must be different of b, but there is no restriction to the value of c, then c can be equal to a or b.

b.

[tex]ax+b=ax+c\\\\b=c[/tex]

Here you obtain that b = c. But the statement of the question says that a, b and c are three different numbers.

c.

[tex]ax+b=ax+b\\\\0=0[/tex]

In this case you have that whichever values of a, b and are available solutions of the equation. Furthermore, when you obtain 0=0, there are infinite solutions to the equation.

Then, the answer is:

c. ax+b=ax+b

Answer:

ax + b = ax + b

Step-by-step explanation:

i just answered it

let us build equation for unknown legs

If we keep the length pf one leg as x

the other leg would be x +3

so we can build a relationship using pythagoras theorem

x^2 + (x+3)^2 = 15^2

x^2 + x^2 + 6x + 9 = 225

2x^2 + 6x + 9 = 225

2x^2 + 6x+ 9-225 = 0

2x^2 + 6x - 216 = 0

x^2 + 3x - 108 = 0 dividing whole equation by 2

x^2 + 12x - 9x - 108 = 0

x ( x + 12 ) - 9 (x + 12) = 0

(x -9) ( x +12) = 0

solutions for x are

x = 9 or x = -12

as lengths cannot be negative

one side length is 9cm

and other which is( x + 3)

9 + 3

12cm

The lengths of the legs of the right angled triangle is 9 feet and 12 feet.

Pythagoras theorem is used to show the relationship between the sides of a right angled triangle. It is given by:

Hypotenuse² = First Leg² + Second leg²

Let x represent the length of one leg. The other leg is three more = x + 3, hypotenuse = 15 ft. Hence:

15² = x² + (x + 3)²

x² + 6x + 9 + x² = 225

2x² + 6x - 216 = 0

x² + 3x - 108 = 0

x = - 12 or x = 9

Since the length cant the negative hence x= 9, x + 3 = 12

The lengths of the legs of the right angled triangle is 9 feet and 12 feet.

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Answer:2/3-4

Step-by-step explanation:

Hi,

The correct answer is √ra = v or v = √ra.

The original equation is a = v^2/r.

Then we multiply r to get ra = v^2

After that we √ra = √v^2

Our final answer is then √ra = v

XD

Answer:

what we have to tell

Step-by-step explanation:

please send the correct information

Answer:

The answer on PLATO is Graph Z.

Step-by-step explanation:

I just had this question and got it right!!!

Hope this Helps!!!